upiter has a mass of approximately . jupiter’s moon ganymede has a mass of approximately and it orbits jupiter at a distance of approximately . calculate the approximate magnitude of the attractive gravitational force between ganymede and jupiter.

Answers

Answer 1

The approximate magnitude of the attractive gravitational force between ganymede and jupiter  is 16.35 x 10^21 N .

According to Newton’s Law of Gravitation, the gravitational force between two bodies is directly proportional to the masses of the two objects and is inversely proportional to the square of the distance between them.

The above statement can be represented by the following equation:

F = Gx (m1)x (m2)/r^2

Here G = Universal Gravitational Constant = 6.67 x 10^-11 N m^2/kg^2

m1 and m2 are the masses of two bodies

r is the distance between the bodies

Putting m1= Mass of Jupiter= 1.89 x 10^27 kg

m2 =Mass of Ganymede 1.48 x 10^23 kg

r = Distance between Jupiter and Ganymede = 1.07 x 10^9 meters

F = 6.67 x 10^-11 x 1.89 x 10^27 x 1.48 x 10^23/(1.07 x 10^9)^2

On solving the above equation F comes out to be 16.35 x 10^21 N.

Thus, the approximate magnitude of the gravitational force between Ganymede and Jupiter is 16.35 x 10^21 N.

What is gravitational force?

Because it consistently attempts to pull masses together rather than pushing them apart, the gravitational force is known as attractive. In actuality, every thing in the cosmos, including you, is pulling on every other object.

Gravitation is the force in physics that draws two masses together. Unbelievably, every single particle of matter in the cosmos attracts every other particle through gravity. The phrases gravitation and gravity are sometimes used synonymously to refer to the attraction that exists between anything with mass or energy.

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Related Questions

A current of 0.2A flows through a component with a resistance of 40 ohms. Calculate the potential difference.

Answers

The potential difference of a current of 0.2A that flows through a component with a resistance of 40 ohms is 8V.

How to calculate potential difference?

Potential difference is difference in potential energy between two points in an electric field i.e. the difference in charge between two points in an electrical circuit.

The potential difference of an electrical current can be calculated by multiplying the current by the resistance as follows:

Voltage = current (I) × resistance (R)

According to this question, a current of 0.2A flows through a component with a resistance of 40 ohms. The potential difference is as follows:

V = 0.2A × 40ohms

V = 8V

Therefore, the potential difference of a current of 0.2A that flows through a component with a resistance of 40 ohms is 8V.

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a small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of 7530 n/c. the mass of the water drop is 3.09 × 10-9 kg. how many excess electrons or protons reside on the drop?

Answers

The number of excess protons that reside on the drop is 2.52 * [tex]10^{-6}[/tex]

To suspend a water drop in mid air, the electric field force must point in upward direction. This means that the charge is positive i.e., Protons.

∑ [tex]F_{y}[/tex] = [tex]F_{E}[/tex] - mg = 0 ( Since it is motionless )

[tex]F_{E}[/tex] = mg = qE

q = mg / E = Ne

N = mg / eE

where,

N = No. of Protons

m = Mass of the water drop

g = Acceleration due to gravity

e = Electric charge

E = Magnitude of electric field

Given that,

m = 3.09 * [tex]10^{-9}[/tex] kg

g = 9.81 m / [tex]s^{2}[/tex]

e = 1.6 * [tex]10^{-6}[/tex] C

E = 7530 N / C

N = ( 3.09 * [tex]10^{-9}[/tex] * 9.81 ) / ( 1.6 * [tex]10^{-6}[/tex] * 7530 )

N = 30.31 * [tex]10^{-9}[/tex] / 12.048 * [tex]10^{-3}[/tex]

N = 2.52 * [tex]10^{-6}[/tex]

Protons are the positive charges that are present in an atom. It is present inside the nucleus of an atom.

Therefore, the number of excess protons that reside on the drop is 2.52 * [tex]10^{-6}[/tex]

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the top and bottom ends of a windshield wiper blade are 33 inches and 13 inches, respectively, from the pivot point. while in operation, the wiper sweeps through 165°.

Answers

The area swept by the wiper blade is 1324.04 inches^2.

The top and bottom ends of a windshield wiper blade move in the form of a circle.

