Which statement best describes the cart.

0.1 ml of  volumetric pipette is required to prepare 250 ml of copper sulfate solution.

Size of pipettes is determined by a wide range of factors such as physical properties of liquid,precision and accuracy of results to be obtained.

For knowing what size of pipette is to be used for making 0.015 M copper sulfate solution ,first the mass of copper sulfate to be used in making the solution is to be determined.Substituting the known parameters in the molarity formula mass of copper sulfate to be used is determined.

M=mass/molar mass×1/volume of solution in liters

mass=0.015×159.60×0.25=0.5985 g

Now to find out the volume of pipette to be used,using the density formula the volume of pipette can be obtained.

volume=0.5985/3.6=0.1

Therefore,0.1 ml of pipette is to be used for preparing 250 ml of 0.015 M copper sulfate solution.

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The required empirical formula

This is further explained below.

Generally, The empirical formula of a chemical compound is the most straightforward representation of the atom counts in the molecule as whole numbers.

As a straightforward illustration of this idea, consider the empirical formula of sulfur monoxide, which is denoted by the symbol SO, and compare it to the empirical formula of disulfur dioxide, which is denoted by the symbol S2O2.

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The number of unit cells in the given quantity is 2.23x10²³ unit cells

:Given Aluminum has an atomic mass of 27g mol-1

>Crystal is face-centered cubic structure

 >number of aluminium atoms in l0 g mass        

 so w =10g

> the number of unit cells in the given quantity is to be calculated 

Number of atoms of Al  = (mass /molar mass ) x Nₐ

                        =(w/M)xNa   , where Na =6.022x 10²³

There are 4 atoms present in the unit cell it will crystallize in a face-centered  cubic crystal
.>.On solving the above values

we get the number of unit cells as= (10/27)x 6.022x10²³ unit cells

The number of unit cells in the given quantity is 2.23x10²³  unit cells

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1. To prepare 0.5 M NiCl₂ solution, dissolve 64.8 g of NiCl₂ in 1 L of water

2. To prepare 0.5 M NiCl₂.6H₂O solution, dissolve 118.8 g of NiCl₂.6H₂O in 1 L of water

1. How to prepare 0.5 M NiCl₂ solution

We'll begin by obtaining the mole of NiCl₂. This can be obatined as follow:

Mole = Molarity x Volume

Mole of NiCl₂ = 0.5 × 1

Mole of NiCl₂ = 0.5 mole

Finally, can obtain the mass of NiCl₂ needed to prepare the solution as follow:

Mass = mole × molar mass

Mass of NiCl₂ = 0.5 × 129.6

Mass of NiCl₂ = 64.8 g

Thus, to prepare 0.5 M NiCl₂, dissolve 64.8 g of NiCl₂ in 1 L of water

2. How to prepare 0.5 M NiCl₂.6H₂O solution

We'll begin by obtaining the mole of NiCl₂.6H₂O This can be obatined as follow:

Mole = Molarity x Volume

Mole of NiCl₂.6H₂O = 0.5 × 1

Mole of NiCl₂.6H₂O = 0.5 mole

Finally, can obtain the mass of NiCl₂.6H₂O needed to prepare the solution as follow:

Mass = mole × molar mass

Mass of NiCl₂ = 0.5 × 237.6

Mass of NiCl₂.6H₂O = 118.8 g

Thus, to prepare 0.5 M NiCl₂.6H₂O dissolve 118.8 g of NiCl₂.6H₂O in 1 L of water

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Answer: 0.1533 moles of NH3

Explanation: The reaction need 2 moles of ammonia and 3 moles of copper oxide to take place. If you have 0.230 moles of copper oxide you need:

0.230/3=0.0767*2=0.1533 moles of NH3

The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.

Applied force define as the force applied to by an object to other object.applied force is contact force or a non contact force.

Friction force is the force exerted by a surface that resist the motion of body or against motion of body.friction is contact force. When the applied force increases , the frictional force also increases. when the applied force is larger than friction force object will move.

