Answer:
The function is missing in the question. The function of the transverse pulse in the wire is given by [tex]$y=\frac{6}{x^2 +3}$[/tex]
Explanation:
A transverse wave can be defined as the wave whose direction of displacement is always perpendicular to the direction of propagation. For example, surface wave at water bodies. While a pulse can be defined as a sudden change in a constant quantity such as a pulse of the radiation or current.
Let the wire of infinite length in both the directions and also the magnitude of deflection of wire be in the same shape except the point of maximum deflection to move along the wire.
Thus the equation of the pulse moving the in the positive x-direction moving at the speed of 2.10 m/s is
[tex]$y=\frac{6}{(x-2.10)^2 +3}$[/tex].
a force of 35N is exerted over a cylinder with an area of 5m^2. What pressure,in pascals, will be transmitted in the hydraulic system?
Answer:
The answer is 7 PaExplanation:
The pressure transmitted in the hydraulic system can be found by using the formula
[tex]p = \frac{f}{a} \\ [/tex]
f is the force
a is the area
From the question we have
[tex]p = \frac{35}{5} \\ [/tex]
We have the final answer as
7 PaHope this helps you
I NEED HELP PLZ I HAVE NO CLUE WHAT THE ANSWER IS AND I REALLY NEED TO GET AN A ON THIS TEST!
Answer:
I'm pretty sure its c
Hope you get a good grade-
branches of sicence
Answer: Natural science can be divided into two main branches
Explanation:
life science and physical science. Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, astronomy and Earth science.
Please help!!! I will give brainliest,
Answer:
C. a liter of salt water.
Explanation:
Defination of Solution =>
a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).
Which of the following are electromagnetic waves?a. Water wavesb. Radio wavesc. Sound wavesd. Seismic waves
Answer:
Radio waves
Explanation:
Radio wavs are electromagnetic waves.
Hope this helped!
9. In the graph below, what is the force being exerted on
the 16-kg cart?
A. 4N
C. 16N
B. 8N
D. 32 N
Answer:
D
Explanation:
Select the correct answer.
The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's motion?
A. It's not moving.
B.It's moving at a constant speed.
C.It's moving at a constant velocity
D.It's speeding up.
Answer:
It isn't moving
Explanation:
A motorcycle moving at a constant velocity suddenly accelerates at a rate of 4.0 m/s^2 to a speed of 35 m/s in 5.0 s. What was the initial speed of the motorcycle?
Answer:
15m/sExplanation:
Step one:
given data
acceleration a=4m/s^2
final velocity v=35m/s
time t=5 seconds
Step two:
Required
initial velocity u=?
Applying the first equation of motion
v=u+at
substituting we have
35=u+4*5
35=u+20
u=35-20
u=15 m/s
The initial velocity is 15m/s
A student throws a 110 g snowball at 6.5 m/s at the side of the schoolhouse, where it hits and sticks.
What is the magnitude of the average force on the wall if the duration of the collision is 0.19 s ?
Answer:
3.6NExplanation:
Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time.
the expression is Ft=mv
where F= force
m= mass
t= time
v= velocity
Step one:
given data
mass m= 110g= 0.11kg
velocity v= 6.5m/s
time t= 0.19seconds
Step two:
we also know that the force on impulse is given as
Ft=mv
F=0.11*6.5/0.19
F=0.715/0.19
F=3.76N
The magnitude of the average force on the wall if the duration of the collision is 0.19 is 14N
1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the centripetal force acting on the car? *
A- 1 N
B- 100 N
C- 1000 N
D- 10000 N
Answer:
its a
Explanation:
Hypothesis: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will ________ because the toy car ____
Answer:
If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.
Explanation:
I hope this helped
Hypothesis: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car gains more potential energy at the higher starting point.
When a toy car moves along a sloped racetrack, it converts its potential energy (due to its height above the ground) into kinetic energy (energy of motion). The higher the starting height of the racetrack, the more potential energy the toy car possesses initially.
As the toy car moves down the sloped track, it will accelerate due to the force of gravity. The potential energy is converted into kinetic energy, and the car's speed increases. According to the law of conservation of energy, the total mechanical energy (sum of potential and kinetic energy) remains constant as long as no external forces, such as friction, act on the car.
Therefore, if the starting height of the racetrack is increased, the toy car will have more potential energy to start with. As it moves down the track, it will convert this increased potential energy into kinetic energy, resulting in a higher speed compared to when it starts from a lower height.
To know more about speed here
https://brainly.com/question/17661499
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A bicycle mechanic is checking a road bike's chain. He applies force F = 48 N to a pedal at the angle shown in (Figure 1) while keeping the wheel from rotating. The pedal is 17 cm from the center of the crank; the gear has a diameter of 16 cm.
