Answer:
B im pretty sure.
Explanation:
11. A car travels at 40 m/s, decelerates at a constant 4 m/s² until rest.
Determine speed and distance after decelerating in 10 seconds!
Answer:
Speed is 0 m/s.
Distance is 200 meters.
Explanation:
One-Dimensional MotionIn this scenario, we can treat speed as the absolute value of velocity and distance as absolute value of displacement since we are dealing with one-dimensional motion.
There’ll only exist one component of vector, by applying magnitude formula, it’ll return value as shown below:
Suppose we have a one-dimensional vector, [tex]\displaystyle{\vec v = 5\hat i}[/tex], this represents a vector with magnitude of [tex]\displaystyle{|\vec v | = \sqrt{5^2} = 5}[/tex].
Theorem I - Magnitude of One-Dimensional Vector
Suppose we have a vector [tex]\displaystyle{\vec v = a\hat i}[/tex] then the magnitude is [tex]\displaystyle{|\vec v| = \sqrt {a^2} = |a|}[/tex].
Speed and Distance, Velocity and DisplacementSpeed and distance both are scalar quantity which means they only have magnitude but lack the direction. In one-dimensional motion, speed is defined to be the absolute value of velocity and direction is defined to be the absolute value of displacement, the reason is shown above regarding one-dimensional vector.
An example would be, consider a car moves at velocity of -4 m/s, this means that a car just moves to negative direction or opposite direction of positive at 4 m/s. The negative and positive sign refer to the direction that an object moves, to know how fast they are moving, we consider its magnitude which is speed.
This can also be said same to displacement and distance, but be aware that this can only be applied to straight horizontal or vertical line movement or else the motion will become two-dimensional.
SolutionFrom the problem, there’s no specific distance or displacement’s graph so we will assume that the car is moving in straight horizontal line. The car is moving at speed of 40 m/s and decelerates at 4 m/s².
This means that our acceleration is -4 m/s² since it’s decelerating and is moving at 40 m/s from start. Therefore, we can apply a general physic formula which is:
[tex]\displaystyle{v = u+at}[/tex]
Where v is final velocity, u is initial velocity, a is acceleration and t is time. As said, we can treat speed = positive velocity in this scenario so substitute u = 40 m/s and a = -4 m/s² in the formula.
[tex]\displaystyle{v=40-4t}[/tex]
Now substitute t = 10 in the formula:
[tex]\displaystyle{v = 40-4(10)}\\\\\displaystyle{v=40-40}\\\\\displaystyle{v=0 \ \sf{m/s}}[/tex]
Therefore, the speed of car at 10 seconds is 0 m/s, it’s not moving at this moment.
Next, we find distance which we can use the following formula:
[tex]\displaystyle{s = ut + \dfrac{1}{2}at^2}[/tex]
Substitute u = 40, t = 10 and a = -4 in:
[tex]\displaystyle{s=40(10)+\dfrac{1}{2}(-4)(10)^2}\\\\\displaystyle{s = 400-2(100)}\\\\\displaystyle{s=400-200}\\\\\displaystyle{s=200 \ \sf{m}}[/tex]
Therefore, in 10 seconds, it’ll be able to travel 200 meters.
Please let me know if you have any questions!A car is going through a dip in the road whose curvature approximates a circle of radius 200 m. At what velocity will the occupants of the car appear to weigh 20% more than their normal weight (or their normal weight times 1.2)?
Answer:
Explanation:
The solution along with the diagram can be found in the attachment. Feel free to raise doubts.
Centripetal force is defined as the force that allows the object to follow a curvature path.
The velocity will be 19.80 m/s.
Given:
Normal Force = 1.2 x weight
Normal Force = 1.2 Mg
Mass = Mass of car + occupants
Centripetal Acceleration = [tex]\text a_c[/tex]
Now, applying the equilibrium equation:
[tex]\begin{aligned} \sum \text F&= \text m \times \text a_c\\\\\text F_n - \text{mg} &= m \times \text a_c\\\\1.2 \text{Mg} - \text{Mg} &= m \times \text a_c\\\\\text a_c &=0.2 \;\text g\\\end[/tex]
Now, substituting the value in the formula:
[tex]\begin {aligned} \text a_c &=\dfrac{\text v^2}{\text r}\\\\0.2 \text g &= \dfrac {\text v ^2}{\text r}\\\\\text v &= \sqrt{0.2 \times 9.8 \times 200}\\\\\text v &= 19.80 \;\text {m/s}\end[/tex]
Thus, the velocity will be 19.80 m/s.
