The concentration of the new solution, given that 2/3 of it's initial volume was boiled away is 0.758 M
We'll begin by obtaining the new volume of the solution.This can be obtained as follow:
Volume of stock solution (V₁) = 1 mL Volume of water boiled away = 2/3 = 0.67 mL Volume of new solution (V₂) = ?V₂ = 1 - 0.67
V₂ = 0.33 mL
How to determine the concentration of the new solutionThe concentration of the new solution can be obtained as follow:
Concentration of stock solution (M₁) = 0.250 MVolume of stock solution (V₁) = 1 mL Volume of new solution (V₂) = 0.33 mL Concentration of new solution (M₂) =?M₁V₁ = M₂V₂
0.250 × 1 = M₂ × 0.33
0.250 = M₂ × 0.33
Divide both side by 0.33
M₂ = 0.250 / 0.33
M₂ = 0.758 M
From the calculation made above, we can conclude that the concentration of the new solution is 0.758 M
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What is the concentration in molarity of a solution which is 4.61 %m/v
xylene (MM = 106.2 g/mol ) in toluene (MM = 92.30 g/mol)?
The molarity of the given solution will be 0.434 M . Since the concentration is given in percentage in mass/volume form, the molarity of the solution will be calculated as follows:
Here,
Concentration= 4.61% m/v
Molecular mas of xylene= 106.2g/mol
Moecular mass of toulene = 92.30g/mol
Molarity is defined to be as moles of solute present per liter of solution. Here we are dealing with two liquids, the one having greater amount will be taken as the solvent and the one having lower amount will be taken as the solute
4.61% m/v = 4.61 g xylene/100 ml toulene
= 4.61 g xylene/L
Now Converting this to moles / L we will get:
46.1 g xylene x 1
mol/106.2 g = 0.434 moles xylene per L of toulene
Molarity (M) = No of moles of solute / Volume of solute( L)
= 0.434 moles / 1 L
= 0.434 M
So, the concentration of the given solution in molarity will be equal 0.434M
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how do you get that 1000g = 1 kg
Arrange the following compounds in the order indicated below
and explain carefully the factors that lead to each other.
(a)
Increasing acid strength, CH,COOH, CH,CH.COOH,
CHFCOOHCH,CHCICOOH, CHCICH CH.COOH.
CHICCI,COOH, CH,CHCICOOH, CHCOOH,
(b) Decreasing base strength: NH,CH,, N(CH),.
(CH,)NH, CHÍNH
Any chemical compound that has carbon-hydrogen or carbon-carbon bonds is considered an organic substance in chemistry. Millions of organic compounds have been identified because of carbon's capacity for catenation.
Arrange the following compounds in the order indicated below
and explain carefully the factors that lead to each other.
The acid gets stronger the more EWG there is. Furthermore, the acid will be more potent if EWG is located closer to the source (COOH).
In sequence of increasing acidity:
(CH 3) 2CHCOOH < CH3CH2COOH < CH3COOH < ClCH2CH2COOH < ClCH2COOH
Similar to R groups, +I groups raise nitrogen's electron density, which raises an amine's basicity (an electron-rich substance is basic). The basic character of the supplied amines is influenced by the number of R groups on nitrogen. Basicity is also influenced by steric obstruction. Less basicity and more steric obstruction.
(CH3)2NH > CH3NH2 > (CH3 )3N > NH3
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Between periods at a hockey game, a machine called an ice resurfacer is used
to smooth down the ice. Explain how this affects the speed of the players on
the ice and why it has that effect.
8. Gold and copper are both metallic conductors that have resistivity in the range of 2 x 10-²
2m. The semiconductor silicon has a resistivity of 6.4 x 102m. On an atomic level, what
causes the resistivity of silicon to be so much higher?
Gold and copper are both metallic conductors that have resistivity in the range of 2 x 10-².
The semiconductor silicon has a resistivity of 6.4 x 102m.
