The distance d between the golfer and point b where the ball first lands is 4933.17 ft
Initial velocity = 250.0ft/s
Launch angle ([tex]\theta[/tex] )= 25°
slope angle([tex]\phi[/tex]) = 5°
Let d is the distance on the slope after which projectile lands
∴ horizontal distance covered by projectile
x = dcos[tex]\theta[/tex]
Vertical distance covered by projectile
y = dsin[tex]\theta[/tex]
now Considering horizontal motion
Initial horizontal velocity [tex]v_{x} = v cos25[/tex]
then position after time t
d cos5 = 250cos25×t
d = 227.44t ---------1.
when we consider vertical motion then
Initial vertical velocity [tex]v_{y} = v sin25[/tex]
[tex]v_{y} = v sin\theta t-\frac{1}{2}gt^{2}[/tex]
-d sin5 = 250 sin25.t - gt²/2
-d = 1212.25t - 56.221 t²
1212.25t - 56.221 t² + d = 0 ----2
put value of d in equation 2
1212.25t - 56.221t² + 227.44t =0
t(1212.25+227.44 - 56.221 t) =0
t(1234.69 - 56.221 t) = 0
t = 21.96 ,t≠0
substitute the value of t in equation 1
d = 227.44t
d = 227.44×21.96
d = 4933.17 ft
The distance d between the golfer and point b where the ball first lands is 4933.17 ft
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an ink-jet printer steers charged ink drops vertically. each drop of ink has a mass of 10-11 kg, and a charge due to 751896 extra electrons. it goes through two electrodes that gives a vertical acceleration of 104 m/s2. the deflecting electric field is mv/m.
The deflecting electric field is 0.83mv/m
Acc. to the newtons 2nd law - there is an acceleration when a force acts on an object.
F = ma (equation 1)
where
F is force
m is mass of object
a is acceleration
Electric field intensity- it is defined as force experienced by a unit positive charge placed at that point.
it is denoted by E = F/q
where
F is force
q is the charge
F = Eq (equation2)
from 1 and 2 equation we get
ma = Eq
E = ma /q
Charge on the drop of ink.is q.
(e is the charge on an electron.)
so,
q = 751896×e
q = 751896×1.6 ×⁻¹⁹
q = 12.03 ×10⁻¹⁴
m = 10⁻¹¹kg
a = 10⁴ m/s²
using above values
E = ma /q
E = 10⁻¹¹×10⁴/12.03 ×10⁻¹⁴
E = 0.83mv/m
The deflecting electric field is 0.83mv/m
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I already found Rx = -0.2 and Ry = -3. The magnitude is the square root of 0.2^2 + 3^2 = 3.01 I only need help understanding why when I plus in to solve for the direction why it won’t accept 86.2 when tan^-1(-3/0.2) doesn’t work. Please help explain to me the real answer or how I’m wrong. Thank you in advance
The values you found are incorrect.
