The distance between Ricardo and Jane :
a) 24.33 m of distance.
b) 34.55° east of the south.
Evaluating the equation given :
Now that we all know what we need to do in this question, let's head for each part of the problem.
a) Distance between Ricardo and Jane
In this case, we'd like to analyze the given data:
Ricardo (which we'll call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 13 m at 30° south of west. therefore the distance between them, are going to be the point where they both stop and face each other.
Let's call the space between them as "D", to urge the distance of D, consistent with the picture will be:
D = J - R (1)
However, as they're facing in different angles and directions, we cannot do the difference of their values distance a bit like that. so as to do that, we'd like to calculate the components in the "x" and "y" axis of each vector. therein way, we will get the components of x and y of the Distance D, and then, the full distance between them will be:
D = √Dx² + Dy² (2)
So, let's get the components of x and y of R and J.
For Ricardo (R):
Rx = R sin60° = 28 sin60°
= -24.25 m
Ry = R cos60° = 28 cos60°
= 14 m
The sign "-" it's because R it's on the second quadrant, therefore in x, we'll need to add the negative.
For Jane (J):
Jx = J cos30° = 13 cos30°
= -10.39 m
Jy = J sin30° = 13 sin30°
= -6.5 m
Again, the negative is added because J is on the third quadrant.
Now that we've the components, let's calculate vector D using expression (1):
Dx = -10.39 - (-24.25) = 13.86 m
Dy = -6.5 - 14 = -20.5 m
Now, using expression (2) we will finally know the distance between Jane And Ricardo:
D = √(-20)² + (13.86)²
D = 24.33 m
This is the distance between Jane and Ricardo.
b) Direction of Ricardo walking to Jane
In this case, we have already got the components of x and y of the distance between them, so, to understand the direction:
Tanα = Dy/Dx
α = tan⁻¹ (Dy/Dx)
Replacing the values we have:
α = tan⁻¹ (-20/13.86)
α = 55.45°
Which should south of east or:
β = 90 - 55.45
β = 34.55°
Ricardo should walk 34.55° east of south
The question is incomplete. the full exercise is the following:
"Ricardo and Jane are standing under a tree within the middle of a pasture. An argument ensues, and that they walk away in different directions. Ricardo walks 28.0 m during a direction 60.0° west of north. Jane walks 12.0 m during a direction 30.0° south of west. They then stop and switch to face each other.
(a) what's the distance between them?
(b) In what direction should Ricardo walk to travel directly toward Jane?"
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If the speed doubles, by what factor must the period change if is to remain unchanged?
You have to double the period as well in order to keep it unchanged.
Concept of speedSpeed is calculated as follows: speed = distance * time. Knowing the units for distance and time is necessary to calculate the units for speed.
The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in seconds (s).
What is the formula for speed?The formula for speed is as straightforward as dividing a distance by a time.
To calculate speed, divide the distance travelled (say, 3 metres) by the passing time (say, 3 seconds) (one metre per second).
So, the rate at which an object’s position changes in any direction can be defined as speed.
The speed formula is as follows: [Speed = Distance]
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What is the final speed?
Answer:
30 m/s
Explanation:
We can first list out the 3 kinematics equations:
[tex]v = u + at \\ {v}^{2} = {u}^{2} + 2as \\ s = ut + \frac{1}{2} a {t}^{2} [/tex]
Where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
s is the displacement
With all the 3 equations, we can now list the values needed for the first part of the question which is to find the acceleration for this first part.
Given:
v = 14 m/s
u = 6 m/s
t = 8s
We can use the first kinematics equation to solve for a. (v = u + at)
14 = 6 + a x 8
14 = 6 + 8a
8a = 14 - 6
8a = 8
a =
[tex]1 \frac{m}{ {s}^{2} } [/tex]
Now with this acceleration, we can find the final speed for the second part of the question by using the same kinematics equation. (v = u + at)
Given,
u = 14 m/s
t = 16 s
a =
[tex]1 \frac{m}{ {s}^{2} } [/tex]
v = 14 + (1)(16) = 14 + 16 = 30 m/s
the resistance of two conductors of equal cross-sectional area and equal lengths are compared, and are found to be in the ratio 1:2. the resistivity of the materials from which they are constructed must therefore be in what ratio?
