Answer:
Displacement is the vector difference between the ending and starting positions of an object. It may be very different from the distance the object has travelled along the way. Velocity is the rate at which displacement changes with time.
Explanation:
at a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.8 ∘∘ from the centerline
∅=2021rad is the phase difference (in radians) in the light from the two slits.
using the formula below
Φ =( [tex]2\pi d/[/tex]β )sinα
∅=2021rad
What is phase difference?The time difference between the same points within the two sounds' wave cycles (the peaks or positive-going zero crossings, for example), expressed as a fraction of one wave cycle, determines the phase difference between two sound waves of the same frequency travelling past a fixed spot.
Phase shift occurs when the sine and cosine function graphs are moved to the left or right of where they usually are, or we can say that the function is moved horizontally how far from its normal position. Functions are typically moved from their normal place.
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help! an asteroid is heading towards us at 15 km/s . scientists decide the best solution is to attach a rocket to the asteroid and fire it to change the trajectory of the asteroid. if the rocket is fired for 8 min, the scientists calculate that the new speed for the asteroid will be 21 km/s and its new trajectory will be at an angle of 33 ∘ to its original path.
The acceleration of the asteroid which is moving at a speed of 15km/s is [tex]a = (0.0058i + 0.023j)km/s^{2}[/tex].
What is trajectory ?A mass-moving object's route through space as a function of time is known as its trajectory or flight path. A full trajectory is defined by location and momentum at the same time in classical mechanics since a trajectory is determined by Hamiltonian mechanics using canonical coordinates.
[tex]v_{i} = 15km/s\\v_{f} = 21km/s(cos33i + sin33j)\\v_{f} = 21km/s(0.83i + 0.54j)\\t = 8 min = 480 s\\a = v_{f} - v_{i}/t\\a = 17.83i + 11.34j - 15i/480\\a = (0.0058i + 0.023j)km/s^{2}[/tex]
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Use the position-time graph below to answer the following questions.
What is the displacement of the object?
What is the distance travelled by the object?
Sketch the velocity-time graph that corresponds to this data.
Answer:49
Explanation:47484=4848489
Conversations with astronauts on the lunar surface were characterized by a kind of echo in which the earthbound person's voice was so loud in the astronaut's space helmet that it was picked up by the astronaut's microphone and transmitted back to Earth. It is reasonable to assume that the echo time equals the time necessary for the radio wave to travel from the Earth to the Moon and back (that is, neglecting any time delays in the electronic equipment). Calculate the distance from Earth to the Moon (in km) given that the echo time was 2.52 s and that radio waves travel at the speed of light (3.00 ✕ 10^8 m/s).
The correct answer is 378000 km.
The speed of light is the rate at which light waves move through distinct substances. In instance, it has now been established that the speed of light in a vacuum is 299,792,458 metres per second.
Using the equation
distance = speed × time,
the total distance travelled is calculated.
Consequently, the overall distance travelled is
Distance = ( 3.00 × 10^8 m/s ) ( 2.52 )
= 756000000 m
The total distance travelled divided by two determines the distance between the Earth and the Moon.
Distance between earth to moon = 756000000/2
= 378000000 meters
= 378000 km.
Approximately 384 thousand kilometres separate the Earth and the Moon.
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How does the kinetic energy of the car traveling 32 m/s compare to the energy released by burning a gallon of gasoline. That is, what is the ratio of the two?
The ratio of burning a gallon of gasoline to kinetic energy of the car is 1.27*102 :1
Burning a gallon of gasoline yields Egas = 1.3×108 J of energy.
A car's mass may vary in the range of 990 to 2000 kg.
Kinetic energy of a car is given as 1/2mv2
K.E = ½ m(32)2
K.E = ½*2000(32)2
K.E =1000 * 1024
K.E = 1.024 * 106 J
Comparing the Energy of gas to the kinetic energy of the car travelling at 32 m/s we have
Gas: Car = 1.3×108 J: 1.024 * 106 J
= (1.3 ×〖10〗^8)/(1.024×〖10〗^6 )
= 1.27*102 :1
Hence, the ratio of the energy of a burning gallon of gasoline to that of a car (assume weight is 2000 kg) moving at 32 m/s is 1.27*102 :1.
