Answer:
θ = 1.22 λ / D
Above is the formula calculated for a circular aperature
If the wavelength is multiplied by 5 then the angle of resolution would be 5 times as great or 5 * θ
5 * θ = .5 seconds
a wrench 0.3 meters long lies along the positive yy-axis, and grips a bolt at the origin. a force is applied in the direction of ⟨0,−3,1⟩⟨0,−3,1⟩ at the end of the wrench. find the magnitude of the force in newtons needed to supply 100 newton-meters of torque to the bolt.
The magnitude of the force in newtons needed to supply 100 newton-meters of torque to the bolt is 359N.
What is magnitude of force?The amount that encapsulates the force's power is known as its magnitude. Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10." Magnitude may be thought of as simply the "value" or "amount" of any physical quantity.
The force applied that applies torque is:
Fz = 100 N-m / .3m = 333.33 N
Find the angle:
theta = tan^-1 ( 5/2) = 68.19 degrees
Total force:
F= 333.33 / sin(68.19) = 359N
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A car moved a total distance of 120 km in 90 minutes (1.5 hours). What was
the speed of the car?
OA. 45 km/hr
OB. 30 km/hr
OC. 60 km/hr
OD. 80 km/hr
A man fire a bullet with a velocity of 500 m/s velocity upward.( use gravity 10m/s2.
calculate
A the maximum could the bullet rise
B THE VELOCITY OF THE BULLET AT t=10s ,20s and 60s
C. the time require to move up
D. the time of flight
E the height it rise at t=20s
F. the height it rise when first velocity equal to 40 m/s
The maximum height reached by the bullet is 12,500 m.
The velocity of the of the bullet at 10s is 600 m/s.
The velocity of the of the bullet at 20s is 700 m/s.
The velocity of the of the bullet at 60s is 1,700 m/s.
The time required for the object to move to maximum height is 50.5 seconds.
The height reacted by the bullet at time, t = 20 seconds is 12,000 m.
The height risen by the bullet when the first velocity is 40 m/s is 80 m.
What is the maximum height reached by the bullet?The maximum height reached by the bullet is calculated as follows;
v² = u² - 2gh
v² = 2gh
h = v² /2g
h = (500²)/(2 x 10)
h = 12,500 m
Velocity of the of the bullet at various time intervalv = u + at
when t = 10 s
v = 500 m/s + 10(10)
v = 600 m/s
when the time, t = 20 seconds
v = 500 + 20(10)
v = 700 m/s
when the time, t = 60 s
v = 500 + 20(60)
v = 1,700 m/s
Time required for the object to move to maximum heightt = √(2h/g)
t = √(2 x 12,500 / 9.8)
t = 50.5 seconds
Height reacted by the bullet at time, t = 20 secondsh = ut + ¹/₂gt²
h = (500 x 20) + ¹/₂(10)(20²)
h = 12,000 m
Height risen by the bullet when the first velocity is 40 m/sh = v² /2g
h = (40²)/(2 x 10)
h = 80 m
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Karen is asked to look at two spots of light and judge which one gets brighter over time. Both spots start out at 100 units of brightness. She notices that the right spot is brighter when it is 110 units. If she is presented with two new spots of light both starting at 300 units, how much brighter will one have to get before she will be able to reliably detect the difference?.
One of the light spots will have to get 330 units brighter than the other for her to be able to tell the difference.
In the case of the first bulb, she noticed the difference when the right was 0.10 % brighter than the other one.
100 * 0.10 = 10
100 + 10 = 110
If we apply the same sense in the second case, one of the spots will have to be 0.10% brighter than the other.
300 * 0.10=30
300+30 = 330
In order to tell the difference, the other spot should be at 330 units of brightness.
The unit of brightness is Lumen. It is use to calculate the total amount of brightness emitted from a source over a unit of time.
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compare copper sulfate with the elements that form copper sulfate
Copper sulfate is a salt that is made up of the copper ion and the sulfate ion further, the sulfate ion is the combination of the sulfur and the oxygen atom.
What is a Chemical compound?The chemical compound is a combination of two or more either similar or dissimilar chemical elements
As given in the problem we have to compare copper sulfate with the elements that form copper sulfate,
The salt copper sulfate is composed of the copper ion and the sulfate ion. In addition, the sulfate ion is a mixture of sulfur and oxygen atoms.
