Answer:
I believe it's 2. I am not sure though.
Connor is the paper
football champion of
all of Black Middle
School. If he thumps a
paper football with an
initial velocity of 3.0
meters per second at
an angle of 30
degrees, how far will
the football travel?
Explanation:
First we have to descompose velocity, and get Velocity of X and Y side:
Vx = V * cos 30°
Vx = 3 m/s * 0,866...
Vx = 2,598 m/s
Vy = V * sen 30°
Vy = 3 m/s * 0,5
Vy = 1,5 m/s
Lets calculate time of fly:
Firat, lets calulate up time:
uT = (Fv - Iv) / g
uT = (0 m/s - 1,5 m/s) / -9,8 m/s^2
uT = -1,5 m/s / -9,8 m/s^2
uT = 0,15 s
Like up time is equal to down time, time of fly will be:
T =uT + dT
T = 0,15 s + 0,15 s
T = 0,3 s
Now for calculate how far will reach, lets aplicate the formula:
d = Vx * T
d = 2,598 m/s * 0,3 s
d = 0,779 meters
Will reach 0,779 meters
Gud luck
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a distance of 0.5 m
before the 1.56-kg target launched. What is the target's velocity as it leaves the spring?
Please help.
(A) 10m/s
(B) 20m/s
(C) 40m/s
(D) 30m/s
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
Un gas ideal ocupa un volumen de 4.00 m3 a una presión absoluta de 200 kPa. ¿Cuál será la nueva presión si el gas es comprimido lentamente hasta 2.00 m3 a temperatura constante?
Given :
Initial pressure, [tex]P_i=200\ kPa[/tex].
Initial volume, [tex]V_i= 4\ m^3[/tex].
Final volume, [tex]V_f = 2 \ m^3[/tex].
To Find :
Final pressure, [tex]P_f[/tex].
Solution :
We know, at constant temperature :
[tex]P_iV_i=P_fV_f\\\\P_f=\dfrac{P_iV_i}{V_f}\\\\P_f=\dfrac{200\times 4}{2}\\\\P_f=400\ kPa[/tex]
Therefore, new pressure is 400 kPa.
Hence, this is the required solution.
Describe how light is used in modern forms of communication.
Explanation:
Visible light communication (VLC) is a wireless method that uses light emitted by LEDs to deliver networked, mobile, high-speed communication similar to Wi-Fi, leading to the term Li-Fi. It can be used as standalone solution or in a supplementary role to radio-frequency (RF) or cellular network communication.
A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is 5m/s^2. What is the gravitational force exerted on the satellite by the planet?
A. 0N
B. 200N
C. 5000N
D. 10000N
Answer: 5000N
Explanation:
The basic principle of a circular orbit is that Fg = m × ac, so as we have the mass and the centripetal acceleration (also called normal acceleration) we just have to operate. Fg = 1000kg × 5m/s² = 5000N
The gravitational force exerted on the satellite of mass 1000 kg moving in a circular orbit with a centripetal acceleration of 5 m/s² by the planet is 5000 N (option C).
The gravitational force exerted on the satellite by the planet will be equal to the planet's gravity, which is equal to the centripetal force, so:
[tex] F_{g} = F_{c} = ma_{c} [/tex]
Where:
m: is the mass of the satellite = 1000 kg
[tex]a_{c}[/tex]: is the centripetal acceleration = 5 m/s²
The, the force acting on the satellite is:
[tex] F_{c} = ma_{c} = 1000 kg*5 m/s^{2} = 5000 N [/tex]
Therefore, the gravitational force exerted on the satellite by the planet is 5000 N (option C).
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https://brainly.com/question/11332442?referrer=searchResultshttps://brainly.com/question/24783651?referrer=searchResultsI hope it helps you!
Un automóvil se mueve hacia el norte siguiendo una trayectoria rectilínea con una velocidad constante, recorre 195 Km cada 1.3 h. ¿Calcula la velocidad con que se mueve?
Answer:
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Explanation:
La velocidad es una magnitud que expresa la relación entre el espacio recorrido por un objeto, el tiempo empleado para ello y su dirección.