The resistivity of the materials must be constructed in ratio A₂ = 2A.
What is Resistivity?
The resistance of a wire can be defined as
R = ρL/A
Where,
ρ is Resistivity
L is Length of the conductor
A is Area of cross section of the conductor.
R₁/R₂ = (L₁/L₂) × (A₂/A₁) ----> rearranging it for A
A₂ = (R₁/R₂) × (L₂/L₁) × A₁
A₂ = (R/R) × (2L/L) × A
A₂ = 2A
Therefore, cross section area of another conductor must be 2A.
The strength with which a substance resists electric current is known as electrical resistivity, which is a fundamental attribute of materials. A substance that permits electric current to flow easily has a low resistance. The Greek letter is often used to symbolize resistivity. The ohm-meter is the SI unit used to measure electrical resistivity.
A substance's ability to resist the flow of current, or electrons, can be characterized as a physical attribute. A specific substance with specific dimensions is distinguished by its physical property of resistivity.
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1. Initial velocity=0 km/h
Final velocity=24 km/h
Time=3 seconds
2. Initial velocity=0 km/h
Final velocity=35 m/s
Time=5 seconds
3. Initial velocity=20 km/h
Final velocity=60 km/h
Time=10 seconds
4. Initial velocity=50 m/s
Final velocity=150 m/s
Time=5 seconds
What is the acceleration for each problem?
The accelerations for each problem are:
1. 2.22m/[tex]s^{2}[/tex]
2. 7m/[tex]s^{2}[/tex]
3. 1.45m/[tex]s^{2}[/tex]
4. 20m/[tex]s^{2}[/tex]
What is acceleration due to gravity?The acceleration which is gained by the object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/[tex]s^{2}[/tex]. Acceleration due to gravity is a vector, which means it has both magnitude and direction. The acceleration due to gravity at the surface of the Earth is represented by letter g. It has standard value defined as 9.80665 m/s2 (32.1740 ft/s2). However, actual acceleration of a body in free fall varies with location.
1. Initial velocity=0 km/h
Final velocity=24 km/h= 6.66m/s
Time=3 seconds
acceleration =[tex]\frac{6.66-0}{3}[/tex]=2.22m/[tex]s^{2}[/tex]
2. Initial velocity=0 km/h
Final velocity=35 m/s
Time=5 seconds
acceleration = [tex]\frac{35-0}{5}[/tex]=7m/[tex]s^{2}[/tex]
3. Initial velocity=20 km/h=5.55[tex]m/s^{2}[/tex]
Final velocity=60 km/h= 20m/[tex]s^{2}[/tex]
Time=10 seconds
acceleration= [tex]\frac{20-5.55}{10}[/tex]= 1.45m/[tex]s^{2}[/tex]
4. Initial velocity=50 m/s
Final velocity=150 m/s
Time=5 seconds
acceleration= [tex]\frac{150-50}{5}[/tex]= 20m/[tex]s^{2}[/tex]
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you're driving down the highway late one night at when a deer steps onto the road in front of you. your reaction time before stepping on the brakes is , and the maximum deceleration of your car is
The distance between you and the deer when you come to a stop is
s = d - 30 = 18 m.
The maximum speed you could have and still not hit the deer is
v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]
= 26m/s
What is the distance between you and the deer?You're driving down the highway late one night at 20m/s when a deer steps onto road d in front of you.
Your reaction time before stepping on the brakes is 0.50s and the maximum deceleration of your car is 10m/s2.
Given,
Speed = 20m/s
Time = 0.50 s
Distance = d
Deceleration = 10m/s2
D = R × T
D = Vi × Tr
D = (20 m/s) × (0.50 s)
D = 10 m
Dd = [ Vf^2 - Vi^2 ] / [ 2 × (-10 m/s^2) ]
Dd = [ (0.0 m/s)^2 - (20 m/s)^2 ] / (-20 m/s^2)
Dd = [ -400 m^2/s^2 ] / (-20 m/s^2)
Dd = 20 m
The total distance traveled is
Dt = D + Dd
Dt = (10 m) + (20 m)
Dt = 30 m
The distance between you and the deer when you come to a stop is
s = d - 30 = 18 m.
