An array of 30 LED bulbs is used in an automotive light. The probability that a bulb is defective is 0.001 and defective bulbs occur independently. Determine the following: a. Probability that an automotive light has two or more defective bulbs. b. Expected number of automotive lights to check to obtain one with two or more defective bulbs.

Answers

Answer 1

Answer:

a) 0.0005 = 0.05% probability that an automotive light has two or more defective bulbs.

b) 4000 automotive lights.

Step-by-step explanation:

For each LED, there are only two possible outcomes. Either it is defective, or it is not. Defective bulbs occur independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

An array of 30 LED bulbs is used in an automotive light. The probability that a bulb is defective is 0.001.

This means that, respectively, [tex]n = 30, p = 0.001[/tex].

a. Probability that an automotive light has two or more defective bulbs.

This is:

[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]

In which

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{30,0}.(0.001)^{0}.(0.999)^{30} = 0.9704[/tex]

[tex]P(X = 1) = C_{30,1}.(0.001)^{1}.(0.999)^{29} = 0.0291[/tex]

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.9704 + 0.0291 = 0.9995[/tex]

[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9995 = 0.0005[/tex]

0.0005 = 0.05% probability that an automotive light has two or more defective bulbs.

b. Expected number of automotive lights to check to obtain one with two or more defective bulbs.

0.0005 = 0.05% probability that an automotive light has two or more defective bulbs.

The number of expected trials to obtain n successes with p probability is given by:

[tex]E = \frac{n}{p}[/tex]

In this case, we have that [tex]n = 2, p = 0.0005[/tex]. So

[tex]E = \frac{n}{p} = \frac{2}{0.0005} = 4000[/tex]

4000 automotive lights.


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Step-by-step explanation:

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The University of South Texas is interested in determining if there is a difference in the average weight gain between male students (group 2) and female students (group 1) during their freshman year. They take a random sample of 10 male students and 10 female students. Find the confidence interval with 95% confidence. The 95% confidence interval is (2.4, 20.4). A. We are 95% confident that the population mean weight gain for male University of South Texas students is 2.4 more to 20,4 more than female University of South Texas students. B. We are 95% confident that the population mean weight gain for female University of South Texas students is 2.4 more to 20.4 more than male University of South Texas students. C. We are 95% confident that the sample mean weight gain for female University of South Texas students is 2.4 more to 20.4 more than male University of South Texas students. D. We are 95% confident that the sample mean weight gain for male University of South Texas students is 2.4 less to 20.4 more than female University of South Texas students.

Answers

Answer: A. We are 95% confident that the population mean weight gain for male University of South Texas students is 2.4 more to 20,4 more than female University of South Texas students.

Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Which fraction has a terminating decimal?
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- 4/7
- 1/3
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Answers

Answer: D) 3/150

==========================================================

Explanation:

With the use of a calculator, we see that,

11/19 = 0.57894736842106...., the decimals eventually repeat; but unfortunately my calculator ran out of room to show the repeating portion4/7 = 0.5714285714285714..., the block "571428" repeats forever1/3 = 0.333333.... the 3s go on forever3/150 = 0.02

So 3/150 converts to the terminating decimal 0.02

The word "terminate" means "stop". In the other decimal values, the decimal digits go on forever repeating the patterns mentioned.

----------------------

A non-calculator approach will have us simplify 3/150 into 1/50 after dividing both parts by the GCF 3. Then notice how 50 has the prime factorization of 2*5*5. The fact that the denominator 50 can be factored in terms of only 2's and 5's is enough evidence to conclude that the fraction converts to a terminating decimal.

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Answers

Answer:

$20 + (1.75 * p)

Step-by-step explanation:

This is just a guess hope this is correct.

Hope this helps! :)


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Answers

Answer:

it would be a closed circle and to the right

Step-by-step explanation:

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Answers

Answer:

4 Adults and 6 Children went to the movies.

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

a) The centripetal force equation is:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:


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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

Answer:

Hi

Step-by-step explanation:

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Answers

Answer:

The slope is 5 and the y-intercept is at (0, 6)

Step-by-step explanation:

Parallel lines have the same slope, so the slope of the equation is 5. The equation is y = 5x + 6, so the y-intercept is 6.

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Answers

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Answer:

4/8

I don't really have an explanation-

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