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Drag each tile to the correct location.
An aspect of climate change involving cloud cover is one example of a negative feedback loop. Complete the steps of this negative feedback
loop.
increased formation
of clouds
decreased temperatures
increased evaporation
from oceans
increased carbon dioxide in
atmosphere
increased greenhouse effect
and warmer temperatures
1
+
increased precipitation
Edmentum. All rights reserved.
Answer:
Look at the image please
Explanation:
what is kinetics force
Answer:
Explanation:
Kinetic force is the force caused kinetic energy. Kinetic energy is energy this is in movement such as a moving car or a falling rock.
A 450 N trunk rests on a 30 degree inclined plane. What is the force acting down the
plane (parallel force)?
Answer: What is the force acting down the plane?
• Opp= hyp (sinq)= 450(sin30)= 225 N
• What is the force acting perpendicular to the plane?
• adj= hyp (cosq)= 450(cos30)= 390 N
Explanation:
What will happen to a satellite's orbit if its engines are turned on, causing it to
gain velocity tangential to its orbit?
O A. The height of its orbit will decrease.
OB. It will lose kinetic energy.
C. It will lose gravitational potential energy.
OD. The height of its orbit will increase.
Enter an expression in the box to Write the equation of the line perpendicular to y=-3x-1 that passes through the point (3,4).
Y = ?
Answer: -3x+13
Explanation:
The slope of the line that passes through the point (3,4) is 1/3. Then , the intercept of the perpendicular line is 3 . Then, the equation of the line is y = 1/3x + 3.
What are coordinates ?Coordinates are numbers which describes the position of a shape, curve or line. The coordinates are written in terms of x and y axis values. A line or curve passing through certain points can be represented by an equation.
For a straight line the equation is y = mx + c
where m is the slope of the line and c be the intercept on y- axis.
For two perpendicular lines, the slope will be opposite inverse of each other.
The slope of the line y = -3x + 1 is -3. Then, the slope of the line which is perpendicular to this line is - (1/-3) = 1/3.
Then the equation of the line is y = 1/3 x + c.
given the line passes through the point (3,4).
Then,
4 = 1/3×3 + c
c = 3.
Therefore, the equation of the second line is y = 1/3 x + 3.
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A car, with an initial velocity of 22 m/s west, travels for 345 seconds. If it has a final velocity of 44 m/s west what is its’ acceleration?
Answer: 0.064 m/s²
Explanation:
Initial velocity = 22m/s
Final velocity = 44m/s
Time taken = 345 seconds
Acceleration = (Final velocity - Initial velocity) / Time taken
= (44 - 22) / 345
= 22/345
= 0.0637681
= 0.064 m/s²
Therefore, the acceleration is 0.064 m/s².
you are arguing over a cell phone while trailing an unmarked police car by 26.0 m; both your car and the police car are traveling at 110 km/h. your argument diverts your attention from the police car for 2.0 s (long enough for you to look at the phone and yell,"i won't do that!"). at the beginning of that 2.0 s, the police officer begins braking suddenly at 5.00 m/s2. suppose that you take another 0.500 s to realize your danger and begin braking
The speed of the car when you hit the police car is 26.154 m/s.
The speed of the car's v = 110km/h = 30.56 m/s
The total time travel will also include the reaction time:
t = 2 + 0.4 = 2.4 s
For police,
The acceleration, a = - 5 m/s²
The distance traveled is:
[tex]S(p) = vt + (\frac{1}{2} ) \times at^{2}[/tex]
[tex]S(p) = 30.56 \times 2.4 + \frac{1}{2} \times (-5) \times (-2.4)^{2}[/tex]
S(p) = 58.93 m
Now, the original gap between the car was 25 m.
Therefore, the final gap = (25 − 73.33 + 58.93) m = 10.6 m
As a result, let's say that at time t₀, the distance between the cars is 10.6 meters.
The speed of the police car at t₀ will be:
v(p) = (30.56 − 5 × 2.4) = 18.56m/s.
Now, the collision occurs at a time t when S = S(p)
We pick your position's coordinates to be S = 0 and the police car's position to be S(p) = 10.6m at time t₀ .
Therefore,
[tex]S(p) - 10.6 = 18.56(t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}[/tex]
S(p) = 10.6 + 18.56t − 2.5t²
And,
[tex]S = 30.56 (t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}[/tex]
When the distances are equal.
