The distance the red ball travelled between 12 s and 24 s is 2116.8 m
What is free fall?Free fall is motion under gravity.
What is the distance traveled by the red ball between 12s and 24If we assume the red ball is falling freely, it has an initial velocity of zero.
Using the equation of motion s = ut - 1/2gt², we find the distance it travels or height it drops after the given time. where
u = initial velocity = 0 m/s, t = time and g = accleration due to gravity = 9.8 m/s²So, s = ut - 1/2gt²
s = 0 × t - 1/2gt²
s = -1/2gt²
Distance the red ball fall in 12 s.Since the distance the red ball falls is s = -1/2gt² with t = 12 s, we have
s = -1/2gt²
= -1/2 × 9.8 m/s² × (12 s)²
= -1/2 × 9.8 m/s² × 144 s²
= -4.9 m/s² × 144 s²
= -705.6 m
Distance the red ball fall in 24 s.Since the distance the red ball falls is s = -1/2gt² with t = 24 s, we have
s' = -1/2gt²
= -1/2 × 9.8 m/s² × (24 s)²
= -1/2 × 9.8 m/s² × 576 s²
= -4.9 m/s² × 576 s²
= -2822.4 m
So, the distance the red ball travelled between 12 s and 24 s is d = s' - s
= -2822.4 m - (-705.6 m)
= -2822.4 m + 705.6 m
= -2116.8 m
So, the distance the red ball travelled between 12 s and 24 s is 2116.8 m
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which areas in the atmosphere could have the lowest concentration of water vapor
Answer:
Thermosphere. Located between about 80 and 700 kilometers (50 and 440 miles) above Earth's surface is the thermosphere, whose lowest part contains the ionosphere. In this layer, temperatures increase with altitude due to the very low density of molecules found here. It is both cloud- and water vapor-free
Explanation:
i might be wrong
a daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. (don't try this at home.) the speed of the horse is 9.28 m/s and the vertical distance from the limb to the saddle is 3.00 m.
Using time and velocity relationship, we concluded that he horse will be in air for 0.80 seconds.
What is the relationship between time and velocity?velocity-time. In evenly accelerated, straight-line motion, the relationship between velocity and time is straightforward. The magnitude of the velocity change increases with lengthier acceleration. When acceleration is constant, the change in velocity is exactly proportional to time.
Both the horse and the human have constant accelerations, which are 0 for the horse and g downward for the human.
(A) Take into account the man's vertical motion after he leaves the limb (with v₀ = 0, yi = 3m).
Finding the man's time of fall from y = y₀ + vt + 1/2 a t² requires modeling him as a particle with continuous acceleration.
when v₀ = 0
t = √(2(y - y₀)/a)
= √ (2(0 - 3) / -9.28)
= √0.64
= 0.80s
Complete Question -
A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0m/s, and the distance from the limb to the level of the saddle is 3.00m. (a) For what time interval is he in the air?
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a golfer wants a new set of clubs to improve her game. in an experiment, she goes to the driving range and compares the distance she hits a bucket of golf balls with drivers of different materials in the head before making her purchase decision. in this simple experiment, the independent variable is the group of answer choices swing speed of the golf club prior to striking the golf ball. wind direction when the experiment took place. type of material used to make the club head. distance the golf ball traveled. type of material used to make the golf ball.
In this simple experiment, the independent variable is the type of material used to make the club head.
What is a club head?In golf, the bottom of the club is called the club head, or simply the head.
It is the portion of the golf club intended to strike the ball.
Clubheads are also found on putters, irons, hybrids, woods, and drivers.
Many male amateur golfers play the game at clubhead speeds of 80 to 90 mph.
The fastest LPGA pros average 90 to 100 mph. Golfers on the tour typically swing the club at rates of 110 to 115 mph or even more, while long-drive competitors can reach 140 mph.
In golf, torso rotation and wrist position at impact are the best ways to manage clubface angles.
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which of the following best represents r = a - b
Option A from the following options represents the resultant vector r = a-b, therefore the correct answer is option A.
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out which of the following vector best represents r = a - b,
As per the triangle law of the vector addition, the resultant sum is represented by the closing side of the triangle in regular order.
Thus, the correct answer is option A.
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Which event occurs when an atom undergoes nuclear fusion?
OA. Its nucleus loses all its mass.
OB. Its nucleus combines with another nucleus.
C. Its nucleus breaks apart.
OD. Its nucleus absorbs energy.
Answer:According to the context, its nucleus breaks apart is an event that occurs when an atom undergoes nuclear fission.
