A navigation buoy floating on the sea oscillates up and down as a wave passes.
In exactly two minutes, six complete wavelengths pass the buoy.
What is the frequency of the waves?
A 0.050 Hz
B 0.33 Hz
C 3.0 Hz
D 20 Hz
STUDENTS

Answers

Answer 1

Frequency of the waves is 0.05 Hz

Number of complete wavelength, λ = 6

therefore distance covered = 6 Wavelength

Time taken to complete 6 wavelengths, t = 2 min

Since 1 min = 60 sec

2 min = 2 * 60 = 120 sec

Frequency can be defined as the number of wave cycles completed per second by a wave.

It is the ratio of velocity to the wavelength.It is denoted by FThe unit used for the frequency is hertz, Hz.Mathematically, F = [tex]\frac{Velocity}{Wavelength}[/tex]

As we know, Velocity = [tex]\frac{Distance}{Time}[/tex] = [tex]\frac{6 Wavelength}{120}[/tex]

F = [tex]\frac{Velocity}{Wavelength}[/tex]

F = [tex]\frac{6 wavelength}{120 wavelength}[/tex]

F = [tex]\frac{6}{120}[/tex]

F = 0.05 Hz

Therefore frequency of the navigation buoy floating on the sea oscillates as a wave is 0.05 Hz.

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Related Questions

A 100.0 kg person will need to climb a 10.0 m stairway how many times to "work off" each excess 20 Cal (kcal) consumed?

Answers

The person must climb the stairs about eight times.

What is the energy required?

We know that energy is the ability to do work. Work and energy are two quantities that are dimensionally similar to each other. In this case, we are trying to obtain the number of times that A 100.0 kg person will need to climb a 10.0 m stairway how many times to "work off" each excess 20 Cal (kcal) consumed.

Now;

Work done by the person = mgh =  100.0 kg  * 10 m/s^2 * 10 m = 10000 J

To convert from joules to kcal, we know that;

1 kcal = 4184 J

x =  10000 J

x = 1 kcal *  10000 J/4184 J

x = 2.39 kcal

In order to burn off the excess calories, the person must climb the stairs;

20 kcal/2.39 kcal = 8

The person must climb the stairs about eight times.

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An objects
A) weight
B) density
C) mass
D) Any of these.
determines the extent of resistance to a change of motion.
OA
OB
OC
OD

Answers

The extent of resistance to a change of motion is determined by an objects mass. The mass of the object is measured in kilograms.

Answer:

B

Explanation:

Which of the following scenarios shows an object with a negative velocity and a negative acceleration?

Question 6 options:

A pig moves toward the reference point speeding up.


A pig moves away from the reference point slowing down.


A pig moves toward the reference point slowing down.


A pig moves away from the reference point speeding up.

Answers

C.  The following scenarios that shows an object with a negative velocity and a negative acceleration is "a pig moves toward the reference point slowing down."

What is negative velocity?

A negative velocity occurs when an object moves in the negative direction.

Example of negative velocity;

If a car is moving away from you (reference point) then the velocity is positive. If a car is coming towards you (reference point) then the same vector reverses direction and hence the velocity is negative.

What is negative acceleration?

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion. Thus, the acceleration of the object will be negative.

Thus, the following scenarios that shows an object with a negative velocity and a negative acceleration is "a pig moves toward the reference point slowing down."

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which of the statements is not correct ​

Answers

Answer:

The electrostatic interactive force between electrical charges is exactly the same as the gravitational interaction between them

Explanation:

The magnitude of charge is independent of the weight and displacement of the charge but only sign of the charge is the dependent factor.

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An object originally moving at a speed of 20.0
meters per second accelerates uniformly for 5.0 seconds to a final speed of 50.0 meters per second. What is the acceleration of the object?

Answers

Answer:

6.0 m/s^2           There are 2 places of accuracy. (5.0 has only two places)

Explanation:

Formula

This uses the formula

a = (vf - vi)/t where

a is the accelerationvf is the final speedvi is the starting speed.t is the time taken

Solution

Substitute the givens into the formula

a = (50m/s - 20 m/s)/5

a = 30/5

a = 6 m/s^2

A Bicycle is turned upside down the front wheel is running,where will the valve stop

Answers

The valve will stop when the wheel stops.

How can the wheel stops?