The sum/resultant vector is
[tex]\hat R = \hat A + \hat B \\\\ \hat R = (5.00\,\mathrm m)\,\hat\imath + (6.00\,\mathrm m)\,(-\cos(30.0^\circ)\,\hat\imath - \sin(30.0^\circ)\,\hat\jmath) \\\\ \hat R = (2.00\,\mathrm m) \,\hat\imath - (3\sqrt3\,\mathrm m)\,\hat\jmath \\\\ \hat R \approx \boxed{(2.00\,\mathrm m)\,\hat\imath - (5.20\,\mathrm m)\,\hat\jmath}[/tex]
The magnitude of the resultant is
[tex]\|\hat R\| = \sqrt{(2.00\,\mathrm m)^2 + (-5.20\,\mathrm m)^2} \approx \boxed{5.57\,\mathrm m}[/tex]
The direction or angle the resultant makes with the positive horizontal axis is [tex]\theta[/tex] such that
[tex]\tan(\theta) \approx \dfrac{-5.20\,\mathrm m}{2.00\,\mathrm m} \approx -2.60[/tex]
Note the signs of the [tex]\hat\imath[/tex] and [tex]\hat\jmath[/tex] components of [tex]\hat R[/tex]. They tell us that [tex]\hat R[/tex] points into the fourth quadrant, and this means we can take the inverse tangent of both sides without any extra steps*. We then get
[tex]\theta \approx \tan^{-1}(-2.60) \approx \boxed{-67.0^\circ}[/tex]
* There would have been an extra step if [tex]\hat R[/tex] were pointing into either the second (negative [tex]\hat\imath[/tex], positive [tex]\hat\jmath[/tex]) or third quadrant (both negative [tex]\hat\imath[/tex] and [tex]\hat\jmath[/tex]). The inverse tangent function has a range of -90° to 90°, which means upon taking the inverse tangent of both sides of
[tex]\tan(\theta) = \dfrac{R_y}{R_x} \implies \theta = \tan^{-1}\left(\dfrac{R_y}{R_x}\right)[/tex]
we would only recover some angle [tex]\theta[/tex] between -90° and 90°. Yet our resultant must have some angle between -180° and -90°, or between +90° and +180° to belong to quadrant II or III. To get around this, we add an appropriately chosen multiple of 180° to the right side after taking the inverse tangent.
the escape speed from the earth is 1.12 ⇥104 m s 1, so that a gas molecule travelling away from the earth near the outer boundary of the earth’s atmosphere would, at this speed, be able to escape from the earth’s gravitational field and be lost to the atmosphere. at what temperature is the average speed of (a) oxygen molecules, and (b) helium atoms equal to 1.12 ⇥104 m s 1? (c) can you explain why our atmosphere contains oxygen but not helium?
Given Quantity
v esc =1.12×10 4 m/s: escape speed from the Earth =1.12×10 m/s: escape speed from the Earth
m = 2(1.66 \times 10^{-27}) = 3.32 \times 10^{-27}{kg}m=2(1.66×10 −27)=3.32×10 −27 kg: molecular mass of helium
We calculate the temperature at which helium atoms has an rms speed equal to the escape speed.
The rms speed is equal to the following
v rms = 3kT/m (1)
where kk is the Boltzmann constant, TT is the temperature, and mm is the molecular mass.
Manipulating Equation (1)(1) to be equal to the escape speed, we can calculate the temperature to be
v esc= 3kT/m esc
v esc= = 3kT/m esc
Tesc=mv2esc/3k
What is gravitational field?
A gravitational field is a framework used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. As a result, a gravitational field, which is measured in n. per kilogram, is employed to describe gravitational phenomena.
Therefore,
the escape speed from the earth is 1.12 ⇥104 m s 1, so that a gas molecule travelling away from the earth near the outer boundary of the earth’s atmosphere would, at this speed, be able to escape from the earth’s gravitational field and be lost to the atmosphere. at what temperature is the average speed of (a) oxygen molecules, and (b) helium atoms equal to 1.12 ⇥104 m s 1? (c) can you explain why our atmosphere contains oxygen but not helium?
Given Quantity
v esc =1.12×10 4 m/s: escape speed from the Earth =1.12×10 m/s: escape speed from the Earth
$ k= 1.38 \times 10^{-3}$: Boltzmann constant
m = 2(1.66 \times 10^{-27}) = 3.32 \times 10^{-27}{kg}m=2(1.66×10 −27)=3.32×10 −27 kg: molecular mass of helium
We calculate the temperature at which helium atoms has an rms speed equal to the escape speed.
The rms speed is equal to the following
v rms = 3kT/m (1)
where kk is the Boltzmann constant, TT is the temperature, and mm is the molecular mass.
Manipulating Equation (1)(1) to be equal to the escape speed, we can calculate the temperature to be
v esc= 3kT/m esc
v esc= = 3kT/m esc
Tesc=mv2esc/3k
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An enemy ship appears on your radar screen! You send out a radar ping, which is a signal
that travels through space at a constant velocity, bounces off an object, and then returns to
your ship. The radar ping moves at 300,000,000 m/s. You send out the signal and it takes
0.00026667 seconds for the signal to return; how far away is the enemy ship?
