We take the +x direction to be horizontal to the right and the +y direction to be up.
Newton’s second lawThe equations for the x, y components of the force as per Newton’s second law are:
Fx=Fcosθ−f=ma
Fy=Fsinθ−FN−mg=0
Now, f=μkFN and the second equation from above gives
FN=Fsinθ−mg,
which yields f=μk(Fsinθ−mg).
This expression is replaced for f in the first equation to obtain
Fcosθ−μk(Fsinθ−mg)=ma.
For a = 0 ,
the force is F= cosθ− μksinθ− μkmg
With μk=0.65, m = 5.0kg,
and θ = 70∘, we obtain F = 118 N.
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5. in cars, one battery terminal is connected to the metal body. how does this allow a single wire to supply current to electrical devices rather than two wires?
The battery’s negative terminal is attached to the chassis or metal body in automobiles. A single wire is used to connect the positive terminal to multiple electrical appliances.
The chassis is next connected to the negative terminal of the gadgets, completing the circuit for the current flow.
What happens if a battery’s terminals are connected?There will be a low resistance path for the current to travel when a wire is connected directly between a battery’s two terminals.
The battery will swiftly deplete, and the wire will become slightly heated (the amount of heat depends on the wire’s diameter; the smaller the diameter, the more heat).
Why is it necessary to connect a battery’s terminals?A battery can generate power when it is included in a circuit. The positive terminal (cathode) and the negative terminal are the two ends of a battery (anode).
A circuit is created by connecting the two terminals with wire. A current of electricity is created as electrons move across the wire.
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A rock is dropped from a cliff and takes 6 seconds to hit the ground. At what time is the acceleration of the rock the greatest?
Can one-dimensional motion have zero distance but a nonzero displacement? what about zero displacement but a nonzero distance?.
One-dimensional motion cannot have zero distance with a non zero displacement.
zero displacement occur but a nonzero distance not.
Distance is known as the total path taken by an object.
Displacement is known as the shortest distance taken or path taken.
Distance have only magnitude where displacement has both magnitude and direction. It cannot have zero displacement with nonzero distance because distance has only magnitude.There will be zero displacement but a non zero distance.
In a circular motion because displacement is the shortest distance covered.
One-dimensional motion cannot have zero distance with a non zero displacement.
zero displacement occur but a nonzero distance not.
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Can some one Explain to me how the orbits of the planets around the sun work?
Kepler 2nd and 3rd law are tricky can someone explain?
Since the powerful gravitational pull of the Sun, all of the the solar system's planets revolve around it. The Sun basically attracts the solar system's planets, encompassing Earth, as well as allows them to be in orbit.
What is Kepler's law?Kepler's laws of planetary motion was initially published at 1609 and 1619 by Johannes Kepler which implies the description of the main orbits of planets around the Sun.
They explain the following scenarios:
Planets move in elliptical orbits all around the Sun.A planet grab the similar quantity of space in the similar time not relating of the place it is in its orbit.A planet's orbital period is usually proportional to the size of its orbit.Thus, this way, the orbits of the planets around the sun work.
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an object moving in 1-dimension along a horizontal surface denoted as the x-axis. the object is initially moving in the positive x-axis direction and the rate of energy decrease of the object is proportional to the square of its speed.
The acceleration of the moving object can be defined by [tex]a_x = mv^{2} _0 * \lambda/(\lambda v_0t + m)^{2}[/tex].
What is acceleration?In physics, acceleration is the rate at which the velocity of an object changes over time. They are vector quantities and accelerations. The direction of the net force acting on an item determines the direction of its acceleration.
Acceleration is the rate at which the speed and direction of a moving object change over time. A point or object is going ahead directly when it accelerates or decelerates.
the question is incomplete
An object moving in 1-dimension along horizonta surface denoted as the x-axis. The object is initially moving in the positive X-axis direction and the rate of energy decrease of the object is proportional to the square of its speed dE ~Avz In this equation A is a constant with units of kglm_ The speed of the object at b 0 s is Vo: What is the speed of the object as function of t > 62 HINT: since the object is moving along horizontal surface its energy is simply its kinetic energy: Substitute the equation for kinetic energy into the above differential equation for energy to determine the acceleration of the object:
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A cyclist and a bike have a combined mass of 99kg. show that the combined weight is 990n
Explanation:
9.80665 N/kg is the force applied by Earth's gravity on a 1 kg of mass (that is then the weight of 1kg mass). the acceleration due to this gravity is usually correspondingly defined as 9.81m/s².
now we have 99 kg.
that means we have to multiply 9.81 by 99
99×9.81 = 971.19 N
if we just roughly round the weight of 1 kg from 9.81 to 10 N, we get then the proposed 99×10 = 990 N result.
but as you can see, this is not very precise.
