Answer: 200 Meters after 10 minutes.
Step-by-step explanation:
To find the answer you must multiply 20 for every minute.
Hope this helped :D
The rectangle below has an area of 30k3 + 6k2.
The width of the rectangle is equal to the greatest common
monomial factor of 30k3 and 6k2.
What is the length and width of the rectangle?
9514 1404 393
Answer:
length: (5k +1)width: 6k^2Step-by-step explanation:
The GCF of the two terms is the second term: 6k^2. When that is factored out, you have ...
area = (6k^2)(5k +1)
According to the problem statement, this is interpreted as ...
width: 6k^2
length: 5k+1
A town's population of children increased from 376 to 421 during the past year.
Which equation shows how to find the percent increase?
Answer:
The percentage increase equation is:
Percentage Increase = [ (Final Value - Starting Value) / |Starting Value| ] × 100
The percentage increase = 11.97%
Step-by-step explanation:
Given
Starting Value = 376
Final Value = 421
To determine
Percentage Increase =?
The percentage increase equation:
Percentage Increase = [ (Final Value - Starting Value) / |Starting Value| ] × 100
= [(421 - 376) / (376)] × 100
= [45 / 376] × 100
= 11.97%
Therefore, the percentage increase = 11.97%
Answer:
3700 kings
Step-by-step explanation:
Solve the system of linear equations, using the Gauss-Jordan elimination method. (If there is no solution, enter NO SOLUTION. If there are infinitely many solutions, express your answer in terms of the parameters t and/or s.) x1 2x2 8x3
Answer:
Infinitely solution exists,
Required solution is, [tex](x_1,x_2,x_3)=(0, 4(1-t),t)[/tex]
Step-by-step explanation:
We have the given equations:
[tex]x_1+2x_2+8x_3=8[/tex]
[tex]x_1+x_2+4x_3=4[/tex]
Here, the augmented matrix is :
[tex]\left[\begin{matrix}1&2&8&8\\1&1&4&4\end{matrix}\right][/tex]
Now, find the echelon form of the augmented matrix.
[tex]=\left[\begin{matrix}1&2&8&8\\0&-1&-4&-4\end{matrix}\right]^{R_1\rightarrow R_2-R_1}[/tex]
[tex]=\left[\begin{matrix}1&0&0&0\\0&-1&-4&-4\end{matrix}\right]^{R_1\rightarrow R_1+2R_2}[/tex]
Therefore, [tex]x_1=0[/tex]
[tex]-x_2-4x_3=-4[/tex]
[tex]\Rightarrow x_2=4(1-x_3)[/tex]
Let [tex]x_3=t[/tex], then the required solution is
[tex](x_1,x_2,x_3)=(0, 4(1-t),t)[/tex]
Help out pls need help on this question
Answer:
[tex]\huge\boxed{\sf Option \ 4}[/tex]
Step-by-step explanation:
y = The total cost
x = The number of movie tickets.
So, The equation that represents the function is:
y = 10.25 x
This shows that the total cost is equal to the cost of 1 ticket multiplied by the no. of tickets.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807In a large population, very close to 25% of the observations will fall below the
25th percentile (Q1), and close to 75% fall below the 75th percentile (Q3). The
Web site of the Educational Testing Service reports that on the SAT
Mathematics test, with a possible perfect score of 800, the 96th percentile of
1,475,623 scores nationwide is a score of 720.
What is the best estimate of exactly how many scores were below 720?
A. 84
ооо
B. 1,417,000
C. 557
D. 80%
оо
E. 192,000
PREVIOUS
Answer:
1,417,000
Step-by-step explanation:
Given that:
Score = 1,475,623
96% of nationwide
96% of score gives the best estimate of the number of scores below 720
0.96 * 1475623
= 1416598.08
The best estimate is 1,417,000
the maximum slope for a hand propelled wheelchair ramp should be a 1 inch rise to every 12 inches of blank. What is the maximum ramp angle recommended to the nearest degree?
