The time when both the balls meet is found to be 8.4seconds.
By Newton’s third equation of motion
h = ut -1/2 gt²
-(210-h) = ½ ×gt²
h= 210 -1/2 gt² (eq.1)
Now, we apply same equation for the ball thrown upward with initial speed of 25m/s
h = ut -1/2 gt²
h = 25t -1/2gt² (eq.2)
On comparing eq. 1 and eq. 2 we get,
210 -1/2gt² = 25t -1/2gt²
210 = 25t
t = 8.4 sec.
Thus, the time when both the balls meet is found to be 8.4sec.
There are three laws of motion, which are stated by Sir, Isaac Newton. He describes the relation between the motion of the object and the forces which are acting on it during a projectile or simple motion. On the basis of three laws of motion, equations are dervied which are used to find the speed, height, velocity or acceleration of the object.
The three equations of motions are as follows:-
1. V= u + at
2. S= ut +1/2 at²
3. v²=u² + 2as.
Where, v is the final velocity, u is initial velocity, a is acceleration, s is distance covered and t is time taken.
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A motorcycle enters a freeway with a speed of 5.8 m/s and accelerates uniformly for 65 m in 7.2 s.
How fast is the car moving after this time?
The speed of the motorcycle is 9.02777m/s in 7.2 sec.
What is acceleration?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
v(0) = 5.8
s(0)=0
s(7.2) = 65
s(t) =at^2/2 + v(0)t
s(7.2) = a(7.2)^2 + 5.8(7.2) = 65
a = (65-41.76)/51.84
a= 23.24/51.84 = about 0.4483 m/s²
v(t) = s'(t) = at +v(0) = at +5.8
v(7.2) = 0.4483(7.2) + 5.8
= 9.02777
velocity in 7.2 seconds is about 9.03 meters per second
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Match each word with its definition. Match the items in the left column to the items in the right column.
1. displacement
2. distance
3. scalar
4. mass
5. kinematics
6. vector
7. time
A. the length of the entire path an object travels from start to end
B. the change of position of an object from start to finish
C. the property a body possesses as evidenced by its inertia
D. a quantity expressed as a magnitude and a unit
E. displacement is this type of quantity
F. an area of physics dealing with mathematical methods of describing motion
G. that which allows us to place events in their order of happening
The items in the left column matched to the items in the right column:
A. the length of the entire path an object travels from start to end - Distance B. the change of position of an object from start to finish - displacement C. the property a body possesses as evidenced by its inertia - mass D. a quantity expressed as a magnitude and a unit - Scaler E. displacement is this type of quantity - vector F. an area of physics dealing with mathematical methods of describing motion - Kinematics G. that which allows us to place events in their order of happening - time.What is distance?This is the length between two different points; say point A to B. It is measured in meters ( m).
In conclusion, the length of the entire path an object travels from start to end is regarded as distance
Vectors are quantities which have both magnitude and direction.
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Ty works two jobs and attends college part-time. he averages 5 hours of sleep per night most nights of the week. what are the health risks of his sleep deprivation?
The health risks include Health Effects of Sleep Loss, Poor glucose tolerance and diabetes.
Both adults and kids who are obese.
Vascular disease and high blood pressure.
Anxiety signs.
Depressed attitude
Using alcohol.
What negative impacts might a lack of sleep cause?Sleep deprivation can leave you cranky and confused. Many people might not be aware of the potential effects on your capacity to lose weight, memory, health, and even your sexual life.
You run the risk of developing heart disease if you have sleep disorders or persistent sleep deprivation.
Chest pains.
A heart attack.
Abnormal heartbeat
Elevated blood pressure
Stroke.
Which five consequences might insomnia have?Chronic sleep deprivation has been linked to high blood pressure, heart attacks, strokes, obesity, diabetes, depression, anxiety, impaired brain function, memory loss, weakened immune system, and lower levels of energy.
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On his fishing trip Justin rides in a boat 15 km south. The fish aren't biting, so they go 5 km west. They then follow a school of fish 1km north. What distance did they cover? What was their displacement?
The total distance covered is 21 km while their displacement is 14.87 km SouthWest.
Distance and displacementThe distance covered by a moving body is the product of the speed of movement and the total time taken.
Displacement, on the other hand, is the property of a body or an object to be moved from one place to another.
