The object displacement over the 9 seconds interval will be 0 m. Displacement can be define as the shift in the position of an object with respect to the reference frame.
What does a physical displacement mean?An object's location changes if it moves with regard to a reference frame, like when a passenger moves to the back of an airplane or a lecturer moves to the right with respect to a whiteboard. Displacement is the term used to explain this shift in position.
How is the displacement formula created?The distance an item travels from its starting point until it reaches a certain velocity can be calculated using the formulas t = (v vi)/g and y = gt2/2 + vit. The equation for the object's velocity at a particular distance from the starting point is the outcome of this.
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A horse can run at a speed of 12 m/s. At this rate, how long will it take for it to travel 52 m? (Express your answer in sec, rounded to one decimal place.)
A horse that can run at a speed of 12 m/s will travel a distance of 52 m in a period of 4.33 seconds
We know that,
v = d / t
where,
v = Velocity
d = Distance
t = Time
Given that,
v = 12 m / s
d = 52 m
t = d / v
t = 52 / 12
t = 4.33 s
Velocity is the displacement of an object in a given amount of time. It is denoted by V.
Therefore, the time taken by the horse is 4.33 seconds
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A small amount of sodium hydroxide is added to water. When the chemical 1 point
★
reaction reaches equilibrium, the pH is 12. Which statement and conclusion
about sodium hydroxide is correct?
O
The negative log of the concentration of OH-ions is 12. Sodium hydroxide is a
strong base.
O
The negative log of the concentration of OH-ions is 2. Sodium hydroxide is a strong
acid.
The negative log of the concentration of OH-ions is 12. Sodium hydroxide is a
strong acid.
O
The negative log of the concentration of OH-ions is 2. Sodium hydroxide is a strong
base.
The concentration of (OH −) Hydroxide ions increase when the excessive base is added to the solution of Sodium Hydroxide as the base itself dissociates to give out OH − ions which increase their concentration per unit volume.
when sodium hydroxide NaOH dissolves in water it separates into positively charged sodium ions cations and negatively charged hydroxide ions anions. these ions move round in the water, free and unbiased of every other, although cations have a tendency to be surrounded greater intently with the aid of anions and vice versa.
Sodium while sodium is added to water, the sodium melts to form a ball that moves around at the surface. It fizzes unexpectedly, and the hydrogen produced may also burn with an orange flame before the sodium disappears. The resulting huge concentration of OH- makes the solution greater basic and results in a dramatic growth inside the pH.
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you are on an airplane traveling 30° south of due west at 120 m/s with respect to the air. the air is moving with a speed 47 m/s with respect to the ground due north. 1)what is the speed of the plane with respect to the ground?
Answer:
Vp = 120 cos 210 + 120 sin 210 = Vi1 + Vy1 due East zero coordinates
Vp = -103.9 i - 60 j vector description of velocity of plane
Vw = 47 j vector description of wind
V = Vp + Vw = -103.9 i - 13 j
V = (103.9^2 + 13^2)^1/2 = 104.7
Cos θ = -103.9 / 104.7 = 187.1 deg X-component of final velocity
Sin θ = -13 / 104.7 = 187.13 deg Y-component of final velocity
(Final velocity = 104.7 m/s 7.1 deg S of W)
Does a charge on an atom change the number of valence electrons?
It is thought that oxidation/reduction reactions take place in an atom's valence shell. Therefore, the existence or absence of additional valence electrons is related to the formal charge.
Any of the fundamentally negative charged atom-external particles called valence electrons participate in the synthesis of chemical bonds. The atomic number (Z) of oxygen is 8. The oxygen atom's nucleus has 8 protons (this is what makes it an oxygen atom).
Therefore, the neutral atom should have 8 electrons, but 2 of them are thought to be in the inner core. We typically represent oxygen in a molecule as R- OR, with 2 lone pairs on the oxygen. While the O center is thought to have half of the 2 electrons that make up the C-O bond or 1 electron, these 2 lone pairs are thought to have a charge that is totally connected with the O atom.
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A spring has a natural length of 0.64m.It extended 0.024 m when a load of 3.6 N is applied. What would bring about an extension of 0.02m.
3N would bring about an extension of 0.02m.