The maximum speed you could have and still not hit the deer is
v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]
= 26m/s
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Help me please for Number 1
The mass of the object is obtained as 130 g.
What is the tripe beam balance?The triple beam balance is the kind of balance that could be used to measure the mass of a substance. There are so many kinds of balance that could be used in science and these include;
1) beam balance
2) Spring balance
3) unequal arm balance
We read the mass of the object by looking at all the points that we have set on the triple beam balance to achieve the balance point. In the case of the substances that we have seen in the image of the question, the mass of the object is obtained as 130 g.
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which of the statements regarding displacement is true? displacement is a scalar quantity just as length. displacement depends on the chosen origin of coordinates. displacement has the same meaning of distance. displacement tells the average direction of motion. displacement depends on time elapsed during the motion.
The statement "displacement tells the average direction of motion" regarding displacement is true.
What is velocity?Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.
A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.
Average velocity is calculated by taking the displacement vector from the start and end-point of an object’s path, and dividing its magnitude by the time interval. The average velocity always has the same direction as that displacement vector.
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What are gears? Gears are wheels Gears are ramps with teeth Gears are wheels with teeth Gears are twisted ramps
A device that regulates how much engine power flows to a machine's moving parts, frequently made of connected sets of wheels with teeth around the edges. Hence, option C is correct.
What is Gear?A gear is a spinning, circular machine element with teeth that can be cut, or in the case of a cogwheel or gearwheel, they can be inserted. These teeth, known as cogs, mesh with another toothed part to transmit (convert) torque and speed. The fundamental idea underlying how gears work is comparable to the fundamental idea behind how levers work. Cog is another casual term for gear. A power source's speed, torque, and direction can all be altered by geared devices.
So, the exact definition of gear is that gears are wheels with teeth.
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Answer:
Gears are wheels with teeth
The disadvantages of _____ telescopes include chromatic aberration and longer size.
The disadvantages of refractive telescopes include chromatic aberration and longer size.
This was the telescope developed by Newton in 1668.It is the simplest type of telescope which has a tube with lenses on both ends. The light enters through the lens on the farther end of telescope. The light is refracted to a point near the lens on the near end. It is then then further magnified when seen through the lens on the eyepiece.
Even though it was more reliable, it was really heavy and had a larger aperture and longer body. Since high quality lenses were costly to make, cheaper lenses were used mostly. So there was chromatic aberration.
Therefore, the disadvantages of refractive telescopes include chromatic aberration and longer size.
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a vector is 55.1 m long pointing in a 13.9 degree angle
The y-component of the vector is 13.24 m.
What is vector component?Vector components allow us to break a single vector quantity into two or more scalar quantities with which we have more mathematical experience.
The two component of a vector include;
y-component of the vectorx-component of the vectorWhat is x-component of a vector?The component of a vector that acts in horizontal direction is known as x-component of the vector.
What is y-component of a vector?The component of a vector that acts in vertical direction is known as y-component of the vector.
The y-component of the vector is calculated as follows;
Vy = V sinθ
Vy = 55.1 m x sin(13.9)
Vy = 13.24 m
Thus, the y-component of the vector is 13.24 m.
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The complete question is below:
a vector is 55.1 m long pointing in a 13.9 degree angle. Find the y-component of the vector.
Are masks effective in slowing the spread of COVID-19? In a few sentences, make a hypothesis and design and describe an experiment on how you could TEST this yourself using common household materials.
Answer:
Not really, because wearing a mask can lower your immune system and covid can be caught like any other virus body contact and body fluids. So since you can still get it through those ways then you're going to get it and be worse off than if you don't wear a mask.
you can test this by not wearing a mask and see how not bad it is catching covid over getting it while you wear a mask.
Explanation:
Answer:
Yes
Explanation:
Hypothesis- if masks are used to protect yourself from Covid-19 then the spread of the virus will decrease
You could test this by:
Getting a mask and using materials such as shampoo, soap, honey, glue, or (safe) chemicals to see how much the masks absorbs the materials. By doing so you can show how the mask can help block certain materials from entering or leaving the mask area therefore slowing the spread of Covid.
By deflecting cathode rays with a magnetic field thomson was able to measure what property of electrons?.
The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.
What property of the electron did Thomson measure?
