What is the slope of the line y=x+4?
O A.
1112
OB.
OC. 4
OD. -4

What Is The Slope Of The Line Y=x+4?O A.1112OB.OC. 4OD. -4

Answers

Answer 1
Slope is 1/2
Because y = mx + b
The fraction next to the variable x is the slope, m.

Related Questions

Juan and his children went into a restaurant where they sell drinks for $2 each and tacos for $4 each. Juan has $40 to spend and must buy a minimum of 11 drinks and tacos altogether. If xx represents the number of drinks purchased and yy represents the number of tacos purchased, write and solve a system of inequalities graphically and determine one possible solution.

Answers

The system of inequalities for the given situation is x+y≤11 and 2x+4y≥40.

Given that, the cost of each drink = $2 and the cost of each taco = $4.

What is a system of inequalities?

A system of inequalities is a set of two or more inequalities in one or more variables. Systems of inequalities are used when a problem requires a range of solutions, and there is more than one constraint on those solutions.

x represents the number of drinks purchased and y represents the number of tacos purchased.

Juan has $40 to spend and must buy a minimum of 11 drinks and tacos altogether.

So inequalities are x+y≤11 and 2x+4y≥40

Therefore, the system of inequalities for the given situation is x+y≤11 and 2x+4y≥40.

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Integrate the following function:

Answers

Answer: None of these

Step-by-step explanation:

First term

[tex]\int 12e^{12t} \text{ } dt=12 \int e^{12t} \text{ } dt=e^{12t}+C[/tex]

Second term

[tex]\int \sqrt[3]{27t} \text{ } dt=3\int t^{1/3} \text{ } dt=\frac{9}{4}\sqrt[3]{t^4}+C[/tex]

Third term

[tex]\int \frac{5}{t} \text{ } dt=5 \int \frac{1}{t} \text{ } dt=5\ln t+C[/tex]

Fourth term

[tex]\int 15 \text{ } dt=15t+C[/tex]

Adding these integrals, we get

[tex]\int g(t) \text{ } dt=e^{12t}+\frac{9}{4}\sqrt[3]{t^4}+5\ln t+15t+C[/tex]

which matches none of the options.

Solve the equation, 13|x−8|=10. Select each correct answer. Responses x=−30 x equals negative 30 x=−22 x equals negative 22 x=103 x equals 10 over 3 x = 8 x, = 8 x = 30 x, = 30 x = 38 x, = 38

Answers

The solution to the equation 1/3|x - 8| = 10 is x = 38

What are expressions?

Expressions are mathematical statements that are represented by variables, coefficients and operators

How to determine the solution to the equation?

The equation is given as

1/3|x - 8| = 10

Multiply through by 3

So, we have

|x - 8| = 30

Remove the absolute bracket

So, we have

x - 8 = 30

Add 8 to both sides of the equation

So, we have

x = 38

Hence, the solution to the equation is x = 38

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Wild Safari Tours charges $75 per person for a day trip, and deducts $25 for every fourth person in a group of four or more. What is the cost for a group of four? a group of nine? Show work.

Answers

The cost for a group of nine will be $625.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

total number of people in the group is nine

total amount that will be charged will be = $75×9= $675

the amount that will deduct is  $25

there will be to groups will be 2

so total amount that will be deducts =  $25×2=  $50

so total cost will be $675- $50=  $625

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Classify the indicated pairs of angles.

Answers

Answer:

can you send a link or photo of the angles?

Step-by-step explanation:

What is the greatest common factor of 26 and 4?​

Answers

Answer:

2

Step-by-step explanation:

List of positive integer factors of 26 that divides 4 without a remainder. We found the factors and prime factorization of 4 ad 26. The biggest common factor number is the GCF number. So the greatest common factor 4 and 26 is 2.

Jaun's age, x, is 4 times his age 15 years ago

Answers

The expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

How to rewrite the statement as an expression?

The mathematical statement is given as

Jaun's age, x, is 4 times his age 15 years ago

From the statement, we have:

x represent Juan's current age

This means that his age 15 years ago is

15 years ago = x - 15

4 times his age 15 years ago is

4 * 15 years ago = 4 * (x - 15)

The above equation is equivalent to his current age

So, we have

x = 4 * (x - 15)

Hence, the expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

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What is the least possible degree of the polynomial graphed above?

