Why does decreasing air pressure indicate an approaching storm?

Since an object's instantaneous velocity equals the derivative of its displacement at a certain point, we can also state that the instantaneous velocity at time t = 1 is around 2 meters per second.

The derivative of x with respect to t, or the upper limit of the average velocity as the elapsed time approaches 0, is the instantaneous velocity of an object:

v (t) equals d d t x (t). v (t) equals d d t x (t).

Instantaneous velocity is a vector having a dimension of length per time, similar to average velocity. The speed of an object at a specific time is its instantaneous speed. The instantaneous velocity is obtained by adding the direction to the speed.

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Answer:

Hazard

Explanation:

A hazard is a source or a situation with the potential for harm in terms of human injury or ill-health, damage to property, damage to the environment, or a combination of these.

Answer:The electrostatic force is directly related to the product of the charges and inversely related to the square of the separation distance.

Explanation:

Answer: A. use a thicker piece of wire.

Explanation:

A device that regulates how much engine power flows to a machine's moving parts, frequently made of connected sets of wheels with teeth around the edges. Hence, option C is correct.

A gear is a spinning, circular machine element with teeth that can be cut, or in the case of a cogwheel or gearwheel, they can be inserted. These teeth, known as cogs, mesh with another toothed part to transmit (convert) torque and speed. The fundamental idea underlying how gears work is comparable to the fundamental idea behind how levers work.  Cog is another casual term for gear. A power source's speed, torque, and direction can all be altered by geared devices.

So, the exact definition of gear is that gears are wheels with teeth.

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Answer:

Gears are wheels with teeth

Answer:

30 m/s

Explanation:

We can first list out the 3 kinematics equations:

[tex]v = u + at \\ {v}^{2} = {u}^{2} + 2as \\ s = ut + \frac{1}{2} a {t}^{2} [/tex]

Where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

s is the displacement

With all the 3 equations, we can now list the values needed for the first part of the question which is to find the acceleration for this first part.

Given:

v = 14 m/s

u = 6 m/s

t = 8s

We can use the first kinematics equation to solve for a. (v = u + at)

14 = 6 + a x 8

14 = 6 + 8a

8a = 14 - 6

8a = 8

a =

[tex]1 \frac{m}{ {s}^{2} } [/tex]

Now with this acceleration, we can find the final speed for the second part of the question by using the same kinematics equation. (v = u + at)

Given,

u = 14 m/s

t = 16 s

a =

[tex]1 \frac{m}{ {s}^{2} } [/tex]

v = 14 + (1)(16) = 14 + 16 = 30 m/s

Answer:

The refractor telescope has many advantages and disadvantages. One of the disadvantages is that the lenses are made of glasses therefore it has to be perfect with no air bubbles or scratches in the glass as this will impair the users viewing. Another disadvantage is that lense are weakest around the edges because they are thinnest there and that is the only place they are being supported by the telescope so this can lead to easy breakage. The lense can have colour distortion which means when white light goes through the lense it is split into colours. Since violet right is refracted more than red, the violet is brought to a focus clearer and this will make the image coloured and blurred, this is called chromatic aberration. Some advantages of refractor telescopes is that refractor telescopes are rugged meaning it is more resistant to misalignment than the reflector telescopes after their initial alignment. The glass surfaces don’t really need cleaning because it is sealed from the atmosphere this is efficient! The images are sharper, steadier and better than a reflector telescope because the tube is closed off from the outside and there will be no effects of changing temperatures or air currents. The focal length of a lense is proportional to the size of the image that is produced. Therefore if the focal length is longer the image will be larger. How bright an image will be also depends on how much light is collected by the telescope.

Answer:

See below

Explanation:

d = 1/2 a t^2

1.226 = 1/2 a (.5)^2

a = 1.226/(1/2 * .5^2)

a = 9.808 m/s^2

A researcher tests acceleration due to gravity then the acceleration due to gravity measured by the researcher is 9.808 m/s².

In mechanics, acceleration refers to the speed at which an object's velocity varies over time. how many accelerations each vector has. An object's acceleration is determined by the direction of the net force exerted on it.

Due to the fact that it has both a magnitude and a direction, acceleration is a vector quantity. Velocity is a different vector property.

