Answer:
C
Explanation:
Some of the mass
Answer:
D. Mass was transformed into energy during the process.
You are pushing a large box across a frictionless floor by applying a constant horizontal force. If the box starts at rest, you have to do work W 1 in order for the box to travel a distance d in time T . How much work would you have to do, in terms of W 1 , to make the box go the same distance in half the time
Answer:
You would have to do four times the work W₁ to make the box go the same distance in half the time.
Explanation:
By definition work is:
[tex] W = F*d [/tex] (1)
Where:
F: is the force and d: is the distance
On the other hand, the force is given by:
[tex] F = ma [/tex] (2)
By entering equation (2) into (1):
[tex] W = F*d = m*a*d [/tex] (3)
Also, we can express the acceleration in terms of distance and time by using the following kinematic equation:
[tex] d_{f} = d_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex] (4)
Where:
[tex]d_{f}[/tex]: is the final distance
[tex]d_{0}[/tex]: is the initial distance = 0
[tex]v_{0}[/tex]: is the initial speed = 0 (the box starts at rest)
t: is the time
[tex] d_{f} = \frac{1}{2}at^{2} [/tex]
Solving for a:
[tex] a = \frac{2d_{f}}{t^{2}} [/tex] (5)
Initially we have:
t = T₁, W = W₁, [tex]d_{f}[/tex] = d
[tex] a_{1} = \frac{2d}{T_{1}^{2}} [/tex]
[tex] W_{1} = m*a_{1}*d = m*d*\frac{2d}{T_{1}^{2}} = 2m(\frac{d}{T_{1}})^{2} [/tex]
And when the box goes the same distance in half the time:
[tex] t = \frac{T_{1}}{2} [/tex]
The acceleration is (from equation 5):
[tex]a_{2} = \frac{2d_{f}}{t^{2}} = \frac{2d}{(\frac{T_{1}}{2})^{2}} = \frac{8d}{T_{1}^{2}}[/tex] (6)
Finally, the work W₂ in terms of W₁ is:
[tex]W_{2} = m*a_{2}*d = m*d*\frac{8d}{T_{1}^{2}} = 8m(\frac{d}{T_{1}})^{2} = 4*[2m(\frac{d}{T_{1}})^{2}] = 4W_{1}[/tex]
Therefore, you would have to do four times the work W₁ to make the box go the same distance in half the time.
I hope it helps you!
pressure problem solving..
We know that Formula to calculate Pressure is Pressure = Force/Area.
It is given that the Water jet exerts a pressure of 20 Mega Pascal on an area of 5m². We convert 20 Mega pascal to Pascal => 20 * 1000000 So, we get Pressure P = 20000000 Pascals, Area = 5 m² Putting values we get Force = P * A => Force = 20000000 * 5
=> Force = 100000000 N
Status weighs 2400 N and base area is 500 cm². Converting the base area from cm² to m², we get Area a = 0.05 m², Force F = 2400 N. Putting values we get Pressure = 2400 * 0.05=> Pressure = 48000 Pascal
It is given that the base area of an object = 3 cm² and the pressure exerted will be 21 Pa. Firstly, We will convert the area from cm² to m² and we get Area a = 0.0003 m², and P = 21 Pa. Putting values in equation we get Force/ Weight of object => F = P*A => F = 21 * 0.0003=> F = 0.0063 N
It is given that the lady weighs 50 kN so, Force F = 50 kN. We will convert force from kN to N => F = 50 * 1000 => F = 50000 N. And, the surface area of heels is 0.0001 m². Putting values in equation, We get : Pressure = F/A => P = 50000/0.0001=> P = 500000000 Pa
It is given that the pressure box exerts on the ground is 20 kPa. The weight of the box is 400 N. First, we will convert pressure from kPa to Pa. Pressure = 20 * 1000 => P = 20000 Pa and Force F = 400 N. Putting these values in equation we get Area = F/P =>Area = 400/20000 => Area = 0.02 m²
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As shown in the figure below, April enters a race. She runs leftward 100 m to her horse, then she rides 500 m
to her truck, then she drives 1000 m in a total time of 120 s.
