How many hours are in a full day and night? I have been told 24 hrs but is that right?

Answer:

book resting on a shelf has no potential energy relative to the shelf since it has a height of zero meters relative to the shelf. However, if the book is elevated to some height above the shelf, then it has potential energy proportional to the height at which it resides above the shelf.

An object can have both kinetic and potential energy at the same time. For example, an object which is falling, but has not yet reached the ground has kinetic energy because it is moving downwards, and potential energy because it is able to move downwards even further than it already has. The sum of an object's potential and kinetic energies is called the object's mechanical energy.

As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.

Another important concept is work.

The question is incomplete. Here is the complete question.

The image below was taken with a camera that can shoot anywhere between one and two frames per second. A continuous series of photos was combined  for this image, so the cars you see are in fact the same car, but photographed at differene times.

Let's assume that the camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive?

Answer: v = 6.5 m/s

Explanation: The question asks for velocity of the car. Velocity is given by:

[tex]v=\frac{\Delta x}{\Delta t}[/tex]

The camera took 7 pictures of the car and knowing its length is 5.3, the car's displacement was:

Δx = 7(5.3)

Δx = 37.1 m

The camera delivers 1.3 frames per second and it was taken 7 photos, so time the car drove was:

1.3 frames = 1 s

7 frames = Δt

Δt = 5.4 s

Then, the car was driving:

[tex]v=\frac{37.1}{5.4}[/tex]

v = 6.87 m/s

The car drove at, approximately, a velocity of 6.87 m/s

The velocity of the car will be 6.5 m/s.The rate of change of displacement is defined as speed.

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

t is the time for camera deliver= 1.3 frames per second

l is the  length = 5.3 meters

The instantaneous velocity is given as;

[tex]\rm v = \frac{\triangle x }{\triangle t } \\\\ \rm \triangle x = 7 \times 5.3 \\\\ \rm \triangle x = 37.1 m[/tex]

The time engaged is find as;

1.3 frames = 1 s

[tex]\rm \triangle t= 7 \ frames \\\\ \rm \triangle t=5.4 sec[/tex]

Hence the velocity of the car driving;

[tex]\rm v= \frac{37.1}{5.4} \\\\ \rm v= 6.87 m/sec[/tex]

Hence the velocity of the car will be  6.5 m/s.

To learn more abouty the velocity refe to the link;

https://brainly.com/question/862972

Answer:

The pressure exerted by the brick on the table is 18,933.3 N/m².

Explanation:

Given;

height of the brick, h = 0.1 m

density of the brick, ρ = 19,300 kg/m³

acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

P = ρgh

P = (19,300)(9.81)(0.1)

P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².

Answer:

R = 1.8 m

Explanation:

This is a simple harmonic movement exercise, at the bottom of the swing the acceleration is vertical upwards and the speed is tangential to the trajectory, that is horizontal; the expression for the centralized acceleration is

              [tex]a_{c}[/tex] = v² / R

              R = v² /a_{c}

where the radius is equal to the length of the swing

let's calculate

            R = 8.1 / 4.5

            R = 1.8 m

Answer:

To calculate the absolute pressure we used the depth as 2 m instead of 2 mm because the given dimensions for the swimming pool do not make sense (they are too small).  

The absolute pressure on the bottom of a swimming pool is 1.21x10⁵ Pa.

Explanation:

The absolute pressure is given by:

[tex]P_{A} = P_{g} + P_{atm}[/tex]

Where:

[tex]P_{g}[/tex]: is the gauge pressure

[tex]P_{atm}[/tex]: is the atmospheric pressure = 1 atm = 101325 Pa

The gauge pressure can be found as follows:

[tex]P_{g} = \rho gh[/tex]

Where:

ρ: is the density of water = 1000 kg/m³

g: is the gravity = 9.81 m/s²

h: is the height or the depth

Since the given dimensions in the statement for the swimming pool do not make sense (they should be in meters instead of millimeters), we will use h = 2 m.

