The correct answer is 21 m.
The term "uniformly accelerated motion" refers to a body or object moving at a consistent rate of acceleration. The absence of velocity does not imply constant acceleration. Therefore, if a body is in motion such that the amount of change in its velocity in equally spaced time intervals will be constant, then that is what is meant by uniform acceleration or uniform acceleration definition.
Given initial velocity = 0 m/s
acceleration = 6 m/s^2
The body's movement in nth seconds in terms of distance,
S_n = u + a/2 (2n-1)
S_4 = 0 + 6/2 ( 2 × 4 - 1 )
S_4 = 3 ( 8 -1 )
S_4 = 3 × 7
S_4 = 21 m
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rajesh used a lens to burn a piece of paper.what is the lens?draw a ray diagram related to this process
If we want to burn a paper by focusing sunlight then we have to use a converging lens that can converge all sunlight at a point called the focus.
Thus Convex lens is used to burn the paper.
What is the lens?The transmissive optical device known as a lens employs refraction to focus or disperse a light beam. While a compound lens is made up of numerous simple lenses (elements), they are typically oriented along a common axis, as opposed to a simple lens, which is made up of a single transparent piece. Materials like glass or plastic are used to create lenses, which are then polished, ground, or molded into the desired shape. Unlike a prism, which refracts light without concentrating, a lens can focus light to create an image. Lenses are also used to describe instruments that focus or scatter waves of radiation other than visible light, such as explosives, microwaves, and electron lenses.
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How much force is needed to accelerate a 1400 kg car from rest to 14 meters/sec in 7 seconds?
Answer:
2800 N
Explanation:
Acceleration = change in velocity / change in time
= 14 m/s / 7 s = 2 m/s^2
F = ma
= 1400 (2) = 2800 N
A car goes from 30 m/s to 10 m/s how long does it take with a acceleration of -2
[tex] \large \bf \implies{s = 200 \: m}[/tex]
Step-by-step explanation:Given :Initial velocity (u) = 30 m/sFinal velocity (v) = 10 m/sAcceleration (a) = -2 m/s²To Find :-Distance (s) = ?Solution :-Using third equation of motion we have find the distance :2as = v² - u²Putting the values according to equation :2 × (-2) × s = (10)² - (30)²-4s = 100 - 900-4s = -800[tex]s = \frac{ \cancel{- 800}}{ \cancel{- 4}}[/tex]s = 200 mPlease help I will mark brainliest
Answer:
1.) B
2.) Polar Regions or high altitudes.
Explanation:
A car and a delivery truck both start from rest and accelerate at the same rate. However, the car accelerates for twice the amount of time as the truck. What is the final speed of the car compared to the truck?.
Answer: twice as much
Explanation:
you're welcome!
A hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2
a. How long does it take him to catch his opponent?
b. How far has he travelled in this time? (Assume the player with the puck remains in motion at a constant speed.)
After 3.0 s, If the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2 then it would take 3.13 seconds to catch his opponent.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem, a hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2,
Let us assume the time taken to catch up would be t seconds.
The distance traveled by the hockey player = 2.8×3 + 2.8×t
By using the second equation of the motion,
s = ut+0.5at² = 2.8×3 + 2.8×t
1.75t² - 2.8t -8.4 = 0
t = 3.13 seconds
The distance traveled by the hockey player to catch up = 2.8×(3+3.13)
=17.164 meters
Thus, it would take 3.13 seconds to catch his opponent.
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A population of a tree snail species has different patterns in their shells. These slight differences in appearance among the individual members of the species are called variations. How do you think these variations get passed on from one generation of tree snails to the next? Select the answer that best matches your thinking.
The variations get passed on from one generation of tree snails to the next from both parents to offspring and through the environment (Option C is correct).
What is genetic variation?The expression of genetic variation refers to differences in the nucleotide sequences between individuals of the same special which are passed across generations from parents to offspring and are selected by natural selection.
In conclusion, the variations get passed on from one generation of tree snails to the next from both parents to offspring and through the environment (Option C is correct).
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Name the three particles of the atom and their respective charges (positive, negative, neutral)
Answer:
Positive: Proton, Negative: Electron, Neutral: Neutron
Explanation:
How much heat energy is required to raise the temperature of 7 kg of Copper from 0°C to 10°C?
Answer:
H= Mass × specific heat capacity ×change in temperature
= 2×380×(10-0)
=2×380×10
=7600 Joules
A passenger elevator travels from the first floor to the 60th floor, a distance of 210m, in 35s. What is the elevator’s speed?
