Which of the following is NOT a level of organization in an ecosystem? a. community c. population b. ecosystem d. all of the above are levels of organization

Answers

Answer 1

Answer:

d. all of the above are levels of organization

Explanation:

The followings are the levels of the organization in an ecosystem

1. Individual

2. Population

3. Community

4. Ecosystem

5. Biome

6. Biosphere

So as per the given situation, it involved all three levels that are mentioned in the question

hence, the correct option is d.

Therefore the same is to be considered

Answer 2

The given option are all consisting in the level of organization of ecosystem. Thus, option D is correct.

The ecosystem has been the geographical representation comprising plants, animals, and other biotic and abiotic components.

The ecosystem has been organized in the levels for the understanding of the working and the activity of the ecosystem. The levels of the ecosystem has been:

IndividualPopulationCommunityEcosystemBiomeBiosphere

The organizational levels of the ecosystem have been comprised of community, population, and ecosystem. Thus all the given are level or organizations in the question. Thus, option D is correct.

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Related Questions

what are 3 properties of liquids

Answers

Liquids have fixed volume but no fixed shape. ...

Liquids flow from higher to lower level.

Liquids have their boiling points above room temperature, under normal conditions.

elements x and y are represented as x: atomic number 40, atomic mass 20 and y: atomic number 16 , atomic mass 8 for each of the elements write the electronic configuration using the s,p,d and f notations

Answers

Electronic configuration of x will be1s² 2s² 2p⁶ 3s² 3p⁶ 4s² and electronic configuration of y will be 1s² 2s² 2p⁴.

Given,

Atomic number of x = 20

Atomic mass = 40

Atomic number of y = 8

Atomic mass of y= 16

Electronic configuration, sometimes referred to as electronic structure or electron configuration, is the arrangement of electrons in orbitals that surround an atomic nucleus.

A standardized notation is used for expressing electron configurations, in which the energy level and type of orbital are written first, followed by the number of electrons in the orbital. For instance, the electronic structure of carbon, which has an atomic number of 6, is 1s² 2s² 2p².

So, According to the question-

As we already know that atomic number equals number of electrons.

Hence,

Electronic configuration of x = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

Electronic configuration of y = 1s² 2s² 2p⁴

The given question is erroneous , the correct question should be-

Elements x and y are represented as x: atomic number 20, atomic mass 40 and y: atomic number 8 , atomic mass 16 for each of the elements write the electronic configuration using the s, p, d and f notations.

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Using Gay-Lussac's Law, calculate what the new pressure in the following situation.
A tank of acetylene sits on the back of a truck. During the afternoon, the temperature
of a gas has reached 38°C (311 K) with a pressure of 508 kPa. That night, the
temperature drops to 29°C (302 K). Since the gas was in a metal tank, the volume
remained constant. What is the new pressure?

Answers

Answer: 311kpa

Explanation:

Calculate the number of particles in 5.0 grams of NaCl.

Answers

Answer:

5.2 × 10²² particles NaCl

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

5.0 g NaCl

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

Step 3: Convert

[tex]5.0 \ g \ NaCl(\frac{1 \ mol \ NaCl}{58.44 \ g \ NaCl} )(\frac{6.022 \cdot 10^{23} \ particles \ NaCl}{1 \ mol \ NaCl} )[/tex] = 5.15229 × 10²² particles NaCl

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

5.15229 × 10²² particles NaCl ≈ 5.2 × 10²² particles NaCl

17. Which of the following represent the correct net ionic equations from the double replacement reaction of
calcium nitrate and potassium phosphate?
a. Caaq) + PO43- (aq) → CaPO4(s)
b. Q Ca2+ (aq) + 3 PO43- (aq) → Caz(PO4)3(S)
c. 3 Ca2+ (aq) + 2 PO.3(aq) → Caz(PO4)2(S)
d. 2 NO3(aq) + Ca2+
+ Ca(NO3)2(S)

Answers

Answer:

D. 2 NO3(aq)+Ca2+

Explanation:

Reaction of calcium nitrate and potassium phosphate produce calcium phosphate and potassium nitrate. The net ionic equation for this is written as : [tex]3 Ca^{2+} (aq) +2PO_{4} ^{3-} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s)[/tex]. Thus option C is correct.

What is double displacement reaction?

In a double displacement reaction, two species or groups in reactant side are displaced in the products.

In a balanced chemical equation, all the reactants have to be in proper stochiometric ratio and the states of all species are mentioned in brackets.

In an ionic equation all the ions and charges are balanced both side and the number of each elements on both side too. The net ionic equation represents the formation of a solid product from its ions.

