A block of mass 5.00 kg rests on a horizontal surface where the coefficient of kinetic friction between the two is 0.200. a string attached to the block is pulled in direction 25 degrees with horizontal, resulting in a 2.50-m/s2 acceleration by the block. find the tension in the string. (g = 9.80 m/s2)

Answers

Answer 1

The tension in the string is 19.8 N.

What is mass?Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.For instance, a kilogram mass weighs around 2.2 pounds at the surface of the planet. However, the same kilogram mass would weigh just about 0.8 pounds on Mars and about 5.5 pounds on Jupiter.An object's mass is a crucial indicator of how much stuff it contains. Weight is a measurement of an object's gravitational pull. It is influenced by the object's location in addition to its mass. As a result, weight is a measurement of force.

Find the tension in the string:

The net force on the block will be:

T - Fr = Fnet = ma

Where T is the tension and Fr is the frictional force

T - ukR = ma

Where R is the upwards normal force equal to the block's weight. R = mg

therefore,

T - uk mg = ma

T - 0.2(5 x 9.8) = 5(2)

=> T = (0.2 x 5 x 9.8) + 5(2) = 19.8 N

This is the tension in the string.

For the free body diagram, draw a block and show a rope connected horizontally to it. The tension in the string will be along the rope outwards from the block. Now, the frictional force will be between the ground and the block and it will be in the opposite direction to the direction of tension of the rope. The force due to gravity will act vertically downwards while the normal force R will act vertically upwards.

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Related Questions

in a women's 100-m race, accelerating uniformly, laura takes 2.16 s and healan 3.22 s to attain their maximum speeds, which they each maintain for the rest of the race. they cross the finish line simultaneously, both setting a world record of 10.4 s.

Answers

The acceleration of Laura is 5.32 m/s² and that of Healen is 3.75 m/s².

What is velocity?

Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.

A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.

Maximum speed of Laura is [tex]\Delta_{t1} = 2s[/tex]

Maximum speed of Healen is [tex]\Delta_{t2} = 3s[/tex]

Each runs at a constant acceleration for a given time interval, giving,

[tex]\Delta x_a = \frac{1}{2} a\Delta t^2[/tex]

This reaches final velocity

⇒ [tex]v = a\Delta t[/tex]

⇒ [tex]\Delta x_v = v(T - \Delta t)[/tex]

⇒ [tex]\Delta x_v =a\Delta t(T - \Delta t)[/tex]

Each sprinter's acceleration is calculated as follows:

Laura :-

⇒ [tex]\Delta t_1 = 2s[/tex]

⇒ [tex]a_1 = \frac{100m}{18.8s^2}[/tex]

⇒ [tex]a_1[/tex] = 5.32 m/s²

Healen :-

⇒ [tex]\Delta t_2 = 3s[/tex]

⇒ [tex]a_2 = \frac{100m}{26.7s^2}[/tex]

⇒ [tex]a_2[/tex] = 3.75 m/s²

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Full question

In a women's 100 m race, accelerating uniformly, Laura takes 2.00 s and Healan 3.00 s to attain their maximum speeds, which they each maintain for the rest of the race. They cross the finish line simultaneously, both setting a world record of 10.4 s.

A) What is the acceleration of each sprinter?

What are gears? Gears are wheels Gears are ramps with teeth Gears are wheels with teeth Gears are twisted ramps

Answers

device that regulates how much engine power flows to a machine's moving parts, frequently made of connected sets of wheels with teeth around the edges. Hence, option C is correct.

What is Gear?

A gear is a spinning, circular machine element with teeth that can be cut, or in the case of a cogwheel or gearwheel, they can be inserted. These teeth, known as cogs, mesh with another toothed part to transmit (convert) torque and speed. The fundamental idea underlying how gears work is comparable to the fundamental idea behind how levers work.  Cog is another casual term for gear. A power source's speed, torque, and direction can all be altered by geared devices.

So, the exact definition of gear is that gears are wheels with teeth.

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Answer:

Gears are wheels with teeth

3) a current of 20 a passes through an oven’s heating element which has a resistance of 10 ω for 2.5 hours. determine the power input of the fireplace and the consumed electrical energy in kwh.