Answers

Answer:

2

Step-by-step explanation:

The graph looks to be like a parabola. Due to the end behaviour of the graph (Up in both quadrants 1 and 2) it can be said that the graph has a positive leading coefficient.

Hope that helps

The sum of two and eight times a number is -134. What is the number?
A) Translate the statement above into an equation that you can solve to answer this question. Do not solve
it yet. Use z as your variable.
The equation is
B) Solve your equation in part [A] for x.
Answer: x =

Answers

Answer:

A) 2 + 8x = -134

B) x = -17

Step-by-step explanation:

Note: I am assuming the question says use x as a variable, not z. Otherwise part B does not make sense

If we let variable x be the number then
8 times a number ==> 8x

2 and 8 times a number ==> 2 + 8x

2 and 8 times a number is -134 ==> 2 + 8x = -134

A) Equation form is 2 + 8x = -134

B) Equation is
2 + 8x = -134

Subtract 2 from both sides:
2 - 2 + 8x = -134 - 2
8x = -136

Divide both sides by 8 to give
8x/8 = -136/8
x = - 17

A dinner set can be bought for $110000 cash or by a deposit of $37000 and 24 equal monthly installments of $4600 each. How much more will the dining set cost using the hire purchase method of payment?​

Answers

The difference between the dining set cost using the hire purchase method of payment is $37400.

How to calculate the cost?

It should be noted that when the hire purchase is used and there is a deposit of $37000 and 24 equal monthly installments of $4600 each.

The total amount will be:

= $37000 + ($4600 × 24)

= $37000 + $110400

= $147400

On the other hand, the dinner set can be bought for $110000 cash.

Therefore, the difference will be:

= Hire purchase - Cash.

= $147400 - $110000.

= $37400

Therefore, the difference between the dining set cost using the hire purchase method of payment is $37400.

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A farmer has 150 yards of fencing to place around a rectangular garden. The fence will have an opening that is 1/3 of the garden's length. Write a function A(x) that describe the area of the garden, where x is the length of the garden. Find the dimensions if that has a maximum area, and find the maximum area

Answers

The garden has a length of 37.5 yards and width of 37.5 yards as well as an opening of 12.5 yards.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the length and y represent the width.

150 yards of fencing is available, hence:

2(x + y) = 150

x + y = 75

y = 75 - x     (1)

The area (A) of the garden is given as:

A = xy

A = x(75 - x)

A = 75x - x²

The maximum area is at A' = 0

A' = 75 - 2x

75 - 2x = 0

x = 37.5 yards

y = 75 - x = 75 - 37.5 = 37.5

Opening of the garden = 1/3 * 37.5 = 12.5 yards

The garden has a length of 37.5 yards and width of 37.5 yards as well as an opening of 12.5 yards.

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Let [tex]\alpha[/tex] and [tex]\beta[/tex] be real number such that [tex] - \frac{\pi}4 < \beta < 0 < \alpha < \frac{\pi}{4} .[/tex] If [tex]\sin( \alpha + \beta ) = \frac{1}{3}[/tex] and [tex]\cos( \alpha - \beta ) = \frac{2}{3}[/tex] , then the greatest integer less than or equal to [tex] \bigg( \frac{ \sin( \alpha ) }{ \cos( \alpha ) } + \frac{ \cos( \beta ) }{ \sin( \alpha ) } + \frac{ \cos( \alpha ) }{ \sin( \beta ) } + \frac{ \sin( \beta ) }{ \cos( \alpha ) } \bigg) {}^{2} \\[/tex]​ is

Answers

Step-by-step explanation:

We have,

[tex]\begin{gathered} \bullet \: \bold{ - \dfrac{\pi}{4} < \beta < 0 < \alpha < \dfrac{\pi}{4} } \\ \\ \implies \: - \dfrac{\pi}{4} < \alpha + \beta < \dfrac{\pi}{4} \end{gathered}[/tex]

[tex]\begin{gathered} \rm\bullet \: \: \: \sin( \alpha + \beta ) = \dfrac{1}{3} \: \: \: \: \: and \: \: \: \: \: \cos( \alpha - \beta ) = \dfrac{2}{3} \\ \end{gathered} [/tex]

