The total distance (in kilometers) that India has plowed into Asia is 330,000 km.
total distance (in kilometers) that India has plowed into Asia
The total distance (in kilometers) that India has plowed into Asia is calculated as follows;
distance = speed x time
distance = 6 cm/year x (55 x 10⁶ years)
distance = 330,000,000 cm
distance = 330,000 km
Thus, the total distance (in kilometers) that India has plowed into Asia is 330,000 km.
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Calculate the potential energy stored in a cart of mass 506.8 g elevated to a height of 20.60 cm. Your
result should be reported in Joules.
A cart of mass 506.8 g elevated to a height of 20.60 cm has a stored potential energy of 1.024 J.
The energy that is held within an object because of its position in relation to a zero point is known as potential energy. An object has gravitational potential energy if it is positioned at a height above (or below) the zero height.
P.E. = mgh, where m is the mass in kilograms, g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and h is the height in meters, which is the formula for gravitational force.
Here,
Mass M = 0.5068 kg
Acceleration due to gravity, g = [tex]9.81 \frac{m}{s^{2} }[/tex]
Height, h = 0.2060 m
PE = m × g × h
= (0.5068) × (9.81) × (0.2060)
= 1.024 J
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HELP
Find the value of each calculation, rounded to the correct number of significant figures.
15.2÷4.368=
The value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.
What is significant figures?Significant figures is a digit that is meaningful with respect to the precision of a measurement.
Significant figures constitutes a digit that is nonzero, followed by a nonzero digit, or (for trailing zeroes) justified by the precision of the derivation or measurement.
According to this question, the following arithmetic expression is given:
15.2 ÷ 4.368 = 3.47985348
No. of significant figures: 9No. of decimals: 8Scientific notation: 3.47985348 × 100Therefore, the value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.
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how does the distance from an eye chart affecr the number of letters that are recognized on a line?
The correct answer is eye chart, the position of the viewer, light in the room.
The number of letters identified on a particular line is directly related to the distance between an eye chart and the person undergoing an eye test.
Distances from the eye chart are used to identify defects in a patient's visual sight. Someone is nearsighted if they are unable to perceive objects in the distance. He will therefore see a hazy image of the letters if he looks away from the eye chart and tries to read it.
And someone with long sight is unable to perceive nearby objects. One will not be able to read the letters on the chart if they are closer to him because of his farsightedness.
Therefore, the distance from the eye chart affects the ability to perceive the letters that are displayed there.
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Which of the following elements have the same amount of valence electrons as Sulfur (5)?
O N. Br, and Xe
O F, As, and Sn
O Si, P, and CI
O O, Se, and Te
Answer:
Explanation:
it's c
Each circled letter in the circuit diagram represents a meter that is used to
measure a quantity in the circuit. Which meters show the amount of charge
passing a point each second?
A
C
m
A. C and D
ww
(В
There are meters created to precisely measure the fundamental values of voltage, current, and resistance for analyzing and testing circuits.
What exactly is a circuit schematic for a meter?Any apparatus designed to precisely detect and present an electrical quantity in a way that can be understood by a human is referred to as a meter. The majority of the current flows via one branch, while the remainder flows through the other branch. At the point of meter insertion, an ammeter is used to measure the amount of current (in amps or milliamps) flowing in a circuit. The circuit element you are measuring is always linked in series with an ammeter. The most frequent measurements in an electrical circuit are typically made with a meter. Current is measured by an ammeter.
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A mass of 4 kg rests on a horizontal plane. A horizontal force P is gradually applied until at a force P = 10.6 N, the mass just
begins to slide. What is the coefficient of static friction between the mass and the surface?
