What is the mode of the data set?
8 5 3 9 12 9 2 3 6 11

Answer:43.1 km/h

Step-by-step explanation:

Suppose velocity of motorist [tex]\vec{v_1}=50\hat{j}[/tex]

The appeared velocity of wind or resultant velocity is [tex]\vec{v_r}=60[\hat{i}\cdot \frac{1}{\sqrt{2}}+\hat{j}\cdot \frac{1}{\sqrt{2}}][/tex]

Suppose the true velocity of wind is [tex]v_2[/tex]

so, [tex]\vec{v_1}+\vec{v_2}=\vec{v_r}[/tex]

[tex]\vec{v_2}=\frac{60}{\sqrt{2}}\hat{i}+(\frac{60}{\sqrt{2}}-50)\hat{j}\\\vec{v_2}=42.42\hat{i}-7.57\hat{j}\\absolute\ velocity=\sqrt{42.42^2+(-7.57)2}=43.09\approx 43.1\ km/h[/tex]

if you  would've payed attention you wouldn't ask brainly-

Step-by-step explanation:

ans:7*(-(3-5))..........

Answer: 108 tickets must be sold to cover the cost.

123 tickets must be sold to make a profit of approximately $980.68

Step-by-step explanation:

Just divide 859.32 from 8 to find out how many tickets must be sold to cover the cost. Same for part b.

Hope this helps!

a. It takes 108 tickets to cover the cost.

b. It takes 230 tickets to make a $980.68 profit.

Hope that helps! I did the questions AND calculated to see if they were correct. (They are correct lol)

Answer:

false

Step-by-step explanation:

Answer:

63 gallons

Step-by-step explanation:

3 gallons = 4x 3 = 12 quarts

12+2 = 14

14 x 18 = 252 quarts

252 / 4 = 63 gallons

9514 1404 393

Answer:

  5°

Step-by-step explanation:

The angle for 12 inches of ramp length and the angle for 12 inches of run are very similar. Both are near 4.8°, so are 5° when rounded.

If we say 12 inches of run, then the tangent relation applies.

  Tan = Opposite/Adjacent

  tan(α) = (1 in)/(12 in)

  α = arctan(1/12) ≈ 4.764°

The maximum angle is about 5°.

Answer:

y= -2x + 9

Step-by-step explanation:

I got 2x because you use rise over run. As you can see in the image, the slope goes up two and to the left one ( 2x). It's plus 9 because that where it intersects the 9 on the y-intercept. The slope is negative because the line is going down from left to right ( always read it from left to right).

I hope this helps. I'm not that great at explaining so....:)

Answer:

2x+y-9=0

Step-by-step explanation:

let's take two co ordinates

(X1,y1)=(4,1)

(X2,y2)=(3,3)

Equation using two point :

(y-y1)/(y2-y1)=(x-x1)/(x2-x1)

plug in the values,(y-1)/(3-1)=(x-4)/(3-4)

(y-1)/2=(x-4)/-1

-1*(y-1)=(x-4)*2

-y+1=2x-8

0=2x+y-9

2x+y-9=0

Answer:

The answer is 2

Step-by-step explanation:

Addition is considered first before subtraction

So 4+(-2) and -3+3 are considered separately and later their results are added

(2+0=2)

Answer: Charles

Step-by-step explanation:

Michael made 19 out of 30 free-throws. This gives 19/30 = 0.63

Larry's free throw average was 0.745.

Charles' was 0.81.

John made 47 out of 86 free-throws. This gives 47/86 = 0.55

The best free-throw shooter was Charles

Answer:

Charles

Step-by-step explanation:

The best free-throw shooter was Charles

Answer:

x = 13

Step-by-step explanation:

m∠ABC + m∠CBD = 180°       {linear pair}

3x + 43 + 6x +  20 = 180

3x + 6x + 43 + 20 = 180

    9x  + 63           = 180

                     9x = 180 - 63

                    9x = 117

                     x = 117/9

x = 13

Answer:

Its either C or D but i think its D

Step-by-step explanation:

Answer:

X=-2

Step-by-step explanation:

x-5=-7

x-5+5=-7+5

X=-2

Answer:  x = 2/3y + 4

Hope it helped u,

pls mark as the brainliest

^v^

Answer:

The percentage increase equation is:

Percentage Increase = [ (Final Value - Starting Value) / |Starting Value| ] × 100

The percentage increase = 11.97%

Step-by-step explanation:

Given

Starting Value  = 376

Final Value = 421

To determine

Percentage Increase =?

