a student investigates the density of an aluminum cola can by submerging it in a measuring cylinder of water. When completely submerged, a full can of unopened cola displaces 337 ml of water. The student then empties the can, she finds that it holds 332 ml of cola and that the mass of the empty can is 13.5g when it's empty. Calculate the density of the aluminum used to make the can.

(I did 337-332= 5ml 13.5g/5ml= 2.7 g/cm^3 . I think I got it wrong)

Answer:

alpha particle

Explanation:

I'm pretty sure it's supposed to be "daughter", but I see that it's not a choice so my second best choice would be alpha particle

Answer:

When n = 1 then it means the first shell of an atom whereas n = 2 means the second shell of an atom and so on.

Explanation:

When n = 1 then it means the first shell of an atom whereas n = 2 means the second shell of an atom and so on.

As every atom consists of three sub-atomic particles which are protons, neutrons, and electrons.

Protons and neutrons reside inside the nucleus of an atom and electrons revolve outside the nucleus of the atom.

A covalent bond is defined as the bond formed by sharing of electrons between the two combining atoms.

Therefore, the given questions are answered as follows.

There are 2 electrons in the n = 1 shell.

There are 5 electrons in its n = 2 shell.

There are 5 electrons in nitrogen's outer shell before sharing electrons.

6 electrons are being shared between the two nitrogen atoms.

Covalent bonds exist between the two nitrogen atoms.

Explanation:

1. In the 1 shell there are 2 electrons

2. in the second shell there are 5 electrons

3. To complete the 2 shell are needed 3 electrons

4. Each of them share 3 elections

5. 3 bonds exist between the two nitrogen atoms

Answer:

1 liter = 0.264172 us gallon

Explanation:

The mass number for a carbon atom which contains 6 neutrons is 12.

Answer:

Explanation:

The answer is Xe.

Yeah i just use this calculator

https://www.calculatorsoup.com/calculators/physics/density.php

The arrangement of the objects according to density is;

Solids;

Cork

Ice

Silver ring

Gold ring

Liquids

Gasoline

Seawater

Mercury

The term density is used to describe the value that is obtained as the ratio between the mass and the volume of an object. When we have a mixture of objects, the objects would be separated based on the ones that are denser. We know that the denser liquids would always be found towards the bottom of the vessel that contains the mixture of substances.

Similarly, the solids that are more dense would always tend to sink inside the mixture while the ones that are less dense are closer to the surface.

Now let us arrange the substances according to the densities of each.

Solids;

Cork

Ice

Silver ring

Gold ring

Liquids

Gasoline

Seawater

Mercury

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The MOST likely happened in a situation where the police chief has reported that the evidence from the crime scene has been contaminated is the fact that outside materials were mixed in with collected evidence (Option B).

The expression crime scene refers to all evidence found in a given place after a crime, which is fundamental to solving this type of police case.

In conclusion, the MOST likely happened in a situation where the police chief has reported that the evidence from the crime scene has been contaminated is the fact that outside materials were mixed in with collected evidence (Option B).

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Answer: 0.656168 Feet per minute

Explanation:



0.656168 feet per minute

The formula is:

for an approximate result, divide the speed value by 1829

An atomic mass is the mass of a chemical element's single atom. It involves the masses of the three atomic subatomic particles: protons, neutrons and electrons.

Volume of Naoh(V1)= 30cc

Normality of Naoh(N1)= 1N

Volume of excess Hcl(V2) = ??

Normality of Hcl(N2) = molarity × basicity

= 2×2 = 4 × 1.01 = 4.04N

Using,

V1N1 = V2N2

30×1 = V2 × 4.04

I.e. V2 = 7.42cc

Volume of excess acid = 7.42 cc

  Volume of Hcl neutralized by metal=    100 - 7.42

= 92.575 cc

Therefore,  gm.eqv of Hcl = gm.eqv of metal

(92.575/1000) × 4.04 = 4/E

I.e E = 10.09

Atomic mass= E × basicity

                      = 10.09 × 2

                      = 20.18amu ans

The atomic mass is 20.18 amu

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Answer:

if eel u gngg ferr

Explanation:

asdads

The reasons that studying the periodic trends of elements is important towards having a good understanding of chemistry as the periodic table contain full information regarding an element. The second reason is that it gives brief knowledge about increasing and decreasing of atomic number as well mass of the elements. The third reason is that it shows metals as well as non metals separately.

