Step-by-step explanation:
[tex] \frac{f}{5} = - 8[/tex]
[tex]f = - 8 \times 5[/tex]
[tex]f = - 40[/tex]
Sohan and his sister ate 2/5 of 25 chocolates. How many chocolates they didn't eat?
4 is a rational number because it can be written as the fraction 4/1. True of false?
Answer:
true
Step-by-step explanation:
K
Order the numbers below from least to greatest.
1
2-3√6, -7,34
Choose the correct answer below.
O A.
2₁
7
OB. 7
O C. -3,
OD. -3,
7
4'
-
3.4, √6,-3
3.4, √6
7 1
42 √6,3.4
7 1
42.3.4, √6
Answer:
the anwser is B
Step-by-step explanation:
B is the best option choice given
Answer:
1. -7, -3, square root of 6, 2, 34
Step-by-step explanation:
transistors are used to build computer chips. The size of the earliest transistors
The number of times that the old transistor is bigger than the new ones in the computer is 1 × 10^6.
How to illustrate the information?It should be noted that the the side of the earliest form of transistors for computer was 1 × 10⁴.
Now, the size of the transistor today was illustrated as 1 × 10^-².
Therefore, the difference in size will be about:
= 1 × 10⁴ / 1 × 10^-²
= 1 × 10^6
Therefore, the number of times that the old transistor is bigger than the new ones in the computer is 1 × 10^6.
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Type an essay response to the following prompt. Completely explain all parts of your response and use the rubric to determine what you need to include in your essay. Describe a real-world situation in which opposite quantities combine to make zero.
A real-world situation in which opposite quantities combine to make zero is that "John bought 4 oranges and gave his friend 4 oranges. How many does he have?
How to illustrate the information?It should be noted that the information is that we should real-world situation in which opposite quantities combine to make zero.
An example will be that John bought 4 oranges and gave his friend 4 oranges.
The number of oranges that he has left will be:
= 4 - 4
= 0
Therefore, the combination gives zero.
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ASAP not that hard for 15 points
Answer:
24
Step-by-step explanation:
When 2 gallons of gasoline is added the tank goes from 1/6 full to 1/4 full. So the equation is:
2 = (1/4 - 1/6)x
2 = (1/12)x
x = 24
Total capacity of the tank is 24 gallons.
URGENT!!⚠️
a local record store invested $400,000 in charitable trust fund so that they can offer scholarships to their employees. the interest rate is 4.2% compounded quarterly. how much interest is available from the trust fund for the scholarships each year?
Answer:
I am here to help!
Step-by-step explanation:
if it's each year won't the company have 168k?
8) Which are not true.
a)
6.68> 6.8
b)
6.86 <6.88
c)
6.8 = 6.08
d)
6.6>6.08
e) 6.86> 6.8
f)
6.8<6.6
The given statement which are not true are a) , c) , and f)
we have to check whether the given statement is true or not
a) 6.68 > 6.8
6.68 can be written as 6+ 0.68 and 6.8 can be written as 6+ 0.8
then we have 6 both the sides , only need to compare 0.68 and 0.8
we know that 0.8 is greater than 0.68