Now,

[tex]\begin{gathered} y= \bigg( \dfrac{ \sin( \alpha ) }{ \cos( \beta ) } + \dfrac{ \cos( \beta ) }{ \sin( \alpha ) } + \dfrac{ \cos( \alpha ) }{ \sin( \beta ) } + \dfrac{ \sin( \beta ) }{ \cos( \alpha ) } \bigg)^{2} \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \bigg( \dfrac{ \sin( \alpha ) }{ \cos( \beta ) } + \dfrac{ \sin( \beta ) }{ \cos( \alpha ) } + \dfrac{ \cos( \beta ) }{ \sin( \alpha ) } + \dfrac{ \cos( \alpha ) }{ \sin( \beta ) } \bigg)^{2} \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \bigg( \dfrac{ \sin( \alpha ) \cos( \alpha ) + \sin( \beta \cos( \beta ) ) }{ \cos( \beta ) \cos( \alpha) } + \dfrac{ \sin( \alpha) \cos( \alpha ) + \sin( \beta ) \cos( \beta ) }{ \sin( \alpha ) \sin( \beta ) } \bigg)^{2} \\\end{gathered}[/tex]

[tex]\begin{gathered} \implies y= \bigg( \dfrac{ \sin( \alpha + \beta ) }{ \cos( \beta ) \cos( \alpha) } + \dfrac{ \sin( \alpha + \beta ) }{ \sin( \alpha ) \sin( \beta ) } \bigg)^{2} \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \sin^{2} ( \alpha + \beta ) \bigg( \dfrac{ 1 }{ \cos( \beta ) \cos( \alpha) } + \dfrac{ 1 }{ \sin( \alpha ) \sin( \beta ) } \bigg)^{2} \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \sin^{2} ( \alpha + \beta ) \bigg( \dfrac{\cos( \beta ) \cos( \alpha) + \sin( \alpha ) \sin( \beta ) }{ \cos( \beta ) \cos( \alpha) \sin( \alpha ) \sin( \beta )} \bigg)^{2} \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \sin^{2} ( \alpha + \beta ) \bigg( \dfrac{\cos( \alpha - \beta ) }{ \cos( \beta ) \cos( \alpha) \sin( \alpha ) \sin( \beta )} \bigg)^{2} \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \dfrac{4\sin^{2} ( \alpha + \beta ) \cdot\cos^{2} ( \alpha - \beta ) }{ \left \{2\cos( \alpha ) \cos( \beta ) \cdot 2\sin( \alpha ) \sin( \beta ) \right \}^{2} } \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \dfrac{4\sin^{2} ( \alpha + \beta ) \cdot\cos^{2} ( \alpha - \beta ) }{ \left \{\cos( \alpha + \beta ) + \cos( \alpha + \beta ) \right \} ^{2} \left \{ \cos( \alpha - \beta ) - \cos( \alpha + \beta ) \right \}^{2} } \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \dfrac{4\sin^{2} ( \alpha + \beta ) \cdot\cos^{2} ( \alpha - \beta ) }{ \left \{ \cos^{2} ( \alpha - \beta ) - \cos^{2} ( \alpha + \beta ) \right \}^{2} } \\\end{gathered}[/tex]

[tex]\begin{gathered} \implies y= \dfrac{4\sin^{2} ( \alpha + \beta ) \cdot\cos^{2} ( \alpha - \beta ) }{ \left \{ \cos^{2} ( \alpha - \beta ) - 1 + \sin^{2} ( \alpha + \beta ) \right \}^{2} } \\\end{gathered}[/tex]

Putting the values given above, we get,

[tex]\begin{gathered} \implies y= \dfrac{4 \cdot \dfrac{1}{9} \cdot\dfrac{4}{9} }{ \left \{ \dfrac{4}{9} - 1 + \dfrac{1}{9} \right \}^{2} } \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \dfrac{\dfrac{16}{81} }{ \left \{ \dfrac{5}{9} - 1\right \}^{2} } \\\end{gathered}[/tex]

[tex]\begin{gathered} \implies y= \dfrac{\dfrac{16}{81} }{ \left \{ \dfrac{5 - 9}{9}\right \}^{2} } \\\end{gathered} [/tex]

[tex]\begin{gathered} \implies y= \dfrac{\dfrac{16}{81} }{ \left \{ \dfrac{- 4}{9}\right \}^{2} } \\\end{gathered}[/tex]

[tex]\begin{gathered} \implies y= \dfrac{\dfrac{16}{81} }{ \dfrac{16}{81}} \\\end{gathered} [/tex]

[tex]⟹y=1[/tex]

Suppose a single fair die is rolled. Find the probability that it a is a 6, given that it is an even number.
The probability is?

