What is the relationship between change in position and velocity?

Answer:

Newton's Universal Law of Gravitation is a law created by Newton (obviously). It is the equation [tex]F=G\frac{m1m2}{r^{2} }[/tex] where F is the force of gravity, G is the gravitational constant (varies between places), m1 and m2 are the masses of the 2 objects and r is the distance between the centers of the 2 masses.

Newton's law of gravitation, states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.

Hope that provides a basic overview

Answer:d=80,001 m

Explanation:df = di + Vave(t)

d = 0 + 300,000,000(0.00026667)

d = 80,001 m

The correct answer is 21 m.

The term "uniformly accelerated motion" refers to a body or object moving at a consistent rate of acceleration. The absence of velocity does not imply constant acceleration. Therefore, if a body is in motion such that the amount of change in its velocity in equally spaced time intervals will be constant, then that is what is meant by uniform acceleration or uniform acceleration definition.

Given initial velocity = 0 m/s

acceleration = 6 m/s^2

The body's movement in nth seconds in terms of distance,

S_n = u + a/2 (2n-1)

S_4 = 0 + 6/2 ( 2 × 4 - 1 )

S_4 = 3 ( 8 -1 )

S_4 = 3 × 7

S_4 = 21 m

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The distance the red ball travelled between 12 s and 24 s is 2116.8 m

Free fall is motion under gravity.

If we assume the red ball is falling freely, it has an initial velocity of zero.

Using the equation of motion s = ut - 1/2gt², we find the distance it travels or height it drops after the given time. where

So, s = ut - 1/2gt²

s = 0 × t - 1/2gt²

s = -1/2gt²

Since the distance the red ball falls is s = -1/2gt² with t = 12 s, we have

s = -1/2gt²

= -1/2 × 9.8 m/s² × (12 s)²

= -1/2 × 9.8 m/s² × 144 s²

= -4.9 m/s² × 144 s²

= -705.6 m

Since the distance the red ball falls is s = -1/2gt² with t = 24 s, we have

s' = -1/2gt²

= -1/2 × 9.8 m/s² × (24 s)²

= -1/2 × 9.8 m/s² × 576 s²

= -4.9 m/s² × 576 s²

= -2822.4 m

So, the distance the red ball travelled between 12 s and 24 s is d = s' - s

= -2822.4 m - (-705.6 m)

= -2822.4 m + 705.6 m

= -2116.8 m

So, the distance the red ball travelled between 12 s and 24 s is 2116.8 m

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Answer: 1. -15m/s

2. -37.5m

Explanation:

1. -3m*5=-15m/s

2. v=velocity. d=displacement. t=time. a=acceleration

d=vt+(1/2)at^2

d=0*5+(1/2)(-3)(5)^2   ==> car was at rest before accelerating

d=0+(1/2)(-3)(25)

d=(1/2)(-75)

d=-37.5 meters

The egg is traveling at least at a speed due to gravity of 20 m/s.

The force of gravity causes items to fall toward the ground. The force of gravity accelerates items as they descend to the ground. Velocity is a measure of the speed and direction of motion, and acceleration is a change in velocity. The longer an object is in free fall, the faster it descends toward the ground due to gravity.

In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall. By the time it has been falling for 2 seconds (9.8 m/s plus 9.8 m/s), it is moving at 19.6 m/s, and so on.

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A. Another conclusion that can be drawn from the student experiment is the ball stops because there is some force acting on it.

There are several forces that will act on an object moving on an inclined plane. These forces include the following;

When the object is moving up, gravitational force will tend to pull the object downwards and the frictional force will tend to oppose this downward motion of the object.

When the object is rolled down the plane, gravitational force tends to aid the motion of the object while frictional force tends to slow the object down.

Eventually, the object stops because the frictional force opposing the object motion is greater than the gravitational force pushing the object downwards.

Thus, another conclusion that can be drawn from the student experiment is the ball stops because there is some force acting on it.

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Answer:Apparently the further displacement should be of other 3 cm; but, let's consider the development of the spring on one vertical plain, and fixed on a wall by the upper end.

Now the spring doesn't look circular; but as a stick fixed on the wall. Before placing the first 100 grams weight, the stick is not horizontal; but its overhanging end is lower by the measured length of the spring at rest. The length line of the spring with its horizontal projection line forms an angle.