Answers

In a day, an electrical resistance heater uses 10 kW-h of electricity. In the same day, the heater delivers 9 kW-h of heat to the house in which it is located.

What is resistance ?

A measurement of an object's resistance to the flow of electrical current is called electrical resistance. Electrical conductance, which gauges how easily an electric current moves, is its reciprocal quantity. Mechanical friction and electrical resistance conceptually have some similarities. Electrical resistance is measured in ohms (), the SI unit of electrical resistance, whereas electrical conductance is measured in siemens (S), also known as the mho (), the SI unit of electrical conductance.

An object's resistance is significantly influenced by the material it is constructed of. Electrical insulators like rubber typically have very high resistance and low conductance, whereas electrical conductors like metals typically have very low resistance and high conductance. Resistivity or conductivity are used to measure this relationship.

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URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS

Answers

Answer: A. use a thicker piece of wire.

Explanation:

A researcher tests acceleration due to gravity by dropping a pebble in an evacuated tube. after 0.5 seconds the pebble falls 1.226 meters. What is the acceleration due to gravity measured by the researcher? SHOW WORK

Answers

Answer:

See below

Explanation:

d = 1/2 a t^2

1.226 = 1/2 a (.5)^2

a = 1.226/(1/2 * .5^2)

a = 9.808 m/s^2

A researcher tests acceleration due to gravity then the acceleration due to gravity measured by the researcher is 9.808 m/s².

What is acceleration?

In mechanics, acceleration refers to the speed at which an object's velocity varies over time. how many accelerations each vector has. An object's acceleration is determined by the direction of the net force exerted on it.

Due to the fact that it has both a magnitude and a direction, acceleration is a vector quantity. Velocity is a different vector property.

According to the question,

Time, t = 0.5 seconds

Distance, s = 1.226 meters

s = 1/2 a t²

1.226 = 1/2 a (0.5)²

a = 1.226 / (1/2 *0.5²)

a = 9.808 m/s²

So, the acceleration due to gravity is 9.808 m/s².

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an electrician needs to install a surface-mounted, nonmetallic, weatherproof cabinet on the outside of a concrete block building. since the cabinet must be mounted in a wet location, it must be mounted so there is at least in. of airspace between the cabinet and the wall.

Answers

Since the cabinet must be mounted in a wet location, it must be mounted so there is at least 1/4 of airspace between the cabinet and the wall.

What is airspace?

The area of the atmosphere that is under the authority of a nation above its territory, including its territorial waters, or, more broadly, any particular three-dimensional area of the atmosphere

It is not the same as aerospace, the umbrella term for the Earth's atmosphere and the proximity of outer space.

Wherever it is deemed necessary for air traffic control to exercise any sort of direct executive oversight over aircraft operating there, that area of the sky is known as controlled airspace.

A range of areas and zones, including those where flying operations are either completely prohibited or subject to restrictions, may be included in the further division of airspace.

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Are masks effective in slowing the spread of COVID-19? In a few sentences, make a hypothesis and design and describe an experiment on how you could TEST this yourself using common household materials.

Answers

Answer:

Not really, because wearing a mask can lower your immune system and covid can be caught like any other virus body contact and body fluids. So since you can still get it through those ways then you're going to get it and be worse off than if you don't wear a mask.

you can test this by not wearing a mask and see how not bad it is catching covid over getting it while you wear a mask.

Explanation:

Answer:

Yes

Explanation:

Hypothesis- if masks are used to protect yourself from Covid-19 then the spread of the virus will decrease

You could test this by:

Getting a mask and using materials such as shampoo, soap, honey, glue,  or (safe) chemicals to see how much the masks absorbs the materials. By doing so you can show how the mask can help block certain materials from entering or leaving the mask area therefore slowing the spread of Covid.

013 10.0 points
Given: The battleship and enemy ships A
and B lie along a straight line. Neglect air
friction.
A battleship simultaneously fires two shells
with the same initial velocity at these two
enemy ships.
battleship
If the shells follow the parabolic trajectories
shown in the figure, which ship gets hit first?
1. both at the same time
2, need more information
3. A
4. B

Answers

Ship A with a greater angle of projection will hit the target first.

What is time of flight?

The time of flight is the time a projectile takes to reach maximum height and return to the plane of projection. The time of flight is just double the maximum-height time.