The coefficient of static friction between the mass and the surface is 0.270
How to determine the coefficient of frictionFrom the question given above, the following data were obtained:
Mass (m) = 4 KgForce (F) = P = 10.6 N Acceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 4 × 9.8 = 39.2 NCoefficient of friction (μ) =?We can obtain the coefficient of friction as illustrated below:
Frictional force (N) = coefficient of friction (μ) × normal reaction (N)
F = μN
10.6 = μ × 39.2
Divide both sides by 39.2
μ = 10.6 / 39.2
μ = 0.270
Thus, the coefficient of static friction between the mass and the floor is 0.270
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Marissa's car accelerates at a rate Of 42.60 m/?. How long does it take
for Marissa's car to accelerate from a speed of 88.5 km/h to a speed of
96.5 km/h?
The correct answer is 0.0539 sec.
Since we are aware that a body's position changes over time, the concept of velocity is introduced. The vector quantity known as velocity is sometimes referred to as the rate of change of location. The body's velocity increases as it changes position more quickly over time.
The acceleration of the car is 42.60 m/s^2.
Initial speed u = 88.5 km/h = 24.5 m/s
final speed v = 96.5 km/h = 26.8 m/s
The amount of time the car needs to travel from a speed of 24.5 m/s to a speed of 26.8 m/s must be determined. An object's acceleration is determined by:
t = v-u/a
t = (26.8 - 24.5) / 42.6
t = 0.0539 sec
Therefore, it takes the car 0.0539 seconds to increase from a speed of 24.5 m/s to a speed of 26.8 m/s. This is the necessary remedy as a result.
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1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball
1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball 13.50 N Leftwards
What is acceleration ?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
Any object's mass and acceleration in the force's direction are multiplied together to form the net force exerted on it.
Here, F = m*a
F = 1.5*9.0 = 13.50 N
Since, the acceleration is to the left, the net force also acts towards left.
13.50 N Leftwards
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Rhea, with a radius of 7.63 x 105 m, is the second-largest moon of the planet Saturn. If the mass of Rhea is 2.31 x 1021kg, what is the acceleration due to gravity on the surface of this moon?
The acceleration due to gravity on the surface of this moon:
Solution:
R = 7·63x105 m m
M = 2·31x10² 1 kg
g= GM/R2
= 6.67x10" x 2.3 x [tex]10^{21}[/tex]/[tex](7.63*10^{5} )^{2}[/tex]
=g = 15.4077 x [tex]10^{10}[/tex]/[tex](7.63)^{2} * 10^{10}[/tex]
= g = 0·2646 m/s².
An object on the Moon weighs 1/6 of its weight on the Earth's surface. This is because the gravitational acceleration on the Moon is six times that of Earth. The value of g is determined by the mass of the gigantic body and its radius. It depends on your body. The value of g is constant for months. g is called gravitational acceleration. The acceleration of an object in free fall under the influence of gravity. Expressed as the rate of increase in velocity per unit time, it is assigned a standard value of 980.665 centimeters per second per second.
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An object accelerates from rest at a constant rate of 4ms^_2 for a distance 200m.How fast is the object moving at that time?How long did it take for the object to reach that velocity?
The speed of the object is 40 m/s and the object takes 10 seconds to reach its velocity.
The rate at which an object's velocity with respect to time varies is known as acceleration. They are vector quantities. The direction of the net force acting on an object determines the direction of its acceleration.
The constant acceleration of the object starting from rest is 4 m/s².
The object covers a distance of 200 m.
So,
Initial velocity, u = 0 m/s
Acceleration, a = 4 m/s²
Distance, d = 200 m
Using the equation of motion,
v² - u² = 2as
v² = u² + 2as
v² = (0)² + 2 × 4 × 200
v² = 1600
v = √1600 m/s
v = 40 m/s
The time the object takes for the object to reach the velocity v will be:
v = u + at
at = v - u
t = (v - u) / a
t = ( 40 - 0) / 4
t = 10 sec
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When people do a bungee jump they are asked how much they weigh. Why?
To do a bungee jump people need to be given a bungee rope that will stretch the right amount for their weight.
To fill the water tank at the bottom with the right amount of water for their weight.
To register the world record for their weight in the tournament.