A spring force is the force required or applied to compress or stretch a spring on an object attached to it. When an object exerts a force on a spring, the spring exerts an equal and opposite force on the object. It always acts to return the mass to its equilibrium position.
so here it is given that a spring has a natural length of 0.64m.It extended 0.024 m when a load of 3.6 N is applied.
formula
F₂/F₁=x₂/x₁
so
F₂=x₂/x₁*F₁
=0.02/0.024*3.6
=3N
So from the given data and using the equation we solved the proble and got 3N as the final answer
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An object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm. The image height is
Since the magnification is equal to 1, the image height is the same as the object height which is 5 cm
What is Optical Magnification ?Magnification is when the ratio of the size of the image to the size of the object is greater than 1
Given that an object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm.
The object distance u = 20 cmThe object height h = 5 cmFocal length f = 10 cmThe image distance v = ?The image height H = ?To find the image height, let us first find the image distance by using the formula below
1/f = 1/u + 1/v
Substitute all the parameters
1/10 = 1/20 + 1/v
1/v = 1/10 - 1/20
1/v = (2 - 1)/20
1/v = 1/20
v = 20 cm
Magnification = v/u = H/h
20/20 = H/5
H = 5 cm
Therefore, the image height is the same as the object height which is 5 cm
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A simple pendulum has time period of 2s. It is called second pendulum. Fimd the length of second pendulum on earth and moon(gm=g/6)
The length of the second pendulum on earth is 1m and on the moon 1/6m.
Given:
The time period of a second pendulum T = 2s
By using the formula T = 2π √l/g we can calculate the length of the pendulum on earth and the moon.
Here g = acceleration due to gravity and
l = the length of the pendulum.
Now
l = g(T/ 2π)^2
l = 9.8 m/s^2(2s / 2 x 3.14)^2
le = 1 m
Now calculate the length of the pendulum on the moon
T = 2π √lm/gm ∴ gm = ge/6
Now putting the value of g we get.
or 2 = 2 π √lm / ge/6
2 = 2 π √6lm / π ^2le
lm = le/6
now given le = 1m
lm = 1/6 m
Thus the length of the second pendulum on earth is 1m and on the moon 1/6m.
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Where in the hispanic world can you find a place that has coastlines on the same side of the country that are on both the pacific ocean and the caribbean sea?.
Answer: Panama
Explanation:
A load weighing 0.3 kg was suspended on the left edge of a homogeneous beam weighing 0.4 kg. At what distance from the left edge it is necessary to establish a fulcrum so that the lever is in balance, if the length of the beam is 70cm,
The "arm" of the lever is the handle or bar; it is the portion that you push or pull against. The point on which the lever rotates or balances is known as the "fulcrum.
What is a fulcrum and Lever?The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.
Torque is essential to the operation of levers. The point on which the lever rotates or balances is known as the "fulcrum. Your hand's fingers serve as the fulcrum when using a fork. A lever's pivot point serves as an illustration of a fulcrum.To learn more about fulcrum refer to:
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Conversations with astronauts on the lunar surface were characterized by a kind of echo in which the earthbound person's voice was so loud in the astronaut's space helmet that it was picked up by the astronaut's microphone and transmitted back to Earth. It is reasonable to assume that the echo time equals the time necessary for the radio wave to travel from the Earth to the Moon and back (that is, neglecting any time delays in the electronic equipment). Calculate the distance from Earth to the Moon (in km) given that the echo time was 2.52 s and that radio waves travel at the speed of light (3.00 ✕ 10^8 m/s).
The correct answer is 378000 km.
The speed of light is the rate at which light waves move through distinct substances. In instance, it has now been established that the speed of light in a vacuum is 299,792,458 metres per second.
Using the equation
distance = speed × time,
the total distance travelled is calculated.
Consequently, the overall distance travelled is
Distance = ( 3.00 × 10^8 m/s ) ( 2.52 )
= 756000000 m
The total distance travelled divided by two determines the distance between the Earth and the Moon.
Distance between earth to moon = 756000000/2
= 378000000 meters
= 378000 km.
Approximately 384 thousand kilometres separate the Earth and the Moon.
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THE FIRST PERSON TO GIVE ANSWERS GETS BRAINLIEST
PLEASE HELP URGENT
Answer:
momentum = mass x velocity
1×50=50_
mu=mv
mu+mv=(m1+m2)v
50×1+20×0.5=v(1+0.5)
v=60÷1.5
v=40
If you run 12 km at an average speed of 4 km/h, how much time does it take? ___ hours
consider two protons initially at rest separated by a distance . the two protons are then moved towards each other until they are again at rest a distance apart.
Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.16 MeV.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.
In classical physics, an object of mass m moving at a speed of v has kinetic energy.
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An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength, but would differ based on what physical property of light?.
An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength but would differ due to the amplitude property of light.
