a student investigates the density of an aluminum cola can by submerging it in a measuring cylinder of water. When completely submerged, a full can of unopened cola displaces 337 ml of water. The student then empties the can, she finds that it holds 332 ml of cola and that the mass of the empty can is 13.5g when it's empty. Calculate the density of the aluminum used to make the can.
(I did 337-332= 5ml 13.5g/5ml= 2.7 g/cm^3 . I think I got it wrong)
The density of the can is 0.041 g/mL.
What is the density?The term density is the ratio of the mass to the volume of an object. We know that the volume is an intrinsic property of the substance. The volume does not change thus, it can be used to identify a substance.
Now we have that the volume of the liquid that the can could hold is 332 ml. This is the real volume of the aluminum can. The mass of the can is found to be 13.5g.
Density = mass/volume = 13.5g / 332 ml = 0.041 g/mL
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I need help please..
The mass of the object is obtained as 608.5 grams.
What is density?The term density refers to the ratio of the mass to the volume of an object. The density of an object does not change thus we could use the density of an object to identify that object. If we have the density of the object, that alone could be used to trace the exact kind of material that we are dealing with.
Now we know that the density of the object is 6.095 g/cm^2
Volume of the object is obtained as 99.830 mL
Density = mass/volume
mass = density * volume
mass = 6.095 g/cm^2 * 99.830 mL
mass = 608.5 grams
Hence, the mass of the object is obtained as 608.5 grams.
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You mix 500.0 mL of 0.250 M iron(III) chloride solution with 475.0 mL of 0.350 M barium chloride solution. Assuming the volumes are additive, what is the molarity of chloride ion in the mixture
0.74 mol/lit
You mixed 500.0 mL of 0.250 M iron(III) chloride solution with 475.0 mL of 0.350 M barium chloride solution
As per given in the above statement,
volume of fecl3 = 5oo.ml
fecl3 = 0.250 M
= 0.250 mol/litre
volume of Bacl2, = 175.0mL
Bacl2 = 0.350M
= 0.350 mol/litre
we need to calculate moles of fecl3 and
Bacl2
first :
fecl3= 0.250 mol/litre (Molarity)
moles of FeCl3, = molarity * volume
= 0.250 * 500 ml
= 0.125 moles
moles of fecl3 = 0.125 moles
now, bacl2 = 0.350M
moles of bacl2 = molarity * volume
= 0.350 * 175/1000
= 0.061 moles
furthermore:
one mole of bacl2 will give one mole of ba^+2 and 3 moles of cl-
0.125 moles of fecl3 = 3 * 0.125 cl-
= 0.375 moles of cl-
similarly :
one mole of bacl2 will give one mole of ba^+2 and 2 mole of cl-
= 0.061 moles of bacl2 = 2 * 0.061
= 0.122 moles of cl-
total volume of solution :
= 500 ml + 1750 ml
= 0.675 litre
total number of moles of cl-
= 0.375 + 0.122
= 0.497 moles
now,
molarity of cl- = total moles of solute / volume of solution
= 0.497 moles/ 0.675 litre
= 0.74 mol/lit
molarity of cl- = 0.74 mol/lit
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Why are nutrient molecules important?
Nutrient molecules are important because the body breaks down nutrient molecules into absorbable molecules that can produce energy in the body for carrying out daily tasks.
In order to sustain life and promote growth and health, our bodies need nutrients that are chemical components that can be found in food. Nutrients must come from our diet because the human body is unable to produce them.Three primary roles that nutrients play in the body include: supplying energy, supporting bodily structure, and controlling chemical reactions.Our body needs a variety of nutrients, including carbohydrates, protein, fat, minerals, vitamins, roughage, etc.Macronutrients are nutrients that must be present in large quantities. The three types of macronutrients are proteins, lipids, and carbohydrates. These might be metabolically converted into cellular energy.The body needs micronutrients in smaller levels, yet they are still necessary for performing basic activities. All of the necessary minerals and vitamins are considered micronutrients.Therefore, nutrient molecules are important for overall growth of our body.