It can be done either applying the force manually or let the natural friction force work.The force can be applied manually by pulling up the brakes.

The other way by which it stop is :

When we ride on a bicycle, we rotate the pedals, which in turn rotate the chainrings, which rotate the rear sprocket, hence, making the rear wheel to move forward. This rotation brings in angular speed and angular acceleration.The friction is applied from the ground to stop it from slipping. Here, the forces working are the rotational and the frictional along with angular acceleration and speed. When the bicycle is upside down, the frictional force from the ground becomes zero. The chain rings also don’t control the front wheel. The angular acceleration will be opposed by some force. Here, the frictional force that will act will be from the air and the inertia is applied to the rotational motion of the wheel which is now in the air and not on the ground. Once the friction from air is greater than angular motion, the wheel stop automatically.

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According to Kepler's laws of planetary motion
the ratio of the mean radius of the orbit of a
planet cubed to the period of revolution of
the planet squared is constant for all planets
orbiting the Sun. Sketch a graph representing
this relationship.

Answers

The ratio of the cubes of any two planets' average distances from the sun (r) to their squares representing their periods (T) is equal to one.

What is the Kepler's law?

First Law: The sun is at the center of elliptical planetary orbits.

Second Law: Equal areas are covered in equal amounts of time by the radius vector from the sun to a planet.

Third Law: For every planet, the ratio of the cube of the ellipse semimajor axis to the square of the period of revolution is the same.

The third law of Kepler, also referred to as the Law of Harmonies, states that the ratio of any two planets' squared periods to their squared average distances from the sun is equal to one. The third law compares a planet's orbital radius and period to those of other planets.

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What’s more dense, a 200g bar of Aluminum or a 2g cube of Aluminum?

Answers

Answer:

2g cube of Aluminum

Explanation:

A rectangular pool is 3 feet wide. It is 4 times as long as it is wide. Label the diagram with the dimensions of the pool. Then find the perimeter of the pool.

Answers

The perimeter of the pool is measured as 30 feet.

What is the perimeter?

We know that a rectangle is a four sided polygon recall that a polygon is any figure that has n sides. The number of sides in a  polygon could move from three to infinity. The polygons come in different shapes and are solids with definite values of surface areas and volumes.

The rectangle is four sided which each of the angles of the rectangle adding up to give 360 degrees. It must be noted that the opposite sides of the rectangle are equal to each other.

We have the following information;

Length of the pool = 4(3 feet) = 12 feet

Width of the pool = 3 feet

Since perimeter = 2 ( length + width)

Perimeter = 2( 12 + 3)

Perimeter = 30 feet

Hence, the perimeter of the pool is measured as 30 feet.

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Convert 277.01 pm to cm (use scientific notation).

Answers

277.01 picometers is equivalent to 2.7701 × 10-⁸ centimetres in scientific notation. Details about how to convert picometers to centimetres can be found below.

How to convert picometers to centimetres?

Picometers is the SI unit of length that is equal to 10−¹² meters.

On the other hand, centimetres is another S.I unit of length that is equal to 10-² metres.

The conversion factor of picometers to centimetres is as follows:

1 picometre = 1 × 10-¹⁰ centimetres

277.01 picometers is equivalent to 2.7701 × 10-⁸ centimetres

Therefore, 277.01 picometers is equivalent to 2.7701 × 10-⁸ centimetres in scientific notation.

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What ia the speed of A car travels 100meters in 50 seconds what's it's speed

Answers

100/50 M/sec=2 M/sec

A light-year (ly) is the distance light travels in one year (at speed of 2.998 × 10^8 m/s ). An astronomical unit (AU) is the average distance from the Sun to Earth, 1.50 × 10^8 km. 1 year = 3.156 × 10^7 s.

A. How many meters are there in 1.50 ly ?

B. How many AU are there in 1.50 ly light-year?

Answers

There are few points given to us in this question.

The speed of lightTime (in seconds) in a yearDistance between Earth and SunSpeed of light in m/s

A) There are 1.41× 10^16 m in 1.5 light years

B) There are 9.4 × 10^4 AU in 1.5 light years

What is a light year?

Many might confuse it with time because of the presence of term “year” this term is actually used for space objects to measure distance. Light Year is the distance travelled by light in one Earth year.

It’s a term named by German scientist Friedrich Bessel who first used it in 1838.

One light year is about 6 trillion miles or 9.46 trillion kilometers.