The first 100 grams load is decomposed in function of the new angle: one component in line with the stick, the other one perpendicularly respect to it. The same happens with 200 grams.

The flection momentum is given by the perpendicular component of the load with respect to the stick line in overload, and the measure of the stick itself. Such component is inversely proportional to the other component, and decreases in relation to higher load while the other component (that doesn't produce flexion) encreases.

I assume that I can't calculate the new displacement because is not given the height of the spring at rest, the length of the development of the spring. Accordingly, I cannot calculate all various angles of the stick in relation with gravity.

Explanation:

When a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.

Hooke's law states that the applied force [F] equals a constant k times the displacement or change in length [x].

Mathematically - F = - Kx

Given is a situation in which a stretch of 8 cm is caused by a 100g mass.

From this, we can write -

Mass [m] = 100 g = 0.1 Kg

Displacement [x] = 8 cm = 0.08 m

According to the question -

The spring constant [K] can be calculated using Hook's law as -

F = -Kx

mg = -Kx

K = - mg/x

K = - (0.1 x 9.8) / 0.08

K = - 12.25 N/m

|K| = 12.25 N/m

Now, when mass [M] = 25g = 0.025 Kg, using Hook's law -

|F| = |- kx| = kx

Mg = 12.25x

x = Mg/12.25

x = (0.025 x 9.8)/12.25

x = 0.02

x = 2 cm

Therefore, when a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.

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The rate constant increases by a factor of 1.3 when the temperature increases from 200k to 400k for a reaction with an activation energy of 845 j/mol.

ln k2/k1 = 845/8.314 (1/200 - 1/400)

ln k2/k1 = 0.254

k2/k1 = 1.3

The Arrhenius equation, which has the form lnk=RE(T1T1), relates the activation energy (Ea) and rate constants (k1 and k2) of a chemical process at two distinct temperatures (T1 and T2).

Where T1 and T2 are the temperatures of rates k1 and k2 (respectively) in K, k1 and k2 are rate constants, Ea is the activation energy in J/mol, and R is the gas constant which has a value of 8.314 J/K mol.

The activation energies employed were 20.1 kJ/mol and 59.8 kJ/mol.

The rate constants K1 and K2 are 1016 e-2000/T and 1015 e-1000/T, respectively, for two distinct reactions.

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The approximate magnitude of the attractive gravitational force between ganymede and jupiter  is 16.35 x 10^21 N .

According to Newton’s Law of Gravitation, the gravitational force between two bodies is directly proportional to the masses of the two objects and is inversely proportional to the square of the distance between them.

The above statement can be represented by the following equation:

F = Gx (m1)x (m2)/r^2

Here G = Universal Gravitational Constant = 6.67 x 10^-11 N m^2/kg^2

m1 and m2 are the masses of two bodies

r is the distance between the bodies

Putting m1= Mass of Jupiter= 1.89 x 10^27 kg

m2 =Mass of Ganymede 1.48 x 10^23 kg

r = Distance between Jupiter and Ganymede = 1.07 x 10^9 meters

F = 6.67 x 10^-11 x 1.89 x 10^27 x 1.48 x 10^23/(1.07 x 10^9)^2

On solving the above equation F comes out to be 16.35 x 10^21 N.

Thus, the approximate magnitude of the gravitational force between Ganymede and Jupiter is 16.35 x 10^21 N.

Because it consistently attempts to pull masses together rather than pushing them apart, the gravitational force is known as attractive. In actuality, every thing in the cosmos, including you, is pulling on every other object.

Gravitation is the force in physics that draws two masses together. Unbelievably, every single particle of matter in the cosmos attracts every other particle through gravity. The phrases gravitation and gravity are sometimes used synonymously to refer to the attraction that exists between anything with mass or energy.

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The ball rises 53.361 m above the point where the bat hit the ball.

When a batter hits a ball high in a baseball game, the ball remains in the air for 6.6 seconds.

The acceleration of gravity is 9.8 m/s².

The vertex value of time is half of 6.6 seconds or 3.3 seconds.

Therefore, the final velocity at the maximum height is v = 0 m/s

Now, using the equation of motion:

v - u = gt

v = u + gt

u × sin(θ) = - gt

u × sin(θ) = 9.8 × 3.3

u × sin(θ) = 32.34 m/s

Now, by using the equation of motion:

v² - u² = 2gh

h = ( v² - u²) / 2g

h = ( 0 - (32.34)² ) / 2(9.8)

h = (1045.8756) / 19.6

h = 53.361 m

The ball rises 53.361 meter high.

