Which waves are electromagnetic and can travel through a vacuum?

Light and heat waves
Longitudinal and transverse waves
Sound waves
Surface waves

Answer:

Decrease the distance between the two objects.

Explanation:

The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:

F = GM₁M₂ / r²

NOTE: G is the gravitational force constant.

From the equation:

F = GM₁M₂ / r²

We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.

Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.

Considering the question given above,

To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.

Answer:

Decrease the distance between the two objects.

Explanation:

hit me wit that brainliest, please and thank you

Answer:

F = 250 [N] (Force exerted by Sunita)

Explanation:

First we must understand the use of the lever, in the attached picture we see that it is fulcrum and other features.

The moment that the load exerts with respect to the fulcrum should be calculated, as the distance is 1 [m].

[tex]M=F*d\\M=1000*1\\M=1000[N*m][/tex]

Now Sunita must exert the same moment using the remaining distance (4 [m]).

[tex]1000=F_{sunita}*4\\F_{sunita}=1000/4\\F_{sunita}=250 [N][/tex]

Answer:

The Total Mechanical Energy

As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Explanation:

Answer:

the correct result is r = 3.71 10⁸ m

Explanation:

For this exercise we will use the law of universal gravitation

          F = [tex]- \frac{m_{1} m_{2} }{r^2}[/tex]

We call the masses of the Earth M, the masses of the moon m and the masses of the rocket m ', let's set a reference system in the center of the Earth, the distance from the Earth to the moon is d = 3.84 108 m

rocket force -Earth

          F₁ = - \frac{m' M }{r^2}

rocket force - Moon

          F₂ = - \frac{m' m }{(d-r)^2}

in the problem ask for what point the force has the relation

          2 F₁ = F₂

let's substitute

          2 [tex]2 \frac{M}{r^2} = \frac{m}{(d-r)^2}[/tex]

          (d-r) ² = [tex]\frac{m}{2M}[/tex] r²

           d² - 2rd + r² = \frac{m}{2M} r²

           r² (1 -\frac{m}{2M}) - 2rd + d² = 0

Let's solve this quadratic equation to find the distance r, let's call

           a = 1 - \frac{m}{2M}

           a = 1 - [tex]\frac{7.36 10^{22} }{2 \ 5398 10^{24}}[/tex] = 1 - 6.15 10⁻³

           a = 0.99385

            a r² - 2d r + d² = 0

           r =  [tex]\frac {2d \frac{+}{-} \sqrt{4d^2 - 4 a d^2}} {2a}[/tex]

           r = [2d ± 2d [tex]\sqrt{1-a}[/tex]] / 2a

           r = [tex]\frac{d}{a}[/tex]   (1 ± √ (1.65 10⁻³)) =  [tex]\frac{d}{a}[/tex] (1 ± 0.04)

           r₁ = \frac{d}{a} 1.04

           r₂ = \frac{d}{a} 0.96

let's calculate

           r₁ = [tex]\frac{3.84 10^8}{0.99385}[/tex] 1.04

           r₁ = 401.8 10⁸ m

          r₂ = \frac{3.84 10^8}{0.99385} 0.96

          r₂ = 3.71 10⁸ m

therefore the correct result is r = 3.71 10⁸ m

Answer:

yes

Explanation:

if your destination is on the top floor, but you are facing towards the bottom floor, you are facing the wrong way. It's all relative. Honestly, I hate this question, because then it turns into, is it possible to go backwards anywhere. Backwards and forwards, right and left, it's all relative to which way you are facing and where you want to go. If something is on the left and you turn 180 degrees, then that thing is on the right. If you are going forward towards your house and you turn around, you are now going backwards, relative to your house. But if your perspective is relative to that tree in the opposite direction of your house, you are now facing the right way. See, it's all relative to where you are going.

Answer:

(a) [tex]Net\ Force = 2N[/tex] towards the right

(b) The green team wins

Explanation:

Given

[tex]Blue = 40N[/tex]

[tex]Green = 42N[/tex]

Solving (a): The net force

Because the force in the opposite directions, the net force is the subtraction of the smaller force from the bigger one.

