Answer: 54.12 m
Explanation:
PLEASE HELP ME!! I NEED ANSWERS ASAP!!!!
Answer:
I do not know the answer because not all of the information is there.
Explanation:
Answer:
Beep Beep
Explanation:
If a container, with a fixed number of molecules inside, is
reduced in volume, less molecules will hit the sides of the
container per unit time, causing less pressure.
TRUE
FALSE
Check it
Answer:
FALSE
FALSE
FALSE
FALSE
The world record for a woman running a marathon is approximately 2.25 hours. If a marathon's distance is 26.2 miles (42164.81 meters) and it is run
in a southeast direction, what is the velocity?
60 mph southeast
0.09 mph southeast
Omph southeast
11.6 mph southeast
Answer:
11.6mph South East
Explanation:
Given parameters:
Time = 2.25hrs
Displacement = 26.2miles south east
Unknown:
Velocity = ?
Solution:
Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.
Now;
Velocity = [tex]\frac{displacement}{time taken}[/tex]
Velocity = [tex]\frac{26.2}{2.25}[/tex] = 11.6mph South East
Answer:
11.6mph south east.
when does a circuit is said to be over loaded?
Answer:
Every electric circuit in a wiring system must be protected against overloads. A circuit overload occurs when the amount of current flowing through the circuit exceeds the rating of the protective devices. The amount of current flowing in a circuit is determined by the load -- or the "demand" -- for current.
Explanation:
Hope this helps :)
10. The Earth's radius is about 6370 km. An object that has a mass of 20 kg is taken to a
height of 160 km above the Earth's surface. How much does the object weigh at this
height?
Answer:
Weight:
P =m·g₁ = 20·9.55 = 191 H
Explanation:
Given:
R = 6 370 км = 6 370·10³ m
m = 20 kg
h = 160 km = 160·10³ m
g = 9.8 m/s²
____________________
P - ?
Acceleration of free fall at the Earth's surface:
g = G*M / R² (1)
Acceleration of free fall at height h:
g₁ = G*M / (R + h) ² (2)
Divide (1) by (2):
g / g₁ = ((R + h) / R)²
g / g₁ = ( 1 + h / R)² = ( 1 + 160 / 6 370)² ≈ 1.026
g₁ = g / 1.026 = 9.8 / 1.026 ≈ 9.55 m/s²
Weight:
P =m·g₁ = 20·9.55 = 191 H
Dale and Alex push on opposite sides of a couch. Dale pushes to the left with a force of 40 N, while Alex pushes to the right with a force of 32 N. If the
couch has a mass of 28 kg, what is the acceleration of the couch?
A. 2.6 m/s^2 right
B. 2.6 m/s^2 left
C. 0.3 m/s^2 left
D. 0.3 m/s^2 right
0.3 m/s^2 left will be the acceleration of the couch.
we have given in the statement
force towards left 40 N
force towards right 32 N
net force = 40-32 = 8 N towards left
couch mass = 28 kg
now we will use newtons 2nd law to find acceleration
F=ma, here f is force m is mass a is acceleration
a=F/m
a=8/24
a=0.285 ≅ 0.3 N
An object's rise in velocity rate is referred to as acceleration. It is a vector quantity that is sign-sensitive, and the route shift and body speed variance establish the sign norm. it's unit is m/s^2To know more about acceleration visit : https://brainly.com/question/3046924
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0.3 m/s squared left Answer:
Explanation:
Damage to internal organs will present as pain associated with a particular surface area of the body. Why would something like irritation to the diaphragm, which is between the thoracic and abdominal cavities, feel like pain in the shoulder or neck?
7. What is the acceleration of a 24.00 kg mass pushed by an 8.0 N force?
Answer:
3 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{24}{8} \\ [/tex]
We have the final answer as
3 m/s²Hope this helps you
How much work is done by an applied force to lift a 15-Newton 3Meters and 9.8?
Given=
Unknown=
Formula=
Solution=
Answer=
The work done by the applied force of 15 Newton to lift the object up 3 meters is 45 J
W = F d
W = Work done
F = Force
d = Distance
F = 15 N
d= 3 m
W = 15 * 3
W = 15 J
Work done is the amount of force required to move an object. It is denoted by W. Its unit is usually Joules.
Therefore, the work done to lift the object is 15 J
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Britney is on the starting line to run a track race. The distance around the track is 400m.