that is 0.8> 0.68
so 6+0.8 > 6+0.68
hence 6.8 > 6.68
but we are given that 6.68 > 6.8 so the statement is not true
b) 6.86 < 6.88
we know 0.86 < 0.88
hence 6.86 < 6.88 statement is true
c) 6.8 = 6.08
0.8 is not equal to 0.08
therefore 6.8 is not equal to 6.08 and hence statement is not true
d) 6.6 > 6.08
true
e) 6.86 > 6.8
true
f) 6.8< 6.6
6.8 is greater than 6.6 so the statement is not true
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Tn=2[n-1]-5 find t14
habbsbzbzbzbzbbzbBbbababsbsbsbsbsbs
1 + 1 please also explain as much as possible
Answer: 2
Step-by-step explanation:
Please open this:
Let [tex] \rm\hat{i}, \hat{j} \: and \: \hat{k} [/tex] be the unit vector along the three positive coordinate axes. Let [tex] \rm\overset{ \to}a = 3 \hat{i} + \hat{j} - \hat{k} ,\\ \rm \overset{ \to}b = \hat{i} + b_{2} \hat{j} + b_3\hat{k}, \: \: \: \: \: \: \: b_{2}, b_{3} \in \mathbb{R}, \\ \rm\overset{ \to}c= c_{1} \hat{i} + c_{2} \hat{j} + c_3\hat{k}, \: \: \: \: \:c_{1},c_{2}, c_{3} \in \mathbb{R}[/tex]
be three vectors such that [tex] \rm b_2b_3 > 0, \overset{ \to}a \cdot\overset{ \to}b = 0[/tex] and [tex] \left(\begin{gathered} 0& \rm - c_{3} & \rm c_{2} \\ \rm c_{3}& \rm 0 & \rm - c_{1} \\ \rm - c_{2}& \rm c_{1} & \rm 0 \end{gathered} \right) \left(\begin{gathered} 1 \\ \rm b_{2} \\ \rm b_3\end{gathered} \right) = \left(\begin{gathered} \rm3 - c_{1} \\ \rm 1 - c_{2} \\ \rm - 1 - c_3\end{gathered} \right)[/tex]
Then which of the following is true
[tex] \rm(1) \: \overset{ \to}a \cdot\overset{ \to}c = 0 \\ \rm(2) \: \overset{ \to}b \cdot\overset{ \to}c = 0 \\ (3) \: \overset{ \to}{| \rm b|} > \sqrt{10} \\(4) \: \overset{ \to}{| \rm c|} \leq \sqrt{11}[/tex]
Computing the matrix product in the last condition gives a system of linear equations in the components of [tex]\vec c[/tex],
[tex]\begin{cases} c_1 + b_3c_2 - b_2c_3 = 3 \\ -b_3c_1 + c_2 + c_3 = 1 \\ b_2c_1 - c_2 + c_3 = -1 \end{cases}[/tex]
and is easily solvable to get
[tex]c_1 = \dfrac{6-2b_3}{2+{b_2}^2+{b_3}^2}, c_2 = \dfrac{2+3b_3}{2+{b_2}^2+{b_3}^2}, c_3 = \dfrac{9-3b_3}{2+{b_2}^2+{b_3}^2}[/tex]
or, using the condition [tex]\vec a\cdot\vec b = 3 + b_2 - b_3 = 0[/tex],
[tex]c_1 = -\dfrac{2b_2}{11 + 6b_2 + 2{b_2}^2}, c_2 = \dfrac{11+3b_2}{11+6b_2+2{b_2}^2}, c_3 = -\dfrac{3b_2}{11+6b_2+2{b_2}^2}[/tex]
• (1) is false, since
[tex]\vec a \cdot \vec c = \dfrac{11}{2 + {b_2}^2 + {b_3}^2} \neq 0[/tex]
because [tex]{b_2}^2+{b_3}^2\ge0 \implies 0<\vec a\cdot\vec c\le\frac{11}2[/tex].
• (2) is true.
[tex]\vec b\cdot \vec c = \dfrac{(3 + b_2 - b_3) (2 + 3b_3)}{2 + {b_2}^2 + {b_3}^2} = \dfrac{(\vec a\cdot\vec b)(2+3b_3)}{2+{b_2}^2+{b_3}^2} = 0[/tex]
• (3) is false. The magnitude of [tex]\vec b[/tex] could be smaller than √10.
Since [tex]\vec a\cdot\vec b=0[/tex], we have
[tex]\|\vec b\| = \sqrt{1 + {b_2}^2 + (3+b_2)^2} = \sqrt{10 + 6b_2 + 2{b_2}^2}[/tex]
and
[tex]2{b_2}^2 + 6b_2 = 2\left({b_2}^2 + 3b_2 + \dfrac94\right) - \dfrac{18}4 = 2\left(b_2 + \dfrac32\right)^2 - \dfrac92 \ge - \dfrac92[/tex]
which is to say, [tex]\|\vec b\| \ge \sqrt{10-\frac92} = \sqrt{\frac{11}2}[/tex].
• (4) is true.