To solve part A, we will first multiply V(light) with time (in seconds) in a year and multiply the product with 1.5 light year per light year.

Now let us understand what is Astronomical Unit AU?

AU is also used to measure distance but within our solar system. It is usually the average distance between Sun and Earth. It is about 93 million miles or 150 million kilometers.

To solve part B, we first convert the light year to AU and we do this by using the final value from part A and then convert it in significant figure to obtain a proper value for the answer.

The calculations are shown in the figures below.

Hence,

A) There are 1.41× 10^16 m in 1.5 light years

B) There are 9.4 × 10^4 AU in 1.5 light years

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A runner can maintain a constant acceleration of 1.1m/s^2 for 8.5 seconds. What distance could the runner cover in that time of starting from rest

Answers

The distance covered by the runner after starting from rest is 39.74 m/s².

The real route length of a moving particle or object is referred to as distance. The shortest distance between a body's initial and final positions is referred to as displacement. Speed is the amount of distance a particle travels in one unit of time.

The constant acceleration of a runner is 1.1 m/s².

The runner maintains the constant acceleration for 8.5 seconds.

So,

a = 1.1 m/s²

t = 8.4 seconds

Since the runner starts from the rest.

Therefore, the initial velocity u = 0 m/s

Using the equation of motion,

s = ut + (1/2) × a × t²

s = 0 × 8.5 + ( 1/2 ) × 1.1 × 8.5 × 8.5

s = ( 1/2 ) × 79.475

s = 39.737 m/s²

s = 39.74 m/s²

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The law of conservation of mass states that ___________

A.) matter cannot be created or destroyed

B.)mass can be created if a chemical reaction occurs

C.) atoms conserve mass when they fuse to form molecules

Answers

The law of conservation of mass states that matter cannot be created or destroyed.

The law of conservation of mass states that the mass of the reactant must be equal to the mass of the product.

In 18th century law of conservation of mass was given by Levoisier.

It states that mass is neither created nor destroyed.

Example -

when wood burns the mass of the suit ,ashes and gases equal to the original mass of the charcoal.

after heating the ice it will convert into water. Mass of the ice does not change after undergoes a physical. Change.

The law of conservation of mass states that matter cannot be created or destroyed.

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A skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 2.6 m/s2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0 .
What is her x position at t=0.80s ?
What is her y position at t=0.80s ?

What is her x velocity component at t=0.80s ?
What is her y velocity component at t=0.80s ?

Answers

a. Her x position at t = 0.80 s is 0.0832 m

b. Her y position at t = 0.80 s is -28.8 m

c. Her x velocity component at t = 0.80s is 2.08 m/s

d. her y velocity component at t = 0.80s is -3.6 m/s

Since the skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 2.6 m/s² toward the east.

Her velocity v = (0i - 3.6j) m/s and her acceleration a = (2.6i + 0j) m/s²a. What is her x position at t = 0.80s ?

Now since she starts from the origin, to find her x position after 0.80 s, using the equation of motion for the x - components of motion,

x = ut + 1/2at² where

u = x - component of velocity = 0 m/s, a = x - component of acceleration = 2.6 m/s² and t = time = 0.8 s

So, substituting the values of the variables into the equation, we have

x = ut + 1/2at²

x = 0 m/s × 0.8 s + 1/2 × 2.6 m/s² × (0.8 s)²

x = 0 m + 1.3 m/s² × 0.64 s²

x = 0 m + 0.832 m

x = 0.832 m

So, her x position at t = 0.80 s is 0.0832 m

b. What is her y position at t = 0.80s ?

Using the equation of motion for her y - components of motion, her y position is y = ut + 1/2at² where

u = y - component of velocity = -3.6 m/s, a = y - component of acceleration = 0 m/s² and t = time = 0.8 s

So, substituting the values of the variables into the equation, we have

y = ut + 1/2at²

y = -3.6 m/s × 0.8 s + 1/2 × 0 m/s² × (0.8 s)²

y = -3.6 m × 0.8 s + 0

y = -28.8 m

So, her y position at t = 0.80 s is -28.8 m

c. What is her x velocity component at t = 0.80s ?

