The unconscious lingering effects of a bad athletic performance may be what is currently causing an athlete distress at the thought of performing. This situation correlates with the Psychodynamic theory.
Psychodynamic theory is first coined by Sigmund Freud. It explains the origins of human behavior. According to Psychodynamic theory:
A human's feelings and actions are affected by unconscious motives.A human's feelings and actions as adults are results of childhood experiences.All actions of a human have a cause ( Mostly unconscious )In this situation, an athlete's distress at the thought of their performance is said to be a result of bad athletic performance in the past. This correlates with the second statement of Psychodynamic theory.
Therefore, Psychodynamic theory of personality explains this situation clearly.
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Calculate the potential energy stored in a cart of mass 506.8 g elevated to a height of 20.60 cm. Your
result should be reported in Joules.
A cart of mass 506.8 g elevated to a height of 20.60 cm has a stored potential energy of 1.024 J.
The energy that is held within an object because of its position in relation to a zero point is known as potential energy. An object has gravitational potential energy if it is positioned at a height above (or below) the zero height.
P.E. = mgh, where m is the mass in kilograms, g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and h is the height in meters, which is the formula for gravitational force.
Here,
Mass M = 0.5068 kg
Acceleration due to gravity, g = [tex]9.81 \frac{m}{s^{2} }[/tex]
Height, h = 0.2060 m
PE = m × g × h
= (0.5068) × (9.81) × (0.2060)
= 1.024 J
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A box has a mass of 30kg and accelerates at a rate of 3 m/s. If the force of friction on the box is 20N, how much force did YOU exert in order to move it?
The Force applied on the box to accelerates it at a rate of 3 m/s² is 404 N.
What is force?Force is a pull or push effect on a body.
The force on a body is related to the mass and the acceleration of the body.
The formula to calculate force is given below:
Force = mass * accelerationConsidering the given question;
The force involved are:
frictional forcea net force which produces acceleration of the boxthe force of gravity on the boxThe force applied on the boxForce applied = Net force + weight of the body + frictional force
weight of the body = mass * acceleration due to gravity, g
Weight of the body = 30 * 9.8 m/s
Weight of the body = 294 N
Net Force = 30 * 3 = 90 N
Force applied = 90 N + 294 N + 20 N
Force applied = 404 N
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if I have two forces pushing on an object 5n to the left and 10 N to the right, is this object balanced? why or why not?
Answer:
It is unbalanced
Explanation:
There are 5 more newtons of force being exerted toward the right.
Kinematics time question
For any physics free fall problem, a student is taught that the velocities on a graph have the same magnitude as those that are horizontally equivalent. For example, if you have two points that are both at the same height during free fall, one will be positive and the other will be negative--but they will be of the SAME magnitude.
Let's say we have a problem where an object was launched with a positive initial velocity in the upward direction. All we would have to do is change that upward initial velocity to downward (making it negative). Everything else stays the same, such as gravity.
Now here is the part where I get a bit confused. Why can we simply just use the inverse of the initial velocity without taking into account the time that has passed? Doesn't time start once the object leaves the starting point? If this is true, why can we use the same time for the kinematic equations?
The same kinematics equation is used to calculate initial velocity because the time taken to get to that point is the same time taken for the object to fall. Also, the acceleration due to gravity is constant only changing sign due to the direction of the motion.
What is kinematics?Kinematics is the study of the movement or motion of objects as well their forces that cause the motion.
Kinematics studies the interaction between forces that cause motion and the various forms of motion of the objects acted upon by the force.
Examples of kinematics include:
firing an arrowshooting a footballhitting a baseball with a baseball batThe following terms are terms involved in kinematics:
speed- this is the distance covered per unit time by a moving body.velocity- this is the displacement of a body per unit timeacceleration - this is the change in velocity of a body per unit time.In kinematics, a form of motion where a body is falling freely under gravity is known as free fall.
For a body undergoing free, its velocity could either be negative or positive depending on the direction of motion.
