Please identify the type of inference happening at letter A and the type of interference happening at letter B. If this was a sound wave, which (A or B) do you think would be louder and why?

Please Identify The Type Of Inference Happening At Letter A And The Type Of Interference Happening At

Answers

Answer 1

Answer:

B i think

Explanation:

B because it travels in the same wavelentgh.............

[tex]gjkrejktg[/tex]

Answer 2

Type A is constructive interference and Type B wave gives destructive interference. The constructive interference would be louder.

What is interfernece?

Interference can be described as a natural phenomenon that occurs at every place and at every moment. Interference can be defined as the phenomenon in which two waves superpose to produce the resultant wave of the lower, higher, or same amplitude. Light waves are produced randomly by most of the sources.

The interference of light from the soap bubble which reflects colors when illuminated by a light source. The starting point of the wave produced may be a maximum or a minimum,  and there is no way to predict which phase the wave will start.

Interference can either be constructive interference or destructive interference. Constructive interference occurs when the crest of one wave falls on the crest of another wave and the amplitude is maximum.

In destructive interference, when the crest of one wave falls on the trough of another wave and the amplitude is minimum. The phase and displacement of these waves are not the same.

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Related Questions

A positive ion is called a ____________ and a negative ion is called an

Answers

Answer:

Cation

Explanation:

Best way to remember this one is a CATion is PAWS-itive!

A train is traveling at a speed of 80\,\dfrac{\text{km}}{\text{h}}80 h km ​ 80, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction when the conductor applies the brakes. The train slows with a constant acceleration of magnitude 0.5\,\dfrac{\text{m}}{\text{s}^2}0.5 s 2 m ​ 0, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. We want to find the distance the train travels from the time the conductor applies the brakes until the train comes to a complete stop. Which kinematic formula would be most useful to solve for the target unknown? Choose 1 answer:

Answers

Answer:

The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters

Explanation:

The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22.[tex]\bar 2[/tex] m/s

The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²

Therefore, we have the following suitable kinematic equation of motion;

v² = u² - 2 × a × s

Where;

v = The final velocity = 0 (The train comes to a stop)

s = The distance the train travels before coming to a stop

Substituting the  values gives;

0² = 22.[tex]\bar 2[/tex]² - 2 × 0.5 × s

2 × 0.5 × s = 22.[tex]\bar 2[/tex]²

s = 22.[tex]\bar 2[/tex]²/1 = 493 67/81 m = 40/81 km

The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.

Answer:

v^2=v0^2+2aΔx

Explanation:

cuz khan academy says so

please help lol
im also on my sisters acc btw

Answers

Answer:

D. Smooth muscle

Explanation:

Smooth muscle is a type of muscle tissue which is used by various systems to apply pressure to vessels and organs. Smooth muscle is composed of sheets or strands of smooth muscle cells. These cells have fibers of actin and myosin which run through the cell and are supported by a framework of other proteins.

Can I get brainliest please since I have enough explanation

Help on this pls. !!!!!

Answers

Answer:

C

Explanation:

what are the 5 destructive tests used in fiber analysis

Answers

Most common are destructive tests, such as stress, fatigue and micro sectioning tests. There are also methods that allow non-destructive testing (NDT), so the material can be still be used after testing. Common methods are ultrasonic, X-ray, HF Eddy Current, Radio Wave testing or thermography.

John has an object suspended in the air. It has a mass of 50 kilograms and is 50 meters above the ground. Calculate the objects potential energy.

Answers

Answer:

the objects potential energy is 24500 J.

hope this helps <3

characteristics of radiation from the sun's energy would be

A. heat from a distance source, elcetromagnatic waves and energy that travels through space.
B. Direct contact of the energy source of sufaces
C. Movement of heat through fluids
WHICH ONE IS THE ANSWER HELPPP

Answers

Answer:

Answer is A

Explanation:

The number of waves that pass a given point in a second is___.

1- amplitude
2- wavelength
3- frequency
4- wave speed

Answers

Answer:

Frequency

Explanation:

The frequency ( ) of a wave is the number of waves passing a point in a certain time.

Which of the following best describes a hypothesis?
O A. A question that scientists study
B. A possible answer to a scientific question
C. An explanation supported by many observations
O D. A list of scientific data

Answers

I am 99% sure it is B :)

Answer:

B. A possible answer to a scientific question

Explanation:

It's usually a possible or testable explanation made on the basis of limited evidence as a starting point for further investigation.