Answers

Answer:  1/3

Explanation:

"given it is an even number" tells us that the outcomes could be anything from this set {2,4,6}. We ignore the odd numbers entirely.

We have one copy of "6" out of three total items.

Therefore, we end up with a probability of 1/3

This is approximately equal to the decimal form 0.333 and the percent form 33.3%

I would stick to the fraction form since it's most exact. However, if your teacher instructs otherwise then be sure to follow said instructions of course.

Let A = {10, 20, 30, 40, 50, 60} and B = {10, 20, 50}. What is A ∩ B?

Answers

A∩B = {10, 20, 50}

The given two function is

A = { 10, 20, 30, 40, 50, 60}

B = { 10, 20, 50}

We have to find the value of function of A∩B

A∩B means the number which is common in both the function,

The number common in function A and B is 10, 20, 50.

Therefore the function A∩B = {10, 20, 50}

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Would be wonderful, if anyone could help me understand what steps you should do for this one.

Answers

The value of x is 6 is proved by equating line segment PM and MR as M is the midpoint of line PR.

What is midpoint of line segment?

The midpoint divides the line segment into two equal parts. As the number line progresses, the leftmost numbers become smaller, and the rightmost numbers become larger. Adding, subtracting, and multiplying can also be done using a number line like for addition move towards right and for subtraction move towards left.

It is given that M is the midpoint of line segment PR which implies M will divide PQ into two equal parts that is PM (2x + 5) equals MR (4x - 7). now calculating x value first :

PM = MR

2x+5 = 4x -7

4x -2x = 5 + 7

2x = 12

x = 12/2

x = 6

Hence proved that the value of x is 6

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A circular dartboard with a diameter of 24 inches has a circular bullseye at its center. The diameter of the target is 10 inches. If a poorly thrown dart is equally likely to hit anywhere on the dartboard, what is the probability of it hitting the target? (Write your answer as a fraction.)

Answers

The value of the probability of hitting the target is 0.1736.

According to the statement

We have to find that the value of the probability.

So, For this purpose, we know that the

Probability is the branch of mathematics that studies the possible outcomes of given events together with the outcomes' relative likelihoods and distributions.

From the given information:

A circular dartboard with a diameter of 24 inches has a circular bullseye at its center. The diameter of the target is 10 inches.

Then

Area of a circular dartboard = [tex]\pi r^{2}[/tex]

Area of a circular dartboard = [tex](3.14)* 12^{2}[/tex]

Area of a circular dartboard = [tex](3.14) *144[/tex]

Area of a circular dartboard = 452.16 inches

And then

Area of a circular bullseye = [tex]\pi r^{2}[/tex]

Area of a circular bullseye = [tex](3.14)* 5^{2}[/tex]

Area of a circular bullseye = [tex](3.14) * 25[/tex]

Area of a circular bullseye = 78.5

Then

Probability of hitting the target = Area of a circular bullseye / Area of a circular dartboard

Probability of hitting the target = 78.5 / 452.16

Probability of hitting the target = 0.1736.

So, The value of the probability of hitting the target is 0.1736.

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612,315 in scientific notation

Answers

Answer: 6.12315 × 105

Step-by-step explanation: No worry's just here for the fun of it

Multiplying each digit of one number by each digit of another number won’t work when you’re multiplying numbers with more than three digits

Answers

Answer: this statement would be true because that would mean that 100x100=1

Step-by-step explanation:hope it helps, brainliest? i could really use it

15. Which relation has a domain of {-5, -3, 0) and a range of {1, 2, 3, 4, 5, 6, 7, 8)?
O {(2,-5), (3,-3), (6, 0), (7,-5), (1, 0), (8,-5), (4, -3), (5, 0))
O((-5, 8), (-5, 2), (-3, 3), (-3, 1), (0, 4), (0, 5), (-5, 7), (-3, 6)}
{(-5, -5), (-3,0), (2, 8), (1,7), (5, 3), (6,4)}
((-5, 9), (10, -3), (2, 1), (3, 4), (0, 5), (6, 8), (0, 7)}

Answers

Among the four options provided in the reference diagram for the question attached thereby along with the question statement, {(-5, 8), (-5, 2), (-3, 3), (-3, 1), (0, 4), (0, 5), (-5, 7), (-3, 6)} is the relation that has a domain of {(-5), (-3), 0} and a range of {1, 2, 3, 4, 5, 6, 7, 8}.