The chemical formula for the copper sulfate is CuSO₄ which is made up of a Copper (Cu) atom, Sulphur (S) atom, and Oxygen (O) atom.
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Bob and carol are both observing the moon at exactly the same time. However, bob is in miami and carol is in los angeles. Bob observes the moon in the first quarter phase. In what phase will carol observe the moon to be?.
Bob and Carol are both observing the moon at exactly the same time. However, bob is in Miami and carol is in Los Angeles. Bob observes the moon in the first quarter phase. Carl will also observe the moon in the first quarter phase.
The moon cycle consists of four primary and secondary phases.
The four primary phases are New Moon, First Quarter Phase , Full Moon, and the Last Quarter.
During the new moon and full moon periods, there are definite chances of solar and lunar eclipses.
The secondary phases of the moon are waxing crescent, waxing gibbous, waning gibbous, and waning crescent.
In the southern hemisphere and northern hemisphere, people observe the same phases of the moon.
As Miami and Los Angeles are in the southern hemisphere i.e. south of the equator, therefore, people living in that hemisphere will observe the moon in the same phases. Thus Bob and Carol will also observe the moon in the first quarter phase from different cities.
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A 0.7500 cm diameter plastic sphere, used in a static electricity demonstra-tion, has a uniformly distributed 60.0 pc charge on its surface. what is the potentialnear its surface?
For a 0.7500 cm diameter plastic sphere, used in a static electricity demonstration, the potential near its surface is 144V.
CalculationV= kq/r = 9 x [tex]10^{9}[/tex] [tex]\frac{6*10^{-11}}{0.00375}[/tex]
=144 V
What is potential?The magnitude of the potential point per unit charge is the electric potential at a specific point. However, the following definition is far more accurate: The amount of work required to move a unit positive charge from infinity to a certain place is known as the electric potential at that location.
Potential is characterized as a thing’s potential to materialize. The greatest grades to which a specific student is capable are an illustration of potential.
What does voltage’s potential mean?The external effort required to move a charge in an electric field from one position to another is known as an electric potential difference, or voltage.
The difference in potential energy experienced by an object is known as its electric potential.
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How far did car A travel in the time interval t = 0 to t = 6?
Answer: Problem 03.043 - Velocity-time graph The figure shows a plot of vx(for a car traveling in a straight line. Vx (m/s) 20 | 15 20 7(s) What is aav.x between t = 9.00 s and t = 110 s? 7 m/s2 What is Vav,x for the time interval from t= 9.00 s to r= 110 s? What is Vav.x for the interval t = 0 to t= 15.0 s? m/s What is the increase in the car's speed between 10.0 s and 15.0 s? m/s How far does the car travel from time t = 100 s to t = 170 s?
The answer is 03.043 but i dont know maybe my brain is incorrect but I got 03.043. :| hope it helped if its correct.
Explanation: Well, I havent done math in a while bc im not in school anymore so i forgot all that stuff :|
Which is a type of fundamental force?
friction
spring force
normal force
weak interaction
According to the research, the correct option is weak interaction. A type of fundamental force is weak interaction.
What are fundamental forces?They are those that cannot be explained based on other more basic ones, where the particles interact by virtue of some characteristic that they possess and according to physics, four fundamental forces are recognized at the quantum level:
GravitationalElectromagneticStrong nuclear forceWeak interactionIn this sense, weak interaction is manifested in the transmission of particles where neutrinos and antineutrinos are emitted, without electrical charge and whose mass is very small or even zero, as in the case of the photon.
Therefore, we can conclude that according to the research, the correct option is weak interaction. A type of fundamental force is weak interaction.
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A wave as represented by the equation Y = 2 sin π (0.5x - 200t) Where all distances are measured in cm and in Second. For this wave, calculate a) frequency b)wave length C )Speed d) Amplitude e)period f)wave number g)angular velocity
By calculating, a) frequency = 100 Hz b)wavelength = 4 cm C )Speed = 400 cm/s d) Amplitude = 2 cm e)period = 0.01 s f)wave number = 0.5π g)angular velocity = 200π.