The percentage increase equation:

Percentage Increase = [ (Final Value - Starting Value) / |Starting Value| ] × 100

                                  = [(421 - 376) / (376)] × 100

                                  = [45 / 376] × 100

                                  = 11.97%

Therefore, the percentage increase = 11.97%

Answer:

3700 kings

Step-by-step explanation:

Answer:

1) m ∠B = 132°

2) m ∠B = 113°

Step-by-step explanation:

1. In triangle ABC, m ∠A=36, and m ∠C=12. Calculate m ∠B.

We are given measure of 2 angles and we need to find the third angle.

We know that, sum of angles of triangle = 180°

We can write as:

∠A + ∠B + ∠C = 180°

Now put m ∠A=36 and m ∠C=12, to find m ∠B

[tex]\angle A + \angle B + \angle C = 180\\36+ \angle B +12=180\\\angle B+48=180\\\angle B=180-48\\\angle B=132[/tex]

So, we get m ∠B = 132°

2. In triangle ABC, m ∠A=40, and m ∠C=27. Calculate m ∠B.

We are given measure of 2 angles and we need to find the third angle.

We know that, sum of angles of triangle = 180°

We can write as:

∠A + ∠B + ∠C = 180°

Now put m ∠A=40 and m ∠C=27, to find m ∠B

[tex]\angle A + \angle B + \angle C = 180\\40+ \angle B +27=180\\\angle B+67=180\\\angle B=180-67\\\angle B=113[/tex]

So, we get m ∠B = 113°

Answer:

y=4

Step-by-step explanation:

Step-by-step explanation: Input is the same as the x term.

If the input is -2, we substitute a -2 in for x.

So we have y = 2(-2) + 8 or y = -4 + 8 which is 4.

So the output or the y term is 4.

9514 1404 393

Answer:

Step-by-step explanation:

The GCF of the two terms is the second term: 6k^2. When that is factored out, you have ...

  area = (6k^2)(5k +1)

According to the problem statement, this is interpreted as ...

  width: 6k^2

  length: 5k+1

Answer:

Step-by-step explanation:

92

Answer:

The maximum acceleration over that interval is [tex]A(6) = 28[/tex].

Step-by-step explanation:

The acceleration of this car is modelled as a function of the variable [tex]t[/tex].

Notice that the interval of interest [tex]0 \le t \le 6[/tex] is closed on both ends. In other words, this interval includes both endpoints: [tex]t = 0[/tex] and [tex]t= 6[/tex]. Over this interval, the value of [tex]A(t)[/tex] might be maximized when [tex]t[/tex] is at the following:

Start by calculating the value of [tex]A(t)[/tex] at the two endpoints:

Apply the power rule to find the first and second derivatives of [tex]A(t)[/tex]:

[tex]\begin{aligned} A^{\prime}(t) &= 3\, t^{2} - 15\, t + 12 \\ &= 3\, (t - 1) \, (t + 4)\end{aligned}[/tex].

[tex]\displaystyle A^{\prime\prime}(t) = 6\, t - 15[/tex].

Notice that both [tex]t = 1[/tex] and [tex]t = 4[/tex] are first derivatives of [tex]A^{\prime}(t)[/tex] over the interval [tex]0 \le t \le 6[/tex].

However, among these two zeros, only [tex]t = 1\![/tex] ensures that the second derivative [tex]A^{\prime\prime}(t)[/tex] is smaller than zero (that is: [tex]A^{\prime\prime}(1) < 0[/tex].) If the second derivative [tex]A^{\prime\prime}(t)\![/tex] is non-negative, that zero of [tex]A^{\prime}(t)[/tex] would either be an inflection point (if[tex]A^{\prime\prime}(t) = 0[/tex]) or a local minimum (if [tex]A^{\prime\prime}(t) > 0[/tex].)

Therefore [tex]\! t = 1[/tex] would be the only local maximum over the interval [tex]0 \le t \le 6\![/tex].