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a string or rope will break apart if it is placed under too much tensile stress. thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. one type of steel has density 7710 kg/m3 and will break if the tensile stress exceeds 7.0×108n/m2. you want to make a guitar string from a mass of 4.2 g of this type of steel. in use, the guitar string must be able to withstand a tension of 900 n without breaking. your job is the following.
The maximum length the string can have is 13.02 meter.
(a) Determine the maximum length the string can have
Answer:
As we know that density(p)= mass(m)/volume(V)
Solve for volume(V)= mass/density
If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg
And if density is in kg/m^3
Then volume will be V= 0.0037/7730 =>
4.79^10-7m^3
Now we know that stress = Force/Area
For Area = force/stress => 900/7*10^8=> 2795.95m^2
For length= volume/Area => 4.79^10-7/2795.95
Length= 13.02 m
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Which statements best describe the law of conservation of energy? Check all that apply.
The total amount of energy in the universe remains constant.
Energy can be created or destroyed.
Energy cannot be created or destroyed.
Energy can change from one type to another.
In a closed, isolated system, energy is conserved.
Answer:
the 2nd one and the 3rd one
Answer:
1,3,4,5
Explanation:
just got the answer correct on edge
A shuttle bus slows to a stop with an average acceleration of -1.8 m/s^2. How long does it take the bus to slow down from 9.0 m/s to 0.0 m/s?
Time taken to slow down the speed will be 5 seconds.
Average acceleration of the bus, a = 1.8 m/s²
Initial velocity of the bus, u = 9.0 m/s
Final velocity of the bus, v = 0 m/s
According to the First Equation of the motion which relates the acceleration, velocity and time we can say that
v = u + at
v - u = at
0 - 9 = (-1.8) * t
9 = 1.8 * t
t = [tex]\frac{9}{1.8}[/tex]
t = 5 s
Therefore 5 seconds will be required by the bus to slow down its speed from 9.0 m/s to 0.0 m/s
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A car starts with a velocity of 10 m/s. it
accelerates for 3 seconds at a rate of 2
m/s/s. what is its final velocity?
The final velocity would be 20m/s.
What is a final velocity?An object's final velocity is the speed at which it is moving after experiencing an acceleration over a period of time.The final step in calculating velocity is to multiply the initial velocity by the acceleration over time.The velocity at time t following the starting velocity is represented by the symbol v. Despite frequently being referred to as the last velocity, it is not the "last velocity" of an item.Distance and displacement are connected to speed and velocity in the same way. Velocity is a vector, whereas speed is a scalar. Speed is denoted by the letter v (italic), while velocity is denoted by the letter V. (boldface). A bar is added to the symbol over typical values.What is its final velocity?
Using the first equation of motion
V = U + at
where V = Final Velocity
U = Initial Velocity
a = Acceleration
t = Time
V = 10 + 1*10
V = 20 m/s.
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Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down the runway. A smaller plane with the same acceleration has a takeoff speed of 40 m/s . Starting from rest, after what distance will this smaller plane reach its takeoff speed?
Answer:600 m is required for smaller plane to reach its takeoff speed. ... So 300 m is required for smaller plane to reach its takeoff speed.
Explanation:
Answer:
300 m
Explanation:
Find acceleration of first plane
v = a t
80 = a (30) shows a = 2.67 m/s^2
For the smaller plane
v = at
40 = 2.67 t shows t = 14.98 seconds
d = 1/2 a t^2
= 1/2 2.67 (14.98^2) = 299.6 = ~ 300 meters
consider two protons initially at rest separated by a distance . the two protons are then moved towards each other until they are again at rest a distance apart.
Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.16 MeV.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.
In classical physics, an object of mass m moving at a speed of v has kinetic energy.