To do a bungee jump people need to be given a bungee rope that will stretch the right amount for their weight which is why it must be measured and is denoted as option A.
What is Weight?This is referred to as the force which acts on a body or object as a result of gravity and is denoted as:
W = mg where m is mass and g is acceleration due to gravity.
In the case of a bungee jump, a rope is used and the weight of individuals have to be known so as to select the one which can stretch the right amount to prevent accidents.
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What do you observe now do the same with the second plastic shopping bag square
The observation is that we will observe a large shadow in dark color on the wall.
How to illustrate the information?The light will be blocked if we place our largest plastic shopping bag between the light source and the wall.
When something stops the path of the light, the light can't pass through it, and we may see a black shadow where it can't.
Therefore, we may state that a shadow will be visible when a bag is held between a light source and a wall.
If the bag is transparent, we will still be able to see a shadow, but it won't be as dark as previously because transparent materials let some light through but not as much as other materials do.
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What do you observe if you switch on your light source. make sure it's shining onto a wall hold your largest plastic shopping bag square between the light source and the wall
in the soapbox derby, young participants build non-motorized cars with very low-friction wheels. Cars race by rolling down a hill. Assume that the track begins with a 63-ft-long (1m = 3.28 ft) section tilted 12 degrees below horizontal. What is the maximum possible acceleration of a car moving down this stretch of track?
The maximum possible acceleration of a car moving down this stretch of track is 2.083 m/s².
What is maximum acceleration?
The maximum acceleration of an object is the maximum change in the velocity of the object with time.
The maximum possible acceleration of a car moving down this stretch of track is calculated as follows;
tanθ = a/g
where;
θ is the angle of inclination of the tracka is the maximum acceleration of the car g is acceleration due to gravitya = g tanθ
a = (9.8 m/s²) tan(12)
a = 2.083 m/s²
Thus, the maximum possible acceleration of a car moving down this stretch of track is 2.083 m/s².
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calculate the kinetic energy of a 820 kg compact car moving at 23 m/s.
Answer:
216,890 J
Explanation:
We first define the Kinetic Energy Formula:
K.E =
[tex] \frac{1}{2} m {v}^{2} [/tex]
where m is the mass of the object in kg, and v is the velocity in m/s.
Given from the information from the question, we substitute the values in to find K.E.
K.E of car =
[tex] \frac{1}{2} (820) {(23)}^{2} \\ = 216890 \: joules[/tex]
Note that the SI unit for Energy is Joules or J.
A long rectangular, yellow sign with diagonal black stripes on it means:
O There is a highway ahead
O Be prepared to stop
O The guardrails of a narrow bridge are ending
OYou are going the wrong way
A long rectangular, yellow sign with diagonal black stripes on it means Be prepared to stop.
Hazard warning signs consist of black diagonal stripes on a yellow background. WA-36 signs are used to mark roadway obstructions that are passable from either side. Hazard warning signs consist of black diagonal stripes on a yellow background. WA-36 signs are used to mark roadway obstructions that are passable from either side.
Warning sign. These signs warn of dangerous or unusual conditions such as curves, turns, inclines, and side streets. They are usually diamond-shaped and have black letters or symbols on a yellow background. These markings, yellow diagonal lines, are found on roads and highways to indicate narrow roads or obstructions in the lane. This area resembles a triangle with a solid yellow diagonal line inside the outline.
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. A man rows a boat in still water at 6.0km/h, he wishes to
row due north across a river 3.0km wide which is flowing
due east at 2.0km/h. calculate
a. The direction in which he must head the boat
b. The time taken to reach the other bank
The direction in which he must head the boat is 30° West of North. The time taken to reach the other bank is 0.86 hours.
Velocity of boat with respect to water, [tex]V_{BW}[/tex] = 6 km / h
Velocity of river, [tex]V_{W}[/tex] = 2 km / h E
If the boat has to reach the exact opposite side of the river from the starting point, the boat should go upstream.
