For the diagram below, a siren is going off in the distance to the left. The
diagram shows the diffraction of the siren's sound wave around the wall. If
you were behind the wall (position labeled "X") what would you hear?
Sound waves
from source to
the left, rooving
to the right.
OA. You would not hear anything because there is no sound wave at
that position.
OB. You would not hear anything, because the wall would block the
sound of the siren.
OC. You would hear the siren, but the pitch would sound higher.
OD. You would hear the siren and think it was located at the opening in
the wall.

Create a graph with the x-axis indicating time and the y-axis showing distance (displacement from the top) (label axes and give units for each).

A line with an upward slope that progressively becomes steeper as it continues will be the one that fits the data the best. Avoid using straight lines to connect the graph's points.

This is further explained below.

Generally,  the equation for distance is  mathematically given as

d = ut + ½.at²

Therefore

For 1.0s

d = 0.5 x 9.80 x (1²)

d= 4.90 m

For 2.0s

d' = 0.5 x 9.80 x (2²)

d'= 19.60 m

For 3.0s, 4.0s, 5.0s Respectively

d'' = 44.10m

d''' = 78.40 m

d'''' = 122.50m

In conclusion, Draw a graph with the y-axis representing distance (displacement from the top) and the x-axis representing time (label axes and give units for each).

The line that provides the greatest fit will be an upwardly sloping line that gradually becomes steeper as it goes on. Do not connect the graph points with lines that are straight.

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Answer:

0.0917 m

Explanation:

Fnet = 0

Fb1 + Fb2 - mg = 0

ρ1V1g + ρ2V2g - mg = 0

(725)V1(9.8) + (1000)V2(9.8) = (6.70)(9.8)

7105V1 + 9800V2 = 65.7

Volume of cylinder = pi * r^2 * h = 8.48 * 10^-3 m^3

let x = percentage of volume in oil

V1 = (8.48 * 10^-3)x

V2 = (8.48 * 10^-3)(1-x)

7105(8.48 * 10^-3)x + 9800(8.48 * 10^-3)(1-x) = 65.7

x = 0.764

Height in oil = Total height * x = (0.120 m)(0.764)

Height in oil = 0.0917 m

The measurements are accurate but not precise.

Measurement is the basis for all scientific and technological developments. The measurement of any quantity is not perfect and there are always some uncertainties that cause errors in the measurements. While measuring anything we define the measurements in terms of precision and accuracy.

The accuracy of a measurement is a measure of how close the calculated value is to the true value. While precision tells to what resolution or limit the quantity is measured. For example, suppose the true value of a length is 10.578 cm. In the first case, the value comes out to be 10.4 cm. In the second case, the value comes out to be 10.378 cm. In the above example, the first value is accurate because it is close to the true value but the second value is precise because it contains more digits after the decimal.

Similarly, in the above case, a block with a known value of the volume of 15 cm^3 and the measurements are 14.6, 14.7, 14.7, 14.6 cm^3. As the values are close to the true value but they contain less number of digits after decimals, these values are accurate but not precise.

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Solar nebula is created when 99% of the gas and dust materials were gathered into the center of a flattened disc during the formation of the solar system.

The explosion of flattened disc created waves in space that compressed the cloud of gas and dust.  The cloud is all gravitationally bounded together.  

As the cloud continued to fall inward, the center eventually became so hot that it became a star, the Sun, and blew away most of the new solar system's gas and dust with a powerful stellar wind.

This squeeze caused the cloud to begin collapsing as gravity pulled the gas and dust together to form the solar nebula.

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The mass of the cannonball is 12.5 kg.

Force on cannonball = 2500N

Acceleration on cannonball= 200 m/s²

From, Newton's second law of motion

Force = Mass × Acceleration

Mass = [tex]\frac{Force}{Acceleration}[/tex] .......(i)

Now, putting the values in equation (i),

Mass = [tex]\frac{2500}{200}[/tex]

Mass = 12.5 kg

Thus, the mass of the cannonball is 12.5 kg.

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The current in the Primary coil of an ideal step-down transformer is 0.125A.

The transformer is a device that is used to change the value of alternating voltage from one value to another, according to the requirements. It is of two types namely, Step up transformer and Step-down Transformer.