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how do you get that 1000g = 1 kg
Unit 3 Problems #2
Write the hobel gas configuration &
Lewis dof diagram for:
Be, O, AI, CI, Ni, Xe, W
An atom's noble gas configuration starts with the elemental symbol of the last noble gas that came before it, then moves on to the arrangement of the remaining electrons.
A Lewis electron dot diagram, also known as an electron dot diagram, Lewis diagram, or Lewis structure, is a diagram that employs dots to represent the valence electrons of an atom. The number of dots corresponds to the atom's valence electron count.
Write the noble gas configuration & Lewis dot diagram for:
Be, O, AI, CI, Ni, Xe, W
The diagrams known as Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.
Be - [He] 2s 2O - [He] 2s 2 2p4Al - [Ne] 3s 2 3p1Cl - [Ne] 3s 2 3p5Ni - [Ar] 3d 8 4s 2Xe - [Kr] 4d 10 5s 2 5p 6W - [Xe] 4f 14 5d 4 6s 2To know more about noble gas configuration & Lewis dot diagram, click on the link below:
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Consider the reaction, 2 C3H8O(g) + 9 O2(g) → 6 CO2(g) + 8 H2O(g).
a. When 12 mol O2(g) react, how many moles of CO2(g) form?
When 12 moles of O₂ (g) react with C₃H₈O (g) then 8 moles of CO₂ (g) is produced. This is the chemical combustion reaction of propanol producing vapor of CO₂.
How to calculate the amount of CO₂ produced?Alcohols undergo combustion reaction in the presence of oxygen gas to produce vapor of CO₂ and water.
In the given equation,
2 C₃H₈O (g) + 9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)
To calculate the number of moles of CO₂ produced, first we have to balance the equation:
Divide the equation by 2
C₃H₈O (g) + 9/2 O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)
Calculate the number of moles of CO₂ (g) produced with 1 mol of O₂ (g)
9/2 O₂ (g) → 3 CO₂ (g)
1 O₂ (g) → 3÷9/2 CO₂ (g) = 0.66 mol CO₂ (g)
For 12 mol of O₂ (g),
12 × 0.66 = 8 mol CO₂ (g)
Therefore, 8 mol of CO₂ (g) is produced from 12 mol of O₂ (g).
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A farmer used too much pesticide (bug spray) and it washed down into the pond environment. What could happen to the Biotic AND Abiotic factors in the pond?
In a pond, the biotic factors include:
fishescrabssnailsplanktonalgaeThe abiotic factors are:
sunlighttemperaturerainfalldissolved mineralsWhat are the biotic and abiotic factors in a pond?Biotic factors are the living components of an environment whose activities affect the environment.
Biotic factors include plants, animals, bacteria, fungi, etc,
Abiotic factors are the non-living components of an environment that affect the environment.
Biotic and abiotic factors interact with each other.
In a pond, the biotic factors include:
fishescrabssnailsplanktonalgaeThe abiotic factors include:
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How do you compare the direction of the applied force and friction force
The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.
Applied force define as the force applied to by an object to other object.applied force is contact force or a non contact force.
Friction force is the force exerted by a surface that resist the motion of body or against motion of body.friction is contact force. When the applied force increases , the frictional force also increases. when the applied force is larger than friction force object will move.
Example , if we applied force to the right direction the friction force acts in left direction.that is opposite to applied force.
Therefore,The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.
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12. What structures does the fish have that are NOT present in the fly?
A 39.2 g sample of copper took
up the 4.4 cm3 of space.
What is the density of the
copper piece in g/cm3?
[?] g/cm³
A 39.2 g sample of copper took up the 4.4 cm³ of space , so the Density of the copper sample is 8.9 g/cm³.