Explanation:
experimenter a uses a test charge q0 and experimenter b uses a test charge 2q0 to measure an electric field produced by stationary charges. a finds a field that is:
A finds a field that is the same as the field found by B.
How to find the electric field?The physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field is known as an electric field (or E-field). Additionally, it describes the physical environment of a system of charged particles.
No matter how large the test charge is, stationary charges always produce the same electric field at a certain area.
At a distance "r" from it, the electric field created by a stationary charge "q" is given as
[tex]E = K_{q} /r^{2}[/tex]
Thus, the appropriate option is e) the same as the field found by B.
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As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.
As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).
What Is Gravity?Greatness is the estimation or supreme esteem of an amount. A size is spoken to by a positive, genuine number.Some illustrations of the drive of gravity incorporate: The drive that holds the gasses within the sun. The drive that causes a ball you toss within the discuss to come down once more. The drive causes a car to coast downhill once you aren't venturing on the gas. The drive that causes a glass you drop to drop to the floor.Forces are the way that vitality is exchanged from one protest to another when they connected, but powers are not the vitality itself. Gravity may be a constrain, so it fair gives one way for objects to trade and change vitality to diverse states.As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).
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the average weight of an elephant is 4000N the surface area of thr sole of its foot is 0.1m^2 calculate the pressure by one foot of an elephant
Answer
Explanation:pressure = Force/area
Force = 4000N
Area=0.1m
pressure = 4000/0.1
=40000P.a
A stone is thrown vertically downward from a cliff 208.0-m tall. during the last half second of its flight, the stone travels a distance of 48.5 m. find the initial speed of the stone.
A stone is thrown vertically downward from a cliff, the initial speed of the stone is 76.246m/s.
CalculationHeight of the cliff = 208m
Distance travelled during last half second = 48.5 m
According to the second equation of motion:
[tex]s1= vt + 1/2 gt^{2}[/tex]
[tex]v= (2x_{1} - gt^{2})/2t[/tex]
v= [tex]\frac{2(48.5) - (9.8)(0.5)^{2} }{2(0.5)}[/tex]
v= 94.55 m/s
If the initial speed of the ball is u,
then again from the equation of motion, we get initial speed as
u=[tex]\sqrt{v^2 - 2gh}[/tex]
=[tex]\sqrt{94.55^2 -2(9.8)(208-48.5)}[/tex]
u= 76.246 m/s
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a ball is kicked at an angle of 33 degrees relative to horizontal with a velocity of 70m/s. how much of this velocity is in the vertical direction? group of answer choices
velocity is in the vertical direction is 38.124m/s
Projectile motion may be defined as a particle moves along the curved pat with the constant acceleration when through near the earth surface.
It is a parabolic because it is affected by gravity.
along x axis velocity responsible for horizontal motion
along y axis velocity responsible for vertical motion
path followed by a projectile is known as a trajectory.
a ball is kicked at an angle of degrees = 33 degree
velocity of ball, v= 70m/s
v has two components one in horizontal and in one vertical.
velocity is in the vertical direction is given by
[tex]v_{x} = v sin\theta[/tex]
[tex]v_{x} = 70 sin(33)[/tex]
[tex]v_{x} = 38.124[/tex]m/s
velocity is in the vertical direction is 38.124m/s
The given question is incomplete. The complete que is
a ball is kicked at an angle of 33 degrees relative to horizontal with a velocity of 70m/s. how much of this velocity is in the vertical direction? group of answer choices
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What causes the curved, upper surface of water that commonly appears when using a graduated cylinder?
The stronger force of attraction between the molecule of the material and the walls of container caused the upper surface to be curved and the curved surface is known as Concave meniscus.
When the molecules of the solution or nay solvent attached to the walls of the container due to stronger attraction with the walls, it create a concave surface at the top, which is known as Meniscus and principle behind Meniscus is surface tension.
In contrast, a convex meniscus develops when the liquid’s dissolved particles are more attracted to one another than to the substance of the container, for example in barometers.
When the surface of a liquid, like as water, comes into contact with another phase (a solid, liquid, or gas), a phenomenon known as surface tension takes place, which resist the external force acting on it.
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In a competition, an athlete threw a flying disk 137.4 meters through the air. while in flight, the disk traveled at an average speed of 10.9 m/s. how long did the disk remain in the air?
The answer is 12.6 seconds.