Answer:d=80,001 m
Explanation:df = di + Vave(t)
d = 0 + 300,000,000(0.00026667)
d = 80,001 m
help what does this mean
String instruments have different thicknesses of strings. This allows for the instrument to have different notes that give off different __________.
a. amplitude
b. pitch
c. wavelengths
d. rarefaction
Hurry help me please!!!! question: because protons and electrons in an atom carry opposite charges, they are attracted to each other and thus maintain the boundaries of the atom as a ____ system.
1. double open
2. double closed
3. singular open
4. singular closed
Because protons and electrons in an atom carry opposite charges, they are attracted to each other and thus maintain the boundaries of the atom as a singular closed system.
An atom consist of equal number of electrons and protons, due to which the attractive force between them binds the atom together and hence no exchange of matter takes place, therefore an atom posses closed system.
If we consider that energy is emitted, when electrons emit energy, then this energy is absorbed in the atom, thus preventing the electrons from hitting the nucleus. More specifically, as the electron wave travels around the nucleus, it emits energy, but this energy is recaptured when the wave doubles back on itself in 1/2 or full wavelengths to form a standing wave.
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What should you do every time you exercise?
A.
Warm up
B.
Drink plenty of water
C.
Stretch
D.
All of the above
Answer:
D. All of the above
Explanation:
Because it's the most logical answer.
A gust of wind blows an apple from a tree.
As the apple falls, the force of gravity on the apple is 9.16 N downward, and the force of the wind on the apple is 1.87 N to the right.
What is the direction of the net external force on the apple (measured from the downward vertical, so that the angle to the right of downward is positive)?
Answer in units of degrees
The direction of the apple is 78.5 degrees.
What is force?We know that force is that which brings about motion. Force acts on an object when it is stationary and makes it to move or makes a moving object to change direction.
The magnitude and the direction of the vector is regarded as very important when we are trying to solve for a particular vector.
Now we can see that the force of gravity acts vertically while the force that is exerted by the wind acts horizontally. This implies that we now have right angled triangle and the direction of the force could be obtained geometrically as;
tan^-1(9.16 N/ 1.87 N)
= 78.5 degrees
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How do gender roles differ from gender stereotypes?:
The attitudes and expectations around gender roles are often founded on gender stereotypes, or oversimplified ideas about the attitudes, attributes, and behavior patterns of males and females, rather than on any inherent or natural gender distinctions.
Gender stereotypes are broadly accepted ideas about traits that are considered suitable for males and females. There really are gender stereotypes regarding character, profession, and skills. These prejudices are reflected in gender roles, which are commonplace actions.
Hence Understanding these beliefs and their origins is essential to conquering them even if they are typically damaging to society.
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An iron ring is magnetized by placing it near the north pole of a bar magnet. How would the magnetic field lines of the iron ring appear once it is magnetized?.
The magnetic field lines of the magnetized iron ring are concentrated near the north and south poles of the ring.
When an iron ring is put near the north pole of a bar magnet, the bar magnet's magnetic field lines are drawn to it. As a result, the iron ring gets magnetic, and its field lines become concentrated towards the ring's north and south poles.
By matching the north pole of the iron ring with the north pole of the bar magnet, the iron ring is magnetized. This produces a strong magnetic field between the two poles, magnetizing the iron ring. The iron ring's magnetic field lines will be visible as a series of concentric circles around the bar magnet's north pole.
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You push horizontally on a 120 N box that is initially resting on a horizontal table. The coefficient of static friction between the box and the table is 0.75 and the coefficient of kinetic friction is 0.40. Find the friction force on the box if push is equal to 84 N.
The frictional force acting on the block is completely static in nature and is equal to 90 Newton's.
What is Friction?
Friction is a force that acts opposite to the direction of motion of body in order to oppose its motion.