Given in question
Y = 2 sin π (0.5x - 200t)
Y = 2 sin (0.5πx - 200πt)
Comparing it with the standard form of a wave equation:
Y = Asin (kx - ωt) where
A= amplitude
K = wave number = 2π/λ where λ = wavelength
ω = Angular velocity = 2πf where f = frequency
We get
a) 2πf = 200π
f = 100 Hz
b) 2π/λ =0.5π
λ = 2π/0.5π
λ = 4 cm
c) Speed v = ω/k
v = 200π/0.5π
v = 400 cm/s
d) A= amplitude = 2 cm
e) period = 1/f = 0.01 s
f) K = wave number = 0.5π
g) ω = Angular velocity = 200π
Therefore, by comparing a) frequency = 100 Hz b)wavelength = 4 cm C )Speed = 400 cm/s d) Amplitude = 2 cm e)period = 0.01 s f)wave number = 0.5π g)angular velocity = 200π.
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5) A ball is thrown into the air vertically from the ground level with an initial speed of 20m/s. (a) How long is the ball in the air?
(b) What height does the ball reach?
The time spent in air by the ball is 2.04 seconds.
The maximum height reached by the ball is 20.41 m.
Time of motion of the ballThe time of motion of the ball is calculated as follows;
v = u - gt
where;
v is the final velocity of the ball at maximum height = 0u is the initial velocity of the ballg is acceleration due to gravityt is time of motion0 = u - gt
gt = u
t = u/g
given;
the initial, u = 20 m/sthe acceleration due to gravity, g = 9.8 m/s²t = (20) / 9.8
t = 2.04 s
Maximum height reached by the ballThe maximum height reached by the ball is calculated as follows;
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (20²) / (2 x 9.8)
h = 20.41 m
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You are driving down the road at a constant speed. Another car going a bit faster catches up with you and passes you. Choose the correct position graph for both vehicles on the same set of axes, and notes the point on the graph where the other vehicle passes you.
Answer: Option 4 (last graph)
Explanation:
1. Since you're driving at a constant speed, the line for your car will be linear. This rules out the first option.
2. This is a position time graph (x-t) graph. This means that to be moving forwards, there should be a positive slope. Option 3 can be eliminated as your car has a slope of 0. A slope of 0 on a position time graph shows an object at rest, not an object in motion.
3. The 2nd option can be ruled out as it represents that you are going faster than the other car. The steeper the slope = the faster the speed.
4. This ultimately leaves you with the last option as your final answer!
011 10.0 points
The acceleration due to gravity on planet X is one fifth that on the surface of the earth.
If it takes 4.6 s for an object to fall a certain distance from rest on earth, how long would it take to fall the same distance on planet X?
Answer in units of s.
If it takes 4.6 seconds for an object to fall a certain distance from rest on earth, then it would take 10.29 seconds to fall the same distance on planet X.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
Keep in mind that these calculations only apply to uniform acceleration.
As given in the problem, The acceleration due to gravity on planet X is one-fifth that on the surface of the earth. If it takes 4.6 s for an object to fall a certain distance from rest on earth, then we have to find how long would it take to fall the same distance on planet X,
By using the second equation of motion given by newton,
Let us suppose the acceleration due to gravity on the earth is 10 m / s²
S = ut + 1/2at²
= 0 + 0.5×10×4.6²
= 105.8 meters
The acceleration due to gravity on planet X = 2 meters / second
S = ut + 1/2at²
105.8 = 0 + 0.5×2×t²
t² = 105.8
t = 10.29 seconds
Thus, it would take 10.29 seconds to fall the same distance on planet X
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Show your work on the following problems.
1.
An airplane accelerates down a run-way at 3.20 m/s? for 32.8 s until is finally lifts off the ground
Determine the distance traveled before take-off.
2.A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. De
acceleration of the car and the distance traveled.
3.
A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the
acceleration of the car and the distance traveled.
4.
A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of
the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a
uniform acceleration).
The distance travelled by the airplane before takeoff is 1721 m.