Answer:
T = 102.3 ≈ 100
Explanation:
r(pedal) = 17 cm = 0.017 m
r(gear) = 16 cm / 2 = 8 cm = 0.008 m
θ = 180°-110° = 70°
F = 48 N
T = ?
τ₁ = r(pedal)*F*cosθ = (0.017 m)(48 N)cos(70°) = 0.28 N*m (*negative because it is applied clockwise)
τ₂ = -τ₁ = -(-0.28 N*m) = 0.28 N*m
τ₂ = r(gear)*T*cosθ
T = τ₂÷(r(gear)*cosθ) = 0.28 N*m ÷ (0.008 m * cos(70°))
T = 102.3 ≈ 100 ( 2 sig figs)
in the woman's mouth if
she is drinking through a straw extending 0.085 m above the surface of the drink? Note:
Assume the drink has a density of 1015 kg/m^3. ????
Answer:
hi mate,
interesting question, first of all the pressure is determined by using the following formula:
Pg = p * G * h
where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:
p = 1015 kg/m3
G = 9.8m/s2
h = 0.085 m
insert these values into the equation above:
Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal
hope it helps, :-)
please mark me as brainliest
A magnet of mass 0.20 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, causing the copper to warm up. The speed of the magnet as it emerges from the tube is 1.50 m/s. How much heat energy is dissipated to the environment?
Answer:
The energy lost to the environment is 0.461 J
Explanation:
Given;
mass of the magnet, m = 0.2 kg
height of fall, h = 35 cm = 0.35 m
initial speed of the magnet, u = 0
final speed of the magnet, v = 1.5 m/s
Initial energy of the magnet is given by;
E₁ = P.E₁ + K.E₁
E₁ = mgh₁ + ¹/₂mu²
E₁ = (0.2 x 9.8 x 0.35) + ¹/₂(0.2)(0)²
E₁ = 0.686 J
Final energy of the magnet as it emerges from the tube is given by;
E₂ = mgh₂ + ¹/₂mv²
E₂ = (0.2 x 9.8 x 0) + ¹/₂(0.2)(1.5)²
E₂ = 0 + 0.225 J
The energy lost to the environment is given by;
E = E₂ - E₁
E = 0.225 J - 0.686 J
E = -0.461 J (negative sign indicates lost energy to the environment)
Therefore, the energy lost to the environment is 0.461 J
A parallel-plate capacitor with circular plates of radius 40 mm is being discharged by a current of 6.0 A. At what radius (a) inside and (b) outside the capacitor gap is the magnitude of the induced magnetic field equal to 75% of its maximum value?(c) What is that maximum value?
Answer:
A) r = 0.03 m
B) r = 0.0533 m
C) B_max = 0.00003 T
Explanation:
Formula for magnetic field inside the capacitor when it is parallel to the length element is;
B_in = (μ_o•I•r/(2πR²)
Formula for maximum magnetic field is;
B_max = (μ_o•I/(2πR)
Formula for magnetic field outside the capacitor is; B_out = (μ_o•I/(2πr)
A) Magnetic field inside the capacitor is gotten from our first equation above;
B_in = (μ_o•I•r/R²)
Since we want to find the radius at which the magnitude of the induced magnetic field equal to 75% or 0.75 of its maximum value.
Thus;
B_in = 0.75B_max
(μ_o•I•r/(2πR²) = 0.75((μ_o•I/(2πR))
μ_o•I and 2πR will cancel out to give;
r/R = 0.75
r = 0.75R
We are given R = 40 mm = 0.04 m
r = 0.75 × 0.04
r = 0.03 m
B) magnetic field outside the capacitor is; B_out = (μ_o•I/(2πr)
Thus for the magnitude of the induced magnetic field equal to 75% or 0.75 of its maximum value:
B_out = 0.75B_max
(μ_o•I/(2πr) = 0.75((μ_o•I/(2πR))
μ_o•I and 2π will cancel out to give;
1/r = 0.75/R
r = R/0.75
r = 0.04/0.75
r = 0.0533 m
C) B_max = μ_o•I/(2πR)
μ_o is a constant known as vacuum of permeability with a value of 4π × 10^(-7) T.m/A
Thus;
B_max = (4π × 10^(-7) × 6)/(2π × 0.04)
B_max = 0.00003 T
A 5 kg projectile is shot with an initial velocity of 8 m/s from a height of 10 meters. If the acceleration due to gravity is 9.8 m/s^2, what is the total initial energy of the projectile?
