The measurements are accurate but not precise.
Measurement is the basis for all scientific and technological developments. The measurement of any quantity is not perfect and there are always some uncertainties that cause errors in the measurements. While measuring anything we define the measurements in terms of precision and accuracy.
The accuracy of a measurement is a measure of how close the calculated value is to the true value. While precision tells to what resolution or limit the quantity is measured. For example, suppose the true value of a length is 10.578 cm. In the first case, the value comes out to be 10.4 cm. In the second case, the value comes out to be 10.378 cm. In the above example, the first value is accurate because it is close to the true value but the second value is precise because it contains more digits after the decimal.
Similarly, in the above case, a block with a known value of the volume of 15 cm^3 and the measurements are 14.6, 14.7, 14.7, 14.6 cm^3. As the values are close to the true value but they contain less number of digits after decimals, these values are accurate but not precise.
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What is the length of the x-component of the vector shown below?
34°
8
OA. 4.5
OB. 6.6
OC. 5.4
OD. 8
Answer: B
Explanation: I am 99% sure that is correct I remember doing something very simular
A racing car reaches a speed of 42 m/s. It then begins to decelerate, using its parachute and braking system, and comes to rest 5.5 s later. Find the rate of deceleration.
The rate of deceleration of a racing car that reaches a speed of 42m/s is 7.64m/s.
How to calculate deceleration?Deceleration is the amount by which a speed or velocity decreases.
The rate of deceleration can be calculated using the following formula:
d = (v - u)/t
Where;
d = decelerationv = final velocityu = initial velocityt = timeAccording to this question, a racing car reaches a speed of 42m/s. It then begins to decelerate, using its parachute and braking system, and comes to rest 5.5s later. The deceleration can be calculated as follows:
d = (42 - 0)/5.5
d = 42/5.5
d = 7.64m/s
Therefore, the rate of deceleration of a racing car that reaches a speed of 42 m/s is 7.64m/s.
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A shuttle bus slows to a stop with an average acceleration of -1.8 m/s^2. How long does it take the bus to slow down from 9.0 m/s to 0.0 m/s?
Time taken to slow down the speed will be 5 seconds.
Average acceleration of the bus, a = 1.8 m/s²
Initial velocity of the bus, u = 9.0 m/s
Final velocity of the bus, v = 0 m/s
According to the First Equation of the motion which relates the acceleration, velocity and time we can say that
v = u + at
v - u = at
0 - 9 = (-1.8) * t
9 = 1.8 * t
t = [tex]\frac{9}{1.8}[/tex]
t = 5 s
Therefore 5 seconds will be required by the bus to slow down its speed from 9.0 m/s to 0.0 m/s
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consider two protons initially at rest separated by a distance . the two protons are then moved towards each other until they are again at rest a distance apart.
Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.16 MeV.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.
In classical physics, an object of mass m moving at a speed of v has kinetic energy.
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1. With what force will a car hir a free if the car has a mass of 3,000 kg and accelerating at a rate of 2 m/st?
The force the car will use to hit the tree, given it has a mass of 3000 Kg and accelerating at 2 m/s² is 6000 N
How to determine the forceFrom the question given above, the filling data were obtained:
Mass (m) = 3000 KgAcceleration (a) = 2 m/s²Force (f) = ?Force is related to acceleration according to the following formula:
Force = mass × acceleration
Thus, we can obtain the force as illustrated below:
Force = mass × acceleration
Force = 3000 × 2
Force = 6000 N
From the calculation made above, we can conclude that the force the car will use to hit the tree is 6000 N
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What is the position of the mailbox? (I really don’t understand this)
Answer:
The graph is a velocity-time graph, showing velocity as an f(t), (function of time).
The graph depicts the following:
For 6 seconds, the mailman travels at the constant rate of 3m/s. At second 6, he abruptly stops (when he stops for the mailbox which he overshot) which is represented by the dotted vertical line. He then stays at the constant rate of 0 m/s (stationary) for 2 seconds before he goes into reverse for 2 seconds at the rate of 2m/s before arriving back at the mailbox.
Some items to note:
In a real-world situation, the abrupt stop would be unrealistic and therefore may be a slope for about 1 second.
A dotted line represents a break in the graph, for our situation, it means the velocity has dropped.
A negative velocity, like in his graph, is just going in reverse.
To find the position of the mailbox:
Change the graph to a position-time graph which shows position as an f(t). Using this new graph, you can find the position of the mailbox using time at the 10th second.
Just a quick note, changing between types of graphs is an essential part of physics and you should be able to do it with no reference. It is in your best interest to learn this to be able to apply it in the future.
Hope that helps
Conversations with astronauts on the lunar surface were characterized by a kind of echo in which the earthbound person's voice was so loud in the astronaut's space helmet that it was picked up by the astronaut's microphone and transmitted back to Earth. It is reasonable to assume that the echo time equals the time necessary for the radio wave to travel from the Earth to the Moon and back (that is, neglecting any time delays in the electronic equipment). Calculate the distance from Earth to the Moon (in km) given that the echo time was 2.52 s and that radio waves travel at the speed of light (3.00 ✕ 10^8 m/s).