Gold and copper are metals whereas silicon is a semiconductor . Metals are good conductors and semi conductors are not as good as metals and hence they have more resistivity. This can be attributed to band gap at the atomic level. The energy gap between valence band and conduction band is very less in metals but considerable more in semiconductors. For conduction to happen, the electrons must move from valence band to conduction band. This is easier in metals and hence resistivity is lesser in metals than in semiconductors.To know more about semiconductor visit :
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12. What structures does the fish have that are NOT present in the fly?
A car travels 65km/hour and gets 15miles/gallon of gasoline. How many gallons are needed for a 3 hour trip?
Answer:
pls check your question again i think you question is wrong.
HELP PLSSS
Oscar left a partially deflated balloon in his hot car for a couple of hours. When he returned the balloon seemed to be fully inflated. Somehow the volume of the balloon increased without anyone adding more air! Explain how this happened.
What are some of the ways that the features of carbon-to-carbon bonds influence the stability and 3-D structure of organic molecules?
Answer:
In order to draw the 3-D structure of an organic compound, we can use wedge-dash representation.
A biochemical engineer isolates a bacterial gene fragment and dissolves a 12.0−mg sample in enough water to make 30.0 mL of solution. The osmotic pressure of the solution is 0.340 torr at 25°C. (a) What is the molar mass of the gene fragment? g/mol (b) If the solution density is 0.997 g/mL, how large is the freezing point depression for this solution (Kf of water = 1.86°C/m)?
The molar mass of the gene is 2.22 * 10^4 g/mol and the freezing point depression is 3.35 * 10^-5 °C
What is the molar mass?We know that the osmotic pressure is obtained by the use of the formula';
π = iCRT
i = Van't Hof factor
C = concentration of the solution
R = gas constant
T = temperature
C = π/iRT
C = 0.340/1 * 62.4 * 298
C = 1.8 * 10^-5 M
Now;
n/M = C * V
12 * 10^-3/M = 1.8 * 10^-5 * 30 * 10^-3
M = 12 * 10^-3/1.8 * 10^-5 * 30 * 10^-3
M = 12 * 10^-3/ 5.4 * 10^-7
M = 2.22 * 10^4 g/mol
Mass of the solution is obtained from density * volume = 0.997 g/mL * 30.0 mL = 29.91 g
Molality of the solute = 12 * 10^-3g/ 2.22 * 10^4 g/mol * 1/ 29.91 * 10^-3
= 1.8 * 10^-5 m
ΔT = K m i
ΔT = 1.86°C/m * 1.8 * 10^-5 m * 1
ΔT = 3.35 * 10^-5 °C
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The surface temperature on Mercury has been measured to be 603 K . What is this temperature in degrees Celsius? 603 K=
If the surface temperature on Mercury has been measured to be 603 K, this temperature is equivalent to 329.84°C (degrees Celsius).
What is temperature?Temperature is the measure of cold or heat, often measurable with a thermometer.
Kelvin, which is denoted by K, is the International System of Units (S.I unit) or the base unit of thermodynamic temperature.
However, Kelvin can be converted to degree Celsius as follows:
K = 273.16 + °C
According to this question, the surface temperature on Mercury has been measured to be 603 K. This temperature can be converted to °C as follows:
603K = 273.16K + °C
°C = 603 - 273.16
°C = 329.84°C
Therefore, if the surface temperature on Mercury has been measured to be 603 K, this temperature is equivalent to 329.84°C (degrees Celsius).
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Aluminium having atomic mass 27 g mol crystallises in face centred pack
The number of unit cells in the given quantity is 2.23x10²³ unit cells
:Given Aluminum has an atomic mass of 27g mol-1
>Crystal is face-centered cubic structure
>number of aluminium atoms in l0 g mass
so w =10g
> the number of unit cells in the given quantity is to be calculated
Number of atoms of Al = (mass /molar mass ) x Nₐ
=(w/M)xNa , where Na =6.022x 10²³
There are 4 atoms present in the unit cell it will crystallize in a face-centered cubic crystal
.>.On solving the above values
we get the number of unit cells as= (10/27)x 6.022x10²³ unit cells
The number of unit cells in the given quantity is 2.23x10²³ unit cells
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Number of O atoms in 8.25x10-3 mol Al(NO3)3
the half life of throium is 18.72 days. how many days are required for 1000 gr to become 250 gr?
