Identify the chromatography term that corresponds to each definition.
A value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent Choose...
A method used to separate components of a mixture Choose...
The substance to which the sample is bound at the start of an experiment Choose...
The substance that carries the components of a mixture Choose...

Answers

Answer 1

Answer:

A value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent- Retention factor

The substance to which the sample is bound at the start of an experiment- stationary phase

The substance that carries the components of a mixture- mobile phase

Explanation:

The retention is defined as a value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent. It shows us how effective a solvent is at separating a mixture.

The stationary phase is the the substance to which the sample is bound at the start of an experiment. The solvent pick up the substance to be analyzed from this stationary phase. The different components of the mixture are found to move up the stationary phase at different speeds, causing them to eventually  separate from each other.

The mobile phase is the substance that carries the components of a mixture during chromatography.


Related Questions

How many moles are in 3.30 x 1024 molecules of N2I6

Answers

Divide the number of molecules N by avogadro's constant.

Let n be the number of moles then,

[tex]n=\frac{N}{N_A}=\frac{3.3\cdot10^{24}}{6.022\cdot10^{23}}=5.48\mathrm{mol}[/tex]

Hope this helps.

Rank the following elements in INCREASING Atomic Radius: Fe, Ni, K, Ti (SMALLEST TO
LARGEST)
a. Ti, Ni, Fe, K
b. Ni, Fe, Ti, K
c. Fe, Ti, K, Ni
d. K, Ti, Fe, Ni

Answers

Answer:

b. Ni, Fe, Ti, K

Explanation:

The given elements are present in period 4 of periodic table. Now we will discuss the trend of atomic radius along period.

Atomic radius:

" It is the smallest distance from nucleus to the outer most valance shell of an atom"

When we move from left to right in the periodic table the number of valance electrons in an atom increase. The atomic size goes to decrease in same period because of edition of electron with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. In this way positive charge is also going to increase and this charge is greater in effect than the charge of electrons. This effect causes the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell come closer to the nucleus.

As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Ni ∠ Fe ∠ Ti ∠ K

A student determines the chromium(III) content of a solution by first precipitating it as chromium(III) hydroxide, and then decomposing the hydroxide to chromium(III) oxide by heating. How many grams of chromium(III) oxide should the student obtain if her solution contains 56.0 mL of 0.600 M chromium(III) nitrate?

Answers

Answer:

Explanation:

Chromium nitrate Cr( NO₃ )₂

Chromium hydroxide Cr( OH)₃

Chromium oxide ( Cr₂O₃ )

1 mole of chromium nitrate will form 1 mole of chromium hydroxide

1 mole of chromium hydroxide will form one mole of chromium oxide .

Moles of chromium nitrate in 56 mL of .6 M solution

= .056 x .6 = .336 moles

.336 moles of chromium nitrate will produce .336 moles of chromium hydroxide and .336 moles of chromium hydroxide will produce .336 moles of chromium oxide .

So chromium oxide produced = .336 moles

Molecular weight of chromium oxide = 152

.336 moles of chromium oxide is equal to

.336 x 152 grams of chromium oxide

= 51.07 grams .

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