The correct answer is 378000 km.
The speed of light is the rate at which light waves move through distinct substances. In instance, it has now been established that the speed of light in a vacuum is 299,792,458 metres per second.
Using the equation
distance = speed × time,
the total distance travelled is calculated.
Consequently, the overall distance travelled is
Distance = ( 3.00 × 10^8 m/s ) ( 2.52 )
= 756000000 m
The total distance travelled divided by two determines the distance between the Earth and the Moon.
Distance between earth to moon = 756000000/2
= 378000000 meters
= 378000 km.
Approximately 384 thousand kilometres separate the Earth and the Moon.
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The force of gravity between two bodies is 6.68x10³ N.
The force of gravity between two bodies is 6.673 x 10-11 N m²/kg²
Greater gravitational forces will be used to attract heavier things since the force of gravity is directly related to the mass of both interacting components. Therefore, the gravitational pull between two objects grows as their respective masses do as well. The gravity force between two objects is equal to their respective masses multiplied by two. If one of the items triples in mass, the gravitational pull between them will also triple. The gravitational force between two objects is multiplied by two when their masses are each doubled, and so on. More distance will lead to decreased gravitational forces since the force of gravity is inversely related to the square of the difference between two interacting objects. Therefore, the gravitational pull between two things weakens as they go farther apart.
So any two items will be attracted to one another by a gravitational force of 6.673 x 10-11 N m² / kg²
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Use the position-time graph below to answer the following questions.
What is the displacement of the object?
What is the distance travelled by the object?
Sketch the velocity-time graph that corresponds to this data.
Answer:49
Explanation:47484=4848489
Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called ______that line the walls of your lungs.
Popliteal
Arterial
Alveoli
Capillaries
Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called alveoli that line the walls of your lungs.
Lungs :Your lungs contain tiny, balloon-shaped air sacs called alveoli. Moving oxygen and carbon dioxide (CO2) molecules into and out of your bloodstream is what the alveoli are there for. Alveoli are a crucial component of your respiratory system, which includes the body parts that aid in breathing.
What lines walls of alveoli?An alveolus is made up of an extracellular matrix encircled by capillaries, a layer of simple squamous epithelium (extremely thin, flattened cells), and an epithelial layer. The alveolar membrane, also known as the respiratory membrane, which permits the exchange of gases, includes the epithelial lining.
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THE FIRST PERSON TO GIVE ANSWERS GETS BRAINLIEST
PLEASE HELP URGENT
Answer:
momentum = mass x velocity
1×50=50_
mu=mv
mu+mv=(m1+m2)v
50×1+20×0.5=v(1+0.5)
v=60÷1.5
v=40
Where in the hispanic world can you find a place that has coastlines on the same side of the country that are on both the pacific ocean and the caribbean sea?.
Answer: Panama
Explanation:
Helppp Mass in motion lab report
The purpose of the motion lab is to collect experimental data on two constant-speed cars with different constant speeds and a dynamic car showing acceleration.
The laboratory report must document the experiments and raw data included in the report, provide sufficient information to reproduce or extend the data analyze the data, and draw conclusions. It has three main functions presenting and creating. Recommendations based on experimental work
In this lab, we were able to study projectile motion by determining the ball's initial velocity and finally predicting the projectile's range. In this projectile motion lab, we used the equations of motion for a projectile to predict distance. It combines the examination of a person's anatomy with the measurement of function during activity.
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you leave the airport in college station and fly 26.0 km in a direction 34.0∘ south of east. you then fly 46.0 km due north. part a how far must you then fly to reach a private landing strip that is 32.0 km due west of the college station airport? express your answer with the appropriate units.
I must fly about 62.56 km in the Southwest direction to reach a private landing strip that is 32.0 km due west of the college station airport.
This can be understood through concept of Vectors. Vectors are defined as entity which has both direction and magnitude.
According to the question, 27 km in a direction 34.0° south of east hence angle is -34°.
Along x axis = 27cos (-34) ° and along y axis = 27sin (-34) °
Along x axis ≈ 22.4 km and along y axis ≈ -15.1 km.
Now, fly 46 km due north.
Along y axis=46, along x axis = 0
Next, along x axis ≈ 22.4 km, Along y axis ≈ -15.1 + 46 ≈ 30.9 km
Hence (22.4, 30.9)
Final Position is 32 km due west is that is ( -32, 0)
Distance between (22.4, 30.9) and ( -32, 0)
√ {(22.4 - (-32)) ² + (30.9 - 0) ²}
≈ 62.56 km Direction Southwest
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Two gases are contained in gas bulbs connected by a valve. Gas a is present in a 1 liter bulb at a pressure of 818 torr. Gas b exerts a pressure of 328 torr in a 1 liter bulb. The valve is opened and the two gases come to equilibrium. What is the partial pressure of gas a expressed after equilibrium?.
