I need before 11:28
8. An object is sliding on a surface accelerating rightward,
according to the diagram on the right.
a. Use the mass and acceleration to find the Fnet.
b. Use the Fnet and Fapp to find the Ffrict.
c. Use the mass and acceleration due to gravity, 9.8 m/s²
to find the Fgrav.
d. Use the Fgrav to find the Fnorm-
Ffrict =
Fnet =
mass = 60 kg
r
Fnorm=
Fgrav =
Fapp=1257
Answer:
b
Explanation:
Calculate the average speed (in m/s) of a cheetah that run 140 meters in 5 seconds
Given :
Distance travelled by Cheetah = 140 mTime taken by Cheetah = 5 seconds.How to calculate average speed?
Average speed is calculated by Distance travelled / time taken.
Here, we know distance is 140 m and time is 5 seconds. Substituting the values,
=) Distance / Time
=) 140 m / 5 s
=) 28 m/s.
Therefore, the average speed (in m/s) of a cheetah that runs 140 meters in 5 seconds is 28m/s.
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An autographed baseball rolls off of a 1.2 m
high desk and strikes the floor 0.76 m away
from the desk. How fast was it rolling on the desk before
it fell off? The acceleration of gravity is 9.81 m/s2.
The autographed baseball rolled off at 0.3762m/s before it fell off.
What is acceleration?Acceleration is the rate of change of the velocity of an object with respect to time.
Given the following data:
Initial velocity = 0 m/s (assuming it started from rest).
Vertical distance = 1.2 meters
Horizontal distance = 0.76 meters
Acceleration due to gravity = 9.81
To find how fast the autographed baseball was rolling on the desk before it fell off:
we will use the second equation of motion to determine the time required:
S = ut + 1/2at²
Where:
S is the displacement or distance covered.
u is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting the given values into the formula, we have;
S = ut + 1/2at²
=0*t + 1/2 * 9.81 * t²
t = 2.02 seconds
Next, we would determine the horizontal speed:
horizontal speed= horizontal distance/time
horizontal speed=0.76/2.02
horizontal speed=0.3762m
Horizontal speed = 0.3762m/s
Therefore, the autographed baseball rolled off at 0.3762m/s before it fell off.
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The village blacksmith dunks a red-hot horseshoe into a large bucket of 22°C water. How much heat was lost by the horseshoe in vaporizing 0.981 kg of water?
Q=mcΔT and Q=mhv (Heat of vaporization of water = 2,260,000 J/kg and the specific heat is 4187 J/kg°C) Round to the tenth place.
The heat lost in this case is obtained as 2537.1 kJ.
What is the heat lost?We know that heat is the form of energy that exists due to temperature difference between two bodies. In this case, the village blacksmith dunks a red-hot horseshoe into a large bucket of 22°C water. This led to the evaporation of 0.981 kg of water.
Now there are two distinct processes here;
The heat required to heat the water from 22 degrees to boiling pointHeat required to vaporize the water.The total heat lost = mcdT + mL
= 0.981 kg * 4187 J/kg°C * ( 100 - 22) + 0.981 kg * 2,260,000 J/kg
H = 320 kJ + 2217
H = 2537.1 kJ
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The drawing shows two tug-of-war teams. Each person in the red team is
pulling with a force of 250 N. Each person in the blue team is pulling with a
force of 200 N.
S
AX
a What is the total force exerted by the blue team?
b What is the total force exerted by the red team?
c What is the resultant (unbalanced) force on the rope?
d Which team will win?
a) Force exerted by blue team = 1200N
b) Force exerted by red team=1250N
c) Resultant =50N in the direction of red team
d) Red team will win as they are pulling with greater force
There are 6 people on blue team and 5 people on red team
so here it is given that in blue team a person exerts a force of 250N and number of people is 6 , then total force will be 200x6=1200N
so here it is given that in red team a person exerts a force of 200N and number of people is 5 , then total force will be 250x5=1250N
the unbalance force here is 1250-1200=50N
from the above we know that red team have an extra force of 50N so they will win the match as they are pulling with greater force.
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A drone starts from rest and travels 50m with an acceleration of 5 m/s2. How long does
this take?
A 4.5 s
B 20 s
C 10.5 s
D 48.5 s
A drone starts from rest and travels 50m with an acceleration of 5 m/s2. it takes 4.5s.