2. The acceleration of the race car is 11.2 m/s², and Distance travelled by the car is 79.9 m.
3. The acceleration of the bullet is 1.62 * 10⁵ m/s².
What is the distance travelled by the airplane before takeoff?The distance travelled by the airplane before takeoff is determined using the formula:
s = ut + ¹/₂at²
u = 0; a = 3.20 m/s², t = 32.8 s
s = 0 * 32.0 + ¹/₂ * 3.2 * 32.8²
s = 1721 m
2. The acceleration of the race car is calculated as follows:
a = (v - u)/t
v = 46.1 m/s, u = 18.5 m/s, t = 2.47 s
a = (46.1 - 18.5)/2.47
a = 11.2 m/s²
Distance travelled, s = 18.5 * 2.47 + ¹/₂ * 11.2 * 2.47²
s = 79.9 m
3. The acceleration of the bullet is calculated as follows:
a = (v² - u²)/2s
where v = 0 m/s, u = 521 m/s, s = 0.840 m
a = (0² - 521²)/2 * 0.840
a = 161572.0238
a = 1.62 * 10⁵ m/s²
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One way to control avalanches is to send explosive charges to key areas on mountain slopes to trigger small avalanches before larger ones can build up. Norway, for instance, uses solar- powered launchers that fire pre-timed charges. Your launcher fires charges at an angle of 70 degrees from the horizontal and a speed of 200 m/s. If you fire a charge and it travels a horizontal distance of 300 m away from you, how high up the slope will it strike?.
By using uniform motion, the high up the slope will it strike is 730.62 m.
We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
θ = 70⁰
vi = 200 m/s
x = 300 m
Find the initial velocity in x and y axis
vx = vi cosθ = 68.40 m/s
vy = vi sinθ = 187.94 m/s
Find the time taken to reach 300 m
vx = x / t
68.4 = 300 / t
t = 4.39 second
Find the time taken to reach maximum height
vt = vo + a . t
0 = vy - g . t
vy = gt
187.94 = 9.8 . t
t = 19.18 second
The motion of projectile is raising to maximum height, hence
s = vo . t + 1/2 . a . t²
h = vy . t - 1/2 . g . t²
h = 187.94 . 4.39 - 1/2 . 9.8 . 4.39²
h = 730.62 m
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steam is accelerated in a steady-flow nozzle from a low velocity to a velocity of 210 m/s at a rate of 3.2 kg/s. if the temperature and pressure of the steam at the nozzle exit are 200 ºc and 600 kpa, what is the exit area of the nozzle?
The exit area of the nozzle is 0.000861 m² which is calculated using ideal gas equation.
What is an ideal gas?
Velocity = 280 m/s
Rate = 2.5 kg/s
Pressure = 2 MPa
Temperature = 400°C
Using equation of Ideal gas
PV= RT
V= RT/P
V= 0.0965 [tex]m^{3}[/tex]/ kg
Using equation of continuity
(dm/dt) = [tex]A_{1}[/tex]v/V
[tex]A_{1}[/tex]= 0.000861 [tex]m^{2}[/tex].
A theoretical gas known as an ideal gas is made up of several randomly moving point particles with no interparticle interactions. Because it abides by the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis, the ideal gas concept is helpful.
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Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal in the top and bottom is 0. 1 cm thick and the metal in the sides is 0. 05 cm thick.
The amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal on the top and the bottom is 0.1 cm thick and the metal on the sides is 0.05 cm thick is 8.8 cm.
The formula for calculating the volume of a cylinder is given below.
V = πr^2 h
Get the differential of the volume as shown:
dV = V/ h dh + V / r dr
V/ h = πr^2
V/ h = 2 πr h
Now, the differential becomes
dV = πr^2dh + 2πrh dr
Given the following parameters i.e. diameter and height
dh = 0.1 + 0.1 = 0.2 cm
dr = 0.05 cm
h = 10 cm
d = 4 cm
r = 2cm
Substituting the values in the above equation, we get
dV = 3.14(2)^2(0.2) + 2(3.14)(2)(10)(0.05)
dV = 2.512 + 6.28
dV = 8.792 cm
dV = 8.8 cm
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URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
The diagram below shows a portion of the electromagnetic spectrum. Which of the following statements correctly explains the relationship between FM and AM radio waves?
Answer: The difference is in how the carrier wave is modulated, or altered
Explanation:
With AM radio, the amplitude, or overall strength, of the signal is varied to incorporate the sound information. With FM, the frequency (the number of times each second that the current changes direction) of the carrier signal is varied
couldnt read that so gave my input hope it helps or is closly related to one of the answers
Answer: C. FM radio waves carry more energy than AM radio waves. This is supported by the fact that FM radio waves have a shorter wavelength compared to AM radio waves.
Explanation:
A truck driver has a shipment of apples to deliver to a destination 500 miles away. The trip usually takes him 9.0 hours. Today he finds himself daydreaming and realizes 110 miles into his trip that that he is running 20 minutes later than his usual pace at this point.
