Which number lines have points that represent additive inverses? Check all that apply.

Which Number Lines Have Points That Represent Additive Inverses? Check All That Apply.

Answers

Answer 1
2 Answers: B and D

===================================================

Explanation:

Choice B is one answer because -2 and 2 are additive inverses that add to -2+2 = 0

Choice D is a similar story. We have -5+5 = 0

In general, if x is some number then -x is its additive inverse. So we can say x+(-x) = 0 or -x+x = 0. In short, additive inverses add to 0.

Answer 2

Answer:

B and D

Step-by-step explanation:


Related Questions

can you please help me with this question ​

Answers

Answer:

B. 4 mL

Step-by-step explanation:

What is the slope of (0,4) and (3,10)? Please helppppp a girl outt !

Answers

Answer:

M=6 OR slope=6

Step-by-step explanation:

Use slope formula

Answer:

The slope of the given line is 2

Step-by-step explanation:

Slope is defined as the change of y over the change of x or rise over run. This is calculated by subtracting the second set of vales from the first set of values.

For y:

We have 10 and 4 for the y coordinates (y is the second number in a coordinate set). We will subtract 4 from 10, to get a result of 6.

For x:

We have 3 and 0 for the x coordinates (x is the first number in a coordinate set). We will subtract 0 from 3, to get a result of 3.

Slope is 6/3 or 2/1

The slope of the given line is 2

There were 130 faculty at a conference. If there were 18 more women than men attending, how many of each gender attended the conference?

Answers

Answer:

the number of men be 56

And, the number of women be 74

Step-by-step explanation:

The computation of the number of each genders attended the conference is shown below;

Let us assume the number of men be x

And, the number of women be y

Now the equations would be

x + y = 130 .............. (1)

And,

y = 18 + x ................ (2)

Now put the y value in the equation 1

x + 18 + x = 130

2x = 130 - 18

2x = 112

x = 56

Now the y is

= 18 + 56

= 74

So, the number of men be 56

And, the number of women be 74

what are the terms in the expression 2x-4y+8?
A.) 8
B.) 2x and 4y
C.) 2x, -4y, and 8
D.) 2, 4, and 8

P.S PLS HELP DUE TODAY!!!​

Answers

I’m pretty sure is 8, because there are no like terms in there so I’m sorry if I’m wrong.

I need help Nkaocjsjbsiss

Answers

Answer:

46

Step-by-step explanation:

it wouldn't change if it was to be rotated

Kim received a discount of $8.60 when she purchased an item for $20. What was the percent of the discount?

Answers

Hi there!

The percentage of the discount is 43%

To find this answer you have to butterfly multiply, in other words, you have 8.60 over 20 (20 representing the 100% of the total amount and 8.60 being the amount of the discount that has to be found). With the two over each other in a fraction form, you multiply the numerator by the 100. Then you divide that product by the denominator. In this case it would be 8.60 x 100 divided by 20. Equaling 43.

Hope this helps!

The mean lifetime of a tire is 48 months with a standard deviation of 77 months. If 147 tires are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 0.83 months?

Answers

Answer:

0.55199

Step-by-step explanation:

When we have a random number of samples, We solve using z score formula

z = (x-μ)/σ/√n where

x is the raw score

μ is the population mean

σ is the population standard deviation

n is random number of samples

z = 0.83/77/√147

z = 0.13069

Probabilty value from Z-Table:

P(x<48.83) = 0.55199

The probability that the mean of the sample would differ from the population mean by less than 0.83 months is 0.55199

IF YOU ANSWER THIS YOU WILL HAVE BRAINLIEST AND FRIEND REQUEST

Answers

Answer:

Uhm answer what? there is no picture nor question.

Step-by-step explanation:

theres nothing there

Step-by-step explanation:

do u play among us

1. Jared borrowed $300 from his mother to buy an x-box 360. Jared will pay her back in 4 years with 3.5% simple interest. How much total money will he payback to his mother at the end of the 4 years? (Hint: which formula should you use simple or compound, what is the principal, what is the rate, what is the time.)

2. Jackie deposits $225 in an account that pays 4.1% interest compound annually. How much money would Jackie have in her account after 1.5 years? (Hint: which formula should you use simple or compound, what is the principal, what is the rate, what is the time.)