HELP NEEDED ASAP I'M GIVING BRAINLIEST

1) Select the best answer from the choices below. Light has many properties of waves, but sometimes it also behaves like:


a

A photon

b

Polarized light

c

Ultraviolet rays

d

A stream of particles


2) What type of waves transmit signals in satellite communication?

a
Microwaves
b
X-rays
c
Gamma Rays
d
Radio Waves

3) Cell phones use digital signals to send and receive information. These digital signals travel as what kind of wave?

a
Gamma rays
b
X-rays
c
Microwaves
d
Radio waves

Answers

Answer:

1.

d . A stream of particles

2. D. Radiowave

3. Microwaves

Answer:

1.

d . A stream of particles

2. D. Radiowave

3. Microwaves

Explanation:

Imagine you are running PE class. You run the first 1000 meters in 3 minutes and then get tired and run the last 600 meters in 5 minutes. What was your *average* speed?

Answers

Answer:

Va = 3.77 [m/s]

Explanation:

We know that speed is defined as the relationship between the distance traveled in a given time.

v = L/t

where:

v = speed [m/s]

L = distance = 1000 [m]

t = time = 3 [min] = 180 [s]

Therefore the first speed is:

v = 1000/180

v = 5.55 [m/s]

Now the second velocity:

t = 5 [min] = 300 [s]

v = 600/300

v = 2 [m/s]

The average speed is calculated by the sum of both speeds divided by two.

Va = (5.55 + 2) /2

Va = 3.77 [m/s]

A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances friction *


Fg sin 36 degrees
Fg cos 36 degrees
Fg tan 36 degrees
Fg x N

Answers

Given :

A box weighing 12,000 N is parked on a 36° slope.

To Find :

What will be the component of the weight parallel to the plane that balances friction.

Solution :

The component of that will be parallel to the plane to balance friction is :

[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]

Therefore, component of force to balance friction is F sin 36° .

Hence, this is the required solution.


W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m

Answers

Answer:

0.73m

Explanation:

Given parameters:

W1  = 220N

D1  = 0.6m

W2 = 180N

Unknown

D2 = ?

Solution:

The torque on each side must be balanced;

 Torque  = force x distance

     T₁   = T₂  

  W1  x D1  = W2 x D2

Insert the parameters and solve for D2;

   220 x 0.6  = 180 x D2

     132  = 180D2

     D2 = [tex]\frac{132}{180}[/tex]   = 0.73m

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground. If the kinetic frictional force between the plow and the field is 250 N. What is the Normal Force from the ground onto the plow? And what is the acceleration of the plow?

Answers

Given :

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground.

The kinetic frictional force between the plow and the field is 250 N.

To Find :

The Normal Force from the ground onto the plow.

The acceleration of the plow.

Solution :

Normal force = mg + F sin Ф

= 75×10 + 700 × sin 35°

= 1151.50 N

Now,

ma = 700 cos Ф - 250

75×a = 323.4

a = 4.31 m/s²

Hence, this is the required solution.

If no work is done, the total energy is not changed. In that situation, if the kinetic energy changes, what must happen to the potential energy?

Answers

Answer:

the potential energy will also change

Explanation:

kinetic energy and potential energy are inversely proportional to each other, so if kinetic energy changes, potential energy will also change..

John walks four kilometers east, two kilometers north as shown in the diagram below. What is John’s displacement

4 km

11 km

2 km north

7 km east

Answers

not 100% positive, but i believe 7 km east?
I think its 7 km east

A motor with a resistance of 320 is connected to a voltage source. Four amps of current flows
in the circuit. What is the voltage of the source?
I

Answers

Answer:

V = 1280 [V]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.

Therefore we have:

V = I*R

where:

V =  voltage [V] (Units of volts)

I = current = 4 [amp]

R = resistance = 320 [ohms]

V = 4*320

V = 1280 [V]

i would appreciate it if u would answer

Answers

Answer:

A) Kinetic energy and gravitational energy

Explanation:

The blimp has kinetic energy, because it is moving. When it circles the event, it gains and uses kinetic energy. It also has potential energy because it has the potential to go a lot faster, and because it has so much stored energy and pressure.

Hope this helps!

What is the potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high?

Answers

PE = mgh, g= 9.8 m/s^2
10 kg * 9.8 m/s^2 * 300 m
= 29400 J

The potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high is 29400J

POTENTIAL ENERGY:

Potential energy refers to the energy due to the position of an object. It can be calculated by using the following formula:

P.E = m.g.h

Where;

m = mass of the rock

g = gravitational force of Earth (9.8m/s²)

h = height (m)

According to this question, a rock weighs 10.0 kg and is sitting on top of a hill 300 meters high. The potential energy can be calculated as follows:

P.E = 10 × 9.8 × 300

P.E = 29400J

Therefore, the potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high is 29400J.