At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?
The speed at which the driver must drive for the remaining time to complete the trip in the usual time is 61.25 miles per hour.
What are the total distance the driver needs to cover and the approximate time?The total distance the driver should cover is 500 miles and this should be completed in 9 hours.
What is the regular speed?
Based on the information provided, the regular speed is:
500 miles/ 9 hours = 55.55 miles per hourHowever, we know today he has covered 110 miles and he is 20 minutes late. This means, there are 390 miles to cover and the remaining time is 6.7 hours.
500 miles= 9 hours or 540 minutes110 miles = x118.8 minutes + 20 extra minutes = 138.8 minutes = 2.3 hours9 hours - 2.3 hours = 6.7 hoursBased on this, let's calculate the new speed:
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a baseball is thrown straight into the air with an initial velocity of 85 mph. How far will the ball travel if it takes 5.4 seconds to land?
A) 316.0 m
B) 179.3 m
C) 432.5 m
D) 62.71 m
D. The distance traveled by the baseball during the given time is 62.32 m.
Distance traveled by the baseball
The distance traveled by the baseball is calculated as follows;
s = vt - ¹/₂gt²
where;
s is the distance traveled by the baseballv is the initial velocity of the baseballg is acceleration due to gravityt is the time of motion of the baseballThe given parameters;
v, initial velocity of the baseball = 85 mph = 38 m/s
g is acceleration due to gravity = 9.8 m/s²
t is the time of motion, = 5.4 seconds
Substitute the given parameters and solve for the distance travelled by the baseball as shown below.
s = (38 m/s)(5.4 s) - ¹/₂(9.8 m/s²)(5.4 s)²
s = 205.2 - 142.88
s = 62.32 m
Thus, the distance traveled by the baseball during the given time is 62.32 m.
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Niagra falls is 170 feet tall. How much gravitational potential energy is lost when a pound of water falls from
the top of the falls to the bottom of the falls? Answer in BTU.
The amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.
What is Gravitational Potential Energy?
The gravitational potential energy of a body is due to virtue of its position. A body of mass 'm' at height 'h' is given by -
P.E. = mgh
Given in the is Niagara falls which 170 feet tall. A pound of water falls from the top of the falls to the bottom of the fall. From this we can write -
Height of Niagra falls = 170 feet tall = 51.81 m
Mass of water = 1 pound = 0.46kg
Assume that the potential energy of the pound of water at 170 feet tall is (P[1]) and that at the bottom is (P[2]).
Now, at the top of falls, the potential energy of 1 pound of water = P[1] =
m x g x h = 0.46 x 9.8 x 51.81 = 233.55 J
At the bottom of the falls -
P[2] = 0
The amount of gravitational potential energy lost = P[1] - P[2] =
233.55 - 0 = 233.55 joules.
Therefore, the amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.
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Which timeline best shows the history development of cell theory
Answer:
you did not show a timeline luckly i did the the quiz it is the second timeline
Explanation:
Answer:
b
Explanation:
I did the test
Venus has the smallest orbital eccentricity of any of the planets. What is the eccentricity of Venus?(1 point)
Responses
1.0300
0.8040
0.0068
0.0000
The eccentricity of Venus is = 0.0068. That is option C.
What is orbital eccentricity?The orbital eccentricity is defined as the measurement that is used to show how an orbit deviates from the shape of a circle.
The Venus is one of the planets of the universe that is the second closest to the sun.
The Venus is one of the planets that has a small orbital eccentricity being 0.006772 which is approximately 0.0068. This means that it is closest to being circular in shape.
The planets with the largest orbital eccentricity is the planet Mercury with orbital eccentricity of 0.2056.
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The road is 6 kilometers long. How
long is the road in meters?
Answer:
6000 meters
Explanation:
Because 6kilometers is 6000 maters
During which of the following intervals is no unbalanced force acting on the car?
The friction force that is exerted on the car's rotating wheels causes an imbalanced force to be applied to the vehicle, which then accelerates. The center of the circle the car is turning is the target of both the unbalanced force and the acceleration. Your body, however, continues to move and is in motion.
An object's motion may vary if an imbalanced force is applied to it. The small car will alter speed, direction, or even halt if a heavier, faster toy car moves into its path or along its side. The small toy car is being subjected to a stronger force, which is why its motion has changed.