According to the question,

Time, t = 0.5 seconds

Distance, s = 1.226 meters

s = 1/2 a t²

1.226 = 1/2 a (0.5)²

a = 1.226 / (1/2 *0.5²)

a = 9.808 m/s²

So, the acceleration due to gravity is 9.808 m/s².

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In a day, an electrical resistance heater uses 10 kW-h of electricity. In the same day, the heater delivers 9 kW-h of heat to the house in which it is located.

A measurement of an object's resistance to the flow of electrical current is called electrical resistance. Electrical conductance, which gauges how easily an electric current moves, is its reciprocal quantity. Mechanical friction and electrical resistance conceptually have some similarities. Electrical resistance is measured in ohms (), the SI unit of electrical resistance, whereas electrical conductance is measured in siemens (S), also known as the mho (), the SI unit of electrical conductance.

An object's resistance is significantly influenced by the material it is constructed of. Electrical insulators like rubber typically have very high resistance and low conductance, whereas electrical conductors like metals typically have very low resistance and high conductance. Resistivity or conductivity are used to measure this relationship.

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The acceleration of Laura is 5.32 m/s² and that of Healen is 3.75 m/s².

Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.

A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.

Maximum speed of Laura is [tex]\Delta_{t1} = 2s[/tex]

Maximum speed of Healen is [tex]\Delta_{t2} = 3s[/tex]

Each runs at a constant acceleration for a given time interval, giving,

[tex]\Delta x_a = \frac{1}{2} a\Delta t^2[/tex]

This reaches final velocity

⇒ [tex]v = a\Delta t[/tex]

⇒ [tex]\Delta x_v = v(T - \Delta t)[/tex]

⇒ [tex]\Delta x_v =a\Delta t(T - \Delta t)[/tex]

Each sprinter's acceleration is calculated as follows:

Laura :-

⇒ [tex]\Delta t_1 = 2s[/tex]

⇒ [tex]a_1 = \frac{100m}{18.8s^2}[/tex]

⇒ [tex]a_1[/tex] = 5.32 m/s²

Healen :-

⇒ [tex]\Delta t_2 = 3s[/tex]

⇒ [tex]a_2 = \frac{100m}{26.7s^2}[/tex]

⇒ [tex]a_2[/tex] = 3.75 m/s²

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Full question

In a women's 100 m race, accelerating uniformly, Laura takes 2.00 s and Healan 3.00 s to attain their maximum speeds, which they each maintain for the rest of the race. They cross the finish line simultaneously, both setting a world record of 10.4 s.

A) What is the acceleration of each sprinter?

In the Modified Block letter style, the date, complimentary close, and signature block are positioned approximately one-half inch to the right of center or at the right margin.

Following the proper format while writing business letters is crucial. There are specific methods that business letters have to be written.

The modified block letter style, which places one space between the body of the letter and the addresses of the sender and recipient, is one of the several letter kinds. In this form of letter, one space corresponds to around half an inch to the right of centre or at the right margin. Modified block letter formats are largely the same as full-block business letters.

Modified block format is a different extensively used format. The letter body, along with the sender and recipient's addresses, are left justified and single-spaced in this format. On the other hand, tab to the centre and start typing for the date and closure. Semi-Block. Semi-block is the last and least popular type of style.

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The minimum angle at which the box starts to slip is  20.30°, the acceleration once the box has begun to move is 1.10 m/s2 and final velocity of the box is 3.41 m/s^2.

Given:

Mass of the box m = 25.2 kg

Acceleration due to gravity g = 9.8 m/s^2

Coefficient of kinetic friction between the ramp and box  μk=0.25

Coefficient of static friction μs = 0.37

Part(A)

By inctreasing, parallel component of the weight will also increase but the force will decrease.

Let say θ be the angle of repose.