What is acceleration?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
u= 0m/s
s = 50m
a = 5m/s²
t = ?
s = ut + 1/2 at²
50 = 0 + 1/2 * 5 * t²
t² = 50 *2/5
t² = 20s
t = 4.47s
t = 4.5s
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According to newtons 1st law of motion if u leave a cookie on a plate and there is no one else in the house,where will the cookie be in an hour?
Which is not the measurement of speed
Km/h S/M Mph M/S MS
It is observed that 54.90 mL of water at 20∘C completely fills a container to the brim. When the container and the water are heated to 60∘C, 0.35 g of water is lost. Part A What is the coefficient of volume expansion of the container? Density of water at 60 ∘C is 0.98324 g/mL.
The coefficient of volume expansion is given as 1.5012 x10^-4
What is volume?
A volume can simply be defined as the amount of space occupied by any three-dimensional solid. The solids can take the shape or form of a cube, a cuboid, a cone, a cylinder or a sphere
Volume of water that is lost
= (0.35) * (0.98324) mL
= 0.3441 mL
The original volume of
55.50 mL will increase to
55.8441 mL
V(t) = Vo [1 + γ(60.0 - 18.7)]
=> coefficient of volume expansion,
γ = (Vt - Vo) / [Vo * 41.3]
= (0.3441) / [(55.50) (41.3)
= 1.5012 x10^-4
The coefficient of the volume expansion can be the measure of the fractional change of size per unit change in the temperature with the surrounding pressure being constant.
In conclusion, the coefficient of volume is most applicable to the fluids.
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What were you doing when you felt most passionate and alive and where?
A happiness that is full of significance and delight as well as a sense of vitality and freedom results from this kind of all-consuming desire. This is your chance to live a more fulfilled life where finding joy in what you do instead of pursuing the one thing you love is the goal.
Passion fuels our motivation. It aids us in constructing our dreams and goals. It's how we decide what our life's job is, and why we put in the effort to get there. Our lives are useless and unfulfilling without passion—for our friends and family, for creating beauty, for giving back, or for fulfilling a higher purpose.
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1. Compare the kinetic energy distributions for the heavy vs. light particles at the same
temperature. Are these the same or different? What about the speed distributions?
2. Compare the kinetic energy distributions for the heavy vs. light particles at different
temperatures. Are these the same or different? What about the speed distributions?
3. Compare the kinetic energy distributions for the mixture to those of the heavy-only and light-
only gases at the same temperature. Are these the same or different? What about the speed
distributions?
4. Summarize your observations about the relationships between molecular mass (heavy vs.
light), kinetic energy, particle speed, and temperature.
Only when the average speed of the heavy particles is lower than that of the light particles will the average kinetic energy of the light particles equal the average kinetic energy of the heavy particles.
How do the kinetic energy of the light and heavy particles compare?Only when the average speed of the heavy particles is lower than that of the light particles will the average kinetic energy of the light particles equal the average kinetic energy of the heavy particles.
As the temperature rises, the particles accumulate kinetic energy and quicken. The actual average speed of the particles is influenced by both their mass and temperature; at a given temperature, larger particles travel more slowly than lighter ones.
Given that the formula for calculating a particle's kinetic energy is
Ek = 1/2 mu²,
The formula for particle speed is [tex]$$c = [3RT/M]^{1/2[/tex].
The graphs of kinetic energy and particle speed show that the heavier particles only have higher peaks, whilst the lighter particles only have lower peaks.
It is clear from the graphs and the temperatures employed that the graphs' shapes were nearly identical. It does not appear to be significantly impacted by temperature.
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find the derivative of y with respect to time:. 2√t/3(√t)^2
Answer:
See below
Explanation:
2√t/(3(√t)^2) I added parentheses for what I think you were asking
This equals 2/3 * t^1/2 / t
= 2/3 * t ^-1/2
derivative is -1/2 * 2/3 * t ^(-1/2 -1)
- 1/3 t^(-3/2)
What advances have happened that allow us to look inside the living juman brain
Answer:
Brain imaging aka Neuroimaging explores a series of mechanisms such as cognition, information processing, and brain changes in the functioning state. In addition, MRI, Magnetic resonance imaging, is a medical imaging test that produces detailed images of the brain.
Explanation:
A car accelerates from rest to a speed of 33 m/s. If the distance traveled by the car is 125m, how long
did it take for the car to reach this speed?
The car reaching to the given speed at the time, t = 0.264 s
Equation :To know the time of the car reaching to the given time use formula,
s = d / t
where,
s is speed
d is distance
t is time
Given,
distance, d = 125m
speed, s = 33m/s
time, t = ?