What is the average speed?The distance traveled is divided by the time interval to determine average speed.For instance, someone traveling at an average speed of 40 miles divided by 40 minutes, or 1 mile per minute, is traveling 20 miles north and then 20 miles south (60 mph).Distance is divided by time to obtain average speed, expressed in miles per hour. Okay, let's speak about average speed. Instantaneous speed refers to the distance you are traveling at a given moment. The total distance you will go over a period of time at an average speed of 100 kilometers per hour is thus.How long did the disk remain in the air:
Given data:
d= 137.4 meters
v=10.9 m/s
v=d/t
t=d/v
t=137.4/10.9
t=12.6 seconds.
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Help me with this high school physics question!
Answer:
[tex]6.373219 \times 10^6 \; meters[/tex]
or
[tex]\rm 6.373 \times 10^6 \; meters\; or\;3 \;significant \;decimal \;digits[/tex]
Explanation:
The gravitational force can be calculated with the formula:
[tex]\boxed {F_g=\dfrac{GMm}{R^2}}[/tex]
where
[tex]\rm F_g = gravitational \; force\\G = gravitational constant\\M = mass\;of\;earth\\m = mass\; of\; the \; person\\[/tex]
[tex]\rm R\;=\;distance\;from\;center\;of\;earth\;to\;surface[/tex]
Multiplying both sides of the above equation by R and dividing both sides by [tex]\rm F_g[/tex] gives us a R² in terms of the others
==> [tex]\rm R^2 = \dfrac{GMm}{F_g}[/tex] (1)
Given
[tex]F_g = 1030 N, M = 5.97\times 10^24\;kg\; \;and \;m = 105kg\\\\[/tex]
and knowing that [tex]\rm G = 6.67 \times 10^{-11} \; Nm^2/kg^2[/tex]
substitute these values to get
[tex]\rm R^2 =\dfrac{(6.67 \times 10^{-11})(5.97 \times 10^{24})(105)}{1030}[/tex]
[tex]\rm 4.05931 \times 10^{13} = 40.5931 \times 10^{10}\\\\R = \sqrt{40.5931 x 10^{12}} \\\\= 6.373219 \times 10^6 \; meters\\\\[/tex]
What is the equation describing the voltage across the capacitor, vc, as the capacitor is discharging in terms of the peak voltage v0 and the time constant of the circuit τ?.
Vc=Vo * e^(-t/τ) is the equation describing the voltage across the capacitor, vc, as the capacitor is discharging in terms of the peak voltage v0 and the time constant of the circuit τ.
As we all know, a capacitor is a device that stores electrical energy in an electric field. It is composed of two conducting plates separated by an insulating material called a dielectric. When a voltage is applied to the plates, an electric field is created across the dielectric, and this field stores energy.
The voltage across a capacitor, as it is discharged, follows the equation vc=vo*e^(-t/τ). This equation describes the voltage across the capacitor, vc, in terms of the peak voltage v0 and the time constant of the circuit τ. The time constant is simply the time it takes for the voltage across the capacitor to decay to 1/e of its initial value.
So what does this all mean? Basically, the voltage across a capacitor will decay exponentially over time, and the time constant of the circuit will determine how quickly this decay occurs.
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A load weighing 0.3 kg was suspended on the left edge of a homogeneous beam weighing 0.4 kg. At what distance from the left edge it is necessary to establish a fulcrum so that the lever is in balance, if the length of the beam is 70cm,
The "arm" of the lever is the handle or bar; it is the portion that you push or pull against. The point on which the lever rotates or balances is known as the "fulcrum.
What is a fulcrum and Lever?The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.
Torque is essential to the operation of levers. The point on which the lever rotates or balances is known as the "fulcrum. Your hand's fingers serve as the fulcrum when using a fork. A lever's pivot point serves as an illustration of a fulcrum.To learn more about fulcrum refer to:
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As the pressure of an enclosed gas decreases to half its original value, what happens to the volume of the gas if temperature is held constant?
a. the volume decreases to one-fourth of its original value.
b. the volume increases to four times its original value.
c. the volume decreases to half of its original value.
d. the volume increases to twice its original value.
The new volume of the gas will increase to twice the original volume (Option D)
Data obatined from the questionFrom the question given above, the following data were obtained:
Initial volume (V₁) = V Temperature = constant Initial pressure (P₁) = PNew pressure (P₂) = 1/2P = 0.5PNew volume (V₂) =? How to determine the new volumeThe new volume of the gas can be obtained as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
Since the temperature is constant, we have:
P₁V₁ = P₂V₂
P × V = 0.5P × V₂
Divide both side by 0.5P
V₂ = (P × V) / 0.5P
V₂ = V / 0.5
V₂ = 2V
Thus, the new volume of the gas will increase to twice the original volume (Option D)
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Which of the following is a liquid?
