In the equation for Newton's second law, what does Fnet stand for?

Question 14 options:

Net external force


Internal force


Frictional force

The structure of the kangaroo paw flower fits with a bird pollinator because of its tabular structure.

The tabular structure of the kangaroo paw flower fits with a bird pollinator because it gives easy access to the nectar of the flower. These flowers are covered with hairs and have pointed lobes, which are in curved shape at their tips that gives them the appearance of kangaroo paws. These curved tips and tabular structure provides good access to the bird pollinators as well as the colorful petals also attracts the pollinators towards itself.

So we can conclude that The structure of the kangaroo paw flower fits with a bird pollinator because of its tabular structure.

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This implies that the opening price was 21080.28.

Closing index = 21029.47

plus down movement =50.81

The Dow Jones Industrial Average measures the stock price performance of 30 large companies listed on US stock exchanges. Stock index. Others include the S&P 500 Index and NASDAQ.

The Opening Price Index represents the average opening price of the day before the trading day. During trading, the price must have experienced fluctuations, ups and downs. However, at the end of the trading day, the closing price was reported at 21029.47, down 50.81.

Adding back from this closing index report, the opening price was 50.81 or about 51 basis points higher than the closing price.

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The voltage drop in the second resistor such that the drop in the first resistor is 7 volts using conservation of potential in a loop we get the value of potential drop to be equal to 8 volts .

Voltage is a physical quantity that is responsible for movement of charges in a wire the difference in potential between two points causes the flow of charges.

Its S.I unit is voltage (V)

Electric current is a physical quantity which refers to the flow of electric charge per unit area across a cross section of unit area.

Its S.I unit is ampere (A).

Given:

Total voltage across the circuit = 15 V

Voltage drop across first resistor = 7V

Resistance of first resistor = 10002 ohm

Resistance of second resistor= 22002 ohm

Now we know about conservation of charge and Kirchhoff's law.

Kirchhoff law states that the sum of potential in a loop is always conserved. In first resistor we noticed a drop of 7 volt it means that the remaining voltage must drop across the second resistor.

Therefore, the drop in the voltage using conservation of potential in a loop we get the value of potential drop to be equal to 8 Volt .

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Note: The question is incomplete in the portal. Here is the complete question.

Question: Two resistors with resistance R₁ equal to 10002 and R₂ equal to 22002 respectively are connected in series circuit, such that the potential drop through the first resistor of resistance 10002 is of 7V find the voltage drop in second resistor using divider rule.

Answer:

40.0

Explanation:

[tex]\int^{10}_{2} f(x) \text{ } dx \approx 2f(2)+3f(4)+2f(7)+f(9) \\ \\ =2(0)+3(3)+2(8)+15 \\ \\ =0+9+16+15 \\ \\ =40[/tex]

Behavioral geneticists can ascertain how genes affect the environment and population by examining close relatives. Additional explanation Individual variances result from variations in hereditary variables.

Gender, disorders/diseases, blood type, and other characteristics that each person possesses can be handed down to their offspring. The expansion of the human population is facilitated by these genetic variations. The carrying capacity of the ecosystem is influenced by the population. The ability of the environment to provide the resources it possesses for a creature's life within reasonable bounds is known as carrying capacity. Environmental issues will arise if the population surpasses the carrying capacity of the resources generated or made available.

These issues include a lack of available natural resources, the growth of pollution, or competition for scarce natural resources. so that initiatives to manage or control the environment, such as recycling or processing industrial waste, can be made. To lessen environmental exploitation that affects the entire human population, the study of human behavior based on the nature of genes will be helpful. Studying close relatives enables behavioral geneticists to ascertain the effect of humans from the nature of their genes on the carrying capacity of the environment and their effect on living populations. The population of quality and productive human resources will have a positive impact on the environment.

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Walking, running, and breathing are examples of motion. For rolling of ball, the street is a frame of reference and an insect on the ball is an inappropriate frame of reference.

A frame of reference, also known as a reference frame, is a perspective used in physics to assess whether an object is moving.  A frame of reference is an environment or object that is thought to be stationary. The Earth itself, despite its motion, serves as the most frequently used frame of reference.

Some examples of motion are:

Motion is a part of many of our daily activities, including walking, running, closing doors, etc.

Another illustration of motion is the passage of air into and out of our lungs.

The vehicles that transport passengers between the point of pickup and the destination have motion.

A ball is rolling down the street that it is moving.

For a ball rolling down the street, the street is an appropriate frame of reference as it is rest as compared to the ball.

For the same example, the insect sitting on the rolling ball is a part of the rolling ball.

Therefore, the insect is an inappropriate frame of reference for the motion of the ball rolling down the street.

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Chromatography is a laboratory technique for separating a mixture into its components.

What is Chromatography?