What is density?Density is the ratio of the mass of a substance and the volume occupied by that substance. Density measures how tightly-packed the particles in a substance are the more tightly packed the particles are, the denser the substance will be.
The formula for calculating the density of a substance is given below as:
Density = mass/volume
Given :
The mass of the copper sample = 39.2 g
The volume of the copper sample = 4.4 cm³
Hence, the density of the copper sample will be:
The density of copper sample = 39.2 g/4.4 cm³
The density of copper sample =8.9 g/cm³
Therefore, the density of the copper sample is 8.9 g/cm³
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Answer: 8.9
Explanation: sample of 39.2 grams sample of copper took up to 4.4 centimeters of space. And then you will get the density of the copper piece in g/cm3.
PLEASE HELP
What is the frequency of a photon whose energy (E) is 7.48 x 10 -6 J?
Answer:
1.128*10¹⁹ [GHz].
Explanation:
1) the initial formula is
E=hν, where ν - required frequency,
2) according to the formula above
[tex]\nu=\frac{E}{h};\\ \nu=\frac{748*10^{-8}}{663*10^{-36}}=1.128*10^{28}[Hz][/tex]
what statement can be made about an electrically neutral atom’s number of protons and electrons?
How many moles of ammonia would be required to react exactly with
0.230 moles of copper(II) oxide in the following chemical reaction?
2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)
Answer: 0.1533 moles of NH3
Explanation: The reaction need 2 moles of ammonia and 3 moles of copper oxide to take place. If you have 0.230 moles of copper oxide you need:
0.230/3=0.0767*2=0.1533 moles of NH3
What are some of the ways that the features of carbon-to-carbon bonds influence the stability and 3-D structure of organic molecules?
Answer:
In order to draw the 3-D structure of an organic compound, we can use wedge-dash representation.
A biochemical engineer isolates a bacterial gene fragment and dissolves a 12.0−mg sample in enough water to make 30.0 mL of solution. The osmotic pressure of the solution is 0.340 torr at 25°C. (a) What is the molar mass of the gene fragment? g/mol (b) If the solution density is 0.997 g/mL, how large is the freezing point depression for this solution (Kf of water = 1.86°C/m)?
The molar mass of the gene is 2.22 * 10^4 g/mol and the freezing point depression is 3.35 * 10^-5 °C
What is the molar mass?We know that the osmotic pressure is obtained by the use of the formula';
π = iCRT
i = Van't Hof factor
C = concentration of the solution
R = gas constant
T = temperature
C = π/iRT
C = 0.340/1 * 62.4 * 298
C = 1.8 * 10^-5 M
Now;
n/M = C * V
12 * 10^-3/M = 1.8 * 10^-5 * 30 * 10^-3
M = 12 * 10^-3/1.8 * 10^-5 * 30 * 10^-3
M = 12 * 10^-3/ 5.4 * 10^-7
M = 2.22 * 10^4 g/mol
Mass of the solution is obtained from density * volume = 0.997 g/mL * 30.0 mL = 29.91 g
Molality of the solute = 12 * 10^-3g/ 2.22 * 10^4 g/mol * 1/ 29.91 * 10^-3
= 1.8 * 10^-5 m
ΔT = K m i
ΔT = 1.86°C/m * 1.8 * 10^-5 m * 1
ΔT = 3.35 * 10^-5 °C
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Arrange the following compounds in the order indicated below
and explain carefully the factors that lead to each other.
(a)
Increasing acid strength, CH,COOH, CH,CH.COOH,
CHFCOOHCH,CHCICOOH, CHCICH CH.COOH.
CHICCI,COOH, CH,CHCICOOH, CHCOOH,
(b) Decreasing base strength: NH,CH,, N(CH),.
(CH,)NH, CHÍNH
Any chemical compound that has carbon-hydrogen or carbon-carbon bonds is considered an organic substance in chemistry. Millions of organic compounds have been identified because of carbon's capacity for catenation.