For a body moving against gravity, its velocity is negative whereas for a body falling to the earth, its velocity is positive.
For a body falling freely under gravity, its velocity is the same as gravity accelerates the body to a constant value of 9.81 m/s².
The time taken to get to that height above the ground is the same time it will take the objects to fall to ground.
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how does the distance from an eye chart affecr the number of letters that are recognized on a line?
The correct answer is eye chart, the position of the viewer, light in the room.
The number of letters identified on a particular line is directly related to the distance between an eye chart and the person undergoing an eye test.
Distances from the eye chart are used to identify defects in a patient's visual sight. Someone is nearsighted if they are unable to perceive objects in the distance. He will therefore see a hazy image of the letters if he looks away from the eye chart and tries to read it.
And someone with long sight is unable to perceive nearby objects. One will not be able to read the letters on the chart if they are closer to him because of his farsightedness.
Therefore, the distance from the eye chart affects the ability to perceive the letters that are displayed there.
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3. An object is dropped from 600m, If it is initially at rest, how fast will it go as it
Hits the ground?
The velocity of the object as it hits the ground, given the data from the question is 108.486 m/s
How to determine the final velocityWe'll begin by obtaining the time take to reach the ground. this is illustrated below:
Height (h) = 600 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
600 = ½ × 9.8 × t²
600 = 4.9 × t²
Divide both side by 4.9
t² = 600 / 4.9
Take the square root of both side
t = √(600 / 4.9)
t = 11.07 s
Finally, we can obtain the final velocity as follow:
Time (t) = 11.07 sInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) =?v = u + gt
v = 0 + (9.8 × 11.07)
v = 0 + 25.088
v = 108.486 m/s
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the passage below was published by montesquieu in 1748 how did these ideas influence the founding fathers of the united states
The passage below was published by Montesquieu in 1748. They decided to separate the powers of government into three branches. Option D
This is further explained below.
Who is Montesquieu?Generally, Montesquieu was a French judge, a man of letters, historian, and political philosopher.
His full name was Charles Louis de Secondat, Baron de La Brède et de Montesquieu, although he is most often known by his nickname, Montesquieu.
He is the primary originator of the notion of the separation of powers, which is incorporated into the constitutional framework of numerous countries around the globe.
In conclusion, The following text was written by Montesquieu and first appeared in print in the year 1748. They came to the conclusion that the powers of the government should be divided into three distinct branches. The D Option
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cq
The passage below was published by Baron de Montesquieu in 1748. How did these ideas influence the Founding Fathers of the United States?
answer choices
They decided to establish a constitutional monarchy.
They decided to establish a representative form of government.
They decided to separate the powers of government into three branches.
They decided each branch of government should be able to check the other branches.
. A man rows a boat in still water at 6.0km/h, he wishes to
row due north across a river 3.0km wide which is flowing
due east at 2.0km/h. calculate
a. The direction in which he must head the boat
b. The time taken to reach the other bank
The direction in which he must head the boat is 30° West of North. The time taken to reach the other bank is 0.86 hours.
Velocity of boat with respect to water, [tex]V_{BW}[/tex] = 6 km / h
Velocity of river, [tex]V_{W}[/tex] = 2 km / h E
If the boat has to reach the exact opposite side of the river from the starting point, the boat should go upstream.
Velocity of boat in upstream, [tex]V_{B}[/tex] = [tex]V_{BW}[/tex] - [tex]V_{W}[/tex]
[tex]V_{B}[/tex] = 6 - 2
[tex]V_{B}[/tex] = 4 km / h
θ = [tex]sin^{-1}[/tex] ( [tex]V_{W}[/tex] / [tex]V_{B}[/tex] )
θ = [tex]sin^{-1}[/tex] ( 2 / 4 )
θ = [tex]sin^{-1}[/tex] ( 0.5 )
θ = 30° W of N
cos θ = Adjacent side / Hypotenuse
cos 30° = 3 km / Distance covered by the boat
Distance covered by the boat = 3 / 0.87
Distance covered by the boat = 3.45 km
t = d / v
t = 3.45 / 4
t = 0.86 hr
Therefore,
The direction in which he must head the boat is 30° West of NorthThe time taken to reach the other bank is 0.86 hours.To know more about speed of boat in a river
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N
5
+5 +11
B
10
To
20
D
30
Hint: Fine the slop for each line to determine the speed
time (sec)
40
A
G
10
4
On this graph, positive positions and directions of travel are considered to be North.