Putting values,
33m/s = 125 m / t
t = 33 m/s / 125m
t = 0.264 s
Speed time and distance relation :Speed is calculated as follows: speed = distance x time. Knowing units for distance and time is necessary to calculate the units for speed. The units will be in metres per second (m/s) in this example because the distance is measured in metres (m) and the time is measured in seconds (s).
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WHAT IS greenhouse EFFECT?
Answer: the trapping of the sun's warmth in a planet's lower atmosphere, due to the greater transparency of the atmosphere to visible radiation from the sun than to infrared radiation emitted from the planet's surface.
Explanation:
Answer:
The greenhouse effect is a process that occurs when energy from a planet's host star goes through its atmosphere and heats the planet's surface, but greenhouse gases in the atmosphere prevent some of the heat from returning directly to space, resulting in a warmer planet
A marble is thrown downward at a speed of 10.0 m/s from the top of a 30.0 m tall
building. 0.50 s later, a second marble is thrown downward. At what speed must the
second marble be thrown so that the two marbles reach the ground at the same time?
The speed of the second marble must be 14.8 m/s so that the two marbles reach the ground at the same time.
What is the time taken bey the first stone to reach the ground?The time taken by the first stone to reach the ground is calculated using the formula below:
h = ut + ¹/₂gt²
where:
h is the heightu is initial velocity or speedt is timeg is acceleration due to gravityFrom the data provided;
h = 30, u = 10m/s, g = 9.8 m/s
30 = 10t + 0.5 * 9.8t²
30 = 10t + 4.9t²
4.9t² + 10t - 30 = 0
t = 1.65 s
For the second marble, time taken = 1.65 - 0.50
t = 1.15 s
Initial velocity, u will be:
30 = u(1.15) + 0.5 * 9.8 * 1.15²
1.15u = 30 - 12.96
u = 14.8 m/s
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Question 12 (1 point)
Football player Joe is running toward the opponent's goal line with the football, and slows down as he encounters the other team. If the opponent's goal line is the reference point, which of the following best describes his motion?
Question 12 options:
Negative Velocity, Positive Acceleration
Negative Velocity, Negative Acceleration
Positive Velocity, Positive Acceleration
Positive Velocity, Negative Acceleration
Answer:
d
Explanation:
I remember it was right
What is the angle of rotation (in degrees) between two hands of a clock if the radius of the clock is 0.70 m and the arc length separating the two hands is 1.0 m?
The angle of rotation (in degrees) between two hands of a clock if the radius of the clock is 0.70 and the arc length separating the two hands is 1.0 m is 81.8°.
What is the angle of rotation (in degrees) between two hands of a clock?The angle of rotation (in degrees) between two hands of a clock if the radius of the clock is 0.70 m and the arc length separating the two hands is 1.0 m is determined as follows:
Total angle in a clock = 360°
radius of the clock, r = 0.70
Circumference of the circle = 2πr
Length of the arc = 1.0 m
Angle that makes the arc length = θ
Length of arc, l = θ/360 * 2πr
Angle that makes the arc length, θ = l * 360/2πr
Angle that makes the arc length, θ = 1.0 * 360 * 7/ (2 * 22 * 0.7)
Angle that makes the arc length, θ = 81.8°
In conclusion, the angle of rotation (in degrees) between two hands of a clock if the radius of the clock is found from the length of the arc and the radius of the clock.
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Differentiate between velocity, acceleration, and deceleration. (I'm getting really desperate) help!!!!!!!!!!!!!!!!!!!!!!
(This is for my cyber physical education, i don't have physics yet but i couldn't find physical education in the pick a subject :/)
Velocity is the rate of change of displacement with time while acceleration refers to the rate of change of velocity with time.
Deceleration means the amount a speed or velocity decreases.
Velocity = displacement / time
Velocity is measured in m/s ( meters per second)
Acceleration = velocity / time and is measured in m/s2 ( meters per second square )
This also means that velocity differ from acceleration in that they have different unit as velocity is measured in m/s and acceleration is measured in m/s2
What is velocity?Velocity can simply be defined defined as the rate of change of velocity with time. It is a derived quantity. That is, a quantity which is obtained from the combination of one or more fundamental quantities. The units of derived quantities are called derived units.