Given in the question is a box of weight 120 N initially resting on a horizontal table. From the data given, we can write -
Weight of box [W] = 120 Newton
Coefficient of static friction (μ[s]) = 0.75
Coefficient of Kinetic friction (μ[k]) = 0.40
Horizontal push (F[h]) = 84 N
The frictional force is given by -
For Static friction - F[s] = μ[s] N
For Kinetic friction - F[k] = μ[k] N
Now, initially the box is at rest. When a horizontal force of 84 Newton is applied on it, the static friction will try to oppose the motion. For forward motion of the block -
F[h] - F[s] ≥ 0
F[h] - μ[s] N ≥ 0
84 - 0.75 x 120 ≥ 0 (Normal Reaction [N] = Weight)
84 - 90 ≥ 0
- 6 ≥ 0
which is false.
This means that the static frictional force is greater than horizontal push and opposes the motion. The force due to static friction will only exist since, the body was able to move, so kinetic friction is of no use here.
So, the frictional force on the block will be = F[s] = μ[s] N = 90 Newtons.
Therefore, the frictional force acting on the block is completely static in nature and is equal to 90 Newton's.
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Suppose the magnitude of an electric field that exerts a 4. 80 x 10-17 n force on an electron is 300 n/c. What magnitude of the force does this field exert on a proton?.
The magnitude of the force exerted by the electric field on the proton will be 4.80 × 10—¹⁷ N.
The force exerted by the electric field on the electron =
4.80 × 10—¹⁷ N.
The direction of the electric field that is exerting force on the electron = West
The magnitude of the electric field is,
[tex] = \frac{4.80 \times 10 ^{ - 17} }{1.6 \times 10 - 19} [/tex]
= 300 N/C
The magnitude of the electric field is 300 N/C.
The magnitude of the force exerted by the electric field on the proton will be,
The magnitude of the force exerted by the electric field on the electron = The magnitude of the force exerted by the electric field on the electron.
[tex] = 4.80 \times 10 ^{ - 17} [/tex]
Therefore, the magnitude of the force exerted by the electric field on the proton will be 4.80 × 10—¹⁷ N.
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1) A man walks 10km north and then 10km west.
a) What distance has he covered?
b) How would you measure his
displacement?
c) What angle would his displacement be at compared to
north?
The distance covered by man was 20 km, his total displacement would be 14.14 km and the angle of his displacement would be 45° compared to the north.
What is displacement?Displacement is defined as changes in an object's position referred to as displacement. It is a vector quantity that has both a direction and a magnitude.
As per the given condition,
Distance covered by man = 10 km + 10 km = 20 km
Total displacement will be the hypotenuse of two north and west sides.
⇒ Total displacement = √(10²+10²)
⇒ Total displacement = √(100+100)
⇒ Total displacement = √200
⇒ Total displacement = 10√2
⇒ Total displacement = 14.14 km
The angle of his displacement would be : tan⁻¹(10/10) = 45°
Hence, the distance covered by the man was 20 km, his total displacement would be 14.14 km and the angle of his displacement would be 45° compared to the north.
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calculate the deceleration of a bullet initially travelling at 360 m/s, if it is brought to rest after travelling 8.5 cm into a tree trunk which it has struck.
The de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².
What is Acceleration in Kinematics?Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -
a = Δv/ΔtGiven is a bullet initially travelling at 360 m/s struck into a tree trunk 8.5 cm inside and comes to rest. From this, we can write
initial velocity [u] = 360 m/s
final velocity [v] = 0 m/s
distance travelled [d] = 8.5 cm = 0.085 m
The time span after which bullet comes to rest will be -
Δt = d/u
Δt = 0.085/360 = 2.36 x 10 ⁻⁴ seconds
a = Δv/Δt
Δv = 0 - 360 = - 360 m/s
a = (v - u)/Δt
a = - 360/(2.36 x 10 ⁻⁴)
a = - 152.54 x 10⁴ m/s²
Therefore, the de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².
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Which measurement has three significant digits?
0.050 kg
0.205 s
500 m
1.030 g
If at some point along the straight line directly between two charges the strength of the electric field at that point is found to be zero what can we say for sure about those two charges?.