If we assume that the efficiency of a transformer is 100 percent, then the power in the primary coil is equal to the power in the secondary coil.

Power is expressed as P=V×I

Where P is power, V is voltage, and I is current.

if the transformer is ideal then;

Output power = Input power

(V output)×(I output) = (V input)×(I input)

=> 30 = 240×(I input)

=> I input = 30/240 = 0.125 A

Thus, the current in the Primary coil of an ideal step-down transformer is 0.125A.

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Calcium Bromide, commonly known as calcium dibromide, is an ionic compound since the second element is a nonmetal, resulting in an ionic compound. It is referred to as a hydrated salt.

A chemical compound is a material made up of several similar molecules that include atoms from more than one chemical element and are kept together by chemical bonds. A molecule made up of only one element's atoms is hence not a compound.

A solution is a form of homogenous combination made of two or more components in chemistry. A solute in such a combination is a material that has been dissolved in another substance known as a solvent.

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Answer:

The Force

Explanation:

Gravitational Acceleration is the Acceleration of a free fall of a object.

Answer:

Because it has a limit of up to 80°C

Explanation:

Answer:8. How is 2D acceleration different from centripetal accele

a. It always acts in the same direction.

It is calculated with a different equation.

C.

It has x and y components but the acceleration is the same for each.

None of the above.

of 1D motion?

Explanation:

Answer:

θ = 1.22 λ / D

Above is the formula calculated for a circular aperature

If the wavelength is multiplied by 5 then the angle of resolution would be 5 times as great or 5 * θ

5 * θ = .5 seconds

For the given values, Other planet's mass is 2.81 x 10²⁶ m.

Planetary mass is a measurement of an object's mass in astronomy that resembles a planet. Planets in the Solar System are often measured using the astronomical system of units, where the Sun's mass, solar mass (M), serves as the unit of mass.

Given,

Other planet's radius (R) equals 7.40 x 10(7) m

M=0.028kg; string mass

L=4m for the string's length

Time on other planet (Tp) equals 0.0605 seconds

Earth time (Te) equals 0.0320 seconds.

Let's start by locating lead on Earth.

The formula for linear mass density is;

μ = M/L = 0.028/4 = 0.007 Kg/m

The equation for the wave's speed in this instance is Ve = L/t = 4/0.032 = 125 m/s.

The formula yields the spring's (Fe) tension;

Fe=(Ve)2=0.007 x 125 = 0.875 N

Newton's second law of motion, when applied to this earth lead, yields the following results:

Fy= Fe-Wl = 0

Fe = W as a result of Fe - W(l) = 0. (l)

Weight(W) equals Mg, as we know.

So, Fe = M(l)g.

Where g is the acceleration caused by gravity on earth, which is 9.81, and M(l) is the mass of the lead.

M(l) = Fe/g = 0.875/9.81 = 0.089kg as a result.

Let's compute the lead on the second planet using the same technique;

The characteristic of a substance that doesn't change is its linear density:

μ = 0.007 Kg/m

The equation for the wave's speed in this instance is Vp = L/t = 4/0.0605 = 66.11 m/s.

The formula yields the spring's (Fp) tension;

Fp = (Vp)2, which is 0.007 x 66.11² = 30.59 N.

Newton's second law of motion, when applied to this earth lead, yields the following results:

Fy=Fp-Wl = 0

Fe - W(l) = 0 and Fp = W as a result (l)

Weight(W) equals Mg, as we know (p)

Therefore, Fp = M(l)g (p)

where g(p) is the acceleration caused by the gravity of this other planet and M(l) is the mass of lead.

gp = Fp/M(l) = 30.59/0.089 = 343.70 m/s2 as a result.

According to the gravity equation, the planet's acceleration is given by the formula g = (GM)/r2.

M being the topic, we have;

(gr²)/G = M

G, with a value of 6.6742 x 10(-11) Nm2/kg2, is the gravitational constant.

Planet mass is M.

Planetary radius is r.

Thus;

M = [343.70 x (7.4 x 10^(7))²] / 6.6742 x 10^(-11)

Mass = 2.81 x 10^(26)m

You are exploring a newly discovered planet. The radius of the planet is 7.20 × 107 m. You suspend a lead weight from the lower end of a light string that is 4.00 m long and has mass 0.0280 kg. You measure that it takes 0.0685 s for a transverse pulse to travel from the lower end to the upper end of the string. On earth, for the same string and lead weight, it takes 0.0370 s for a transverse pulse to travel the length of the string. The weight of the string is small enough that its effect on the tension in the string can be neglected.