J.J. Thomson measured the electron's mass in terms of its physical characteristics.Similar experiments were conducted with cathode rays and magnets by William Crookes, who came to the conclusion that cathode rays were made up of negatively charged molecules based on his observations of the rays' deflection by magnetic fields.J.J. Thomson used a Crookes, or cathode ray, tube to conduct experiments that discovered the electron in 1897. He provided evidence that cathode rays have a negative charge.The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.
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PLEASE HELP
Obtain expressions in component form for the position vectors having the following polar coordinates.
After conversion into cartesian coordinates, we can write the position vectors as -
a) → r = 12.4 m , θ = 170° ↔ - 12.21 i + 2.15 j
b) → r = 4 cm , θ = 50° ↔ 2.57 i + 3.06 j
c) → r = 20 inches , θ = 210° ↔ - 17.32 i - 10 j
What are cartesian coordinates?Cartesian coordinates are two-dimensional coordinates which are used to represent a point in X-Y plane. They are, in general, written in the form (x, y), such that x is the horizontal distance of point from origin and y is the vertical distance of point from origin.
Given are the position vectors in polar coordinates of three points in X-Y coordinate system.
It is important to remember the following relations, in order to transform from polar coordinates (r, θ) into cartesian coordinates (x, y) -
x = r cosθ
y = r sinθ
a) → r = 12.4 m , θ = 170°
x = 12.4 x cos (170°) = 12.4 x -0.98480775301 = -12 .21
y = 12.4 x sin (170°) = 12.4 x 0.17364817766 = 2.15
In cartesian form → ( -12.21 i + 2.15 j )
b) → r = 4 cm , θ = 50°
x = 4 x cos (50°) = 4 x 0.64278760968 = 2.57
y = 4 x sin (170°) = 4 x 0.76604444311 = 3.06
In cartesian form → ( 2.57 i + 3.06 j )
c) → r = 20 inches , θ = 210°
x = 20 x cos (210°) = 20 x -0.86602540378 = -17.32
y = 20 x sin (210°) = 20 x -0.5= -10
In cartesian form → ( -17.32 i - 10 j )
Therefore, in two - Dimensional cartesian system, we can write the position vectors as -
a) → r = 12.4 m , θ = 170° ↔ - 12.21 i + 2.15 j
b) → r = 4 cm , θ = 50° ↔ 2.57 i + 3.06 j
c) → r = 20 inches , θ = 210° ↔ - 17.32 i - 10 j
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Which of the following is not a pure form of a substance? a. Element b. Atom c. Molecule d. Mixture e. Compound
Suppose you go on a trip that covers 360 km and takes 6 Hours. What would your average speed be? 2. A car travels around a mountain. It travels a distance of 120 miles in 3 hours. What is the average speed of the car?
I need the answer for this and I want a step by step explanation on how you got the answer and if I need to use formulas.
Answer:
60 m/hStep-by-step
explanation:S = d/t
S= 360/60
S= 60
URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
Answer: A. use a thicker piece of wire.
Explanation:
Sameer went on his bike from Delhi to Gurgaon at a speed of 60km/hr and came back at a speed of 40km/hr. what is his average speed for entire journey.
The average speed for the entire journey is 48 km/hr.
The average speed is the sum distance which is traveled by the object in a particular time interval, as the average speed is a scalar quantity and it is presented by the magnitude and has no direction.
here the first speed v₁ is 60 km/hr and the second speed v₂ is the 40 km/hr .So, The formula we are referring to for calculating the average speed
S = 2v₁v₂/(v₁+v₂)
here, v₁+v₂ = 60+40 =100
Now substituting the desired values in the formula
= 2 x 60 x40/(100)
= 4800/100
= 48 km/hr
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One way to control avalanches is to send explosive charges to key areas on mountain slopes to trigger small avalanches before larger ones can build up. Norway, for instance, uses solar- powered launchers that fire pre-timed charges. Your launcher fires charges at an angle of 70 degrees from the horizontal and a speed of 200 m/s. If you fire a charge and it travels a horizontal distance of 300 m away from you, how high up the slope will it strike?.
By using uniform motion, the high up the slope will it strike is 730.62 m.