This is a laboratory technique for separating mixture. The mixture is dissolved in a liquid solvent (gas or liquid) called the mobile phase, which passes it through a system (column, capillary tube, plate, or sheet) to which the material is attached, called the stationary phase. Because different constituents of a mixture have different affinities for the stationary phase and are retained for different periods of time depending on their interaction with its surface, the constituents move with different apparent velocities in the moving fluid, causing them to separate. The separation is based on the differential partitioning of the mobile and stationary phases. Subtle differences in the partition coefficient of the compound result in differential retention in the stationary phase and thus affect the separation.

Chromatography can be analytical or preparative . The reason of analytical chromatography is to separate the components of a mixture for later use and then form of purification.This process is associated with higher costs due to the manufacturing method. Analytical chromatography is usually performed on smaller amounts of material and aims to determine the presence of analytes or measure their relative proportion in a mixture. The two types are not mutually exclusive.

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Considering the definition of velocity, the total time elapsed is 1.2292 h.

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it.

In other words, velocity can be defined as the amount of space traveled per unit of time with which a body moves.

The velocity can be calculated using the expression:

velocity= displacement÷ time

In this case, you know:

Then, the elapsed time to travel each of the distances is calculated by the definition of velocity:

65 mph= 50 miles÷ time to travel 50 miles

65 mph× time to travel 50 miles= 50 miles

time to travel 50 miles= 50 miles÷ 65 mph

time to travel 50 miles= 0.7692 h

75 mph= 40 miles÷ time to travel 40 miles

75 mph× time to travel 40 miles= 40 miles

time to travel 40 miles= 40 miles÷ 75 mph

time to travel 40 miles= 0.53 h

The elapsed time will be the sum of the time it takes to travel each distance:

elapsed time= time to travel 50 miles + time to travel 40 miles

elapsed time= 0.7692 h + 0.53 h

elapsed time= 1.2992 h

Finally, the total time elapsed is 1.2292 h.

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The current density of the copper wire is determined as 0.182 A/m².

The current density of a material is the amount of electric current flowing per unit cross-sectional area of a material.

The current density of the copper wire is calculated as follows;

J = I/A

where;

Substitute the given parameters and solve for the area of the wire,

A = πr²

where;

A = π(3.5 x 10⁻³)²

A = 3.85 x 10⁻⁵ m²

J = (7 x 10⁻⁶) / (3.85 x 10⁻⁵)

J = 0.182 A/m²

Thus, the current density of the copper wire is determined as 0.182 A/m².

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Answer:

-5

Explanation:

the red line is showing that you are going down to -8 and the blue line is showing that you should go up, which means you are adding three to -8. When 3 is added to -8, you get -5.

Frequency of the waves is 0.05 Hz

Number of complete wavelength, λ = 6

therefore distance covered = 6 Wavelength

Time taken to complete 6 wavelengths, t = 2 min

Since 1 min = 60 sec

2 min = 2 * 60 = 120 sec

Frequency can be defined as the number of wave cycles completed per second by a wave.

As we know, Velocity = [tex]\frac{Distance}{Time}[/tex] = [tex]\frac{6 Wavelength}{120}[/tex]

F = [tex]\frac{Velocity}{Wavelength}[/tex]

F = [tex]\frac{6 wavelength}{120 wavelength}[/tex]

F = [tex]\frac{6}{120}[/tex]

F = 0.05 Hz

Therefore frequency of the navigation buoy floating on the sea oscillates as a wave is 0.05 Hz.

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The distance below the intended target the dart hit is 0.26 m.

The time taken for the  dart to fall is calculated as follows;

X = Vxt

where;

t = X/Vx

t = 2.7/12

t = 0.23 seconds

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

h = ¹/₂(9.8)(0.23²)

h = 0.26 m

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The final velocity of Luis is 29.4 m/s

It is given that

Acceleration a = 9.8m/s^2, time t = 3.0 second

initial velocity = 0 m/s

Free fall is characterised as a scenario where an object is only affected by gravity. The ball experiences an external force, which quickens its motion. Gravitational acceleration is another name for this rate of free fall acceleration. A downward motion without any beginning force or speed is called a free fall.