Mathematically, time of flight is given as;

T = (2usinθ)/g

where;

u is the initial velocity of projectionθ is angle of projection

The time of flight depends on initial velocity of the object and angle of projection.

When the initial velocity of both ships is the same and angle of projection varies, the difference in the time of flight will depend greatly on the angle of projection.

Thus, ship A with a greater angle of projection will hit the target first.

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In the ____ letter style, the date, complimentary close, and signature block are positioned approximately one-half inch to the right of center or at the right margin.

Answers

In the Modified Block letter style, the date, complimentary close, and signature block are positioned approximately one-half inch to the right of center or at the right margin.

Following the proper format while writing business letters is crucial. There are specific methods that business letters have to be written.

The modified block letter style, which places one space between the body of the letter and the addresses of the sender and recipient, is one of the several letter kinds. In this form of letter, one space corresponds to around half an inch to the right of centre or at the right margin. Modified block letter formats are largely the same as full-block business letters.

Modified block format is a different extensively used format. The letter body, along with the sender and recipient's addresses, are left justified and single-spaced in this format. On the other hand, tab to the centre and start typing for the date and closure. Semi-Block. Semi-block is the last and least popular type of style.

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According to history, the concept that all matter is composed of atoms was first proposed by.

Answers

Answer:

John Dalton

Explanation:

Answer:

chemist John Dalton

Explanation:

:)

​you're driving down the highway late one night at when a deer steps onto the road in front of you. your reaction time before stepping on the brakes is ​, and the maximum deceleration of your car is

Answers

The distance between you and the deer when you come to a stop is

s = d - 30 = 18 m.

The maximum speed you could have and still not hit the deer is

v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]

  = 26m/s

What is the distance between you and the deer?

You're driving down the highway late one night at 20m/s when a deer steps onto road d in front of you.

Your reaction time before stepping on the brakes is 0.50s and the maximum deceleration of your car is 10m/s2.

Given,

Speed = 20m/s

Time = 0.50 s

Distance = d

Deceleration = 10m/s2

D = R × T

D = Vi × Tr

D = (20 m/s) × (0.50 s)

D = 10 m

Dd = [ Vf^2 - Vi^2 ] / [ 2 × (-10 m/s^2) ]

Dd = [ (0.0 m/s)^2 - (20 m/s)^2 ] / (-20 m/s^2)

Dd = [ -400 m^2/s^2 ] / (-20 m/s^2)

Dd = 20 m

The total distance traveled is

Dt = D + Dd

Dt = (10 m) + (20 m)

Dt = 30 m

The distance between you and the deer when you come to a stop is

s = d - 30 = 18 m.

The maximum speed you could have and still not hit the deer is

v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]

  = 26m/s

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1. Initial velocity=0 km/h
Final velocity=24 km/h
Time=3 seconds

2. Initial velocity=0 km/h
Final velocity=35 m/s
Time=5 seconds

3. Initial velocity=20 km/h
Final velocity=60 km/h
Time=10 seconds

4. Initial velocity=50 m/s
Final velocity=150 m/s
Time=5 seconds

What is the acceleration for each problem?

Answers

The accelerations for each problem are:

1. 2.22m/[tex]s^{2}[/tex]

2. 7m/[tex]s^{2}[/tex]

3. 1.45m/[tex]s^{2}[/tex]

4. 20m/[tex]s^{2}[/tex]

What is acceleration due to gravity?

The acceleration which is gained by the object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/[tex]s^{2}[/tex]. Acceleration due to gravity is a vector, which means it has both magnitude and direction. The acceleration due to gravity at the surface of the Earth is represented by letter g. It has standard value defined as 9.80665 m/s2 (32.1740 ft/s2). However, actual acceleration of a body in free fall varies with location.