Periodic table is defined as a table consist of chemical elements contains a series of atomic number generally in rows due to the reason that elements possesses same atomic number lie in the vertical columns.

Therefore, The reasons that studying the periodic trends of elements is important towards having a good understanding of chemistry as the periodic table contain full information regarding an element. The second reason is that it gives brief knowledge about increasing and decreasing of atomic number as well mass of the elements. The third reason is that it shows metals as well as non metals separately.

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Electrophoresis can be defined as a molecular biology procedure to separate biomolecules depending on the weight and electrical charges.

Electrophoresis is a molecular biology procedure in which biomolecules such as DNA or proteins can be separated by their electrical charges and weight. For example, DNA has a negative charge thereby it migrates to the positive pole under an electrophoretic field and different DNA molecules can also be separated by their weight in base pairs.

In conclusion, electrophoresis is a technique used in molecular biology laboratories to separate biomolecules depending on the weight and electrical charges.

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A sample of matter with both a definite and unchanging composition and specific chemical properties is referred to as a pure material.

A mixture is a substance comprised of two or more dissimilar chemicals that are not chemically linked.

Classify the following materials as: pure substance (element or compound) or mixture (heterogeneous or homogeneous) .

Materials

Pure substances and mixtures are the two broad categories into which matter can be divided. A sort of matter known as a pure substance has qualities and a steady composition throughout the sample. Physically combining two or more elements and/or compounds results in a mixture. The two types of mixtures are homogeneous and heterogeneous. Pure substances include both elements and compounds. Substances made up of multiple atom types are known as compounds. The simplest compounds are called elements because they only contain one kind of atom.

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Answer:

the answer is d the nucleus

Explanation:

the nucleus is like in the middle of a cell and I think is the most important.

hope this helps :)

Explanation:

Hi, I think the answers Iodine.

hope it helps

The zeros significant or not significant in number 0.02050 is significant zeros is 2 = in 2050  and not significant zeros is 2  = 0.0

Significant and non significant zeros,

All zeros between two non - zeros digits are significant like in 0.0205

All leading zeros are not significant .they are nothing than place holders

All trailing zeros to the right of the decimal are significant.  

All trailing zeros in a whole no. with no decimal is not significant.

Here,in the no.

                                0.02050    

                                ↓  ↓   ↓  ↓

            not significant   ||  significant

Thus,The zeros significant or not significant in number 0.02050 is significant zeros is 2 = in 2050  and not significant zeros is 2  = 0.0

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Valence electrons are the electrons present  in the outermost shell s and p, or outermost energy level, of an atom.

valence electrons in each group are:-

Groups 3-12 (transition metals)= 2* (Here  4s shell is complete and it  cannot hold any more electrons).

Valence electrons  determine the electrical conductivity of an element. Depending on the nature of elements it can be metal, non-metal, or metalloid.

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Answer:

0.20

Explanation:

Molarity= no of moles/volume in litre

=5/25

= 0.20M

The number of moles of CO₂ produced by the complete combustion of 86.2 g of sucrose, C₁₂H₂₂O₁₁ is 3.024 moles

We'll begin by obtaining the mole of 86.2 g of sucrose, C₁₂H₂₂O₁₁. This can be obtained as follow

Mole = mass / molar mass

Mole of C₁₂H₂₂O₁₁ = 86.2 / 342

Mole of C₁₂H₂₂O₁₁ = 0.252 mole

C₁₂H₂₂O₁₁ + 12O₂ -> 12CO₂ + 11H₂O

From the balanced equation above,

1 mole of C₁₂H₂₂O₁₁ reacted to produce 12 moles of CO₂.