The area swept by the wiper blade can be calculated by subtracting the area covered by the bottom end by the area covered by the top end i.e,

Area swept by blade(A) = Area covered by top end of blade - Area covered by bottom end of blade

A = A1 - A2

A1 =  π(13)^2 x 165/360 = 1567.25 inches^2

A2 = π(33)^2 x 165/360 = 243.21 inches^2

A= 1567.25 - 243.21 = 1324.04 inches^2

Thus, the area swept by the wiper blade is 1324.04 inches^2.

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What mass of the following solutes will dissolve in 100 g of water?
KCL at 50 c?
Pb(NO3)2 at 50 C?

Answers

A solute is a material that dissolves in a solution. The amount of solvent present in fluid solutions is larger than the amount of solute. The two most common examples of solutions in daily life are salt and water. Salt is the solute because it dissolves in water.

For KCl at 50 C.

42.6 g KCl x (35.0g H2O/100 g H2O) = 14.9 which means 14.9 g KCl can be dissolved in 35.0 g H2O. Because 19.7 g of KCl is more than what will dissolve, it will be saturated.

For Pb(NO3)2 at 50 C

The solubility of Pb([tex]NO_{3}[/tex])² Pb( [tex]NO_{3}[/tex] )² is 56.5 g/100 mL at 20∘C 20 ∘ C Thus, 100 mL of water can dissolve 56.5 g of Pb([tex]NO_{3}[/tex])² P b ( [tex]NO_{3}[/tex])²

The mass of the following solutes are

19.7 g of KCl

56.5 g of Pb([tex]NO_{3}[/tex])²

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At the end of the experiment you will be assessing the purity of your aspirin by measuring its absorbance at 525 nm. If the absorbance measurement is found to be 0. 010 then what is the % salicylic acid impurity in your aspirin?.

Answers

The absorbance of ASP and Sal standard mixed solutions in different concentrations (0.05 to 30 and 0.02 to 8 ug/ml for ASP and SAL, respectively) was measured against solvent (H2O; ACN 90: 10v/v) as blank at 229 nm and 296 nm.

Calibration graphs were created by graphing absorbance versus concentrations and using regression equations.

The calibration graphs revealed that ASP and SAL follow Beer's law. ASP and SAL at values of 0.3-30 and 0.1-10 pg/ml, respectively. Statistical parameters were computed, demonstrating that Tcal values were greater than Ttab values. Good linearity was detected, with R2 values of (0.9996 and 0.9992, respectively) for ASP and SAL. The calibration plot's linear regression results indicate a solid linear connection between concentration fluctuation and response.

Regression analysis was used to determine linearity.

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If you change the magnetic field inside a closed loop of wire, you induce in the loop _______.

Answers

If you change the magnetic field inside a closed loop of wire, you induce in the loop is current .

As per the Faraday law, the current help to induce the electric field in a close loop.

Electric field- it is defined as the electric force per unit charge. The direction of the field is taken to be in the direction of the force which applied on a positive test charge.

It is outward from a positive charge. It is inward from a negative charge.

If you change the magnetic field inside a closed loop of wire, you induce in the loop is current .

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At the instant a ball is fired horizontally over a level range, a ball held at the side of the first is released and drops to the ground. If air resistance can be neglected, which ball – the one threw or the one dropped from rest – strikes the ground first? Why?

Answers

They hit the ground at the same time

Explanation:

The ball that dropped to the ground instead of being thrown will fall first since it only has one force pushing it: gravity.

The other ball has momentum from the horizontal throw so it's fighting against the gravity of the earth to keep going forward. Therefore, the ball dropped instead of thrown is the one that will strike the ground first.

Jessica jogs on a path that is 25 kilometers long to get to the park that is south of the jogging . If it takes Jessica 2.5 hours then

Answers

The speed of Jessica as she jogs on a path that is 25 kilometers long in 2.5 hours is 10 km/hr.

What is the speed of a moving body or object?

The speed of a moving body or object is the distance covered by the moving body over a given period of time.

Mathematically, speed is expressed as follows;

speed = distance covered/time taken

The units of speed include; km/hr/ mi/hr, m/s, etc.

Considering the information provided about the movement of Jessica:

The distance or path length covered by Jessica = 25 kilometers

Time taken to cover the distance = 2.5 hours

Speed of Jessica during the jogging period = 25 km/2.5 hrs

Speed of Jessica = 10 km/hr

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a runner uniformly accelerates from rest to a speed of 6 m/s in 4s. What is the acceleration of the runner?