Answer: 650 joules
Explanation:
Total energy (kinetic + potential)
1/2×mv^ + mgh
1/2×5×8×8+ 5×9.8×10
1/2×320 + 5×98
320/2 + 480
320/2 + 980/2 (multipling to make the denominator equal)
1300/2 = 650 joules
Hope it helps, if you don't understand try doing it yourself with the formula.
:)
Ruby has an index of refraction of 1.7. Calculate the maximum angle with respect to the normal at which a light ray escapes a ruby if the ruby is in air.
a. 17°
b. 36°
c. 53°
d. 90°
e. Light escapes at all incident angles.
Answer:
Umm sorry just came for the points.
An object has a mass of 15 kg and is accelerating to the right at 16.3 m/s2. The free-body diagram shows the horizontal forces acting on the object. A free body diagram with 2 forces. The first vector is pointing right, labeled F Subscript a Baseline 250 N. The second vector is shorter pointing left, labeled F Subscript f Baseline. What is the frictional force, Ff, acting on the object?
Answer:
A. -5.5 N
Explanation:
I can confirm that the answer is A.
A 8.45μC particle with a mass of 6.15 x 10^-5 kg moves perpendicular to a 0.493-T magnetic field in a circular path of radius 34.1 m. How much time will it take for the particle to complete one orbit?
a. 92.7 s
b. 0.0927 s
c. 9.27 s
d. 927 s
This question is incomplete, the complete question is;
A 8.45μC particle with a mass of 6.15 x 10⁻⁵ kg moves perpendicular to a 0.493-T magnetic field in a circular path of radius 34.1 m.
How much time will it take for the particle to complete one orbit?
a. 92.7 s
b. 0.0927 s
c. 9.27 s
d. 927 s
Answer:
it will take 92.7 seconds for the particle to complete one orbit.
Option a) 92.7 s is the correct option
Explanation:
Given that;
mass m = 6.15 x 10⁻⁵ kg
q = 8.45μC = 8.45 × 10⁻⁶ C
B = 0.493
we know that
Time period T = 2πr / V
where r = mv/qB
so T = 2πm/qB
we substitute
T = (2 × 3.14 × 6.15 x 10⁻⁵) / ( 8.45 × 10⁻⁶ × 0.493)
T = 0.0003862 / 0.000004165
T = 92.7 sec
Therefore it will take 92.7 seconds for the particle to complete one orbit.
Option a) 92.7 s is the correct option
a pot of water at 20.0ºC is warmed to 100º when 40000cal is added. what is the mass of the water?
Answer:
500 g
Explanation:
m = Mass of water
c = Specific heat of water = [tex]1\ \text{cal/g}^{\circ}\text{C}[/tex]
[tex]\Delta T[/tex] = Temperature difference = [tex]100-20=80^{\circ}\text{C}[/tex]
Q = Heat added = 40000 cal
Heat is given by
[tex]Q=mc\Delta T\\\Rightarrow m=\dfrac{Q}{c\Delta T}\\\Rightarrow m=\dfrac{40000}{1\times 80}\\\Rightarrow m=500\ \text{g}[/tex]
The mass of water is 500 g.
if the motor m rotates in the direction shown by the arrow what is going on
The question is incomplete,I will complete the question and provide the answer.
Due to the nature of the question,I will sketch an answer/solution to the question and submit it as an attachment.
So you will be having two attachments,
1) The question
2) The solution
From the options given in the first attachment with is the question,the correct answer is option C.
1 AND 2 ARE GOING UP.
Proper explanation using sketch and arrows is given in the second attachment which shows the solution to the question.
What is Energy in physics?
Answer:
Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.
Explanation:
Hope this helps!
Please help, I'm really struggling here, I can't do science :(
The mass of Jupiter is about 320 times the mass of Earth. However, Jupiter’s gravity affects Earth very little because_____________. a Earth is so far from Jupiter. b Earth is so small. c Jupiter is made of gas. d Jupiter is nearer to the sun than Earth is.
Answer:no sure sorry
Explanation:
A pressure antinode in a sound wave is a region of high pressure, while a pressure node is a region of low pressure.
True
False
5. Peter had an inflated balloon that he released and flies across the room. The balloon slows down and then stops on top of the dinning table, As the balloon slows downs the force becomes
A.balanced
B.frictional
C.restricted
D.unbalanced
A 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V and negligible internal resistance. At the instant when the resistor is dissipating electrical energy at a rate of 300 W, how much energy has been stored in the capacitor?