Therefore,

0.252 mole of C₁₂H₂₂O₁₁ will react to produce = 0.252 × 12 = 3.024 moles of CO₂.

Thus, 3.024 moles of CO₂ were produced from the reaction

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The limiting reactant of the reaction will be aluminum (Al).

In chemical reactions, limiting reactants are reactants that are available in limited quantity. Thus, these reactant determines how much of the products are formed. Other reactants in the same reaction are said to be in excess.

From the equation of the reaction:

[tex]2Al + 2KOH + 6HOH --- > 2 KAl (OH)_4 + 3H_2[/tex]

The mole ratio of Al to KOH to HOH is 2:2:6 or 1:1:3.

Mole of 3.0 g Al = 3/27

                           = 0.111 moles

Mole of 15 mL, 8 M KOH = 8 x 15/1000

                                   = 0.12 moles

Mole of 75 mL of distilled water = 75/18

                                             = 4.167 moles

From the above number of moles of each reactant and the mole ratio, it is obvious that Al with 0.111 moles is the limiting reactant.

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Answer:

4.0 grams?

Explanation:

I DONT KNOW IF I AM RIGHT but if i am i wish u luck <3

hope i helped

The average molecular weight of bovine cytochrome c = 13800 Da

Explanation:

bovine cytochrome c contains 2 methionine residues

so the 1 mole of bovine cytochrome c will contain 2 moles of methionine residues.

molar mass methionine residue = 149 g/mol

if both residues are present at the terminal, then

'C' terminal eliminates the 'H' group and the 'N' terminal eliminate the 'OH' group

its mass = (2*149) - 1 - 17 = 280 g

mass of methionine residues in 1 mole of bovine cytochrome c = 280 g

mass % of methionine residues in bovine cytochrome c = 2%

mass % = (mass of individual component / total mass of the compound ) *100

mass % of methionine residues = (mass of individual methionine residues/mass of bovine cytochrome c ) *100

mass of individual methionine residues = 280 g

mass % of methionine residues in bovine cytochrome c = 2%

2 = (mass of individual methionine residues/mass of bovine cytochrome c ) *100

(2/100) = (280 / mass of bovine cytochrome c)

0.02 = (280 / mass of bovine cytochrome c)

mass of bovine cytochrome c = 280 / 0.02 = 14000 g

mass of bovine cytochrome c = 14000 g

since this calculation is done for 1 mole of bovine cytochrome c

so the mass of 1-mole bovine cytochrome c = 14000 g

mass of 1-mole bovine cytochrome c = molecular weight of bovine cytochrome c

The molecular weight of bovine cytochrome c = 14900 g/mol

1 g/mol = 1 Da

the molecular weight of bovine cytochrome c when both residues are terminal  = 14900 Da

when both residues are not present at the terminal, then

non-terminal eliminate H2O group

mass of residues = 2*(149 -18 ) = 262 g

mass % of methionine residues = (mass of individual methionine residues/mass of bovine cytochrome c ) *100

2 = ( 262 / mass of bovine cytochrome c ) *100

0.02 = 262 / mass of bovine cytochrome c

mass of bovine cytochrome c = 262 / 0.02 = 13100 g/mol

the molecular weight of bovine cytochrome c  = 13100 Da

when one residue is N terminal and one is non-terminal

N- terminal eliminate 'OH' group and non-terminal eliminate H2O group

mass of residues = (2*149) - 18 - 17 = 263 g

mass % of methionine residues = (mass of individual methionine residues/mass of bovine cytochrome c ) *100

2 = ( 263 / mass of bovine cytochrome c ) *100

0.02 = 263 / mass of bovine cytochrome c

mass of bovine cytochrome c = 263 / 0.02 = 13150 g/mol

the molecular weight of bovine cytochrome c = 13150 Da

when one residue is C terminal and one is non-terminal

C- terminal eliminates the 'H' group and non-terminal eliminates the H2O group

mass of residues = (2*149) - 18 - 1 = 279 g

mass % of methionine residues = (mass of individual methionine residues/mass of bovine cytochrome c ) *100