1000 m
500 m
100 m
What is April's average speed over the 120 s period?
m
Answer:
13.33m/s
Explanation:
The average velocity is the ratio of total distance traveled to the total time taken to complete the distance. The International System of Units (SI) unit of velocity is the meter per second (m/s). The Velocity is given by the equation:
Velocity = total distance traveled / total time taken
The total distance traveled = Distance traveled by horse + distance traveled by truck + remaining distance traveled = 100 m + 500 m + 1000 m = 1600 m
Total time taken = 120 s
Velocity = total distance traveled / total time taken = 1600 m / 120 s = 13.33 m/s
Velocity = 13.33 m/s
part 1 of 2 Consider the acceleration of a particle along a straight line with an initial position of 8m and an initial velocity of 3 m/s. acceleration (m/s²) what is the velocity at 1 s
Answer:
Using, s=ut+
2
1
at
2
s
1
=u+
2
1
a
or, 3=u+
2
a
∴a=6−2u
s
2
=2u+
2
1
a×4
8=2u+2a
Solving the equations
8=2u+2(6−2u)
8=2u+12−4u
2u=4
u=2m/s
∴a=6−2u=6−4=2m/s
2
Pulmonary circulation involves blood flow to and from the heart and the ____?
body
digestive organs
skin
brain
lungs
Answer: Lungs
Explanation:
I NEED SOMEOME TO HELP MEEEE NOWWWW I WILL GIVE YOU. 75 POINTSSSS
Select the best answer for the question.
7. What is the amount of MMF generated by a 50-turn electromagnetic coil supplied by 12 VDC at a current of 1 ampere?
O A. 50 ampere-turns
B. 38 ampere-turns
C. 12 ampere-turns
D. 600 ampere-turns
The correct answer is 600 ampere-turns
We shall first get the expression that provides the magnetomotive force. It is calculated by multiplying the number of spins on the wire by the current flowing through it. To get the solution, we shall alter and substitute the necessary values.
It is crucial to keep in mind that magnetomotive force (mmf), which is similar to electromotive force (emf), drives a current of electrical charge through magnetic circuits. The phrase "magnetomotive force" is deceptive, though, as it neither denotes a force nor something that moves.
M.M.F = NI
N= 50
I = 12 at a current of 1 ampere
M.M.F = NI
= 50 × 12
=600 ampere-turns
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What is the equivalent resistance of the circuit
120.0 V
10.00 Ω
30,0 Ω
20.0 Ω
The equivalent resistance of the circuit20.0 Ω
The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated. Essentially, the circuit is designed either in Series or Parallel.
In a series circuit, the equivalent resistance is the algebraic sum of the resistances. The current through the circuit can be found from Ohm's law and is equal to the voltage divided by the equivalent resistance.
Resistors are in parallel when one end of all the resistors are connected by a continuous wire of negligible resistance and the other end of all the resistors are also connected to one another through a continuous wire of negligible resistance
The equivalent resistance is 20 OHM
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A light wave passes through an aperture (that is, a narrow slit). When it does so, the degree to which the wave spreads out will be...
Explanation:
Single slit diffraction
Diffraction is the phenomenon of spreading out of waves as they pass through an aperture or around objects. Diffraction occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of the incident wave. For very small aperture sizes, the vast majority of the wave is blocked. in case of large apertures the wave passes by or through the obstacle without any significant diffraction.
Calculate the magnitude of the cat's acceleration (assumed constant) while it is stopping.
Express your answer with the appropriate units.
The correct answer is 9.11 g m/s^2
Height from which a cat drops, h = 3.6 ft = 3.6 x 0.305 m = 1.098 m
Distance travelled to stop the cat, s = 12 cm = 0.12 m
Using the equation, v^2 = u^2 + 2as,
v^2 = 0 + 2gh = 2 x 9.8 x 1.098 = 21.52
v = 4.63 m/s
Speed of the cat when it the floor, v = 4.63 m/s
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Please help meeeee
For a velocity versus time graph how do you know what the velocity is at a certain time? How do you know the acceleration at a certain time?
Answer:
Explained below
Explanation:
For a velocity time graph, the y - axis will represent velocity while the x - axis will represent time.
Now, to calculate velocity at a certain time t, we will draw a perpendicular line from the time on the x-axis to the graph line and trace the horizontal line from that point to the y-axis which will give the corresponding velocity at that time.
Now, for the acceleration at a time t. After getting the velocity like explained above, we now divide the velocity by the time.
A large pot is placed on a stove and 1.2 kg of water at 14°C is added to the pot. The temperature of the water is raised evenly to 100°C just before it starts to boil. (a) What amount of heat is absorbed by the water in reaching 100°C? (b) The water then boils until all of it has evaporated, turning to water vapor at 100°C. How much heat does the water absorb in this process?