Example , if we applied force to the right direction the friction force acts in left direction.that is opposite to applied force.    

Therefore,The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.

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The molar mass of the gene is  2.22 * 10^4 g/mol and the freezing point depression is  3.35 * 10^-5 °C

We know that the osmotic pressure is obtained by the use of the formula';

π = iCRT

i = Van't Hof factor

C = concentration of the solution

R = gas constant

T = temperature

C = π/iRT

C = 0.340/1 * 62.4 * 298

C = 1.8 * 10^-5 M

Now;

n/M = C * V

12 * 10^-3/M =  1.8 * 10^-5  * 30 * 10^-3

M =  12 * 10^-3/1.8 * 10^-5  * 30 * 10^-3

M =  12 * 10^-3/ 5.4 * 10^-7

M = 2.22 * 10^4 g/mol

Mass of the solution is obtained from density * volume = 0.997 g/mL * 30.0 mL = 29.91 g

Molality of the solute = 12 * 10^-3g/ 2.22 * 10^4 g/mol * 1/ 29.91 * 10^-3

= 1.8 * 10^-5 m

ΔT = K m i

ΔT =   1.86°C/m * 1.8 * 10^-5 m * 1

ΔT = 3.35 * 10^-5 °C

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The mass of the object is obtained as  608.5 grams.

The term density refers to the ratio of the mass to the volume of an object. The density of an object does not change thus we could use the density of an object to identify that object. If we have the density of the object, that alone could be used to trace the exact kind of material that we are dealing with.

Now we know that the density of the object is 6.095 g/cm^2

Volume of the object is obtained as  99.830 mL

Density = mass/volume

mass = density * volume

mass = 6.095 g/cm^2 *  99.830 mL

mass = 608.5 grams

Hence, the mass of the object is obtained as  608.5 grams.

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Answer:

The answer(s) will be A and B

Explanation:

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In a pond, the biotic factors include:

The abiotic factors are:

Biotic factors are the living components of an environment whose activities affect the environment.

Biotic factors include plants, animals, bacteria, fungi, etc,

Abiotic factors are the non-living components of an environment that affect the environment.

Biotic and abiotic factors interact with each other.

In a pond, the biotic factors include:

The abiotic factors include:

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When 12 moles of O₂ (g) react with C₃H₈O (g) then 8 moles of CO₂ (g) is produced. This is the chemical combustion reaction of propanol producing vapor of CO₂.

Alcohols undergo combustion reaction in the presence of oxygen gas to produce vapor of CO₂ and water.

In the given equation,

2 C₃H₈O (g) + 9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)

To calculate the number of moles of CO₂ produced, first we have to balance the equation:

Divide the equation by 2

C₃H₈O (g) + 9/2 O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)

Calculate the number of moles of CO₂ (g) produced with 1 mol of O₂ (g)

9/2 O₂ (g) → 3 CO₂ (g)

1 O₂ (g) → 3÷9/2 CO₂ (g) = 0.66 mol CO₂ (g)

For 12 mol of O₂ (g),

12 × 0.66 = 8 mol CO₂ (g)

Therefore, 8 mol of CO₂ (g) is produced from 12 mol of O₂ (g).

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can't give an answer to your question if there isn't a picture or being specific in the question.

Answer: 2 Out of 4

Explanation:

Bc my mom told me

An atom's noble gas configuration starts with the elemental symbol of the last noble gas that came before it, then moves on to the arrangement of the remaining electrons.

A Lewis electron dot diagram, also known as an electron dot diagram, Lewis diagram, or Lewis structure, is a diagram that employs dots to represent the valence electrons of an atom. The number of dots corresponds to the atom's valence electron count.

Write the noble gas configuration & Lewis dot diagram for:

Be, O, AI, CI, Ni, Xe, W

The diagrams known as Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.

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Sodium bicarbonate is a white crystalline powder. NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.

Sodium bicarbonate is a white crystalline compound. It is alkaline. Sodium bicarbonate is a compound made up of sodium, hydrogen, carbon, and oxygen.