Answers

Answer:

See below

Explanation:

Acceleration = change in velocity / change in time

=  6 m/s / 4 s = 1.5 m / s^2

3. Which of the following best represents the estimated age of the universe?
13.7 billion
37 billion
13.7 million
3.7 million years

Answers

Based on a Hubble Constant of 70, the universe is thought to be 13.7 billion years old. The Hubble Constant of 82.4 determined by Jee's team places the universe's age at roughly 11.4 billion years.

What is a Universe ?

Everything exists in the cosmos. It encompasses all of space as well as the matter and energy that it holds. Even time is a part of it, and you are obviously a part of it. Along with the other planets and their numerous moons, Earth and the Moon are all components of the cosmos.

Numerous religious people, including a large number of scientists, believe that God created the cosmos and the numerous processes guiding physical and biological evolution, and that these processes later led to the creation of galaxies, our solar system, and life on Earth.

Hence, estimated age of the universe is 13.7 billion years old

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block?
km
min²'
10) A 209g block slides down a ramp with an acceleration of 2,000.
acting on the block?
What force is acting on the block?

Answers

116.11 N is the force.

We have given that mass= 209g=0.209Kg

acceleration=2000Km/min²=555.556m/s².

We know that

F=m.a

= 0.209kg x 555.556m/s².

=116.11N

Force is an influence that can change the position or the motion of an object. In other words it can be stated as change in velocity of the object with respect to mass. it has both magnitude and direction. its unit is N.

Mass it is a quantitative measure of all the matter in this universe.  it is can be measured as the amount of matter of an object . it unit is kilogram (Kg).

Acceleration is defined as the rate of change which occur in the velocity of an object with respect to time. its unit is m/s².

So from the above data the force acting is 116.11N

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the inner planets—mercury, venus, earth, and mars—are believed to have been formed by . masses of cold hydrogen and helium collisions with large galaxies the combining of asteroid-sized debris

Answers

The inner planet Mercury, Venus, Earth, and Mars are believed to have been formed by the combination of asteroid-sized debris.

Exactly, what is space debris?

Planets are formed through the collision of asteroid-sized space debris.

Space debris includes both naturally occurring meteoroids and man-made (artificial) orbital junk.

The majority of manufactured debris is in orbit around the Earth, unlike meteoroids, which are in orbit around the sun (thus the phrase "orbital" debris").

The collisions of micrometeoroids, which are dust-sized pieces of asteroids and comets, naturally produce some debris.

Operational satellites may become space trash due to their short lifespans.

Due to the elevated potential of collision with and damage to operational satellites, the building of space trash poses a particularly catastrophic threat to humankind's future in space exploration.

Additionally, it might harm the environment of Earth.

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Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal in the top and bottom is 0. 1 cm thick and the metal in the sides is 0. 05 cm thick.

Answers

The amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal on the top and the bottom is 0.1 cm thick and the metal on the sides is 0.05 cm thick is 8.8 cm.

The formula for calculating the volume of a cylinder is given below.

V = πr^2 h

Get the differential of the volume as shown:

dV = V/ h dh + V / r dr

V/ h = πr^2

V/ h  = 2  πr h

Now, the differential becomes

dV =  πr^2dh +  2πrh dr

Given the following parameters

dh = 0.1 + 0.1 = 0.2 cm

dr = 0.05 cm

h = 10 cm

r = 4 cm

Substituting the values in the above equation, we get

dV = 3.14(2)^2(0.2)  + 2(3.14)(2)(10)(0.05)

dV = 2.512 + 6.28

dV = 8.792 cm

dV = 8.8 cm

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When the parachute is fully open, the effective drag coefficient of the skydiver plus the parachute increases to 60. 0 kg/m. What is the drag force fdrag acting on the skydiver immediately after she has opened the parachute?.

Answers

After the effective drag coefficient of the skydiver plus the parachute increases to 60. 0 kg/m, drag force acting on the skydiver immediately after she has opened the parachute is found to be 188160N.

When a skydiver opens their parachute, what force increases?

Air pressure

An open parachute expands the skydiver’s cross-sectional area as he falls, increasing the amount of air resistance he faces (as observed in the animation below).

As soon as the parachute is opened, air resistance outweighs the pull of gravity.

How does the drag formula work?

According to the drag equation, drag D is equal to the drag coefficient. Cd multiplied by density r, velocity V squared, and the reference area.

We must choose a value for Cd in order to calculate drag given the air conditions, shape, and inclination of the object.