3. Stephanie placed $1,700 in an account that earns 6% interest compounded annually. How much money will she have in the account at the end of 48 months? (Hint: which formula should you use simple or compound, what is the principal, what is the rate, what is the time.) ​

Answers

Answer:

1) future value = present value x [1 + (i x n)] = $300 x [1 + (3.5% x 4)] = $342

2) using the compound interest formula:

future value = $225 x (1 + 4.1%)¹°⁵ = $238.98

Using the simple interest formula doesn't yield the same answer = $225 x [1 + (4.1% x 1.5)] = $238.84. In this case it is close due to a very short period of time and low interest rate.

3) future value = present value x (1 + i)ⁿ = $1,700 x (1 + 6%)⁴ = $2,146.21

since the interest is annual, we must convert 48 months to 4 years

Which fraction is less than 1/2?

A. 3/8

B. 5/8

C. 5/7

D. 9/16

Answers

Answer:

a. vfsvcsgefceveggevehe

A.
4/8 would be 1/2 and 3/8< 1/2
The others are above 1/2

When using substitution to solve this system of equations, what is the result of the first step x=6y+3
x+2y=5

Answers

First step: you have to plug in 6y+3 into the equation and solve
Example: 6y+3+2y = 5

The result of first step is 6y+3+3y = 5 and values of x and y after solving are 1/4 and 9/2 respectively.

What is substitution method?

The substitution method is the algebraic method to solve simultaneous linear equations. As the word says, in this method, the value of one variable from one equation is substituted in the other equation.

Given that, the two equations x=6y+3 and x+2y=5 being solved by substitution method

So, the equations are,

x=6y+3.......(i)

x+2y=5......(ii)

Substituting eq(i) in eq(ii)

6y+3+2y = 5

8y = 2

y = 1/4

Put y = 1/4 in eq(i)

x = 6x1/4+3

x = 9/2

Hence, The result of first step is 6y+3+3y = 5 and values of x and y after solving are 1/4 and 9/2 respectively.

For more references on substitution method, click;

https://brainly.com/question/14619835

#SPJ2

what is the value of x (M5/6) (M1/6)square root of 7=mxsquare

Answers

Answer:

it turns out google has the answer

Step-by-step explanation:

can i get brainlyest

5. Identify the type and subtype of each of the fol-

lowing problems.

a. Shawn has 15 marbles, which is 7 more mar-

bles than Kyle has. How many marbles does

Kyle have?

b. Tiffany has 12 blocks, 5 of which are cubes

and the rest cylinders. How many blocks are

cylinders?

c. Peter had some carrots. After he ate 3 of

them, he had 14 carrots left. How many car-

rots did Peter have before?

d. In a bag of 17 marbles, 9 marbles belong to

Kelly and the rest belong to Shauntay. How

many marbles belong to Shauntay?

Answers

Answer:

a) Kylie has 8 marbles

b) 7 Cylinders

c) 17 carrots

d) 8 marbles belong to Shauntay

Step-by-step explanation:

5. Identify the type and subtype of each of the fol-

lowing problems.

a. Shawn has 15 marbles, which is 7 more marbles than Kyle has. How many marbles does Kyle have?

Shawn = 15 marbles

S = K + 7

15 = K + 7

K = 15 - 7

K = 8 marbles

Kylie has 8 marbles

b. Tiffany has 12 blocks, 5 of which are cubes and the rest cylinders. How many blocks are cylinders?

T = 12 blocks

Cubes = 5

Cylinders = the rest

12 blocks = Cubes + Cylinders

Cylinders = 12 - Cubes

Cylinders = 12 - 5

Cylinder = 7

c. Peter had some carrots. After he ate 3 of them, he had 14 carrots left. How many carrots did Peter have before?

Number of carrots Peter has before

= Number of carrots he ate + Number of carrots he has now

= 14 + 3

= 17 carrots

d. In a bag of 17 marbles, 9 marbles belong to Kelly and the rest belong to Shauntay. How many marbles belong to Shauntay?

Total number of Marbles = 17

Kelly = 9 marbles

Shauntay = ?