While distance is a scalar quantity, displacement is a vector quantity.
In this case, the total distance covered by Justing can be calculated as:
15 km + 5 km + 1 km = 21 km
The displacement can be calculated from the attached image:
[tex]hyp^2 = opp^2 + adj^2[/tex]
= [tex]14^2 + 5^2[/tex]
= 221
= 14.87 km
Thus, they have been displaced by 14.87 km from the starting point in the SouthWestern direction.
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Select the option that best summarizes the reason for the use of position-time graphs when studying physical science. (1 point)
O Position-time graphs show the relationship between the position of an object (shown on the x-axis) and the time (shown on the y-axis) to show displacement.
O Position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show acceleration.
O Position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show displacement.
O Position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity.
x
====================================Position, Distance, and Displacement
========================================================
Hello! Lets begin!
1. Which answer best describes displacement?
A) Displacement is a vector quality showing total length of an area traveled by a particular object.2. Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?
D) The nine ball traveled a distance of 7 meters and was displaced by 1 meter.3. What is velocity?
B) Velocity is a vector quantity that tells the distance an object has traveled over a period of time.4. Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?
C) The slope of the line is equal to zero and the object will be stationary.5. Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.
B) The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity._______________________________________________________
Good luck my peeps! ;D
The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity.
What is velocity?Velocity is a vector quantity that tells the distance an object has traveled over a period of time.
Displacement is a vector quality showing total length of an area traveled by a particular object.
Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?
The slope of the line is equal to zero and the object will be stationary.
The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity.
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The specific heat of the metallic element rhodium is 0. 240 j/g-k at 25°c. If 586 j of heat is added to an 80. 0 g block of rhodium metal that is initially at 25. 0°c, what is the expected final temperature of the block?.
Answer:
55.5 ° C
Explanation:
A unit of K and a degre C are the same increment
586 j / (80 g C ) = .240
C = 30.5 degree increase from 25 c = 55.5 ° C
Which is the pH of a 1 x 10 to the power of -4 mol HCI solution?
The pH of the 1×10⁻⁴ M hydrochloric acid, HCl solution is 4
We'll begin by obtaining the concentration of the hydrogen ion, H⁺ in th solution. This is illustrated below:
Dissociation equation
HCl(aq) —> H⁺(aq) + Cl¯(aq)
From the balanced equation above,
1 mole of HCl contains 1 mole of H⁺
Therefore,
1×10⁻⁴ M HCl will also contain 1×10⁻⁴ M H⁺
How to determine the pH of the solutionThe pH of the solution can be obtained as follow:
Hydrogen ion concentration [H⁺] = 1×10⁻⁴ MpH =?pH = –Log H⁺
pH = –Log 1×10⁻⁴ M
pH = 4
Thus, we can conclude that the pH of the solution is 4
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A cat runs 13.1m in 8.0s. How long (in s) will it take the cat to run 5.5km?
The time cat will take to run 5.5km is 55.89 minutes.
Equation :according to given details,
distance = 13.1m
time = 8 s
speed = ?
distance (b) = 5.5km = 5500m
time = ?
speed = ?
So by using formula,
speed = distance / time
speed = 13.1m/8s
speed = 1.64 m/s
As now we have speed using same formula
s = d / t
t = d / s
t = 5500m / 1.64 m/s
t = 3,353.65 sec
t = 55.89 minutes
Speed, distance and time relativity :Speed is calculated as distance times speed. You need to be aware of the units for distance and time in order to calculate the units for speed. The units in this example will be metres per second (m/s), since the distance is measured in metres (m) and the time is measured in seconds (s).
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he speed of sound through air is linearly related to the temperature of the air. if sound travels at 324 m/ sec at 0 degrees celcius and at 344 m/ sec at 0 degrees celcius
The speed of sound through air is linearly related to the temperature of the air is 1m/ sec per degree Celcius.
The speed of sound through air is linearly related to the temperature of the air. If sound travels at 324 m/sec at 0 degrees Celcius and at 344 m/ sec at 20 degrees Celcius.
1. Construct a literal model relating the speed of sound (s) and the air temperature (t). Interpret the slope of this model.
From the word, the problem pulls out the two points (0,324) and (20,344). Use these to find the slope of the linear model.