1. Initial velocity=0 km/h

Final velocity=24 km/h= 6.66m/s

Time=3 seconds

acceleration =[tex]\frac{6.66-0}{3}[/tex]=2.22m/[tex]s^{2}[/tex]

2. Initial velocity=0 km/h

Final velocity=35 m/s

Time=5 seconds

acceleration = [tex]\frac{35-0}{5}[/tex]=7m/[tex]s^{2}[/tex]

3. Initial velocity=20 km/h=5.55[tex]m/s^{2}[/tex]

Final velocity=60 km/h= 20m/[tex]s^{2}[/tex]

Time=10 seconds

acceleration= [tex]\frac{20-5.55}{10}[/tex]= 1.45m/[tex]s^{2}[/tex]

4. Initial velocity=50 m/s

Final velocity=150 m/s

Time=5 seconds

acceleration= [tex]\frac{150-50}{5}[/tex]= 20m/[tex]s^{2}[/tex]

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You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
a. How long does it take the stone to reach the bottom of the cliff?
b. How far from the base of the cliff does the stone hit the ground?
c. What are the horizontal and vertical components of the stone’s velocity just before it hits the ground?

Answers

a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.

from above statement we got

height = 78.4 m

since the ball is thrown, so its vertical velocity would be zero

u = 0

taking g = 9.8m/s^2

now, using the equation of motion

h = ut + gt^2/2

now putting all the values in it

we got ,

78.4 = 9.8 * t^2/ 2

by solving we got,

t = 4 sec

b) now, since along the horizontal , no force acting and accelaration is zero so

R = ut , R is RANGE

R = 5 * 4

range =  20 m

c)  vertical components of the stone’s velocity just before it hits the ground = v sin θ =

horizontal   components of the stone’s velocity  just before it hits the ground = v cos θ

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What is the final speed?

Answers

Answer:

30 m/s

Explanation:

We can first list out the 3 kinematics equations:

[tex]v = u + at \\ {v}^{2} = {u}^{2} + 2as \\ s = ut + \frac{1}{2} a {t}^{2} [/tex]

Where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

s is the displacement

With all the 3 equations, we can now list the values needed for the first part of the question which is to find the acceleration for this first part.

Given:

v = 14 m/s

u = 6 m/s

t = 8s

We can use the first kinematics equation to solve for a. (v = u + at)

14 = 6 + a x 8

14 = 6 + 8a

8a = 14 - 6

8a = 8

a =

[tex]1 \frac{m}{ {s}^{2} } [/tex]

Now with this acceleration, we can find the final speed for the second part of the question by using the same kinematics equation. (v = u + at)

Given,

u = 14 m/s

t = 16 s

a =

[tex]1 \frac{m}{ {s}^{2} } [/tex]

v = 14 + (1)(16) = 14 + 16 = 30 m/s

a sinusoidal wave travels along a lightweight string with wavelength 1 and frequency f1. it reaches a heavier string, with a slower wave speed, and continues on with wavelength  2 and frequency f2. which is true?

Answers

The true statement for sinusoidal wave travelling  along a light weight string =

lambda₂<  lambda₁  and f₂ = f₁

λ₂ ≤ λ₂

Sinusoidal wave :  

The sine or sinusoidal wave may be a curve that describes a smooth repetitive oscillation. we will define the sine wave as “The wave form in which the amplitude is always proportional to sine of its displacement angle at every point of time”. All waves are often made by adding up sine waves

Why is it called sinusoidal wave?

Then the waveform shape produced by our simple single loop generator is usually referred to as a Sine Wave as it is said to be sinusoidal in its shape. this sort of waveform is called a sine wave because it is based on the trigonometric sine function used in mathematics.

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give the instantaneous velocity (including unit vector) of the object at t=1.5s

Answers

Since an object's instantaneous velocity equals the derivative of its displacement at a certain point, we can also state that the instantaneous velocity at time t = 1 is around 2 meters per second.

The derivative of x with respect to t, or the upper limit of the average velocity as the elapsed time approaches 0, is the instantaneous velocity of an object:

v (t) equals d d t x (t). v (t) equals d d t x (t).

Instantaneous velocity is a vector having a dimension of length per time, similar to average velocity. The speed of an object at a specific time is its instantaneous speed. The instantaneous velocity is obtained by adding the direction to the speed.

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8. A rock is dropped from a cliff and takes 6 seconds to hit the ground. At what time is the
acceleration of the rock the greatest?

Answers

Answer:

A hiker drops a heavy stone over a cliff and hear it strike the cliff base 2.8seconds after dropping it.