Velocity of boat in upstream, [tex]V_{B}[/tex] = [tex]V_{BW}[/tex] - [tex]V_{W}[/tex]
[tex]V_{B}[/tex] = 6 - 2
[tex]V_{B}[/tex] = 4 km / h
θ = [tex]sin^{-1}[/tex] ( [tex]V_{W}[/tex] / [tex]V_{B}[/tex] )
θ = [tex]sin^{-1}[/tex] ( 2 / 4 )
θ = [tex]sin^{-1}[/tex] ( 0.5 )
θ = 30° W of N
cos θ = Adjacent side / Hypotenuse
cos 30° = 3 km / Distance covered by the boat
Distance covered by the boat = 3 / 0.87
Distance covered by the boat = 3.45 km
t = d / v
t = 3.45 / 4
t = 0.86 hr
Therefore,
The direction in which he must head the boat is 30° West of NorthThe time taken to reach the other bank is 0.86 hours.To know more about speed of boat in a river
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A box with a mass of 30kg accelerates at a rate of 3m/s. If the force of friction on the box is 20N, how much force did you exert in order to move it?
The force exerted in order to move the box is 404 N.
What is force?Force is a pull or push effect on a body.
The force on a body is related to the mass and the acceleration of the body.
The acceleration of a body is inversely related to the mass of of the body and directly related to the force acting on it.
Force = mass * acceleration.
Net force = Force applied - (weight of the body + frictional force)
Force applied = Net force + weight of the body + frictional force
Weight of the body = 30 * 9.8 m/s = 294 N
Net Force = 30 * 3 = 90 N
Force applied = 90 N + 294 N + 20 N
Force applied = 404 N
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the muscles in a grasshopper's legs can propel the insect upward at 3.0m/s how high can the grasshopper jump
The grasshopper attains an initial velocity of 3m/seconds and with this velocity can attain a maximum height of 0.4591 metre.
What is acceleration due to gravity?Acceleration due to gravity is a constant acceleration (changes if the change in height is considerable to earth's diameter) that an object experiences towards earth. Its value near the surface is 9.8u.
Given:
Initial velocity attained by the grasshopper=3m/s
Acceleration due to gravity=9.8u
According to Newton's third law every action has an equal and opposite reaction.
It's mathematical expression for motion is v^2=u^2-2×a×s
Where-
v is final velocity of the grasshopper
u is initial velocity of the grasshopper
a is acceleration due to gravity
s is the total distance
We can only apply Newton's law of motion for those bodies which have constant acceleration. The grasshopper also has a constant acceleration due to gravity which pulls it downward.
According to question for maximum displacement the final velocity will become zero
Substituting these value in Newton's third equation of motion we get
0 - 9 = 2 × 9.8 × s
Maximum displacement of the grasshopper = 0.4591 metre.
The grasshopper attains an initial velocity of 3m/seconds and with this velocity can attain a maximum height of 0.4591 metre.
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The half-life of a source of carbon-14 is 5760 years. After how many years will the
number of radioactive particles left be 12.5% of the original amount?
Show your working out here.
Accordingly, just half of the initial 14C will be present after 5,760 years, followed by a quarter after 11,490 years, an eighth after 17,280 years, and so on.
What does half-life mean?The half-life of a radioactive sample is the amount of time it takes for half of its atomic nuclei to spontaneously transform into other nuclear species and emit particles and energy. Alternatively, it is the amount of time it takes for a radioactive sample to disintegrate at a rate of one disintegration per second.
Briefing:The half-life of carbon-14 is 5760 years.
Therefore, after
1- half-life there is 50 %=1/2 of the original amount left.
2- half-life there is 25 %=1/4 of the original amount left.
3- half-life there is 12.5 %=1/8 of the original amount left.
Therefore, the time it takes for 3 half-lives of carbon-14 to pass would be your answer.
5760 * 3 = 17280 years
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An object moves to the right at a rate of 8m/s. Moving to the right is the positive direction. What is the speed and velocity?