Total = Kelly + Shauntay

Shauntay = Total - Kelly's marbles

= ( 17 - 9) marbles

= 8 marbles

8 marbles belong to Shauntay

Answer:

a) Kylie has 8 marbles

b) 7 Cylinders

c) 17 carrots

d) 8 marbles belong to Shauntay

Step-by-step explanation:

5. Identify the type and subtype of each of the fol-

lowing problems.

a. Shawn has 15 marbles, which is 7 more marbles than Kyle has. How many marbles does Kyle have?

Shawn = 15 marbles

S = K + 7

15 = K + 7

K = 15 - 7

K = 8 marbles

Kylie has 8 marbles

b. Tiffany has 12 blocks, 5 of which are cubes and the rest cylinders. How many blocks are cylinders?

T = 12 blocks

Cubes = 5

Cylinders = the rest

12 blocks = Cubes + Cylinders

Cylinders = 12 - Cubes

Cylinders = 12 - 5

Cylinder = 7

c. Peter had some carrots. After he ate 3 of them, he had 14 carrots left. How many carrots did Peter have before?

Number of carrots Peter has before

= Number of carrots he ate + Number of carrots he has now

= 14 + 3

= 17 carrots

d. In a bag of 17 marbles, 9 marbles belong to Kelly and the rest belong to Shauntay. How many marbles belong to Shauntay?

Total number of Marbles = 17

Kelly = 9 marbles

Shauntay = ?

Total = Kelly + Shauntay

Shauntay = Total - Kelly's marbles

= ( 17 - 9) marbles

= 8 marbles

8 marbles belong to Shauntaya) Kylie has 8 marbles

b) 7 Cylinders

c) 17 carrots

d) 8 marbles belong to Shauntay

Step-by-step explanation:

5. Identify the type and subtype of each of the fol-

lowing problems.

a. Shawn has 15 marbles, which is 7 more marbles than Kyle has. How many marbles does Kyle have?

Shawn = 15 marbles

S = K + 7

15 = K + 7

K = 15 - 7

K = 8 marbles

Kylie has 8 marbles

b. Tiffany has 12 blocks, 5 of which are cubes and the rest cylinders. How many blocks are cylinders?

T = 12 blocks

Cubes = 5

Cylinders = the rest

12 blocks = Cubes + Cylinders

Cylinders = 12 - Cubes

Cylinders = 12 - 5

Cylinder = 7

c. Peter had some carrots. After he ate 3 of them, he had 14 carrots left. How many carrots did Peter have before?

Number of carrots Peter has before

= Number of carrots he ate + Number of carrots he has now

= 14 + 3

= 17 carrots

d. In a bag of 17 marbles, 9 marbles belong to Kelly and the rest belong to Shauntay. How many marbles belong to Shauntay?

Total number of Marbles = 17

Kelly = 9 marbles

Shauntay = ?

Total = Kelly + Shauntay

Shauntay = Total - Kelly's marbles

= ( 17 - 9) marbles

= 8 marbles

8 marbles belong to Shauntay

Step-by-step explanation:

please helpwill give brainlyest

Answers

Answer:

10/9

Step-by-step explanation:

1/3+7/9=10/9

Step-by-step explanation:

= 1 + 7

3 9

= 9+21

27

= 28

27 ans

What is the slope of the line that passes through (0,0) (3,4)?

Answers

Answer:

M = 4/3 - c/3

Step-by-step explanation:

Answer:

4/3

Step-by-step explanation:

The slope formula is the difference in y over the difference in x, so 4-0/3-0.

Which rate is the lowest price?
$3.00/6 lb
$2.50/5 lb
$2.40/4 lb
$2.40/6 lb

Answers

2.40/6 I believe tell me if it is right
$3.00/6=2
$2.50/2=2
$2.40/4=.60
$2.40/6=.40 this is the lowest price

Riley needs to save at least $150 for a new phone. She has already saved $80. If she can
set aside $14 each week, how many weeks does she need to save money before she can
purchase the phone she wants?

HELP!!!

Answers

Answer:

5

Step-by-step explanation:

Since Riley has already saved 80 dollars and she needs to save 150 dollars.