1. During which time interval (AB, BC, CD, DE, EF, FG) was the cart traveling at its greatest speed?
2. During which time interval(s) (AB, BC, CD, DE, EF, FG) was the cart at rest?
3. During which time interval(s) (AB, BC, CD, DE, EF, (FG) did the cart travel in a negative direction?
4. What was the cart's instantaneous speed at 6 seconds?
5. What was the cart's instantaneous speed at 22 seconds?
6. What was the cart's instantaneous speed at 40 seconds?
7. Describe the cart's behavior between 18 and 32 seconds. (location, speed, direction of travel, and distance traveled
Answer:
h
Explanation:
1) FG
Explanation:
During which time interval (AB, BC, CD, DE, EF, FG) was the cart traveling at its greatest speed?
Aaron ran 500 meter in 100 Seconds. Find the speed in km per hour.
Answer:
50km
cuz he ran so fast in 100 seconds
Rhea, with a radius of 7.63 x 105 m, is the second-largest moon of the planet Saturn. If the mass of Rhea is 2.31 x 1021kg, what is the acceleration due to gravity on the surface of this moon?
The acceleration due to gravity on the surface of this moon:
Solution:
R = 7·63x105 m m
M = 2·31x10² 1 kg
g= GM/R2
= 6.67x10" x 2.3 x [tex]10^{21}[/tex]/[tex](7.63*10^{5} )^{2}[/tex]
=g = 15.4077 x [tex]10^{10}[/tex]/[tex](7.63)^{2} * 10^{10}[/tex]
= g = 0·2646 m/s².
An object on the Moon weighs 1/6 of its weight on the Earth's surface. This is because the gravitational acceleration on the Moon is six times that of Earth. The value of g is determined by the mass of the gigantic body and its radius. It depends on your body. The value of g is constant for months. g is called gravitational acceleration. The acceleration of an object in free fall under the influence of gravity. Expressed as the rate of increase in velocity per unit time, it is assigned a standard value of 980.665 centimeters per second per second.
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An archer shoots an arrow over flat ground. The speed of the arrow is 45m/s. A.) What is the maximum possible range of the arrow? B.) At this range, what is the maximum height? C.) What 2 angles will give a range of 90 meters?
the answer is 80 degrees so simple try solving again
In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which consists of protons with an energy of 2.8×10−11J, has a current of 80 nA. The protons in the beam mostly come to rest within the tumor. The radiologist has ordered a total dose corresponding to 3.6×10−3J of energy to be deposited in the tumor. How long should the beam be in order to deliver the required dose?
The number of protons that strike the tumor each second is [tex]1.7*10^8[/tex] protons.
What is proton beam therapy?Since it do not produce proper outcomes, proton beam therapy is only appropriate for certain types of cancer, such as highly complex brain, head and neck cancers, and sarcomas.
Here, it is mentioned that
Energy of proton = [tex]2.8*10^{-11}[/tex] Joules.
Current = 84 nA = [tex]84*10^{-9}[/tex] Ampere.
As well as
Energy of total dose = [tex]3.4*10^{-3}[/tex]
The quantity of charge per unit time is mentioned as:
Q = It = Ne
Number of proton (N) = Q/e
[tex]N=\frac{2.8*10^{-11}}{1.602*10^{-19}}[/tex]
[tex]N=1.75*10^8[/tex]
Thus, this is the number of proton in the given scenario.