[tex]P_{g} = \rho gh = 1000 kg/m^{3}*9.81 m/s^{2}*2.0 m = 19620 Pa[/tex]

Hence, the absolute pressure is:

[tex]P_{A} = P_{g} + P_{atm} = 19620 Pa + 101325 Pa = 120945 Pa = 1.21 \cdot 10^{5} Pa[/tex]        

Therefore, the absolute pressure on the bottom of a swimming pool is 1.21x10⁵ Pa.

I hope it helps you!                                                  

Answer:

A. Momentum of the grizzly bear is 3241.56 Kgm/s

B. The human will run at 28.56 m/s

Explanation:

A. Determination of the momentum of the grizzly bear.

Mass of grizzly bear = 420 lb

Velocity of grizzly bear = 17 m/s

momentum of the grizzly bear =?

Next, we shall convert 420 lb to Kg. This can be obtained as follow:

1 lb = 0.454 kg

Therefore,

420 lb = 420 lb × 0.454 Kg / 1 lb

420 lb = 190.68 Kg

Thus, 420 lb is equivalent to 190.68 Kg

Finally, we shall determine the momentum of the grizzly bear as follow:

Mass of grizzly bear = 190.68 Kg

Velocity of grizzly bear = 17 m/s

momentum of the grizzly bear =?

Momentum = mass × velocity

Momentum = 190.68 × 17

Momentum = 3241.56 Kgm/s

Thus, the momentum of the grizzly bear is 3241.56 Kgm/s

B. Determination of how fast the human will run.

Mass of human = 250 lb

Momentum of human = momentum of the grizzly bear

Momentum of the grizzly bear is 3241.56 Kgm/s

Momentum of human = 3241.56 Kgm/s

Velocity of human =?

Next, we shall convert 250 lb to Kg. This can be obtained as follow:

1 lb = 0.454 kg

Therefore,

250 lb = 250 lb × 0.454 Kg / 1 lb

250 lb = 113.5 Kg

Thus, 250 lb is equivalent to 113.5 Kg

Finally, we shall determine how fast the human will run as follow:

Mass of human = 113.5 Kg

Momentum of human = 3241.56 Kgm/s

Velocity of human =?

Momentum = mass × velocity

3241.56 = 113.5 × velocity

Divide both side by 113.5

Velocity = 3241.56 / 113.5

Velocity = 28.56 m/s

Therefore, the human will run at 28.56 m/s to match the momentum of the grizzly bear

2 conditioner are

Explanation:

force applied and displacement produced

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

Answer:

60%

Explanation:

The force applies an acceleration in the reverse direction of

29 N = (0.145 kg) a   →   a = 200 m/s²

and in order to hit the ball back with speed 40.0 m/s, this acceleration is applied over time t such that

200 m/s² = (40.0 m/s - (-40.0 m/s)) / t   →   t = (80.0 m/s) / (200 m/s²) = 0.4 s

Answer:

The tangential force will act as a torque on the body, increasing its angular velocity and thus also increasing its kinetic energy. By the work-kinetic-energy theorem, work has been done on the body. Yes, in non-uniform circular motion the work done on the object is non-zero, for the reason you stated.

Explanation:

Answer:

2.is the most massive object in the system, and less massive objects orbit more massive objects

is considered as a single focus by the objects describing elliptical paths about the sun.

Answer:

Mechanical advantage = 3

Explanation:

Given:

Weight = 300 N

Force load = 100 N

Find:

Mechanical advantage:

Computation:

Mechanical advantage = Weight/Force Load

Mechanical advantage = 300/100

Mechanical advantage = 3

Mechanical advantage is the ratio of output force to the input force.It is also used to find the efficiency of the system.The value of mechanical advantage is 3.

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtained efficiency of  forces in levers and pulley.

It is an effective way of amplify the force in simple machines like lever  The theoretical mechanical advantage is defined as ratio of the force responsible for he useful work in system  to the applied force.

The theoretical value may be grater than the actual value of mechanical advantage because in the theoretical mechanical advantage friction is assumed to be absent.

The given data in the problem is;

weight that lifted (output)=300

Effort force(input) =100

Mathematically it is given as;

[tex]\rm M A= \frac{F_O}{F_I} \\\\\rm M A= \frac{300}{100}\\\\\rm M A=3[/tex]

Hence the value of mechanical advantage is 3.