Now we know that

Ff= μs × mg × cosθ = mg × sinθ = Wp

Then we will get

θ = tan−1(μs)

θ = tan-1 (0.37) = 20.30 °

Part(B)

As the box starts sliding the frictional force becomes kinetic friction

The kinetic frictional force

F(k) = μ(k) x mg x cos(20.30)

= 0.25 × 25.2 × 9.8 × cos (20.30)

= 57.91 N

Now calculate the parallel component of the weight

W(p) = mg x sinθ

W(p) = 25.2 x 9.8 x cos (20.30)

= 85.68 N

Now calculate net force

F(net) = W(p) − F(k) = 85.68 − 57.91 = 27.77 N

Acceleration of the box

a = Fn/m = 27.77/25.2 = 1.10 m/s2

Part(C)

The box has moved a distance s = 5.3 m

The final speed of the box = v

Now

v = √ 2as

v = √ 2 x 1.10 x 5.3

v = 3.41 m/s^2

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The complete question is

A 25. 0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0. 250, and the coefficient of static friction is 0. 350. Part A) As the angle θ is increased, find the minimum angle at which the box starts to slip. Express your answer using two significant figures. Part B) At this angle, find the acceleration once the box has begun to move. Express your answer using two significant figures. Part C) At this angle, how fast will the box be moving after it has slid a distance 5.3 m along the loading ramp? Express your answer using two significant figures.

The accelerations for each problem are:

1. 2.22m/[tex]s^{2}[/tex]

2. 7m/[tex]s^{2}[/tex]

3. 1.45m/[tex]s^{2}[/tex]

4. 20m/[tex]s^{2}[/tex]

The acceleration which is gained by the object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/[tex]s^{2}[/tex]. Acceleration due to gravity is a vector, which means it has both magnitude and direction. The acceleration due to gravity at the surface of the Earth is represented by letter g. It has standard value defined as 9.80665 m/s2 (32.1740 ft/s2). However, actual acceleration of a body in free fall varies with location.

1. Initial velocity=0 km/h

Final velocity=24 km/h= 6.66m/s

Time=3 seconds

acceleration =[tex]\frac{6.66-0}{3}[/tex]=2.22m/[tex]s^{2}[/tex]

2. Initial velocity=0 km/h

Final velocity=35 m/s

Time=5 seconds

acceleration = [tex]\frac{35-0}{5}[/tex]=7m/[tex]s^{2}[/tex]

3. Initial velocity=20 km/h=5.55[tex]m/s^{2}[/tex]

Final velocity=60 km/h= 20m/[tex]s^{2}[/tex]

Time=10 seconds

acceleration= [tex]\frac{20-5.55}{10}[/tex]= 1.45m/[tex]s^{2}[/tex]

4. Initial velocity=50 m/s

Final velocity=150 m/s

Time=5 seconds

acceleration= [tex]\frac{150-50}{5}[/tex]= 20m/[tex]s^{2}[/tex]

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Answer: solid state

Explanation:

The change from the liquid state to the solid state is called freezing. As the liquid cools, it loses thermal energy. As a result, its particles slow down and come closer together. Attractive forces begin to trap particles, and the crystals of a solid begin to form.

a) her speed is  26.43m/s

b)  Total distance traveled = 100 + 49.89

= 149.89m

c) Total time is 10.846 seconds

acceleration is the rate of change of the velocity of an object with respect to time.

From the question,

a) The car’s speed just after leaving the icy portion of the road is the first part

We have s = ut + 1/2at²

Here s = 100m, a = 1, u = 33.5 m/s

100 = 0* t + 1/2 * (-1) * t²

t = 7.07 seconds

After 7.07 seconds cars speed is given by v =u +at

u = 33.5m/s, a = -1

velocity = 33.5 + (-1) * 7.07 = 26.43m/s

So velocity of car on leaving icy surface = 26.43m/s

b) Time taken after icy surface

           0 = 26. 43 - 7 * t

            t = 3.776 seconds

 Distance traveled during this time

v² = u² + 2as

0 = (26.43)² + 2 * (-7) * S

s = 49.89 m

Total distance traveled = 100 + 49.89

= 149.89m

c) Total time taken = 3.776 + 7.07

Total time is 10.846 seconds

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The minimum heat required is 129.7KJ.

Given

Mass of water (m) = 50g

Initial temperature [tex]T_{i}[/tex] = 20°C

Final temperature [tex]T_{f}[/tex] = 100°C

Specific heat of water =4190 J/kg-k

The heat of vaporization (L) = 22.6 × 10 5 j/kg .

The heat required = Heat required to raise water temperature from 20 to 100 + Heat to vapourize water thoroughly.