Sodium bicarbonate can be used as an antacid. It can also be used in making ear drops.  It is used in cleaning the mouth and teeth because of its  antibacterial properties.

The chemical reaction when sodium bicarbonate reacts with tartaric acid is given below:

NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.

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Answer:

Melting and boiling points are unique to the chemicals just like facial recognition. That does not necessarily means it is like a fingerprints.

Explanation:

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carbon molar mass: 12.011 x 2

hydrogen molar mass: 1.008 x 7

nitrogen molar mass: 14.0067

- add all values together:

(12.011x2) + (1.008x7) +1 4.011 = 45.09 g

The molarity of the given solution will be 0.434 M  . Since the concentration is given in percentage in mass/volume  form, the molarity of the solution will be calculated as follows:

Here,

Concentration= 4.61% m/v

Molecular mas of xylene= 106.2g/mol

Moecular mass of toulene = 92.30g/mol

Molarity is defined to be as moles of solute present per liter of solution.  Here  we are dealing with two liquids, the one having greater amount will be taken  as the solvent and the one having lower amount will be taken as the solute

4.61% m/v = 4.61 g xylene/100 ml toulene

= 4.61 g xylene/L

Now Converting this to moles / L we will get:

46.1 g xylene  x 1

mol/106.2 g = 0.434 moles xylene per L of toulene

Molarity (M) = No of moles of solute  / Volume of solute( L)

= 0.434 moles / 1 L

= 0.434 M

So, the concentration of the given solution in molarity will be equal 0.434M

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The number of cubic centimeters (cm³) in 8.14 yd³ is 6.22×10⁶ cm³

Cubic yard (yd³) can be converted to cubic centimeters (cm³) by using the folloing scale

1 yd³ = 764555 cm³

With the above conversion scale, we can obtain the number of cubic centimeters (cm³) in 8.14 yd³. Details below

From the question given above, filling data were obtained:

1 yd³ = 764555 cm³

Therefore,

8.14 yd³ = (8.14 yd³ × 764555 cm³) / 1 yd³

8.14 yd³ = 6.22×10⁶ cm³

From the calculation made above, we can conclude that there are 6.22×10⁶ cubic centimeters in 8.14 yd³

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Answer:

In order to draw the 3-D structure of an organic compound, we can use wedge-dash representation.

Answer:

pls check your question again i think you question is wrong.

If the surface temperature on Mercury has been measured to be 603 K, this temperature is equivalent to 329.84°C (degrees Celsius).

Temperature is the measure of cold or heat, often measurable with a thermometer.

Kelvin, which is denoted by K, is the International System of Units (S.I unit) or the base unit of thermodynamic temperature.

However, Kelvin can be converted to degree Celsius as follows:

K = 273.16 + °C

According to this question, the surface temperature on Mercury has been measured to be 603 K. This temperature can be converted to °C as follows:

603K = 273.16K + °C

°C = 603 - 273.16

°C = 329.84°C

Therefore, if the surface temperature on Mercury has been measured to be 603 K, this temperature is equivalent to 329.84°C (degrees Celsius).

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Any chemical compound that has carbon-hydrogen or carbon-carbon bonds is considered an organic substance in chemistry. Millions of organic compounds have been identified because of carbon's capacity for catenation.

Arrange the following compounds in the order indicated below

and explain carefully the factors that lead to each other.

The acid gets stronger the more EWG there is. Furthermore, the acid will be more potent if EWG is located closer to the source (COOH).

In sequence of increasing acidity:

(CH 3) 2CHCOOH < CH3CH2COOH < CH3COOH < ClCH2CH2COOH < ClCH2COOH

Similar to R groups, +I groups raise nitrogen's electron density, which raises an amine's basicity (an electron-rich substance is basic). The basic character of the supplied amines is influenced by the number of R groups on nitrogen. Basicity is also influenced by steric obstruction. Less basicity and more steric obstruction.

(CH3)2NH > CH3NH2 > (CH3 )3N > NH3

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