Answer:
The energy stored is [tex]E_s = 0.0064 \ J[/tex]
Explanation:
From the question we are told that
The capacitance is [tex]C = 8 \ \mu F = 8*10^{-6} \ F[/tex]
The resistance is R = 3.00-Ω
The emf is [tex]E_t = 70.0 V[/tex]
The power is P = 300 W
Generally the total emf is mathematically represented as
[tex]E_t = E_c + E_r[/tex]
Here [tex]E_c[/tex] is the emf across that capacitor which is mathematically represented as
[tex]E_c = \frac{q}{C}[/tex]
and [tex]E_r[/tex] is the emf across the resistor which is mathematically represented as
[tex]E_r = \sqrt{P R}[/tex]
So
[tex]E_t = \sqrt{PR} + \frac{q}{C}[/tex]
=> [tex]q = C[E_t - \sqrt{PR} ][/tex]
Generally the energy stored in a capacitor is mathematically represented as
[tex]E_s = \frac{q^2}{2C}[/tex]
=> [tex]E_s = \frac{[C [ E_t - \sqrt{PR} ]]^2}{2C}[/tex]
=> [tex]E_s = \frac{[8.0*10^{-6} [ 70 - \sqrt{300 * 3}}{2 *(8.0*10^{-6})}[/tex]
=> [tex]E_s = 0.0064 \ J[/tex]
The energy that has been stored in the capacitor will be 0.0064 J. The stored energy is utilized in the different electrical works.
What is a capacitor?A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.
An electric insulator or vacuum, such as glass, paper, air, or a semi-conductor termed a dielectric, can be used as the non-conductive zone.
The given data in the problem is;
C is the capacitance = 8.00-μF = 8.00 ×10 ⁻⁶
R is the resistance = 3.00-Ω
E is the emf = 70.0 V
P is the power = 300 W
The total emf is the sum of the emf due to the capacitor and emf due to the resistor;
[tex]\rm E_t = E_C + E_R[/tex]
The emf generated by the capacitor is;
[tex]\rm E_C = \frac{q}{C}[/tex]
[tex]\RM E_R = \sqrt{PR}[/tex]
[tex]\rm E_t = \frac{q}{C} + \sqrt{PR} \\\\ \rm q= C [ E_t-\sqrt{PR} ]\\\\[/tex]
Generally, the energy stored in the capacitor is;
[tex]\rm E_S= \frac{q^2}{2C} \\\\ \rm E_S= \frac{\rm C [ E_t-\sqrt{PR} ]\\\\^2}{2C} \\\\ \rm E_S= \frac{\rm 8.0 \times 10^{-6}[ 70-\sqrt{300\times 3} ]\\\\^2}{2 \times (8.0 \times 10^{-6}} \\\\ \rm E_S= 0.0064 \ J[/tex]
Hence the energy that has been stored in the capacitor will be 0.0064 J.
To learn more about the capacitor refer to the link;
https://brainly.com/question/14048432
A sample with a path length of 1 cm absorbs 99.0% of the incident light at a wavelength of 274 nm, measured with respect to an appropriate solvent blank. Tyrosine is known to be the only chromophore present in the sample that has significant absorption at 274 nm. Calculate the molar concentration of tyrosine in the sample.
Answer:
17. NADH has a molar extinction coefficient of 6200 M2 cm at 340 nm. Calculate the molar concentration of NADH required to obtain an absorbance of 0.1 at 340 nm in a 1-cm path length cuvette. 18. A sample with a path length of 1 cm absorbs 99.0% of the incident light at a wavelength of 274 nm, measured with respect to an appropriate solvent blank. Tyrosine is known to be the only chromophore present in the sample that has significant absorption at 274 nm. Calculate the molar concentration of tyrosine in the sample.
Explanation:
1
Betty is sitting on of her surfboard out in the ocean. She is waiting for the
perfect wave to come along so she can ride it in to shore. As she waits, she
notices that the waves roll by in patterns, or sets. As the top of each wave
passes by Betty, it pushes her up. Which part of the wave does this? *
Explanation:
yooooooooo
My favorite Naruto couple fighting together!!!! Remember this?! And remember.........this?!
I cried so hard when he died.
Answer:
ok tbh i didnt cry when neji died but now when i think about it i just cry thinking about how himawari could have met her uncle
Explanation:
If the weight of a person is 500 newton what is his mass on the earth ?
Answer:
The person is on the Moon having a weight of 500 N. The acceleration of gravity on the Moon is approximately 1.6 m/s2. What is your his, which includes his space suit?
f= Force (of gravity)=500N
g=acceleration of gravity=1.6m/s^2
m=mass=312kg
m=f/a= 500N/1.6 m/s^2 = 500 (kg-m/1.6m/s^2) = 500/1.6kg = 312kg
his mass is 312kg