Arrange the following compounds in the order indicated below
and explain carefully the factors that lead to each other.
The acid gets stronger the more EWG there is. Furthermore, the acid will be more potent if EWG is located closer to the source (COOH).
In sequence of increasing acidity:
(CH 3) 2CHCOOH < CH3CH2COOH < CH3COOH < ClCH2CH2COOH < ClCH2COOH
Similar to R groups, +I groups raise nitrogen's electron density, which raises an amine's basicity (an electron-rich substance is basic). The basic character of the supplied amines is influenced by the number of R groups on nitrogen. Basicity is also influenced by steric obstruction. Less basicity and more steric obstruction.
(CH3)2NH > CH3NH2 > (CH3 )3N > NH3
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Can the melting point of a substance be used as its fingerprint?
Answer:
Melting and boiling points are unique to the chemicals just like facial recognition. That does not necessarily means it is like a fingerprints.
Explanation:
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Which of the following measurements have four significant figures? Select all that apply. A.1,001g B.120.0mL C.0.0007cm D.5,000s
Answer:
The answer(s) will be A and B
Explanation:
Hope this helps and may God bless you<3
is a one time explanation of one observation a hypothesis and a scientific theory 100 points
One time explanation of one observation is a hypothesis.
Whenever, an assumption is made juts by observation and without proper testing then that is referred as an hypothesis.
For example- If my friend is late, so I might assume that he or she must have been stuck in traffic. So, this assumption is not tested yet and is made based on my observation. So, this is a hypothesis.
Whenever, a conclusion is given after several experiments and testing after observing something in science is referred as scientific theory.
For example- Atomic theory given by Dalton was based on several experiments. However, theories can also be proved wrong as Dalton's theory was proved wrong later on my JJ Thomson.
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Sodium bicarbonate (NaHCO3) is commonly known as baking soda. Sodium bicarbonate is a white solid that can dissolve in water. Under the proper conditions, sodium bicarbonate can release carbon dioxide (CO2) gas.
Select all of the physical properties of sodium bicarbonate
Sodium bicarbonate is a white crystalline powder. NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.
Sodium bicarbonate:
Sodium bicarbonate is a white crystalline compound. It is alkaline. Sodium bicarbonate is a compound made up of sodium, hydrogen, carbon, and oxygen.
Sodium bicarbonate can be used as an antacid. It can also be used in making ear drops. It is used in cleaning the mouth and teeth because of its antibacterial properties.
The chemical reaction when sodium bicarbonate reacts with tartaric acid is given below:
NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.
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HELP PLSSS
Oscar left a partially deflated balloon in his hot car for a couple of hours. When he returned the balloon seemed to be fully inflated. Somehow the volume of the balloon increased without anyone adding more air! Explain how this happened.