OA. Steak
OB. Sugar
OC. Juice
OD. Smoke
Answer: Juice
Explanation:
A vector with a magnitude of 22 m points due north. A second vector has a magnitude of 12 m, and points due south. What is the magnitude of the resultant?
you are on an airplane traveling 30° south of due west at 120 m/s with respect to the air. the air is moving with a speed 47 m/s with respect to the ground due north. 1)what is the speed of the plane with respect to the ground?
Answer:
Vp = 120 cos 210 + 120 sin 210 = Vi1 + Vy1 due East zero coordinates
Vp = -103.9 i - 60 j vector description of velocity of plane
Vw = 47 j vector description of wind
V = Vp + Vw = -103.9 i - 13 j
V = (103.9^2 + 13^2)^1/2 = 104.7
Cos θ = -103.9 / 104.7 = 187.1 deg X-component of final velocity
Sin θ = -13 / 104.7 = 187.13 deg Y-component of final velocity
(Final velocity = 104.7 m/s 7.1 deg S of W)
Change 1m² into cm², mm² and km²
1m² = 10000cm²
1m² = 1000000mm²
1m² = 1e-6km²
which is larger
a, same size
b, 2 ft
c, 2 m
for anyone who wants points answer this :)
An object is dropped from a 32 m tall building. How fast will it be going when it strikes
the ground?
Answer: 25.04m/s
Explanation:
v^2 = v^2o + 2a(x-xo)
v^2 = velocity
v^2o = initial velocity
a = acceleration
x = final position/distance
xo = initial position/distance
In this case, the initial velocity is 0 since the ball wasn't moving before it was dropped. The final position is 32 as the motion ended after the ball traveled 32m. The initial position is 0. The acceleration is 9.8m/s (free fall). Plug these numbers into the formula:
v^2 = 0 + 2(9.8)(32)
v^2 = 25.04396135
Round to get 25.04m/s
A horse can run at a speed of 12 m/s. At this rate, how long will it take for it to travel 52 m? (Express your answer in sec, rounded to one decimal place.)
A horse that can run at a speed of 12 m/s will travel a distance of 52 m in a period of 4.33 seconds
We know that,
v = d / t
where,
v = Velocity
d = Distance
t = Time
Given that,
v = 12 m / s
d = 52 m
t = d / v
t = 52 / 12
t = 4.33 s
Velocity is the displacement of an object in a given amount of time. It is denoted by V.
Therefore, the time taken by the horse is 4.33 seconds
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You drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles.
the average speed?
The average speed for the two events is 25.2 m/s
What is Average Speed ?Average speed is the ratio of the total distance travelled by a body to the total time. It is measured in m/s
If you drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles. To calculate the average speed, first convert the mile to meter
1 mile = 1609.34 m
10 miles = 10 × 1609.34 = 16093.4 m
Calculate the time for each event.
speed = distance / time
time = distance / speed
T1 = 16093.4 / 20
T1 = 804.67 s
T2 = 16093.4 / 34
T2 = 473.34 s
Total time t = T1 + T2
t = 804.67 + 473.34
t = 1278.01 s
Total distance s = 16093.4 + 16093.4
s = 32186.8 m
Average speed = s / t
Average speed = 32186.8 / 1278.01
Average speed = 25.19 m/s
Therefore, the average speed for the two events is 25.2 m/s approximately.
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A simple pendulum has time period of 2s. It is called second pendulum. Fimd the length of second pendulum on earth and moon(gm=g/6)
The length of the second pendulum on earth is 1m and on the moon 1/6m.
Given:
The time period of a second pendulum T = 2s
By using the formula T = 2π √l/g we can calculate the length of the pendulum on earth and the moon.
Here g = acceleration due to gravity and
l = the length of the pendulum.
Now
l = g(T/ 2π)^2
l = 9.8 m/s^2(2s / 2 x 3.14)^2
le = 1 m
Now calculate the length of the pendulum on the moon
T = 2π √lm/gm ∴ gm = ge/6
Now putting the value of g we get.
or 2 = 2 π √lm / ge/6
2 = 2 π √6lm / π ^2le
lm = le/6
now given le = 1m
lm = 1/6 m
Thus the length of the second pendulum on earth is 1m and on the moon 1/6m.
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A cannon ball is shot horizontally off a 86.5 m hill with an initial horizontal velocity of 105 m/s. What horizontal distance will the cannon ball travel?