Learn more about the mechanical advantage refer to the link;

https://brainly.com/question/7638820?referrer=searchResults

Answer:

The common speed is 1.95 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states that the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of all of them:

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

If a collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum

is written as:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

If both masses stick together after the collision at a common speed v', then:

[tex]m_1v_1+m_2v_2=(m_1+m_2)v'[/tex]

The common velocity after this situation is:

[tex]\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}[/tex]

The truck of m1=1200 N (weight) travels at v1=2 m/s and hits a stationary mass (v2=0) of m2=30 N (weight). After the bodies collide, they keep moving together. Before we can calculate the common speed, we need to calculate the masses of the bodies, since they are given as weights.

[tex]m_1=\frac{P_1}{g}=\frac{1200}{9.8}=122.45 Kg[/tex]

[tex]m_2=\frac{P_2}{g}=\frac{30}{9.8}=3.06 Kg[/tex]

Now calculate the common speed:

[tex]\displaystyle v'=\frac{122.45 * 2+3.06 * 0}{122.45+3.06}[/tex]

[tex]\displaystyle v'=\frac{244.9}{125.51}=1.95\ m/s[/tex]

The common speed is 1.95 m/s

Explanation:

Sun— Nuclear energy is converted to heat and light energy

Corn absorbs sunlight in order to produce sugars and oxygen for plant growth.

Corn is fermented to produce ethanol, which is burned to power generators to give an electrical current The speaker takes the electrical current and produces sound.

Answer:

sun, corn, corn, speaker

Explanation:

i took the k-12 test! have an amazing day! XX <3

Answer:

The free end of the blade has a tangential velocity of about 88.19 m/s

Explanation:

The angular velocity of the blades is  [tex]2 \pi /5.7\,\,rad/sec[/tex]

since the blades are 80 m long, then the tangential velocity of the free end of the blade is:

[tex]v_{tan} \approx 88.19\,\,m/s[/tex]

Answer:

A) conductors

Explanation:

A conductor can be defined as any material or object that allows the free flow of current or electrons (charge) in one or more directions in an electrical circuit. Some examples of a conductor are metals, tungsten, copper, aluminum, iron, graphite, etc.

Basically, the main purpose of a conductor in physics is to provide a low-resistance path between electrical circuits or components. This low-resistance path is to ensure that the electrical components allows the free flow of electrons and thus, enabling charge transfer.

Hence, the electrons in conductors move about more freely than the electrons in insulators which is why this type of material can be used to create electric circuits because it would significantly provide a low-resistance path between the electric circuits.

Answer:

The mountain is 403 m tall

Explanation:

Horizontal Launch

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

It's given that if a ball is kicked from the top of the Sugarloaf Mountain, it will land near its base without hitting the side. The initial speed is v=9.37 m/s and it reaches a horizontal distance of d=85 m. Solving the equation for h:

[tex]\displaystyle h=\frac{d^2g}{2v^2}[/tex]

Substituting:

[tex]\displaystyle h=\frac{85^2*9.8}{2*9.37^2}[/tex]

[tex]\displaystyle h=403 \ m[/tex]

The mountain is 403 m tall

Answer:

the free-fall acceleration on the moon is 1.68 m/s^2

Explanation:

recall the formula for the gravitational potential energy (under acceleration of gravity "g"):

PE = m * g * h

replacing with our values for the problem:

46 J = 91 * g * 0.3

solve for the "g" on the Moon:

g = 46 / (91 * 0.3)

g = 1.68  m/s^2

Answer:

See the explanation below.

Explanation:

First, we must determine the mass of the baseball, we know that the weight of a body is defined as the product of mass by gravity.

[tex]w=m*g[/tex]

where:

w = weight = 1.47[N]

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

[tex]m=w/g\\m = 1.47/9.81\\m = 0.149[kg][/tex]

We now know that kinetic energy is converted to potential energy as the ball descends. By means of the following equation, we can determine the potential energy when the baseball is 10 meters high.

[tex]E_{pot}=m*g*h\\[/tex]

where:

Epot = potential energy [J]

m = mass = 0.149[kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 10 [m]

Now replacing:

[tex]E_{pot}=0.149*9.81*10\\E_{pot}=14.7[J][/tex]

In theory, this same energy must be converted to kinetic energy just before the ball hits the floor. But we see that we only have 12 [J] of kinetic energy.