9514 1404 393
Answer:
5°
Step-by-step explanation:
The angle for 12 inches of ramp length and the angle for 12 inches of run are very similar. Both are near 4.8°, so are 5° when rounded.
If we say 12 inches of run, then the tangent relation applies.
Tan = Opposite/Adjacent
tan(α) = (1 in)/(12 in)
α = arctan(1/12) ≈ 4.764°
The maximum angle is about 5°.
Michael made 19 out of 30 free-throws this basketball season. Larry's free throw average was 0.745 and Charles' was 0.81. John made 47 out of 86 free-throws. Who is the best free-throw shooter
Answer: Charles
Step-by-step explanation:
Michael made 19 out of 30 free-throws. This gives 19/30 = 0.63
Larry's free throw average was 0.745.
Charles' was 0.81.
John made 47 out of 86 free-throws. This gives 47/86 = 0.55
The best free-throw shooter was Charles
Answer:
Charles
Step-by-step explanation:
The best free-throw shooter was Charles
x is 4 more than two - thrice of y
Answer: x = 2/3y + 4
Hope it helped u,
pls mark as the brainliest
^v^
There are 65 children in the sixth grade.There are 5 more boys than girls.
a.how many girls are in the class
b.what is the ratio of boys to girls.
c.If 5 more girls joined the class what is the ratio of boys to girls now?
HURRY
What is the value of the expression 4+(-2)
-3+3
Answer:
The answer is 2
Step-by-step explanation:
Addition is considered first before subtraction
So 4+(-2) and -3+3 are considered separately and later their results are added
(2+0=2)
Question #7
Revisit
The average age of three people, A, B and C is 32 years. If 2 more people, D and E are
included, the five people's average age becomes 34 years. What is D and E's average age?
Answer:
ytviykgti
Step-by-step explanation:
It costs $859.32 to have a school dance. The dance is $8 per ticket.
a. How many tickets must sold to cover the cost?
b. How many tickets must be sold to make a $980.68 profit?
Answer: 108 tickets must be sold to cover the cost.
123 tickets must be sold to make a profit of approximately $980.68
Step-by-step explanation:
Just divide 859.32 from 8 to find out how many tickets must be sold to cover the cost. Same for part b.
Hope this helps!
a. It takes 108 tickets to cover the cost.
b. It takes 230 tickets to make a $980.68 profit.
Hope that helps! I did the questions AND calculated to see if they were correct. (They are correct lol)
Help I'll make you a Brainlest
Answer:
x = 13
Step-by-step explanation:
m∠ABC + m∠CBD = 180° {linear pair}
3x + 43 + 6x + 20 = 180
3x + 6x + 43 + 20 = 180
9x + 63 = 180
9x = 180 - 63
9x = 117
x = 117/9
x = 13
What is the output of the equations y=2x + 8 if the input is -2?
Answer:
y=4
Step-by-step explanation:
Step-by-step explanation: Input is the same as the x term.
If the input is -2, we substitute a -2 in for x.
So we have y = 2(-2) + 8 or y = -4 + 8 which is 4.
So the output or the y term is 4.
Solve for x x-5=-7
X=-2
X=-5
X=-1
X=-3
Answer:
X=-2
Step-by-step explanation:
x-5=-7
x-5+5=-7+5
X=-2
Help ASAP!!! What’s the value of x
Answer:
x=8
Step-by-step explanation:
∠B=∠A
Base Angle Thm/ Def. of Iso.
72=9x
x=8
The equation below expresses the approximate
height h, in meters, of a ball t seconds after it is
launched vertically upward from the ground.
h(t) = –16t2 + 25t. At how many different times will the ball be 7 ft. High?
Answer:
The ball will be the 7 ft high at 2 different times.