The speed of the elevator, given that it travels a distance of 210 m in 35 s is 6 m/s
Formula for speedThe formula for calculating the speed of an object is given as follow:
Speed = distance / time
How do I calculate the speed of the elevator?Considering the question given above, we can obtain the speed of the elevator as follow:
Distance = 210 mTime = 35 sSpeed =?Speed = distance / time
Speed = 210 / 35
Speed = 6 m/s
From the calculation made above, we can see that the speed of the elevator is 6 m/s
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During the experiment, the temperature of the spectrophotometer cavity is measured before inserting the cuvette. what is the main purpose of recording this temperature?
Dilution is needed to bring the unknown’s absorbance within the range of the standard curve.
If the dilution procedure is documented, it is possible to calculate the full-strength concentration after determining the diluted unknown quantity. Beer’s Law only applies to diluted solutions; hence it is preferable to dilute the unknown than to create new standards.
WHAT PURPOSE DOES A SPECTROPHOTOMETER SERVE?Spectrophotometers gauge transmittance (T) and absorbance (A) (T). Photons per second are used to quantify the light’s intensity. A blank sample, which does not absorb light when light passes through it, is represented as (I).
What is the spectrophotometer’s fundamental tenet?The principle of the spectrometer. The spectrophotometer is a device that calculates how much light a substance absorbs.
The spectrophotometer measures the light intensity of a sample by passing a light beam through it.
How does a spectrophotometer function and what is it?A spectrophotometer is a device that counts the number of photons (light’s energy) absorbed after they have passed through a sample solution.
The spectrophotometer can also be used to determine the concentrations (amounts) of known chemical substances.
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As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.
The power supplied by the gravitational force will increase because (Power=work/time).
What happens to a freely falling object's speed as it descends?A falling object gains momentum as it descends.
An increase in air resistance is caused by a speed increase.
At some point, the force of air resistance grows strong enough to counteract the pull of gravity.
Since there is no net force at this point, the object will stop accelerating.
Although the direction and magnitude of velocity fluctuate, the acceleration caused by gravity remains constant and downward.
The ball has zero velocity at the highest point in its trajectory, and it picks up speed as it descends back toward the earth.
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Help asap.
How do particles move when a transverse wave passes through a medium?
A. Up to a crest, then down through a trough, then back
B. Through a compression followed by a rarefaction
C. In wavelengths and amplitudes
OD. Along circular or elliptical paths
Answer:Transverse waves cause the medium to move perpendicular to the direction of the wave.
Explanation:
In a transverse wave, particles of the medium vibrate up and down perpendicular to the direction of the wave. In a longitudinal wave, particles of the medium vibrate back and forth parallel to the direction of the wave.
Clara jogs 600 m in 5 minutes
The biggest school in the world is in lucknow, india. it has more than 40,000 students and 2500 teachers! would it be easier to make new friends in a school with 40,000 kids than a school with fewer than 100 kids?
School population.
What is the population in school?The total number of full-time and part-time students who were enrolled in the institution during the reporting period.The biggest school in the world is the City Montessori School in Lucknow. With more over 45,000 students, it was included as the largest city school in the Guinness Book of World Records in 2013.The degree to which pupils engage with or participate in a lesson, course, etc.Education among the populace contributes to the well of their families and communities. Education about the population raises students' and teachers' awareness while also changing their attitudes.The biggest school in the world is in lucknow, india. it has more than 40,000 students and 2500 teachers! would it be easier to make new friends in a school with 40,000 kids than a school with fewer than 100 kids? School population.
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a group of students prepare for a robotic competition and build a robot that can launch large spheres of mass m in the horizontal direction with a variable speed and from a variable vertical position and a fixed horizontal position x
Gravity is the sole force acting on the body during free fall motion.
The student should launch the sphere at 2v0 because it will land in the 3 point zone at a distance of around 1.41D.
The variables mentioned are;
the sphere's travel distance when thrown from a height, H = D
The speed at which the ball travels to D = v0
The launcher's current available height is H/2.
The available speeds are v0 and 2v0.
Using the formula H = ut + (1/2)gt2, where u is the beginning velocity of the ball's vertical motion, the following is obtained:
H = (1/2)·g·t²
The time it takes for the ball to fall from H is given by t = ((2H/g)).
The length, D = v0 (2H/g),
we obtain when the height is H/2;
t = √(2·H/(2·g)) = √(H/g)
D1 = v0 (H/g) is the distance traveled.
D = (2) v0 (H/g) = ((2)) D1 follows.