[tex]\frac{(344-324)}{(20-0)}[/tex] so the slope is 1m/sec/deg or change of speed of sound per degree change in temperature
plugging this into the point-slope equation for a line where y=s and x=t
s-324 = 1(t-0)
the linear model is s =t + 324
2. Interpret the slope of this model
a) The rate of change of speed of sound with respect to temperature is 1m/ sec per degree Celcius.
In terms of physics, sound may be a vibration that travels through a transmission medium like a gas, liquid, or solid as a sound wave. Sound is the reception of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between roughly 20 Hz and 20 kHz, or the audio range, can cause people to have an auditory sensation. These are sound waves with wavelengths starting from 17 meters (56 ft) to 1.7 millimeters in the air at air pressure (0.67 in). Ultrasounds are sound waves with a frequency above 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of various species have different hearing ranges.
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THREE-DIMENSIONAL THINKING
If you cause the surfaces between two touching objects to change, how
will the friction be affected? Make a claim. Support your explanation with
evidence and logical connections.
Type answer here.
Clear
The correct answer is The minuscule hills and valleys of two contacting surfaces grow, which causes friction. Describe how friction is impacted by the pressure pressing two surfaces together. The amount of friction between two surfaces increases as the force pulling the surfaces together increases.
Frictional force is the force produced when two surfaces slide against and touch each other. The surface texture and amount of force needing them together have the biggest an impact on these forces.
The forces of adhesion between the sites of contact areas of the surfaces, which are always minutely uneven, are the primary cause of friction between objects. The action of the imperfections of the harder surface tilling across the softer surface shears these "fused" connections, causing friction.
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two point charges are brought closer together, increasing the magnitude of the electrostatic force between them by a factor of . by what factor was their separation decreased?
Distance between them is decrease by an element of 0.21
Evaluating :
Two point charges are brought closer together, increasing the force by an element of 22
Let the first force be
F = [tex]\frac{kq_{1} q_{2} }{r^{2} } ...........1[/tex]
where q₁ q₂ are charges and r is that the distance between new force F' = [tex]\frac{Kq_{1} q_{2} }{r^{2} } ................2[/tex]
divide equation 1 & 2
[tex]\frac{F}{F'}[/tex] = [tex]\frac{r^{2} }{r'^{2} }[/tex]
[tex]22= \frac{r^{2} }{r'^{2} }[/tex]
r' = [tex]\frac{r}{\sqrt{22} }[/tex] ≈0.213r
F₁ represents the first electric force between the two point charges.
F₂ represents the new electric force between the 2 point charges.
r₁ represents the first separation distance between the two point charge.
r₂ represents the new separation distance between the 2 point charge.
Distance between them is decrease by an element of 0.21
Electric Force:
The term 'electric force' exists when two or more electric charges are situated at a specific distance. The variation of electrical force with point charge magnitude is a linear one, whereas the variation of electrical force with the separation distance between the charges is an inversely square one.
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A car moving with an initial speed of 16 meters per second is brought to rest uniformly in 4. 0 seconds. How far does the car travel during this 4. 0-second interval?.
The car in a time of 4 seconds will travel a distance of: 32 m
The formulas for uniformly varied rectilinear motion (UVRM) and procedures we will use to solve this exercise are:
a = (vf - vi) /tx = (vf²-vi²)/ (2a)Where:
x = distancevf = final velocityvi = initial velocitya = accelerationt= timeInformation about the problem:
vi = 16 m/svf= 0 m/st = 4 sa = ?x= ?Applying the acceleration formula we have:
a = (vf - vi) /t
a = (0 m/s - 16 m/s) /4 s
a = (-16 m/s) /4 s
a = -4 m/s²
Acceleration is negative because the car is decelerating
Applying the distance formula, we get:
x = (vf²-vi²)/ (2a)
x = [(0 m/s)²- (16 m/s)²]/ (2 * -4 m/s²)
x = (0 m²/s²- 256 m²/s²)/ -8 m/s²
x = -256 m²/s²/ -8 m/s²
x = 32 m
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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Two airplanes leave an airport at the same
time. The velocity of the first airplane is
710 m/h at a heading of 27.5
◦
. The velocity
of the second is 650 m/h at a heading of 167◦
.
How far apart are they after 3.3 h?
