which atom is involved in giving your heart energy to beat

Answer:According to the context, its nucleus breaks apart is an event that occurs when an atom undergoes nuclear fission.

Explanation:

Answer:

[tex]6.373219 \times 10^6 \; meters[/tex]
or
[tex]\rm 6.373 \times 10^6 \; meters\; or\;3 \;significant \;decimal \;digits[/tex]

Explanation:

The gravitational force can be calculated with the formula:
[tex]\boxed {F_g=\dfrac{GMm}{R^2}}[/tex]

where
[tex]\rm F_g = gravitational \; force\\G = gravitational constant\\M = mass\;of\;earth\\m = mass\; of\; the \; person\\[/tex]
[tex]\rm R\;=\;distance\;from\;center\;of\;earth\;to\;surface[/tex]

Multiplying both sides of the above equation by R and dividing both sides by [tex]\rm F_g[/tex] gives us a R² in terms of the others

==> [tex]\rm R^2 = \dfrac{GMm}{F_g}[/tex]   (1)

Given

[tex]F_g = 1030 N, M = 5.97\times 10^24\;kg\; \;and \;m = 105kg\\\\[/tex]

and knowing that [tex]\rm G = 6.67 \times 10^{-11} \; Nm^2/kg^2[/tex]

substitute these values to get

[tex]\rm R^2 =\dfrac{(6.67 \times 10^{-11})(5.97 \times 10^{24})(105)}{1030}[/tex]

[tex]\rm 4.05931 \times 10^{13} = 40.5931 \times 10^{10}\\\\R = \sqrt{40.5931 x 10^{12}} \\\\= 6.373219 \times 10^6 \; meters\\\\[/tex]

3N would bring about an extension of 0.02m.

A spring force is the force required or applied to compress or stretch a spring on an object attached to it. When an object exerts a force on a spring, the spring exerts an equal and opposite force on the object. It always acts to return the mass to its equilibrium position.

so here it is given that a spring has a natural length of 0.64m.It extended 0.024 m when a load of 3.6 N is applied.

formula

F₂/F₁=x₂/x₁

so

F₂=x₂/x₁*F₁

=0.02/0.024*3.6

=3N

So from the given data and using the equation we solved the proble and got 3N as the final answer

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The average speed for the two events is 25.2 m/s

Average speed is the ratio of the total distance travelled by a body to the total time. It is measured in m/s

If you drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles. To calculate the average speed, first convert the mile to meter

1 mile = 1609.34 m

10 miles = 10 × 1609.34 = 16093.4 m

Calculate the time for each event.

speed = distance / time

time = distance / speed

T1 = 16093.4 / 20

T1 = 804.67 s

T2 = 16093.4 / 34

T2 = 473.34 s

Total time t = T1 + T2

t = 804.67 + 473.34

t = 1278.01 s

Total distance s = 16093.4 + 16093.4

s = 32186.8 m

Average speed = s / t

Average speed = 32186.8 / 1278.01

Average speed = 25.19 m/s

Therefore, the average speed for the two events is 25.2 m/s approximately.

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Answer: Juice

Explanation:

In this simple experiment, the independent variable is the type of material used to make the club head.

In golf, the bottom of the club is called the club head, or simply the head.

It is the portion of the golf club intended to strike the ball.

Clubheads are also found on putters, irons, hybrids, woods, and drivers.

Many male amateur golfers play the game at clubhead speeds of 80 to 90 mph.

The fastest LPGA pros average 90 to 100 mph. Golfers on the tour typically swing the club at rates of 110 to 115 mph or even more, while long-drive competitors can reach 140 mph.

In golf, torso rotation and wrist position at impact are the best ways to manage clubface angles.

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The "arm" of the lever is the handle or bar; it is the portion that you push or pull against. The point on which the lever rotates or balances is known as the "fulcrum.

The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.

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The purpose of the motion lab is to collect experimental data on two constant-speed cars with different constant speeds and a dynamic car showing acceleration.

The laboratory report must document the experiments and raw data included in the report,  provide sufficient information to reproduce or extend the data analyze the data, and draw conclusions. It has three main functions presenting and creating. Recommendations based on experimental work

In this lab, we were able to study projectile motion by determining the ball's initial velocity and finally predicting the projectile's range. In this projectile motion lab, we used the equations of motion for a projectile to predict distance. It combines the examination of a person's anatomy with the measurement of function during activity.