Answer: The charges must be like charges (both positive or both negative).
Explanation:
When is the best time to stretch?
A.
After a workout session
B.
Before you exercise
C.
In the middle of a workout
D.
You don't need to stretch
Answer: B
Explanation:
The gravitational field on the surface of the earth is stronger than that on the surface of the moon. If a rock is transported from the moon to the earth, which properties of the rock change?.
The property of the rock that will change if it is transported from the moon to the earth, is the weight.
The weight of an object is directly proportional to the action of gravity on the mass of that object. It can be confirmed with the weight formula:
W = m * g
Where:
W = weightm = massg = gravityBy contrast, the mass of an object indicates the amount of matter it contains, it is a constant magnitude.
What is weight?It is the physical magnitude that expresses the force exerted by gravity on the mass of a body, this is expressed in units of the international system in Newton.
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Suppose a 100-gram mass, when attached to a spring, causes the spring to stretch 8 cm.
What would you expect a 25-gram mass to do when attached to the same spring?
(1 point)
O Stretch the spring 4 cm.
O Stretch the spring 8 cm.
O Stretch the spring 32 cm.
O Stretch the spring 2 cm.
Answer:Apparently the further displacement should be of other 3 cm; but, let's consider the development of the spring on one vertical plain, and fixed on a wall by the upper end.
Now the spring doesn't look circular; but as a stick fixed on the wall. Before placing the first 100 grams weight, the stick is not horizontal; but its overhanging end is lower by the measured length of the spring at rest. The length line of the spring with its horizontal projection line forms an angle.
The first 100 grams load is decomposed in function of the new angle: one component in line with the stick, the other one perpendicularly respect to it. The same happens with 200 grams.
The flection momentum is given by the perpendicular component of the load with respect to the stick line in overload, and the measure of the stick itself. Such component is inversely proportional to the other component, and decreases in relation to higher load while the other component (that doesn't produce flexion) encreases.
I assume that I can't calculate the new displacement because is not given the height of the spring at rest, the length of the development of the spring. Accordingly, I cannot calculate all various angles of the stick in relation with gravity.
Explanation:
When a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.
What is Hook's law?Hooke's law states that the applied force [F] equals a constant k times the displacement or change in length [x].
Mathematically - F = - Kx
Given is a situation in which a stretch of 8 cm is caused by a 100g mass.
From this, we can write -
Mass [m] = 100 g = 0.1 Kg
Displacement [x] = 8 cm = 0.08 m
According to the question -
The spring constant [K] can be calculated using Hook's law as -
F = -Kx
mg = -Kx
K = - mg/x
K = - (0.1 x 9.8) / 0.08
K = - 12.25 N/m
|K| = 12.25 N/m
Now, when mass [M] = 25g = 0.025 Kg, using Hook's law -
|F| = |- kx| = kx
Mg = 12.25x
x = Mg/12.25
x = (0.025 x 9.8)/12.25
x = 0.02
x = 2 cm
Therefore, when a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.
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A car accelerates from rest at -3m/s^2
1. What is the velocity at the end of 5 seconds?
2. What is the displacement after 5 seconds?
Answer: 1. -15m/s
2. -37.5m
Explanation:
1. -3m*5=-15m/s
2. v=velocity. d=displacement. t=time. a=acceleration
d=vt+(1/2)at^2
d=0*5+(1/2)(-3)(5)^2 ==> car was at rest before accelerating
d=0+(1/2)(-3)(25)
d=(1/2)(-75)
d=-37.5 meters
During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 6.6 s, how
high above the point where it hits the bat
does it rise? Assume when it hits the ground
it hits at exactly the level of the bat. The
acceleration of gravity is 9.8 m/s².
Answer in units of m.
The ball rises 53.361 m above the point where the bat hit the ball.
When a batter hits a ball high in a baseball game, the ball remains in the air for 6.6 seconds.
The acceleration of gravity is 9.8 m/s².
The vertex value of time is half of 6.6 seconds or 3.3 seconds.
