the question is in a picture

Answer:

c

Explanation:

Answer:

C

Explanation:

got it right on edge

Answer:

no

Explanation:

Answer:

1850 psi

Explanation:

Answer:

.................

Explanation:

....

...............

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

[tex](P_{1})-(P_{2})=P_{3}[/tex]

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

[tex](85) - 85 = P_{3}\\P_{3}= 0[/tex]

There is no movement of any of the balls, they remain at rest after the impact.

Answer:

4.0s

Explanation:

v = v_0 + a*t -> t = (v - v_0) / a

v = 20.0m/s, v_0 = 8.0 m/s, a = 3.0 m/s^2

t = (20.0 - 8.0) / 3.0 = 4.0s

Answer:

t = 4.0 s

Explanation:

Given:

V₁ = 8.0 m/s

V₂ = 20.0 m/s

a =3.0 m/c²

______________

t - ?

a = ( V₂ - V₁ ) / t

t = ( V₂ - V₁ ) / a

t = ( 20.0 - 8.0 )/ 3.0 = 12.0 /3.0 = 4.0 s

The time taken for the rock to return to its initial height is 6.4 seconds.

The time taken for the rock to hit the water flowing out at the base of the dam is 2.8 seconds.

The time taken for the rock to return to its initial height is calculated as follows;

h = Vy(t) + ¹/₂gt²

88 = (21 x sin58)(t) + 4.9t²

88 = 17.8t + 4.9t²

4.9t² + 17.8t - 88 = 0

solve the quadratic equation using formula method;

a = 4.9, b  = 17.8, c = -88

t₁ = -6.4 seconds

t₂ = 2.8 seconds

The negative time indicates the time taken for the rock to travel back to its initial position.

Also, the positive time indicates the time taken for the rock to fall from the given height.

Thus, the time taken for the rock to return to its initial height is 6.4 seconds.

The time taken for the rock to hit the water flowing out at the base of the dam is 2.8 seconds.

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Answer:

Explanation:

The path of the Earth–Moon system in its solar orbit is defined as the movement of this mutual centre of gravity around the Sun. Consequently, Earth's centre veers inside and outside the solar orbital path during each synodic month as the Moon moves in its orbit around the common centre of gravity.

Answer:

B

Explanation

the moon is constantly falling but moving fast enough to continue falling around the earth.

Answer:

B

Explanation:

Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.

It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.

Answer:

5.14m/s

Explanation:

First we need to get the Maximum height reached by the rocket;

H = u²sin² theta/2g

H = 25²sin² 40/2(9.8)

H = 625(0.5878)/19.6

H = 18.74m

Get the velocity after 1.5secs

Using the equation of motion

H = ut + 1/2gt²

18.74 = u(1.5)+1/2(9.8)(1.5)²

18.74 = 1.5u + 4.9(2.25)

18.74 = 1.5u + 11.025

1.5u = 18.74 - 11.025

1.5u = 7.715

u = 7.715/1.5

u = 5.14m/s

Hence the velocity after 1.5secs is 5.14m/s

Answer:

D- Interference

Explanation:

When two waves meet they interfere with one another resulting in Interference

Given that,

Mass of a sprinter = 70 kg

Initial velocity, u = 0

Final velocity, v = 10 m/s

Time, t = 3 s

To find,

Power output.

Solution,

The work done by the sprinter is equal to its kinetic energy.

[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 70\times 10^2\\\\=3500\ J[/tex]

Let P is power output. Power is equal to work done per unit time. So,

[tex]P=\dfrac{3500\ J}{3\ s}\\\\=1166.67\ W[/tex]

So, the power output is 1166.66 W.

The correct answer is a = 539.68 m/[tex]s^2[/tex]

A push or pull that one thing applies to another is known as force. An object is considered to exert a force when it accelerates through space because acceleration is the rate at which an item's speed changes. The second law of motion of Newton explains this concept.

The equation F=ma, where "F" stands for force, "m" for mass, and "a" for acceleration, illustrates the link between force and acceleration.

Force applied = F = 3.40 N

The bullet's weight = m = 6.30 g = 0.0063 kg

The bullet's rate of acceleration can be expressed as = a = F/m

a = 3.40 / 0.0063

a = 539.68 m/[tex]s^2[/tex]

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Situations that illustrate the conservation of mechanical energy is (d) Both a and b.

According to the principle of mechanical energy conservation, a system's entire mechanical energy is conserved, meaning that energy cannot be generated or destroyed and can only be internally transformed from one form to another provided the forces acting on the system are conservative in nature.