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The mass of an object that requires 15.0N to accelerate it at rate of 3 m/s² is 1.17 kg.

The mass of an object is the quantity of matter present in an object.

The mass of an object is related to its acceleration and the applied force by the given formula below:

force = mass * acceleration

mass = force/acceleration

From the data provided:

force applied = 15.0 N

acceleration = 3 m/s²

The force applied overcomes the weight of the body.

Total force applied = weight + net force

Total force = mg + ma

Total force = m(g + a)

m = force/(g + a)

mass = 15(9.8 + 3)

m = 1.17 kg

Therefore, the mass of the object is 1.17 kg.

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The values you found are incorrect.

The sum/resultant vector is

[tex]\hat R = \hat A + \hat B \\\\ \hat R = (5.00\,\mathrm m)\,\hat\imath + (6.00\,\mathrm m)\,(-\cos(30.0^\circ)\,\hat\imath - \sin(30.0^\circ)\,\hat\jmath) \\\\ \hat R = (2.00\,\mathrm m) \,\hat\imath - (3\sqrt3\,\mathrm m)\,\hat\jmath \\\\ \hat R \approx \boxed{(2.00\,\mathrm m)\,\hat\imath - (5.20\,\mathrm m)\,\hat\jmath}[/tex]

The magnitude of the resultant is

[tex]\|\hat R\| = \sqrt{(2.00\,\mathrm m)^2 + (-5.20\,\mathrm m)^2} \approx \boxed{5.57\,\mathrm m}[/tex]

The direction or angle the resultant makes with the positive horizontal axis is [tex]\theta[/tex] such that

[tex]\tan(\theta) \approx \dfrac{-5.20\,\mathrm m}{2.00\,\mathrm m} \approx -2.60[/tex]

Note the signs of the [tex]\hat\imath[/tex] and [tex]\hat\jmath[/tex] components of [tex]\hat R[/tex]. They tell us that [tex]\hat R[/tex] points into the fourth quadrant, and this means we can take the inverse tangent of both sides without any extra steps*. We then get

[tex]\theta \approx \tan^{-1}(-2.60) \approx \boxed{-67.0^\circ}[/tex]

* There would have been an extra step if [tex]\hat R[/tex] were pointing into either the second (negative [tex]\hat\imath[/tex], positive [tex]\hat\jmath[/tex]) or third quadrant (both negative [tex]\hat\imath[/tex] and [tex]\hat\jmath[/tex]). The inverse tangent function has a range of -90° to 90°, which means upon taking the inverse tangent of both sides of

[tex]\tan(\theta) = \dfrac{R_y}{R_x} \implies \theta = \tan^{-1}\left(\dfrac{R_y}{R_x}\right)[/tex]

we would only recover some angle [tex]\theta[/tex] between -90° and 90°. Yet our resultant must have some angle between -180° and -90°, or between +90° and +180° to belong to quadrant II or III. To get around this, we add an appropriately chosen multiple of 180° to the right side after taking the inverse tangent.

Answer:

(174^2 + 88.4^2)^1/2 = 195 m       magnitude of resultant vector

(tan θ = 88.4 / 174 = .508 or 26.9 deg)

Kepler used the extensive records of planetary positions measured by  Tycho to discover that the orbits of the planets are elliptical.

The planets would be listed from smallest to largest in order of size: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter. The gas giants are Jupiter and Saturn, whereas the more distant Uranus and Neptune are known as the ice giants.

The International Astronomical Union (IAU) downgraded Pluto to a dwarf planet since it failed to satisfy all three criteria for a full-sized planet. Pluto essentially meets all the criteria, with the exception of the one that it "has not cleared its nearby vicinity of other objects."

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The magnetic field lines of the magnetized iron ring are concentrated near the north and south poles of the ring.

When an iron ring is put near the north pole of a bar magnet, the bar magnet's magnetic field lines are drawn to it. As a result, the iron ring gets magnetic, and its field lines become concentrated towards the ring's north and south poles.

By matching the north pole of the iron ring with the north pole of the bar magnet, the iron ring is magnetized. This produces a strong magnetic field between the two poles, magnetizing the iron ring. The iron ring's magnetic field lines will be visible as a series of concentric circles around the bar magnet's north pole.