She starts the race and runs 400m around the track. She ends up in the same place where
she started. What distance did she cover? What was her displacement?
The subjective perception of the frequency of sound is called ?
Answer: The subjective perception of the frequency of sound is called a Pitch
Explanation: Because the Pitch has a lowest and highest of a sound fundamental
If you are satisfied please leave a like
F x T = m (Vf - Vi)
in this equation what does the M stand for
Answer:
m = mass [kg]
Explanation:
This equation is characteristic of the amount of motion and momentum.
[tex]F*t = m*(v_{f}-v_{i})[/tex]
where:
F = force [N] (units of Newtons)
t = time = [s]
m = mass [kg]
Vf = final velocity [m/s]
Vi = initial velocity [m/s]
Now using the units and placing them in the equation above.
[tex][N]*[s] = [kg]*(m/s-m/s)\\[/tex]
[tex][N]=[kg*m/s^{2} ][/tex]
Now replacing:
[tex][kg*m/s^{2}]*[s]=[kg*m/s][/tex]
The s² is cancelled with the s, therefore.
[tex][kg*m/s]=[kg*m/s][/tex]
At the mail racing championship in England, the winner moved at an average velocity of 2.4 mm/s [ford] for 140 s. Determine the winning snail's displacement during this time interval. [
Answer:
Explanation: 1.2 mm
Time= 140 sec
Initial Velocity= 0
Average Velocity= 2.4 mm/s
Displacement= 0.5* (2.4/140) *140 = 1.2 mm
HELP URGENT- will give brainliest if correct
Answer:
6 km is the right answer
hope it helps you
Explanation:
please mark me as brainliest
Suppose, that you are measuring the length of a wood block and the edge of your block appears to be lined up exactly with a millimeter mark. How would you express the estimate part of a millimeter when you record the block’s length?
When taking the measurement, the estimate part of a millimeter when recording the block’s length can be expressed as ± 0.5 mm.
What are measurements?Measurements are the processes by which the attributes and properties of a given object or substance is quantified.
There are two types of measurements that can be obtained from any given object and they are:
quantitative measurementsqualitative measurementsQuantitative measurements measures the properties of objects in terms of numbers. Some examples of quantitative measurements are length, temperature, time, mass, etc.
Qualitative measurements describe the non-numerical features of objects such as color, texture, etc.
The measurement of length of a block of wood is a quantitative measurement.
The uncertainty or estimate of a measurement is half plus or minus the smallest division in the measurement.
The uncertainty or estimate of the millimeter block = ¹/₂ * 1 mm
The uncertainty or estimate of the millimeter block = ±0.5 mm
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if A.B=A.C
does this imply that B must be equal to c ?
I need answer with example please
Answer:
Yes
Explanation:
[tex]Consider\ three\ variables\ a,b\ and\ c.\\If,\\ab=ac\\a*b=a*c\\We\ may\ now\ divide\ the\ LHS\ and\ RHS\ by\ a,\\Hence,\\\frac{a*b}{a} =\frac{a*c}{a}\\Hence,\\b=c[/tex]
[tex]Ex: \\Consider\ a=5, b=6.\\Hence\ if,\\a*b=a*c\\5*6=5*c\\Hence,\\30=5c\\Hence, c=\frac{30}{5}\\c=6\\As\ b\ also\ equals\ to\ 6,\\b=c[/tex]
What does an electromagnet in an electric motor do? I need help asap
Answer:the Correct Answer is
It transforms electrical energy into mechanical energy.
Explanation:
I got the answer right
As a 3.0 kg bucket is being lowered into a 10 m deepwell, starting from top, the tension in the rope is 9.8 N. theacceleration of the bucket will be:____________A) 6.5 m/s2 downwardB) 9.8 m/s2 downwardC) zeroD) 3.3 m/s2 upwardE) 5.6 m/s2 upward
Answer:
A) 6.5 m/s²
Explanation:
Mass of the bucket, m = 3.0 kg
depth of the well, d = 10 m
tension on the rope, T = 9.8 N
The net downward force on the bucket is given as;
T = mg - ma
where;
a is downward acceleration of the bucket
9.8 = (3 x 9.8) - 3a
9.8 = 29.4 - 3a
3a = 29.4 - 9.8
3a = 19.6
a = 19.6 / 3
a = 6.53 m/s² downwards
Therefore, the acceleration of the bucket is 6.53 m/s² downwards
What is the voltage of a circuit that has a current of 3.7 amps and a resistance of 1.5 ohms.