So, we have:

[tex]Net\ Force = Green - Blue[/tex]

Substitute values for Blue and Green

[tex]Net\ Force = 42N- 40N[/tex]

[tex]Net\ Force = 2N[/tex]

Solving (b): Who wins the round

The body will move toward the Green Team because the force larger [tex](42N > 40N)[/tex]

So, the green team will win

Answer:

It is because there are a odd number of wavelengths fitting onto the string

Explanation:

The general formula for the harmonics on a string loose at one end is f = nv/2L where n = odd integer, v = speed of wave in string and L = length of string.

For a string loose at one end, there are a odd number of wavelengths which can fit onto the string. Since this is the case, we only have harmonics of odd numbers and thus we have even number harmonics missing.

Answer:

1.000 metre

Explanation:

I hope it's helpful

Answer:

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8m s2 = 9800N To draw a Free Body Diagram, draw an elevator cage (I am sure you would get lots of points for drawing it with intricate detail) with a downward force of 9800 N. I hope this helps,

Explanation:

Explanation:

❀ [tex] \underline {{\underline{ \text{Given} }}}: [/tex]

❀ [tex] \underline{ \underline{ \text{To \: find}}} : [/tex]

❀ [tex] \underline{ \underline{ \text{Solution}}} : [/tex]

[tex] \boxed{ \sf{force = mass \times acceleration}}[/tex]

Plug the known values :

⟶[tex] \sf{1000 \times 9.8}[/tex]

⟶ [tex] \sf{9800 \: N}[/tex]

[tex] \red{\boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 9800 \: N}}}}[/tex]

Hope I helped !♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

122444 Kg

Explanation:

Using the formula for gravitational force;

F= Gm1m2/r^2

Given that

G = constant of gravitation = 6.67 × 10−11 newton-metre2-kilogram−2.

m1 and m2 = the masses

r= distance of separation

Note that the question specifically mentioned that the masses are identical

so m1=m2 = m^2

F= Gm^2/r^2

Fr^2 = Gm^2

m^2 = Fr^2/G

m^2 = 1 × 1^2/6.67 × 10−11:

m =√ 6.67 × 10−11

m= 122444 Kg

Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

[tex] P = \frac{W}{t} [/tex]

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

[tex] W = F*d [/tex]

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

[tex] F = mg = 400 kg*9.81 m/s^{2} = 3924 N [/tex]

Hence, the average power is:

[tex] P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W [/tex]                    

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!                  

The average power developed by a motor as it lifts the mass is 4,900 W.

The given parameters:

The average power developed by a motor as it lifts the mass is calculated as follows;

[tex]P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{400 \times 9.8 \times 10}{8} \\\\P = 4,900 \ J/s[/tex]

Thus, the average power developed by a motor as it lifts the mass is 4,900 W.

Learn more about average power here:https://brainly.com/question/19415290

Answer:

6.75 m/s²

Explanation:

The following data were obtained from the question:

Mass (m) of object = 40 Kg

Force applied (Fₐ) = 300 N

Force of friction (Fբ) = 30 N

Acceleration (a) =?

Next, we shall determine the net force acting on the mass. This can be obtained as follow:

Force applied (Fₐ) = 300 N

Force of friction (Fբ) = 30 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 300 – 30

Fₙ = 270 N

Thus, the net force acting on the mass is 270 N.

Finally, we shall determine acceleration of the mass. This can be obtained as follow:

Mass (m) of object = 40 Kg

Net force (Fₙ) = 270 N

Acceleration (a) =?

Net force = mass × acceleration

Fₙ = m × a

270 = 40 × a

Divide both side by 40

a = 270 / 40

a = 6.75 m/s²

Therefore, the acceleration of the mass is 6.75 m/s²

Answer:

500 N

Explanation:

Given that,

The upward force is 800 N and the downward forces are 400 N, 500 N, 400 N.