Answer:Given parameters: Mass of object = 6.7kg Velocity = 8m/s Unknown parameter: Kinetic energy = ? Energy is defined as the ability to do work. There are two forms of energy; Kinetic and potential energy. Kinetic energy is the energy due to the motion of a body. Whereas, potential energy is the energy due to the position of a body usually at rest. Kinetic energy is mathematically expressed as; Kinetic energy = where m is the mass of the body v is the velocity of the bodySince we have been given both mass and velocity, input the parameter to solve for the unknown; Kinetic energy = x 6.7 x 8² = 214.4JSo the kinetic energy of the body is 214.4J
Explanation:
Please help me with this question
The displacement of Hermione is zero since the initial point and the final point are the same.
Displacement is the smallest distance between two positions, i.e. the starting and finishing points.
Hermione follows a circular path and hence her motion is circular motion. We know that one cycle of a circular motion is the movement of an object from one point in the circle to the same location after completing a complete revolution. Since the initial point and the final point are the same, it is obvious that there is only one point between which a displacement must be considered, which turns out to be zero.
Furthermore, even though Hermione walks on the circle path eight times, her displacement is still zero because the displacement involved for the 'n' number of cycles of circular motion is also zero.
As a result, Hermione's displacement is zero because the initial and final points are the same no matter how many times she walks around the circular path.
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The approximate speed-time graph for a car on a 5-hour journey is shown in Figure P1.21. (There is a very quick driver change midway to prevent driving fatigue!)
a State in which of the regions OA, AB, BC, CD, DE the car is
i accelerating,
ii decelerating,
iii travelling with uniform speed.
b Calculate the value of the acceleration, deceleration or constant speed in each region.
c What is the distance travelled over each region?
d What is the total distance travelled?
e Calculate the average speed for the whole journey.
a) OA acceleration AB uniform speed travel BC acceleration CD uniform speed travel DE deceleration.
b). OA 80 AB 160 BC 45 CD 100 DE 50 d). 435 e). OA 80 AB 80 BC 40 CD 100 DE -200 87
Describe acceleration.acceleration: the rate at which the speed and direction of a moving object vary over time. When something moves faster or slower, it is considered to be accelerating. Motion on a circle accelerates even while the speed is constant because the direction is always changing.
According to given data;
A) OA acceleration AB moving at a constant speed BC acceleration CD traveling at a constant speed DE deceleration, according to the information provided.
B). OA 80
AB 80
BC 40
CD 100
DE -200
C.) OA 80
AB 160
BC 45
CD 100
DE 50
D). 435
E). 87
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A bicycle tire contains 2.00L of gas at an absolute pressure of 7.00 x 10 5 N/m2 and temperatures
The final pressure of the tire will be 6.99 N/m²
The initial volume of tire = 2.00 L
The initial pressure of the tire = 7.00 × 10 5 N/m²
The initial temperature of the tire was 31 °C
P1V1 = P2V2
7.00 × 10 5 N/m² × V1 = 101325×100
V1 ⇒ 1.45×10^(-5) m³ = 1.45×10^(-2) L
Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)
The pressure of released gas filling the entire:
2 L = 2 L/(7.00 × 10^5 N/m² × 1.45×10^(-5) m³)
⇒ 1.197 ×10^(-4) N/m²
New pressure = 7.00 × 10^5 N/m² - 1.197 ×10^(-4) N/m²
⇒ 6.99 N/m²
Hence the New Pressure of the tire is 6.99 N/m²
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Which of the following settings describe a displacement vs time graph that looks like this
Answer:
Image result for Which of the following settings describe a displacement vs time graph that looks like this
Displacement time graph for rest is a straight line with zero slope. Displacement time graph for uniform motion is a straight line with non-zero slope. Displacement time graph for uniform acceleration is a parabola. The three scenarios are shown in the attached plot.