A piece of plywood in which several holes are being drilled successively has been secured to workbench by means of two nails. Knowing that the drill exerts a 15-n·m couple on the piece of plywood, determine the magnitude of the resulting forces applied to the nails for the given locations. The nails are located at b and c. The magnitude of the resultant is n

Answers

The magnitude of force applied to the nails when they are located between point A and B is 37.5 N.

The magnitude of force applied to the nails when they are located between point B and C is 62.5N.

The force applied to the nails when they are located between point A and C is 29.41N

The moment exerted by the drill machine is: M =15 N⋅m

(a) The magnitude of force applied to the nails when they are located between point A and B.

Fa=M/AB

AB is distance between points A and B.

Plug in all the values in the above equation.

Fa=15 N⋅m/450mm

=15 N⋅m/0.45m

=37.5 N

Therefore, the magnitude of force applied to the nails when they are located between point A and B is 37.5 N.

(b)The magnitude of force applied to the nails when they are located between point B and C.

Fb=M/BC

BC is distance between points B and C.

Substitute all the values in the above equation.

Fb=15 N.m/240mm

=15 N.m/0.24m

= 62.5N

Thus, the magnitude of force applied to the nails when they are located between point B and C is 62.5N.

(c) The distance between points AC is,

AC=√(AB)2+(AC)2

Plug in all the values in the above equation.

AC=√(450mm)2 +(240mm)2

=510mm

=0.51m

The magnitude of force applied to the nails when they are located between point A and C.

Fc=M/AC

Substitute all the values in the above equation.

Fc=15 N⋅m/0.51m

=29.41 N

Thus, the force applied to the nails when they are located between point A and C is 29.41N

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A 25. 0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0. 250, and the coefficient of static friction is 0. 350.

Answers

The minimum angle at which the box starts to slip is  20.30°, the acceleration once the box has begun to move is 1.10 m/s2 and final velocity of the box is 3.41 m/s^2.

Given:

Mass of the box m = 25.2 kg

Acceleration due to gravity g = 9.8 m/s^2

Coefficient of kinetic friction between the ramp and box  μk=0.25

Coefficient of static friction μs = 0.37

Part(A)

By inctreasing, parallel component of the weight will also increase but the force will decrease.

Let say θ be the angle of repose.

Now we know that

Ff= μs × mg × cosθ = mg × sinθ = Wp

Then we will get

θ = tan−1(μs)

θ = tan-1 (0.37) = 20.30 °

Part(B)

As the box starts sliding the frictional force becomes kinetic friction

The kinetic frictional force

F(k) = μ(k) x mg x cos(20.30)

= 0.25 × 25.2 × 9.8 × cos (20.30)

= 57.91 N

Now calculate the parallel component of the weight

W(p) = mg x sinθ

W(p) = 25.2 x 9.8 x cos (20.30)

= 85.68 N

Now calculate net force

F(net) = W(p) − F(k) = 85.68 − 57.91 = 27.77 N

Acceleration of the box

a = Fn/m = 27.77/25.2 = 1.10 m/s2

Part(C)

The box has moved a distance s = 5.3 m

The final speed of the box = v

Now

v = √ 2as

v = √ 2 x 1.10 x 5.3

v = 3.41 m/s^2

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The complete question is

A 25. 0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0. 250, and the coefficient of static friction is 0. 350. Part A) As the angle θ is increased, find the minimum angle at which the box starts to slip. Express your answer using two significant figures. Part B) At this angle, find the acceleration once the box has begun to move. Express your answer using two significant figures. Part C) At this angle, how fast will the box be moving after it has slid a distance 5.3 m along the loading ramp? Express your answer using two significant figures.

which of the statements regarding displacement is true? displacement is a scalar quantity just as length. displacement depends on the chosen origin of coordinates. displacement has the same meaning of distance. displacement tells the average direction of motion. displacement depends on time elapsed during the motion.

Answers

The statement "displacement tells the average direction of motion" regarding displacement is true.

What is velocity?

Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.

A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.

Average velocity is calculated by taking the displacement vector from the start and end-point of an object’s path, and dividing its magnitude by the time interval. The average velocity always has the same direction as that displacement vector.

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. Removing thermal energy from liquid water can cause it to change to what state?

