help pleaseeeeeeeeeee ty

The steps for constructing the bisector of an angle by using a ruler and compasses are as follows:

Step 1:

Take a compass and place its point on the angle's vertex Q.

Step 2:

Adjust the compass to the medium wide setting. The exact width is not important.

Step 3:

Without changing the compasses' width, draw an arc across each leg of the angle.

Step 4:

Now, place the compass on the point where one arc crosses a leg and draw the arc in the interior of the angle.

Step 5:

Without changing the compass setting repeat for the other leg so that the two arcs cross.

Step 6:

Now by using a ruler draw a line from the vertex to the point where the arcs cross.

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The statement that explains whether Juliana is correct is A. She is correct because she can multiply 6 and 10 by any number to form an equivalent ratio.

From the information, it should be noted that

Juliana says that she can use the patterns of equivalent ratios in the multiplication table below to write an infinite number of ratios that are equivalent to 6:10.

It should be noted that she is correct because she can multiply 6 and 10 by any number to form an equivalent ratio.

An example is (6 × 2)/(10 × 2) = 12/20

It should be noted that 6/10 is equivalent to 12/20.

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ΔJKL is congruent to ΔPQR. This statement is true.

Two figures are congruent if they have the same area and one figure is an exact image of the other.

Two triangles can be proven congruent by 4 axioms or rules.

Given: in triangles ΔJKL and ΔPQR:

Hence by AAS axiom of congruency triangles are congruent.

ΔJKL ≅ ΔPQR

The statement is true.

Disclaimer: The complete question is : In ΔJKL and ΔPQR, if JK= PQ, ∠J=∠P, and ∠K =∠Q, then ΔJKL must be congruent to ΔPQR.

True or False

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The annual premium of Tom Harris is $29.05

Annual premium is the amount of money that policyholder has to pay in a policy year.

Annual formula = (face value of policy per $1000)* (rate of insurance)

Given that Tom Harris is twenty four years old man want to purchase a $7000 for a ten year term insurance.

From the given table we can say that the rate of insurance for a 24 year old man per $1000 for a 10 year terms is 4.15

Face value of insurance = $7000

Face value of insurance per $1000 = 7000/1000 =$7

Then the annual premium = $7 * 4.15 =$ 29.05

Therefore, the annul premium paid by Tom Harris is $29.05

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Answer: 50 1/4

Step-by-step explanation:

Answer:

Step 1: 20

Step 2: 40

Step 3: 45

Step 4: 90

Step 5: 84

Step 6: 21

Step 7: 1

I did get 1 by following the steps.

The first five terms of the sequence area s follows:

4, 6 , 8 , 10, 12

Each term of the sequence is 2 more than the previous term.

The third term is 8.

The sequence is an arithmetic sequence base on the difference.

Using arithmetic sequence formula,

aₙ = a + (n - 1)d

where

Therefore, let's used the third term to find the first term.

8 = a + 2d

8 = a + 2(2)

8 = a + 4

a = 8 - 4

a = 4

Therefore, the first term of the sequence is 4.

Hence, the first five terms of the sequence area s follows:

4, 6 , 8 , 10, 12

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The margin of error is 3.083 min

Margin of Error: The margin of error is the range of error permitted around the sample statistic in order to estimate the population parameter. The margin of error indicates the size of the confidence interval. The breadth of the confidence interval increases with the margin of error.

Sample size, n=24

Sample mean, ¯x=31.5 min

Sample standard deviation, s=7.3 min

Confidence level, c=95%

=0.95

From the given information we can calculate the below-required quantities,

Significance level, α=1−c=1−0.95=0.05

Degrees of freedom, DOF=n−1

=24−1

=23

Now from the t-distribution table,

The value of t (α2, DOF) is,

t (0.025,23) = 2.069  

Hence the margin of error will be,

MOE= t (α2, DOF) × s/√ n

=2.069×7.3/√24

=3.083 min

i. The upper limit of the confidence interval will be,

UL=¯x + MOE=31.5+3.083=34.583

The lower limit of the confidence interval will be,

LL=¯x−MOE

=31.5−3.083

=28.417

Hence, the 95% confidence interval is (28.417,34.583)

(28.417,34.583)

The answer is 28.417,34.583

ii. The required answer is MOE=3.083 min

ii. We have found the 95% confidence interval for the population mean to be (28.417,34.583). This means with 95 % confidence; it can be said that the population mean commute time is between the bounds of the confidence interval.