Part A

Assuming that the mass of the planet is distributed with spherical symmetry, what is its mass?

Express your answer with the appropriate units.

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The average velocity of the brady is 0m/s when he walks in given interval of time.

Average velocity is defined as the ratio of displacement to the time interval in which the displacement occur.

V = Δx/Δt

Where

V is average velocity

Δx is the displacement

Δt is the time interval

brady walks in north direction = 30 m

brady walks in the south direction = 30 m

displacement = 30m - 30m

Δx=0m

Brady's displacement is 0 meters to the right of where he started.

Δt = 60 sec

average velocity is given as

V = Δx/Δt

0/60 = 0m/s

The average velocity of the brady is 0m/s when he walks in given interval of time.

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Time taken by the boat to accelerate is 1 min 4 s.

V[tex]f_{2}[/tex] - V[tex]o_{2}[/tex] = 2 a X ,

a = Vf2 - Vo2 / 2 X

= (26 m/s)2 -(13m/s)2 /  2(1250m)

= 507 m2/s2 / 2.5 m = 0.203 m/s2

Solve for time using the equation with acceleration known.

Vf = at + Vo ,

t = Vf - Vo / a = 26m/s -13m/s/ 0.203 m/s2

  = 64 s

  = 1 min 4 s

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The pressure is 107417976.4 N[tex]m^{-2}[/tex].

The pressure of water at a given height/ depth can be determined by:

Pressure = σhg

Where: σ is the density of water, h is the height/ depth, and g is the gravitational force.

Given that; h = 10994 m, but σ = 997 kg/[tex]m^{3}[/tex] and g = 9.8 m/[tex]s^{2}[/tex]

Thus, the pressure of water at the deepest part of the ocean will be:

Pressure = 997 x 10994 x 9.8

              = 997 x 107741.2

              = 107417976.4

Pressure  = 107 420 KN [tex]m^{-2}[/tex]

In order to measure an object's surface tension, a force must be applied perpendicularly to the object's surface over a given area. Gauge pressure is the amount of pressure in relation to the surrounding pressure. Pressure is expressed using a number of different units.

In relation to an object's surface, pressure is the amount of force per unit area that is applied perpendicularly. P, or "p," serves as its symbol.

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The distance between Ricardo and Jane :

a) 24.33 m of distance.

b) 34.55° east of the south.

Evaluating the equation given :

Now that we all know what we need to do in this question, let's head for each part of the problem.

a) Distance between Ricardo and Jane

In this case, we'd like to analyze the given data:

Ricardo (which we'll call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 13 m at 30° south of west. therefore the distance between them, are going to be the point where they both stop and face each other.

Let's call the space between them as "D", to urge the distance of D, consistent with the picture will be:

D = J - R (1)

However, as they're facing in different angles and directions, we cannot do the difference of their values distance a bit like that. so as to do that, we'd like to calculate the components in the "x" and "y" axis of each vector. therein way, we will get the components of x and y of the Distance D, and then, the full distance between them will be:

                            D = √Dx² + Dy² (2)

So, let's get the components of x and y of R and J.

For Ricardo (R):

                              Rx = R sin60° = 28 sin60°

                                     = -24.25 m

                       Ry = R cos60° = 28 cos60°

                                    = 14 m

The sign "-" it's because R it's on the second quadrant, therefore in x, we'll need to add the negative.

                          For Jane (J):

                            Jx = J cos30° = 13 cos30°

                                      = -10.39 m

                        Jy = J sin30° = 13 sin30°

                                           = -6.5 m

Again, the negative is added because J is on the third quadrant.