Answer in units of m.
The distance between first airplane and second airplane after 3.3 hours of their departure is 4210.67 meters
Write cosine formula for vector addition?The cosine formula for vector addition is -
|R|² = |A|² + |B|² + 2AB cosφ
Where - φ is the angle between vectors A and B.
Given is two airplanes that leave the airport at same time. The velocity of the first airplane is 710 m/h at a heading of 27.5°. The velocity of the second airplane is 650 m/h at a heading of 167°.
The length of the position vector of first airplane →
|OA| = velocity x time = 710 x 3.3 = 2343 miles.
The length of the position vector of second airplane →
|OB| = velocity x time = 650 x 3.3 = 2145 miles
Angle between vectors OA and OB →
φ = 167° - 27.5° = 139.5°
In the triangle ΔOAB, using the triangle law of vector addition, we get →
OA + AB = OB
AB = OB - OA
AB = OB + (- OA)
Now, using the formula for resultant of addition of two vectors →
AB² = (OB)² + (- OA)² + 2(OA)(- OB) cosφ
AB² = OB² + OA² + - 2(OA)(OB)cosφ
AB² = 54,89,649 + 46,01,025 - 2 x 2343 x 2145 x cos(139.5°)
AB² = 54,89,649 + 46,01,025 - 2 x 2343 x 2145 x - 0.76
AB² = 1,00,90,674 + 76,39,117.2 = 1,77,29,791.2
AB = √1,77,29,791.2
AB = 4210.67 meters
Hence, the distance between first airplane and second airplane after 3.3 hours of their departure is 4210.67 meters
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. A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a
distance of 110 m. Determine the acceleration of the car.
The acceleration of the car is 4.05 m / s², if it accelerates uniformly over a period of 5.21 seconds for 110 meters.
We know that,
a = v / t
v = d / t
where,
a = Acceleration
v = Velocity
t = Time
d = Distance
Given that,
t = 5.21 s
d = 110 m
v = 110 / 5.21
v = 21.11 m / s
a = 21.11 / 5.21
a = 4.05 m / s²
Acceleration is the rate of change of velocity of an object over it period of movement. It is denoted as a.
Therefore, the acceleration of the car is 4.05 m / s².
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when the car comes to a sudden stop, the passenger __________
Continues decelerate
a rocket moves through outer space at 12,800 m/s. at this rate how much time would be required to travel the distance from earth to the moon, which is 380,000 km?
The time required to travel the distance from earth to the moon, which is 380,000 km is 34545.45sec.
To find timeThe formula of speed is speed = distance/time. To check out what the checks are for speed, you must to understand the units for distance and time.
As we know that
Speed = distance/ time
first, convert km into m of distance
then 380,000 km distance will be 380000000m.
putting the given values in the formula
12800 = 380000000 / time
The time required would be
34545.45 seconds.
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If we apply a potential difference of 4. 50 v between the ends of a wire that is 2. 50 m in length and 0. 654 mm in radius, the resulting current through the wire is 17. 6 a. What is the resistivity of the wire material?.
According to the resistance, the resistivity of wire material is 1.37 x 10¯⁷ Ωm.
We need to know about the resistance of conductive material to solve this problem. Resistance can be defined as the ratio of the voltage applied to current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
The resistance of the material depends on its resistivity and follows this equation
R = ρ . L / A
where ρ is resistivity, L is the length of the material and A is the surface.
From the question above, we know that
V = 4.5 V
L = 2.5 m
r = 0.654 mm = 6.54 x 10¯⁴ m
I = 17.6 A
Find the surface area
A = π . r²
A = π . ( 6.54 x 10¯⁴ )²
A = 1.34 x 10¯⁶ m²
Find the resistivity of the wire
R = V / I
ρ . 2.5 / (1.34 x 10¯⁶)= 4.5 / 17.6
ρ = 1.37 x 10¯⁷ Ωm
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G a 240 v<0 source source supplies a balance, three-phase load in a delta configuration. the line current is 3 a<45. what is most nearly the magnitude of the complex power measured across the load
The magnitude of the complex power measured across the load is 1200VA.