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0.1 J of elastic potential energy will be stored by the spring when it gets compressed by 0.2 m if it has the spring constant of 5 N/m.

Elastic potential energy can be defined as the potential energy stored by the spring when it is stretched or compressed.

According to the question.

Compression in the spring, x = 0.2 m

Spring constant, k = 5 n/m

Elastic potential Energy, U = [tex]\frac{1}{2} (0.2)^{2} (5)[/tex]

U = 0.1 J

0.1 J of elastic potential energy will be stored by the spring.

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The property of the rock that will change if it is transported from the moon to the earth, is the weight.

The weight of an object is directly proportional to the action of gravity on the mass of that object. It can be confirmed with the weight formula:

W = m * g

Where:

By contrast, the mass of an object indicates the amount of matter it contains, it is a constant magnitude.

It is the physical magnitude that expresses the force exerted by gravity on the mass of a body, this is expressed in units of the international system in Newton.

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Because protons and electrons in an atom carry opposite charges, they are attracted to each other and thus maintain the boundaries of the atom as a  singular closed system.

An atom consist of equal number of electrons and protons, due to which the attractive force between them binds the atom together and hence no exchange of matter takes place, therefore an atom posses closed system.

If we consider that energy is emitted, when electrons emit energy, then this energy is absorbed in the atom, thus preventing the electrons from hitting the nucleus. More specifically, as the electron wave travels around the nucleus, it emits energy, but this energy is recaptured when the wave doubles back on itself in 1/2 or full wavelengths to form a standing wave.

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The magnitude of the force exerted by the electric field on the proton will be 4.80 × 10—¹⁷ N.

The force exerted by the electric field on the electron =

4.80 × 10—¹⁷ N.

The direction of the electric field that is exerting force on the electron = West

The magnitude of the electric field is,

[tex] = \frac{4.80 \times 10 ^{ - 17} }{1.6 \times 10 - 19} [/tex]

= 300 N/C

The magnitude of the electric field is 300 N/C.

The magnitude of the force exerted by the electric field on the proton will be,

The magnitude of the force exerted by the electric field on the electron = The magnitude of the force exerted by the electric field on the electron.

[tex] = 4.80 \times 10 ^{ - 17} [/tex]

Therefore, the magnitude of the force exerted by the electric field on the proton will be 4.80 × 10—¹⁷ N.

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The example of mass and weight being proportional is Force = mass * acceleration.

The proportionality can be direct or inverse proportionality.

Direct proportionality can be defined as the increase in the second quantity if there is an increase in the first quantity when both quantities are related.

Inverse proportionality can be defined as a decrease in the second quantity when the first quantity is increased when both quantities are related.

Mass and weight are proportional to each other.

For that we can consider the example given below:

weight is the force exerted by the earth's gravity on the particle.

we know that

force = Mass * acceleration

as weight = force

weight = mass * acceleration

so if the acceleration is constant the increasing weight mass also increases.

so at constant acceleration weight and mass are directly proportional.

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Answer: The charges must be like charges (both positive or both negative).

Explanation:

The mass of the electric car moving at the given speed and kinetic energy is determined as 920 kg.

The kinetic energy of an object is the energy possessed by the object due to the motion of the object. The kinetic energy of an objects is determined from the product of object's mass and its velocity.

The mass of the electric car is calculate by applying kinetic energy formula as follows;

K.E = 0.5 mv²

where;

Substitute the given parameters and solve for the mass of the electric car.

m = (K.E)/(0.5v²)

m = (222640) / (0.5 x 22²)

m = 920 kg

Thus, the mass of the electric car moving at the given speed and kinetic energy is determined as 920 kg.

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The speed and the direction of motion of player 2 is 2.2 = M1xV1 + M2xV2

2.2 = 47x1.1 + 38×V2

2.2 = 51.7 + 38xV2

-49.5 = 38×V2

V2 = -1.3 m/sec.

It means that the second object is moving opposite to first object.

Momentum is product of mass and velocity. It is a vector quantity and it's S.I unit kgxmeter/sec.

In above question

Player one has

M1 = 47 kg

V1 = 1.1 m/sec

Player two has

M2 = 38 kg

V2 = not given

Total momentum = 2.2 kgxm/sec

Total momentum = momentum of first body + momentum of second body

2.2 = M1xV1 + M2xV2

2.2 = 47x1.1 + 38×V2

2.2 = 51.7 + 38xV2

-49.5 = 38×V2

V2 = -1.3 m/sec.