Answers

Answer: solid state

Explanation:

The change from the liquid state to the solid state is called freezing. As the liquid cools, it loses thermal energy. As a result, its particles slow down and come closer together. Attractive forces begin to trap particles, and the crystals of a solid begin to form.

An automobile is traveling on a long straight highway at a steady 33.5 m/s when the driver sees a wreck 150m ahead on the side of the road. At that instant, she applies the brakes (ignore reaction time). Between her and the wreck are two different surfaces. First there is 100m of ice, where her deceleration is only 1m/s^2. From then on she is on dry concrete, where her deceleration is a more normal 7m/s^2.
a) What was her speed just after leaving the icy portion of the road?
b) How much total distance does it take her to stop?
c) What is the total time it took her to stop?

I just need b and c!! The answers are given but I can't figure out how to get to them.
Answers given by the WS -
B - 165.9m
C - 7.4s

Answers

a) her speed is  26.43m/s

b)  Total distance traveled = 100 + 49.89

= 149.89m

c) Total time is 10.846 seconds

What is acceleration?

acceleration is the rate of change of the velocity of an object with respect to time.

From the question,

a) The car’s speed just after leaving the icy portion of the road is the first part

We have s = ut + 1/2at²

Here s = 100m, a = 1, u = 33.5 m/s

100 = 0* t + 1/2 * (-1) * t²

t = 7.07 seconds

After 7.07 seconds cars speed is given by v =u +at

u = 33.5m/s, a = -1

velocity = 33.5 + (-1) * 7.07 = 26.43m/s

So velocity of car on leaving icy surface = 26.43m/s

b) Time taken after icy surface

           0 = 26. 43 - 7 * t

            t = 3.776 seconds

 Distance traveled during this time

v² = u² + 2as

0 = (26.43)² + 2 * (-7) * S

s = 49.89 m

Total distance traveled = 100 + 49.89

= 149.89m

c) Total time taken = 3.776 + 7.07

Total time is 10.846 seconds

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Suppose you go on a trip that covers 360 km and takes 6 Hours. What would your average speed be? 2. A car travels around a mountain. It travels a distance of 120 miles in 3 hours. What is the average speed of the car?


I need the answer for this and I want a step by step explanation on how you got the answer and if I need to use formulas.

Answers

Answer:

60 m/hStep-by-step

explanation:S = d/t

S= 360/60

S= 60

Advantages and disadvantages of refracting telescope

Answers

Answer:

The refractor telescope has many advantages and disadvantages. One of the disadvantages is that the lenses are made of glasses therefore it has to be perfect with no air bubbles or scratches in the glass as this will impair the users viewing. Another disadvantage is that lense are weakest around the edges because they are thinnest there and that is the only place they are being supported by the telescope so this can lead to easy breakage. The lense can have colour distortion which means when white light goes through the lense it is split into colours. Since violet right is refracted more than red, the violet is brought to a focus clearer and this will make the image coloured and blurred, this is called chromatic aberration. Some advantages of refractor telescopes is that refractor telescopes are rugged meaning it is more resistant to misalignment than the reflector telescopes after their initial alignment. The glass surfaces don’t really need cleaning because it is sealed from the atmosphere this is efficient! The images are sharper, steadier and better than a reflector telescope because the tube is closed off from the outside and there will be no effects of changing temperatures or air currents. The focal length of a lense is proportional to the size of the image that is produced. Therefore if the focal length is longer the image will be larger. How bright an image will be also depends on how much light is collected by the telescope.

A cheetah can go from a state of resting to running at 20 m/s in just 2 seconds. what is the cheetah’s average acceleration? responses 0.1 m/s2 0.1 m/s 2 10 m/s2 10 m/s 2 0.1 m/s 0.1 m/s 10 m/s

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The cheetah that can go from a state of resting to running at 20 m/s in just 2 seconds has an average acceleration of: 10 m/s²

The formulas for uniformly varied rectilinear motion (UVRM) and procedures we will use to solve this exercise are:

a = (vf - vi) /t

Where:

vf = final velocityvi = initial velocitya = accelerationt= time

Information about the problem:

vi =  0 m/svf= 20 m/st = 2 sa = ?