We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
θ = 70⁰
vi = 200 m/s
x = 300 m
Find the initial velocity in x and y axis
vx = vi cosθ = 68.40 m/s
vy = vi sinθ = 187.94 m/s
Find the time taken to reach 300 m
vx = x / t
68.4 = 300 / t
t = 4.39 second
Find the time taken to reach maximum height
vt = vo + a . t
0 = vy - g . t
vy = gt
187.94 = 9.8 . t
t = 19.18 second
The motion of projectile is raising to maximum height, hence
s = vo . t + 1/2 . a . t²
h = vy . t - 1/2 . g . t²
h = 187.94 . 4.39 - 1/2 . 9.8 . 4.39²
h = 730.62 m
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A piece of plywood in which several holes are being drilled successively has been secured to workbench by means of two nails. Knowing that the drill exerts a 15-n·m couple on the piece of plywood, determine the magnitude of the resulting forces applied to the nails for the given locations. The nails are located at b and c. The magnitude of the resultant is n
The magnitude of force applied to the nails when they are located between point A and B is 37.5 N.
The magnitude of force applied to the nails when they are located between point B and C is 62.5N.
The force applied to the nails when they are located between point A and C is 29.41N
The moment exerted by the drill machine is: M =15 N⋅m
(a) The magnitude of force applied to the nails when they are located between point A and B.
Fa=M/AB
AB is distance between points A and B.
Plug in all the values in the above equation.
Fa=15 N⋅m/450mm
=15 N⋅m/0.45m
=37.5 N
Therefore, the magnitude of force applied to the nails when they are located between point A and B is 37.5 N.
(b)The magnitude of force applied to the nails when they are located between point B and C.
Fb=M/BC
BC is distance between points B and C.
Substitute all the values in the above equation.
Fb=15 N.m/240mm
=15 N.m/0.24m
= 62.5N
Thus, the magnitude of force applied to the nails when they are located between point B and C is 62.5N.
(c) The distance between points AC is,
AC=√(AB)2+(AC)2
Plug in all the values in the above equation.
AC=√(450mm)2 +(240mm)2
=510mm
=0.51m
The magnitude of force applied to the nails when they are located between point A and C.
Fc=M/AC
Substitute all the values in the above equation.
Fc=15 N⋅m/0.51m
=29.41 N
Thus, the force applied to the nails when they are located between point A and C is 29.41N
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3) a current of 20 a passes through an oven’s heating element which has a resistance of 10 ω for 2.5 hours. determine the power input of the fireplace and the consumed electrical energy in kwh.
In a day, an electrical resistance heater uses 10 kW-h of electricity. In the same day, the heater delivers 9 kW-h of heat to the house in which it is located.
What is resistance ?A measurement of an object's resistance to the flow of electrical current is called electrical resistance. Electrical conductance, which gauges how easily an electric current moves, is its reciprocal quantity. Mechanical friction and electrical resistance conceptually have some similarities. Electrical resistance is measured in ohms (), the SI unit of electrical resistance, whereas electrical conductance is measured in siemens (S), also known as the mho (), the SI unit of electrical conductance.
An object's resistance is significantly influenced by the material it is constructed of. Electrical insulators like rubber typically have very high resistance and low conductance, whereas electrical conductors like metals typically have very low resistance and high conductance. Resistivity or conductivity are used to measure this relationship.
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A 25. 0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0. 250, and the coefficient of static friction is 0. 350.
The minimum angle at which the box starts to slip is 20.30°, the acceleration once the box has begun to move is 1.10 m/s2 and final velocity of the box is 3.41 m/s^2.
Given:
Mass of the box m = 25.2 kg
Acceleration due to gravity g = 9.8 m/s^2
Coefficient of kinetic friction between the ramp and box μk=0.25
Coefficient of static friction μs = 0.37
Part(A)
By inctreasing, parallel component of the weight will also increase but the force will decrease.
Let say θ be the angle of repose.