You need to prepare 250ml of a 0.015 M CuSo4 solution. You are given .015M CuSO4 solution. What size volumetric pipet do you need to prepare your 250ml solution?
0.1 ml of volumetric pipette is required to prepare 250 ml of copper sulfate solution.
How to determine size of pipettes while making solutions?Size of pipettes is determined by a wide range of factors such as physical properties of liquid,precision and accuracy of results to be obtained.
For knowing what size of pipette is to be used for making 0.015 M copper sulfate solution ,first the mass of copper sulfate to be used in making the solution is to be determined.Substituting the known parameters in the molarity formula mass of copper sulfate to be used is determined.
M=mass/molar mass×1/volume of solution in liters
mass=0.015×159.60×0.25=0.5985 g
Now to find out the volume of pipette to be used,using the density formula the volume of pipette can be obtained.
volume=0.5985/3.6=0.1
Therefore,0.1 ml of pipette is to be used for preparing 250 ml of 0.015 M copper sulfate solution.
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How good were your predictions in the warm-up?
can't give an answer to your question if there isn't a picture or being specific in the question.
Answer: 2 Out of 4
Explanation:
Bc my mom told me
A graduated cylinder is filled to 20mL. A piece of silver is added to the cylinder and the volume of water increases to
30mL. The density of silver is 10.49 g/mL, what is the mass of this piece of silver?
Answer:
104.9 g
Explanation:
If you add a piece of silver to water which increases the volume of the water from 20 mL to 30 mL, according to water displacement, the piece of silver must be 10 mL (30 mL - 20 mL = 10 mL).
You can find the mass by multiplying the volume of silver by the density. The denisty exists as a ratio comparing the mass (g) of silver per every 1 mL. It is important to arrange the ratio in a way that allows for the cancellation of units (mL should be in the denominator).
10 mL 10.49 g
-------------- x ----------------- = 104.9 g
1 mL
A farmer used too much pesticide (bug spray) and it washed down into the pond environment. What could happen to the Biotic AND Abiotic factors in the pond?
In a pond, the biotic factors include:
fishescrabssnailsplanktonalgaeThe abiotic factors are:
sunlighttemperaturerainfalldissolved mineralsWhat are the biotic and abiotic factors in a pond?Biotic factors are the living components of an environment whose activities affect the environment.
Biotic factors include plants, animals, bacteria, fungi, etc,
Abiotic factors are the non-living components of an environment that affect the environment.
Biotic and abiotic factors interact with each other.
In a pond, the biotic factors include:
fishescrabssnailsplanktonalgaeThe abiotic factors include:
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How many cubic centimeters are there in 8.14 yd3
Express the volume in cubic centimeters to three significant figures.
The number of cubic centimeters (cm³) in 8.14 yd³ is 6.22×10⁶ cm³
Conversion scaleCubic yard (yd³) can be converted to cubic centimeters (cm³) by using the folloing scale
1 yd³ = 764555 cm³
With the above conversion scale, we can obtain the number of cubic centimeters (cm³) in 8.14 yd³. Details below
From the question given above, filling data were obtained:
Volume (in yd³) = 8.14 yd³ Volume (in cm³) =?1 yd³ = 764555 cm³
Therefore,
8.14 yd³ = (8.14 yd³ × 764555 cm³) / 1 yd³
8.14 yd³ = 6.22×10⁶ cm³
From the calculation made above, we can conclude that there are 6.22×10⁶ cubic centimeters in 8.14 yd³
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Determine the molar mass of C₂H₇N. Provide an answer to two decimal places.
carbon molar mass: 12.011 x 2
hydrogen molar mass: 1.008 x 7
nitrogen molar mass: 14.0067
- add all values together:
(12.011x2) + (1.008x7) +1 4.011 = 45.09 g
Unit 3 Problems #2
Write the hobel gas configuration &
Lewis dof diagram for:
Be, O, AI, CI, Ni, Xe, W
An atom's noble gas configuration starts with the elemental symbol of the last noble gas that came before it, then moves on to the arrangement of the remaining electrons.