As per the question statement, we are required to determine the relation which has a domain of {-5, -3, 0) and a range of {1, 2, 3, 4, 5, 6, 7, 8).

To solve this question, we will use the trial-and-error method on the options provided. We have to find out possible (x, y) combination, where "x" belongs to the set of {(-5), (-3), 0} and "y" belongs to the set of {1, 2, 3, 4, 5, 6, 7, 8}, and match these combinations with the options.

The first option has x values from the set of {1, 2, 3, 4, 5, 6, 7, 8} and y values from the set of {(-5), (-3), 0}. Hence, it is not the correct answer.

The second option has x values from the set of {(-5), (-3), 0} and y values from the set of {1, 2, 3, 4, 5, 6, 7, 8}. Hence, it is one possible correct answer.

The third and fourth options have values out of the sets of {(-5), (-3), 0} and {1, 2, 3, 4, 5, 6, 7, 8}. Hence, they are not the correct answers.

Therefore,  {(-5, 8), (-5, 2), (-3, 3), (-3, 1), (0, 4), (0, 5), (-5, 7), (-3, 6)} is the relation that has a domain of {(-5), (-3), 0} and a range of {1, 2, 3, 4, 5, 6, 7, 8}.

Range & Domain of a Function: In a function, say [y = f(x)], the set of values we can plug into the function, i.e., "x" is the domain for the function while, the set of outputs the function will produce on inputs of x, will form the Range of the function.

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5. The Cupcake Café makes 4 and 1/2 times as much revenue on doughnuts as muffins. If total sales were $44,000 for May, what dollar amount of each was sold?

Answers

Answer:

Step-by-step explanation:

According to the question, the cupcake cafe makes 1/2 times as much revenue on doughnuts as muffins and the total revenue is total sales were $44,000. Let us assume that the revenue on muffins is X and then the revenue on doughnuts is 412X. 4 1 2 X . The amount of money earned from muffins is 20000 dollars

Which Law of Exponents is used to write (3ab)³ as the equivalent expression 27a³b³?
Choose the correct answer below.
OA. Product of a Power Law
B. Power of a Power Law
C. Power of a Product Law
OD. Power of a Quotient Law
...

Answers

Answer:

A) product of a power law

Step-by-step explanation:

most sensible

2) What is the area of figure ABCD, in
square centimeters?
8 cm.
6 cm
6 cm
B
15 cm

Answers

Answer:

138cm^2

Step-by-step explanation:

Trianle area = (b*h)/2

b = 8cm + 15cm

h = 6cm

Triangle area = (23*6)/2

138/2 = 69cm^2

Upper triangle area

--------------------------------

since both triangles share the same base and height

69*2 = 138cm^2

How would you find the missing number in a mean sequence where you only know one number? (and also the mean of the known number and the missing number)

Answers

Step-by-step explanation:

The mean of a set of numbers is the average of those numbers. You can find the mean by adding the set of numbers and dividing by how many numbers are given. If you are given the mean and asked to find a missing number from the set, use a simple equation.

Add up the numbers you know. The problem states a mean of 58 with this set of numbers: 43, 57, 63, 52 and x. Assign the missing number a value of “x.” So add 43, 57, 63 and 52 to get 215.

Set up your equation by adding 215 plus “x” (the missing number), divided by 5, the number of values given. Set that side of the equation equal to the mean, 58. So, your equation would look like this: [tex] \frac{215+x}{5} = 58 [/tex]

Multiply each side by 5 since our goal is to get “x” by itself. This process cancels the 5 on the left side of the equation and gives you 290 on the right side (58 × 5). Now, your equation should look like this: [tex] 215+x=290 [/tex]

Subtract 215 from each side as you continue to work to get “x” alone. This cancels out the 215 on the left side of the equation and gives you 75 on the right side. Now, your equation should show that x = 75. Therefore, the missing number is 75.

Check the missing number by adding all the numbers together and dividing by 5.