We have
[tex]\|\vec c\| = \dfrac{\sqrt{11} \sqrt{11 - 6b_3 + 2{b_3}^2}}{2 + {b_2}^2 + {b_3}^2}[/tex]
In terms of [tex]b_2[/tex] alone,
[tex]\|\vec c\| = \dfrac{\sqrt{11}\sqrt{11 + 6b_2 + 2{b_2}^2}}{11+6b_2+2{b_2}^2} = \dfrac{\sqrt{11}}{\sqrt{11+6b_2+2{b_2}^2}}[/tex]
Now,
[tex]11 + 6b_2 + 2{b_2}^2 = 2\left(b_2+\dfrac32\right)^2 + \dfrac{13}2 \ge \dfrac{13}2[/tex]
which means
[tex]\|\vec c\| \le \dfrac{\sqrt{11}}{\sqrt{11 + \frac{13}2}} \le \sqrt{11}[/tex]
The revenue function for a real estate agency is based on a percentage of the amount of monthly sales made by agents. The cost function for the agency is based on the commissions, paid to the agent plus the fixed monthly costs. both functions are shown below where X is the dollar amount of the monthly sales made by agents.
• Revenue function: f (x) = 0.03
• Cost function: g (x) = 0.015x + 4,600
The agency will break, even when the revenue function is equal to the cost function. For the agency to break even, what amount of monthly transactions, in dollars, must be generated by its agents?
• Between $0 and $2000
• Between $4,500 and $4,700
• Between $153,000 and $155,000
• Between $305,000 and $307,000
Answer:
D. Between $305,000 and $307,000
Step-by-step explanation:
A. This is a result of finding 4,600(0.03 + 0.015).
B. This is a result of using the y-intercept for the cost function.
C. This is a result of incorrectly solving the equation 0.03x = 0.015x + 4,600 by dividing 4,600 by 0.03
instead of 0.015 in the final step.
D. This is a result of correctly solving the equation 0.03x = 0.015x + 4,600 ⇒ 0.015x = 4,600 then dividing
4,600 by 0.015 to get approximately 306,667.
Solve the following equation. Then place the correct number in the box provided. 8 + x = 13 + 2x
Answer:
-5
Step-by-step explanation:
8 + x - 8 = 13 + 2x - 8
The 8 cancels on the left
x - 2x = 13 + 2x - 8 - 2x
The 2x cancels on the right
x - 2x = 13 - 8
Do the calculation to find
- x = 5
- x . (-1) = 5 . (-1)
Times by -1 to cancel the negative sign because you arises to find x and not -x
You finally get x = -5
Answer: You must have typed it wrong cause they can not equal each other
Step-by-step explanation:
8 + 1 does not equal 13 + 2
nor with two, three, four, and so on.
I watched ad still does not let me see answer!
Answer:
That's unfortunate. :(
If sin theta= 1/4 and theta is acute, find tan
(pi/2- theta).
Answer:
3.8723
Step-by-step explanation:
[tex]sin(\theta) = \frac{1}{4}[/tex]
So [tex]\theta = sin^{-1}(\frac{1}{4}) = 0.25268[/tex] radians or [tex]14.48^{\circ \:}[/tex]
[tex]\frac{\pi}{2}} \text\;in\;radians=90 ^{\circ}[/tex]
[tex]\text{So\;} \frac{\pi}{2} - \theta = 90 - 14.48 = 75.52^{\circ}[/tex]
[tex]\tan(\frac{\pi}{2}-\theta) = \tan(75.52) = 3.8723[/tex]
Write the following number in decimal notation.
Four hundred twenty-seven thousandths
Writing Four hundred twenty-seven thousandths in decimal notations gives 0.0000023419
How to write Four hundred twenty-seven thousandths in decimal notationGiven data
Four hundred twenty-seven thousandths
Four hundred twenty-seven thousand is written in figures as follows
400 000 + 20 000 + 7 000 = 427000
Four hundred twenty-seven thousandths = 1 / 427000
using calculator gives
= 2.3419 * 10^-6 ( in standard form )
= 0.0000023419 ( in decimal notation)
what is decimal notations?This a term in mathematics used to refer to a way of rewriting numbers in fractions to decimal form. it consists of a value and a point, then the required numbers.