Explanation:
i. ii. iii. An object travels from the rest with a constant acceleration of 10m/s². Determine the speed v at the end of 10s. the average speed for the 10s interval. the distance covered after 10s
20m/s is the average speed for the 10s interval
Given, a=10m/s 2u=0m/s (dropping)
t=2secSo, v=u+at=0+10(2)=20m/s
Velocity after 2sec=20m/s
Acceleration is it always the same?There will always be non-zero acceleration whenever there is a change in velocity, whether it is brought on by a change in speed or a change in direction. Stephen J If the net force is not constant, acceleration is not constant either.
When motion is accelerated continuously, the speed rises by the same amount every second. Free fall is the most illustrative and significant example. Gravity causes a constant acceleration when anything is thrown or dropped, with a constant value of around 10 metres per second squared.
When the magnitude and direction of the rate at which an item is changing its location stay constant, the object has constant velocity.
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is the density of an object always the same as its mass?
Responses
yes
no
A golf ball and a ping pong ball might be about the same size and shape. Which measurement would be similar?
Responses
mass
density
volume
weight
Earth's atmosphere, which traps heat and radiation from the sun, makes temperature more unstable, even when we are rotated away from the sun at night.?
Responses
True
False
Liquid water and a protective atmosphere are examples of:
Responses
Factors that all planets in our solar system have
Factors that allow for life on Earth
Factors that the Earth does not have
Which example is an organism?
Responses
a rattlesnake
a colony of ants
a population of butterflies
Which ability do all organisms have?
Responses
quickly escaping from predators
changing shape to blend into their surroundings
reproducing
consuming other organisms
Which characteristic of life is demonstrated by sweating?
Responses
ability to growability to grow,
ability to reproduce
ability to maintain structure and balance (homeostasis)
ability to breathe
What characteristic of life is demonstrated when you shiver to warm up your body?
Responses
maintaining homeostasis
acquiring energy
reproducing
Which term refers to the action an organism takes due to a change in the environment?
heredity.
stimulus
response
metabolism
The leaves on a green plant soak up sunlight to make food. A cow's stomach digests grass that was eaten.
Which characteristic of life do these examples demonstrate?
Responses
heredity
growth
homeostasis
metabolism
this is for Science
The answers include the following:
The density of an object always the same as its mass - false.A golf ball and a ping pong ball might be about the same size and shape therefore the measurement which would be similar is volume.Earth's atmosphere, which traps heat and radiation from the sun, makes temperature more unstable, even when we are rotated away from the sun at night is false.Liquid water and a protective atmosphere are examples of factors that allow for life on EarthA rattlesnake is an example of an organism.The ability to reproduce is what all organisms have.Ability to maintain structure and balance (homeostasis) is demonstrated by sweating. Maintaining homeostasis is the characteristic of life is demonstrated when you shiver to warm up your body.Stimulus is the action an organism takes due to a change in the environment.The leaves on a green plant soak up sunlight to make food and a cow's stomach digests grass that was eaten is referred to as metabolism.What is Photosynthesis?This is the process in which green plants manufacture food in the presence of sunlight and is a type of metabolic reaction.
Other examples of metabolic reactions include digestion process which involves a cow's stomach digests grass that was eaten.
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If a scientist was investigating the affect of pH on plant growth, what are things that should be held constant? Check all that apply.
Question 3 options:
The amount of water given to the plants each day.
The length of time each plant is exposed to light.
The temperature where the plants are stored.
The type of plant that is tested.
The things that should be held constant are the amount of water given to the plant each day, the length of time each plant is exposed to light and the temperature where the plants are stored.
What is a pH scale?Using a pH scale, acids and bases can be determined. The scale has a 0 to 14 range. In order to detect whether a chemical is an acid or a basic, Litmus paper is employed as an indication. The color of the paper, which corresponds to the numbers on the pH scale, indicates the type of chemical being tested. For instance, vinegar, which has a pH of 2.4, is an acid.
Now, according to the question,
The concentration of carbon dioxide in water affect the pH of the plant, so it depends on that how much water is given to the plant. The temperature also affect the pH of the plant so, the length of time each plant is exposed to light and the temperature where the plants are stored will also affect the pH on plant growth that's why these things should be held constant.