D₁ = D/(√2) ≈ 0.71·D
D₁ ≈ 0.71·D
We have at pace 2v0;
D2 = 2v0 (H/g) = 2 v2 v0 (H/g) = 2 v0 (2H/g) = 2D1 1.41D
D₂ ≈ 1.41·D
The 2 point zone is equal to D/2 x D = 0.5 D x D. (This is where position D1 0.71D is placed)
The 3 Point Zone is located at position D2 1.41D and is defined as D x 3D/2 = D x 1.5D.
The student should launch the sphere at the speed, 2v0, such that the ball will land at D2 1.41D, which is in the 3 Point Zone, given that the ball lands at D2, where it is in the 3 Point Zone.
Complete Question -A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.
The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.
When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.
Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.
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if a resistor with a current of 20 ma through it converts 12 j of electrical energy into heat energy in 60 s, what is the voltage across the resistor?
The voltage across the resistor is 0.2V.
Heat energy is given as H = [tex]I^{2}[/tex]Rt.
What is a resistor ?Voltage across the resistor is
V= 0.2v
12 = [tex]0.02^{2}[/tex]×R×60
R= 500 ohms.
voltage across the resistor is
V=IR
V= 0.02^{2} ×500
V= 0.2V
A resistor is an electrical component with two terminals that implements electrical resistance as a circuit element. Resistors are employed in electronic circuits for a variety of purposes, including lowering current flow, adjusting signal levels, dividing voltages, biasing active devices, and terminating transmission lines.
An electrical component known as a resistor controls or restricts the passage of electrical current in an electronic circuit. Additionally, resistors can be used to supply a specified voltage to an active device like a transistor.
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She takes a random sample of mcdonald's restaurants from florida, georgia, alabama, and tennessee, and calculates a chi-square test statistic of 2.589 and a p-value = 0.7682.
Option A) Since the p-value is greater than 0.05, we have no evidence that the sandwiches are not purchased similarly across all the four different states as per the statistical data.
How do statistics work?A statistic, according to the Longman Dictionary of Contemporary English, is a person who has perished as a result of a specific type of accident or illness and is merely another statistic.
These things cannot be reduced to a statistic data.
In conclusion, there are a total of five reasons to study statistics. These are, to be able to conduct research efficiently, to read and evaluate journal articles, to further develop critical thinking and then also develop proper analytical skills, to act as an informed consumer, and to then recognize the times whenever you get the need to hire outside statistical help.
As per the question,
p = 0.7682
and thus, we have p > 0.05
And if p > 0.05 then we fail to reject the null hypothesis and results are not significant.
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An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet. As a result, what happens to the mass and weight of the object?.
Answer:
SEE below
Explanation:
MASS is a measure of the amount of matter in an object....it will remain the same ....
WEIGHT is a measure of gravitational pull on the object and is inversely dependent on the square of the distance between the two bodies...so weight will be LESS than on the surface of the planet
URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
The diagram shows two girls pushing on a box with equal and opposite forces. Which statement best describes the forces required to move the box to the right?
Answer: the forces must be unbalanced, with the force from the left greater than the force from the right.
Explanation:
a golfer hits a golf ball with an initial velocity of 250.00 ft/s at an angle of 25° with the horizontal. knowing that the fairway slopes downward at an average angle of 5°, determine the distance d between the golfer and point b where the ball first lands.
The distance d between the golfer and point b where the ball first lands is 4933.17 ft
Initial velocity = 250.0ft/s
Launch angle ([tex]\theta[/tex] )= 25°
slope angle([tex]\phi[/tex]) = 5°
Let d is the distance on the slope after which projectile lands
∴ horizontal distance covered by projectile
x = dcos[tex]\theta[/tex]
Vertical distance covered by projectile
y = dsin[tex]\theta[/tex]
now Considering horizontal motion
Initial horizontal velocity [tex]v_{x} = v cos25[/tex]
then position after time t
d cos5 = 250cos25×t
d = 227.44t ---------1.
when we consider vertical motion then
Initial vertical velocity [tex]v_{y} = v sin25[/tex]
[tex]v_{y} = v sin\theta t-\frac{1}{2}gt^{2}[/tex]
-d sin5 = 250 sin25.t - gt²/2
-d = 1212.25t - 56.221 t²
1212.25t - 56.221 t² + d = 0 ----2
put value of d in equation 2
1212.25t - 56.221t² + 227.44t =0
t(1212.25+227.44 - 56.221 t) =0
t(1234.69 - 56.221 t) = 0
t = 21.96 ,t≠0
substitute the value of t in equation 1
d = 227.44t
d = 227.44×21.96
d = 4933.17 ft
The distance d between the golfer and point b where the ball first lands is 4933.17 ft
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When a coin is tossed in the air, it travels upward, gradually slows down, momentarily reaches zero speed, then moves back
downward with increasing speed. Which statement best explains this change in the coin's motion?
a.The force of gravity causes the coin to change its velocity.
b.The coin's inertia decreases on the way up and increases on the way down.
c.The action-reaction force pair of gravity and the applied force cancel each other.
d.The coin remains in its state of upward motion until the force.