It means that the second object is moving opposite to first object.

Therefore, The speed and the direction of motion of player 2 is 2.2 = M1xV1 + M2xV2

2.2 = 47x1.1 + 38×V2

2.2 = 51.7 + 38xV2

-49.5 = 38×V2

V2 = -1.3 m/sec.

It means that the second object is moving opposite to first object.

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The deflecting electric field is 0.83mv/m

Acc. to the newtons 2nd law - there is an acceleration when a force acts on an object.

F = ma     (equation 1)

where

F is force

m is mass of object

a is acceleration

Electric field intensity- it is defined as force experienced by a unit positive charge placed at that point.

it is denoted by E = F/q

where

F is force

q is the charge

F = Eq     (equation2)

from 1 and 2 equation we get

ma = Eq

E = ma /q

Charge on the drop of ink.is q.

(e is the charge on an electron.)

so,

q = 751896×e

q = 751896×1.6 ×⁻¹⁹

q = 12.03 ×10⁻¹⁴

m = 10⁻¹¹kg

a = 10⁴ m/s²

using above values

E = ma /q

E = 10⁻¹¹×10⁴/12.03 ×10⁻¹⁴

E = 0.83mv/m

The deflecting electric field is 0.83mv/m

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Answer:

D. All of the above

Explanation:

Because it's the most logical answer.

After a collision, there is no change in the momentum from the initial situation. This statement  satisfies the law of conservation of momentum. Hence, Option D is correct.

Momentum is the sum of an object's mass and velocity, and it is a property of all moving objects. This can be expressed mathematically as p=MV, where p stands for momentum. The momentum of an object can fluctuate because its velocity can. When describing the momentum of a system of objects, the Law of Conservation of Momentum is helpful. The Law of Conservation of Momentum, in its most basic form, states that the total momentum of an isolated system stays constant.

Hence, the momentum will be the same after the collision as it was before the collision.

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The frictional force acting on the block is completely static in nature and is equal to 90 Newton's.

Friction is a force that acts opposite to the direction of motion of body in order to oppose its motion.

Given in the question is a box of weight 120 N initially resting on a horizontal table. From the data given, we can write -

Weight of box [W] = 120 Newton

Coefficient of static friction (μ[s]) = 0.75

Coefficient of Kinetic friction (μ[k]) = 0.40

Horizontal push (F[h]) = 84 N

The frictional force is given by -

For Static friction - F[s] = μ[s] N

For Kinetic friction - F[k] = μ[k] N

Now, initially the box is at rest. When a horizontal force of 84 Newton is applied on it, the static friction will try to oppose the motion. For forward motion of the block -

F[h] - F[s] ≥ 0

F[h] - μ[s] N ≥ 0

84 - 0.75 x 120 ≥ 0            (Normal Reaction [N]  = Weight)

84 - 90 ≥ 0

- 6 ≥ 0

which is false.

This means that the static frictional force is greater than horizontal push and opposes the motion. The force due to static friction will only exist since, the body was able to move, so kinetic friction is of no use here.

So, the frictional force on the block will be = F[s] =  μ[s] N = 90 Newtons.

Therefore, the frictional force acting on the block is completely static in nature and is equal to 90 Newton's.

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The continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as Trade winds

These winds helps ships to travel west. It also steers hurricanes. These winds are air currents that are closer to the Earth's surface. These winds start as warm air from equator and as it travels to polar regions it gets cooler. Trade winds can be found 30 degrees North and South of the equator.

The subtropical high pressure belts extends from 35 degrees North and South of the equator. It is also called as Horse latitude. The equatorial low pressure belt is the area where the trade winds from Horse latitudes of both hemispheres converges.

Therefore, the continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as Trade winds

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A sled is initially moving on a straight track at 3.5 m/s. The final velocity of the sled will be 3.75m/s. When the acceleration is 2.0 m/s².

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on an item determines the direction of its acceleration.

Given parameters:

Initial velocity  = 3.5m/s

Final velocity  = ?

Time taken  = 2s

acceleration = 2m/s²

[tex]a = v_f - v_i/t[/tex]

2 = x - 3.5/2

x = 3.75 m/s

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