[tex] \frac{43+57+63+52+75}{5} = \frac{290}{5} = 58 [/tex]

After rolling a fair, six-sided die 100 times, it was observed that the probability of rolling a 2 was 12%. What would the probability be of rolling a 2 the next time that same die is rolled?​

Answers

Answer:

The probability of rolling a 2 the next time that same die is rolled is 0.167.

Step-by-step explanation:

In this question it is given that there is rolling dice that is six sided and which is rolled for a 100 times and it was further observed that the probability of rolling a 2 was 12%.

Firstly, let us understand what is probability;

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true.

Now,

Let us understand the concept of impossibility and certainty of an event;

An event's probability is a number between 0 and 1, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Further, In the above-mentioned condition, it is observed that the die has been rolled a 100 times;

The probability of getting X is only 12%.

Now,

In the condition where the die is rolled in for an extra time being a six sided, the probability of getting a 2 is 1/6.

=> 1/6

=> 0.167

Therefore, the probability of rolling a 2 the next time that same die is rolled is 0.167.

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given g(x) = 2x/x-2, x≠2. find g¹³(8)​

Answers

Answer:

8/3

Step-by-step explanation:

[tex]g^2 (x)=\frac{2\left(\frac{2x}{x-2} \right)}{\frac{2x}{x-2}-2} \\ \\ =\frac{4x}{2x-2(x-2)} \\ \\ =\frac{4x}{4} \\ \\ =x[/tex]

From this, we can see that g(x) is its own inverse. Thus, [tex]g^{13}(x)=g(x)[/tex]

So,

[tex]g^{13}(8)=\frac{2(8)}{8-2}=8/3[/tex]

please help the answer is 97 but i want to know the process of doing it ASAP

Answers

Answer:

  97

Step-by-step explanation:

You want the value of the composition of functions f and g for x=4.

Composition

The ring operator signifies a composition of functions. It works right to left. That is, ...

  [tex](f\circ g)(x)=f(g(x))[/tex]

A composition is evaluated using the Order of Operations, working from inner parentheses outward.

Application

  [tex](f\circ g)(4)=f(g(4)) = f(3-\dfrac{1}{2}4^2)=f(-5)\\\\=4(-5)^2-3=100-3=\boxed{97}[/tex]

2h+j+5k=57
h+j+k=16
h+6j+2k=35

Answers

Hey, could you perhaps provide a little bit more info regarding what method/topic/skill you are required to use in order to solve the following? Also, are these three different expressions, or are they a part of the same question. Thanks!

QUICK IM TIMED
Solve the simultaneous question x-2y=10 X=6y+2

Answers

Answer:

x = 32

y = 5

Step-by-step explanation:

2y=10

X=6y+2

Put both equations in the same format

x - 6y = 2

Manipulate the equations so that they have a common coefficient

6y = 30

Solve for one coefficient

(x - 6y = 2) + (6y = 30)

x + (-6y + 6y) = 2 + 30

x = 2 + 30

x = 32

Solve for the other coefficient

2y = 10

y = 5

x - 6y = 2

32 - 6y = 2

-6y = 2 - 32

-6y = -30

y = -30/-6

y = 5

A yard has a perimeter of 400 feet. If eight times the length of the yard equals seventeen times the width

Answers

The length and width of the yard with perimeter of 400 feet are 136 ft and 64 ft respectively.

How to find perimeter of a rectangular yard?

The yard has a perimeter of 400 feet.

Eight times the length of the yard equals seventeen times the width.

Therefore,

perimeter of a rectangular yard = 2(l + w)

where

l = lengthw = width

Therefore,

8l = 17w

Hence,

l = 17 / 8 w

perimeter of a rectangular yard = 2(17 / 8 w + w)

perimeter of a rectangular yard = 2( 25  /8 w)

perimeter of a rectangular yard = 50/ 8 w

400 = 50 / 8 w

cross multiply

3200 = 50w

divide both sides by 50

w = 3200 / 50

w = 64 ft

l = 17 / 8 × 64 = 136 ft

Therefore, the length and width of the yard with perimeter of 400 feet are 136 ft and 64 ft respectively.

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Answers

Answer:

a=25

b=90

c=45

d=25

e=90

g=130

h=50

i=130

k=85

l=95

n=95

Step-by-step explanation:

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