Step-by-step explanation:
The height in meters of the ball is given by the following equation:
[tex]h(t) = -16t^2 + 25t[/tex]
7 feet high
The height, by the equation, is given in meters, so we have to work in meters. Since each feet has 0,3048 meters, 7 feet have have 2.1336 meters. So, we have to solve the following equation
[tex]2,1336 = -16t^2 + 25t[/tex]
[tex]16t^2 - 25t + 2,1336 = 0[/tex]
At how many different times will the ball be 7 ft. High?
We have to find the number of solutions for the equation above.
It is given according to the value of [tex]\Delta = b^2 - 4ac[/tex]. If it is positive, there are two solutions, zero one solution and negative no solutions.
In this equation [tex]a = 16, b = -25, c = 2.1336[/tex]. So
[tex]\Delta = b^2 - 4ac = (-25)^2 - 4*16*2.1336 = 488[/tex]
Since the coefficient is positive, the ball will be the 7 ft high at 2 different times.
Please answer this correctly without making mistakes
Answer:
63 gallons
Step-by-step explanation:
3 gallons = 4x 3 = 12 quarts
12+2 = 14
14 x 18 = 252 quarts
252 / 4 = 63 gallons
median of 57,75,40,34,45,60,45,44\
Answer:
the median is 45
Step-by-step explanation:
The computation of the median is as follows:
First arrange in a sequential order
34, 50, 44, 45, 45, 60, 57, 75
Now as we can see that there are 8 numbers
= n ÷ 2
= 8 ÷ 2
= 4 number
= 45
Hence, the median is 45
The same is relevant and considered too
Are carnivores consumers
Answer:
Yes, herbivores, carnivores, and omnivores are consumers.
Hope this helps :)
Answer:
yes it is yes here's your answer for the emanation use search hope it works
I GIVE BRAINLIEST
Point A is located in which quadrant?
Answer:
II
Step-by-step explanation:
Quadrant I is +x + y
Quadrant II is -x + y
Quadrant III is -x - y
Quadrant IV is +x -y
At the grocery store, Mr. Arnett allowed
What is the slope of this line?
- 2/3
2/3
1/3
- 1/3
Answer:
2/3
Step-by-step explanation:
slope =(y1-y2)/(x1-x2)
slope=(1-(-1))/(6-3)
slope =2/3
The acceleration, in meters per second per second, of a race car is modeled by A(t)=t^3−15/2t^2+12t+10, where t is measured in seconds. What is the car’s maximum acceleration on the time interval 0≤t≤6 ?
Answer:
The maximum acceleration over that interval is [tex]A(6) = 28[/tex].
Step-by-step explanation:
The acceleration of this car is modelled as a function of the variable [tex]t[/tex].
Notice that the interval of interest [tex]0 \le t \le 6[/tex] is closed on both ends. In other words, this interval includes both endpoints: [tex]t = 0[/tex] and [tex]t= 6[/tex]. Over this interval, the value of [tex]A(t)[/tex] might be maximized when [tex]t[/tex] is at the following:
One of the two endpoints of this interval, where [tex]t = 0[/tex] or [tex]t = 6[/tex].A local maximum of [tex]A(t)[/tex], where [tex]A^\prime(t) = 0[/tex] (first derivative of [tex]A(t)\![/tex] is zero) and [tex]A^{\prime\prime}(t) <0[/tex] (second derivative of [tex]\! A(t)[/tex] is smaller than zero.)Start by calculating the value of [tex]A(t)[/tex] at the two endpoints:
[tex]A(0) = 10[/tex].[tex]A(6) = 28[/tex].Apply the power rule to find the first and second derivatives of [tex]A(t)[/tex]:
[tex]\begin{aligned} A^{\prime}(t) &= 3\, t^{2} - 15\, t + 12 \\ &= 3\, (t - 1) \, (t + 4)\end{aligned}[/tex].
[tex]\displaystyle A^{\prime\prime}(t) = 6\, t - 15[/tex].
Notice that both [tex]t = 1[/tex] and [tex]t = 4[/tex] are first derivatives of [tex]A^{\prime}(t)[/tex] over the interval [tex]0 \le t \le 6[/tex].
