A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below: Depth (m) Cone resistance, qc (MN/m2 ) 2.0 3.12 3.5 4.25 5.0 5.14 6.5 9.23 8.0 12.2 The average unit weight of the sand is 16.5 kN/m3 . Determine the friction angle at each depth using Eq. (3.52)

Answer: Ohm Ω

Explanation:

The resistance can be defined as the hindrance offered to the flow of current. Lower the current the higher is the resistance. The SI unit of resistance is ohm Ω. When one ampere current flows from an object or wire the application of one volt of potential difference on it the resistance so produce is one ohm. Resistance can be achieved by the application of the certain gadgets in the circuit which can prevent the flow of excess current from devices and can prevent shock circuit.

Answer:

True

Explanation:

It's just because of the processing

Answer:

This can be achieved through the use of a built-in fiber-optic network of cables that deliver light and heat energy to the point of breakage.

Explanation:

Self-healing polymers are materials designed to aid the internal healing of materials like plastics, and metals. Shape-memory materials used in the making of plastic frames for glasses and sunglasses allow these materials to snap back into shape when they crack.

This is possible because heat is needed to help a deformed material regain its shape. Built-in fiber-optic network of cables serve the purpose of delivering heat to the deformed or cracked area, thus helping them to regain their shape.

Answer:

stink

Explanation:

Answer:

the pitch point im pritty sure what is is

The point of contact of two pitch circles of mating gears is called the pitch point.

A pitch point is where two pitch circles frequently come into touch. A common point of contact between two pitch circles of mating gears is called a pitch point. The pitch circle and is centered on the top of the teeth. Dedendum circle, also known as the root circle, is the circle traced through the base of the tooth.

The pressure angle, often known as the “tooth shape,” is the angle at which pressure from one gear's tooth is transferred to another gear's tooth. Pure rolling motion will occur at pitch point.

Therefore, it is pressure point.

Learn more about the pressure point, refer to:

https://brainly.com/question/2510654

#SPJ6

Answer:

True

Explanation:

Many chickens lay eggs of that size and eggs from chickens are the most commonly used

Answer:

 Chemical engineering

Uses chemical processes to find new ways to produce goods. Making antibiotics, pesticides, safe clothes, and foods.

·         Civil engineering

Builds structures to try and make them efficient. Makes a tornado-proof house, explosion-proof bunker, or easily navigable subway system.

·         Electrical engineering

Develops the electrical components for things. Game systems, keyboards, projectors, or hard drives.  

·         Mechanical engineering

Mechanical engineers work with things with mechanical processes and moving parts. Drills, wheels, elevators, or cranes.  

·        

·    

·      

Answer:

NICE

Explanation:

tesla lol how did you not know that?

Answer:

Tesla is a car that is able to drive automatically.

Answer:

The answer is below

Explanation:

The lengths of the rods are not given.

Let us assume the length of rod 1 = 1500 mm and the length of rod 2 = 800 mm

Solution:

The normal strain is defined as the change in member length δ divided by the initial member length L. The normal strain (ε) is:

ε = δ / L

δ = εL

For rod 1:

[tex]\delta_2=\epsilon_2 L_2\\\\\delta_2=0.0010\ mm/mm*1500\ mm=1.5\ mm[/tex]

The axial elongation of rod 2 is 1.5 mm. Since rigid bar ABC is attached to rod 2, the rigid bar move down by same amount.

The rigid bar moves down 1.8 mm but rods 1 will not be stretched by this amount. Because there is a gap between rod (1) and the rigid bar at B, the first deflection of 1 mm would not cause an elongation in rod 1. Therefore, the elongation in rods (1) is:

[tex]\delta_1=1.5\ mm-1\ mm=0.5\ mm[/tex]

The normal strain in rod 1 is:

[tex]\epsilon_1=\frac{\delta_1}{L_1} =\frac{0.5\ mm}{800\ mm} \\\\\epsilon_1=0.000625\ mm/mm[/tex]

Answer:

The condition does not hold for a compression test

Explanation:

For a compression test the engineering stress - strain curve is higher than the actual stress-strain curve and this is because the force needed in compression is higher than the force needed during Tension.  The higher the force in compression leads to increase in the area therefore for the same scale of stress the there is more stress on the Engineering curve making it higher than the actual curve.

Hence the condition of : on the same scale for stress, the tensile true stress-true strain curve is higher than the engineering stress-engineering strain curve. does not hold for compression test

Answer:

You can look it up

Explanation: if you don't know what it is look it up on .

Answer:

The change in length of the circular strut DC = 0.0028 in.

The vertical displacement of the rigid bar at point B = 0.00378 in.

Explanation:

We have the following parameters or information in the question given above:

=> The outer diameter = 15 in., the inner diameter = 14.4 in., the modulus elasticity of E = 29,000 ksi, and the Point load P = 5kips.

The diagram showing the rigid bar ACB is supported by an elastic cir-cular strut DC  is given in  the attached picture below.

According to Newton's law of motion, it can be seen that the force on CD, that is FCD is equal and opposite to ACD. Hence, FCD = ACD.

Where FCD = p × [4 + 5] ÷ [sin Ф × 4].

kindly note that from the diagram sin Ф = 3/5, cos Ф = 4/5 and tan Ф = 3/4. Also p =5.

Hence, FCD =[ 5 × 9] ÷ [3/5 × 4] = 18.75 kip. So FCD = ACD.

The next thing here is to determine the area and length of CD, say the area of CD is G, thus, G = π/4 × [ 15² - 14.4²] = 13.854 in².

The lenght of CD is = √[4² + 3²] = √[16 + 9] = 5ft. Thus, 5 × 12 = 60in.

Hence, the change in length of the circular strut DC = [18.75 × 60] ÷ 13.854 × 29000 = 0.0028 in.

The vertical deflection of CD = 0.0028 × 3/5 = 0.00168 in.

We have that; 4 /CV = 9BV. Hence, BV = 9/4× CV.

(CV = vertical deflection of CD).

The vertical displacement of the rigid bar at point B = 9/ 4 × 0.00168 in = 0.00378 in.  

Explanation:

(1) 174 inch

(2)1 foot 3.6 inches

(3) 39.649 centimetre

(4)175 decimeter

(5)26.25 feet

Answer:

kindly check the drawing of the  FBD of the beam with reactions at A & B. A is a pin, B is a roller in the attached picture.

Explanation:

Without further ado, let's dive straight into the solution to the question above. From the diagram of the FBD of the beam with reactions at A & B it can be shown that the reaction moment is anticlockwise while the moment is clockwise.

The system is at equilibrium and the it does not matter where you place the couple (pure) moment.

The distance from A to C can either be equal or not. If AY = 2.15 kN and M = 25.8. Then, the distance between A and B = 25.8/2.15 = 12m.

Answer:

С.) The force acting on the pole exceeded its yield strength.

Explanation:

Answer:

The correct answer is C. The force acting on the pole exceeded its yield strength.

Explanation:

I got it right on the Plato test.

Answer: c. Centre of pressure​

Explanation:

Pressure is applied on a surface when a force is exerted on a particular point on that surface by another object when the two come into contact with each other.

The point where the pressure is applied is known as the centre of the pressure with the force then spreading out from this point much like an epicentre in an earthquake.

Answer:

No because it is something to gain knowledge of peoples lives.

Answer: i was not suprised because, it is something all people need to know to gai  knowledege about it.

Answer:

Explanation:

How does an aircraft take off?

They are lift, weight, thrust and drag. Lift pushes the airplane up. The way air moves around the wings gives the airplane lift. The shape of the wings helps with lift, too.

HOPE THIS HELPS!