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Answer

Explanation:pressure = Force/area

Force = 4000N

Area=0.1m

pressure = 4000/0.1

=40000P.a

The length of the second pendulum on earth is 1m and on the moon 1/6m.

Given:

The time period of a second pendulum T = 2s

By using the formula T = 2π √l/g we can calculate the length of the pendulum on earth and the moon.

Here g = acceleration due to gravity and

l = the length of the pendulum.

Now

l = g(T/ 2π)^2

l = 9.8 m/s^2(2s / 2 x 3.14)^2

le = 1 m

Now calculate the length of the pendulum on the moon

T =  2π √lm/gm      ∴ gm = ge/6

Now putting the value of g we get.

or 2 = 2 π √lm / ge/6

2 = 2 π √6lm / π ^2le

lm = le/6

now given le = 1m

lm = 1/6 m

Thus the length of the second pendulum on earth is 1m and on the moon 1/6m.

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The statement is wrong and the correct average speed of the student will be 3/2 or 1.5 miles per hour.

Given in the question,

The student climbs the mountain at a speed of 1 mile per hour, then the distance traveled by the student uphill is given by

Distance = Speed × Time,

Put in the values, we get

Distance = 2 × 1 = 2 miles

So the student travels 2 miles uphill and turns around and climbs back at 3 miles per hour.

So the time taken by the student to climb back is given by

Time = Distance/Speed

Time = 2/3 hr

So Now

Total distance traveled by the student = Uphill climb  +  Downhill Climb

Total distance traveled by the student = 2 + 2

Total distance traveled by the student = 4 miles

Total time taken = Time to climb uphill +  time to climb downhill

Total time taken = 2 +  2/3 hr

Total time taken = 8/3 hr

Now average speed is given by the formula,

Average Speed  =  Total Distance traveled/Total Time taken

Average Speed  = 4 / (8/3)

Average Speed  = (4 × 3) / 8

Average Speed  = 12 / 8

Average Speed  = 3/2 miles per hour

Therefore, the statement that the average speed will be 3 miles per hour is wrong and the correct average speed of the student will be 3/2 or 1.5 miles per hour.

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The electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]

The radius of the ring is: [tex]a[/tex]

The charge on the ring is: [tex]q[/tex]

The coulomb's constant is: [tex]k = \frac{1}{{4\pi {\varepsilon _0}}}[/tex]

The expression of the electric field is: [tex]E = \frac{{kq}}{{{r^2}}}[/tex] .......(i)

Here,

[tex]r[/tex] ⇒ distance = [tex]\sqrt {{z^2} + {a^2}}[/tex]

Now, putting [tex]r[/tex] in equation (i), we get,

[tex]\begin{array}{c}\\E = \frac{{kq}}{{{{\left( {\sqrt {{z^2} + {a^2}} } \right)}^2}}}\\\\ = \frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}\\\end{array}[/tex]

The electric field along the z-direction is

[tex]dE\left( z \right) = dE\cos \theta[/tex] ........(ii)

here, [tex]\cos \theta = \frac{z}{{\sqrt {{z^2} + {a^2}} }}[/tex]

Integrating equation (ii), we get,

[tex]\begin{array}{c}\\\int {d{E_z}} = \int {dE\cos \theta } \\\\E\left( z \right) = E\cos \theta \\\end{array}[/tex].......(iii)

Now substituting the values in equation (iii), we get,

[tex]\begin{array}{c}\\E\left( z \right) = \left( {\frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}} \right)\left( {\frac{z}{{\left( {\sqrt {{z^2} + {a^2}} } \right)}}} \right)\\\\ = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}\\\end{array}[/tex]

Therefore, the electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]

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Consider a uniformly charged ring in the [tex]xy[/tex] plane, centered at the origin. The ring has radius [tex]a[/tex] and positive charge [tex]q[/tex] distributed evenly along its circumference. What is the magnitude of the electric field along the positive [tex]z[/tex] axis? Use k in your answer, where [tex]k = \frac{1}{4 \pi \epsilon_0}[/tex]

Vc=Vo * e^(-t/τ) is the equation describing the voltage across the capacitor, vc, as the capacitor is discharging in terms of the peak voltage v0 and the time constant of the circuit τ.