Es decir, la velocidad se define como la relación que se establece entre la distancia recorrida y el tiempo transcurrido en el movimiento de un móvil.
Se puede calcular la magnitud de la velocidad utilizando la siguiente expresión:
[tex]velocidad=\frac{distancia}{tiempo}[/tex]
En este caso:
distancia= 195 kmtiempo= 1.3 hReemplazando:
[tex]velocidad=\frac{195 km}{1.3 h}[/tex]
Resolviendo:
velocidad=150 [tex]\frac{km}{h}[/tex]
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
According to the Declaration of Independence, all people are created in what manner?
Answer:
All men are created equal.
Explanation:
We hold these truths to be self-evident, that all men are created equal, that they are endowed by their Creator with certain unalienable Rights, that among these are Life, Liberty and the pursuit of Happiness.
-Declaration of Independence
Why work and energy both have same unit? Give reasons?
Answer:
Explanation:
both have same unit because energy is defined as the ability to do work and work is the measure of transfer of energy when an objects moved from one place to another place so both are same thats why both have same units
What is the function of hammer and anvil in human ear
Answer:
Vibrations of the eardrum are in turn translated into oscillations of tiny bones (ossicles) found within the middle ear. The Hammer, Anvil, and Stirrup magnify the oscillations and relay this information to the chamber of the inner ear.
Answer:
The Hammer, Anvil, and Stirrup magnify the oscillations and relay this information to the chamber of the inner ear.
a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy
Answer:
2.00v
Explanation:
What must follow the division of the nucleus to complete the process of binary fission
Answer:
Replication of the DNA must occur. Segregation of the "original" and its "replica" follow. Cytokinesis ends the cell division process. Whether the cell was eukaryotic or prokaryotic, these basic events must occur.
Melanie ran the 100 meters race in 12 seconds what was her avarage speed?
Answer:
melanie ran 8.3 meters per second
Explanation:
I think thats right, hope it helps.
Does water pressure depend on the total amount of water present?
(Will pick brainliest)
Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
A ball is thrown through the air.What condition(s) would enable the ball to continue in its state of motion?
A. a tailwind
B. a headwind
C. no air resistance or gravity
D. contact with another object
Answer:
C) No air resistance or gravity
Explanation:
For headwind imagine an airplane flying. The wind is hitting the front of the aircraft. Just like the wind is hitting the front of the ball. This increases the drag force and the ball will eventually slow and let the force of gravity act.
For tailwind imagine a sailboat. The wind catches the sail a pushes the boat. Both the wind and boat are going the same way so the angle of the wind is coming from behind. This is why it is called a tail wind.
If a ball is thrown, it has wind resistance and gravity. Otherwise just imagine the ball traveling all around the earth. Because the ball only has the force of lift and thrust, the ball will stay in motion until it hits something strong enough to counteract its thrust.
The description does not state any contact with another object. Also the ball will immediately stop if it has less newtons of force.
A hilly road is spiral in shape.
A ball rolling on the ground has what form of energy?
A. KE
B. Chemical
C. PE
D. None
Answer:
a kinetic energy
Explanation:
because it is moving
A model rocket accelerates at 15.3 m/s2 with a force of 44 N.
Calculate the mass of the rocket. Round your answer to the nearest tenth of a kg.
The mass of the rocket is
kg.
Answer:
The answer is 2.88 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{44}{15.3} \\ = 2.875816...[/tex]
We have the final answer as
2.88 kgHope this helps you
Answer:
2.9
Explanation:
In the equation you get 2.88 but you round that to the nearest tenth so you get 2.9
How long will it take to travel 200.000 m [N] traveling 10 m/s [N]?
Answer: here are 1,000m in a km, so 200km is 200,000m
200,000m/10m/s = 20,000s
Explanation:
Answer:
15.9k
Explanation:
A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atm. If the balloon is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atm. What is the new volume of the balloon?
5.0 L
0.19 L
4.9 L
1.9 L
Answer:
4.9L hope this helped!
What is the Net Force acting
on the box below?