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Answer:

the answer will be (-1, -6.5)

Step-by-step explanation:

The midpoint formula is [tex](\frac{x^1 + x^2}{2} , \frac{y^1 + y^2}{2} )[/tex]

so you would do [tex](\frac{2 - 4)}{2} , \frac{-9-4}{2} )[/tex] , the only reason it is subtracting is that a positive and a negative make a negative so you might as well subtract, either way, if you insert the equation by doing 2 + (-4) you will get the same thing

then you would just do the math and get your answer

Hope this helps :)

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{2}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-4}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -4 +2}{2}~~~ ,~~~ \cfrac{ -4 -9}{2} \right) \implies \left(\cfrac{ -2 }{2}~~~ ,~~~ \cfrac{ -13 }{2} \right)\implies \left(-1~~,~~-6\frac{1}{2} \right)[/tex]

Answer:

16<24

Step-by-step explanation:

4+(4×3)<(12×2)

4+12<24

=16<24

Answer:

the first one is D. {3/2}

second one is C. {-10}

Step-by-step explanation:

hope this helps

Answer:

3.5 in decimal form or 3 1/5

Step-by-step explanation:

Answer:

= - 1 1/6

Step-by-step explanation:

1 1/2 - 2 1/3

= 1 2/6 - 2 3/6

= 8/6 - 15/6

= - 7/6

= - 1 1/6

The length of the rectangle = 21 cm

and the width of the rectangle = 19 cm

In this question, the length and width of a rectangle are consecutive odd integers.

Let n, n + 2 be the width and the length of a rectangle.

The perimeter of the rectangle is 80 centimeters.

Using the formula of the perimeter of the rectangle ,

P = 2 × [n + (n + 2)]

80 =  2(2n + 2)

40 = 2(n + 1)

20 = n + 1

n = 19

This means, the width of the rectangle is 19 centimeters.

And the length = n + 2

                         = 19 + 2

                         = 21 cm

Therefore, the length of the rectangle = 21 cm

and the width of the rectangle = 19 cm

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Answer:

Vertex=(-3,6) and Y intercept is 15/(0,15)

The values of x that will make x² = 9 are positive 3 and negative 3.

A quadratic equation is an algebraic equation that has highest degree of 2, therefore, it also has two roots or we can say it has two solutions.

We know sign distributions that negative distributed to a negative is positive and positive distributed to a positive also results in positive.

∴ 9 can be obtained by either multiplying (-3)(-3) or (3)(3).

So, the value of x that will make x² = 9 is

x = ± √9

x = ± 3.

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Answer:

Step-by-step explanation:

The reason why you should save money because if you spend all of your money you won't able to take care of yourself, your house, or have nothing to do

(4,5) i'm pretty sure I can't explain why but just go with it

Answer:

x = 12

Step-by-step explanation:

First, distribute the 3 into the parentheses:

3(x-2) = 2x+6 ----> 3x-6 = 2x+6

Next, combine like terms by adding 6 to both sides of the equation:

3x-6 = 2x+6 ----> 3x = 2x+12

Then, subtract 2x from both sides:

3x = 2x+12 ----> 1x = 12

Finally, divide both sides by 1 to get x by itself:

x = 12

The statement [tex]\begin{aligned} \lim_{x \rightarrow b} f(x)=1 \end{aligned}[/tex] will be true. Then the correct option is D.

The value that approaches the output for the given input value. Limits are a very important tool in calculus.

The graph of the function is shown below.

The function is a piecewise function. The function is continuous between o to a, a to b, and b to till ∞.

The value of the function at b will be 1 which can be shown as,

[tex]\begin{aligned} \lim_{x \rightarrow b} f(x)=1 \end{aligned}[/tex]

The statement [tex]\begin{aligned} \lim_{x \rightarrow b} f(x)=1 \end{aligned}[/tex] will be true. Then the correct option is D.