Answer:
V = 5.55 volts
Explanation:
Given that,
Current, I = 3.7 A
Resistance, R = 1.5 ohms
We need to find the voltage of the circuit. Let V is the voltage. We can find it using Ohm's law as follows :
V = IR
Substituting all the values, we get :
[tex]V=3.7\times 1.5\\\\=5.55\ V[/tex]
So, the voltage of the circuit is 5.55 V,
A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 4.15 m and mass 7.98 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.396 rad/s2.
Answer:
4.535 N.m
Explanation:
To solve this question, we're going to use the formula for moment of inertia
I = mL²/12
Where
I = moment of inertia
m = mass of the ladder, 7.98 kg
L = length of the ladder, 4.15 m
On solving we have
I = 7.98 * (4.15)² / 12
I = (7.98 * 17.2225) / 12
I = 137.44 / 12
I = 11.45 kg·m²
That is the moment of inertia about the center.
Using this moment of inertia, we multiply it by the angular acceleration to get the needed torque. So that
τ = 11.453 kg·m² * 0.395 rad/s²
τ = 4.535 N·m
The Torque will be "4.535 N.m".
Given:
Mass of ladder,
m = 7.98 kgLength of ladder,
L = 4.15 m
The moment of inertia will be:
→ [tex]I = \frac{mL^2}{12}[/tex]
[tex]= \frac{7.98\times (4.15)^2}{12}[/tex]
[tex]= \frac{7.98\times 17.2225}{12}[/tex]
[tex]= 11.45 \ kg.m^2[/tex]
hence,
The torque will be:
→ [tex]\tau = 11.453\times 0.395[/tex]
[tex]= 4.535 \ N/m[/tex]
Thus the above approach is correct.
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A toy car in the figure below runs off the edge of a table that is h = 1.36 m high. The
car lands d= 0.88 m from the base of the table. How fast was the car going on the
table?
The toy car was going at a speed of 1.66 m/s on the table.
When the toy car runs off the edge of the table, it travels vertically as well as horizontally and it is an example of a horizontal projectile from a height.
The distance covered vertically will be equal to the height of the table which is 1.36m. And horizontal distance is given as d.
Vertical distance = H = 1.36m
Horizontal distance = d = 0.88m
Now, we for a free-falling body, in
Speed in vertical direction = u = 0 m/s
Distance = h = 1.36
Using the second equation of motion,
h = ut + 1/2gt²
Put in the value, we get
1.36 = (0)t + 1/2(9.8)t²
t² = 1.36/4.9
t² = 0.278
t = 0.53 seconds
Now distance traveled in a horizontal direction is given by
Distance in horizontal direction = Speed on table × time of travel
Put in the value, we get
0.88 = V × 0.53
V = 0.88/0.53
V = 1.66 m/s
So, the toy car was going at a speed of 1.66 m/s on the table.
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needdd helppppppppp
Answer:
divide 223 by 74 and you'll get your answer
A 120V AC signal is available at the wall port. You are required to convert it to a constant DC voltage of 12V for a laptop to operate. What are the three electrical components you will be using to achieve the same? Name the components in order and the function it performs.
Answer:
The following components shall be used in given order:
1. Step Down Transformer 2. Diode as Rectifier 3. Capacitor
Explanation:
The following components shall be used in given order:
1. Step Down Transformer 2. Diode as Rectifier 3. Capacitor
1.STEP DOWN TRANSFORMER:
The step down transformer is first used to convert the 120 V AC signal into 12 V AC signal. Because the output required is of 12 V.
2.DIODE AS RECTIFIER:
Now, the PN Junction diode is used as a rectifier to convert the 12 V AC signal to 12 V DC signal.
3.CAPACITOR:
Now, the output is in waveforms. So, in order to linearize it in the form of DC current, we use capacitor. The main function of capacitor is to smoothen the signal into a straight line.
Which of the following will increase if the voltage in a circuit is increased?
Check all that apply
A.Magnetic force
B. Resistance
C. Current
D. Heat produced by the circuit
Answer:
D i think (apologies if incorrect)
HELP right awayyy !!!