The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time can be used to define velocity.

using v = u + at

v = 0 + 9.8 x 3

v = 29.4 m/s

Hence, final velocity of Luis is 29.4 m/s

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The Height of the rocket ship rises above the launch pad after 94 seconds of flight is 47m

Constant upward Acceleration(a) = 6.3m/sec²

Initial Upward Velocity [tex]V_{i}[/tex] = 0

Final Upward Velocity [tex]V_{f}[/tex] = a × t

= 6.3 × 94

= 592.2 m/sec

Let Height be h

Using relation:

[tex]V_{f2}[/tex]² + [tex]V_{i^{2} }[/tex]² = 2 × a × h

592.2 - 0 = 2 × a × h

h = 592.2 / (2× a)

= 592.2 / 2*6.3

= 47 m

So height above the ground is 47  m

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The acceleration of the fireman sliding down a pole who weighs 100 kg with a frictional force of 137 N is 8.44 m / s²

According to Newton's second law of motion

F = m a

Net downwards force = F - f

F = Applied force

f = Frictional force

m = Mass

a = Acceleration

m = 100 kg

f = 137 N

g = 9.81 m / s²

F = m g

F = 100 * 9.81

F = 981 N

Net downwards force = 981 - 137

Net downwards force = 844 N

F = m a

a = 844 / 100

a = 8.44 m / s²

Therefore, the acceleration of the fireman is 8.44 m / s²

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The force applied on the object caused a change in the acceleration of the object, from certain periods, the acceleration increased, in some periods it remained constant, while in some periods, the acceleration decreased to zero.

The acceleration of an object an object is the change in the velocity of the object with time.

a = Δv/Δt

where;

From the given graph, we will explain the impact of the applied force on acceleration in the following points;

Thus, the force applied on the object caused a change in the acceleration of the object, from certain periods, the acceleration increased, in some periods it remained constant, while in some periods, the acceleration decreased to zero.

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The average for each checkpoint is:

point 1 t_{avg} = 2.07 sec

point 2 t_{avg} = 3.16 sec

point 3 t_{avg} = 4.11 sec

point 4 t_{avg} = 4.92 sec

We have the graph for each interval.

The magnitude of the average is:

t_{avg} = Σ ( t_(i) / n)

where t_{avg} is the average time, t_(i) each time the magnitude is measured and n is the number of times the measurement is repeated for the same point.

The table for the times measured for each interval is:

Measurement        times for each interval

                           1          2             3            4

1                         2.02    3.17       4.12        4.93

2                         2.05    3.07       3.98        4.81

3                         2.15    3.25       4.23         5.01

Now, the average time to reach the get married checkpoint is:

For point 1:

t_{avg} = (2.02 + 2.05 + 2.15) / 3

t_{avg} = 2.07 s

For point 2:

t_{avg} = (3.17 +3.07 + 3.25) / 3

t_{avg} = 3.16 s

For point 3:

t_{avg} = (4.12 + 3.98 + 4.23) / 3

t_{avg} = 4.11 s

For checkpoint 4:

t_{avg} = (4.93 + 4.81 + 5.01) / 3

t_{avg} = 4.917 s

We employ the significant figures criterion for the sum, which is steady in that the result must be provided with the least amount of decimal places.

t_{avg} = 4.92 s

Therefore, the average times for each checkpoint are:

point 1: t_{avg} = 2.07 s

point 2: t_{avg} = 3.16 s

point 3: t_{avg} = 4.11 s

point 4: t_{avg} = 4.92 s

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The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .

The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.

Given the initial velocity of the ball (u) =  0

Distance travelled by the ball (s) = 200m

Acceleration (a) = 10 m/s²

As we know:

v² = u² + 2as

Putting values:

v² = 0+2 × (10 m/s²) × (200 m)

v = 44.73 m/s.

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Strategy and tactics are important in sports and games as they help the players define their objectives, work towards them and achieve them using their competitive advantage.

Strategy in sports refers to the plans used to reduce uncertainty that following one course of action will worsen the team's position, that is using another plan.

Strategy is important is it enables the player to have a predefined target and also work towards them.

Tactics are actions and strategies planned to achieve an overall objective in sport that objective is predominantly to win.

Tactics can depend on a number of factors such as opposition, players available for selection, the importance of the game and possibly even weather.

Thus, Strategy and tactics are important in sports and games as they help the players define their objectives, work towards them and achieve them using their competitive advantage.

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If a runner accelerated from rest for 12 s, at which time the runner has traveled 100 m, then the runner's average and final velocities would be  8.33 m /s  and 16.66 m/s.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

By using the second equation of motion given by newton,

S = ut + 1/2at²

100 = 0 + 0.5*a*12*12

a = 100 / 72

a =  1.388 meters / second²

The final velocity of the runner = 12*1.388

                                                    =16.66 m/s

The average velocity = 16.66 /2

                                    =8.33 m /s

Thus, the average velocity of the runner would be 8.33 m /s  and the final velocity of the runner would be 16.66 m/s

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The breaking acceleration of the car must be - 44.5 m/s² so that the car stops in time and avoid hitting the Ilama.

Given in the question

The car is driving at the speed of 14 m/s and the reaction time is 0.05 seconds. So the distance traveled by car before hitting the break is,

Distance = Speed × time

Distance = 14 × 0.05

Distance = 0.7 meters

So, now the Ilama is 2.9 meters away and the distance traveled before hitting the break is 0.7 meters.