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Where in the hispanic world can you find a place that has coastlines on the same side of the country that are on both the pacific ocean and the caribbean sea?.
Answer: Panama
Explanation:
THE FIRST PERSON TO GIVE ANSWERS GETS BRAINLIEST
PLEASE HELP URGENT
Answer:
momentum = mass x velocity
1×50=50_
mu=mv
mu+mv=(m1+m2)v
50×1+20×0.5=v(1+0.5)
v=60÷1.5
v=40
are their final velocities necessarily equal? explain. yes, the final velocity is the instantaneous velocity at the moment a sprinter crosses the fini
The answer is statement 2 which states that only the average velocity must be same but not necessarily the instantaneous velocity.
The given situation is that two sprinters start the race on a straight track, in which they cross the finish line at the same time. So, they covered the same amount of distance at the same amount of time. This means that both their average velocity is equal, since it is independent of instantaneous velocity.One sprinter might start the race faster and finish at a slower speed whereas the other sprinter might start the race slower and finish the race at a faster speed. In this situation the final velocities are not equal.Instantaneous velocity is the velocity of an object at a specific time whereas average velocity is the average velocity of an object throughout the time.
The given question is incomplete. The complete question is:
Two sprinters start a race along a straight track at the same time and cross the finish line at the same time.
Are their final velocities necessarily equal? Explain.
1 ) Yes, the final velocity is the instantaneous velocity at the moment a sprinter crosses the finish line, which will be the same between two sprinters. The instantaneous velocities for the entire race must be the same.
2) No, the final velocity is just the instantaneous velocity at the moment a sprinter crosses the finish line, which can vary between two sprinters. Only the average velocity for the entire race must be the same.
Therefore, the correct answer is statement 2.
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What is the length of the x-component of the vector shown below?
34°
8
OA. 4.5
OB. 6.6
OC. 5.4
OD. 8
Answer: B
Explanation: I am 99% sure that is correct I remember doing something very simular
For each question, select the right answer from the choices below:
a Object A weighs 30 N on Earth. Object B weighs 30 N on the Moon (which
has a gravitational field strength 1/6 the size of Earth's). Which object has the greater mass?
i. A
ii. B
iii. neither of them
iv. depends on air resistance
Option (ii) B is the correct option. The object on the moon has greater mass.
To resolve this, utilize the formulas Force = Mass * Acceleration.
The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.
Calculating the mass on earth:
30 N = 9.8 m/s² * mass
This results in a mass of 3.0 kg for the object on Earth.
Calculating the mass of the moon:
30 N = 1.6 m/s²2 * mass
Thus, the moon's object has a mass of 19. kg.
This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).
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If we apply a potential difference of 4. 50 v between the ends of a wire that is 2. 50 m in length and 0. 654 mm in radius, the resulting current through the wire is 17. 6. What is the resistivity of the wire material?.
According to the resistance, the resistivity of wire material is 1.37 x 10¯⁷ Ωm.
We need to know about the resistance of conductive material to solve this problem. Resistance can be defined as the ratio of the voltage applied to current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
The resistance of the material depends on its resistivity and follows this equation
R = ρ . L / A
where ρ is resistivity, L is the length of the material and A is the surface.
From the question above, we know that
V = 4.5 V
L = 2.5 m
r = 0.654 mm = 6.54 x 10¯⁴ m
I = 17.6 A
Find the surface area
A = π . r²
A = π . ( 6.54 x 10¯⁴ )²
A = 1.34 x 10¯⁶ m²
Find the resistivity of the wire
R = V / I
ρ . 2.5 / (1.34 x 10¯⁶)= 4.5 / 17.6
ρ = 1.37 x 10¯⁷ Ωm
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1. With what force will a car hir a free if the car has a mass of 3,000 kg and accelerating at a rate of 2 m/st?