It is the amplitude of light which makes one sample brighter than other.
The amplitude plays an important part in differentiating the same colors of the same wavelength. It tells us about the brightness or intensity of a certain light wave as compared to others of the same wavelength. So, whenever two same colors look different due to brightness, it is due to the amplitude property of the light.
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experimenter a uses a test charge q0 and experimenter b uses a test charge 2q0 to measure an electric field produced by stationary charges. a finds a field that is:
A finds a field that is the same as the field found by B.
How to find the electric field?The physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field is known as an electric field (or E-field). Additionally, it describes the physical environment of a system of charged particles.
No matter how large the test charge is, stationary charges always produce the same electric field at a certain area.
At a distance "r" from it, the electric field created by a stationary charge "q" is given as
[tex]E = K_{q} /r^{2}[/tex]
Thus, the appropriate option is e) the same as the field found by B.
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Which of the following is a liquid?
OA. Steak
OB. Sugar
OC. Juice
OD. Smoke
Answer: Juice
Explanation:
the average weight of an elephant is 4000N the surface area of thr sole of its foot is 0.1m^2 calculate the pressure by one foot of an elephant
Answer
Explanation:pressure = Force/area
Force = 4000N
Area=0.1m
pressure = 4000/0.1
=40000P.a
a daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. (don't try this at home.) the speed of the horse is 9.28 m/s and the vertical distance from the limb to the saddle is 3.00 m.
Using time and velocity relationship, we concluded that he horse will be in air for 0.80 seconds.
What is the relationship between time and velocity?velocity-time. In evenly accelerated, straight-line motion, the relationship between velocity and time is straightforward. The magnitude of the velocity change increases with lengthier acceleration. When acceleration is constant, the change in velocity is exactly proportional to time.
Both the horse and the human have constant accelerations, which are 0 for the horse and g downward for the human.
(A) Take into account the man's vertical motion after he leaves the limb (with v₀ = 0, yi = 3m).
Finding the man's time of fall from y = y₀ + vt + 1/2 a t² requires modeling him as a particle with continuous acceleration.
when v₀ = 0
t = √(2(y - y₀)/a)
= √ (2(0 - 3) / -9.28)
= √0.64
= 0.80s
Complete Question -
A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0m/s, and the distance from the limb to the level of the saddle is 3.00m. (a) For what time interval is he in the air?
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A car starts with a velocity of 10 m/s. it
accelerates for 3 seconds at a rate of 2
m/s/s. what is its final velocity?
The final velocity would be 20m/s.
What is a final velocity?An object's final velocity is the speed at which it is moving after experiencing an acceleration over a period of time.The final step in calculating velocity is to multiply the initial velocity by the acceleration over time.The velocity at time t following the starting velocity is represented by the symbol v. Despite frequently being referred to as the last velocity, it is not the "last velocity" of an item.Distance and displacement are connected to speed and velocity in the same way. Velocity is a vector, whereas speed is a scalar. Speed is denoted by the letter v (italic), while velocity is denoted by the letter V. (boldface). A bar is added to the symbol over typical values.What is its final velocity?
Using the first equation of motion
V = U + at
where V = Final Velocity
U = Initial Velocity
a = Acceleration
t = Time
V = 10 + 1*10
V = 20 m/s.
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A stone is thrown vertically downward from a cliff 208.0-m tall. during the last half second of its flight, the stone travels a distance of 48.5 m. find the initial speed of the stone.
A stone is thrown vertically downward from a cliff, the initial speed of the stone is 76.246m/s.
CalculationHeight of the cliff = 208m
Distance travelled during last half second = 48.5 m
According to the second equation of motion:
[tex]s1= vt + 1/2 gt^{2}[/tex]
[tex]v= (2x_{1} - gt^{2})/2t[/tex]
v= [tex]\frac{2(48.5) - (9.8)(0.5)^{2} }{2(0.5)}[/tex]
v= 94.55 m/s
If the initial speed of the ball is u,
then again from the equation of motion, we get initial speed as
u=[tex]\sqrt{v^2 - 2gh}[/tex]
=[tex]\sqrt{94.55^2 -2(9.8)(208-48.5)}[/tex]
u= 76.246 m/s
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You drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles.
the average speed?