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you are flying a plane at a rate of 8m/s north. the wind is blowing 6m/s south. What is your resultant
Your resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.
What are vector quantities?The quantities that have both magnitude and direction are called vector quantities. Example - velocity, acceleration, force etc.
Given in the question is a plane flying at a rate of 8m/s north and the wind is blowing 6m/s south.
In order to find the resultant, refer to the diagram attached. The north direction is represented by +y axis and south direction is represented by -y axis.
The velocity vector representing you will be [v1] = 8 j
The velocity vector representing the wind will be [v2] = - 6 j
Resultant vector [v] = v1 - v2 [Opposite and unequal vectors]
v = 8 j - 6 j
v = 2 j
Therefore, you resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.
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the muscles in a grasshopper's legs can propel the insect upward at 3.0m/s how high can the grasshopper jump
The grasshopper attains an initial velocity of 3m/seconds and with this velocity can attain a maximum height of 0.4591 metre.
What is acceleration due to gravity?Acceleration due to gravity is a constant acceleration (changes if the change in height is considerable to earth's diameter) that an object experiences towards earth. Its value near the surface is 9.8u.
Given:
Initial velocity attained by the grasshopper=3m/s
Acceleration due to gravity=9.8u
According to Newton's third law every action has an equal and opposite reaction.
It's mathematical expression for motion is v^2=u^2-2×a×s
Where-
v is final velocity of the grasshopper
u is initial velocity of the grasshopper
a is acceleration due to gravity
s is the total distance
We can only apply Newton's law of motion for those bodies which have constant acceleration. The grasshopper also has a constant acceleration due to gravity which pulls it downward.
According to question for maximum displacement the final velocity will become zero
Substituting these value in Newton's third equation of motion we get
0 - 9 = 2 × 9.8 × s
Maximum displacement of the grasshopper = 0.4591 metre.
The grasshopper attains an initial velocity of 3m/seconds and with this velocity can attain a maximum height of 0.4591 metre.
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[Honors] Vector A points in the negative x direction and has a magnitude of 25 units. The Vector B points in the
positive y direction. Find the magnitude of B if A + B has a magnitude of 35 units
The magnitude of B if A + B has a magnitude of 35 units is 24.49 units.
On paper, operations involving coplanar vectors, including addition and subtraction, can be represented. In reality, vectors are simply straight lines with arrowheads that can be drawn quickly and easily on a flat surface using a few basic rules.
Vector A is along the x-axis and vector B is along +y axis. Thus 90 is the angle between A and B ,
given |A| = 25
|A + B| = 35
We know that resultant |R| = |A + B| = √(A^2 + B^2 + 2ABcos90°)
35 = √ 25^2 + B^2 + 0
35^2 = 25^2 + B^2
B = √35^2 - 25^2
B = √1225 - 625
B = √600
B = 24.49 units.
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A long rectangular, yellow sign with diagonal black stripes on it means:
O There is a highway ahead
O Be prepared to stop
O The guardrails of a narrow bridge are ending
OYou are going the wrong way
A long rectangular, yellow sign with diagonal black stripes on it means Be prepared to stop.
Hazard warning signs consist of black diagonal stripes on a yellow background. WA-36 signs are used to mark roadway obstructions that are passable from either side. Hazard warning signs consist of black diagonal stripes on a yellow background. WA-36 signs are used to mark roadway obstructions that are passable from either side.
Warning sign. These signs warn of dangerous or unusual conditions such as curves, turns, inclines, and side streets. They are usually diamond-shaped and have black letters or symbols on a yellow background. These markings, yellow diagonal lines, are found on roads and highways to indicate narrow roads or obstructions in the lane. This area resembles a triangle with a solid yellow diagonal line inside the outline.
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WILL GIVE BRAINLIEST!!!!
According to the giant impact hypothesis, the young proto-Earth and a Mars-sized protoplanet called Theia collided. The collision ejected material into space called ejecta material. What implication could this collision have for the Moon?