The force the car will use to hit the tree, given it has a mass of 3000 Kg and accelerating at 2 m/s² is 6000 N
How to determine the forceFrom the question given above, the filling data were obtained:
Mass (m) = 3000 KgAcceleration (a) = 2 m/s²Force (f) = ?Force is related to acceleration according to the following formula:
Force = mass × acceleration
Thus, we can obtain the force as illustrated below:
Force = mass × acceleration
Force = 3000 × 2
Force = 6000 N
From the calculation made above, we can conclude that the force the car will use to hit the tree is 6000 N
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problem 11.043 - uniformly accelerated motion of two particles - dependent multi-part problem - assign all parts skip to question note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. two automobiles a and b are approaching each other in adjacent highway lanes. at t
The vehicles pass each other after 20.7 seconds
We know that,
s = ut + 1 / 2 a[tex]t^{2}[/tex]
s = Displacement
u = Initial velocity
t = Time taken
a = Acceleration
Given that,
s = 3200 ft = 0.606 mi
[tex]u_{a}[/tex] = 68 mi / [tex]hr^{2}[/tex]
[tex]t_{a}[/tex] = 40 s = 40 / 3600 hr
[tex]u_{b}[/tex] = 37 mi / [tex]hr^{2}[/tex]
[tex]t_{b}[/tex] = 42 s = 42 / 3600 hr
s = [tex]u_{a}[/tex][tex]t_{a}[/tex] + 1 / 2 [tex]a_{a}[/tex][tex]t_{a} ^{2}[/tex]
0.606 = 68 ( 40 / 3600 ) + [tex]a_{a}[/tex] 0.5 ( 40 / 3600 [tex])^{2}[/tex]
[tex]a_{a}[/tex] = - 2422 mi / [tex]hr^{2}[/tex]
s = [tex]u_{b}[/tex][tex]t_{b}[/tex] + 1 / 2 [tex]a_{b}[/tex][tex]t_{b} ^{2}[/tex]
0.606 = 37 ( 42 / 3600 ) + [tex]a_{b}[/tex] 0.5 ( 42 / 3600 [tex])^{2}[/tex]
[tex]a_{b}[/tex] = 2561.63 mi / [tex]hr^{2}[/tex]
[tex]s_{a}[/tex] + [tex]s_{b}[/tex] = 0.606
68 t + 0.5 ( - 2422 ) [tex]t^{2}[/tex] + 37 t + 0.5 ( 2561.63 ) [tex]t^{2}[/tex] = 0.606
105 t + 1280.67 [tex]t^{2}[/tex] - 1211.4 [tex]t^{2}[/tex] - 0.606 = 0
t = 5.75 * [tex]10^{-3}[/tex] hr = 20.7 sec
The equations of motion are basically used to describe the motion of an object using position, velocity, acceleration and time.
Therefore, the vehicles pass each other after 20.7 seconds
The given question is incomplete. The compete question is :
Two automobiles A and B are approaching each other in adjacent highway lanes. At t- 0, A and B are 3200 ft apart, their speeds are VA 68 mi/h and VB 37 mi/h, and they are at points P and Q, respectively. A passes point Q 40 s after B was there and B passes point P42s after A was there. 3200 ft Problem 11.043.b - Uniformly accelerated motion of two particles Determine when the vehicles pass each other
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you leave the airport in college station and fly 26.0 km in a direction 34.0∘ south of east. you then fly 46.0 km due north. part a how far must you then fly to reach a private landing strip that is 32.0 km due west of the college station airport? express your answer with the appropriate units.
I must fly about 62.56 km in the Southwest direction to reach a private landing strip that is 32.0 km due west of the college station airport.
This can be understood through concept of Vectors. Vectors are defined as entity which has both direction and magnitude.
According to the question, 27 km in a direction 34.0° south of east hence angle is -34°.
Along x axis = 27cos (-34) ° and along y axis = 27sin (-34) °
Along x axis ≈ 22.4 km and along y axis ≈ -15.1 km.
Now, fly 46 km due north.