The point is called decimal point. Decimal notations is not used only for numbers less than one. So are numbers in fractions, numbers in decimal may be greater than one. However the question refers to number that is less than one.
The given number: Four hundred twenty-seven thousandth is written in fraction as: 1 / 427000
then from fraction we write the decimal notation using calculator or long division to get 0.0000023419.
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simplify.
−x2+2y−3x2+10
Answer:
(2 (y - 2 x^2 + 5))
Step-by-step explanation:
Simplify the following:
2 y - x^2 - 3 x^2 + 10
Grouping like terms, 2 y - x^2 - 3 x^2 + 10 = 2 y + (-x^2 - 3 x^2) + 10:
2 y + (-x^2 - 3 x^2) + 10
-x^2 - 3 x^2 = -4 x^2:
2 y + -4 x^2 + 10
Factor 2 out of 2 y - 4 x^2 + 10:
Answer: (2 (y - 2 x^2 + 5))
Answer:
(2 (y - 2 x^2 + 5))
Solve the inequality and enter your solution as an inequality comparing the
variable to the solution.
53 + x> 73
Answer here
PLEASE HELP FAST
Answer:
x > 20
Step-by-step explanation:
53 + x > 73
-53 -53
x > 20
643=4 x 160 + n write what n represents in the related division problem
Answer: n is 3
Step-by-step explanation: As you multiply 4 and 160 you'll end up with 640 then add n which then adds to 643. This indicates that n is 3.
which is the least severe from of heat illness
A.) heat cramps
B.) heat exhaustion
C.) heat fatigue
D.) heat stork
the answer is (A heat cramps)
Answer:
heat cramps
Step-by-step explanation:
A wooden board is attached by a carpenter on a metal sheet that was 0.125 inches thick, and the wooden board was 1.5 inches thick. Find the combined thickness of the board and the metal sheet. son
Answer:
1.625
Step-by-step explanation:
1.5+0.125=1.625
Given a scale 2in=35 miles on map what would be 6 inches be
Answer:
105
Step-by-step explanation:
you do 35/2 to find how much 1 inch is which is 17.5 and multiply by 6
(-4,1), (-7,-8) find the distance between these pairs round go the nearest tenth
Answer: 9.4
Step-by-step explanation:
HELPPPPPPPP!!!!! 50 POINTS!
Answer:
a, b, a/2, b/2
Step-by-step explanation:
The coordinates of C are (a,b).
You find the midpoint by taking the averages of the coordinates.
The third blank is a/2.
The fourth blank is b/2.
Answer:
a, b, a/2, b/2
Step-by-step explanation:
Solve w^2=36 where is a real number. Simplify your answer as much as possible.
Answer:
w = 6 (or) w = -6
Step-by-step explanation:
Let's solve the problem,
→ w² = 36
→ w = √36
→ w = + 6
→ w = 6 (or) w = -6
Thus, the answer is 6 & -6.
Apply Servers at a snack shop use the table below to find the total cost for frozen
yogurt, but some of the numbers have worn off. The total cost is proportional to the
number of cups of frozen yogurt. Find the missing numbers in the table.
Number of Cups of Frozen Yogurt
Total Cost ($)
1
2
3
4
18.00
Answer:
totaAal cost is 18
Step-by-step explanation:
Everett, Miguel, and Ramona are partners, sharing income 1:2:3. After selling all of the assets for cash, dividing losses on realization, and paying liabilities, the balances in the capital accounts are as follows: Everett, $53,600 Cr.; Miguel, $45,500 Dr.; and Ramona, $37,900 Cr. How much cash is available for distribution to the partners?
The amount of cash available for distribution to the partners is $46,000.
How is the amount of cash determined?The amount of cash available for distribution to the partners is computed by summing the partners' capital balances.
From the scenario, Miguel owes the partnership $45,500. Since Miguel has not brought in this amount, the cash available for now is $46,000.