However, among these two zeros, only [tex]t = 1\![/tex] ensures that the second derivative [tex]A^{\prime\prime}(t)[/tex] is smaller than zero (that is: [tex]A^{\prime\prime}(1) < 0[/tex].) If the second derivative [tex]A^{\prime\prime}(t)\![/tex] is non-negative, that zero of [tex]A^{\prime}(t)[/tex] would either be an inflection point (if[tex]A^{\prime\prime}(t) = 0[/tex]) or a local minimum (if [tex]A^{\prime\prime}(t) > 0[/tex].)
Therefore [tex]\! t = 1[/tex] would be the only local maximum over the interval [tex]0 \le t \le 6\![/tex].
Calculate the value of [tex]A(t)[/tex] at this local maximum:
[tex]A(1) = 15.5[/tex].Compare these three possible maximum values of [tex]A(t)[/tex] over the interval [tex]0 \le t \le 6[/tex]. Apparently, [tex]t = 6[/tex] would maximize the value of [tex]A(t)\![/tex]. That is: [tex]A(6) = 28[/tex] gives the maximum value of [tex]\! A(t)[/tex] over the interval [tex]0 \le t \le 6\![/tex].
However, note that the maximum over this interval exists because [tex]t = 6\![/tex] is indeed part of the [tex]0 \le t \le 6[/tex] interval. For example, the same [tex]A(t)[/tex] would have no maximum over the interval [tex]0 \le t < 6[/tex] (which does not include [tex]t = 6[/tex].)
Charmaine must choose a number between 49 and 95 that is a multiple of 4, 8, and 12. Write all the numbers that she could choose.
7
Write a 6-digit numeral
that has
7 in the hundredths place,
5 in the thousands place,
4 in the hundreds place,
and o in all other places.
7a. Write the number.
7b. Write in word form.
7c. Write in expanded form.
7d. Write as a fraction.
Step-by-step explanation:
Let's use the number Zero as a placeholder.
7 in the hundredths place,
0.07
5 in the thousands place,
5000.07
4 in the hundreds place,
5400.07
7a. Write the number.
5400.07
7b. Write in word form.
Five thousand four hundred and seven hundredth
7c. Write in expanded form.
5000 + 400 + 0.07
7d. Write as a fraction.
540007 / 100
EASY MATH!!! LOTS OF POINTS!!! WILL MARK BRAINLIEST!!!
The speed of a boat in still water is 25 mph. The boat is traveling on a river with a current flowing south at 10 mph. At what angle upstream should the boat head to travel due west?
A. 21.80°
B. 23.58°
C. 66.42°
D. 68.20°
Answer:
23.58
Step-by-step explanation:
Simplify the expression: 2(2 + g) =
Answer:
4 + 2g
General Formulas and Concepts:
Pre-Algebra
Distributive Property
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightStep-by-step explanation:
Step 1: Define
2(2 + g)
Step 2: Expand
Distribute 2: 2(2) + 2(g)Multiply: 4 + 2gEvaluate the following expression. 5−3+2 help fast
Answer:
4
Step-by-step explanation:
5-3=2 2+2=4
there are no parentheses so you just add/subtract from left to right..
Find the equation of the line shown.
Can someone help me please
Answer:
y= -2x + 9
Step-by-step explanation:
I got 2x because you use rise over run. As you can see in the image, the slope goes up two and to the left one ( 2x). It's plus 9 because that where it intersects the 9 on the y-intercept. The slope is negative because the line is going down from left to right ( always read it from left to right).
I hope this helps. I'm not that great at explaining so....:)
Answer:
2x+y-9=0
Step-by-step explanation:
let's take two co ordinates
(X1,y1)=(4,1)
(X2,y2)=(3,3)
Equation using two point :
(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
plug in the values,(y-1)/(3-1)=(x-4)/(3-4)
(y-1)/2=(x-4)/-1
-1*(y-1)=(x-4)*2
-y+1=2x-8
0=2x+y-9
2x+y-9=0