The balanced molecular equation and complete ionic equation are written for the given  reaction below:

[tex]3 Ca (NO_{3})_{2} (aq)+ 2K_{3} PO_{4} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s) + 6 KNO_{3}(aq)[/tex]

[tex]3 Ca^{2+} (aq) +6 NO_{3}^{-} + (aq)+ 6K^{+} + (aq) 2PO_{4} ^{3-} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s) + 6 NO_{3}^{-} (aq)+ 6K^{+} (aq)[/tex]

Now when the same species on both side is cancelled, then the net ionic equation is written as:

[tex]3 Ca^{2+} (aq) +2PO_{4} ^{3-} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s)[/tex]

Therefore, the correct et ionic equation is option c.

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Calculate the percent composition of Carbon in the
compound shown below. Record your answer with two
decimal places.
C18H18010

Answers

Answer:54.82%

Explanation:

Percentage of carbon = mass of carbon in that compound/ mass of the compund *100

216/394*100 = 54.82%

The energy diagram shows the changes in energy during a chemical reaction.
Which statement best describes the total energy change of the system?
T
Abxaua |ppuanod
Reaction progress
• A. The products have higher potential energy, and energy is
absorbed.
B. The reactants have higher potential energy, and energy is
absorbed.
C. The products have higher potential energy, and energy is released.
D. The reactants have higher potential energy, and energy is released.

Answers

The energy diagram shows the changes in energy during a chemical reaction.

Which statement best describes the total energy change of the system?

T

Abxaua |ppuanod

Reaction progress

• A. The products have higher potential energy, and energy is

absorbed.

B. The reactants have higher potential energy, and energy is

B. The reactants have higher potential energy, and energy isabsorbed.

C. The products have higher potential energy, and energy is released.

D. The reactants have higher potential energy, and energy is released.

How many molecules are in 5 moles of C10H210?

Answers

Answer:

3.0 x 10²⁴molecules

Explanation:

Given parameters:

Number of moles of compound  = 5moles

Unknown:

Number of molecules  = ?

Solution:

A mole is substance that contains the Avogadro's number of particles;

   1 mole  = 6.02 x 10²³ molecules

   5 moles of the compound will give 5 x 6.02 x 10²³ molecules

                = 3.0 x 10²⁴molecules

How many moles of gas does it take to occupy 150 L at a pressure of 4.2 atm and a temperature of 389 K?

Answers

Moles of gas=19.75

Further explanation

The gas equation can be written  

[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

V=150 L

P=4.2 atm

T=389 K

[tex]\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{4.2\times 150}{0.082\times 389}\\\\n=19.75[/tex]

Write out each of the following numbers in the long form:
1) 1 * 10 ^ 3
2)1 * 10 ^ - 5
3) 1 * 10 ^ 14
4)1 * 10 ^ - 2
5)7,* 10 ^ 4

Answers

Answer:

1000

1/100,000

1000000000000000

1/100

70,000

Long-wavelength infrared cameras detect infrared radiation with a wavelength of 1.0 x 10-5 meters. How much energy is in these waves? Talas​

Answers

Answer: The energy of the infrared radiation is [tex]19.8\times 10^{-21}J[/tex]

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

[tex]E=\frac{hc}{\lambda}[/tex]

E= energy

[tex]\lambda [/tex] = wavelength of the wave  =[tex]1.0\times 10^{-5}m[/tex]

h = Planck's constant  = [tex]6.626\times 10^{-34}Js[/tex]

c = speed of light = [tex]3\times 10^8m/s[/tex]

[tex]E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8m/s}{1.0\times 10^{-5}m}[/tex]

[tex]E=19.8\times 10^{-21}J[/tex]

Thus energy of the infrared radiation is [tex]19.8\times 10^{-21}J[/tex]

My grandmother left me some silver years ago. I opened the box containing the silver and it had tarnished. Using the equation below, if I had 300 g of silver that had tarnished and 175g H2S, which would be the limiting reactant?

Answers

Answer:

Silver Ag will be the limiting reagent.

Explanation:

The balanced reaction is:

2 Ag(s) + H₂S(g) ⇒ Ag₂S(s) + H₂(g)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

Ag: 2 moles H₂S: 1 mole Ag₂S: 1 mole H₂: 1 mole

Being:

Ag: 107.87 g/moleH: 1 g/moleS: 32 g/mole

the molar mass of the compounds participating in the reaction is:

Ag: 107.87 g/moleH₂S: 2*1 g/mole + 32 g/mole= 34 g/moleAg₂S: 2*107.87 g/mole + 32 g/mole= 247.74 g/moleH₂: 2* 1 g/mole= 2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate:

Ag: 2 mole* 107.87 g/mole= 215.74 gH₂S: 1 mole* 34 g/mole= 34 gAg₂S: 1 mole* 247.74 g/mole= 247.74 gH₂: 2* 1 mole* 2 g/mole= 2 g

If you have 175g of H₂S, you can apply the following rule of three: if by stoichiomatry 34 grams of H₂S react with 215.74 grams of Ag, 175 grams of H₂S with how much mass of Ag does it react?