Now we know that
Ff= μs × mg × cosθ = mg × sinθ = Wp
Then we will get
θ = tan−1(μs)
θ = tan-1 (0.37) = 20.30 °
Part(B)
As the box starts sliding the frictional force becomes kinetic friction
The kinetic frictional force
F(k) = μ(k) x mg x cos(20.30)
= 0.25 × 25.2 × 9.8 × cos (20.30)
= 57.91 N
Now calculate the parallel component of the weight
W(p) = mg x sinθ
W(p) = 25.2 x 9.8 x cos (20.30)
= 85.68 N
Now calculate net force
F(net) = W(p) − F(k) = 85.68 − 57.91 = 27.77 N
Acceleration of the box
a = Fn/m = 27.77/25.2 = 1.10 m/s2
Part(C)
The box has moved a distance s = 5.3 m
The final speed of the box = v
Now
v = √ 2as
v = √ 2 x 1.10 x 5.3
v = 3.41 m/s^2
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The complete question is
A 25. 0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction is 0. 250, and the coefficient of static friction is 0. 350. Part A) As the angle θ is increased, find the minimum angle at which the box starts to slip. Express your answer using two significant figures. Part B) At this angle, find the acceleration once the box has begun to move. Express your answer using two significant figures. Part C) At this angle, how fast will the box be moving after it has slid a distance 5.3 m along the loading ramp? Express your answer using two significant figures.
What did gravity create when 99% of the gas and dust materials were gathered into the center of a flattened disc during the formation of the solar system?.
gravity created a solar nebula when 99% of the gas and dust materials were gathered into the center of a flattened disc during the formation of the solar system
The explosion of a flattened disc created waves in space that compressed the cloud of gas and dust. The cloud is all gravitationally bounded together.
As the cloud continued to fall inward, the center eventually became so hot that it became a star, the Sun, and blew away most of the new solar system's gas and dust with a powerful stellar wind.
This squeeze caused the cloud to begin collapsing as gravity pulled the gas and dust together to form the solar nebula.
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One way to control avalanches is to send explosive charges to key areas on mountain slopes to trigger small avalanches before larger ones can build up. Norway, for instance, uses solar- powered launchers that fire pre-timed charges. Your launcher fires charges at an angle of 70 degrees from the horizontal and a speed of 200 m/s. If you fire a charge and it travels a horizontal distance of 300 m away from you, how high up the slope will it strike?.
By using uniform motion, the high up the slope will it strike is 730.62 m.
We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
θ = 70⁰
vi = 200 m/s
x = 300 m
Find the initial velocity in x and y axis
vx = vi cosθ = 68.40 m/s
vy = vi sinθ = 187.94 m/s
Find the time taken to reach 300 m
vx = x / t
68.4 = 300 / t
t = 4.39 second
Find the time taken to reach maximum height
vt = vo + a . t
0 = vy - g . t
vy = gt
187.94 = 9.8 . t
t = 19.18 second
The motion of projectile is raising to maximum height, hence
s = vo . t + 1/2 . a . t²
h = vy . t - 1/2 . g . t²
h = 187.94 . 4.39 - 1/2 . 9.8 . 4.39²
h = 730.62 m
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You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
a. How long does it take the stone to reach the bottom of the cliff?
b. How far from the base of the cliff does the stone hit the ground?
c. What are the horizontal and vertical components of the stone’s velocity just before it hits the ground?
a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
from above statement we got
height = 78.4 m
since the ball is thrown, so its vertical velocity would be zero
u = 0
taking g = 9.8m/s^2
now, using the equation of motion
h = ut + gt^2/2
now putting all the values in it
we got ,
78.4 = 9.8 * t^2/ 2
by solving we got,
t = 4 sec
b) now, since along the horizontal , no force acting and accelaration is zero so
R = ut , R is RANGE
R = 5 * 4
range = 20 m
c) vertical components of the stone’s velocity just before it hits the ground = v sin θ =
horizontal components of the stone’s velocity just before it hits the ground = v cos θ
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You walk in a given direction for 20 m during the first 5 seconds of a trip and then 15 m during the next 2 seconds. your average speed is equal to :________
You walk in a given direction for 20 m during the first 5 seconds, your average speed is equal to 5m/s
How can I figure out average speed?Average speed is determined by dividing the total distance you travelled by the total time, whereas average velocity is determined by dividing your displacement (a vector pointing from your initial position to your end position) by the whole time.
What is the rate of an object’s motion?The amount of something that happens or changes in a unit of time is expressed as a rate.
The equation for speed is that Divide the distance an object travels by the time it takes to cover that distance to determine its speed. A unit of distance is divided by a unit of time in the speed equation.
