This is about net force
So the question is what is the net force on the rope? Be sure to include units. So the answer has to be like this ex: 15N left. This isn’t the answer for the first one. And then say which team won so pls help me. Please please help

Answer:

its 24 hours

Explanation:

12 hours during the night and 12 hours during the day

Yes that's right...did anyone tell you something else?

Given that,

6/7 and 24/28

To find,

The above number are in proportion or not.

Solution,

First number is 6/7

Other number is 24/28

Multiply numerator and denominator by 4 to the first number.

[tex]\dfrac{6}{7}=\dfrac{6}{7}\times \dfrac{4}{4}\\\\=\dfrac{6\times 4}{7\times 4}\\\\=\dfrac{24}{28}[/tex]

So, 6/7 and 24/28 are in proportion.

Fraction A is proportional to fraction B because the value of fraction A is equal to fraction B.

Given the following data:

In this exercise, you're required to determine whether or not the two fractions are proportionate i.e whether fraction A is proportional to fraction B.

Two fractions are considered to be proportionate when the value of fraction A is equal to fraction B.

We would write fraction B in its simplest form by dividing both the numerator and denominator by their highest common factor (HCF).

HCF of 24 and 28 = 4.

Dividing by 4, we have:

[tex]Fraction\;B =\frac{24}{28}=\frac{6}{7}[/tex]

In conclusion, fraction A is proportional to fraction B because the value of fraction A is equal to fraction B.

Read more: https://brainly.com/question/18676621

Answer:

[tex]P=18,933.3Pa=18.9kPa[/tex]

Explanation:

Hello!

In this case, since we can compute the volume of the brick as shown below:

[tex]V=0.1m*0.1m*0.2m=0.002m^3[/tex]

Next, we can compute the mass of the brick given its density:

[tex]\rho =m/V\\\\m=V*\rho\\\\m=0.002m^3*19,300kg/m^3\\\\m=38.6kg[/tex]

Now, since the force exerted on the table corresponds to the weight of the brick, we use the gravity to obtain:

[tex]W=38.6kg*9.81m/s^2=378.7N[/tex]

Finally, since the surface of the brick in contact with the table corresponds to the 0.1x0.2 area (length and width), the area on which the weight force is exerted is:

[tex]A=0.1m*0.2m=0.02m^2[/tex]

Therefore, the pressure is:

[tex]P=\frac{F}{A}=\frac{W}{A}=\frac{378.7N}{0.02m^2}\\\\P=18,933.3Pa=18.9kPa[/tex]

Best regards!

Answer:

adbce i think

Explanation:

Answer:

vf = v₁/3 + 2v₂/3

Explanation:

Using the law of conservation of linear momentum,

momentum before impact = momentum after impact

So, Mv₁ + 2Mv₂ = 3Mv (since the railroad cars combine) where v₁ = initial velocity of first railroad car, v₂ = initial velocity of the other two coupled railroad cars, and vf = final velocity of the three railroad cars after impact.

Mv₁ + 2Mv₂ = 3Mvf

dividing through by 3M, we have

v₁/3 + 2v₂/3 = vf

vf = v₁/3 + 2v₂/3

Answer:

shivering raises your body temperature

Answer:

P = 24525 [Pa]

Explanation:

The pressure at the bottom of any vessel can be determined, only by knowing the depth or height of the liquid level. By means of the following equation.

[tex]P=Ro*g*h[/tex]

where:

P = pressure [Pa]

Ro = density of the water = 1000 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 2.5 [m]

Now replacing:

[tex]P=1000*9.81*2.5\\P=24525 [Pa][/tex]

Answer:

We know that the gravitational acceleration in the surface of the Earth can be written as:

g = G*M/r^2

Where:

M = mass of the Earth

r = radius of the Earth.

G = gravitational constant.

The weight of an object of mass m, is written as:

W = m*g = m*(G*M/r^2)

Now, if we move our object to a place that has a mass equal to 1/6 times the mass of the Earth, and 1/3 the radius of the earth.

The gravitational acceleration on this planet is written as:

g' = G*(M/6)/(r/3)^2 = (1/6)*(G*M)/(r^2/9) = (9/6)*(G*M/r^2) = (3/2)*g

then the weight on this planet is:

W' = m*g' = m*(3/2)*g = (3/2)*(m*g)

and m*g was the weight on Earth, then:

W' = (3/2)*(m*g) = (3/2)*W

The new weight is 3/2 times the weight on Earth.

Answer:

BMI is a simple indicator of weight for height and can't differentiate between muscle mass and fat mass. So BMI tends to overestimate the health risk for adults with a high muscle mass, such as some athletes, and underestimate the risk for adults with a low muscle mass, as can occur with sedentary lifestyles.

Explanation:

Hope it is helpful...

Answer:

The answer is below

Explanation:

The equation for a linear line graph is given by:

y = mx + b, where y and x are variables, m is the slope of the graph and b is the y intercept (that is value of y when x is zero).