S = S(p)
30.56 (t - t₀) - (1/2)(5)(t - t₀)² = 10.6 + 18.56t − 2.5t²
t = 0.883 sec
So, the speed of your car during the collision will be:
v = 30.56 - 5(0.883) = 26.154 m/s
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The complete is mentioned below:
You are arguing over a cell phone while trailing an unmarked police car by 25m; both your car and the police car are traveling at 110km/h. Your argument diverts your attention from the police car for 2.0s (long enough for you to look at the phone and yell, “I won’t do that!”). At the beginning of that 2.0s, the police officer begins braking suddenly at 5.0m/s². What is the separation between the two cars when your attention finally returns? Suppose that you take another 0.40s to realize your danger and begin braking. If you too brake at 5.0m/s², what is your speed when you hit the police car?
Planet A has a gravitational field strength of 8.0 N/kg near its surface.
Planet B has three times the mass of Planet A and is half of its size.
What would be the gravitational field strength of planet B near its surface?
Answer: 96 N/kg
Explanation:
approximately 72 billion liters of milk are produced each year in the united states, from 8 million cows. on average, a single cow consumes 13,500 kg of corn feed each year. it requires 40 mj to produce a kilogram of corn feed, which contains 20 mj of energy. there are 15 mj of energy in a single liter of milk.
The energy efficiency of growing corn converted to milk is 50 percent corn efficiency produce 50 percent milk efficiency
Given data
annual milk production = 72 billion liters from 8 million cows
annual milk production = 72 billion liters / 8 million cows
annual milk production = 9000 liters / cow per annum
On average, a single cow consumes 13,500 kg of corn feed each year
40 MJ to produce a kilogram of corn feed, which contains 20 MJ of energy
15 MJ of energy in a single liter of milk
How to solve for energy efficiency of growing corn and converting it to milkEnergy efficiency of corn = energy output / energy input * 100
energy output = 20MJ
energy output = 40MJ
Energy efficiency of corn = 20 / 40 * 100
Energy efficiency of corn = 50 %
Energy efficiency of milk = energy output / energy input * 100
energy output = 13,500 * 20 = 270 000
energy output = 9000 * 15 = 135 000
Energy efficiency of milk = 135 000 / 270 000 * 100
Energy efficiency of milk = 50 %
Therefore 50 percent corn efficiency produce 50 percent milk efficiency
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complete question
Approximately 72 billion liters of milk are produced each year in the United States, from 8 million cows. On average, a single cow consumes 13,500 kg of corn feed each year. It requires 40 MJ to produce a kilogram of corn feed, which contains 20 MJ of energy. There are 15 MJ of energy in a single liter of milk.
1. Calculate the energy efficiency of growing corn and converting it to milk
What are two types of democracy how are they different?
Answer:
representative and liberal democracy
Explanation:
a representative democracy is an indirect democracy where sovereignty is held by the people's representatives. a liberal democracy is a representative democracy with protection for individual liberty and property by rule of law
Describe the term amplitude
Answer:
"the maximum extent of a vibration or oscillation, measured from the position of equilibrium."
hope this helps
Answer:
amplitude and physics the maximum displacement or distance moved by point on a vibrating body or wave measured from its equilibrium position it is equal to 1/2 of the length of the vibration path
(1) astronomers have inherited many useful concepts from antiquity. (2) for example, ancient mathematicians invented angles and a system of angular measure that is still used to denote the positions and apparent sizes of objects in the sky. (3) when we locate stars, we don’t need to know their distances from earth (which are all different). (4) all we need to know is the angle from one star to another in the sky, a property that remains fixed over our lifetimes. (neil f. comins and william j. kaufmann iii, discovering the universe) sentence 2 can best be described as a
The reading of the given passage on astronomy gives;
Sentence (2) is the major supporting detailHow can the parts of the passage be identified?Sentence (1) is the main idea or background statement with regards to astronomy, with regards to the sources of concepts being used in astronomy. It conveys the subject matter of passage.
Sentence (2) gives more light to the statement of sentence (1). It gives the supporting details of the concepts astronomers inherited from antiquity, by outlining them; (angles and angular measure system used locate stellar objects), while sentence (4) gives a little information with regards to the use of angular system.
Therefore;
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How much voltage is in a circuit with a current of 0.1 A and a total resistance of 7.29 Ω?
Answer:
0.729
Explanation: by using ohms laws
the first law of thermodynamics states that the degree of disorder in the universe tends to increase
The degree of disorder in the universe tends to increase due to entropy.
ie. the second law of thermodynamic
First law of thermodynamics is the conservation of energy. Energy can change from one form to another form it neither created nor destroyed.
dQ = dU + dW
where
dQ is the heat transferred.
dW is the work done
dU is change in internal energy.