CalculationThen Average speed = total distance / total time
= 20 + 15 / 5 + 2
= 35/7
= 5 m/s
The average speed is calculated as 5m/s
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1. A vehicle leaves Leeds at 8.00am and
arrives in Newcastle at 10.30am. If the
distance is 140 km, what was the average
speed of the vehicle?
The average speed with which the vehicle travels is equal to 56 Km/hr.
Velocity is measured as a vector quantity. There is a magnitude to it as well as a direction. The magnitude of velocity is measured by speed. The S.I. unit for this is the meter per second. Additionally, there are other units like km/h and km/s. Its dimensional equation is [LT-1].
The average speed of any vehicle is calculated over a given range of time. It is the total distance traveled by the vehicle in the given interval of time divided by the given time interval. It is a scaler quantity.
Average speed= Total Distance/ Time Taken
Given in the question
Distance = 140 km
Time of leaving Leeds = 8.00 am
Time of arriving Newcastle = 10.30 am
Time Taken = Time of arriving Newcastle - Time of leaving Leeds
= 10.30 - 8.00
= 2 hours and 30 minutes
So, the time taken is = 2.5 hr
Put in the values, we get
Average speed= Total Distance/ Time Taken
Average speed= 140/ 2.5 Km/Hr
Average speed= 56 Km/Hr
So, the average speed with which the vehicle travels is equal to 56 Km/hr.
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Does the intitial velocity of an object have anything to do with its acceleration?
Answer: Initial velocity is independent of the slope of the graph; that is, the acceleration. An object thrown downward still accelerates after release at the same rate as an object that is dropped.
Explanation: hope this helps
No.
A stone has the SAME acceleration whether you throw it down, throw it up, throw it sideways, or just drop it.
YOU decide the stone's initial velocity, but it always has the same acceleration after it leaves your hand.
A force of 32n is applied to an area of 12.8m2. work out the pressure
HELPPP MEEEEEEE
The pressure when 32 newtons of force is applied to an area of 12.8 m² is 2.5 Pascals.
The force applied per unit area is defined as pressure.. Its S.I. unit is Pascal. 1 Pascal is equal to one Newton of force applied over an area of one meter squared. Its dimensional formula is [[tex]ML^{-1}[/tex][tex]T^{-2}[/tex]].
Pressure is directly proportional to the force applied and inversely proportional to the area over which the force is applied. And it follows the Pascal law.
Pressure = Force/Area
Given in the Question
Force = 32 Newton
Area = 12.8 m²
Put in the values, we get
Pressure = 32/12.8
Pressure = 2.5 Pascals
Therefore, the pressure when 32 newtons of force is applied to an area of 12.8 m² is 2.5 Pascals.
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suppose you need to design a parachute system to help a remote camera land safely at the bottom of a cave. the camera will drop from a height of one story. it has a mass of about 500 g. a carton of eggs inside a box will model the camera. for your test to be successful, none of the eggs can break when the box lands. you may use string, plastic bags, paper, and any fabrics you have to make a model parachute.
The answer is hang glider.
What is the model?In high school, I created a project for a similar experiment that was accepted.
It matters what you carry the egg in because it is an egg, so something cushioned.
Use the fabric and cut the paper bag to make the kind of parachute I mentioned before.
When people go sky divining, they use a specific kind of parachute because the design is supposed to slow the fall and give them a chance to make a safe landing.
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an electrician needs to install a surface-mounted, nonmetallic, weatherproof cabinet on the outside of a concrete block building. since the cabinet must be mounted in a wet location, it must be mounted so there is at least in. of airspace between the cabinet and the wall.
Since the cabinet must be mounted in a wet location, it must be mounted so there is at least 1/4 of airspace between the cabinet and the wall.
What is airspace?The area of the atmosphere that is under the authority of a nation above its territory, including its territorial waters, or, more broadly, any particular three-dimensional area of the atmosphere
It is not the same as aerospace, the umbrella term for the Earth's atmosphere and the proximity of outer space.
Wherever it is deemed necessary for air traffic control to exercise any sort of direct executive oversight over aircraft operating there, that area of the sky is known as controlled airspace.
A range of areas and zones, including those where flying operations are either completely prohibited or subject to restrictions, may be included in the further division of airspace.
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