Answer:
a) the amount of heat absorbed by the water is 431995.2 J
b) the amount of heat absorbed during evaporation is 2712000 J
Explanation:
Given that;
mass of water Mw = 1.2 kg
Specific heat capacity of water Cw = 4186 J/kg.C
Change in temperature ΔT = final T - Initial T = 100 - 14 = 86°C
Now
A)
Heat required to raise the temperature of water is expressed as:
Q = Mw × Cw × ΔT
Q = 1.2 × 4186 × 86
Q = 431995.2 J
Therefore the amount of heat absorbed by the water is 431995.2 J
B)
Then heat absorbed during evaporation will be:
Q1 = Heat absorbed during phase change from water to steam = Mw × Lv
Lv = latent heat of vaporization of water = 2.26 × 10⁶ J/kg
so
Q1 = 1.2 × 2.26 × 10⁶ = 2712000 J
Therefore the amount of heat absorbed during evaporation is 2712000 J
A 10-mm-diameter cable is strung between a series of poles that are 50 m apart. Determine the horizontal force this cable puts on each pole if the wind velocity is 34 m/s.
Answer:
The value is [tex]F = 562.7 \ N[/tex]
Explanation:
From the question we are told that
The diameter is [tex]d = 10 \ mm = 0.01 \ m[/tex]
The distance between the poles is L = 50 m
The velocity of the wind is [tex]v = 34 \ m/s[/tex]
Generally the horizontal force the cable puts on each other is mathematically represented as
[tex]F = \frac{1}{2} * C_D * \rho * v^2 * A[/tex]
Here A is the area of the rope(i.e assuming the rope to be a cylinder ) which is mathematically represented as
[tex]A = L * d[/tex]
=> [tex]A = 0.01 * 50[/tex]
=> [tex]A = 0.5[/tex]
Here [tex]C_D[/tex] is the coefficient of discharge of the rope and the value is [tex]C_D = 1.5[/tex]
[tex]\rho[/tex] is the density of air with value [tex]\rho = 1.225 \ kg/m^3[/tex]
So
[tex]F = \frac{1}{2} * C_D * \rho * v^2 * A[/tex]
=> [tex]F = \frac{1}{2} * 1.5 * 1.225 * 34^2 * 0.5[/tex]
=> [tex]F = 562.7 \ N[/tex]
A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?
Answer:
11.27N
Explanation:
Given parameters:
Mass of the book = 1.15kg
Unknown:
Magnitude of the normal force = ?
Solution:
The normal force is the vertical force exerted by a body on an object.
It can be described as the weight of an object.
Normal force = mass x acceleration due to gravity
Normal force = 1.15 x 9.8 = 11.27N
Find the altitude of the triangle in the figure below. Answer in units of m.
The altitude of the triangle is 10.1 m.
What is the altitude of the triangle?We can see that the triangle is a right angled triangle as we can see in the image. The altitude of the triangle is the highest point of the triangle. Let us label the angles A B C
C = 50 degrees
B = 90 degrees
A = 180 - (90 + 50) = 40 degrees
Then;
tan 40 = altitude/ 12 m
altitude = tan 40 degrees * 12 m
= 10.1 m
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what is the main cause of seafloor spreading?
Answer:
As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense.
Explanation:
Answer: The main cause of sea floor spreading are the directions and force of the moving tectonic plates.
Explanation:
What is the purpose of a resistor
Answer:
So we can have energy for electronics. It limits the flow of electric current
Explanation:
It’s in the answer!
Answer:
Basically, the function of a resistor is always to oppose the flow of current through it and the strength of this opposition is termed as its resistance.
The amount of inertia of an object depends on its __________________________________.
The greater the ________________________________, the greater its _______________________________.
The greater the _____________________________ of the object, the greater the ___________________________
required to accelerate or slow down the object.
The greater the ____________________________ applied, the greater the acceleration.
Answer:
first one :
the object will stay at the same speed and direction unless it is acted upon by an internal unbalanced force.
A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is his acceleration ? Acceleration= (final velocity-initial velocity)/ time A. 10 m/s/s B. 1.67 m/s/s C. 2.67 m/s/s D. 10.67 m/s/s
Answer:
Acceleration = Δv/t
Acceleration = (8 m/s - 0 m/s)/ 3 s
Acceleration = 8 m/s / 3s
Acceleration = 2.667 m/s²
Explanation:
Answer:
c 2.67
Explanation:
Please help me with all questions I will mark you brainly thank you
Answer:
2 output energy 3 not you full energy
Greta 30 m away her truck she noticed she forgot her tea and returns back to his house. Her total travel time is 240 seconds what is greta average velocity ?
Finding average speed distance
avg = distance/time
time1 – 30 ml + 30 ml
240 s60 m240 s= 0.25m/s
The correct answer is:
• average velocity = 0 m/s
• average speed = 0.25 m/s
What is average speed?The pace at which an object's direction changes as it is traveling is referred to as its velocity and is measured by a particular unit of time and from a particular point of view.