(a) Sometimes referred to as a dissipative force, air resistance contributes to a loss in the total amount of mechanical energy. So, if friction and air resistance are balanced, the total mechanical energy will be conserved. Hence, friction and air resistance balanced is an example of conservation of mechanical energy.

(b) The pendulum bob's height above the tabletop changes continuously as it swings back and forth, which affects its speed. Potential energy is lost as the height drops, whereas kinetic energy is gained simultaneously. However, the bob's total potential and kinetic energy are always constant. There is a conservation of all mechanical energy. There is only a change from kinetic to potential energy; there is neither a gain nor a loss of mechanical energy (and vice versa).

(c) Let's assume that an external force exerted on an object over a certain distance causes the object's total mechanical energy to change. The item gains mechanical energy if the external force (or nonconservative force) exerts positive work. Energy is gained in a quantity equal to the work done on the object. The item loses mechanical energy if the external force (or nonconservative force) exerts negative work. Hence, energy is not conserved.

Both (a) and (b) illustrate the conservation of energy.

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Answer:

Fresultant = - 800 [N]

m = 224.26 [kg]

a = 3.56 [m/s²]

Explanation:

The resulting force can be determined by the arithmetic difference of the air resistance force and the gravity force.

[tex]F_{resultant}=F_{air}-F_{gravity}\\F_{resultant}=1400-2200\\F_{resultant}=-800[N][/tex]

The negative sign of the result means that the force is directed downwards.

The mass can be easily calculated using the definition of the weight of the body. Where the weight is equal to the product of mass by gravitational acceleration.

[tex]W =m*g\\[/tex]

where:

m = mass [kg]

W = weight = 2200 [N]

g = gravity acceleration = 9.81 [m/s²]

[tex]m=W/g\\m=2200/9.81\\m= 224.26 [kg][/tex]

Finally, acceleration can be calculated using Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration.

[tex]F_{resultant}=m*a\\-800 = - 224.26*a\\a=3.56 [m/s^{2} ]\\[/tex]

The positive sign of acceleration tells us that effectively the body moves down.

Answer: the element with the lowest electronegativity

Explanation:

Answer:

B the slope of car postion time graph

Explanation:

Answer:

The slope of the car's position time graph.

Explanation:

Answer:

(b) 2.40 x [tex]10^{3}[/tex] kg/s

Explanation:

Given that: Total mass of the rocket = 3.003 x [tex]10^{5}[/tex] kg

acceleration of the rocket = 36.0 m[tex]s^{-2}[/tex]

speed of the exhausted gases = 4.503 x [tex]10^{3}[/tex] m/s

Rate at which rocket was initially burning fuel = [tex]\frac{mass}{time}[/tex]

But,

time = [tex]\frac{velocity}{acceleration}[/tex]

       = [tex]\frac{4.503*10^{3} }{36.0}[/tex]

       = 125.0833 s

So that;

Rate at which rocket was initially burning fuel = [tex]\frac{3.003*10^{5} }{125.0833}[/tex]

        = 2400.8001

        = 2.40 x [tex]10^{3}[/tex] kg/s

Therefore, the initial rate at which the rocket burn fuel is 2.40 x [tex]10^{3}[/tex] kg/s.

Answer:

a = 0.23 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N]

m = mass = 30 [kg]

a = acceleration [m/s²]

Now we can use Newton's second law, with forces pointing to the right as positives and negative forces pointing towards the left.

[tex]12 - 5 = 30*a\\7 = 30*a\\a = 0.23 [m/s^{2} ][/tex]

Answer:

Plane mirror

Explanation:

A virtual image is a copy of an object formed at the location from which the light rays appear to come.

Answer:

2.5J

Explanation:

Work done = Force x Distance

= 0.5 x 5

= 2.5J

The work done that should be accomplished should be 2.5 J.

Since the force is 5 newtons

The box moves 0.5 meters

So here the work done should be

= Force x Distance

= 0.5 x 5

= 2.5J

here we basically multiply the force with the distance so that the work done should be determined.

hence, The work done that should be accomplished should be 2.5 J.

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Explanation:

Ethics, also called moral philosophy, the discipline concerned with what is morally good and bad and morally right and wrong. The term is also applied to any system or theory of moral values or principles. Its subject consists of the fundamental issues of practical decision making, and its major concerns include the nature of ultimate value and the standards by which human actions can be judged right or wrong.

hope it helps!