Therefore, the final velocity at the maximum height is v = 0 m/s
Now, using the equation of motion:
v - u = gt
v = u + gt
u × sin(θ) = - gt
u × sin(θ) = 9.8 × 3.3
u × sin(θ) = 32.34 m/s
Now, by using the equation of motion:
v² - u² = 2gh
h = ( v² - u²) / 2g
h = ( 0 - (32.34)² ) / 2(9.8)
h = (1045.8756) / 19.6
h = 53.361 m
The ball rises 53.361 meter high.
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What is the
law of universal gravitation?
Answer:
Newton's Universal Law of Gravitation is a law created by Newton (obviously). It is the equation [tex]F=G\frac{m1m2}{r^{2} }[/tex] where F is the force of gravity, G is the gravitational constant (varies between places), m1 and m2 are the masses of the 2 objects and r is the distance between the centers of the 2 masses.
Newton's law of gravitation, states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.
Hope that provides a basic overview
what is the mass of an object that requires 15.0N to accelrate it at rate of 3 m/s2
i need the givens and equation
The mass of an object that requires 15.0N to accelerate it at rate of 3 m/s² is 1.17 kg.
What is the mass of an object that requires 15.0N to accelerate it at rate of 3 m/s²?The mass of an object is the quantity of matter present in an object.
The mass of an object is related to its acceleration and the applied force by the given formula below:
force = mass * acceleration
mass = force/acceleration
From the data provided:
force applied = 15.0 N
acceleration = 3 m/s²
The force applied overcomes the weight of the body.
Total force applied = weight + net force
Total force = mg + ma
Total force = m(g + a)
m = force/(g + a)
mass = 15(9.8 + 3)
m = 1.17 kg
Therefore, the mass of the object is 1.17 kg.
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a sled is initially moving on a straight track at 3.5 m/s. what is its velocity two seconds later, if the sled's recorded acceleration is 2.0 (m/s)/s?
A sled is initially moving on a straight track at 3.5 m/s. The final velocity of the sled will be 3.75m/s. When the acceleration is 2.0 m/s².
What is acceleration?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on an item determines the direction of its acceleration.
Given parameters:
Initial velocity = 3.5m/s
Final velocity = ?
Time taken = 2s
acceleration = 2m/s²
[tex]a = v_f - v_i/t[/tex]
2 = x - 3.5/2
x = 3.75 m/s
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consider a long cylindrical charge distribution of radius r with a uniform charge density rho. find the electric field at distance r from the axis where r < r . assume the charge density is positive (rho > 0).
The electric field at distance r from the axis where r < r . assume the charge density is positive E = p× r / 2 ×e₀
Given:
- Volume of cylinder V = pi×r² ×L
- area A = 2× pi ×r ×L
- permittivity of space : e₀
Finding :
Electric field E at distance r from the axis, where r < R.
Solution:
Step 1: Application of Gauss Law
Form a Gaussian surface within the cylinder with r < R. Th cylinder has two surfaces i.e curved surfaces and end caps. thanks to long charge distribution the flux through is zero, since the surface dA of end cap and E are at 90 degree angle to at least one another; hence, E . dA = E× dA ×cos(90) = 0.
For the curved surface we have:
(surface integral) E.dA = Q_enclosed / e₀
Step 2: The charge enclosed (Q_enclosed) is function of r and proportional density:
Q_enclosed = p ×V
Q_enclosed = p ×pi ×r² ×L
Step 3: the world of the curved surface:
dA = 2× pi ×r ×L
Step 4: Computing E:
E×(2 ×pi ×r ×L) = p× pi ×r^2× L / e₀
E = p×r / 2×e₀
Charge density :The charge density is that the measure of electric charge per unit area of a surface, or per unit volume of a body or field. The charge density tells us what proportion charge is stored in a particular field. Charge density are often determined in terms of volume, area, or length.
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Give an example of what it means to say mass and weight are proportional to each other?.
The example of mass and weight being proportional is Force = mass * acceleration.
The proportionality can be direct or inverse proportionality.