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The estimate of the product is reasonable

The product expression is given as

759 x 68

As an estimate, we have

759 - 760

68 = 70

So, we have:

759 x 68 = 760 * 70

Evaluate the product

759 x 68 = 53200

For the actual product, we have

759 x 68 = 51612

The estimate and the actual product both approximate to 50000

Hence, the estimate of the product is reasonable

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The evaluated value of [tex]log_{7}30[/tex] is 1.748

Change of base formula is used to change the base of the logarithm. It is used to write a logarithm of a number with a given base as the ratio of two logarithms each with the same base that is different from the base of the original logarithm.

According to the change of base formula:

       [tex]log_{a}b = \frac{log_{x}b }{log_{x} a}[/tex]

where base x is considered base 10

According to the question, we have to find the value of [tex]log_{7} 30[/tex]

Thus applying change of base formula we get

    [tex]log_{7} 30 = \frac{log_{10} 30}{log_{10} 7}[/tex]

calculating the value of log from the calculator we get,

        [tex]log_{7} 30 = \frac{1.477}{0.845}[/tex]

        [tex]log_{7} 30 = 1.748[/tex]

Thus evaluated value of [tex]log_{7}30[/tex]  is 1.748

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The distance of both the planes from the starting point will be  1029 miles.

This is a question of time, speed and distance.

Given that:-

Speed of jet plane = 480 mph

Speed of propeller plane = 200 mph

Also, the propeller plane has a 3 hour head start.

We have to find the distance of both the planes from the starting point.

When the jet plane overtakes the propeller plane both of them would have covered the same distance.

Let the time taken by the jet plane to overtake the propeller plane be t hours.

Hence, the propeller plane would have travelled for (t+3) hours.

Hence, we can write,

480*t = 200*(t+3)

480t = 200t + 600

280t = 600

t = 600/280 = 15/7 hours.

Hence, distance from both the planes from the starting point = (15/7)*480 = 1028.57 miles = 1029 miles.

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Answer:

The length of UV is 10 units.

Step-by-step explanation:

It is given that the points T, U, V and W all lie on the same line segment, in that order, such that the ratio of TU:UV:VW is equal to 1:5:2.

Now, we need to calculate UW if TW = 32.

So, TU : UV : VW = 2 : 5 : 5

=> TW = 24

From the above conditions it can be observed that;

=> Ratio of TU = 2

=> Ratio of UV = 5

=> Ratio of VW = 5

Firstly, we have to sum up the total ratio that is;

=> Total = Ratio of TU + Ratio of UV + Ratio of VW

=> Total = 2 + 5 + 5

=> Total = 12

Now, we need to calculate the length of UV from which we get;

=> UV = 5/12 * 24

=> UV = 10

Therefore; length of UV is 10 units.

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After solving, the factors of equation x²-5x+6 are:

So,

Given the equation: x²-5x+6

Then,

Factors are: (x-3) and (x-2)

Therefore, after solving, the factors of equation x²-5x+6 are:

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Answer:

[tex]\frac{3}{22}[/tex]

Step-by-step explanation:

To multiply fractions, just multiply the numerators (tops) times each other and the denominators (bottoms) times each other:

[tex]\frac{-1}{4}[/tex] x [tex]\frac{-6}{11}[/tex] = [tex]\frac{6}{44}[/tex]

Now all we have to do is to simplify.  In this case, just find the largest number that goes evenly into the numerator and the denominator: it is 2.  Divide numerator and denominator by 2 to get the final answer: [tex]\frac{3}{22}[/tex]

Answer:

[tex] \sqrt[5]{x } = - 2 = - 35[/tex]

Algebra is one of the broad areas of mathematics. Roughly speaking, algebra is the study of mathematical symbols and the rules for manipulating these symbols in formulas; it is a unifying thread of almost all of mathematics.

To solve an algebraic word problem:

Define a variable.

Write an equation using the variable.

Solve the equation.

If the variable is not the answer to the word problem, use the variable to calculate the answer.

To know about algebra you have to know about your Arithmetic.

Remember PEMDAS.

Get Positively Comfortable with Negative Numbers.

Show Your Work.

Don't Let the Letters Scare You.

Formulas Are Your Friends.

Be Sure to Answer the Right Question.

Work Practice Problems.

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A real coefficient quadratic equation cannot have one real root and one imaginary root.

Therefore, a real coefficient quadratic equation cannot have one real root and one imaginary root.

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