That is to say, that of the 14 [J] that were had as potential energy (mechanical energy) 2 [J] was converted to internal energy, and the rest was converted to kinetic energy (mechanical energy)

[tex]E_{int}=14-12\\E_{int}=2[J][/tex]

Note: Potential, kinetic and elastic energies are forms of mechanical energy.

Answer:

[tex]\boxed {\boxed {\sf \frac{14}{3} \ or \ 4.6667 \ m/s^2}}[/tex]

Explanation:

Acceleration can be found using the following formula.

[tex]a=\frac{v_f-v_1}{t}[/tex]

where [tex]v_f[/tex] is the final velocity, [tex]v_i[/tex] is the initial velocity and t is the time.

The lizard started at 12.0 m/s and accelerated up to its final velocity of 40.0 m/s in 6 seconds.

Therefore:

[tex]v_f= 40.0 \ m/s \\v_i= 12.0 \ m/s \\t= 6 \ s[/tex]

Substitute the variables into the formula.

[tex]a=\frac{40.0 \ m/s - 12.0 \ m/s}{6 \ s}[/tex]

Solve the numerator first and subtract.

[tex]a=\frac{ 28 \ m/s}{6 \ s}[/tex]

Divide.

[tex]a= \frac{14}{3} \ m/s/s= \frac{14}{3} \ m/s^2[/tex]

[tex]a=4.66667 \ m/s^2[/tex]

The lizard's average acceleration is 14/3 or 4.66667 m/s²

Answer:

4 2/3 m/s

Explanation:

first thing to find the average acceleration is to figure out what the increase in speed was, we can do that by subtracting the original speed from the speed after accelerating, that looks like:

40 - 12 = 28

so the lizard accelerated 28 m/s in 6 seconds, to find the average increase in m/s every second, we divide the m/s by the seconds, which gives us:

28 / 6 = 4.66 = 4 2/3 m/s

Answer:

\alpha  = \frac{2F}{3m} \ \frac{1}{r}

maximmun x =r

Explanation:

In this exercise we are asked for the maximum angular acceleration, let's start by writing the second law of / newton for rotational motion. Let's fix our reference system at the midpoint of the bar that has a length 2r

       Σ τ  = (I₁ + I₂) α

where I₁ and I₂ moment of inertia of the capsule with masses m and 2m, respectively. Let's treat these capsules as point particles

       I₁ = m r²

       I₂ = 2m r²

the troque of a pair of force is the force times the distance perpendicular to the point of application of the force which is the same for both forces, we will assume that the counterclockwise rotation is positive

      Στ  = F x + F x

the angular acceleration is the same because they are joined by the bar of negligible mass, let us substitute

     2 F x = (m r² + 2m r²) α

     α = [tex]\frac{2F x}{3m r^{2} }[/tex]

     α = [tex]\frac{2F }{3m } \ \frac{x}{r^{2} }[/tex]

let's analyze this expression

* for the application point in the center (x = 0) at acceleration is zero

* for the point of application of the torque at the ends the acceleration is

              [tex]\alpha = \frac{2F}{3m} \ \frac{1}{r}[/tex]

this being its maximum value

Answer:

the blue one

Explanation:

Answer:

Explanation:

The formula method is used to calculate termination payments on a prematurely ended swap, where the terminating party compensates the losses borne by the non-terminating party due to the early termination.

Given :

A race car moves along a circular track of radius 100m at a velocity of 25m/s.

To Find :

(a) What is  the time taken to complete one lap of the circular track.

(b) What is the time taken for 10  laps.

Solution :

Circumference of circular track,

[tex]C = 2\pi r\\\\C = 2\times \pi \times 100\ m\\\\C = 628.32 \ m[/tex]

a) Time taken to complete one lap is :

[tex]t= \dfrac{628.32}{25}\ s\\\\t =25.13 \ s[/tex]

b) Time taken to complete 10 laps is :

[tex]t_{10} = 10\times t\\\\t_{10} = 10\times 25.13\ s\\\\t_{10} = 251.3\ s[/tex]

Hence, this is the required solution.