So therefore, velocity is the rate of change of displacement with time while acceleration refers to the rate of change of velocity with time. Deceleration means the amount a speed or velocity decreases.
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Need help ASAP, thanks in advance
For each question, choose answer choice a-e and explain why you chose that answer.
The weight of the box is changed to 50 N.
The weight of the box is changed to 200 N.
The applied force is increased to 50 N.
The applied force is increased to 80 N.
The coefficient of static friction is increased to 0.7.
The coefficient of kinetic friction is increased to 0.5.
The coefficient of kinetic friction is increased to 0.5 and the coefficient of static friction is increased to 0.7.
The weight of the box is changed to 200 N and the coefficient of static friction is increased to 0.7.
The weight of the box is changed to 200 N and the coefficient of kinetic friction is increased to 0.5.
The weight of the box is changed to 200 N and the applied force is increased to 50 N.
Answer:
The Newton's Laws Review includes 60 questions of varying type. Questions pertain to Newton's three laws of motion with an emphasis on the following concepts: inertia, mass, force, the Newton, weight, gravity, free-body diagrams, normal force, tension, spring force, friction, coefficient of friction, force of gravity, net force, acceleration, free fall, acceleration of gravity, air resistance, and terminal velocity. All mathematical analyses are restricted to physical situations in which the object moves in one-dimension - usually either horizontally or vertically (but never both at the same time).
A bicyclist is traveling 10 m/s with an acceleration of 6 m/s?.
How fast is the bicyclist traveling at the end of 20 seconds?
v=u+at
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
From the question
u = 10 m/s
a = 6 m/s²
t = 20 s
Substitute the values into the above formula and solve
That's
v = 10 + 6(20)
= 10 + 120
We have the final answer as
130 m/s
What did the Nuremberg Laws do:
A. Kept Jews from being German citizens and marked them with a Star of David
B. Establish the policy of mass-murder against the Jews
C. Moved Jews from occupied countries to ghettos
D. Prevented Jews from being teachers or judges
A fast train has a speed of 181 km/hr. Because its wheels have a limited grip to the railway, the train must not accelerate at more than 0.058g (where g = 9.81 m/s2) while turning, or it will derail. What is the smallest radius of curvature for the track that the train can tolerate? If there is a curve of radius 1.100 km, what speed must the train mantain to keep the acceleration at the limit?
a. The the smallest radius of curvature for the track that the train can tolerate is 4.44 km
b. The speed must the train mantain to keep the acceleration at the limit is 25 m/s
a. What is the smallest radius of curvature for the track that the train can tolerate?Using the equation for centripetal acceleration, we find the radius of the circle the train can tolerate.
So, centripetal acceleration a = v²/r where
v = speed of train and r = radius of curvature of track.What is the radius of curvature of the track?Making r subject of the formula, we have
r = v²/a
Given that the train has a speed of 181 km/hr and its acceleration must not exceed 0.058g, we have that
v = 181 km/hr = 181 × 1000 m/3600 s = 50.28 m/s and a = 0.058g = 0.058 × 9.81 m/s² = 0.569 m/s²So, substituting the values of the variables into the equation for r,we have
r ≥ v²/a
r ≥ (50.28 m/s)²/0.569 m/s²
r ≥ 2528.0784 m²/s²/0.569 m/s²
r ≥ 4443.02 m
r ≥ 4.44 km
So, the the smallest radius of curvature for the track that the train can tolerate is 4.44 km
b. If there is a curve of radius 1.100 km, what speed must the train mantain to keep the acceleration at the limit?Using the equation for centripetal acceleration, we find the radius of the circle the train can tolerate.
So, centripetal acceleration a = v²/r where
v = speed of train and r = radius of curvature of track.What is the speed of the train?Making v subject of the formula, we have
v = √ar
Given that there is a curve of radius 1.100 km and its acceleration must not exceed 0.058g, we have that
r = 1.100 km = 1100 m and a = 0.058g = 0.058 × 9.81 m/s² = 0.569 m/s²So, substituting the values of the variables into the equation for r,we have
v = √ar
v = √(0.569 m/s² × 1100 m)
v = √(625.9 m²/s²)
v = 25.02 m/s
v ≅ 25 m/s
So, the speed must the train mantain to keep the acceleration at the limit is 25 m/s
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I’m curious to the differences between a rhetorical essay and a persuasive essay? Can anyone help out with a quick thorough answer?