As we all know, a capacitor is a device that stores electrical energy in an electric field. It is composed of two conducting plates separated by an insulating material called a dielectric. When a voltage is applied to the plates, an electric field is created across the dielectric, and this field stores energy.

The voltage across a capacitor, as it is discharged, follows the equation vc=vo*e^(-t/τ). This equation describes the voltage across the capacitor, vc, in terms of the peak voltage v0 and the time constant of the circuit τ. The time constant is simply the time it takes for the voltage across the capacitor to decay to 1/e of its initial value.

So what does this all mean? Basically, the voltage across a capacitor will decay exponentially over time, and the time constant of the circuit will determine how quickly this decay occurs.

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A finds a field that is the same as the field found by B.

The physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field is known as an electric field (or E-field). Additionally, it describes the physical environment of a system of charged particles.

No matter how large the test charge is, stationary charges always produce the same electric field at a certain area.

At a distance "r" from it, the electric field created by a stationary charge "q" is given as

[tex]E = K_{q} /r^{2}[/tex]

Thus, the appropriate option is e) the same as the field found by B.

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Answer: 25.04m/s

Explanation:

v^2 = v^2o + 2a(x-xo)

v^2 = velocity 

v^2o = initial velocity 

a = acceleration 

x = final position/distance 

xo = initial position/distance

In this case, the initial velocity is 0 since the ball wasn't moving before it was dropped. The final position is 32 as the motion ended after the ball traveled 32m. The initial position is 0. The acceleration is 9.8m/s (free fall). Plug these numbers into the formula: 

v^2 = 0 + 2(9.8)(32)

v^2 = 25.04396135 

Round to get 25.04m/s

A stone is thrown vertically downward from a cliff, the initial speed of the stone is 76.246m/s.

Height of the cliff = 208m

Distance travelled during last half second = 48.5 m

According to the second equation of motion:

[tex]s1= vt + 1/2 gt^{2}[/tex]

[tex]v= (2x_{1} - gt^{2})/2t[/tex]

v= [tex]\frac{2(48.5) - (9.8)(0.5)^{2} }{2(0.5)}[/tex]

v= 94.55 m/s

If the initial speed of the ball is u,

then again from the equation of motion, we get initial speed as

u=[tex]\sqrt{v^2 - 2gh}[/tex]

=[tex]\sqrt{94.55^2 -2(9.8)(208-48.5)}[/tex]

u= 76.246 m/s

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1m² = 10000cm²

1m² = 1000000mm²

1m² = 1e-6km²

Since the magnification is equal to 1, the image height is​ the same as the object height which is 5 cm

Magnification is when the ratio of the size of the image to the size of the object is greater than 1

Given that an object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm.

To find the image height, let us first find the image distance by using the formula below

1/f = 1/u + 1/v

Substitute all the parameters

1/10 = 1/20 + 1/v

1/v = 1/10 - 1/20

1/v = (2 - 1)/20

1/v = 1/20

v = 20 cm

Magnification = v/u = H/h

20/20 = H/5

H = 5 cm

Therefore, the image height is​ the same as the object height which is 5 cm

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The stronger force of attraction between the molecule of the material and the walls of container caused the upper surface to be curved and the curved surface is known as Concave meniscus.

When the molecules of the solution or nay solvent attached to the walls of the container due to stronger attraction with the walls, it create a concave surface at the top, which is known as Meniscus and principle behind Meniscus is surface tension.

In contrast, a convex meniscus develops when the liquid’s dissolved particles are more attracted to one another than to the substance of the container, for example in barometers.

When the surface of a liquid, like as water, comes into contact with another phase (a solid, liquid, or gas), a phenomenon known as surface tension takes place, which resist the external force acting on it.

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The last shell of nitrogen has five electrons, according to the nitrogen's electron arrangement. Therefore, nitrogen has five valence electrons.

The valence shell is the final shell to be formed after the configuration of the electrons.

A valence electron is any electron that is present in a valence shell as a whole.

Eg: Since nitrogen has a 7-atomic structure, the atom will contain seven electrons.

Nitrogen's ground state electrical arrangement will be 1s22s22p3.

It has 5 valence electrons.

The number of valence electrons for neutral atoms is the same as its main group number.

An element's column on the periodic table can be used to determine its major group number.

Carbon, for instance, belongs to group 4 and has four valence electrons. With 6 valence electrons, oxygen belongs to group 6.