Greta returns to his house after realizing she forgot her tea 30 meters from her pickup. Her journey takes 240 seconds in all.
What is Greta average velocity ?Avg = distance/time time for calculating average speed distance
1 - 30 ml + 30 ml
240 s60 m
240 s= 0.25m/s
The right response is:
• Average speed: 0 m/s
• The typical speed is 0.25 m/s
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When an ice cube is placed in a glass of warm water, how are the signs and values q for the ice and the warm water related, assuming no heat is lost from or gained by the glass nor the surrounding air
Answer:
q(ice) = -q(warm water)
Explanation:
Ice removes energy if ice is put in warm water and ice retains the very same amount of energy. Thus the water temperature heat sign is negative, and the ice heat sign is positive.
1500 kg wrecking ball traveling at a speed of 3.5 m/s hits a wall that does not crumble but is pushed back 75 cm. If the wrecking ball comes to rest in the wall, what is the size of the force that pushes the wall
Answer:
The size of the force that pushes the wall is 12,250 N.
Explanation:
Given;
mass of the wrecking ball, m = 1500 kg
speed of the wrecking ball, v = 3.5 m/s
distance the ball moved the wall, d = 75 cm = 0.75 m
Apply the principle of work-energy theorem;
Kinetic energy of the wrecking ball = work done by the ball on the wall
¹/₂mv² = F x d
where;
F is the size of the force that pushes the wall
¹/₂mv² = F x d
¹/₂ x 1500 x 3.5² = F x 0.75
9187.5 = 0.75F
F = 9187.5 / 0.75
F = 12,250 N
Therefore, the size of the force that pushes the wall is 12,250 N.
Please help me out! Thank you so much!!!
Answer:
d is answer because w to between 10 to plus 10 more answers d
Simulated gravity in a man-made space station occurs because of _______.
Answer:
In space, it is possible to create "artificial gravity" by spinning your spacecraft or space station
drag and drop the sentences under the categories they belong to.
CLAIM
EVIDENCE
REASON
1. Yogurt is high in calcium and vitamins.
2.Yogurt is good for you.
3. Mondays are the best day of the week.
4. Cheetahs can run up to 70 mph
5. Cheetahs are the fastest animal.
6. Because yogurt is high in calcium and vitamins, it is good for you.
7.The majority of people prefer Mondays to other days of the week.
8. Because most people like Mondays, they're the best day of the week.
9. Because cheetahs can run up to 70 mph, they are the fastest animal.
how is electricity generated from solar cell?
Explanation:
When the sun shines onto a solar panel, energy from the sunlight is absorbed by the PV cells in the panel. This energy creates electrical charges that move in response to an internal electrical field in the cell, causing electricity to flow.
What is the purpose of drawing a motion diagram or a particle
model?
Answer:
What is the purpose of drawing a motion diagram or a particle model? Reason: In a motion diagram or a particle model, we relate the motion of the object with the background, which indicates that relative to the background, only the object is in motion. A coordinate system is helpful when you are describing motion.
Explanation:
1. You are hired to lift 25 kg crates a vertically 1.0 m from the ground onto a truck. How many crates would you have to load onto the truck in 1 minute for your average power output in lifting the crates to be 110 W
Answer:
The number of crate to be lifted is 27
Explanation:
Given;
mass of the crates, m = 25 kg
height in which the crate is lifted, h = 1.0 m
power output, P = 110 W
time to complete the task, t = 1 minutes = 60 s
The input energy is equal to the gravitational energy due to height the crate is lifted is given as;
E(input) = mgh
E(input) = 25 x 9.8 x 1
E(input) = 245 J
Output energy is given as;
E(output) = P x t
E(output) = 110 x 60
E(output) = 6600 J
Let the number of crate to be lifted = n
n x E(input) = E(output)
n x 245 = 6600
n = 6600 / 245
n = 27 crates
A bus leaves an intersection accelerating at +2.0 m/s2. Part A Where is the bus after 7.5 s?
Express your answer to two significant figures and include the appropriate units.
The distance covered is 56 m.
What is acceleration?We define acceleration as the rate at which the velocity changes with time. We can find the position of the bus by the use of the equations of kinematics.
Using the equation;
s = ut + 1/2at^2
u = initial velocity
a = acceleration
t = time taken
Since the bus started from rest u = 0 m/s
s = 1/2at^2
s = 0.5 * 2 * (7.5)^2
s = 56 m
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