What is the complex power?The rms voltage phasor and the complex conjugate of the rms current phasor are combined to create complex power (measured in VA). Real power P and reactive power Q make up the real and imaginary halves of a complicated variable.The phrase "Complex Power" refers to the complex sum of Real Power (P) and Reactive Power (Q). It can be written as S = P+jQ and is expressed in Volt Amps Reactive.Electrical power is essentially represented as a complex number by complex power. It is composed of real and imaginary parts, just like a complex number. The reactive power is represented by the imaginary part, whereas the active power is represented by the real part.The magnitude of the complex power measured across the load is 1200VA.
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a rocket sled having an initial speed of 160 mi/hr is slowed by a channel of water. assume that, during the breaking process, the acceleration a is given by a(v)
The equation of motion in terms of v and x is [tex]\frac{dv}{dx} = -\mu v[/tex]
What is velocity?Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.
A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.
Let [tex]v(t) = \frac{ds}{dt}[/tex] be the velocity of a time t . Now its time rate of change, [tex]\acute{v}[/tex] = [tex]\frac{dv}{dt}[/tex]
is the acceleration, Therefore,
⇒ [tex]a(t)=v^{\prime}(t)=\frac{d}{d t}\left(\frac{d s}{d t}\right)[/tex]
On the other hand, the acceleration will be given by
⇒ [tex]a = - \mu v^2[/tex]
Where [tex]\mu[/tex] is constant, thus
⇒ [tex]\frac{dv}{dt} = -\mu v^2[/tex]
Where is the motion equation expressed in terms of v and t We must now write it in terms of v and x. To accomplish this, we make use of the fact that
⇒ [tex]\frac{d v}{d t}=\frac{d v}{d x} \cdot \frac{d x}{d t}=v \frac{d v}{d x}[/tex]
We now substitute the acquired result into the supplied equation.
⇒ [tex]v \frac{d v}{d x}=\frac{d v}{d t}=-\mu v^2[/tex]
Divide the equation by v ≠ 0
⇒ [tex]\frac{dv}{dx} = -\mu v[/tex]
We have changed the provided equation of motion in terms of v and x in this manner.
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Full question
A rocket sled having an initial speed of 160 mi/h is slowed by a channel of water. Assume that, during the braking process, the acceleration a is given by
[tex]av = -\mu v^2[/tex]
where v is the velocity and \mu is a constant. (a) As in Example 4 in the text, use the relation
[tex]\frac{dv}{dt} = v\frac{dv}{dx}[/tex]
to write the equation of motion in terms of v and x.
After Thanksgiving, Kevin and Gamal use the turkey's wishbone
to
make a wish. If Kevin pulls on it with a force 0.17 N a larger than
the force Gamal pulls
with in the opposite direction, and the
wishbone has a mass of 13
g, what is the wishbone's initial
acceleration?
The acceleration of the wishbone is 13.08 m/s².
What is acceleration?Acceleration is the rate of change of velocity. The S.I unit of acceleration is m/s².
To calculate the initial acceleration of the wishbone, we use the formula below.
Formula:
a = F/m............. Equation 1Where:
a = Acceleration of the wishbonem = Mass of the wishboneF = Net force.From the question,
Given:
F = 0.17 Nm = 13 g = 0.013 kgSubstitute these values into equation 1
a = 0.17/0.013a = 13.08 m/s²Hence, the acceleration of the wishbone is 13.08 m/s².
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the maximum horizontal distance a boy can throw a ball is 45 m. assume he can throw with the seam initial speed at all angles. how high does he throw the ball when he throws it straigth upward
The boy can throw a ball with the same initial speed at all angles then the height of the ball traveled will be 12.6m
What are equation of motion?Equations of motion in physics are equations that explain how a physical system behaves in terms of how its motion changes over time. The behavior of a physical system is described in further detail by the equations of motion as a collection of mathematical functions expressed in terms of dynamic variables.
The three equations are,
v = u + at.
v² = u² + 2as.
s = ut + ½at²
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If the magnified cell had a diameter of 40mm on the computer screen using the 10x ocular lens with the 40x objective lens, what would be the actual diameter of the cell in millimeters?.
The actual diameter of the cell would be 0.1 mm.
How to find the actual diameter of the cell?The magnification caused by the ocular lens is 10x, while the magnification caused by the objective lens is 40x.
As a result, the entire setup will have a 400x overall magnification.
This signifies that a 400x magnification will be applied to an object with a diameter of x m.