Along y axis=46, along x axis = 0
Next, along x axis ≈ 22.4 km, Along y axis ≈ -15.1 + 46 ≈ 30.9 km
Hence (22.4, 30.9)
Final Position is 32 km due west is that is ( -32, 0)
Distance between (22.4, 30.9) and ( -32, 0)
√ {(22.4 - (-32)) ² + (30.9 - 0) ²}
≈ 62.56 km Direction Southwest
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The net force on a moving object suddenly becomes zero and remains zero. The object will.
The net force on a moving object suddenly becomes zero and remains zero then the object will be in rest according to Newton's first law of motion.
The force on an object is equal to its mass times of its acceleration i.e.
F =ma
where , m is the mass , F is the force and a is the acceleration of the object. Its unit is Newton (N).
Newton's first law can be stated as , when an object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force. A reaction force is a force that acts in the opposite direction to an action force.
Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.
V = Δx/Δt
In here , V is velocity , Δx is change in displacement and Δt is change in time of an object.
In hence ,when the net force becomes zero F=0 the velocity of the object will be zero , then the object will remain at rest.
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A fellow student reports his measurements of time for a speed calculation in minutes. How could he express that calculation using SI
base units?
convert minutes to meters and redo his calculations
convert minutes to hours and redo his calculation
convert minutes to seconds and redo his calculation
Okeep his calculation as it is
Convert minutes to seconds and redo his calculation.
How do we measure time?The quick response. Atomic clocks are the most precise timekeeping devices we have for measuring the length of time between two events. Atoms in the clocks jump from one energy level to another as a result of the precise frequency at which these clocks emit electromagnetic radiation, such as microwaves.
Time is an illusion, says theoretical physicist Carlo Rovelli, because our simple perception of its flow doesn't match up with physical reality. In fact, much more, including Isaac Newton's depiction of a constantly ticking clock, is illusory, according to Rovelli's claim in The Order of Time.
How do you calculate hours and minutes?In an hour, there are 60 minutes. Divide the amount of minutes by 60 to convert it to hours. For instance, 120/60=2 means that 2 hours are equal to 120 minutes.
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Astronomers observe a typical star using a telescope and a spectrometer. they will see?
Astronomers observe a typical star using a telescope and a spectrometer, they will see an absorption spectrum and is therefore denoted as option B.
What is an Absorption spectrum?This is referred to as the percentage of incident radiation which have been absorbed by the material over a range of different frequencies.
Astronomers are referred to as scientists who are involved in the study planets and space with the use of instruments such as telescope and a spectrometer and they are most likely to see an absorption spectrum due to the different frequencies of light which are present in space.
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The options are:
an emission spectruman absorption spectruma continuous spectrummore than one of the above.which phrase best describes a chaparral
There are many different types of landforms in the chaparral biome, including rocky hills, level plains, and mountain slopes. Option C
What was the Chaparral Biome's temperature?The Chaparral biome often has very hot days and frigid to freezing nights. The summertime temperature range might be between 15 and 30 degrees.
Winter days are cooler, with temperatures ranging from 4° to 20°. The Chaparral biome has an average temperature of 18 degrees. The average yearly temperature is between -1° and 38° C (30° to 100° F).
Chaparral, or Mediterranean Forests and Shrubs, is a temperate biome distinguished by its hot, dry summers and mild, wet winters. Nearly the majority of the rainfall falls during the winter and spring rainy seasons.
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CQ
Which phrase best describes a chaparral?
O A. Is home to herds of giraffea, zebras, and wildebeests
O B. Receives less than 25 cm of precipitation per year
O C. Has low-growing, tough shrubs and rocky, dry soils
O D. Contains mostly needle-leaved evergreen trees
Answer:
here you go :)
ALL CREDIT TO THE OTHER PERSON!!
Explanation:
Two gases are contained in gas bulbs connected by a valve. Gas a is present in a 1 liter bulb at a pressure of 818 torr. Gas b exerts a pressure of 328 torr in a 1 liter bulb. The valve is opened and the two gases come to equilibrium. What is the partial pressure of gas a expressed after equilibrium?.
The partial pressure of gas expressed after equilibrium is 409 torr.