Here we know,

K[tex]v^{2}[/tex] = mg

K[tex]v^{2}[/tex] = 80 x 9.8

K[tex]v^{2}[/tex] = 784.5

V = 56 m/s

Then fdrag = [tex]60*(56)^2[/tex]

fdrag = 188160 N

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Complete Question

A skydiver of mass 80.0 kg (including parachute) jumps off a plane and begins her descent. for the magnitude of the Throughout this problem use 9.80 acceleration due to gravity.

When the parachute is fully open, the effective drag coefficient of the skydiver plus the parachute increases to 60. 0 kg/m. What is the drag force fdrag acting on the skydiver immediately after she has opened the parachute?

URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS

The diagram below shows a
portion of the electromagnetic
spectrum. Which of the
following statements correctly
explains the relationship
between FM and AM radio
waves?

Answers

Answer:

It's C

Explanation:

The reason why is since AM is longer as shown in the diagram it's either A or C, and since longer wavelengths have less energy it's C.

FM radio waves are shorter therefore it has more energy and can penetrate through walls easier than AM, which are longer waves making it able to travel further distance but has worse quality.

Going off of that, I would assume the answer is C,

“FM radio waves carry more energy than AM radio waves. This is supported by the fact that FM radio waves have a shorter wavelength compared to AM radio waves.”

While a pure substance is melting, additional heat will cause the temperature of a substance to:_______-

Answers

Additional heat will boost the temperature of the liquid once all of the solid has melted.

It is possible to recognize pure compounds and elements by their distinctive melting temperature, which is a characteristic number.

What happens to a pure substance’s temperature as it melts?

Energy is solely directed at changing a substance’s phase during melting; it is not used to alter the substance’s temperature.

Because a substance maintains the same temperature during melting, it is an isothermal process.

What changes in a substance’s temperature occur during melting and boiling?

Even when any kind of heat is applied, the substance’s temperature remains properly constant during melting and boiling.

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What is an alkali metal?

Answers

Answer:

any of the six chemical elements that make up Group 1 (Ia) of the periodic table.

Explanation:

Answer:

Explanation: an alkali metal is a metal that is alkali

Why is that when a small marble hits another small marble, it moves, but when a small marble hits a bigger marble, it does not?​

Answers

Answer:

It depends on the masses of the marbles that collide. The figure shows a marble with a smaller mass hitting a marble with a larger mass. The larger marble is at rest. After the collision, the marble with a smaller mass bounces off in the opposite directions

hope this helps :)

Why is important for scientists to write detailed procedures?

Answers

Answer:Why is important for scientists to write detailed procedures?

Explanation: it lets someone else duplicate your experiment exactly

Answer: It will help you plan how to conduct your experiment and if anyone was to duplicate your experiment, they should end up with the same results.

Difference between hyperbola and parabola (2 points)​

Answers

Answer: GoodMorning: ) ✨  So we should know that A parabola is defined as a set of points in a plane which are equidistant from a straight line or directrix and focus, and that  The hyperbola can be defined as the difference of distances between a set of points, which are present in a plane to two fixed points is a positive constant. So what what I mean by that is that if you have like a y squared term but no x squared term or vice versa so you have an x squared term but no y squared term then you know it's a parabola.

Hope This Helps <3 ✨

The de broglie equation relates the wavelength and the kinetic energy of particles. What is the mass of a particle with a speed of 2. 34 × 10^6 m/s with a de broglie wavelength of 2. 25 × 10^-9 m?.

Answers

The mass of the particle is [tex]\bold{1.26 \times 10^{-34} \,kg}[/tex]

The de Broglie wavelength ([tex]\lambda[/tex]) of a particle in motion is a measure of the particle's capability of demonstrating wave characteristics even though it is just a moving particle.That quantity is associated with the particle's mass, the speed it travels at and Planck's constant ([tex]k = 6.6261\times 10^{-34}\,m^2\,kg/s[/tex]).This question is not a hard one and it just checks your primary knowledge of the formula associated with this concept.That formula is given as follows, you may recall your memory in case it is forgotten.

                        [tex]\lambda &= \frac{k}{mv}[/tex]

Therefore, just substitute the known values correspondingly and find the needed parameter: the velocity in this case.It can be done simply as follows,

                            [tex]\begin{aligned}\\\\m &= \frac{k}{v\lambda}\\\\&= \frac{6.6261\times 10^{-34}\, m^2\,kgs^{-1}}{2.34\times10^6\,ms^{-1}\times 2.25\times 10^{-9}\,m}\\\\&=\small 1.26\times 10^{-31}\, kg\end{aligned}[/tex]

Be cautious to put the units appropriately during the calculations.