Now that we've the components, let's calculate vector D using expression (1):

                                Dx = -10.39 - (-24.25) = 13.86 m

                                      Dy = -6.5 - 14 = -20.5 m

Now, using expression (2) we will finally know the distance between Jane And Ricardo:

                                      D = √(-20)² + (13.86)²

                                                     D = 24.33 m

This is the distance between Jane and Ricardo.

b) Direction of Ricardo walking to Jane

In this case, we have already got the components of x and y of the distance between them, so, to understand the direction:

                                         Tanα = Dy/Dx

                                          α = tan⁻¹ (Dy/Dx)

Replacing the values we have:

                                              α = tan⁻¹ (-20/13.86)

                                               α = 55.45°

Which should south of east or:

                                               β = 90 - 55.45

                                                β = 34.55°

Ricardo should walk 34.55° east of south

The question is incomplete. the full exercise is the following:

"Ricardo and Jane are standing under a tree within the middle of a pasture. An argument ensues, and that they walk away in different directions. Ricardo walks 28.0 m during a direction 60.0° west of north. Jane walks 12.0 m during a direction 30.0° south of west. They then stop and switch to face each other.

(a) what's the distance between them?

(b) In what direction should Ricardo walk to travel directly toward Jane?"

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The answer is 150j.

What is the work done by this force in moving the body through a distance of 10m along the y-axis?

According to the question:

Vector Force F=2i+15j+6k Newtons,

where the i,j,k are the unit of the vector along axes.

Where,

s=displacement

=10j meters

Work done (W)=F.s

=(2i+15j+6k).10j

=20i.j+150j.j+60k.j

=150j

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The density of ceramic statue was found to be 2500kg/m³

First we calculate amount of water displayed

=  28.4 - 17.0 = 11.4N of water displaced.

Now, we calculate the volume of water displayed ,

Volume=water displaced /gravity

=11.4/9.8

Volume = 1.16kg of water.

we know that, density of water = 1000kg/m³

so, density of 1.16 kg= 1.16 x10^-3 m^3

mass of ceramic statue= 28.4 N/9.81 kg = 2.90 kg.

At last we calculate, density of ceramic statue by,

density of ceramic statue = ceramic mass/ density of water

= 2.90/(1.16 x 10^3) = 2500kg/m³

Thus, the density of ceramic statue is found to be 25kg/m³.

The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. Density Formula = m/V, where is the density, m is the object’s mass, and V is its volume. Density Symbol: D

If you are mixing a immiscible liquid in water, then if the density of the liquid sample is less than density of water then it it’s floats on upper surface .

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Answer:

While waves that travel within the depths of the ocean are longitudinal waves, the waves that travel along the surface of the oceans are referred to as surface waves. A surface wave is a wave in which particles of the medium undergo a circular motion.

Explanation:

Are you satisfied or I should continue in the comments.

Distance = Displacement = 8 meters.

While a person's displacement is equal to the shortest path taken, their total distance travelled is equal to their whole trip.

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The running time of Gone in hour and minutes is determined as 1 hour, 2 minutes.

Time conversion is the process by which the unit of time is converted from one form to another.

For example, time can be converted in the following units;

The following conversion factors is used to convert time from one unit to another;

3600 seconds = 1 hour

60 minutes = 1 hour

60 seconds = 1 minute

To convert the running time of Gone to hours and minutes;

3720 seconds = 3600 seconds + 120 seconds

recall 3600 seconds = 1 hour

120 seconds = 120 s/60 s = 2 minutes

3720 seconds = 1 hour, 2 minutes

Thus, the running time of Gone in hour and minutes is determined as 1 hour, 2 minutes.

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The complete question is below;

The running time of Gone is 3720 seconds.  Convert the running time of Gone With the Wind to hours and minutes.

The acceleration is aₓ = 7.54 m/s².

The rate at which an item changes its velocity is known as the vector quantity known as acceleration.

When an object's velocity changes, it is said to be accelerating.

uₓ(t) = (0.980 m/s³) t²

The time-dependent derivative of velocity is acceleration.

aₓ(t) = 2 (0.980 m/s³) t

aₓ(t) = (1.96 m/s³) t

When,

uₓ = 14.5 m/s, the time is:

14.5 m/s = (0.980 m/s³) t²

t = 3.85 s

Connecting to the acceleration equation,

aₓ = (1.96 m/s³) (3.85 s)

aₓ = 7.54 m/s²

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Answer:

323 m.

Explanation:

The frequency is 640 kHz.

(wavelength) = =

We will now change 640KHz to Hz. This is attainable as follows:

1 KHz = 1000 Hz

Therefore,

640 KHz is equal to 640 KHz 1000 Hz / 1 KHz.

640 kHz = 64×10⁴ Hz

As a result, 640KHz is equal to 64025 Hz.