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Cassie walked to her friend's house with an average speed of 1.40 m/s. The distance between
the houses is 205 m. How long did the trip take her?
Answer:
146.4 s
Explanation:
Distance / rate = time
205 m / 1.4 m/s = 146.4 s
a car sitting at a red light begins to accelerate at 2.0 m/s 2 m/s2 when the light turns green. it continues with this acceleration until it reaches a speed of 20 m/sm/s . it then travels at this speed for another few minutes. how far does the car travel in the first 34 ss after the light changes to green?
The car travels a distance of 820m in the first 34s after the light changes to green.
Acceleration, a = 2ms⁻²
Initial velocity, u = 0 ms⁻¹ (Since the car start from rest)
Final velocity, v = 20 ms⁻¹
From first equation of motion,
v - u = at
20 - 0 = 2 × t
20 = 2t
t = 10s
From second equation of motion,
S = ut + ¹/₂ at²
Distance travelled during 10s:
S₁ = 0 × 10 + ¹/₂ × (10)²
S₁ = 100m
Distance travelled for the remaining 36s:
S₂ = v × t
S₂ = 20 × 36
S₂ = 720m
Total distance travelled:
S = S₁ + S₂
S = 100 + 720
S = 820m
Therefore, the car travels a distance of 820m in the first 34s after the light changes to green.
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PLEASE HELP ASAP!!! A hiker walks 12cm North in 2 hours what is his velocity?
Answer:
[tex]\boldsymbol {\boxed{v = 12 \ \dfrac{\text{ km}}{\text{hr}} }}[/tex]
Explanation:
Data:
t = 2 hr
S = 12 km
Find:
[tex]v \ - \ ?[/tex]
-----------------------------------
Solution:
[tex]\boldsymbol {\boxed{v = \dfrac{S}{t} }}[/tex]
Calculations:
[tex]\boldsymbol v =[/tex] 12 km / 2 hr = 6 km/hr.
Answer: [tex]v =[/tex] 6 km/hr.
Abby runs at a constant speed and travels 10 meters in 4 seconds. if abby runs for 8 seconds at this constant speed, how far will he travel?
If Abby runs for 8 seconds at this constant speed, Abby will travel 20 meters at this constant speed.
CalculationThe Speed = 10/4 = 2.5 m/s
Distance = speed x time d=st
In 8 seconds, d=2.5 x 8 = 20 meters
What is the definition of movement speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is traveling along a path. In other words, velocity is regarded as a vector, whereas speed is a scalar value.
Use the speed formula, s = d/t, which states that speed is equal to distance divided by time, to solve for speed or rate.
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this is a multi-part question. once an answer is submitted, you will be unable to return to this part. a piece of plywood in which several holes are being drilled successively has been secured to workbench by means of two nails. knowing that the drill exerts a 29-n·m couple on the piece of plywood, determine the magnitude of the resulting forces applied to the nails for the given locations.
The magnitude of the resulting forces applied to the nails if they are located at A and B is 64.44 N, at B and C is 120.83 N and at A and C is 56.86 N.
We know that,
C = F d
where,
C = Couple
F = Magnitude of resulting forces
d = Distance between two points
Given that,
C = 29 N m
[tex]d_{AB}[/tex] = 450 mm = 0.45 m
[tex]d_{BC}[/tex] = 240 mm = 0.24 m
F = C / d
The magnitude of the resulting forces applied to the nails if they are located at A and B is
F = 29 / [tex]d_{AB}[/tex] = 29 / 0.45
F = 64.44 N
The magnitude of the resulting forces applied to the nails if they are located at B and C is
F = 29 / [tex]d_{BC}[/tex] = 29 / 0.24
F = 120.83 N
The magnitude of the resulting forces applied to the nails if they are located at A and C is
F = 29 / [tex]d_{AC}[/tex]
[tex]d_{BC}[/tex] = √ ( [tex]d_{AB}[/tex] )² + ( [tex]d_{BC}[/tex] )²
[tex]d_{BC}[/tex] = √ ( 0.45² + 0.24² )
[tex]d_{BC}[/tex] = 0.51 m
F = 29 / 0.51
F = 56.86 N
A Couple is two parallel forces of equal magnitude acting in opposite direction.
Therefore, the magnitude of the resulting forces applied to the nails if they are located at
A and B is 64.44 NB and C is 120.83 N A and C is 56.86 NTo know more about couples
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