Which gas is used for bulbs?Incandescent light bulbs are usually filled with argon, which is a common gas. It prolongs bulb life by keeping the tungsten filaments from decaying too quickly. Lighting also makes use of other gases like helium, neon, nitrogen, and krypton.Incandescent lights are what gas lamps are. They generate heat by burning fuel like propane, white gas, or kerosene, and the heat drives light production from the mantles. The mantles, which are made of a ceramic mesh, contain the lantern's flame.The first kind of gas employed, argon, is a gas that is typically found in incandescent light bulbs. Nitrogen may occasionally be added to argon gas. Halogen or xenon gas can be found in some light bulbs. Some light bulbs also include krypton gas.What is the partial pressure of gas expressed after equilibrium:
1. Write out the units given.
V1= 1 L
Ptot= 818 torr
PPB= 328 torr
V2= 1L
2. Remember= PaVa= PtotVtot
3. Add together volumes for total volumes.
1 L + 1 L= 2 liters
4. Plug in values and solve for PP of gas A.
PPA= Ptot x VA/Vtot
818 torr x 1/2 L= 409 torr
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The force of gravity between two bodies is 6.68x10³ N.
The force of gravity between two bodies is 6.673 x 10-11 N m²/kg²
Greater gravitational forces will be used to attract heavier things since the force of gravity is directly related to the mass of both interacting components. Therefore, the gravitational pull between two objects grows as their respective masses do as well. The gravity force between two objects is equal to their respective masses multiplied by two. If one of the items triples in mass, the gravitational pull between them will also triple. The gravitational force between two objects is multiplied by two when their masses are each doubled, and so on. More distance will lead to decreased gravitational forces since the force of gravity is inversely related to the square of the difference between two interacting objects. Therefore, the gravitational pull between two things weakens as they go farther apart.
So any two items will be attracted to one another by a gravitational force of 6.673 x 10-11 N m² / kg²
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An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength, but would differ based on what physical property of light?.
An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength but would differ due to the amplitude property of light.
It is the amplitude of light which makes one sample brighter than other.
The amplitude plays an important part in differentiating the same colors of the same wavelength. It tells us about the brightness or intensity of a certain light wave as compared to others of the same wavelength. So, whenever two same colors look different due to brightness, it is due to the amplitude property of the light.
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If you run 12 km at an average speed of 4 km/h, how much time does it take? ___ hours
a simple formula for the distance traveled (x in meters) by an air car traveling a track uses the initial starting point (x0 in meters), the initial velocity (v0 in units meters per second), and the acceleration (a in units meters per second squared), and the time traveled (t in seconds).
The simple formula for the distance travelled ( in m ) by the air car is s = [tex]V_{0}[/tex] t + 1 / 2 at² which is an equation of motion.
According to equations of motion,
s = ut + 1 /2 at²
where,
s = Distance travelled
u = Initial velocity
t = Time travelled
a = Acceleration
Given that,
u = [tex]V_{0}[/tex]
s = [tex]V_{0}[/tex] t + 1 / 2 at²
Equations of motion are used to describe position of an object as a function of time. It is done using acceleration, velocity, distance and time.
Therefore, the simple formula for the distance travelled is s = [tex]V_{0}[/tex] t + 1 / 2 at²
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Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called ______that line the walls of your lungs.
Popliteal
Arterial
Alveoli
Capillaries
Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called alveoli that line the walls of your lungs.
Lungs :Your lungs contain tiny, balloon-shaped air sacs called alveoli. Moving oxygen and carbon dioxide (CO2) molecules into and out of your bloodstream is what the alveoli are there for. Alveoli are a crucial component of your respiratory system, which includes the body parts that aid in breathing.
What lines walls of alveoli?An alveolus is made up of an extracellular matrix encircled by capillaries, a layer of simple squamous epithelium (extremely thin, flattened cells), and an epithelial layer. The alveolar membrane, also known as the respiratory membrane, which permits the exchange of gases, includes the epithelial lining.
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