Applying the acceleration formula we have:

a = (vf - vi) /t

a = (20 m/s - 0 m/s) /2 s

a = (20 m/s) /2 s

a =  10 m/s²

What is acceleration?

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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An airplane was flying from Cincinnati to Denver. The velocity of an airplane was measured shortly after take off at 10km/min. The velocity was measured again midflight (at its fastest) 18km/min. 90 min passed between the 2 velocity measurements. What is the acceleration of the airplane?
720 km/min2
0.3 km/min2
2 km/min2
0.9 km/min2

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The acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².

How to calculate acceleration?

The acceleration of a moving substance can be calculated by dividing the change in velocity by the time taken as follows:

a = (v - u)/t

Where;

a = accelerationv = final velocity (km/min)u = initial velocity (km/min)t = time (minutes)

According to this question, an airplane was flying from Cincinnati to Denver. The velocity of an airplane was measured shortly after take off at 10km/min. The velocity was measured again mid-flight to be 18km/min.

a = (18km/min - 10km/min)/90min

a = 8km/min ÷ 90min

a = 0.09km/min²

Therefore, acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².

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Sameer went on his bike from Delhi to Gurgaon at a speed of 60km/hr and came back at a speed of 40km/hr. what is his average speed for entire journey.​

Answers

The average speed for the entire journey is 48 km/hr.

The average speed is the sum distance which is traveled by the object in a particular time interval, as the average speed is a scalar quantity and it is presented by the magnitude and has no direction.

here the first speed v₁ is 60 km/hr and the second speed v₂ is the 40 km/hr .So,  The formula we are referring to for calculating the average  speed

  S = 2v₁v₂/(v₁+v₂)

here,   v₁+v₂ =  60+40 =100

Now substituting the desired values  in the formula  

        =  2 x 60 x40/(100)

       =  4800/100

       = 48 km/hr

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what minimum heat is needed to bring 50 g of water at 50 ∘c to the boiling point and completely boil it away? the specific heat of water is 4190 j/(kg⋅k) and its heat of vaporization is 22.6 × 10 5 j/kg .

Answers

The minimum heat required is 129.7KJ.

How to find the minimum heat?

Given

Mass of water (m) = 50g

Initial temperature [tex]T_{i}[/tex] = 20°C

Final temperature [tex]T_{f}[/tex] = 100°C

Specific heat of water =4190 J/kg-k

The heat of vaporization (L) = 22.6 × 10 5 j/kg .

The heat required = Heat required to raise water temperature from 20 to 100 + Heat to vapourize water thoroughly.

Q=mc([tex]T_{f} - T_{i}[/tex]) + mL

Q=0.05 * 4190 (100-20) + 0.05 * 22.6 × [tex]10^{5}[/tex]

Q=(0.16760 + 1.13)× [tex]10^{5}[/tex]

Q=1.2976 × [tex]10^{5}[/tex]

  = 129.7KJ

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How is the electrostatic force (Felect) related to the separation distance (d) the two charges?
1- Keeping the magnitude of charge on both objects constant, conduct a systematic study to collect data relating separation distance to force. The separation distance is defined as the distance between the centers of the two objects; the best strategy involves centering the objects on a gridline and using distances that are a whole number of squares.
2- Draw a graph represent relationship between force and separation

Answers

Answer:The electrostatic force is directly related to the product of the charges and inversely related to the square of the separation distance.

Explanation:

A force of 32n is applied to an area of 12.8m2. work out the pressure



HELPPP MEEEEEEE

Answers

The pressure when 32 newtons of force is applied to an area of 12.8 m² is 2.5 Pascals.

The force applied per unit area is defined as pressure.. Its S.I. unit is Pascal. 1 Pascal is equal to one Newton of force applied over an area of one meter squared. Its dimensional formula is [[tex]ML^{-1}[/tex][tex]T^{-2}[/tex]].

Pressure is directly proportional to the force applied and inversely proportional to the area over which the force is applied. And it follows the Pascal law.

Pressure = Force/Area

Given in the Question

Force = 32 Newton

Area = 12.8 m²

Put in the values, we get

Pressure = 32/12.8

Pressure = 2.5 Pascals

Therefore, the pressure when 32 newtons of force is applied to an area of 12.8 m² is 2.5 Pascals.

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