Calculate the value of [tex]A(t)[/tex] at this local maximum:

Compare these three possible maximum values of [tex]A(t)[/tex] over the interval [tex]0 \le t \le 6[/tex]. Apparently, [tex]t = 6[/tex] would maximize the value of [tex]A(t)\![/tex]. That is: [tex]A(6) = 28[/tex] gives the maximum value of [tex]\! A(t)[/tex] over the interval [tex]0 \le t \le 6\![/tex].

However, note that the maximum over this interval exists because [tex]t = 6\![/tex] is indeed part of the [tex]0 \le t \le 6[/tex] interval. For example, the same [tex]A(t)[/tex] would have no maximum over the interval [tex]0 \le t < 6[/tex] (which does not include [tex]t = 6[/tex].)

Answer:

1,417,000

Step-by-step explanation:

Given that:

Score = 1,475,623

96% of nationwide

96% of score gives the best estimate of the number of scores below 720

0.96 * 1475623

= 1416598.08

The best estimate is 1,417,000

Answer:

Step-by-step explanation:

Expression given → 4 - 9x + 21

Chang's expression → 4 - 3(3x + 7)

Chang's expression is incorrect because the correct expression is [4 - 3(3x - 7)]

Benjamin's expression → 4 + 3(3x + 7)

Benjamin's expression is incorrect because the correct expression is [4 - 3(3x - 7)]

Habib's expression → 4 + 12x

Habib's expression is incorrect because the correct expression is [4 - 3(3x - 7)]

Correct expression → [4 - 3(3x - 7)]

Answer:

4

Step-by-step explanation:

5-3=2      2+2=4

there are no parentheses so you just add/subtract from left to right..

Answer:

x=8

Step-by-step explanation:

∠B=∠A

Base Angle Thm/ Def. of Iso.

72=9x

x=8

Answer:

17 1/3 pounds

Step-by-step explanation:

6 1/2=6.5

6.5×2=13

6.5×2/3=4.3333333333

13+4.33=17.33=17 1/3

So the larger dog weighs 17 1/3 pounds

Please give brainliest, thank me and rate it 5 if this helped you.

Answer:The larger dog weighs 17 1/3 pounds .

Step-by-step explanation:6 1/2 ×  2 2/3

                                           = 13/2 ×   8/3

                                         = 104 /6  

                                         = 52/3

                                       = 17 1/3

That is how you solve it and the steps you do to get to the answer.

But now I will explain.So the first step is you change 6 1/2 and 2 2/3 into a improper fraction which 6 1/2 as an improper fraction is 13/2 and 2 2/3 as an improper fraction is 8/3 .The next  step is you multiply the improper fractions together which are 13/2 multiply 8/3 which you get 104/6.After that you simplify 104/6 ,and you get 52/3 . You divided both 104 and 6 (104/6) by 2 which gives you 52/3. (104 ÷ 2  /6 ÷ 2 =52/3) Lastly you change 52/3 which is a improper fraction into a mixed number which gives you 17 1/3 as your answer.

I hope this helps :)

Please give brainliest if it helps .Thanks :)

Answer:

(y+5)^2=-3/4(x+1)

Step-by-step explanation:

Answer:

Infinitely solution exists,

Required solution is, [tex](x_1,x_2,x_3)=(0, 4(1-t),t)[/tex]

Step-by-step explanation:

We have the given equations:

[tex]x_1+2x_2+8x_3=8[/tex]

[tex]x_1+x_2+4x_3=4[/tex]

Here, the augmented matrix is :

[tex]\left[\begin{matrix}1&2&8&8\\1&1&4&4\end{matrix}\right][/tex]

Now, find the echelon form of the augmented matrix.

[tex]=\left[\begin{matrix}1&2&8&8\\0&-1&-4&-4\end{matrix}\right]^{R_1\rightarrow R_2-R_1}[/tex]

[tex]=\left[\begin{matrix}1&0&0&0\\0&-1&-4&-4\end{matrix}\right]^{R_1\rightarrow R_1+2R_2}[/tex]

Therefore, [tex]x_1=0[/tex]

                [tex]-x_2-4x_3=-4[/tex]

             [tex]\Rightarrow x_2=4(1-x_3)[/tex]

Let [tex]x_3=t[/tex], then the required solution is

 [tex](x_1,x_2,x_3)=(0, 4(1-t),t)[/tex]