The following equation connects a wave's wavelength () and frequency (f):

Wavelength x Frequency = Velocity

v = λf

The radio wave wavelength can be calculated using the formula above as follows:

Frequency (f) equals 64 to 104 Hz

The electromagnetic wave's (v) speed is 3 x 108 m/s.

(wavelength) = =

v = λf

3×10⁸ = λ × 64×10⁴

By 64025, divide both sides.

λ = 3×10⁸ / 64×10⁴

λ = 487m

Consequently, the radio wave's wavelength is 487 m.

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The displacement of the horse is 38.4 m/s.

Given :

velocity of the horse = 3.2 m/s

The time that the horse

displacement of the horse =?

According to the formula,

velocity = displacement/time

we can get the value of displacement.

That is, displacement = velocity×time

Substituting the values of velocity and time, we get

displacement = 3.2 × 12 m

That is, displacement = 38.4 m

Hence, the displacement of the horse is 38.4 m/s.

It measures the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement. The final location of a point relative to its beginning position xi, or a relative position (derived from the motion), is another way to express a displacement. The difference between the end and beginning positions can be used to define the equivalent displacement vector:

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The magnitude of the force that one particle exerts on the other particle is 68.6 N.

The charge of the first particle is q1.

[tex]q _{1}= - 3.77 \times 10 ^{ - 6} \: C[/tex]

The charge on the second particle is q2.

[tex]q _{2}= 6.91\times 10 ^{ - 6} \: C[/tex]

The distance between the two charged particles is d.

d = 0.0584

The magnitude of the force that one particle exerts on another particle is,

[tex]F= k \frac{q _{1} q _{2}}{(d) ^{2} }[/tex]

[tex]F=9 \times 10 ^{9} \times \frac{ - 3.77 \times 10 ^{ - 6} \times 6.91 \times ^{ - 6} }{(0.0584) ^{2} } [/tex]

F = 68.6 Newton

Therefore, the magnitude of the force that one particle exerts on another particle is 68.6 N.

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The time taken for the car to cover the distance of 125 m is 5 seconds

From the question given above, the following data were obtained:

The time taken for the car to cover the 125 m distance can be obtained as illustrated below:

s = (u + v)t / 2

125 = [(10 + 40) × t] / 2

125 = (50 × t) / 2

Cross multiply

50 × t = 125 × 2

50 × t = 250

Divide both sides by 50

t = 250 / 50

t = 5 s

Thus, the time taken by the car to cover the 125 m distance is 5 seconds

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You have found that tides on earth are determined primarily by the position of the moon, with the sun playing only a secondary role. The moon play a greater role in causing tides than the sun, because of the Sun's higher gravitational pull on Earth, the planet revolves around it. Tides, on the other hand, are brought on by variations in the gravitational pull on Earth.

Despite the fact that the gravitational pull between Earth and the Moon is weaker than the attraction between Earth and the Sun, the Moon's considerably closer proximity to Earth causes this attraction to fluctuate more widely throughout the planet.

Because of this, the Sun only has a little secondary effect on tides, which are predominantly caused by the Moon.

Stars are celestial bodies that generate their own energy through the fusing of gases. They resemble bright orbs that burn gas and produce energy. Our solar system's star, the Sun, generates energy through the fusion reaction in which helium transforms into hydrogen.

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The complete question is ''You have found that tides on Earth are determined primarily by the position of the Moon, with the Sun playing only a secondary role. Why does the Moon play a greater role in causing tides than the Sun?- Because the gravitational attraction between Earth and the Moon varies more across Earth than does the gravitational attraction between Earth and the Sun

Answer:

The direction in which this object travels might be changing.

Explanation:

Velocity is a vector quantity. In addition to the rate at which this object moves, velocity also measures the direction of the motion.

In contrast, speed is a scalar quantity. The speed of an object also measure the rate at which this object moves. However, unlike velocity, speed does not account for the direction of the motion.

Hence, even if speed is constant, velocity of this object might not be constant as long as the direction of the motion is changing.

For example, consider an object moving around a circle at a constant rate. The speed of this object will be constant since the rate of the motion is constant. However, the velocity of this object will not be constant since the object needs to keep changing its direction to stay on the track.