Answer:
H = 86.5 m = 1/2 g t^2 to get time for cannon ball to fall 86.5 m
t = (2 * 86.5 / 9.8)^1/2 = 4.20 sec
S = Vx t = 105 m/s * 4.2 s = 441 m horizontal distance
the football team at enormous state university (esu) uses vector displacements to record its plays, with the origin taken to be the position of the ball before the play starts. in a certain pass play, the receiver starts at 1.0i^−5.0j^, where the units are yards, i^ is to the right, and j^ is downfield. subsequent displacements of the receiver are 7.0i^ (he is in motion before the snap), 8.0j^ (breaks downfield), −7.0i^ 3.0j^ (zigs), and 11.0i^ 12.0j^ (zags). meanwhile, the quarterback has dropped straight back to a position −7.0j^.
We shall use the ideas connected to the vector sum to develop this issue. To achieve this, we will add the person's displacement vectors to determine the total distance he has gone from the initial point (0 position) to the destination position.
Then quarterback will throw the ball 44.4 yards in a particular direction with the angle of 54.16 °
t = 25.1seconds.
X(t)= 16cos75°t
Y(t)= 6 + (Vosin75°t - 16t^2)
Converting 78 yards to feet :
1 yard = 3 feet
78feet =?
78×3=234 feet
Y(t)= number of feet above the ground at t seconds
VoCos75° t = 234
t = 234/(VoCos75°)
At this time,4 = y(234/VoCos75°)
4 = 6 + VoSin75°(234/VoCos75) - 16(234/VoCos75°)^2
Vo= 140.66ft/s
Time,t= 234/(140.66× Cos75°)
t = 25.087seconds
t= 25.1 seconds (1 decimal place)
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Which of these coloured stars has the highest surface temperature?
A orange
B red
C white
D yellow
How many valence electrons does the ground-state electron configuration of nitrogen have?.
The last shell of nitrogen has five electrons, according to the nitrogen's electron arrangement. Therefore, nitrogen has five valence electrons.
What are valence electrons?The valence shell is the final shell to be formed after the configuration of the electrons.
A valence electron is any electron that is present in a valence shell as a whole.
Eg: Since nitrogen has a 7-atomic structure, the atom will contain seven electrons.
Nitrogen's ground state electrical arrangement will be 1s22s22p3.
It has 5 valence electrons.
The number of valence electrons for neutral atoms is the same as its main group number.
An element's column on the periodic table can be used to determine its major group number.
Carbon, for instance, belongs to group 4 and has four valence electrons. With 6 valence electrons, oxygen belongs to group 6.
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consider a uniformly charged ring in the xy plane, centered at the origin. the ring has radius aaa and positive charge qqq distributed evenly along its circumference.
The electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]
The radius of the ring is: [tex]a[/tex]
The charge on the ring is: [tex]q[/tex]
The coulomb's constant is: [tex]k = \frac{1}{{4\pi {\varepsilon _0}}}[/tex]
The expression of the electric field is: [tex]E = \frac{{kq}}{{{r^2}}}[/tex] .......(i)
Here,
[tex]r[/tex] ⇒ distance = [tex]\sqrt {{z^2} + {a^2}}[/tex]
Now, putting [tex]r[/tex] in equation (i), we get,
[tex]\begin{array}{c}\\E = \frac{{kq}}{{{{\left( {\sqrt {{z^2} + {a^2}} } \right)}^2}}}\\\\ = \frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}\\\end{array}[/tex]
The electric field along the z-direction is
[tex]dE\left( z \right) = dE\cos \theta[/tex] ........(ii)
here, [tex]\cos \theta = \frac{z}{{\sqrt {{z^2} + {a^2}} }}[/tex]
Integrating equation (ii), we get,
[tex]\begin{array}{c}\\\int {d{E_z}} = \int {dE\cos \theta } \\\\E\left( z \right) = E\cos \theta \\\end{array}[/tex].......(iii)
Now substituting the values in equation (iii), we get,
[tex]\begin{array}{c}\\E\left( z \right) = \left( {\frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}} \right)\left( {\frac{z}{{\left( {\sqrt {{z^2} + {a^2}} } \right)}}} \right)\\\\ = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}\\\end{array}[/tex]
Therefore, the electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]
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Consider a uniformly charged ring in the [tex]xy[/tex] plane, centered at the origin. The ring has radius [tex]a[/tex] and positive charge [tex]q[/tex] distributed evenly along its circumference. What is the magnitude of the electric field along the positive [tex]z[/tex] axis? Use k in your answer, where [tex]k = \frac{1}{4 \pi \epsilon_0}[/tex]