A Lewis electron dot diagram, also known as an electron dot diagram, Lewis diagram, or Lewis structure, is a diagram that employs dots to represent the valence electrons of an atom. The number of dots corresponds to the atom's valence electron count.
Write the noble gas configuration & Lewis dot diagram for:
Be, O, AI, CI, Ni, Xe, W
The diagrams known as Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.
Be - [He] 2s 2O - [He] 2s 2 2p4Al - [Ne] 3s 2 3p1Cl - [Ne] 3s 2 3p5Ni - [Ar] 3d 8 4s 2Xe - [Kr] 4d 10 5s 2 5p 6W - [Xe] 4f 14 5d 4 6s 2To know more about noble gas configuration & Lewis dot diagram, click on the link below:
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How many moles of ammonia would be required to react exactly with
0.230 moles of copper(II) oxide in the following chemical reaction?
2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)
Answer: 0.1533 moles of NH3
Explanation: The reaction need 2 moles of ammonia and 3 moles of copper oxide to take place. If you have 0.230 moles of copper oxide you need:
0.230/3=0.0767*2=0.1533 moles of NH3
what statement can be made about an electrically neutral atom’s number of protons and electrons?
How do you compare the direction of the applied force and friction force
The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.
Applied force define as the force applied to by an object to other object.applied force is contact force or a non contact force.
Friction force is the force exerted by a surface that resist the motion of body or against motion of body.friction is contact force. When the applied force increases , the frictional force also increases. when the applied force is larger than friction force object will move.
Example , if we applied force to the right direction the friction force acts in left direction.that is opposite to applied force.
Therefore,The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.
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Can the melting point of a substance be used as its fingerprint?
Answer:
Melting and boiling points are unique to the chemicals just like facial recognition. That does not necessarily means it is like a fingerprints.
Explanation:
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Which of the following measurements have four significant figures? Select all that apply. A.1,001g B.120.0mL C.0.0007cm D.5,000s
Answer:
The answer(s) will be A and B
Explanation:
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what are the cations and anions of NiS
The correct answer is cation Ni +2 and anion S 2-.
Nickel sulfide
It is discovered that the bonding in NiS is remarkably similar to that in NiO, with a covalent component resulting from bonds between the Ni 3d and the S 3p atom and an ionic contribution resulting from the donation of the Ni 4s electron to the S atom.
With heated concentrated nitric acid or aqua regia, NiS can be easily reactively dissolved, which is followed by sulphur precipitation.
F belongs to Group 7A, while Ni is in Group 5A. (EN: N=3.0, F=4.0) The NF3 molecule and each N-F bond are both polar. F possesses a partial positive charge in the N-F bond. The NF3 molecule and each N-F bond are both non-polar.
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How many significant figures are in 0.20L
I need help please..
The mass of the object is obtained as 608.5 grams.
What is density?The term density refers to the ratio of the mass to the volume of an object. The density of an object does not change thus we could use the density of an object to identify that object. If we have the density of the object, that alone could be used to trace the exact kind of material that we are dealing with.
Now we know that the density of the object is 6.095 g/cm^2
Volume of the object is obtained as 99.830 mL
Density = mass/volume
mass = density * volume
mass = 6.095 g/cm^2 * 99.830 mL
mass = 608.5 grams
Hence, the mass of the object is obtained as 608.5 grams.
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Sodium bicarbonate (NaHCO3) is commonly known as baking soda. Sodium bicarbonate is a white solid that can dissolve in water. Under the proper conditions, sodium bicarbonate can release carbon dioxide (CO2) gas.
Select all of the physical properties of sodium bicarbonate
Sodium bicarbonate is a white crystalline powder. NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.
Sodium bicarbonate:
Sodium bicarbonate is a white crystalline compound. It is alkaline. Sodium bicarbonate is a compound made up of sodium, hydrogen, carbon, and oxygen.
Sodium bicarbonate can be used as an antacid. It can also be used in making ear drops. It is used in cleaning the mouth and teeth because of its antibacterial properties.
The chemical reaction when sodium bicarbonate reacts with tartaric acid is given below:
NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.
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