2 = ( 279 / mass of bovine cytochrome c ) *100

0.02 = 279 / mass of bovine cytochrome c

mass of bovine cytochrome c = 279 / 0.02 = 13950 g/mol molecular weight of bovine cytochrome c = 13950 Da

taking average all this = (14900 + 13100 + 13150 +13950) / 4 = 55100/4 = 13775 Da

The average molecular weight of bovine cytochrome c = 13775 Da

rounding off to three significant figures

The averages molecular weight of bovine cytochrome c = 13800 Da.

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Answer:

ooooookkkkkkllllloooooooogggggo

how many there are of each element for example H20 is 2 hydrogen atoms plus 1 oxygen atom

Answer:

I think cotton

Explanation:

Because in the kitchen ,there is heat that makes us sweat as cotton is a good absorber of water, it will keep us cool in hot atmosphere of the kitchen.

Sorry but please recheck it again this is my analysis

the relationship between turtles and barnacles is an example of

co-evolution, where each species is continually adapting to changes with  the other.

Barnacles attaches to  turtle's shell due to its hardness. Barnacles needs  a hard surface to bind with so that it can thrive. A single barnacle doesn’t harm a turtle. But excessive barnacles can make a turtle inactive,also impact its vision and make it difficult to eat, and sometimes lead to infection.

.The cyprid larvae of barnacle has a special attachment devices which allow it to hold onto the substrate, e.g. cup-shaped attachment organs on the antennae. Once barnacle is settled, the barnacle develops into an adult and attaches in different  ways as gripping the skin, cementing to the shell or boring into it.

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The half life of the radioactive iron-59 is 42 days.

This is the time taken for a radioactive isotope to decay to half of its original size.

The half life of the radioactive iron-59 is calculated as follows;

N(t) = N₀(¹/₂)^t/h

where;

0.4 = 1.6(¹/₂)^84/h

log(0.4/1.6) = 84/h log(¹/₂)

-0.602  = 84/h(-0.3)

84/h = 2

h = 42 days

Thus, the half life of the radioactive iron-59 is 42 days.

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The mass, in grams, of oxygen that will be produced from the reaction to two significant figures, will be 0.17 grams.

Mercury oxide decomposes to liquid mercury and oxygen gas. The equation for the decomposition reaction is represented below:

[tex]2HgO + heat --- > 2Hg + O_2[/tex]

Mole of 2.25 g mercury oxide = mass/ molar mass

                = 2.25/216.59

                       = 0.0104 moles

Mole ratio of mercury oxide that decomposes and oxygen gas produced = 2:1.

Equivalent moles of oxygen gas produced = 0.0104/2

                                 = 0.0052 moles

Mass of 0.0052 moles oxygen gas = mole x molar mass

                                 = 0.0052 x 32

                                         = 0.1664 grams

To 2 significant figures, the amount of oxygen gas produced is 0.17 grams.

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Neutrons have no charge, protons have a positive charge, and electrons have a negative charge. One proton's positive charge and one electron's negative charge are equal. While electrons have essentially negligible mass, protons and neutrons each have a mass of 1.

In which of these statements are protons, electrons, and neutrons correctly compared?

"Quarks are present in protons and neutrons but not in electrons."

Protons and neutrons contain quarks, while electrons do not. Subatomic particles known as quarks have mass but no charge at all. Quarks are the building blocks of protons and neutrons, but electrons are not because they are energy travelling with an electric charge rather than matter with mass. Given that quarks have mass, they cannot be found in electrons.

Undoubtedly among the tiniest particles in the universe are quarks. They are fundamental, irreducible, and incapable of being broken down into smaller parts.

The gravitational force, electromagnetic force, strong nuclear force, and weak nuclear force are the only four fundamental physical forces that quarks can freely interact with.

There are six different types of quarks, and they are never found in nature alone; rather, they form hadrons, which are composed of two or three quarks and are referred to as mesons or baryons, respectively.

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