Using the equation of motion for her x - component of motion, her x velocity compoent after t = 0.8 s is

v = u + at where

u = initial x - component of velocity = 0 m/s, a = x - component of acceleration =  2.6 m/s² and t = time = 0.8 s

So, we have

v = u + at

v = 0 m/s + 2.6 m/s² × 0.8 s

v = 0 m/s + 2.08 m/s

v = 2.08 m/s

So, her x velocity component at t = 0.80s is 2.08 m/s

d. What is her y velocity component at t = 0.80s ?

Using the equation of motion for her y - component of motion, her xyvelocity compoent after t = 0.8 s is

v = u + at where

u = initial y - component of velocity = -3.6 m/s, a = y - component of acceleration =  0 m/s² and t = time = 0.8 s

So, we have

v = u + at

v = -3.6 m/s + 0 m/s² × 0.8 s

v = -3.6 m/s + 0 m/s

v = -3.6 m/s

So, her y velocity component at t = 0.80s is -3.6 m/s

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A construction worker on the 24th floor of a building project accidentally drops a wrench and yells “Look out below” Could a person of ground level hear his warning in time to get out of the way? The speed of sound is about 1100 feet per second

Answers

Answer:

Assuming the height at which the wrench was dropped is 336 feet,

the person will hear the sound in 0.3 sec and the wrench will hit the ground only after 4.58 seconds so there is enough time to get out of the way

Explanation:

Without knowing the exact height at which the 24th floor is located, it would be difficult to determine whether the wrench will hit the ground before the sound hits the ground

Realistically, we can assume each floor of the building is 14' high

So the height at which the 24th floor is located is 24 x 14 = 336 feet

To travel 336 feet at 1100 feet per second, sound will take 336/1100 seconds which is 0.30 second

Let's compute the time taken for the wrench to hit the ground

The acceleration due to gravity is usually taken to be 16 feet/second²

The displacement which is the distance traveled by an object with an initial velocity of u in time t is given by the equation:
s = ut + (1/2)t²

Here the initial velocity is 0

So the equation is
s = 1/2 x 32 x t² = 16t²

To cover 336 feet we substitute 336 for s and get

336 = 16t²

t² = 336/16

t = ±√(336/16) ≈ 4.58 seconds (we only take the positive root)

So the person will hear the sound in 0.3 sec and the wrench will hit the ground only after 4.58 seconds so there is enough time to get out of the way

In general, we can state that if the height from which the wrench was dropped is h then time t taken for wrench too hit the ground is

t = √(h/16) seconds

If this is greater than the time taken for sound to travel the same distance then the person can get out of the way

The Blue Origin rocket ship starts vertically upward from the launch pad a constant
acceleration of 6.3 m/sec2. How high does the rocket ship raise above the launch
pad after 94 seconds of flight?
Assume that the rocket ship moves vertically up all the time. Enter your answer in
meters (m).

Answers

The rocket ship rises to a height of 27.83 km above the launch pad after 94 seconds of flight.

We know that,

s = u t + 1 / 2 a t²

where,

s = Displacement

u = Initial velocity

a = Acceleration

t = Time

Given that,

u = 0

a = 6.3 m / s²

t = 94 s

s = 0 + 1 / 2 ( 6.3 * 94² )

s = 27833.4 m

s = 27.83 km

Displacement the distance between the initial point and final point. It is denoted using s.  

Therefore, the rocket ship rises to a height of 27.83 km above the launch pad after 94 seconds of flight.

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How precise is the measurement of length? Of volume?

Answers

Answer:

The precision corresponds to the least count of the measurements, which is 0.1 cm 0.1 c m for the length of the box. In a similar manner, the precision of the volume is 0.01×103 cm3=10 cm3 0.01 × 10 3 c m 3 = 10 c m 3 .

With what speed must an object be projected vertically upward for it to reach a maximum height of 12.0 m above its starting point?

Answers

The speed that must be attained by the object when its projected upward vertically is 15.34 m/s.

What is speed?

Speed is the ratio of the distance covered by a body to the total time.

To calculate the speed the object must attain, we use the formula below.

Formula:

v² = u²+2gh............. Equation 1

Where:

v = Final speedu = Initial speedg = Acceleration due to gravityh = Height

From the question,

Given:

u = 0 m/sg = 9.8 m/s²h = 12 m

Substitute these values into equation 1

v² = 0²+2×12×9.8v² = 235.2v = √235.2v = 15.34 m/s

Hence, the speed that must be attained by the object when its projected upward vertically is 15.34 m/s.