2nd law states entropy of an isolated system always increases.
S > 0
where s is the change in entropy in the universe.
the degree of disorder in the universe tends to increase due to entropy.
ie. the second law of thermodynamic.
The given question is incomplete
the first law of thermodynamics states that the degree of disorder in the universe tends to increase
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when dropped from rest, any object will fall a total distance of 19.6 m in the first 2 seconds of its fall. how far does the object fall just during the 2nd second (i.e., from time t
The object fall just during the 2nd second is 14.7m.
As we know the equation of motion
equation off motion are equation that describe the behavior of physical system in terms of its motion as a function of time.
using 2nd equation of motion
S = ut +gt²/2
S= distance covered
u = initial velocity
g = acceleration due to gravity
t = time taken (t= 1 sec)
a = g = 9.8 m/s²
u = 0 m/s
At time t=1 sec
S₁ = 0 + 9.8 (1)²/2 = 4.9m
S₁ = 4.9m
S1 is the distance covered in ist second.
At t = time (t= 2 sec)
S₂ = 0 + 9.8 (2)²/2 = 19.6m
S₂ = 19.6m
S2 is the distance covered after 2nd second.
The object fall just during the 2nd second is
S = S₂ - S₁
S = 19.6 - 4.9 = 14.7m
The object fall just during the 2nd second is 14.7m.
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Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(c) how far apart are Owen and Dina.
The distance between Dina and Owen with respect to Ed is 1.44 × 10¹² m.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In the frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Therefore, the distance between Dina and Owen with respect to Ed is:
L = L(p) √[1-(v²/c²)]
L = (1.8 × 10¹² m)√[1-(0.6c)²/c²)]
L = (1.8 × 10¹² m)(0.8)
L = 1.44 × 10¹² m
The distance is 1.44 × 10¹² m.
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Give an example of a situation in which you have experienced sound being reflected, absorbed, and transmitted.
Answer: Absorption is the transformation of radiant power to another type of energy, usually heat, by interaction with matter. The transmittance t of a medium is defined by the ratio of transmitted radiant power to incident radiant power.
Explanation:
Absorption, in wave motion, the transfer of the energy of a wave to matter as the wave passes through it. ... If there is only a small fractional absorption of energy, the medium is said to be transparent to that particular radiation, but, if all the energy is lost, the medium is said to be opaque.
Which unit abbreviation is a measurement of force?
A.
m/s
B.
m/s2
C.
N
D.
N/s
Answer:
N
Explanation:
Plato
if i apply 280 n of force to a 40kg object, what will it's acceleration be?
Answer:
f=ma
f=280N
m=40kg
a=?
280=40a
a=280/40
a=70N/kg
what is the period of an object that makes 6 revolutions a minute
Answer:
[10 section] is gonna be your answer.
A rock is thrown downward at an initial velocity of 20m/s from a 40 meter tall building, what will be its final velocity before hitting the ground?
The final velocity of the rock before hitting the ground is 34.42m/s
Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.
V = Δx/Δt
In here , V is velocity , Δx is change in displacement and Δt is change in time of an object.
We are given that,
The rock thrown downward with initial velocity = (-u) = -20m/s
The height of the building before and after hitting the ground = -Δy = -40 m
Therefore , to get the value of the final velocity (v) of the rock before hitting the ground , then the equation of motion cab be written as,
v² = u² + 2a(Δy )
Here , (a) is the acceleration due to gravity and taken negative (-9.81m/s²) due downward direction of the building then putting all the values in above equation of motion ,
v² = (-20m/s)² + 2(-9.81m/s²) (-40m)
v² = 1184.42m/s
v = 34.42m/s
Hence, the final velocity of the rock before hitting the ground would be 34.42m/s .
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Question 21 of 25
Calculate the capacitance of a system that stores 6.5 x 10-10 C of charge at
Q
50.0 V. Use C =
AV
A. 7.7 * 1010 F
B. 3.1 x 107 F
C. 1.3 x 10-11 F
D. 3.2 x 10-8 F
SUBMIT
Answer:
C. 1.3 x 10-11 F
I took the test and got this correct, hope this helps
Explanation:
This graph shows the decomposition of hydrogen peroxide as it is exposed to air. Marty claims that the graph shows that the reaction speeds up over time. Which sentence describes whether Marty is right and gives a valid reason?
Based on the graph, the correct option is that Marty is right because the change in concentration increases with time; option C.
What are decomposition reactions?
Decomposition reactions are reactions in which a large molecule splits or breaks down into two or more smaller molecules.