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velocity is in the vertical direction is 38.124m/s

Projectile motion may be defined as a particle moves along the curved pat with the constant acceleration when through near the earth surface.

It is a parabolic because it is affected by gravity.

along x axis velocity responsible for horizontal motion

along y axis velocity responsible for vertical motion

path followed by a projectile is known as a trajectory.

a ball is kicked at an angle of degrees = 33 degree

velocity  of ball, v= 70m/s

v has two components one in horizontal and in one vertical.

velocity is in the vertical direction is given by

[tex]v_{x} = v sin\theta[/tex]

[tex]v_{x} = 70 sin(33)[/tex]

[tex]v_{x} = 38.124[/tex]m/s

velocity is in the vertical direction is 38.124m/s

The given question is incomplete. The complete que is

a ball is kicked at an angle of 33 degrees relative to horizontal with a velocity of 70m/s. how much of this velocity is in the vertical direction? group of answer choices

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Answer:

Vp = 120 cos 210 + 120 sin 210 = Vi1 + Vy1     due East zero coordinates

Vp = -103.9 i - 60 j      vector description of velocity of plane

Vw = 47 j         vector description of wind

V = Vp + Vw = -103.9 i - 13 j

V = (103.9^2 + 13^2)^1/2 = 104.7

Cos θ = -103.9 / 104.7 =  187.1 deg     X-component of final velocity

Sin θ = -13 / 104.7 = 187.13 deg      Y-component of final velocity

(Final velocity = 104.7 m/s        7.1 deg S of W)

The answer is 12.6 seconds.

How long did the disk remain in the air:

Given data:

d= 137.4 meters

v=10.9 m/s

v=d/t

t=d/v

t=137.4/10.9

t=12.6 seconds.

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The concentration of (OH −) Hydroxide ions increase when the excessive base is added to the solution of Sodium Hydroxide as the base itself dissociates to give out OH −  ions which increase their concentration per unit volume.

when sodium hydroxide NaOH dissolves in water it separates into positively charged sodium ions cations and negatively charged hydroxide ions anions. these ions move round in the water, free and unbiased of every other, although cations have a tendency to be surrounded greater intently with the aid of anions and vice versa.

Sodium while sodium is added to water, the sodium melts to form a ball that moves around at the surface. It fizzes unexpectedly, and the hydrogen produced may also burn with an orange flame before the sodium disappears. The resulting huge concentration of OH- makes the solution greater basic and results in a dramatic growth inside the pH.

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Using time and velocity relationship, we concluded that he horse will be in air for 0.80 seconds.

velocity-time. In evenly accelerated, straight-line motion, the relationship between velocity and time is straightforward. The magnitude of the velocity change increases with lengthier acceleration. When acceleration is constant, the change in velocity is exactly proportional to time.

Both the horse and the human have constant accelerations, which are 0 for the horse and g downward for the human.

(A) Take into account the man's vertical motion after he leaves the limb (with v₀ = 0, yi = 3m).

Finding the man's time of fall from y = y₀ + vt + 1/2 a t² requires modeling him as a particle with continuous acceleration.

when v₀ = 0

t = √(2(y - y₀)/a)

= √ (2(0 - 3) / -9.28)

= √0.64

= 0.80s

A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0m/s, and the distance from the limb to the level of the saddle is 3.00m. (a) For what time interval is he in the air?

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The rate of deceleration of a racing car that reaches a speed of 42m/s is 7.64m/s.

Deceleration is the amount by which a speed or velocity decreases.

The rate of deceleration can be calculated using the following formula:

d = (v - u)/t

Where;

According to this question, a racing car reaches a speed of 42m/s. It then begins to decelerate, using its parachute and braking system, and comes to rest 5.5s later. The deceleration can be calculated as follows:

d = (42 - 0)/5.5

d = 42/5.5

d = 7.64m/s

Therefore, the rate of deceleration of a racing car that reaches a speed of 42 m/s is 7.64m/s.

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A horse that can run at a speed of 12 m/s will travel a distance of 52 m in a period of 4.33 seconds

We know that,

v = d / t

where,

v = Velocity

d = Distance

t = Time

Given that,

v = 12 m / s

d = 52 m

t = d / v

t = 52 / 12

t = 4.33 s

Velocity is the displacement of an object in a given amount of time. It is denoted by V.

Therefore, the time taken by the horse is 4.33 seconds

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