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you are driving eastbound on the interstate at 70 mi/hmi/h . you observe that you are approaching a truck in your lane at a relative speed of 15 mi/hmi/h .

Answers

The velocity of the truck in relative to the highway is 55 mi / hr

We know that,

[tex]V_{rel}[/tex] = V - [tex]V_{obs}[/tex]

where,

[tex]V_{rel}[/tex] = Relative velocity

V = Object velocity

[tex]V_{obs}[/tex] = Observer velocity

Given that,

[tex]V_{rel}[/tex] = 15 mi / hr

V = 70 mi / hr

[tex]V_{rel}[/tex] = V - [tex]V_{obs}[/tex]

Here the observer is the truck

[tex]V_{rel}[/tex] = V - [tex]V_{truck}[/tex]

15 = 70 -  [tex]V_{truck}[/tex]

[tex]V_{truck}[/tex] = 55 mi / hr

Relative velocity is the velocity of an object with respect to another observer.

Therefore, the velocity of the truck in relative to the highway is 55 mi / hr

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in the 1991 world track and field championships in tokyo, mike powell jumped 8.95 m, breaking by a full 5 cm the 23-year long-jump record set by bob beamon. assume that powell’s speed on takeoff was 9.5 m/s (about equal to that of a sprinter) and that g 9.80 m/s2 in tokyo. how much less was powell’s range than the maximum possible range for a particle launched at the same speed?

Answers

Mike Powell's range was 0.26 m less than the maximum possible range.

We know that,

Horizontal range of the projectile on a flat ground is,

R = v² sin 2θ / g

where,

R = Range

v = Velocity

θ = Angle of projection

g = Acceleration due to gravity

Given that,

v = 9.5 m / s

The maximum possible range of a projectile is achieved when the angle of projection is 45°

R = 9.5² sin 90° / 9.8

R = 9.21 m

The difference between maximum range and Mike Powell's range is

R = 9.21 - 8.95

R = 0.26 m

In a projectile motion, range is the horizontal distance between starting and ending point.

Therefore, Mike Powell's range was 0.26 m less than the maximum possible range.

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Question 8 of 29
Which of the following is an example of Newton's second law of motion?
OA. A wheelbarrow is more difficult to move as more objects are
placed inside.
OB. When a gymnast jumps off the ground, Earth also exerts a force
on the gymnast.
OC. Rocks lose energy as they roll down a hillside.
OD. A satellite in space can travel without slowing down, even after
using up all its fuel.

Answers

Answer:

Option A

Explanation:

In reality what they are trying to say, is that we need to exert more force to accelerate a wheelbarrow that has more mass.

In other words, when mass increases the force exerted to maintain an acceleration increases as well, and this is given by newton's second law of motion, which suggests that the force exerted on a system is proportional to the mass of that system.

[tex]F=ma[/tex]

a small block has constant acceleration as it slides down a frictionless incline. the block is released from rest at the top of the incline, and its speed after it has traveled 6.20 m to the bottom of the incline is 3.80 m/s .

Answers

When the block is 5.00 m from the incline's summit, its velocity is 3.04 m/s.

provided details:

s = 7.80 m

v = 3.8 m/s

if s = 5 m, v?

The block's acceleration must first be determined using the following equation:

Since v02 = 0 due to v2 = v02 + 2as,

3.8² = 2 a 7.8

a = 0.93

Consequently, the final speed is if s = 5m.

v² = 2 (0.93) (5)

= 9.26

v = √9.26

= 3.04 m/s

Complete Question -

A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of the incline, and its speed after it has traveled 7.80 m to the bottom of the incline is 3.80 m/s .What is the speed of the block when it is 5.00 m from the top of the incline? Please show the detailed formulas utilized to obtain the final answer.

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Elvira throws a meatball at the wall. When the meatball hits the wall, it makes a sound. The kinetic energy of the meatball is transferred into the surroundings through what? (Hint: your answer should be a type of wave. )

Answers

Answer:

sound waves

Explanation:

The kinetic energy of the meatball is transferred into the surroundings through sound waves.

When the meatball hits the wall, the kinetic energy of the meatball causes vibrations in the wall and the surrounding air. These vibrations create sound waves which transfers the kinetic energy to sound energy until it runs out of energy.