A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline on the block? Answer in units of N.
Answer:
Explanation:
The sum of the pore along the plane is expressed according to Newton's law
Fn-Ff = ma
Fn is the moving force
Ff = nR = frictional force
m is the Mass
a is the acceleration
Substitute the given values
Fn - nR = ma
Fn - tan31°(mgcostheta) =3.9(9.8)
Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)
Fn - tan31(38.22cos31)= 38.22
Fn - 32.76tan31 = 38.22
Fn-19.68 = 38.22
Fn = 38.22+19.68.
Fn = 57.90N
Hence Fn (moving force) of the inclined block is 57.90
Andrew sells ball pens that have a radium body. This is the most unique feature of his product. Andrew charges a premium price for these pens because of this feature. He is using a strategy.
Answer:
a differentiation strategy
Explanation:
Note, a differentiation strategy occurs when a producer/seller sets apart his/her product from other competitors by giving it unique features such as quality, or other physical uniqueness, and so they may charge a premium price because of these unique features.
Hence, because Andrew's customers recognized this unique features they are willing to buy his ball pens over others; meaning the strategy worked.
Answer:
^^^ isn't wrong but the complete term is "product differentiation strategy"
Explanation:
Hopefully this helps others using plato
A copper rod of crosssectional area 0.500 cm2 and length 1.00 m is elongated by 2.00 * 10-2 mm and a steel rod of the same cross-sectional area but 0.100 m in length is elongated by 2.00 * 10-3 mm. Which rod is under greater tensile strain?
Answer:
They have the same tensile strainExplanation:
Strain of a material is the ratio of its extension to its original length.
strain = e/lo
e is the extension
lo is the original length
For a copper rod;
e = 2.00 * 10^-2mm
lo = 1.00m
convert 1.00m to mm
1.00m = 1*10^-3mm
get the strain
Strain = 2.00 * 10^-2mm/1*10^-3mm
Strain = 2 * 10^{-2+3}
Strain = 2*10^1 = 20
For the steel
e = 2.00 * 10^-3mm
lo = 0.100m
convert 0.100m to mm
0.1m = 0.1*10^-3mm
0.1m = 10^-4mm
get the strain
Strain = 2.00 * 10^-3mm/10^-4mm
Strain = 2 * 10^{-3+4}
Strain = 2*10^1 = 20
Since the value of their strain are the same, this means that they a re under the SAME tensile strain. No one is greater that the other.
The rod under greater tensile strain is ; Neither of them i.e. They both have the same tensile strain
Given data :
Cross sectional area of copper rod = 0.5 cm²
Length of copper rod = 1.0 m = 1 * 10³ mm
Elongation of copper rod ( Ec ) = 2.0 * 10⁻² mm
For Steel
Cross sectional area of steel = 0.5 cm²
Length of steel rod = 0.1 m = 1 * 10² mm
Elongation of steel rod ( Es )= 2.0 * 10⁻³ mm
Determine the Tensile strain of each rod
i) For copper rod
Tensile strain = Ec / Length of copper rod
= ( 2.0 * 10⁻² ) / ( 1 * 10³ )
= 2.0 * 10⁻⁵
ii) For the steel rod
Tensile strain = Es / Length of steel rod
= ( 2.0 * 10⁻³ ) / ( 1 * 10² )
= 2.0 * 10⁻⁵
The Tensile strain for the copper rod and the steel rod is the same ( 2.0 * 10⁻⁵ ) This means that both rods are under the same tensile strain
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One particle has a charge of -1.87 x 10-9C, while another particle has a
charge of -1.10 x 10-9 C. If the two particles are separated by 0.05, what is
the electromagnetic force between them? The equation for Coulomb's law is
Fe = kqjge, and the constant, k, equals 9.00 x 10-9 Nm2/C2,
A. 7.41 x 10-6N
B. -7.41 x 10-6N
C. 3,70 x 10-7N
O
D. -3,70 x 10-7N
Answer:
7.41 x 10⁻²⁴ N
Explanation:
F = (K x the charges of the two particles)/ the square of the distance which is 0.05.