[tex]mass of Ag=\frac{175 grams of H_{2}S* 215.74 grams of Ag}{34 grams of H_{2}S}[/tex]

mass of Ag= 1,110.43 grams

But 1,110.43 grams of Ag are not available, 300 gra s are available. Since you have less mass than you need to react with 175 grams of H₂S, silver Ag will be the limiting reagent.

An experiment shows that 113 mL gas sample at pressure of 721mmHg changed to 901 mmHg.
What is the new volume?

Answers

Answer:

90.4 mL

Explanation:

Step 1: Given data

Initial volume of the gas (V₁): 113 mLInitial pressure of the gas (P₁): 721 mmHgFinal volume of the gas (V₂): ?Final pressure of the gas (P₂): 901 mmHg

Step 2: Calculate the final volume of the gas

According to Boyle's law, the volume of a gas is inversely proportional to the pressure. We can calculate the final volume of the gas using the following expression.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 721 mmHg × 113 mL / 901 mmHg

V₂ = 90.4 mL

3. Gasoline, coal, batteries, and logs all have chemical energy. When they burn that chemical energy will be transformed into energy.​

Answers

Answer:

Thermal energy

Explanation:

When gasoline, coal, batteries and logs are all burn they transform chemical energy to thermal energy.

The chemical energy is the energy held between chemical chains and bonds within an atom.

When they combust, they release thermal energyChemical energy is a potential energy. The thermal energy is a kinetic energyIt increase the average motion of the particles in the mediumThe breaking bond when produces heat which is a form of thermal energy.

A soda bottle is flexible enough that the volume of the bottle can change even without opening it. If you have an empty soda bottle (volume 591 mL) at room temperature (20 degrees Celsius), what will the new volume be if you put it into a freezer (-4.0 degrees Celsius)?

Answers

The new volume = 542.6 ml

Further explanation

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

V₁=591 ml

T₁=20+273=293 K

T₂=-4+273=269 K

[tex]\tt V_2=\dfrac{V_1.T_2}{T_1}\\\\V_2=\dfrac{591\times 269}{293}\\\\V_2=542.6~ml[/tex]

Select all the statements that best describe an atom.
A. contains subatomic particles named the proton, neutron, and electron
B. is the smallest particle of an element that retains its identity in a chemical reaction
C. has no net charge and has a cloud surrounding a dense inner core
D. is the largest particle of an element that retains its identity in a chemical reaction
E. is exactly the same as every other atom and has the same properties

Answers

Answer:

a

Explanation:

contains subatomic particles named the proton,neutron and electron

An atom is the smallest particle of a substance that can take part in a chemical reaction. It is composed of subatomic particles.

The statements that best describe an atom are;

contains subatomic particles named the proton, neutron, and electronhas no net charge and has a cloud surrounding a dense inner coreis the smallest particle of an element that retains its identity in a chemical reaction

Atoms of elements are the smallest particle of the element. According to the law of conservation of mass, atoms of elements retain their identity in a chemical reaction.

An atom is composed of a massive inner core having neutrons and protons and then a cloud of charge hovering over this dense inner core.

The atom has no net charge because the number of protons and electrons are exactly equal.

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What is the volume in cubic millimeters of a 3.54 carat diamond, given that the density of diamond is 3.51 g/mL? (1 carat = 200 mg)

Answers

The volume in cubic millimeters of a 3.54 carat diamond, given that the density of diamond is 3.51 g/mL is 0.202mL.

How to calculate volume?

The volume of a substance can be calculated by dividing the mass by the density of the substance. The formula is as follows:

Volume = mass ÷ density

According to this question, a 3.54 carat diamond has a density of diamond is 3.51 g/mL. The volume is calculated as follows:

Since 1 carat = 200 mgThen, 3.54 carat = 708milligrams

708 milligrams is equivalent to 0.708grams

Volume = 0.708g ÷ 3.51g/mL

Volume = 0.202mL

Therefore, the volume in cubic millimeters of a 3.54 carat diamond, given that the density of diamond is 3.51 g/mL is 0.202mL.

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The heat of vaporization for ethanol is 0.826 kJ/g. Calculate the heat energy in joules required to boil 94.15 g of ethanol.