Group of answer choices
Ejecta material coalesced in the Moon and formed the protoplanet Theia that collided with Earth.
Theia collected ejecta material and with it became the Moon when it coalesced and set up in Earth’s orbit.
Ejecta material formed the Moon when it set up in Earth’s orbit, coalesced, cooled down, and solidified.
Theia brought ejecta material to Earth’s orbit and became the Moon when it cooled down, and solidified.
The implication that the collision will have for the moon is D. Theia brought ejecta material to Earth’s orbit and became the Moon when it cooled down, and solidified.
What does the giant impact theory explain?The hypothesis is the prevailing explanation accepted by the scientific community, and it contends that the moon developed as a result of an object slamming into the early Earth. Earth originated from the residual dust and gas cloud surrounding the newborn sun, just like the other planets.
The Moon may have formed from the ejecta of a collision between the proto-Earth and a planet the size of Mars, according to the giant-impact scenario, also known as the Big Splash or the Theia Impact.
Therefore, based on the information, the correct option is D.
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3) If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av,
the constant, A, has the dimension of which of the following?
a) acceleration
b) length
c) time
d) area
If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av the dimension of which of the following is time.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.
A = x/v
since x is displacement and v is velocity
x/v = m/(m/s) = s
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A rollercoaster has an initial hill that is 25 meters high and a second hill that is 15 meters high. If a car starts at rest at the top of the first hill and rolls to the top of the second hill without losing any energy how fast will it be moving at the top of the second hill?
If a roller coaster loop were perfectly circular, the peak speed would be equal to vmin=gR, where g=9.8m/s2 and R is the radius of the "circle."
What type of power propels a roller coaster to the summit of a hill?Because friction and drag start depriving the car of energy right away, the first hill of a roller coaster is always the steepest part of the ride. A car's energy is virtually completely gravitational potential energy at the summit of the first slope (because its velocity is zero or almost zero).
The transformation of potential energy into kinetic energy drives the motion of a roller coaster. The potential energy of the roller coaster vehicles increases as they are propelled to the summit of the first hill. Potential energy is transformed into kinetic energy as the vehicles fall.
The potential energy will be 0 at the base of the hill.
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anybody knows what's is diffraction of waves
Answer: the spreading of waves around obstacles
Explanation:
Given a cylinder with a radius of 14.4 cm and a height of 16.8 cm, find the lateral surface area
Answer:
1520.03cm²
Explanation:
AL=2πrh=2·π·14.4·16.8
Give 3 examples of how organs systems work together
The digestive system, the circulatory system and the respiratory system all these works together for the maintenance of the body.
What are the three ways that how organs system work together?
1. The heart pumps the blood in our body, the lungs bring the oxygen in and eliminates the carbon dioxide out of the body, and the skin provides the protection and work as a barrier and safe the internal body organs.
2. The digestive, respiratory and circulatory system all these organs works together for extracting the wastes from our body but also absorbing the necessary nutrients which is good for body.
3. Our circulatory system carries the oxygen, minerals, nutrients and water and provide to cell in our body. The cells eliminated the wastes of the body through the respiratory system, by our excretory system and from our skin.
So we can conclude that the digestive system, the circulatory system and the respiratory system all these works together for the maintenance of the body.
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Starting from rest at the center of a skating rink, the two skaters shown push off from each other over a time period of 1.2 seconds.
What is the force of the push by the smaller skater?
SEE PICTURE.