A 557 hz tone is sounded at the same time as a 517 hz tone. what is the beat frequency? hz
When a 557 hz tone is sounded at the same time as a 517 hz tone, the beat frequency would be 40hz.
What does beat frequency mean?The difference in frequency between two waves is known as the beat frequency. It is as a result of both positive and negative interference. While we perceive the regular frequency of the waves as the pitch of the sound, we perceive the beat frequency as the rate at which the loudness of the sound varies.
What is the formula for beat frequency?The difference in frequency between the two superimposed waves is the formula for beat frequency.
What is vibration’s beat?Beat is the pulsing that two waves with slightly differing frequencies combine to create in physics.
CalculationBeat frequency = | f1 - f2 | or no. of cycles/time
= |557-517|
= 40Hz
Thus, the beat frequency is 40Hz
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you are given a vector in the xy plane that has a magnitude of 80.0 units and a y component of -57.0 units. part a what are the two possibilities for its x component?
The two possibilities for its x component are +56.13 units and -56.13 units.
We are given the resultant magnitude and the y component of a vector.
The x- component of the vector along with the y component and the resultant make a right-angled triangle.
The x - component can be calculated by applying the Pythagoras Theorem
Here the square of the resultant is equal to the square of the y-component and x- component.
(80)^2 = (57)^2 + (x)^2
6400 = 3249 + (x)^2
3151 = (x)^2
X=+- 56.13 units
Hence, the two possibilities for its x component are +56.13 units and -56.13 units.
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What do we call what is transported through a sound wave?
Answer:
n the first part of Lesson 1, it was mentioned that sound is a mechanical wave that is created by a vibrating object. The vibrations of the object set particles in the surrounding medium in vibrational motion, thus transporting energy through the medium
A bullet is fired with a velocity of 50m/s at an angle tita to the horizontal.What is the value of tita for maximum range with this velocity. Calculate the maximum range (take g=10m/s).
Answer:
R = V^2 sin 2 θ / g range formula
max range occurs at θ = 45 deg
R = 50^2 m^2/s^2 / 10 m/s^2 = 250 m
The maximum value of angle theta for a velocity of 50 m/s will be 11.47 °, where the final velocity of the bullet is zero and the acceleration due to gravity is 10.
What is velocity?Velocity is a vector quantity measuring the distance covered by an object per unit time. The rate of change in velocity is called acceleration. Velocity have two component one in horizontal axis and other in vertical axis.
For horizontal axis Vh = V cos∅
for vertical axis Vv = V sin∅.
The final velocity V = u + at. Where u is the initial velocity.
Here V = 0 thus u = at.
t = u/a = 50 m/s / 10m/s².
t = 5 seconds.
v = 50 cos∅ = at
∅ = cos⁻¹ (10 m/s² ˣ 5 s)
= 11.46°
Therefore, the angle theta is probably 11.46°.
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What can we do with atoms?
A. bond different atoms together
B. cut them into tiny pieces
C. take out all of the protons
The only possible thing we can do is combine different atoms to form molecules and compounds
so the Correct choice is A
a train travels 220km in 1.5 hours. what’s the average velocity?
Answer:caca
Explanation:
because
A star is moving directly towards earth at a large fraction of the speed of light. How does the light we observe from this star compare to the light received from the same star if it were at rest relative to earth?.
A star is moving directly toward earth at a large fraction of the speed of light. The light we observe from this star compared to the light received from the same star if it were at rest relative to earth will be blueshifted.
In Physics, this phenomenon is called doppler shift as it refers to the change in frequency of the waves relative to an observer who is moving in relation to that source.
A star coming toward earth emits light that appears to have a shorter wavelength as compared to another source of light.
When the star is moving toward earth, its spectral line shift towards the blue end of the light series.