150-80=70

She earns 14 dollars per week:

70/14=5

I also wrote a equation:

(150-80)/14=x

Hope this was helpful!

You can replace any letter in function notation with any number.

A.
True

B.
False

Answers

A. That would be True


If x² + xy – 3y = 3, then at the point (2, 1), dy/dx
(A) 5
(B) 4
(C) 7/3 (D) 2

Answers

Answer:

A

Step-by-step explanation:

We are given the equation:  

[tex]x^2+xy-3y=3[/tex]

And we want to find dy/dx at the point (2, 1).

Find dy/dx. We can take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}[x^2+xy-3y]=\frac{d}{dx}[3][/tex]

Implicitly differentiate:

[tex]\displaystyle 2x+y+x\frac{dy}{dx}-3\frac{dy}{dx}=0[/tex]

Solve for dy/dx:

[tex]\displaystyle \begin{aligned} x \frac{dy}{dx} - 3\frac{dy}{dx} & = -2x - y \\ \\ \frac{dy}{dx}(x - 3) & = -2x - y \\ \\ \frac{dy}{dx} & = \frac{-2x-y}{x-3} \\ \\ & = \frac{2x+y}{3-x} \end{aligned}[/tex]

To find dy/dx at (2, 1), evaluate dy/dx for x = 2 and y = 1. Hence:

[tex]\displaystyle \frac{dy}{dx}\Big|_{(2, 1)}=\frac{2(2)+1}{3 - (2)}=\frac{5}{1}=5[/tex]

Hence, our answer is A.

We want to find the differential dy/dx for the given expression at the given point. We will see that the correct option is A.

How to differentiate the expression?

We have:

x^2 + xy - 3y = 3

First, we need to isolate the variable y in one side of the equation, so we get:

xy - 3y = 3 - x^2

y*(x - 3) = 3 - x^2

y = (x - x^2)/(x - 3)

Now we can differentiate this, remember that if:

f(x) = g(x)*h(x)

then:

f'(x) = g(x)*h'(x) + g'(x)*h'(x)

Using that rule.

dy/dx = (1 - 2x)/(x - 3) - (x - x^2)/(x - 3)^2

Now we need to evaluate this in x = 2 (the x-value of the point) so we get:

(1 - 2*2)/(2 - 3) - (2 - 2^2)/(2 - 3)^2

= (-3)/(-1) - (-2)/(1) = 5

So the correct option is A.

If you want to learn more about differentiation, you can read:

https://brainly.com/question/24898810

Jessie is playing a game and bets $5 on the come out roll. If a 7 or 11 is rolled, she wins $5. This happens with a probability of 29. If a 2,3,or12 is rolled, she loses her $5. This has a probability of 19. If any other number is rolled, she does not win or lose, and the game continues. Find the expected value for Jessie on the come out roll.

Answers

Answer:

.

Step-by-step explanation:

We want to find the expected value for Jessie on the come out roll.

The expected value is EV = $0.50

We know that for an event with outcomes {x₁, x₂, ..., xₙ}, each with probability {p₁, p₂, ..., pₙ}, the expected value is given by:

EV = x₁*p₁ + x₂*p₂ + ... + xₙ*pₙ

Where the probabilities are written in decimal form.

We have the outcomes:

x₁ = winning $5.

p₁ = 0.29

x₂ = losing $5

p₂ = 0.19

x₃ = not win nor lose

p₃ = 1 - 0.19 - 0.29 = 0.52

Then the expected value is:

EV = $5*0.29 - $5*0.19 + $0*0.52 = $0.50

If you want to learn more, you can read:

https://brainly.com/question/22097128

6.) The average delivery charge for a refrigerator is $54. The standard deviation is 53. Find the
range in which at least 75% of the data values will fall.
1

Answers

Answer:

88.9%

Step-by-step explanation:

$-6.97-$114.96

Using the invNorm function on the calculator, the range of 75% of the data values is $-6.97 to $114.96. In stats, not everything makes sense.