The average speed for the two events is 25.2 m/s
What is Average Speed ?Average speed is the ratio of the total distance travelled by a body to the total time. It is measured in m/s
If you drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles. To calculate the average speed, first convert the mile to meter
1 mile = 1609.34 m
10 miles = 10 × 1609.34 = 16093.4 m
Calculate the time for each event.
speed = distance / time
time = distance / speed
T1 = 16093.4 / 20
T1 = 804.67 s
T2 = 16093.4 / 34
T2 = 473.34 s
Total time t = T1 + T2
t = 804.67 + 473.34
t = 1278.01 s
Total distance s = 16093.4 + 16093.4
s = 32186.8 m
Average speed = s / t
Average speed = 32186.8 / 1278.01
Average speed = 25.19 m/s
Therefore, the average speed for the two events is 25.2 m/s approximately.
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1. With what force will a car hir a free if the car has a mass of 3,000 kg and accelerating at a rate of 2 m/st?
The force the car will use to hit the tree, given it has a mass of 3000 Kg and accelerating at 2 m/s² is 6000 N
How to determine the forceFrom the question given above, the filling data were obtained:
Mass (m) = 3000 KgAcceleration (a) = 2 m/s²Force (f) = ?Force is related to acceleration according to the following formula:
Force = mass × acceleration
Thus, we can obtain the force as illustrated below:
Force = mass × acceleration
Force = 3000 × 2
Force = 6000 N
From the calculation made above, we can conclude that the force the car will use to hit the tree is 6000 N
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Which event occurs when an atom undergoes nuclear fusion?
OA. Its nucleus loses all its mass.
OB. Its nucleus combines with another nucleus.
C. Its nucleus breaks apart.
OD. Its nucleus absorbs energy.
Answer:According to the context, its nucleus breaks apart is an event that occurs when an atom undergoes nuclear fission.
Explanation:
you leave the airport in college station and fly 26.0 km in a direction 34.0∘ south of east. you then fly 46.0 km due north. part a how far must you then fly to reach a private landing strip that is 32.0 km due west of the college station airport? express your answer with the appropriate units.
I must fly about 62.56 km in the Southwest direction to reach a private landing strip that is 32.0 km due west of the college station airport.
This can be understood through concept of Vectors. Vectors are defined as entity which has both direction and magnitude.
According to the question, 27 km in a direction 34.0° south of east hence angle is -34°.
Along x axis = 27cos (-34) ° and along y axis = 27sin (-34) °
Along x axis ≈ 22.4 km and along y axis ≈ -15.1 km.
Now, fly 46 km due north.
Along y axis=46, along x axis = 0
Next, along x axis ≈ 22.4 km, Along y axis ≈ -15.1 + 46 ≈ 30.9 km
Hence (22.4, 30.9)
Final Position is 32 km due west is that is ( -32, 0)
Distance between (22.4, 30.9) and ( -32, 0)
√ {(22.4 - (-32)) ² + (30.9 - 0) ²}
≈ 62.56 km Direction Southwest
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Helppp Mass in motion lab report
The purpose of the motion lab is to collect experimental data on two constant-speed cars with different constant speeds and a dynamic car showing acceleration.
The laboratory report must document the experiments and raw data included in the report, provide sufficient information to reproduce or extend the data analyze the data, and draw conclusions. It has three main functions presenting and creating. Recommendations based on experimental work
In this lab, we were able to study projectile motion by determining the ball's initial velocity and finally predicting the projectile's range. In this projectile motion lab, we used the equations of motion for a projectile to predict distance. It combines the examination of a person's anatomy with the measurement of function during activity.
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What is the length of the x-component of the vector shown below?
34°
8
OA. 4.5
OB. 6.6
OC. 5.4
OD. 8
Answer: B
Explanation: I am 99% sure that is correct I remember doing something very simular
consider a uniformly charged ring in the xy plane, centered at the origin. the ring has radius aaa and positive charge qqq distributed evenly along its circumference.
The electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]
The radius of the ring is: [tex]a[/tex]
The charge on the ring is: [tex]q[/tex]
The coulomb's constant is: [tex]k = \frac{1}{{4\pi {\varepsilon _0}}}[/tex]
The expression of the electric field is: [tex]E = \frac{{kq}}{{{r^2}}}[/tex] .......(i)
Here,
[tex]r[/tex] ⇒ distance = [tex]\sqrt {{z^2} + {a^2}}[/tex]
Now, putting [tex]r[/tex] in equation (i), we get,
[tex]\begin{array}{c}\\E = \frac{{kq}}{{{{\left( {\sqrt {{z^2} + {a^2}} } \right)}^2}}}\\\\ = \frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}\\\end{array}[/tex]
The electric field along the z-direction is
[tex]dE\left( z \right) = dE\cos \theta[/tex] ........(ii)
here, [tex]\cos \theta = \frac{z}{{\sqrt {{z^2} + {a^2}} }}[/tex]
Integrating equation (ii), we get,
[tex]\begin{array}{c}\\\int {d{E_z}} = \int {dE\cos \theta } \\\\E\left( z \right) = E\cos \theta \\\end{array}[/tex].......(iii)
Now substituting the values in equation (iii), we get,
[tex]\begin{array}{c}\\E\left( z \right) = \left( {\frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}} \right)\left( {\frac{z}{{\left( {\sqrt {{z^2} + {a^2}} } \right)}}} \right)\\\\ = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}\\\end{array}[/tex]
Therefore, the electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]
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Consider a uniformly charged ring in the [tex]xy[/tex] plane, centered at the origin. The ring has radius [tex]a[/tex] and positive charge [tex]q[/tex] distributed evenly along its circumference. What is the magnitude of the electric field along the positive [tex]z[/tex] axis? Use k in your answer, where [tex]k = \frac{1}{4 \pi \epsilon_0}[/tex]
A racing car reaches a speed of 42 m/s. It then begins to decelerate, using its parachute and braking system, and comes to rest 5.5 s later. Find the rate of deceleration.
The rate of deceleration of a racing car that reaches a speed of 42m/s is 7.64m/s.
How to calculate deceleration?Deceleration is the amount by which a speed or velocity decreases.
The rate of deceleration can be calculated using the following formula:
d = (v - u)/t
Where;
d = decelerationv = final velocityu = initial velocityt = timeAccording to this question, a racing car reaches a speed of 42m/s. It then begins to decelerate, using its parachute and braking system, and comes to rest 5.5s later. The deceleration can be calculated as follows:
d = (42 - 0)/5.5
d = 42/5.5
d = 7.64m/s
Therefore, the rate of deceleration of a racing car that reaches a speed of 42 m/s is 7.64m/s.
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A student contends:
"If I climb up a mountain at 1 mile per hour for 2 hours and then turn around and climb back down at 3 miles per hour, then my average speed will be 2 miles per hour."
What, if anything, is wrong with this statement? If something is wrong, identify it and explain how to correct it. If this statement is correct, explain why.
The statement is wrong and the correct average speed of the student will be 3/2 or 1.5 miles per hour.
Given in the question,
The student climbs the mountain at a speed of 1 mile per hour, then the distance traveled by the student uphill is given by
Distance = Speed × Time,
Put in the values, we get
Distance = 2 × 1 = 2 miles
So the student travels 2 miles uphill and turns around and climbs back at 3 miles per hour.
So the time taken by the student to climb back is given by
Time = Distance/Speed
Time = 2/3 hr
So Now
Total distance traveled by the student = Uphill climb + Downhill Climb
Total distance traveled by the student = 2 + 2
Total distance traveled by the student = 4 miles
Total time taken = Time to climb uphill + time to climb downhill
Total time taken = 2 + 2/3 hr
Total time taken = 8/3 hr
Now average speed is given by the formula,
Average Speed = Total Distance traveled/Total Time taken
Average Speed = 4 / (8/3)
Average Speed = (4 × 3) / 8
Average Speed = 12 / 8
Average Speed = 3/2 miles per hour
Therefore, the statement that the average speed will be 3 miles per hour is wrong and the correct average speed of the student will be 3/2 or 1.5 miles per hour.
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What is the position of the mailbox? (I really don’t understand this)
Answer:
The graph is a velocity-time graph, showing velocity as an f(t), (function of time).
The graph depicts the following:
For 6 seconds, the mailman travels at the constant rate of 3m/s. At second 6, he abruptly stops (when he stops for the mailbox which he overshot) which is represented by the dotted vertical line. He then stays at the constant rate of 0 m/s (stationary) for 2 seconds before he goes into reverse for 2 seconds at the rate of 2m/s before arriving back at the mailbox.
Some items to note:
In a real-world situation, the abrupt stop would be unrealistic and therefore may be a slope for about 1 second.
A dotted line represents a break in the graph, for our situation, it means the velocity has dropped.
A negative velocity, like in his graph, is just going in reverse.
To find the position of the mailbox:
Change the graph to a position-time graph which shows position as an f(t). Using this new graph, you can find the position of the mailbox using time at the 10th second.
Just a quick note, changing between types of graphs is an essential part of physics and you should be able to do it with no reference. It is in your best interest to learn this to be able to apply it in the future.
Hope that helps