Since blue light has a shorter wavelength and this occurrence corresponds to the blue end of the light spectrum hence called blueshift.
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assume there is friction between the wagon and the ground. how do you determine the value of the frictional force, using the y component of the applied force f?
The value of frictional force, using the y component of the applied force f can be found if the co- efficient of friction is known.
First split the applied force F into its vertical and horizontal components [tex]F_{y}[/tex] and [tex]F_{x}[/tex] respectively
[tex]F_{y}[/tex] = F sin θ
Since there is no vertical movement,
Σ [tex]F_{y}[/tex] = 0
[tex]F_{y}[/tex] + [tex]F_{N}[/tex] - mg = 0
[tex]F_{N}[/tex] = [tex]F_{y}[/tex] - mg
[tex]f_{k}[/tex] = [tex]([/tex]μ[tex])_{k}[/tex][tex]F_{N}[/tex]
Therefore, the frictional force [tex]f_{k}[/tex] can be found only the y components if the co-efficient is known.
Frictional force is the opposing force between two objects. It acts along the surface of the object.
Therefore, the value of frictional force, using the y component of the applied force f can be found if the co- efficient of friction is known.
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In chloroplasts,
from the air is converted into
Through photosynthesis, the plant creates glucose, a type of sugar, from water and carbon dioxide from the air.
What is the function of chloroplasts?Chloroplasts, a type of organelle found in plant cells, convert light energy into chemical energy that is relatively stable through the photosynthetic process. They maintain life on Earth in this way.
Chlorophyll stands out among the many kinds of pigments found in nature because it gives plants the ability to absorb the energy they require to develop tissues.
Chlorophyll is found in the plant's microscopic chloroplasts, which are found in its cells. This is where photosynthesis takes place.
Therefore, water and carbon dioxide from the air into glucose.
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A person riding in an airplane drops a rock out of the door of the plane which is moving at 550 mile/hr. The airplane remains on its original horizontal path and maintains a constant velocity. Where will the airplane be located when the rock hits the ground? neglect air resistance.
By using uniform motion, the location of the airplane when the rock hits the ground is ( 550 . √(2h/g) + h )miles.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 550 mile/h
Find the time taken to hit the ground
s = vo . t + 1/2 . a . t²
h = 0 . t + 1/2 . g . t²
t² = 2h/g
t = √(2h/g)
Find the distance traveled by plane
s = vo . t + 1/2 . a . t²
x = vo . t + 1/2 . a . t²
x = 550 . √(2h/g) + 1/2 . g . √(2h/g)²
x = 550 . √(2h/g) + h
the distance traveled is ( 550 . √(2h/g) + h )miles.
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the amount of energy radiated by the earth peaks in the portion of the electromagnetic spectrum. visible light infrared ultraviolet gamma ray
The amount of energy radiated by the earth peaks in the Infrared portion of the electromagnetic spectrum.
The amount of energy radiated by the sun, when reaching the Earth's surface, 49.4 % is infrared radiation, 42.3 % is visible light and 8.3 % is ultraviolet radiation.
Energy is radiated back into the atmosphere after receiving from the sun ( in the form of light ). Since the Earth is much cooler when compared to the Sun, the energy radiated is much weaker. So it is radiated in the form of Infrared radiation ( long wavelength )
Therefore, the amount of energy radiated by the earth peaks in the Infrared portion of the electromagnetic spectrum.
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Write down the value of
Mark is doing a pass to his teammate Dan. Mark is square to Dan; his thumbs are against
his chest and his elbows bent and out. Mark steps toward Dan and releases the ball
towards Dan without fully extending his arms. What type of pass is Mark doing and does
he do the pass correctly?
O Overhead pass: No, he did not bring the ball to his forehead
O Push pass: Yes, he did the pass correctly
O Chest pass: No, he should have fully extended his arms when passing to Dan
O Bounce pass: Yes, he did the pass correctly
Bounce pass: Yes, he did the pass correctly
What is Bounce passing?The bounce pass is thrown in the same motion, but it is directed at the ground instead of the air. The throw should be made so that the ball lands at the receiver's waist. Some advise trying to toss it 3/4 of the way to the receiver, and it would be a decent starting point. However, each player must experiment to determine the right distance to throw it so that it bounces to the receiver. The distance will be simpler to determine if the pass has a decent and consistent backspin.To learn more about bounce passing refer to:
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what is velocity vs time. i need help with my test on edge
Answer:
See below
Explanation:
It is a graph on the x -y coordinate system with (generally ) the y-axis is labelled 'velocity' and the x - axis is 'time' <==== with this, you can look at the time and find the velocity at that time on the graph
Calculate the longest wavelength (nm) that can provide an energy of at least 415 kj/mol.