The magnified cell in the aforementioned scenario has a diameter of 40 mm.
The amplified diameter is 400x when the true diameter is x.
Hence 400x = 40 mm x
= 40 mm/400x
= 0.1 mm
As a result, the cell's real diameter would be 0.1 mm.
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what is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? use 1.67×10−27 kgkg for the mass of a proton, 1.60×10−19 cc for the magnitude of the charge on an electron, and 9.80 m/s2m/s2 for the magnitude of the free-fall acceleration.
The magnitude of the electric field is 1.023 * [tex]10^{-7}[/tex] N / C
We know that,
F = m g
F = q E
where,
F = Force
m =Mass
g = Acceleration due to gravity
q = Charge of an electron
Given that,
m = 1.67 * [tex]10^{-27}[/tex] kg
q = 1.6 * [tex]10^{-19}[/tex] C
g = 9.8 m / [tex]s^{2}[/tex]
F = m g = 1.67 * [tex]10^{-27}[/tex] * 9.8
F = 16.37 * [tex]10^{-27}[/tex] N
F = q E
E = 16.37 * [tex]10^{-27}[/tex] / 1.6 * [tex]10^{-19}[/tex]
E = 1.023 * [tex]10^{-7}[/tex] N / C
Electric field is the field surrounding an electrically charged particle. If any other charged particle enters the field, it exerts force on the particle.
Therefore, the magnitude of the electric field is 1.023 * [tex]10^{-7}[/tex] N / C
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Some rocks are pushed deeper into the earth. As these rocks experience greater heat and pressure, what type of rock will they turn into if they do not melt?.
Some rocks are pushed deeper into the earth. As these rocks experience greater heat and pressure, they will turn into metamorphic rocks if they do not melt.
Although they began as a different kind of rock, metamorphic rocks have undergone significant alteration from their igneous, sedimentary, or previous metamorphic forms. When rocks are exposed to extreme temperatures, high pressures, hot mineral-rich fluids, or, more frequently, some combination of these conditions, metamorphic rocks are created.
Metamorphic rocks, which have been exposed at the Earth's surface as a result of erosion and uplift, can be studied to learn more about the pressures and temperatures that exist at extremely deep levels of the crust. The metamorphic rocks gneiss, slate, marble, schist, and quartzite are a few examples.
The two classifications of metamorphic rocks are foliates and non-foliates. Micas and chlorites make up a sizable portion of foliates.
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The complete question is ''Some rocks are pushed deeper into the earth. as these rocks experience greater heat and pressure, what type of rock will they turn into if they do not melt?
a. molten
b. sedimentary
c. igneous
d. metamorphic
. A family leaves for an evening walk around the neighborhood. They leave at 5 pm and return at 6 pm. They traveled a total of 2.5 miles. What is their average speed?
6. It takes you 20 minutes to walk 1.5 miles to school. How far can you walk in one hour?
I need an explanation on how you got the answer.
The average speed of the family is 2.5 mph.
At the same speed used to walk to school, the distance traveled in one hour is 4.5 miles.
What is average speed?The average speed of an object is the total distance traveled by the object to the total time of motion of the object.
v = total distance / total time motion
total distance = 2.5 miles
total time = 6 pm - 5 pm = 1 hour
v = (2.5 miles) / (1 hour)
v = 2.5 mph
When it takes 20 minutes to walk 1.5 miles, the speed of the motion is calculated as follows;
time = 20 mins / 60 mins/hr = 0.333 hr
v = 1.5 miles / 0.333 hr = 4.5 mph
At this speed, the distance traveled in one hour is calculated as follows;
d = 4.5 mph x 1 hr
d = 4.5 miles
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a piano wire with mass 3.50 g and length 75.0 cm is stretched with a tension of 27.0 n . a wave with frequency 120 hz and amplitude 1.70 mm travels along the wire.
The average power is 0.1570 W.
Piano wire weighs 3.50 g.
Size: 83.0 cm
Tension = 35.0 N
120 Hz is the frequency.
Suppose we need to determine the average power carried by the wave with an amplitude of 1.20 mm.