Direct proportionality can be defined as the increase in the second quantity if there is an increase in the first quantity when both quantities are related.
Inverse proportionality can be defined as a decrease in the second quantity when the first quantity is increased when both quantities are related.
Mass and weight are proportional to each other.
For that we can consider the example given below:
weight is the force exerted by the earth's gravity on the particle.
we know that
force = Mass * acceleration
as weight = force
weight = mass * acceleration
so if the acceleration is constant the increasing weight mass also increases.
so at constant acceleration weight and mass are directly proportional.
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_______ used the extensive records of planetary positions measured by ______ to discover that the orbits of the planets are ________.
Kepler used the extensive records of planetary positions measured by Tycho to discover that the orbits of the planets are elliptical.
What are planets ?The planets would be listed from smallest to largest in order of size: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter. The gas giants are Jupiter and Saturn, whereas the more distant Uranus and Neptune are known as the ice giants.
The International Astronomical Union (IAU) downgraded Pluto to a dwarf planet since it failed to satisfy all three criteria for a full-sized planet. Pluto essentially meets all the criteria, with the exception of the one that it "has not cleared its nearby vicinity of other objects."
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a car starting from rest
moves with a uniform acceleration of 6ms^-2. The distance its covers in the fourth seconds of its motion is
The correct answer is 21 m.
The term "uniformly accelerated motion" refers to a body or object moving at a consistent rate of acceleration. The absence of velocity does not imply constant acceleration. Therefore, if a body is in motion such that the amount of change in its velocity in equally spaced time intervals will be constant, then that is what is meant by uniform acceleration or uniform acceleration definition.
Given initial velocity = 0 m/s
acceleration = 6 m/s^2
The body's movement in nth seconds in terms of distance,
S_n = u + a/2 (2n-1)
S_4 = 0 + 6/2 ( 2 × 4 - 1 )
S_4 = 3 ( 8 -1 )
S_4 = 3 × 7
S_4 = 21 m
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An electric car is being driven through a town at 22 m/s. The kinetic energy of the car is 222640 J. Calculate the mass of the car.
The mass of the electric car moving at the given speed and kinetic energy is determined as 920 kg.
What is kinetic energy?The kinetic energy of an object is the energy possessed by the object due to the motion of the object. The kinetic energy of an objects is determined from the product of object's mass and its velocity.
The mass of the electric car is calculate by applying kinetic energy formula as follows;
K.E = 0.5 mv²
where;
m is mass of the objectv is the velocity of the objectK.E is the kinetic energySubstitute the given parameters and solve for the mass of the electric car.
m = (K.E)/(0.5v²)
m = (222640) / (0.5 x 22²)
m = 920 kg
Thus, the mass of the electric car moving at the given speed and kinetic energy is determined as 920 kg.
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The experimental setup shown in the picture has a fixed ramp and an adjustable ramp. Students roll a ball down the fixed ramp and measure how far up the adjustable ramp the ball travels. During
the experiment, they change the slope of the adjustable ramp and record their data in the table
1
8) The students concluded that the lower the slope of the adjustable ramp, the greater the distance the ball continued to roll. What other conclusion can also be drawn from the findings?
A) The ball stops because there is some force acting on it
B) The only force acting on the ball during its journey is gravity
The ball stops eventually because there is no force acting on it
D) The slope of the ramp has no role to play in the stopping of the ball
A. Another conclusion that can be drawn from the student experiment is the ball stops because there is some force acting on it.
What are the forces acting on an object moving on inclined plane?There are several forces that will act on an object moving on an inclined plane. These forces include the following;
gravitational forcefrictional forceapplied forceWhen the object is moving up, gravitational force will tend to pull the object downwards and the frictional force will tend to oppose this downward motion of the object.
When the object is rolled down the plane, gravitational force tends to aid the motion of the object while frictional force tends to slow the object down.
Eventually, the object stops because the frictional force opposing the object motion is greater than the gravitational force pushing the object downwards.
Thus, another conclusion that can be drawn from the student experiment is the ball stops because there is some force acting on it.
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