So the stopping distance = Distance of Ilama  - distance traveled before hitting the break

So stopping Distance = s = 2.9 - 0.7

stopping Distance = s = 2.2 m

Now we have

Initial Velocity = u = 14 m/s

Final Velocity = v = 0 m/s [ as after applying the break, the car comes to rest]

Stopping Distance = s = 2.2 m

Using the third equation of motion

v² - u² = 2as

Put in the value, we get

(0)² - (14)² = 2a(2.2)

4.4a =  - 196

a = -196/4.4

a = - 44.5 m/s²

Therefore, the breaking acceleration of the car must be - 44.5 m/s².

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In the graphing of constant speed, we get a plateau while when we graph increasing acceleration, we have a straight line graph

The term speed refers to the change in the position of an object with time. If the speed changes by equal amounts in equal time intervals then we could say that the object is undergoing uniform acceleration. If the speed does not increase by equal amounts in equal time intervals then the objects is not undergoing a uniform acceleration.'

Thus if we plot the speed of a body against the time taken, the slope of the graph is taken to be the acceleration of the body. If the plot of the speed against the acceleration is a straight line graph that had  started from the origin of the graph then we have a case of uniform acceleration.

Thus, in the graphing of constant speed, we get a plateau while when we graph increasing acceleration, we have a straight line graph that starts from origin.

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The net force acting on the particle would be and the magnitude of the force would be -12.92i + 6.49j and the magnitude of the force would be 14.46 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The net force on the particle = mass of the particle × acceleration

                                                =3.80*(−3.40i + 1.70j)

                                                = -12.92i + 6.49j

Thus, the magnitude of the net force on the particle would be 14.46 Newtons.

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The types of memories that are stored in the collective unconscious include instinctive patterns and archetypes from ancestral heritage.

The collective unconscious can be defined as  the part of the human mind  that contains distinct types of memories and also instinctive impulses in humans which may shape some of our behaviors regarding specific situations and also environmental contexts (e.g., during danger situations).

In conclusion, the types of memories that are stored in the collective unconscious include instinctive patterns and archetypes from ancestral heritage.

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Answer:h

Explanation:

Answer:

9.5m/s west

Explanation:

Average v= (Final v+Initial v)/2

Average v=(0+19m/s)/2

=9.5m/s west

The unconscious lingering effects of a bad athletic performance may be what is currently causing an athlete distress at the thought of performing. This situation correlates with the Psychodynamic theory.

Psychodynamic theory is first coined by Sigmund Freud. It explains the origins of human behavior. According to Psychodynamic theory:

In this situation, an athlete's distress at the thought of their performance is said to be a result of bad athletic performance in the past. This correlates with the second statement of Psychodynamic theory.

Therefore, Psychodynamic theory of personality explains this situation clearly.

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The correct answer is 10498.3.

The speed of an object is calculated when it moves from one spot to another in time interval t by dividing the distance between the two locations by the time interval. As a result of this definition, the longer it will take the object to travel the specified distance, the greater the separation between the two points.

x = x_0 + (v_x) t

In case of cheetah:

x_0 = 0;

v_c = 97.1 km/h

x = 97.1t _____(1)

In case of gazelle;

x_0 = 52.2 m = 52.2 × 10^-3 km

v_c = 79.2 km/hr

x = 52.2 × 10^-3 + 79.2t ______(2)

equating 1 and 2

52.2 × 10^-3 + 79.2t = 97.1t

52.2 × 10^-3 = 97.1t - 79.2t

52.2 × 10^-3 = 17.9t

52.2 × 10^-3×3600/17.9 = t

t = 10498.3

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The acceleration of the car for it to stop within the given distances at the given speeds will be:

a. acceleration = -47520 mi/h²

b. acceleration = -132000 mi/h²

The acceleration of the car for it to travel a distance of 200 ft is calculated as follows:

initial velocity of the car = 60 mi/h

final velocity of the car = 0 mi/h

distance travelled = 200 ft

5280 ft = 1 mile =

200 ft = 200/5280 miles

acceleration, a = ?

Using the formula:

v² = u² + 2as

0 = 60² + 2 * 200/5280 * a

400a/5280 = -3600

a = -47520 mi/h²

Acceleration for it to stop in 200 ft will be:

v² = u² + 2as

0 = 100² + 2 * 200/5280 * a

400a/5280 = -10000

a = -132000 mi/h²

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The total distance (in kilometers) that India has plowed into Asia is 330,000 km.

The total distance (in kilometers) that India has plowed into Asia is calculated as follows;

distance = speed x time

distance = 6 cm/year x (55 x 10⁶ years)

distance = 330,000,000 cm

distance = 330,000 km

Thus, the total distance (in kilometers) that India has plowed into Asia is 330,000 km.

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