Answer:
Question 4 is actually Acceleration
006 (part 1 of 4) 3.0 points
Both car A and car B leave school at the same time, traveling in the same direction. Car A travels at a constant speed of 74 km/h, while car B travels at a constant speed of 93 km/h. How far is Car A from school 2.7 h later? Answer in units of km.
007 (part 2 of 4) 3.0 points
How far is car B from school 2.7 h later? Answer in units of km.
008 (part 3 of 4) 3.0 points
How long does it take car A to reach a gas station a distance 189 km from the school? Answer in units of h.
009 (part 4 of 4) 3.0 points
How long does it take car B to reach the gas station? Answer in units of h.
1. The distance of car A from the school is 199.8 Km
2. The distance of car B from the school is 251.1 Km
3. The time taken for car A to reach the station is 2.55 hours
4. The time taken for car B to reach the station is 2.03 hours
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
1. How to determine the distance of car A from the schoolSpeed = 74 Km/hTime = 2.7 hoursDistance of car A =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance of car A = 74 × 2.7
Distance of car A = 199.8 Km
2. How to determine the distance of car B from the schoolSpeed = 93 Km/hTime = 2.7 hoursDistance of car B =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance of car B = 93 × 2.7
Distance of car B = 251.1 Km
3. How to determine the time taken for car A to reach the gas stationSpeed = 74 Km/hDistance = 189 KmTime for car A =?Speed = distance / time
74 = 189 / time
Cross multiply
74 × time = 189
Divide both side by 14
Time = 189 / 74
Time for car A = 2.55 hours
4. How to determine the time taken for car B to reach the gas stationSpeed = 93 Km/hDistance = 189 KmDistance = 189 KmTime for car B =?Speed = distance / time
93 = 189 / time
Cross multiply
93 × time = 189
Divide both side by 93
Time = 189 / 93
Time for car B = 2.03 hours
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To pass a vehicle inspection, your Must be heard from 200 feet away.
Ohorn
Omuffler
windshield wipers
stereo
A I think sorry if I'm wrong
Helium balloons pop in a hot car because
Answer:
This is because helium molecules get bigger when they heat up , so if your balloons keep getting hotter , they will eventually pop
Answer:
the helium molecules within the ballon expand as they heat up, resulting in the eventually resulting in popping.
Explanation:
^^^^^
A car is stopped for a traffic signal. When the light turns green,
the car accelerates, increasing its speed from 0 to 5.20 m/s in
0.832 s. What are the magnitudes of (a) the linear impulse and
(b) the average total force experienced by a 70.0-kg passenger
in the car during the time the car accelerates?
Answer:
Impulse, p = 364 N·s
Force F = 437.5 N
Explanation:
First some definitions:
Part (a)
Since the car is initially at rest, its initial momentum is 0.
When the car reaches a velocity of 5.20 m/s, the momentum experienced by a 70 kg passenger is
Δv = 5.20 - 0 = 5.20 m/s
p = 70 kg x 5.20 m/s = 50.3248 kg m/s = 364 N·s
p = 384 N.s
Part (b)
Force is given by F=m(Δv/Δt) = 70 kg x (5.20 m/s / 0.832 s) = 437.5 N
F = 437.5 N
As a ladder leans against a wall it exerts a force on both the wall and ground. What are the two reactant forces on the ladder?
Responses
−Fwall on ladder and −Fground on ladder
−Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline
Fwall on ladder and −Fground on ladder
Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline
Fwall on ladder and Fground on ladder
Fwall on ladder and Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline
−Fwall on ladder and Fground on ladder
−Fwall on ladder and Fground on ladder
Its -Fwallonladdy and -fgroundonladder just made sure to add this since no one else did yet
The two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder
What are the two reactant forces on the ladder?To know the reactant forces on the ladder, we use Newton's third law of motion.
What is Newton's third law of motion?Newton's third law of motion states that for every action, there is an equal and opposite reaction.
So, for the ladder, as the ladder leans against a wall it exerts a force on both the wall and ground.
Now, since the ladder exerts a force on the wall, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the wall is Fladder on wall, then the reaction force of wall on the ladder is Fwall on ladder.
So, Fladder on wall = -Fwall on Ladder
Also, since the ladder exerts a force on the ground, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the ground is Fladder on ground, then the reaction force of ground on the ladder is Fground on ladder.
So, Fladder on ground = -Fground on Ladder
So, the two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder
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