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In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which consists of protons with an energy of 2.8×10−11J, has a current of 80 nA. The protons in the beam mostly come to rest within the tumor. The radiologist has ordered a total dose corresponding to 3.6×10−3J of energy to be deposited in the tumor. How long should the beam be in order to deliver the required dose?
The number of protons that strike the tumor each second is [tex]1.7*10^8[/tex] protons.
What is proton beam therapy?Since it do not produce proper outcomes, proton beam therapy is only appropriate for certain types of cancer, such as highly complex brain, head and neck cancers, and sarcomas.
Here, it is mentioned that
Energy of proton = [tex]2.8*10^{-11}[/tex] Joules.
Current = 84 nA = [tex]84*10^{-9}[/tex] Ampere.
As well as
Energy of total dose = [tex]3.4*10^{-3}[/tex]
The quantity of charge per unit time is mentioned as:
Q = It = Ne
Number of proton (N) = Q/e
[tex]N=\frac{2.8*10^{-11}}{1.602*10^{-19}}[/tex]
[tex]N=1.75*10^8[/tex]
Thus, this is the number of proton in the given scenario.
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Kinematics time question
For any physics free fall problem, a student is taught that the velocities on a graph have the same magnitude as those that are horizontally equivalent. For example, if you have two points that are both at the same height during free fall, one will be positive and the other will be negative--but they will be of the SAME magnitude.
Let's say we have a problem where an object was launched with a positive initial velocity in the upward direction. All we would have to do is change that upward initial velocity to downward (making it negative). Everything else stays the same, such as gravity.
Now here is the part where I get a bit confused. Why can we simply just use the inverse of the initial velocity without taking into account the time that has passed? Doesn't time start once the object leaves the starting point? If this is true, why can we use the same time for the kinematic equations?
The same kinematics equation is used to calculate initial velocity because the time taken to get to that point is the same time taken for the object to fall. Also, the acceleration due to gravity is constant only changing sign due to the direction of the motion.
What is kinematics?Kinematics is the study of the movement or motion of objects as well their forces that cause the motion.
Kinematics studies the interaction between forces that cause motion and the various forms of motion of the objects acted upon by the force.
Examples of kinematics include:
firing an arrowshooting a footballhitting a baseball with a baseball batThe following terms are terms involved in kinematics:
speed- this is the distance covered per unit time by a moving body.velocity- this is the displacement of a body per unit timeacceleration - this is the change in velocity of a body per unit time.In kinematics, a form of motion where a body is falling freely under gravity is known as free fall.
For a body undergoing free, its velocity could either be negative or positive depending on the direction of motion.
For a body moving against gravity, its velocity is negative whereas for a body falling to the earth, its velocity is positive.
For a body falling freely under gravity, its velocity is the same as gravity accelerates the body to a constant value of 9.81 m/s².
The time taken to get to that height above the ground is the same time it will take the objects to fall to ground.
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N
5
+5 +11
B
10
To
20
D
30
Hint: Fine the slop for each line to determine the speed
time (sec)
40
A
G
10
4
On this graph, positive positions and directions of travel are considered to be North.
1. During which time interval (AB, BC, CD, DE, EF, FG) was the cart traveling at its greatest speed?
2. During which time interval(s) (AB, BC, CD, DE, EF, FG) was the cart at rest?
3. During which time interval(s) (AB, BC, CD, DE, EF, (FG) did the cart travel in a negative direction?
4. What was the cart's instantaneous speed at 6 seconds?
5. What was the cart's instantaneous speed at 22 seconds?
6. What was the cart's instantaneous speed at 40 seconds?
7. Describe the cart's behavior between 18 and 32 seconds. (location, speed, direction of travel, and distance traveled
Answer:
h
Explanation:
1) FG
Explanation:
During which time interval (AB, BC, CD, DE, EF, FG) was the cart traveling at its greatest speed?