At equilibrium, the upward forces will become equal to the downward forces. Let the reading in the right hand scale.

x + 800 = 400 + 500 + 400

x + 800 = 1300

x = 1300 - 800

= 500 N

So, the reading in the right hand scale is 500 N.

Answer:

The potential difference between the points is: 0.1 V

Explanation:

Given

To determine

The potential difference between the points is

We can use the formula to determine the potential difference between the points

[tex]V_A-V_B=\frac{W}{q_0}[/tex]

where W is done by moving charge q₀ from point A and point B

substituting W = 2J, and q₀ = 20 C

              [tex]=\frac{2}{20}[/tex]

               [tex]= 0.1[/tex] V

Therefore, the potential difference between the points is: 0.1 V

Answer:

1.429*10^-5 m

Explanation:

From the question, we are given that

Diameter of the cable, d = 3 cm = 0.03 m

Force on the cable, F = 2 kN

Young Modulus, Y = 2*10^11 Pa

Area of the cable = πd²/4 = (3.142 * 0.03²) / 4 = 0.0028 / 4 = 0.0007 m²

The fractional length = Δl/l

Δl/l = F/AY

Δl/l = 2000 / 0.0007 * 2*10^11

Δl/l = 2000 / 1.4*10^8

Δl/l = 1.429*10^-5 m

Therefore, the fractional length is 1.429*10^-5 m long

Answer:

Power = 0.25 Watts

Explanation:

Given:

Work done = 0.50 Joule of work

Time taken = 2.0 second

Find:

Power

Computation:

Power = Work done / Time taken

Power = 0.50 J / 2

Power = 0.25 Watts

If the tired squirrel does all this work in 2 seconds with work of 0.5 J the power is 0.25 Watts.

Given:

Mass, m = 1 kg

Work, W = 0.5 J

Time, t = 2 s

The concept of power, which measures the pace at which work is done or the rate at which energy is transmitted or converted, is crucial to physics. It measures how quickly energy is produced or utilized in a system, to put it simply. In the International System of Units (SI), power is a scalar quantity and is measured in watts (W).

The power is given by:

Power  = Work ÷ Time

P = 0.50 Joules ÷ 2 seconds

P  = 0.25 Watts

Hence, the power exerted by the tired squirrel is 0.25 Watts.

To learn more about Power, here:

https://brainly.com/question/13097380

#SPJ6

Answer:

Friction of the road on the motorcycle in the opposite direction

Explanation:

Khanacademy

Answer:

8.2N

Explanation:

I took the test and got it right :)

Answer:

5m/s/s

Explanation:

The units for velocity is m/s.

The units for acceleration is m/s/s

So, Determine the change in velocity and divide it by the time that change took place.

(30m/s - 10m/s)/4s = 20m/s/(4s) = 5m/s/s

Answer:

The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it

Explanation:

Answer:

C

Explanation:

Energy is neither created or destroyed, but it can change forms...

Answer:

If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.

Explanation:

it’s right

Answer:

638 m.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 94 m/s

Final velocity (v) = 22 m/s

Time (t) = 11 s

Distance (s) =?

We can obtain the distance travelled by using the following formula:

s = (u + v) t /2

s = (94 + 22) × 11 /2

s = 116 × 11 /2

s = 1276 /2

s = 638 m

Thus, the distance travelled is 638 m.

Answer:

your answer is C

Explanation:

Answer:

The total cost in petrol will be: RM 28.43

Explanation:

The distance to be covered is: 330 km

The car does 60 mi per 1 gallon

so we convert this into km per liter as

60 mi/gal = 60 * 1.61 / 4.5 = 21.47 km/liter

Then, if 1 liter is needed to cover 21.47 km, then to cover 330 km one would need:

330 / 21.47 liters = 15.37 liters

Since each liter costs RM 1.85, then the cost in gas will be:

1.85 * 15.37 = RM 28.43

Answer:

Explanation:

I just need points