The longest wavelength (nm) that can provide an energy of at least 415 kj/mol for a signal that is carried down in the consecutive cycles is 6.263 x [tex]10^{38}[/tex] /sec.
What is wavelength?A waveform is a kind of signal that is carried throughout in space or down a wire that has a wavelength, which is the separation between two identical places in the consecutive cycles.
This length can be mostly defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm).
The wavelength, can also be applied to troughs, is the separation between two wave crests.
This frequency can be measured in cycles per second (Hz), which is the also defined as the quantity of vibrations that cross a specific area in a second (Hertz).
What is Plank's Constant?The fundamental universal constant that is known as Planck's constant, or also symbolized as H, is the one that establishes the quantum nature of energy and links the energy of a photon to its frequency.
Energy = plank's constant x frequency
⇒ frequency = energy/ plank's constant
= 4.15 x [tex]10^{5}[/tex]/6.626 x [tex]10^{-34}[/tex]
= 6.263 x [tex]10^{38}[/tex] /sec
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a spherical balloon has a surface charge density of omega on its outer surface and ahs radius a what is the electric field outside of the balloohn at all points in space
The electric field outside the balloon at all points in space is ω/ε where ω = Q/4πa^2.
To find the electric field(E) due to a symmetrical surface, Gauss’ Law is used, which is
E x (ds) = q/ε
Here ds = surface area of the surface
And Q = charge enclosed by the surface
As the balloon is spherical with radius a, its area will be 4πa^2
Putting the values in the above equation
E x 4πa^2 = Q/(ε)
E = Q/4πa^2(ε)
The surface charge density(ω) = Q/4πa^2
Hence
E = ω/ε
Thus, The electric field outside the balloon at all points in space is ω/ε where ω = Q/4πa^2.
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when is something weight less
Answer:
Weightlessness is simply a sensation experienced by an individual when there are no external objects touching one's body and exerting a push or pull upon it. Weightless sensations exist when all contact forces are removed.
The books has a mass of 3.5kg. the coefficient of friction between the book and the wall is 0.85.how much force must be applied to keep the book from slliding
The force that must be applied to keep the book from sliding is 41.17 N.
When a body is pressed against a wall, the four forces act on it, as shown in the image Applied force, Frictional Force, Weight and Normal Force.
To keep the book from sliding, the forces should balance each other in the horizontal and vertical directions. Thus, Applied Force and Normal Force should be equal. And Frictional force and Weight should be equal.
Hence, Applied Force = Normal Force(N)
Frictional Force = Weight (mg)
μN = mg
As applied force = N
μ x applied force = mg
0.85 x Applied Force = 3.5 x 10
Applied Force = 41.17 N
Hence, the force that must be applied to keep the book from sliding is 41.17 N.
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A 0.66 kg block is suspended from the middle of a 1.56 m long string. The ends of the string are attached to the ceiling at points separated by 1 m, and the block can slip along the long string. The acceleration of gravity is 9.81 m/s 2 . What is the tension in the string? Answer in units of N.
The tension in the string suspending the weight of the block is determined as 6.47 N.
What is force of tension?Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
The tension in the rope used in towing the car up hill is calculated as follows;
T = ma
where;
m is mass of the carg is the acceleration due to gravitySubstitute the given parameters and solve for the tension in the string suspending the weight of the block.
T = 0.66 kg x 9.8 m/s²
T = 6.47 N
Thus, the tension in the string suspending the weight of the block is determined as 6.47 N.
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on the famous 18th hole at pebble beach, lionel forrest stands next to his ball on the fairway, 165 meters from the hole. his caddie hands him a golf club that will hit the ball at a 65° angle. the gravitational acceleration is 9.8 m/s2, and a stiff tailwind exactly cancels the effects of air resistance. how hard should lionel hit the ball to land it as close to the hole as possible?
The horizontal distance is R=165m
What is horizontal distance?