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
NiCl2 from the salt NiCl2. 6H2O
1. To prepare 0.5 M NiCl₂ solution, dissolve 64.8 g of NiCl₂ in 1 L of water
2. To prepare 0.5 M NiCl₂.6H₂O solution, dissolve 118.8 g of NiCl₂.6H₂O in 1 L of water
How to prepare solution1. How to prepare 0.5 M NiCl₂ solution
We'll begin by obtaining the mole of NiCl₂. This can be obatined as follow:
Volume = 1 LMolarity = 0.5 MMole of NiCl₂ =?Mole = Molarity x Volume
Mole of NiCl₂ = 0.5 × 1
Mole of NiCl₂ = 0.5 mole
Finally, can obtain the mass of NiCl₂ needed to prepare the solution as follow:
Mole of NiCl₂ = 0.5 moleMolar mass of NiCl₂ = 129.6 g/molMass of NiCl₂ =?Mass = mole × molar mass
Mass of NiCl₂ = 0.5 × 129.6
Mass of NiCl₂ = 64.8 g
Thus, to prepare 0.5 M NiCl₂, dissolve 64.8 g of NiCl₂ in 1 L of water
2. How to prepare 0.5 M NiCl₂.6H₂O solution
We'll begin by obtaining the mole of NiCl₂.6H₂O This can be obatined as follow:
Volume = 1 LMolarity = 0.5 MMole of NiCl₂.6H₂O =?Mole = Molarity x Volume
Mole of NiCl₂.6H₂O = 0.5 × 1
Mole of NiCl₂.6H₂O = 0.5 mole
Finally, can obtain the mass of NiCl₂.6H₂O needed to prepare the solution as follow:
Mole of NiCl₂.6H₂O = 0.5 moleMolar mass of NiCl₂.6H₂O = 237.6 g/molMass of NiCl₂.6H₂O =?Mass = mole × molar mass
Mass of NiCl₂ = 0.5 × 237.6
Mass of NiCl₂.6H₂O = 118.8 g
Thus, to prepare 0.5 M NiCl₂.6H₂O dissolve 118.8 g of NiCl₂.6H₂O in 1 L of water
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Between periods at a hockey game, a machine called an ice resurfacer is used
to smooth down the ice. Explain how this affects the speed of the players on
the ice and why it has that effect.
Forensic scientist Samantha Monzon is collecting physical evidence at a crime scene where someone was murdered. What does this process MOST likely involve?
A.
She will place all items in an airtight, plastic container.
B.
She will have to leave weapons such as guns and knives at the scene.
C.
She will need to obtain a search warrant before she collects anything.
D.
She will collect anything that could be related to the crime.
The process which most likely involves collecting physical evidence at a crime scene is she collecting anything that could be related to the crime and is denoted as option D.
What is Crime?This is referred to as unlawful behavior which is punishable by the law of an area or country and examples include theft, murder etc.
When crime takes place such as in the case of a murder, a professional who is referred to as a forensic scientist is invited to the scene so as to collect anything that could be related to the crime as this will help in the investigations by the appropriate bodies and ensure that justice is served.
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Answer: D. She will collect anything that could be related to the crime.
Explanation:
How many significant figures are in 0.20L
Determine the molar mass of C₂H₇N. Provide an answer to two decimal places.
carbon molar mass: 12.011 x 2
hydrogen molar mass: 1.008 x 7
nitrogen molar mass: 14.0067
- add all values together:
(12.011x2) + (1.008x7) +1 4.011 = 45.09 g
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Al3+, Br−, S2−
The required empirical formula
Zn2+ ---> ZnBr2Al3+ --->ZnSBr− ---->AlBr3S2− ----> Al2S3This is further explained below.
What is the empirical formula?Generally, The empirical formula of a chemical compound is the most straightforward representation of the atom counts in the molecule as whole numbers.
As a straightforward illustration of this idea, consider the empirical formula of sulfur monoxide, which is denoted by the symbol SO, and compare it to the empirical formula of disulfur dioxide, which is denoted by the symbol S2O2.
Zn2+ ---> ZnBr2Al3+ --->ZnSBr− ---->AlBr3S2− ----> Al2S3Read more about the empirical formula
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Aluminium having atomic mass 27 g mol crystallises in face centred pack
The number of unit cells in the given quantity is 2.23x10²³ unit cells
:Given Aluminum has an atomic mass of 27g mol-1
>Crystal is face-centered cubic structure
>number of aluminium atoms in l0 g mass
so w =10g
> the number of unit cells in the given quantity is to be calculated
Number of atoms of Al = (mass /molar mass ) x Nₐ
=(w/M)xNa , where Na =6.022x 10²³
There are 4 atoms present in the unit cell it will crystallize in a face-centered cubic crystal
.>.On solving the above values
we get the number of unit cells as= (10/27)x 6.022x10²³ unit cells
The number of unit cells in the given quantity is 2.23x10²³ unit cells
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the half life of throium is 18.72 days. how many days are required for 1000 gr to become 250 gr?