When an object / medium vibrates, the particle of the object / medium starts to move. This movement of particles is called as sound waves. It is a type of mechanical wave.

Therefore, the kinetic energy of the meatball is transferred into the surroundings through sound waves.

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The region around the earth where charged particles are trapped and spiral around is called:______.

Answers

The region around the earth where charged particles are trapped and spiral around is called magnetosphere .

The motion of charged particle in electric and magnetic field.

F = q(v x B).

Where, the magnetic force becomes centripetal force due to its direction towards the circular motion of the particle.

Hence, if the field (B) and velocity (v ) are perpendicular to each other, then the particle takes a circular path.

And in the above equation , F is magnetic force on charge particle q & B is the magnetic field .

The magnetosphere of the earth can be explained in term of astronomy and planetary science as that, a magnetosphere is a region of space surrounding an astronomical object in which charged particles are affected by that object's magnetic field.

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All gases exhibit ideal behavior in low pressure situations because when the pressure is very low, the gas particles are.

Answers

Gases move slower at temperatures, not pressures.

What happens to gas at low pressure?

The average kinetic energy of the gas particles falls as the temperature rises. Because of this, a greater percentage of gas molecules lack the kinetic energy needed to repel intermolecular forces generated by nearby atoms.As air pressure drops, the air spreads out or expands more widely. There is a consequent drop in temperature.The temperature of a gas is directly proportional to its pressure for a constant volume of gas in a sealed container, according to the pressure law.The amount of oxygen available to breathe likewise reduces when the pressure drops. At very high altitudes, the oxygen levels and air pressure are so low that individuals can get sick or possibly pass away.

All gases exhibit ideal behavior in low-pressure situations because when the pressure is very low, the gas particles are:

Far apart and rarely interacting

- gases move slower at temperatures, not pressures.

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You push horizontally on a 120 N box that is initially resting on a horizontal table. The coefficient of static friction between the box and the table is 0.75 and the coefficient of kinetic friction is 0.40. Find the friction force on the box if push is equal to 84 N.

Answers

The static frictional force acting on the block is equal to 90 Newton's.

What is Friction?

Friction is a force that acts opposite to the direction of motion of body in order to oppose its motion. Frictional force is of two types -

The Static frictional Force - F[s] = μ[s] N

The Kinetic frictional force - F[k] = μ[k] N

Given in the question is a box of weight 120 N initially resting on a horizontal table. From the data given, we can write -

Weight of box [W] = 120 Newton

Coefficient of static friction (μ[s]) = 0.75

Coefficient of Kinetic friction (μ[k]) = 0.40

Horizontal push (F[h]) = 84 N

We know that -

F[s] = μ[s] N           [Static friction]

F[k] = μ[k] N           [Kinetic friction]

Now, initially the box is at rest so the opposite frictional force will be 0.  When a horizontal force of 84 Newton is applied on it, the static friction will try to oppose the motion. For forward motion of the block -

F[h] = F[s]

F[h] = μ[s]

84 = 0.75 x 120            (Normal Reaction [N]  = Weight)

84 = 90 ≥ 0

- 6 = 0

which is false.

This means that the static frictional force is greater than horizontal push and opposes the motion. The force due to static friction will only exist since, the body was able to move, so kinetic friction is of no use here.

So, the frictional force on the block will be = F[s] =  μ[s] N = 90 Newtons.

Therefore, the static frictional force acting on the block is equal to 90 Newton's.

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The expression like a ton of bricks means “a crushing weight.” Would being hit by an actual ton of bricks hurt if it happened on the moon?(1 point)
Responses

No, it would not hurt because the bricks would have little mass.
No, it would not hurt because the bricks would have little mass.

Yes, it would hurt because the bricks would still have the same mass.
Yes, it would hurt because the bricks would still have the same mass.

No, it would not hurt because the bricks would have more weight.
No, it would not hurt because the bricks would have more weight.

Yes, it would hurt because the bricks would still have more weight.

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Answers

Yes, being hit by an actual ton of bricks would still hurt because the bricks would still have the same mass.

What is Mass?

This is referred to as the quantity of matter which is present in a body or object and is usually measured in kilogram.

On the moon which has a very weak gravitational force, the mass of an object is usually the same when compared to that on earth which is the reason why the individual will experience the same feeling of being hurt by the impact of the bricks.

This is therefore the reason why option B was chosen as the most appropriate choice.

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