To use the invNorm function, go to 2nd vars, invNorm. Put .75 in the area, 54 in the mean, and 53 in the standard deviation.

what does the graph of f(x)=-2/3x+490 represent

Answers

Answer:

search that question up on brainly it got the answer bruu

Step-by-step explanation:

First, write the fractions as decimals.
3
4
is
vand
11
1
2
IS
Next, plot the numbers on the number line.
The least number is
The greatest number is
The correct order from least to greatest is

Answers

Answer: d,d,a,,d,c,

Step-by-step explanation:

Answer:

ddadc

Step-by-step explanation:

A thumbtack that is tossed can land point up or point down. The probability of a tack landing point up is 0.2. A simulation was conducted in which a trial consisted of tossing 5 thumbtacks and recording the number of thumbtacks that land point up. Many trials of the simulation were conducted and the results are shown in the histogram.

Based on the results of the simulation, which of the following is closest to the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed?

A 0.09

B 0.19

C 0.28

D 0.72

E 0.91

Answers

Answer:

Option C: 0.28

Step-by-step explanation:

This is a binomial probability distribution problem.

Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;

P(X ≥ 2) = P(2) + P(3) + P(4) + P(5)

From the histogram;

P(5) = 0.02

P(4) = 0.02

P(3) = 0.05

P(2) = 0.19

Thus;

P(X ≥ 2) = 0.19 + 0.05 + 0.02 + 0.02

P(X ≥ 2) = 0.28

From the histogram, it is found that there is a 0.28 = 28% probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed, option C.

------------------

The probabilities given by the histogram are:

[tex]P(X = 0) = 0.33[/tex]

[tex]P(X = 1) = 0.39[/tex]

[tex]P(X = 2) = 0.19[/tex]

[tex]P(X = 3) = 0.05[/tex]

[tex]P(X = 4) = 0.02[/tex]

[tex]P(X = 5) = 0.02[/tex]

The probability of at least 2 up is:

[tex]P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.019 + 0.05 + 0.02 + 0.02 = 0.28[/tex]

0.28 = 28% probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed, option C.

A similar problem is given at https://brainly.com/question/24141790

How many shelves did Andrew stock per hour?

Answers

Answer:

we dont have the info

Step-by-step explanation:

Find the first six terms of the sequence defined by each of these recurrence relations and initial conditions.
a) an=6an-1, a0=2
b) an=a2n-1, a1=2
c) an=an-1+3an-2, a0=1 , a1=2
d) an=nan-1+n2 an-2 a0=1 ,a1=1
e) an= an-1+an-3 , a0=1, a1=2 , a2=0

Answers

Answer:

See explanation

Step-by-step explanation:

Solving (a):

[tex]a_n = 6a_{n-1}[/tex] where [tex]a_0 = 2[/tex]

n = 1

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_1 = 6a_{1-1}[/tex]

[tex]a_1 = 6a_{0}[/tex]

Substitute 2 for [tex]a_0[/tex]

[tex]a_1= 6 * 2[/tex]

[tex]a_1= 12[/tex]

n = 2

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_2 = 6a_{2-1}[/tex]

[tex]a_2 = 6a_{1}[/tex]

Substitute 12 for [tex]a_1[/tex]

[tex]a_2= 6 * 12[/tex]

[tex]a_2= 72[/tex]

n = 3

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_3 = 6a_{3-1}[/tex]

[tex]a_3 = 6a_2[/tex]

Substitute 72 for [tex]a_2[/tex]

[tex]a_3= 6 * 72[/tex]

[tex]a_3= 432[/tex]

n = 4

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_4 = 6a_{4-1}[/tex]

[tex]a_4 = 6a_{3}[/tex]

Substitute 432 for [tex]a_3[/tex]

[tex]a_4 = 6 * 432[/tex]

[tex]a_4 = 2592[/tex]

n = 5

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_5 = 6a_{5-1}[/tex]

[tex]a_5 = 6a_4[/tex]

Substitute 2592 for [tex]a_4[/tex]

[tex]a_5 = 6 * 2592[/tex]

[tex]a_5 = 15552[/tex]

n = 6

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_6 = 6a_{6-1}[/tex]

[tex]a_6 = 6a_{5}[/tex]

Substitute 15552 for [tex]a_5[/tex]

[tex]a_6 = 6 * 15552[/tex]

[tex]a_6 = 93312[/tex]