Answer:
100N
Explanation:
Just took test answer is 100n
A bicycle tire contains 2.00L of gas at an absolute pressure of 7.00 x 10 5 N/m2 and temperatures
The final pressure of the tire will be 6.99 N/m²
The initial volume of tire = 2.00 L
The initial pressure of the tire = 7.00 × 10 5 N/m²
The initial temperature of the tire was 31 °C
P1V1 = P2V2
7.00 × 10 5 N/m² × V1 = 101325×100
V1 ⇒ 1.45×10^(-5) m³ = 1.45×10^(-2) L
Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)
The pressure of released gas filling the entire:
2 L = 2 L/(7.00 × 10^5 N/m² × 1.45×10^(-5) m³)
⇒ 1.197 ×10^(-4) N/m²
New pressure = 7.00 × 10^5 N/m² - 1.197 ×10^(-4) N/m²
⇒ 6.99 N/m²
Hence the New Pressure of the tire is 6.99 N/m²
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27. Raven is a geologist. She is measuring something called the porosity of a rock. The actual porosity of the rock sample is 0.114. Raven measures the porosity as 0.120. What is Raven's percent error on this
measurement?
0.0526%
0.006%
0.600%
5.26%
Raven's percentage error of the measurement is 5.26%
Formula for percentage errorPercentage error = (absolute error / standard measurement) × 100
How to determine the percentage error on the measurementThe pecenrage error of the measurement can be obtained as illustrated below:
Standard measurement = 0.114Measured value = 0.120Absolute error = 0.120 - 0.114 = 0.006Percentrage error =?Percentage error = (absolute error / standard measurement) × 100
Percentage error = (0.006 / 0.114) × 100
Percentage error = 5.26%
Thus, the perecentage error of Raven's measurement is 5.26%
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Answer:
I think the answer is 5.26%
but please let me know if I was wrong.
5.26% is the answer I got
Explanation:
1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball
1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball 13.50 N Leftwards
What is acceleration ?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
Any object's mass and acceleration in the force's direction are multiplied together to form the net force exerted on it.
Here, F = m*a
F = 1.5*9.0 = 13.50 N
Since, the acceleration is to the left, the net force also acts towards left.
13.50 N Leftwards
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What do you observe now do the same with the second plastic shopping bag square
The observation is that we will observe a large shadow in dark color on the wall.
How to illustrate the information?The light will be blocked if we place our largest plastic shopping bag between the light source and the wall.
When something stops the path of the light, the light can't pass through it, and we may see a black shadow where it can't.
Therefore, we may state that a shadow will be visible when a bag is held between a light source and a wall.
If the bag is transparent, we will still be able to see a shadow, but it won't be as dark as previously because transparent materials let some light through but not as much as other materials do.
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What do you observe if you switch on your light source. make sure it's shining onto a wall hold your largest plastic shopping bag square between the light source and the wall
Using something as a medium of exchange in transactions (money)
We can use currency as a medium of exchange in transactions because of its easy availability.
What is the basic medium of exchange for transaction?Currency is the most common medium of exchange accepted as a standard by all parties for settling economic transactions because every region or country has its specific type of currency in which they do transactions and carried out their economic activities world wide. Currency is also considered as a medium of exchange for goods and services. It is money that is present in the form of paper and coins which is issued by a government. Currency is generally accepted because of high value as a method of payment. U.S. dollars ($), euros (€), Japanese yen (¥), and pounds sterling (£) are the examples of currencies of different countries around the world.
So we can conclude that We can use currency as a medium of exchange in transactions because of its easy availability.
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A 3m beam of negligible weight is balancing in equilibrium with a fulcrum placed 1m form its left end. If a force of 50N is applied on its right end, how much force would needs to be applied to the left end.
By applying principle of moment, the force that would be needed to be applied to the left end will be 100 N
What is a Moment ?A moment is the product of a force and its perpendicular distance. It is measured in Nm
Given that a 3m beam of negligible weight is balancing in equilibrium with a fulcrum placed 1m from its left end. If a force of 50N is applied on its right end, the clockwise moment will be equal to anticlockwise moment.
The clockwise moment = 50 × 2 = 100 Nm
The anticlockwise moment = F × 1 = F Nm
Equating the two parameters gives
F = 100 N
Therefore, the force that would be needed to be applied to the left end will be 100 N
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