The angle of launch is θ=65∘
Let the hit velocity be u.
Using the formula of the range of a projectile,
R=u2 sin2θ/g
(165m)=u2sin(2×65∘)/9.8 m/s2
u2=2111 (m/s)2
⟹u≈46m/s
The projectile's horizontal range is the distance it travels while in flight. Since there is no acceleration in the horizontal direction, the greatest distance traveled in the horizontal direction is what is meant by this definition.
Therefore,
on the famous 18th hole at pebble beach, lionel forrest stands next to his ball on the fairway, 165 meters from the hole. his caddie hands him a golf club that will hit the ball at a 65° angle. the gravitational acceleration is 9.8 m/s2, and a stiff tailwind exactly cancels the effects of air resistance. how hard should lionel hit the ball to land it as close to the hole as possible?
The horizontal distance is R=165m
The angle of launch is θ=65∘
Let the hit velocity be u.
Using the formula of the range of a projectile,
R=u2 sin2θ/g
(165m)=u2sin(2×65∘)/9.8 m/s2
u2=2111 (m/s)2
⟹u≈46m/s
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Answer:
lionel should hit the ball at 46m/s
Karen is asked to look at two spots of light and judge which one gets brighter over time. Both spots start out at 100 units of brightness. She notices that the right spot is brighter when it is 110 units. If she is presented with two new spots of light both starting at 300 units, how much brighter will one have to get before she will be able to reliably detect the difference?.
As spots start out at 100 units of brightness. One of the light spots will have to get 330 units brighter than the other for her to be able to tell the difference.
In the case of the first bulb, she noticed the difference when the right was 0.10 % brighter than the other one.
100 * 0.10 = 10
100 + 10 = 110
If we apply the same sense in the second case, one of the spots will have to be 0.10% brighter than the other.
300 * 0.10=30
300+30 = 330
In order to tell the difference, the other spot should be at 330 units of brightness.
The unit of brightness is Lumen. It is use to calculate the total amount of brightness emitted from a source over a unit of time.
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A car is traveling along the road. List three forces that act on it
Answer:
Normal force
Friction force
Gravity force
Explanation:
1.Friction force F is the sum of all the horizontal tire forces.
2.Normal force R is the sum of all normal tire forces applied by ground on the vehicle in the r direction
3gravity g =mgk
Answer:
1. Time
2.Energy
3.speed
Explanation:
1.time : as the driver moves every seconds the driver move is counted and know as time he can drive for an hr
2. Energy : the strength the driver put In to make the car move is energy
3. Speed : speed is the acceleration the driver uses
What is the work required to move a charge q from the other vertex to the center of the line joining the fixed charges?
The work required to move a charge q from the other vertex to the center of the line joining the fixed charges is zero.
The charge on two vertices of the equilateral triangle are Q and -Q which is fixed. On the other vertex is a point charge q. The work done to move the point charge q from the vertex to the midpoint of other two charges Q and -Q is the change in potential energy of the charge q.
We know that,
U = q V
V = k q / r
where,
U = Electric potential energy of a charge
V = Electric potential at a point due to a point charge
k = Coulomb's constant
r = Distance
Change in potential energy of charge q, ΔU = q ΔV
ΔU = q ( [tex]V_{f}[/tex] - [tex]V_{i}[/tex] )
Electric Potential at the midpoint of charges Q and -Q,
[tex]V_{f}[/tex] = k Q / ( a / 2 ) + k ( - Q ) / ( a / 2 ) = 0
Electric Potential at the vertex of charges q,
[tex]V_{i}[/tex] = k q / a + k ( - q ) / a = 0
ΔU = 0
The given question is incomplete. The complete question is:
Two particle with charges Q and -Q are fixed at the vertices of an equilateral triangle with sides of length a, the work required to move a particle with a charge q from the other vertex to the center of the line joining the fixed charges is?
Therefore, the work required to move a charge q from the other vertex to the center of the line joining the fixed charges is zero.
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a cart rolling SW at a velocity of 10 m/s comes to a stop in 2 seconds. What is the car's acceleration?
Acceleration is 5m/s^2.
Explanation:Acceleration = Change in velocity per unit time.
Therefore, Acceleration a = (10m/s)/(2s)
(10m/s)/(2s) = 5m/s^2