The answer is not here but it seems two of the options are the same so I'll assume its A since the answer isn't negative
Answer:
A
Explanation:
just did it
{hope it helps <3 }
What is the mass of an object that has a force of 89 n and an acceleration of 25 m/s2
Answer:
3.56g
Explanation:
You would use the formula F= ma
F= 89N
A= 25m/s^2
M=?
89= 25*m
can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
HELP ASAP ILL DO ANYTHING.!!!!!!
Why does ice cream melt when you are holding it in a cone but not when it is sitting
in the freezer? Answer in terms of particles.
Answer: the heat from the environment melts the ice cream. When it’s in the freezer it doesn’t melt because both the freezer and ice cream are the same temperature
Explanation:
Answer:
the freezer and the ice cream is at the same temp while your hand and the cone is warmer so he heat from the cone transfers to the ice cream and heat it up and its particles move faster as it changes from a solid to a liquid.
You can add an easy question and give me some points if you would like!
Billy stands on a hill without slipping. In which direction is the force of friction acting?
A. along the surface of the hill, toward the bottom of the hill.
B. perpendicular to the surface of the hill
C. straight up
D. Along the surface of the hill toward the top of the hill.
Answer: D. Along the surface of the hill toward the top of the hill.
Hope I helped you!
D. Along the surface of the hill toward the top of the hill.
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m. A diver runs horizontally along the diving board with a speed of v0 = 2.7 m/s and then falls into the pool. Neglect air resistance. Use a coordinate system with the horizontal x-axis pointing in the direction of the diver’s initial motion, and the vertical y-axis pointing up. Let the y-axis be directed vertically down. Express the time t_w it takes the diver to move off the end of the diving board to the pool surface in terms of v_0, h, L, and g. Calculate the time, t_w in seconds, it takes the diver to move off the end of the diving board to the pool surface. Determine the horizontal distance, d_w in meters, from the edge of the pool to where the diver enters the water.
Answer:
1) The time it takes the diver to move off the end of the diving board to the pool surface, [tex]t_w[/tex], is approximately 1.392 seconds
2) The horizontal distance from the edge of the pool to where the diver enters the water, [tex]d_w[/tex], is approximately 5.76 meters
Explanation:
1) The given parameters are;
The height of the diving board above the pool's surface, h = 9.5 m
The length by which the diving board over hangs the pool L = 2 m
The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s
Taking [tex]t_w[/tex] = The time it takes the diver to move off the end of the diving board to the pool surface
Therefore, we have from the equation of free fall;
h = 1/2 × g × [tex]t_w[/tex]²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
9.5 = 1/2 × 9.81 × [tex]t_w[/tex]²
[tex]t_w[/tex] = √(9.5/(1/2 × 9.81)) ≈ 1.392 s
The time it takes the diver to move off the end of the diving board to the pool surface = [tex]t_w[/tex] ≈ 1.392 s
2) The horizontal distance, [tex]d_w[/tex], in meters from the edge of the pool to where the diver enters the water is given as follows;
[tex]d_w[/tex] = L + v₀ × [tex]t_w[/tex] = 2 + 2.7× 1.392 ≈ 5.76 m
∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.
A 0.111 kg hockey puck moving at 55 m/s is caught by a 80 kg goalie at rest. With what speed does the goalie slide on the (frictionless) ice? a 3.78 m/s b 2 m/s C 0.076 m/s d 1.056 m/s
Answer: 0.076 m/s
Explanation:
Momentum is conserved:
m v = (m + M) V
(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V
V = 0.076 m/s
After catching the puck, the goalie slides at 0.076 m/s.
A 0.111 kg hockey puck moving at 55 m/s is caught by a 80 kg goalie at rest. With speed does the goalie slide on the ice is 0.076 m/s
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Momentum is conserved:
m v = (m + M) V
(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V
V = 0.076 m/s
After catching the puck, the goalie slides at 0.076 m/s.
A 0.111 kg hockey puck moving at 55 m/s is caught by a 80 kg goalie at rest. With speed does the goalie slide on the ice is 0.076 m/s.
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