Q=mc([tex]T_{f} - T_{i}[/tex]) + mL

Q=0.05 * 4190 (100-20) + 0.05 * 22.6 × [tex]10^{5}[/tex]

Q=(0.16760 + 1.13)× [tex]10^{5}[/tex]

Q=1.2976 × [tex]10^{5}[/tex]

  = 129.7KJ

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Answer:

A hiker drops a heavy stone over a cliff and hear it strike the cliff base 2.8seconds after dropping it.

As we know velocity is the rate of change of position with respect to time.

Mathematically  [tex]Velocity = \frac{Position}{Time}[/tex]

Also, in a position-time graph, the velocity of a moving object can be represented by the slope of the graph i.e. Tan[tex]\alpha[/tex].

[tex]\alpha[/tex] is the angle made by the slope by the horizontal X-axis.

Distance travelled by the object is recorded on the Y-axis and time taken to complete that particular distance is noted on X-axis.

[tex]Tan\alpha = \frac{Position}{Time}[/tex]

[tex]Tan\alpha = Velocity = \frac{x}{t}[/tex]

According to the graph

for x = 8m, t = 2s

[tex]Tan \alpha = \frac{8}{2}[/tex] = 4 m/s

for x = 12m, t = 3s

[tex]Tan\alpha = \frac{12}{3}[/tex] = 4 m/s

Therefore for every change in distance, the time changes linearly which gives constant velocity as 4m/s.

Option (d) 4 m/s

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Answer:

Choice C

Explanation:

In any programming language, the variable cannot be in quotes.

Many languages regard a string as literal if it is surrounded by a single quote rather than a double quote. Any computer language prohibits putting quotations around a variable. Thus, option C is correct.

Only letters (including uppercase and lowercase characters), numbers, and underscore are permitted in variable names.

A variable's first letter must either be a letter or an underscore. There is no restriction on the length of a variable name or identifier.

Usually, an experiment contains independent, dependent, and controlled variables.

Therefore, A variable in programming is a value that can change based on external factors or data that has been supplied to the program.

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The cheetah that can go from a state of resting to running at 20 m/s in just 2 seconds has an average acceleration of: 10 m/s²

The formulas for uniformly varied rectilinear motion (UVRM) and procedures we will use to solve this exercise are:

a = (vf - vi) /t

Where:

Information about the problem:

Applying the acceleration formula we have:

a = (vf - vi) /t

a = (20 m/s - 0 m/s) /2 s

a = (20 m/s) /2 s

a =  10 m/s²

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:

Not really, because wearing a mask can lower your immune system and covid can be caught like any other virus body contact and body fluids. So since you can still get it through those ways then you're going to get it and be worse off than if you don't wear a mask.

you can test this by not wearing a mask and see how not bad it is catching covid over getting it while you wear a mask.

Explanation:

Answer:

Yes

Explanation:

Hypothesis- if masks are used to protect yourself from Covid-19 then the spread of the virus will decrease

You could test this by:

Getting a mask and using materials such as shampoo, soap, honey, glue,  or (safe) chemicals to see how much the masks absorbs the materials. By doing so you can show how the mask can help block certain materials from entering or leaving the mask area therefore slowing the spread of Covid.

The true statement for sinusoidal wave travelling  along a light weight string =

lambda₂<  lambda₁  and f₂ = f₁

λ₂ ≤ λ₂

The sine or sinusoidal wave may be a curve that describes a smooth repetitive oscillation. we will define the sine wave as “The wave form in which the amplitude is always proportional to sine of its displacement angle at every point of time”. All waves are often made by adding up sine waves

Then the waveform shape produced by our simple single loop generator is usually referred to as a Sine Wave as it is said to be sinusoidal in its shape. this sort of waveform is called a sine wave because it is based on the trigonometric sine function used in mathematics.

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Ship A with a greater angle of projection will hit the target first.

The time of flight is the time a projectile takes to reach maximum height and return to the plane of projection. The time of flight is just double the maximum-height time.

Mathematically, time of flight is given as;

T = (2usinθ)/g

where;

The time of flight depends on initial velocity of the object and angle of projection.

When the initial velocity of both ships is the same and angle of projection varies, the difference in the time of flight will depend greatly on the angle of projection.