A. The force of gravity causes the coin to change its velocity.
What is the effect of force gravity on the upward motion of an object?
Force of gravity always act toward the center of the earth , so when an object is thrown up, the force of gravity will act in opposite direction of motion, that's toward the center of earth.
This will cause the object moving upwards to slow down due to the force of gravity acting on the opposite direction of the object's upward motion.
When a coin is tossed in the air, it travels upward, gradually slows down, momentarily reaches zero speed, then moves back downward with increasing speed due to effect of force of gravity.
Thus, the statement that best explains the change in the coin's motion is "The force of gravity causes the coin to change its velocity".
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Nellie whirls a tether ball in a horizontal circular path over her head. if the action force is nellie pulling on the string, the reaction force is?
The reaction force is string pulling on the Nellie when a tether ball in a horizontal circular path over her head .
A reaction force is a force that acts in the opposite direction to an action force. i.e. Newton's third law of motion describes action and reaction forces and the law states that for every action force, there is an equal and opposite reaction force.
There are Newton's three law of motion which can be describe as ,
The first law is can be stated as, an object will not change its motion unless a external force acts on it.
The second law is describe as, the force on an object is equal to its mass times its acceleration. i.e.
F = ma
In above equation F is force , m is mass and a is acceleration on an object.
The third law can be explained as, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Therefore , from the above discussion can be said as Nellie whirls a tether ball in a horizontal circulars path over her head. if the action force is nellie pulling on the string, the reaction force is string pulling on the Nellie.
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a parallel-plate capacitor has 2.2 cm × 2.2 cm electrodes with surface charge densities ±1.0×10−6c/m2. a proton traveling parallel to the electrodes at 1.4×106 m/s enters the center of the gap between them.
The distance has the proton been deflected sideways when it reaches the far edge of the capacitor is [tex]1.08 * 10^-3[/tex].
What is parallel-Plate Capacitor:
When two parallel plates are connected across a battery, the plates are charged and an electric field is established between them, and this setup is known as the parallel plate capacitor.
The parallel plate capacitor formula is given by:
C = k∈0 A / d.
Now,
The electric field is, E = sigma/epsilon_{o} = (1 * 10 ^ - 6)/(8.85 * 10 ^ - 12) = 1.129 * 10 ^ 5 * N / C
The force on the proton is (F) = q E = 1.6 * 10 ^ - 19 * 1.129 * 10 ^ 3 = 1.81 * 10 ^ - 14 * N
So, the acceleration of the proton is,
a = F/m = (1.81 * 10 ^ - 14)/(1.67 * 10 ^ - 27) = 1.084 * 10 ^ 13 * m / (s ^ 2)
Time taken to cross the plate is (t) = d/u = (2.4 * 10 ^ - 2)/(1.7 * 10 ^ 6) = 1.41 * 10 ^ - 8
Therefore, the required distance travelled distance is,
d = u t + 1/2 * a * t ^ 2
d = 0 + 1/2 * 1.084 * 10 ^ 13 * (1.41 * 10 ^ - 4) ^ 2
d = 1.08 * 10 ^ - 3 * m
Therefore, the distance is 1.08*10^-3 m
A parallel-plate capacitor has 2.4 cm × 2.4 cm electrodes with surface charge densities ±1.0×10^−6C/m2. A proton traveling parallel to the electrodes at 1.4×10^6 m/s enters the center of the gap between them.
By what distance has the proton been deflected sideways when it reaches the far edge of the capacitor? Assume the field is uniform inside the capacitor and zero outside the capacitor
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A plane is traveling 50m drops a package of explores of 134m the acceleration of gravity is 9.8 where does the package strike
Explanation:
Throughout this question, we will be taking the position at which the package is dropped as the origin.
We know that the package lands 100 m from the initial position. We have to investigate the position in the horizontal direction.
To do that, let's first calculate the time of flight of the package.