If Miguel cannot bring in $45,500, it implies that the other two partners will share the loss in their income-sharing ratio before distributing the remaining cash.
Data and Calculations:Partners = Everett, Miguel, and Ramona
Income-sharing ratio = 1:2:3
Capital account balances:
Everett, $53,600 Cr.
Miguel, $45,500 Dr.
Ramona, $37,900 Cr.
Total = $46,000 CR
Thus, the amount of cash available for distribution to the partners is $46,000.
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1. An oil tank has a circular cross section of radius 2.1 metres. It is filled to a depth of 3.4 metres. a) Calculate x, the width in metres of the oil surface. 3-4 m b) What other depth of oil would give the same surface width? 2.1m
Answer:
Step-by-step explanation:
A) We can find half of the width of the surface by applying pythagorean theorem on the right angled triangle formed by three points which are the center of the circle, the point on the circle where the the endpoints of the width and the radius meet, and the midpoint of the width.
let radius=r, width=w
[tex]r^2=(w/2)^2+(3.4-2.1)^2\\[/tex], since the distance between the origin and the midpoint of the width is 3.4m-2.1m.
[tex]-(w/2)^2=(3.4-2.1)^2-r^2, r=2.1\\-(w/2)^2=(1.3)^2-(2.1)^2\\-(w/2)^2=1.69-4.41\\-(w/2)^2=-2.72\\w/2=\sqrt{2.72}\\w=2*\sqrt{2.72}\\w=3.3 meter[/tex]
B) we can find the other depth of oil which can give the same surface area of oil if the now empty part of the cylinder is filled with oil and the now filled part of the cylinder is empty, so the other possible depth for the same surface area of oil is the diameter of the circle minus 3.4 meters:
diameter=4.2 meter, 4.2 meter-3.4 meter:
0.8 meter depth
a. The width (x) of the oil surface is approximately 5.348 meters.
b. Another depth of oil that would give the same surface width (x ≈ 5.348 meters) is approximately 3.402417 meters.
a) Here, we have to calculate the width (x) of the oil surface, we need to find the length of the chord of the circular cross-section at the top of the oil tank.
We can use the formula for the length of a chord in a circle when the depth and radius are known.
Given that the radius (r) of the circular cross-section is 2.1 meters and the depth (d) of the oil is 3.4 meters, the width (x) can be calculated as follows:
x = 2 * √(r * d)
x = 2 * √(2.1 * 3.4)
x = 2 * √(7.14)
x ≈ 2 * 2.674
x ≈ 5.348 meters
So, the width (x) of the oil surface is approximately 5.348 meters.
b) Now, let's find the other depth of oil that would give the same surface width (x = 5.348 meters).
We can rearrange the formula to solve for the depth (d):
x = 2 * √(r * d)
Divide both sides by 2:
x/2 = √(r * d)
Square both sides:
(x/2)² = r * d
Now, plug in the given values (x = 5.348 meters and r = 2.1 meters) and solve for d:
(5.348/2)² = 2.1 * d
2.674² = 2.1 * d
7.145076 = 2.1 * d
Divide by 2.1:
d ≈ 7.145076 / 2.1
d ≈ 3.402417
So, another depth of oil that would give the same surface width (x ≈ 5.348 meters) is approximately 3.402417 meters.
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True or false: An equation in the form of A x + B y = C , where A ≥ 0 , A and B are not both zero, and A, B, and C are integers with a greatest common factor of 1 can represent either a linear or nonlinear function.
Answer:
True
Step-by-step explanation:
This will always be the equation of a line, which represents a linear function.
Y = mx + b solve for m
The equation solved for b gives b = Y - mx
What is subject of formula?A subject of formula can be defined as the the variable that is written in terms of other variables in an equation or expression.
It is also known as the variable that is being sorted out in a given expression or equation.
Example;
To make a the subject from the equation;
ab + c = 1
Take the variable 'c' to the other side
ab = 1 - c
Divide both sides by b, we have;
a = 1 - c/b
Given the expression;
Y = mx + b
Take 'mx' over the equality sign
Y - mx = b
This is also written as;
b = Y - mx
Thus, the equation solved for b gives b = Y - mx
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