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A student drops a ball from a window 5.0 m above the sidewalk. How fast is it moving when it hits the sidewalk?

Answers

The ball's velocity is 9.9 m/s fast when it hits the sidewalk.

What is velocity?

Velocity is the rate of change of displacement.

To calculate how fast the ball was moving when it hits the sidewalk, we use the formula below.

Fromula:

V² = U²+2gS......... Equation 1

Where:

V = Final velocityU = Initial velocityg = Acceleration due to gravityS = Distance

From the question,

Given:

U = 0 m/sg = 9.8 m/s²S = 5 m

Substitute these values into equation 1

V² = 0²+2×5×9.8V² = 98V = √98V = 9.9 m/s

Hence, the ball's velocity is 9.9 m/s fast when it hits the sidewalk.

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A leopard of mass 65 kg climbs 7 m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g = 10 N/kg

Answers

The potential energy gained is 4550 J.

The potential energy that a huge item has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects descend toward one another, potential energy associated with the gravitational field is released.

The potential difference is given as:

U = mgh

Where U is the gravitational energy, m is the mass, g is the acceleration due to gravity, and h is the height.

Now, we have

Leopard's mass, m = 65kg

The height of the tree, h = 7 m

Acceleration due to gravity, g = 10N/kg

Therefore,

U = mgh

U = 65 × 7 × 10

U = 65 × 70

U = 4550 J

Thus, the leopard will need 4550 J of gravitational potential energy to climb 7 meters.

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The table shows data for two groups of plants, one grown with fertilizer and the other without fertilizer. Effect of Fertilizer on Plant Growth No fertilizer Fertilizer Height of plants (cm) 24.1 25.9 25.4 24.1 35.6 30.5 32.1 40.6 30.5 33.8 What effect does the value 35.6 have on the measures of central tendency for the data in the left column? . The mean will be lower than the median and mode B. The mean will be higher than the mode but lower than the median. . The mean will be higher than the median and mode. . The mean will be higher than the median but lower than the mode

Answers

The value 35.6 have on the measures of central tendency for the data in the left column, as mean will be higher than the median and mode. The correct option is C.

What is mean?

The mean is the average of a set of values in mathematics and statistics. There are several ways to compute the mean, including the simple arithmetic mean, the geometric mean, and the harmonic mean.

To find the mean, add all of the numbers together. The total sum is then divided by the number of scores used. The mean or average of the number set in this example is 6.7.

The value 35.6 has a positive effect on the measures of central tendency for the data in the left column, as the mean is greater than the median and mode.

Thus, the correct option is C.

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A person swims at a constant speed of 1 meter per second. What type of function can be used to model the distance the swimmer travels?
Hint: sketch a graph of what this would like and see which parent function it looks like

Answers

If a person swims at a constant speed of 1 meter per second, than the linear function will be used to model the distance travelled by the swimmer.

The parent function is "the principal's of ice"

A linear function is a function that forms a straight line on a graph. It is generally a polynomial function whose degree is at most 1 or 0. Although linear functions are also represented in terms of calculus and linear algebra.

Here Y-axis represents Distance and X-axis represents Time.

Also speed is the rate of change of distance with respect to time i.e. distance is changing linearly with time

Mathematically it is  [tex]Speed = \frac{distance}{time}[/tex].

Change in Distance = Change in time and hence speed is constant.

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pls helppp

A model rocket has a mass of 0.2 kg, with a motor that can provide a force of 100 N. A second model rocket is being built with the
same motor, but it is being designed to accelerate half as much as the first rocket. What kind of change can be made in the design to
achieve this objective? (1 point)
O The mass of the second rocket should be 0.1 kg.
The mass of the second rocket should be 0.01 kg.
The mass of the second rocket should be 0.4 kg.
O The mass of the second rocket should be 0.2 kg.

Answers

The mass of the second rocket should be 0.4 kg in order for the acceleration to be half of the first rocket's acceleration.