Answers

Answer:

The heat energy required to boil 94.15 g of ethanol is 77.7679 kJ.

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, the following formula must be followed:

a ⇒ b

c ⇒ x

Then: [tex]x=\frac{c*b}{a}[/tex]

It is called "heat of vaporization" to the energy necessary to change 1 gram of substance in solid state, to liquid state, without changing its temperature. In this case, the heat of vaporization of ethanol is 0.826 kJ / g, that is, 0.826 kJ of energy is required to change 1 gram of substance from solid state to liquid state. The thermal energy required to boil 94.15 g of ethanol can be calculated using the following rule of three: if 0.826 kJ is required to change 1 gram of ethanol, to change 94.15 grams, how much energy does it require?

[tex]energy=\frac{94.15 grams*0.826 kJ}{1 grams}[/tex]

energy= 77.7679 kJ

The heat energy required to boil 94.15 g of ethanol is 77.7679 kJ.

The heat energy in joules required to boil the ethanol is 77.77 kJ.

The given parameters;

heat of vaporization for ethanol = [tex]\Delta H_{vap}[/tex] = 0.826 kJ/gmass of the ethanol, m = 94.15 g

The heat energy in joules required to boil the ethanol is calculated as follows;

[tex]Q = m\times \Delta H_{vap}[/tex]

Q = 94.15  x  0.826

Q = 77.77 kJ

Thus, the heat energy in joules required to boil the ethanol is 77.77 kJ.

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A sample of methane, CH4, has a mass of 24.00 g. Calculate the number of methane molecules in the sample.

Answers

12 grams of carbon are still present, and 4 grams of hydrogen.

The mass of 6.022 10 23 atoms, molecules, or formula units makes up one mole of a substance, which is known as the molar mass. This value is given in grams per mole. The primary distinction between the two is the fact that molar mass provides the mass of a mole of a certain material. In contrast, molecular weight refers to a substance's molecule's mass.

A mole of CH4 weighs 16 grams.

32 grams is divided by 32 to get 2 moles.

1 mole of CH4 molecules have been eliminated, leaving just 1 mole behind (1 mole = 6.022 1023 gone).

Therefore, 12 grams of carbon are still present, and 4 grams of hydrogen.

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What is the term for metabolic pathways that use ATP to synthesize complex molecules from smaller components?
a. Anabolic pathways
b. Catabolic pathways
c. Fermentation pathways
d. Thermodynamic pathways

Answers

A Anabolic pathways.

on June 21st the rays of the sun fall directly on the Tropic of Cancer true or false pls tell the ans and I follow u​

Answers

Answer:

True

Explanation:

it does! because of the angle between Saturn and Earth and the Sun.

Hope this helps plz hit the crown :D

hi lovessssssss
Hsnsgehsndgd

Answers

hiiiiiiiiiiiiiiiiiiiiiikiiiii

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.9 g of butane is mixed with 18.5 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answers

Answer:

8.8g of CO₂ could be produced

Explanation:

The reaction of combustion of butane, C₄H₁₀, is:

C₄H₁₀ + 13/2O₂ → 4CO₂ + 5H₂O

We need to find moles of butane and oxygen to obtain the limiting reactant. With moles of limiting reactant and the chemical equation we can determine moles of CO₂ and maximum mass that could be produced:

Moles butane -Molar mass: 58.12g/mol-

2.9g * (1mol / 58.12g) = 0.050 moles butane

Moles Oxygen -Molar mass: 32g/mol-

18.5g * (1mol / 32g) = 0.578 moles oxygen

For a complete reaction of 0.050moles of butane are needed:

0.050moles of butane * (13/2mol O₂ / 1mol butane) = 0.325 moles of oxygen

As there are 0.578 moles, the limiting reactant is butane and moles of carbon dioxide produced are:

0.050moles of butane * (4mol CO₂ / 1mol butane) = 0.20 moles of CO₂

The maximum mass that could be produced is - Molar mass: 44g/mol-:

0.20 moles of CO₂ * (44g/mol) =

8.8g of CO₂ could be produced

Pancake syrup has a density of 1.37 g/cm³. A student measures the density of
pancake syrup in the laboratory and obtains a value of 1.42 g/cm³. The students
percent error is
percent.
Hint: You need to apply the significant figure rule for subtraction first; then apply
the significant figure rule for division. Do not round until the end!
Enter your answer as number without a unit. (Example: 2; 2.1; 2.20)

Answers

Percentage error is defined as the difference between estimated value and the factual value in the comparison to the factual value and is expressed as a chance.

In other words, the percent error is the relative error multiplied by 100.