The slope (m) of a line passing through two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex] is given by:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

A) The first line passes through the point (0, 0) and (10, 60). It is represented as (time, velocity). Hence the slope is:

[tex]m=\frac{60 -0}{10-0}=6\ m/min^2[/tex]

B) The second line passes through the point (10, 60) and (15, 60). Hence the slope is:

[tex]m=\frac{60 -60}{15-10}=0\ m/min^2[/tex]

C) The third line passes through the point (15, 60) and (40, -40). Hence the slope is:

[tex]m=\frac{-40 -60}{40-15}=-4\ m/min^2[/tex]

D) The third line passes through the point (40, -40) and (55, 0). Hence the slope is:

[tex]m=\frac{0 -(-40)}{55-40}=2.67\ m/min^2[/tex]

Answer:

[tex]magnetite[/tex]

[tex]hope \: helps...[/tex]

Answer:

B or C

Explanation:

i don't if I'm right or not

Answer:

9800 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 5 kg

Height (h) = 200 m

Potential energy (PE) =?

Potential energy (PE) is the energy stored in an object by virtue of its location. Mathematically, it is expressed as:

PE = mgh

Where:

PE => is the potential energy.

m => is the mass of the object.

g => is the acceleration due to gravity.

h => is the height to which the object is located.

With the above formula, we can obtain the potential energy of the ball at its original height as follow:

Mass (m) = 5 kg

Height (h) = 200 m

Acceleration due to gravity (g) = 9.8 m/s²

Potential energy (PE) =?

PE = mgh

PE = 5 × 9.8 × 200

PE = 9800 J

Therefore, the potential energy of the ball at its original height is 9800 J

Answer:

spring 1 has less potential energy

Explanation:

since spring 2 is clampped down further it will have a greater effect but since sping 1 is barely clamped down it wont show as much energy

Answer:

The answer is 5.0

Explanation:

Hope that helped :D

Answer:

1. 57.99V

2. 37.5Hz

3. 0.7072A

4. 82 ohms

5. 5.18x10^-5F

Explanation:

In answer to this question, we have the Standard equation of AC emf to be

V = V0 x sin ωt

We have

V0 = 82V,

ω = 75π

1.

RMS Voltage =

V0/√2 = 82 /√2

= 82/1.414

= 57.99V

2.

ω = 2π* f

75π = 2πf

Frequency,f = 75π/2π

= 235.5/6.28

= 37.5 Hz

3.

RMS current

= Imax/√2

= 1.00/1.414

= 0.7072A

4.

Reactance

= Vrms/ Irms

= 57.99/0.7072

= 81.999

= 82.0 Ω

5.

Reactance = 1/ ω x C

Reactance = 82

ω = 75π

We put these values into the equation above and make c the subject of the formula

C = 1/82.0 x 75π

C = 1/ 82.0 x 75 x 3.14

C = 1/19311

Capacitance = 5.18x10^-5F

Answer:

ANSWER : 2000 / 40 = 50 m / s

Answer:

88.14 m/s

Explanation:

From the question given above, the following data were obtained:

Radius (r) = length of blade = 80 m

Revolution (rev) = 1

Time (t) = 5.7 s

Velocity (v) =?

The velocity of the blade can be obtained by using the following formula:

v = (rev × 2πr) / t

NOTE: Pi (π) = 3.14

v = (1 × 2 × 3.14 × 80) / 5.7

v = 502.4 / 5.7

v = 88.14 m/s

Therefore, the velocity of the blade is 88.14 m/s

Answer:

The speed and direction of the tangled players is 2.89 m/s towards right.

Explanation:

Given;

mass of the player heading right, m₁ = 40 kg

initial velocity of the player heading right, u₁ = 9.0 m/s

mass of the player heading left, m₂ = 50 kg

initial velocity of the player heading left, u₂ = -2.0 m/s

let the speed of the tangled players = v

Apply the law of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(40 x 9) + (50 x - 2) = v(40 + 50)

360 - 100 = v(90)

260 = v(90)

v = 260 / 90

v = 2.89 m/s (towards right, since it is in position direction)

Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.

Answer:

[tex]1.28 \times 10 ^{-3} m^3/s[/tex]

Explanation:

Given that the radius of the pipe, r =0.0112 m

So, the area of the cross-section, [tex]a= \pi (0.0112)^2 = 3.941\times 10^{-4} m^2[/tex]

Speed of water in the pipe, v=3.25 m/s

Volume flow rate =[tex]av= 3.941\times 10^{-4} \times 3.25 = 1.28\times 10 ^{-3} m^3/s[/tex]

Hence, the volume flow rate is [tex]1.28 \times 10 ^{-3} m^3/s[/tex]

Answer:

For Acellus the answer is 0.00128

Explanation:

Trust me

Answer:

D

Explanation:

Answer:

375 J

Explanation:

Work done is the product of force and distance moved by the object.

W=F*d

Given that ;

Force= F= 250 N

Distance= d =1.5 m

W= 250 * 1.5 =375 J

Explanation:

Helium is the type of atom, with 2 protons in the nucleus.

He-3 (which is the proper form), is an isotope of helium that has an atomic number of 3 (so 2 protons and 1 electron).

The most abundant helium isotope is He-4, just an extra fact.

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 [tex]m/s^{2}[/tex]

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

Impulse = Δp

Impulse = -20000 Ns

Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5[tex]m/s^{2}[/tex]

Answer:

v = 37.8 m/s

Explanation:

       [tex]F_{cent} = F_{g} - F_{n} (1)[/tex]

       [tex]v_{max} = \sqrt{g*r} =\sqrt{9.8 m/s2*146 m} = 37.8 m/s (5)[/tex]