We know that,

F = m a

where,

F = Force

m = Mass

a = Acceleration

Given that,

[tex]F_{1}[/tex] = 100 N

[tex]m_{1}[/tex] = 0.2 kg

[tex]F_{1}[/tex] = [tex]F_{2}[/tex] = 100 N

[tex]a_{2}[/tex] = [tex]a_{1}[/tex] / 2

[tex]F_{1}[/tex] = [tex]m_{1}[/tex] *  [tex]a_{1}[/tex]

[tex]a_{1}[/tex] = 100 / 0.2

[tex]a_{1}[/tex] = 500 m / s²

[tex]a_{2}[/tex] = 500 / 2

[tex]a_{2}[/tex] = 250 m / s²

[tex]m_{2}[/tex] = 100 / 250

[tex]m_{2}[/tex] = 0.4 kg

According to Newton's second law of motion, acceleration of an object is the result of force acting on the object.

Therefore, The mass of the second rocket should be 0.4 kg

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If you are given values for Δx, v, and Δt, which kinematic equation could be used to find v0?​
V = v0 + aΔt
Δx= (v + v0/ 2) Δt
v^2 = v0^2 2aΔx
Δx = v0Δt + 1/2 a (Δt)^2

Answers

The  kinematic equation which could be used to find v₀ is Δx= (v + v₀/ 2) Δt; option B.

What are kinematic equations?

Kinematic equations are equations which relates the motion of a body.

Kinematic equations shows the relationship between the various parameters of motion of a body:

change in position, Δxchange in time, Δtacceleration. ainitial velocity, v₀final velocity, v

The kinematic equations are given below:

V = v + a*ΔtΔx= (v + v₀/ 2) Δtv^2 = v₀² + 2aΔxΔx = v₀Δt + 1/2 a * (Δt)²

Given the values for Δx, v, and Δt, the kinematic equation which could be used to find v₀ is Δx= (v + v₀/ 2) Δt

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European sports car dealer claims that his product will accelerate at a constant rate from rest to a speed of 100 km/h in 8 seconds. What is the speed after the first 5 seconds of acceleration?

Answers

Answer:

[tex]62.5[\frac{km}{h}][/tex]

Explanation:

if the required speed is 's', then it is possible to make up the next equation:

[tex]\frac{100}{8} =\frac{s}{5};[/tex]

finally,

s=100*5/8=62.5 [km/h].

Metric Conversions:
1) 5KL = ?L
2) 3L = ?KL
3) 4g = ?Kg
4) 81Kg = ?g
5) 52dg = ?g
6) 3dm = ?m
7) 14mm = ?m

Answers

The metric conversion of the given quantities is determined as

5 KL = 5,000 L3L  = 0.003 KL4g = 0.004 kg81 kg =  81,000 g52 dg = 5.2 g3 dm = 0.3 m14 mm = 0.014 m

What is metric conversion?

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

The metric conversion of the following quantities is calculated as follows;

5 KL = 5 x 1000 L = 5,000 L

3L = 3 x 1/1000 L = 0.003 KL

4g = 4 x 1/1000 g = 0.004 kg

81 kg = 81 x 1000 g = 81,000 g

52 dg = 52 x 1/10 g = 5.2 g

3 dm = 3 x /10 m = 0.3 m

14 mm = 14 x 1/1000 m = 0.014 m

Thus, the metric conversion of the given quantities is determined as

5 KL = 5,000 L3L  = 0.003 KL4g = 0.004 kg81 kg =  81,000 g52 dg = 5.2 g3 dm = 0.3 m14 mm = 0.014 m

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What will be the acceleration of an object at rest with 70kg if the force exerted is 1400N?

Answers

Force = (mass) x (acceleration)

so

Acceleration = Force / mass

Acceleration = (1400 N) / (70 kg)

Acceleration = 20 m/s²

A cyclist coasts down a hill at 10 m/s. What does 10 m/s describe? Question 2 options: acceleration distance speed velocity

Answers

Answer:

speed

Explanation:

meters per second

Which characteristic is used to measure of light radiated by sh star

Answers

The characteristic that is used to measure light radiated by a star is luminosity. The correct option is C.

What is luminosity?

The radiant power emitted by a light-emitting object with respect to time is measured as luminosity, which is an absolute measure of radiated electromagnetic power.

The total amount of electromagnetic energy radiated per unit of time by a star, cosmos, or other celestial object is referred to as luminosity in astronomy.

The amount of light emitted by a star is measured using luminosity. It is the total amount of emery or light emitted by a star per unit of time. Or it is the total energy produced by a star in one second from its surface.

Thus, the correct option is C.

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Your question seems incomplete, the missing options are:

Size

color

luminosity

temperature

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