Formula of the percentage error :

δ = | actual value - expected value / expected value | × 100 %

Now,

Value obtained in the laboratory, actual value = 1.42 g/cm

Expected value of syrup, expected value = 1.37 g/cm

% error = 1.42 - 1.37 / 1.37 * 100 %

= 1.036 - 1 * 100 % { rounding off }

= 1.04 - 1 * 100 %

= 0.04 * 100 %

= 4 %

% Error = 4 %

Hence, the student % error is 4 % error

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YO SOMEONE JUST ANSWER GODD
Name 3 Rectangular Items that are something you can hold. And then name those items' Length, Width, Height, Area, or Volume.

Name 2 Triangular Items that are something you can hold. And then name those items' Length, Width, Height, Area, or Volume.

Name 3-Dimensional Rectangular Items that are something you can hold. And then name those items' Length, Width, Height, Area, or Volume.

Answers

Answer: dresser table

Explanation:

table can that to

can someone help me with 5-20?

Answers

Answer:

15 is the answer your welcome

The fuel used in many disposable lighters is liquid butane, C4H10 . Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 1.00 g of butane?

Answers

of carbon is present in 4.00 g of butane.

what mass of iron sulfide is obtained if 8 grams of sulfur and 28 grams of iron are taken for the reaction?​

Answers

Mass of iron sulfide obtained : 22 g

Further explanation

Reaction

Fe+S⇒FeS

8 grams of sulfur and 28 grams of iron are taken for the reaction

Find limiting reactant

mol of Fe(Ar=56 g/mol) :

[tex]\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{28}{56}\\\\mol=0.5[/tex]

mol of S(Ar=32 g/mol) :

[tex]\tt mol=\dfrac{8}{32}=0.25[/tex]

Limiting reactant ⇒ S(smaller mol ratio), excess reactant : Fe

mol of FeS based on limiting (S) ⇒0.25(mol ratio from equation = 1 : 1)

Mass FeS(MW=88 g/mol) :

[tex]\tt mass=mol\times MW\\\\mass=0.25\times 88\\\\mass=22~g[/tex]

Commercially, liquid vegetable oils are converted to solid fats such as margarine by : Group of answer choices

Answers

Answer:

hydrogenation

Explanation:

Liquid vegetable oils are converted to solid fats such as margarine by a process known as hydrogenation.

Commercial production of margarine requires the hydrogenation of liquid oil at a relatively high temperature and pressure and in the presence of a catalyst. During the process, a solid catalyst (usually, nickel) is added to a preheated liquid vegetable oil before the dispersion of the hydrogen gas. The polyunsaturated vegetable oil, thus, becomes saturated or partially saturated in the process. The quality of the final product depends on the degree of hydrogenation or saturation.

The process of hydrogenation turns liquid vegetable oils into solid fats like margarine. therefore, the correct option is option B.

Unsaturated molecules undergo a chemical reaction called hydrogenation in which hydrogen gas is added. Unsaturated fats and oils are frequently transformed into saturated forms, which makes them more stable and solid at room temperature. Margarine, shortenings, and other solid fats are frequently made using this method. In order to increase stability, decrease reactivity, or change the physical and chemical properties of organic compounds, hydrogenation can also be employed to diminish or eliminate double or triple bonds in such molecules.

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Your question is incomplete but most probably your full question was,  

70 POINTS AND BRAINLIEST ASAPPPP
During an investigation, the contents of two test tubes were mixed in two different water baths at different temperatures. A record of the investigation is shown below:

Investigation Record
Water Bath Temperature of Bath Substances in Test Tubes
1 160 °F one test tube with deep blue colored starch and iodine solution; one test tube with saliva solution
2 80 °F one test tube with deep blue colored starch and iodine solution; one test tube with saliva solution


The deep blue color of the starch and iodine solution disappears when it reacts with saliva. Which of the following best explains the rate of disappearance of the color when the substances in the test tubes were mixed? (5 points)
Faster in Bath 1 as molecules collide more frequently in Bath 1 than Bath 2
Faster in Bath 2 as molecules collide more frequently in Bath 2 than Bath 1
Faster in Bath 1 as molecules move slower in Bath 1 than Bath 2
Faster in Bath 2 as molecules move slower in Bath 2 than Bath 1

Answers

Answer:

is there anyway u could ut it in diffrent words i do not unders stand

Explanation:

Answer:

I'd say it would be; A. Faster in Bath 1 as molecules collide more frequently in Bath 1 than Bath 2

Explanation:

I'm currently taking the FLVS exam... If I get it wrong then I'll edit asap!

Yep! I got it right. I'll provide a screenshot...

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