We need to calculate the angular frequency
Using formula of frequency
ω = 2[tex]\pi[/tex]f
ω = 753.9 rad/sec
We need to calculate the linear density
Using formula of linear density
μ = M/l
μ = [tex]4.21[/tex] ×[tex]10^{-3}[/tex] kg/m
We need to calculate the average power
[tex]P_{avg}[/tex] = 0.1570 W
What is power ?Physics refers to power as the amount of energy that is transferred or transformed per unit of time. In the International System of Units, the unit of power is the watt, or one joule per second. In ancient literature, activity is another word for power.
Power is correlated with other factors; for instance, the power required to move a ground vehicle is a function of the vehicle's velocity and the traction force acting on its wheels. A motor's output power is calculated by multiplying its torque output by the angular velocity of its output shaft. The power lost by an electrical component in a circuit is also a function of the voltage across the component and the current that flows through it.
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Which mixture of solids can be separated by using both shape and size?
A: Beans, ground coffee, and baking powder
B: Oval beads, marbles, and dice
C: Sand, sea shells, and salt
D: White rice, yellow string beans, and green string beans
The mixture of solids that can be separated by using both shape and size is oval beads, marbles, and dice (option B).
What is a mixture?A mixture in chemistry is any substance that is made up of two or more constituents that can easily be separated using physical means.
Mixtures, unlike compounds, contain substances that retain their chemical composition since there is no chemical bonding.
This makes the components of a mixture separable by physical techniques such as heating, magnetism etc.
Therefore, the mixture of solids that can be separated by using both shape and size is oval beads, marbles, and dice because they are all of different and unique shapes and sizes.
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An 18-year-old runner can complete a 10.0 km course with an average speed of 4.60 m/s. A 50-year-old runner can cover the same distance with an average speed of 4.13 m/s. How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?
Taking into account the definition of speed, the 18-year-old runner must start 247.3945 s after the 50-year-old runner in order to finish the course at the same time.
Definition of speedSpeed is a quantity that expresses the relationship between the space traveled by an object and the time used for it.
In other words, speed can be defined as the change of position of an object in space within a certain amount of time and can be calculated using the expression:
speed= distance traveled÷ time
Time in this caseIn this case, you know:
An 18-year-old runner can complete a 10 km (10000 m, being 1 km equals to 1000 m) course with an average speed of 4.60 m/s. A 50-year-old runner can cover the same distance (10 km) with an average speed of 4.13 m/s.Replacing these values in the speed definition, it is possible to obtain the time that each runner needs to complete the race:
18-year-old runner: 4.60 m/s= 10000 m÷time50-year-old runner: 4.13 m/s= 10000 m÷timeSolving:
18-year-old runner: 4.60 m/s×time= 10000 m → time= 10000 m÷ 4.60 m/s → time= 2173.9130 s50-year-old runner: 4.13 m/s× time= 10000 m → time= 10000 m÷ 4.13 m/s → time= 2421.3075 sTo know the amount of time after which the youngest runner must start to finish the course at the same time as the oldest runner, the difference between the time it takes each runner to finish the course must be made:
difference of time= time of the 50-year-old runner - time of 18-year-old runner
difference of time= 2421.3075 s - 2173.9130 s
difference of time= 247.3945 s
Finally, the 18-year-old runner must start 247.3945 s after the 50-year-old runner in order to finish the course at the same time.
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I throw a rock at 20 m/s off of a cliff. If it takes 5 s to hit the ground, how tall was the cliff
Answer:
100 meters, I believe.
Explanation:
The correct answer for the value of height of the cliff is [tex]22.5[/tex] meter.
Given:
initial velocity: [tex]20[/tex] m/s
Final velocity: [tex]0[/tex] m/s
Time taken: [tex]5[/tex] seconds
To calculate height of the cliff, Use equation of motion:
[tex]s= ut + \dfrac{1}{2}gt^2[/tex]
[tex]g[/tex] will be negative as rock is thrown below the initial point.
[tex]s=[/tex] Height of the cliff
[tex]= 20*5 + \dfrac{1}{2} *(-9.8) * 25[/tex]
[tex]= 100 - 122.5[/tex]
[tex]= -22.5[/tex] meter
negative sign indicates downward direction
Height of the cliff is [tex]22.5[/tex] meter.
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Please help question in the picture below.
Answer:
c. an electron is the particle of an atom that is negatively charged
Explanation:
the other statements are not the best at defining an electron