The general equation of a decomposition reaction is given below;
A → B + CThe decomposition of hydrogen peroxide to give water and oxygen occurs when it is exposed to air.
The given graph of the decomposition of hydrogen peroxide shows that the concentration of hydrogen peroxide decreases with time.
In conclusion, the decomposition of hydrogen peroxide in the presence of air gives oxygen and water.
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The velocity of a 48.0 g shell leaving a 2.95 kg rifle is 391. m/s. What is the recoil velocity of the rifle?
Hi there!
[tex]\large\boxed{ -6.36m/s}[/tex]
Use the equation:
[tex]v_{2} = -\frac{m_{1}}{m_{2}} v_{1}[/tex]
Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:
v2 = ?
m1 = 0.048 kg (converted)
m2 = 2.95
v1 = 391
[tex]v_{2} = -\frac{0.048}{2.95} *391[/tex]
[tex]v_{2} = -6.36m/s[/tex]
Which statement describes an example of static electricity?
A. Negatively charged particles are repelled by other negatively
charged particles
B. An insulator prevents electric charge from moving through it.
C. Electric charge flows past a point in a circuit.
D. A battery provides electrical energy to power a phone.
Answer:it’s a
Explanation:
Static electricity refers to the buildup or imbalance of electric charges on the surface of objects. The correct answer is B. An insulator prevents electric charge from moving through it.
An insulator prevents electric charge from moving through it. This statement describes an example of static electricity because insulators, such as rubber or plastic, do not allow electric charges to flow freely. When an insulator is rubbed or comes into contact with another object, it can cause the transfer of electrons between the two surfaces, leading to a buildup of static charge.
The charges remain stationary on the surfaces of the objects, resulting in an electrical imbalance without the flow of charges through the insulator.
Therefore, the correct answer is B. An insulator prevents electric charge from moving through it.
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find the force required to do 25 joule work when the force causes a displacement of 0.5 m
Answer:
50 NExplanation:
The force required can be found by using the formula
[tex]f = \frac{w}{d} \\ [/tex]
w is the workdone
d is the distance
From the question we have
[tex]f = \frac{25}{0.5} \\ [/tex]
We have the final answer as
50 NHope this helps you
An object has a mass of 40 kg. It is on a planet where the acceleration of gravity is 6.2 m/s2. What is the weight of this object?
Explanation:
The weight is 40 * 6.2 = 248N.
Answer:
248 N
Explanation:
Weight= Gravity*mass
W= 6.2*40
W= 248N
Thank you
an electron moving parallel to a uniform electric field increases its speed from 2.5×107 m/s to 3.9×107 m/s over a distance of 1.6 cm .
The electric field strength of the electron is 212143.75 N/C
To calculate the electric field strength,we use the formula below,
Formula
•E=ma/q............. equation 1
where,
E=electric field strength of the electron
m=mass of the electron
q=charge of an electron
first we need to calculate the acceleration of electron
•
[tex]v {}^{2} = u {}^{2} + 2as..........equation \: 2[/tex]
from the question,
given:
[tex]v = 3.9 \times 10 {}^{7} \frac{m}{s} [/tex]
[tex]u = 2.5 \times 10 {}^{7} \frac{m}{s} [/tex]
[tex]s = 1.6 cm = 1.2 \times 10 {}^{ - 2} [/tex]
substitute the values into equation 2
[tex](3.9 \times 10 {}^{7} ) {}^{2} = (2.5 \times 10 {}^{7} ) {}^{2} + 2(1.2 \times 10 {}^{ - 2} )a[/tex]
solve for a
[tex]1.521 \times 10 {}^{15} = 6.25 \times 10 {}^{14} + 0.024a[/tex]
[tex]a = 1.521 \times 10 {}^{15} - 6.25 \times 10 {}^{14} \div 0.024[/tex]
[tex]a = 8.96 \times 10 {}^{14} \div 0.024[/tex]
[tex]a = 3.73 \times 10 {}^{16} \frac{m}{s {}^{2} } [/tex]
Also given the following constant
[tex]m = 9.1 \times 10 {}^{ - 31} kg[/tex]
[tex]q = 1.6 \times 10 {}^{ - 19} c[/tex]
substitute these values in equation 1
[tex]e = \frac{(9.1 \times 10 {}^{ - 31})(3.73 \times 10 {}^{16} )}{1.6 \times 10 {}^{? - 19} } [/tex]
[tex] = 212143n \div c[/tex]
Hence,the electric field strength of the electron is 212143n/c
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