Here is what we know about the vertical motion taking the downward direction as the positive direction:
the vertical displacement is
s
=
100
m
.
the acceleration is
a
=
g
=
9.81
m
/
s
2
.
the initial velocity of the package is
u
=
0
m
/
s
.
By using an equation that connects the details that we have with the time of flight
t
, we get the time of flight as follows:
s
=
u
t
+
1
2
a
t
2
s
=
0
+
0.5
a
t
2
Make
t
the subject
0.5
a
t
2
=
s
t
2
=
s
0.5
a
t
=
√
s
0.5
a
=
√
100
m
0.5
(
9.81
m
/
s
2
)
≈
4.52
s
The horizontal displacement
x
equals the product of the horizontal velocity
v
x
=
40.0
m
/
s
and the time of flight
t
=
4.52
s
, i.e.
x
=
v
x
t
=
40.0
m
/
s
(
4.52
s
)
≈
181
m
The package will strike the ground at
(
181
m
;
−
100
m
)
.
Part b)
The horizontal component of the velocity is constant throughout the flight and is
v
x
=
40.0
m
/
s
.
For the downward motion, here is what we know:
the vertical displacement is
s
=
100
m
.
the acceleration is
a
=
g
=
9.81
m
/
s
2
.
the initial velocity of the package is
u
=
0
m
/
s
.
By applying an equation that combines the details that we have with the final instantaneous velocity
v
=
v
y
, we get the final instantaneous velocity as follows:
v
2
=
u
2
+
2
a
s
v
=
√
u
2
+
2
a
s
v
y
=
√
(
0
m
/
s
)
2
+
2
(
9.8
m
/
s
2
)
(
100
m
)
≈
44.3
m
/
s
The velocity vector at the instant the package just hits the ground is (40.0 m/s ; 44.3 m/s).
Part c)
At the instant that the plane hits the ground, the plane's position is (181 m ; 0 m): i.e. the plane is directly on top of the package and 100 meters above the ground. This is because horizontally, the plane and the package move with the same velocity.
Part d)
The vertical component of the velocity of the package increases at a steady rate. In fact, the rate or gradient is the acceleration
g
=
9.8
m
/
s
2
.
Which phrase best describes the amplitude of longitudinal waves?
OA. The maximum pressure at a compression
B. The vertical distance from a trough to the midpoint
O C. The distance from a compression to a rarefaction
D. The vertical distance from the midpoint to a crest
what comes to your mind when you think about the Energy, Forces, and Earth's Crust?
a brick is dropped (zero initial speed) from the roof of a building. the brick strikes the ground in 1.90 s. you may ignore air resistance, so the brick is in free fall.
If A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90s then the building is 17.69 meters tall.
What is velocity?Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.
A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.
We have given that
u = 0 m/s (initial velocity)
t = 1.90 s (time)
a = g = 9.80 m/s² (acceleration = falling = gravity)
We will use the second equation of motion to determine the height(S) of the building in meters:
⇒ S = [tex]ut + \frac{1}{2} at^2[/tex]
⇒ S = (0)(1.90) + [tex]\frac{1}{2}[/tex](9.80)(1.90)²
⇒ S = 4.9 × 3.61
= 17.69 meters
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Full question
A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air resistance, so the brick is in free fall. (a) How tall, in meters, is the building?
13. How are controlled experiments useful?
Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object? (1 p
O The slope of the line is positive, and the object will be stationary.
O The slope of the line is negative, and the object will be stationary.
O The slope of the line is equal to zero and the object will be stationary.
O The slope of the line is equal to zero and the object will be in motion.
D. The slope of the line is equal to zero and the object will be in motion.
What is constant velocity?Velocity of a body is said to be constant, if it covers equal distances in equal intervals of time, and also does not change the direction it is moving in
To have a constant velocity, an object must have a constant speed in a constant direction.
Slope of the position time graphslope = change in velocity / change in time
if the velocity is constant, then change in velocity = 0
slope = 0/change in time = 0
In constant velocity, the object will be in motion, but the velocity of the object will not change.
Thus, the slope of the line is equal to zero and the object will be in motion.
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========================================================
Hello! Lets begin!
1. Which answer best describes displacement?
A) Displacement is a vector quality showing total length of an area traveled by a particular object.2. Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?
D) The nine ball traveled a distance of 7 meters and was displaced by 1 meter.3. What is velocity?
B) Velocity is a vector quantity that tells the distance an object has traveled over a period of time.4. Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?
C) The slope of the line is equal to zero and the object will be stationary.5. Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.
B) The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity._______________________________________________________
Good luck my peeps! ;D