Answer:
In a rhetorical essay you only analyze and cite 1 source in a persuasive essay you cite and analyze many different sources
Explanation:
A displacement is related to time as x=Asin(2πft).where A is a constant,t is the time and f is the frequency.Find the dimensions of A.
The dimension of the amplitude, A is L.
What is amplitude of a wave?The amplitude of a wave is the maximum displacement of the wave.
The amplitude of a wave is measured in the units of meters.
The given displacement of the light wave;
x = A sin(2πft)
where;
x is the displacement of the waveA is the amplitude of the wavef is frequency of the wavet is time of the wave's motionDimension of of amplitude, ASince amplitude of a wave measures the wave's displacement, then amplitude will have the same dimension as displacement.
A = meters = L
Thus, the dimension of the amplitude, A is L.
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If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
How to calculate the final velocity a moving object?From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.
It is expressed as;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Initial velocity u = 6m/sAcceleration a = 85m/s²Elapsed time t = 5sFinal velocity v = ?Plug the given values into the first equation of motion and solve for v.
v = u + at
v = 6m/s + ( 85m/s² × 5s )
v = 6m/s + 425ms/s²
v = 6m/s + 425m/s
v = 431m/s
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
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What is the change in the freezing point of water when 68.5 g of sucrose is
dissolved in 500.0 g of water?
Kf of water = -1.86°C/mol
molar mass sucrose = 342.30 g/mol
ivalue of sugar = 1
OA. -0.215°C
OB. 0.254°C
C. -0.744°C
D. 0.0186°C
SUBMIT
When 68.5 g of sucrose is dissolved in 500.0 g of water, the freezing point of the water decreases by -0.744°C.
The correct option is C.
What does freezing point mean?The temperature at which a liquid freezes is known as the freezing point. The freezing point normally rises with increased pressure, much like the melting point does. Combinations and some organic materials, such lipids, have freezing points that are lower than melting points.
Briefing:The following formula is used to determine the freezing point depression:
ΔT = i m
where ,
ΔT is the change in freezing point,
i is the van't Hoff factor,
is the freezing point depression constant, and
m is the molality of the solution.
It is given in the question that the
of water = -1.86°C/mol
molar mass sucrose = 342.30 g/mol
i value of sugar = 1
500.0 g of water and 68.5 g of sucrose are dissolved in it.
ΔT = 1 * -1.86° *m
molality = (68.5/342.3)/(500/1000)= 0.200116857/.5
m = 0.400
ΔT = 1 * -1.86° * 0.400
ΔT = - 0.744°C
The change in the freezing point of water when 68.5g of sucrose is dissolved in 500.0 g of water is - 0.744°C .
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The process of estimating values between measured data points is called
interpolation
extrapolation
parallax
Answer:
interpolation
Explanation:
I got it right on the test.
1.989 x 1030 kg 5.974 x 1024kg 1.5 x 1011 m.
Calculate the gravitational attraction
The Force of Gravitational Attraction is 34.85 ×10²¹N
Gravitational Force is the force acting between two masses separated by a distance. It is dependent on the magnitude of the masses and the distance between the two masses.
The mathematical relation is as follows:
F = Gm₁m₂/r²
where G is Gravitational Constant
m₁ is mass of first body
m₂ is mass of second body
r is the distance between the two masses
Given,
m₁ = 1.989×10³⁰
m₂ = 5.974×10²⁴
r = 1.5×10¹¹
G = 6.6×10⁻¹¹Nm²/kg²
On Substituting the above values,
F = 6.6×10⁻¹¹ × 5.974×10²⁴×1.989×10³⁰/(1.5×10¹¹)²
F = 34.85 ×10²¹N
Hence, the Force of Gravitational Attraction is 34.85 ×10²¹ N
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A Ford F150 can slow to a stop from 60 m/s in 2.44 seconds with an acceleration of -0.207 m/s2. What is the braking distance of the car?
The braking distance of the car, given the data from the question is 145.784 m
How to determine the braking distanceFrom the question given above, the following data were obtained:
Initial velocity (u) = 60 m/sTime (t) = 2.44 sAcceleration (a) = -0.207 m/s²Final velocity (v) = 0 m/Breaking distance (s) =?The breaking distance of the car can be obtained as illustrated below:
s = ut + ½at²
s = (60 × 2.44) + (½ × -0.207 × 2.44²)
s = 146.4 + (-0.616)
s = 146.4 - 0.616
s = 145.784 m
From the calculation made above, we can conclude that the breaking distance of the car is 145.784 m
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