[tex]a_1= 12[/tex]   [tex]a_2= 72[/tex]   [tex]a_3= 432[/tex]   [tex]a_4 = 2592[/tex]   [tex]a_5 = 15552[/tex]   [tex]a_6 = 93312[/tex]

Solving (b):

[tex]a_n = a^2_{n - 1[/tex] where [tex]a_1 = 2[/tex]

We have

[tex]a_1 = 2[/tex] which serves as the first term

n =2

[tex]a_n = a^2_{n - 1[/tex]

[tex]a_2 = a^2_{2-1}[/tex]

[tex]a_2 = a^2_{1}[/tex]

Substitute 2 for [tex]a_1[/tex]

[tex]a_2 = 2^2[/tex]

[tex]a_2 = 4[/tex]

n = 3

[tex]a_3 = a^2_{3-1}[/tex]

[tex]a_3 = a^2_{2}[/tex]

[tex]a_3 = 4^2[/tex]

[tex]a_3 = 16[/tex]

n = 4

[tex]a_4 = a^2_{4-1}[/tex]

[tex]a_4 = a^2_3[/tex]

[tex]a_4 = 16^2[/tex]

[tex]a_4 = 256[/tex]

n =5

[tex]a_5 = a^2_{5-1[/tex]

[tex]a_5 = a^2_4[/tex]

[tex]a_5 = 256^2[/tex]

[tex]a_5 = 65536[/tex]

n = 6

[tex]a_6 = a^2_{6-1[/tex]

[tex]a_6 = a^2_{5[/tex]

[tex]a_6 = 65536^2[/tex]

[tex]a_6 = 4294967296[/tex]

[tex]a_1 = 2[/tex]   [tex]a_2 = 4[/tex]   [tex]a_3 = 16[/tex]   [tex]a_4 = 256[/tex]   [tex]a_5 = 65536[/tex]   [tex]a_6 = 4294967296[/tex]

Solving (c):

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] [tex]a_0=1[/tex]  ; ;  [tex]a_1=2[/tex]

[tex]a_1=2[/tex] ---- First term

n = 2

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_2=a_{2-1}+3a_{2-2}[/tex]

[tex]a_2=a_1+3a_0[/tex]

Substitute values for a1 and a0

[tex]a_2=2+3 * 1[/tex]

[tex]a_2=2+3[/tex]

[tex]a_2=5[/tex]

n = 3

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_3=a_{3-1}+3a_{3-2}[/tex]

[tex]a_3=a_{2}+3a_{1}[/tex]

[tex]a_3=5+3 * 2[/tex]

[tex]a_3=5+6[/tex]

[tex]a_3=11[/tex]

n = 4

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_4=a_{4-1}+3a_{4-2}[/tex]

[tex]a_4=a_{3}+3a_{2}[/tex]

[tex]a_4=11+3 * 5[/tex]

[tex]a_4=11+15[/tex]

[tex]a_4=26[/tex]

n = 5

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_5=a_{5-1}+3a_{5-2};[/tex]

[tex]a_5=a_{4}+3a_3[/tex]

[tex]a_5=26+3 * 11[/tex]

[tex]a_5=26+33[/tex]

[tex]a_5=59[/tex]

n = 6

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_6=a_{6-1}+3a_{6-2}[/tex]

[tex]a_6=a_{5}+3a_4[/tex]

[tex]a_6=59+3*26[/tex]

[tex]a_6=59+78[/tex]

[tex]a_6=137[/tex]

[tex]a_1=2[/tex]   [tex]a_2=5[/tex]   [tex]a_3=11[/tex]   [tex]a_4=26[/tex]   [tex]a_5=59[/tex]   [tex]a_6=137[/tex]

Solving (d):

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex];     [tex]a_0=1[/tex]; [tex]a_1=1[/tex]

[tex]a_1=1[/tex] --- First term

n = 2

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_2=2 * a_{2-1}+2^2a_{2-2}[/tex]

[tex]a_2=2 * a_1+4*a_0[/tex]

[tex]a_2=2 * 1+4*1[/tex]

[tex]a_2=2 +4[/tex]

[tex]a_2=6[/tex]

n = 3

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_3=3 * a_{3-1}+3^2 * a_{3-2}[/tex]