Thus, ship A with a greater angle of projection will hit the target first.

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The statement "displacement tells the average direction of motion" regarding displacement is true.

Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.

A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.

Average velocity is calculated by taking the displacement vector from the start and end-point of an object’s path, and dividing its magnitude by the time interval. The average velocity always has the same direction as that displacement vector.

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Answer:

John Dalton

Explanation:

Answer:

chemist John Dalton

Explanation:

:)

The average speed for the entire journey is 48 km/hr.

The average speed is the sum distance which is traveled by the object in a particular time interval, as the average speed is a scalar quantity and it is presented by the magnitude and has no direction.

here the first speed v₁ is 60 km/hr and the second speed v₂ is the 40 km/hr .So,  The formula we are referring to for calculating the average  speed

  S = 2v₁v₂/(v₁+v₂)

here,   v₁+v₂ =  60+40 =100

Now substituting the desired values  in the formula  

        =  2 x 60 x40/(100)

       =  4800/100

       = 48 km/hr

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The acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².

The acceleration of a moving substance can be calculated by dividing the change in velocity by the time taken as follows:

a = (v - u)/t

Where;

According to this question, an airplane was flying from Cincinnati to Denver. The velocity of an airplane was measured shortly after take off at 10km/min. The velocity was measured again mid-flight to be 18km/min.

a = (18km/min - 10km/min)/90min

a = 8km/min ÷ 90min

a = 0.09km/min²

Therefore, acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².

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The magnitude of force applied to the nails when they are located between point A and B is 37.5 N.

The magnitude of force applied to the nails when they are located between point B and C is 62.5N.

The force applied to the nails when they are located between point A and C is 29.41N

The moment exerted by the drill machine is: M =15 N⋅m

(a) The magnitude of force applied to the nails when they are located between point A and B.

Fa=M/AB

AB is distance between points A and B.

Plug in all the values in the above equation.

Fa=15 N⋅m/450mm

=15 N⋅m/0.45m

=37.5 N

Therefore, the magnitude of force applied to the nails when they are located between point A and B is 37.5 N.

(b)The magnitude of force applied to the nails when they are located between point B and C.

Fb=M/BC

BC is distance between points B and C.

Substitute all the values in the above equation.

Fb=15 N.m/240mm

=15 N.m/0.24m

= 62.5N

Thus, the magnitude of force applied to the nails when they are located between point B and C is 62.5N.

(c) The distance between points AC is,

AC=√(AB)2+(AC)2

Plug in all the values in the above equation.

AC=√(450mm)2 +(240mm)2

=510mm

=0.51m

The magnitude of force applied to the nails when they are located between point A and C.

Fc=M/AC

Substitute all the values in the above equation.

Fc=15 N⋅m/0.51m

=29.41 N

Thus, the force applied to the nails when they are located between point A and C is 29.41N

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Answer: Volume=0.030/0.75

Explanation:

Density= mass/volume ∆density= mass/volume

(1.29- 0.54)= 0.030/volume

0.75 volume= 0.030 Volume=0.030/0.75

The distance between you and the deer when you come to a stop is

s = d - 30 = 18 m.

The maximum speed you could have and still not hit the deer is

v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]

  = 26m/s

You're driving down the highway late one night at 20m/s when a deer steps onto road d in front of you.

Your reaction time before stepping on the brakes is 0.50s and the maximum deceleration of your car is 10m/s2.

Given,

Speed = 20m/s

Time = 0.50 s

Distance = d

Deceleration = 10m/s2

D = R × T

D = Vi × Tr

D = (20 m/s) × (0.50 s)

D = 10 m

Dd = [ Vf^2 - Vi^2 ] / [ 2 × (-10 m/s^2) ]

Dd = [ (0.0 m/s)^2 - (20 m/s)^2 ] / (-20 m/s^2)

Dd = [ -400 m^2/s^2 ] / (-20 m/s^2)

Dd = 20 m

The total distance traveled is

Dt = D + Dd

Dt = (10 m) + (20 m)

Dt = 30 m

The distance between you and the deer when you come to a stop is

s = d - 30 = 18 m.

The maximum speed you could have and still not hit the deer is

v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]

  = 26m/s

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