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Which statement is correct about two objects that have gravitational force?
They have mass.
They move slowly.
They are round in shape.
They have high temperature.



Answers

Answer:

1 and 2

Explanation:

The formula itself has nothing to do with shape or temperature. The formula does have mass and the speed depends on the how great the mass/radius is.

They have mass
They move slowly
A and B

3. A ball rolls along the floor with a constant velocity of 12 m/s. How far will it have gone
after 6 seconds?

Answers

Answer:

the answer is 49 ms do yeah

Answer:

72

Explanation:

hehe

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds.
Determine the acceleration of the car and the distance traveled.

Answers

Answer:

79.8 is the answere

I hope this HELP :)

Explanation:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad,

(46.1)

2

−(18.5)

2

=2(11.17)d

⟹ d=79.8m

kinetic energetic plus potential energy is called

Answers

Object mechanical energy

Which type of carbohydrate is the body unable to digest, but is still important for lowering cholesterol, balances glucose levels, and helps prevent overeating.

Answers

Answer:

Cellulose

Explanation:

Cellulose is the carbohydrate which is unable to be digested by body. Adding fiber's (cellulose)  to one's diet reduces blood cholesterol level because soluble fiber  dissolves in water to form a gel, which moves slowly through the intestines binding up fat, dietary cholesterol, bile salts, and sugar to be excreted. Once excreted, these are no longer available to build more cholesterol. Also cellulose remains undigested but is effectively making one gain more calories, so it helps prevents over eating.

Which statements accurately describe matter

Answers

I hope it is helpful for you ...

A periodic wave is a wave that follows a repeating pattern as it propagates through space. That is, the oscillating pattern repeats at regular intervals of time. This repeating motion is also known as periodic motion

Answers

Answer:

Simple harmonic motion

Explanation:

What is simple harmonic motion?

"Simple harmonic motion is a type of motion directed along a straight line, whose acceleration is fixed towards a point  and is proportional to its distance from that point"

An object is said to be in simple harmonic motion if the following occurs:

• It moves in a uniform path.

• A variable force acts on it.

• The magnitude of the force is proportional to the displacement of the mass.

• The force is always opposite in direction to the displacement direction.

• The motion is repetitive and a round trip, back and

  forth, is always made in equal time periods

which statement is correct about the effectiveness of carbon dating

Answers

Answer:

b

Explanation:

Statement is correct about the effectiveness of carbon dating is that It only works for organisms that died less than about 60,000 years ago.

What is carbon dating?

Even though the plant or animal stops absorbing when it dies, the radioactive carbon it has stored keeps on degrading. Estimating how much is left over allows one to determine how long something has been dead.

The moss was determined to have been frozen for more than 1,500 years based on carbon dating. Now, if other evolutionary ways of dating are consistent with carbon dating, the scientists may have made a significant discovery. However, when used in isolation, carbon dating is at best unreliable and at worst, blatantly wrong.

Statement is correct about the effectiveness of carbon dating is that It only works for organisms that died less than about 60,000 years ago.

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Lucia kicks a ball on a level playing field with an initial velocity of 11.3 m/s at an angle of 35° above the horizontal. Find: Time of flight? Horizontal distance traveled? Maximum height?

Answers

Explanation:

Given that,

Initial velocity, u = 11.3 m/s

Angle above the horizontal, [tex]\theta=35^{\circ}[/tex]

Time of flight :

[tex]t=\dfrac{2u\sin\theta}{g}\\\\t=\dfrac{2\times 11.3\times \sin(35)}{9.8}\\\\t=1.32\ s[/tex]

Horizontal distance traveled  is given by :

x = ut

x = 11.3 m/s × 1.32 s

x = 14.916 m

Maximum height is given by :

[tex]H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(11.3)^2\times \sin^2(35)}{2\times 9.8}\\\\H=2.14\ m[/tex]

Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.

A bugatti chiron travels 116 m/s for 10 seconds.how far did it travel

Answers

Answer:

V=  1,160 m

Explanation:

formula:

            V=  V*  T

remplazamos:

V= 116m /s * 10s

V=  1,160 m

Answer:

V=  1,160 m

Explanation:


Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​

Answers

Answer:

The range is 35.35 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and [tex]g=9.8m/s^2[/tex] the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

[tex]\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}[/tex]

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

[tex]\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ )}{9.8}}[/tex]

[tex]\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}[/tex]

[tex]d=35.35\ m[/tex]

The range is 35.35 m

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