[tex]a_3=3 * a_{2}+9 * a_{1}[/tex]

[tex]a_3=3 * 6+9 * 1[/tex]

[tex]a_3=18+9[/tex]

[tex]a_3=27[/tex]

n = 4

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_4=4*a_{4-1}+4^2*a_{4-2}[/tex]

[tex]a_4=4*a_{3}+16*a_{2}[/tex]

[tex]a_4=4*27+16*6[/tex]

[tex]a_4=204[/tex]

n = 5

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_5=5 * a_{5-1}+5^2 * a_{5-2}[/tex]

[tex]a_5=5 * a_{4}+25 * a_{3}[/tex]

[tex]a_5=5 * 204+25 *27[/tex]

[tex]a_5=1695[/tex]

n = 6

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_6=6 * a_{6-1}+6^2*a_{6-2}[/tex]

[tex]a_6=6 * a_{5}+36*a_{4}[/tex]

[tex]a_6=6 * 1695+36*204[/tex]

[tex]a_6=17514[/tex]

[tex]a_1=1[/tex]   [tex]a_2=6[/tex]   [tex]a_3=27[/tex]   [tex]a_4=204[/tex]   [tex]a_5=1695[/tex]   [tex]a_6=17514[/tex]

Solving (e):

[tex]a_n= a_{n-1}+a_{n-3};\ a_0=1; a_1=2; a_2=0[/tex]

First term: [tex]a_1=2[/tex]

Second Term: [tex]a_2=0[/tex]

n = 3

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_3= a_{3-1}+a_{3-3}[/tex]

[tex]a_3= a_{2}+a_0[/tex]

[tex]a_3= 0+1[/tex]

[tex]a_3= 1[/tex]

n = 4

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_4= a_{4-1}+a_{4-3}[/tex]

[tex]a_4= a_{3}+a_{1}[/tex]

[tex]a_4= 1+2[/tex]

[tex]a_4=3[/tex]

n = 5

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_5= a_{5-1}+a_{5-3}[/tex]

[tex]a_5= a_{4}+a_{2}[/tex]

[tex]a_5= 3 + 0[/tex]

[tex]a_5= 3[/tex]

n = 6

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_6= a_{6-1}+a_{6-3}[/tex]

[tex]a_6= a_{5}+a_{3}[/tex]

[tex]a_6= 3 + 1[/tex]

[tex]a_6= 4[/tex]

[tex]a_1=2[/tex]   [tex]a_2=0[/tex]   [tex]a_3= 1[/tex]   [tex]a_4=3[/tex]   [tex]a_5= 3[/tex]   [tex]a_6= 4[/tex]

Use the graph to answer the question.
What is the average rate of change from x = 3 to x
= 11?
0 -8
1
001-
1
8
08

Answers

Answer:

Negative 1/8 is the answer

Someone please help...​

Answers

Answer:

y=mc

Step-by-step explanation:

QUESTION 4 of 10: Market researchers often report discretionary income. Discretionary income is your disposable income minus your fixed
expenses. Your disposable income is $2,920. After you pay fixed expenses of rent, utilities, groceries, and a car payment, you have $900.
What percentage of your disposable income is discretionary?
a) 18%
b) 31%
c) 45%
d) 69%

Answers

Answer:31

Step-by-step explanation:

Answer:

b) 31 %

Step-by-step explanation:

An employee of an auction house has a list of 25 recently sold paintings. Eight artists were represented in these sales. The sale price of each painting is on the list. Would the correlation coefficient be an appropriate way to summarize the relationship between artist (x) and sale price (y)? Why or why not?

Answers

Answer:

Step-by-step explanation:

Given that:

A list of 25 recently sold paintings in an auction house is available, and eight artists were represented in the sales.

The objective is to determine if the correlation coefficient would be an appropriate way to summarize the relationship between the artist (x) and sale price (y).

From the information given;

NO, The correlation coefficient would not be an appropriate way to summarize the relationship between artist (x) and sale price (y).

The reason is being that since variable (x) is the artist and which is regarded as the categorical variable even though it is attributed to numerical values, it cannot and will not be used in quantitative studies like correlation.  

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