Answer:

its constant i think

Explanation:

or its stable dunno which term will they be using

When a truck is moving north word having mass 2000kg at a constant speed of 50m/s the momentum of the truck is 100000 kg.m/s.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s.

Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum.

The dimensions of the momentum is [M¹ L¹ T⁻¹].

In this problem velocity and mass of the truck is not given, Consider the mass of the truck is 2000kg and speed is 50m/s.

Given,

m = 2000kg

v = 50m/s

The momentum p = mv = 2000×50 =100000 kg.m/s

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Answer:

the lowest frequency f of the sound wave is 214.375 Hz

Explanation:

The computation of the lowest frequency f of the sound wave is shown below;

Length = L= 80 cm

= 0.8 m

V = 343 m/s (sound speed in air )

Now

V1 = n V ÷ 2 L

= 1 × 343 ÷ 2 × 0.8

V1 = 214.375 Hz

Hence, the lowest frequency f of the sound wave is 214.375 Hz

We simply applied the above formula so that the correct value could come

And, the same is to be considered  

Answer:

destructive interference occurs

Answer: B. energy

Explanation:

Answer:D

Explanation:If you want to find the acceleration do Force/mass.

The greatest magnitude of acceleration is of 20 m/s², by the student of 50 kg pushing the chair with 1000 N of force. Hence, option (D) is correct.

As per the Newton's second law, " The applied force on an object is equal to the product of mass of object and acceleration cause by the applied force. Then, the mathematical expression is,

F = ma

Here, F is the applied force, m is the mass and a is acceleration.

(A)

For 20 kg mass and 100 N force, the acceleration is,

F = ma

100 = (20)a

a = 5 m/s²

(B)

For 10,000 kg mass of rocket and 100,000 N force, the acceleration is,

F = ma

100 ,000= (10,000)a

a = 10 m/s²

(C) For a 2,000 kg mass of car and force of 1000 N, the acceleration is,

F = ma

1000 = (2000)a

a = 0.5 m/s²

(D) For a mass of 50 kg student and applied force of 1000 N, the acceleration is,

F = ma

1000 = (50)a

a =20 m/s².

Thus, we can conclude that the greatest magnitude of acceleration is of 20 m/s², by the student of 50 kg pushing the chair with 1000 N of force. Hence, option (D) is correct.

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Answer:

[tex]\boxed {\boxed {\sf 56.25 \ Joules}}[/tex]

Explanation:

Kinetic energy can be found using the following formula:

[tex]E_k=\frac{1}{2}mv^2[/tex]

where m is the mass and v is the velocity.

The mass of the ball is 0.5 kilograms and the velocity is 15 meters per second

[tex]m= 0.5 \ kg \\v= 15 \ m/s \\[/tex]

Substitute the values into the formula.

[tex]E_k=\frac{1}{2} (0.5 \ kg ) * (15 \ m/s)^2[/tex]

First, evaluate the exponent.

[tex]E_k=\frac{1}{2} (0.5 \ kg ) *(225 \ m^2/s^2)[/tex]

Multiply 0.5 kg by  225 m²/s²

[tex]E_k=\frac{1}{2}(112.5 \ kg* m^2/s^2)[/tex]

Multiply 112 kg*m²/s² by 1/2, or divide by 2.

[tex]E_k=56.25 \ kg*m^2/s^2[/tex]

[tex]E_k= 56.25 \ J[/tex]

The kinetic energy of the ball is 56.25 Joules

Answer:

16294 rad/s

Explanation:

Given that

M(ns) = 2M(s), where

M(s) = 1.99*10^30 kg, so that

M(ns) = 3.98*10^30 kg

Again, R(ns) = 10 km

Using the law of gravitation, the force between the Neutron star and the sun is..

F = G.M(ns).M(s) / R²(ns), where

G = 6.67*10^-11, gravitational constant

Again, centripetal force of the neutron star is given as

F = M(ns).v² / R(ns)

Recall that v = wR(ns), so that

F = M(s).w².R(ns)

For a circular motion, it's been established that the centripetal force is equal to the gravitational force, hence

F = F

G.M(ns).M(s) / R²(ns) = M(s).w².R(ns)

Making W subject of formula, we have

w = √[{G.M(ns).M(s) / R²(ns)} / {M(s).R(ns)}]

w = √[{G.M(ns)} / {R³(ns)}]

w = √[(6.67*10^-11 * 3.98*10^30) / 10000³]

w = √[2.655*10^20 / 1*10^12]

w = √(2.655*10^8)

w = 16294 rad/s