The partial pressure of gas expressed after equilibrium is 409 torr.
Which gas is used for bulbs?Incandescent light bulbs are usually filled with argon, which is a common gas. It prolongs bulb life by keeping the tungsten filaments from decaying too quickly. Lighting also makes use of other gases like helium, neon, nitrogen, and krypton.Incandescent lights are what gas lamps are. They generate heat by burning fuel like propane, white gas, or kerosene, and the heat drives light production from the mantles. The mantles, which are made of a ceramic mesh, contain the lantern's flame.The first kind of gas employed, argon, is a gas that is typically found in incandescent light bulbs. Nitrogen may occasionally be added to argon gas. Halogen or xenon gas can be found in some light bulbs. Some light bulbs also include krypton gas.What is the partial pressure of gas expressed after equilibrium:
1. Write out the units given.
V1= 1 L
Ptot= 818 torr
PPB= 328 torr
V2= 1L
2. Remember= PaVa= PtotVtot
3. Add together volumes for total volumes.
1 L + 1 L= 2 liters
4. Plug in values and solve for PP of gas A.
PPA= Ptot x VA/Vtot
818 torr x 1/2 L= 409 torr
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are their final velocities necessarily equal? explain. yes, the final velocity is the instantaneous velocity at the moment a sprinter crosses the fini
The answer is statement 2 which states that only the average velocity must be same but not necessarily the instantaneous velocity.
The given situation is that two sprinters start the race on a straight track, in which they cross the finish line at the same time. So, they covered the same amount of distance at the same amount of time. This means that both their average velocity is equal, since it is independent of instantaneous velocity.One sprinter might start the race faster and finish at a slower speed whereas the other sprinter might start the race slower and finish the race at a faster speed. In this situation the final velocities are not equal.Instantaneous velocity is the velocity of an object at a specific time whereas average velocity is the average velocity of an object throughout the time.
The given question is incomplete. The complete question is:
Two sprinters start a race along a straight track at the same time and cross the finish line at the same time.
Are their final velocities necessarily equal? Explain.
1 ) Yes, the final velocity is the instantaneous velocity at the moment a sprinter crosses the finish line, which will be the same between two sprinters. The instantaneous velocities for the entire race must be the same.
2) No, the final velocity is just the instantaneous velocity at the moment a sprinter crosses the finish line, which can vary between two sprinters. Only the average velocity for the entire race must be the same.
Therefore, the correct answer is statement 2.
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a string or rope will break apart if it is placed under too much tensile stress. thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. one type of steel has density 7710 kg/m3 and will break if the tensile stress exceeds 7.0×108n/m2. you want to make a guitar string from a mass of 4.2 g of this type of steel. in use, the guitar string must be able to withstand a tension of 900 n without breaking. your job is the following.
The maximum length the string can have is 13.02 meter.
(a) Determine the maximum length the string can have
Answer:
As we know that density(p)= mass(m)/volume(V)
Solve for volume(V)= mass/density
If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg
And if density is in kg/m^3
Then volume will be V= 0.0037/7730 =>
4.79^10-7m^3
Now we know that stress = Force/Area
For Area = force/stress => 900/7*10^8=> 2795.95m^2
For length= volume/Area => 4.79^10-7/2795.95
Length= 13.02 m
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problem 11.043 - uniformly accelerated motion of two particles - dependent multi-part problem - assign all parts skip to question note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. two automobiles a and b are approaching each other in adjacent highway lanes. at t
The vehicles pass each other after 20.7 seconds
We know that,
s = ut + 1 / 2 a[tex]t^{2}[/tex]
s = Displacement
u = Initial velocity
t = Time taken
a = Acceleration
Given that,
s = 3200 ft = 0.606 mi
[tex]u_{a}[/tex] = 68 mi / [tex]hr^{2}[/tex]
[tex]t_{a}[/tex] = 40 s = 40 / 3600 hr
[tex]u_{b}[/tex] = 37 mi / [tex]hr^{2}[/tex]
[tex]t_{b}[/tex] = 42 s = 42 / 3600 hr
s = [tex]u_{a}[/tex][tex]t_{a}[/tex] + 1 / 2 [tex]a_{a}[/tex][tex]t_{a} ^{2}[/tex]
0.606 = 68 ( 40 / 3600 ) + [tex]a_{a}[/tex] 0.5 ( 40 / 3600 [tex])^{2}[/tex]
[tex]a_{a}[/tex] = - 2422 mi / [tex]hr^{2}[/tex]
s = [tex]u_{b}[/tex][tex]t_{b}[/tex] + 1 / 2 [tex]a_{b}[/tex][tex]t_{b} ^{2}[/tex]
0.606 = 37 ( 42 / 3600 ) + [tex]a_{b}[/tex] 0.5 ( 42 / 3600 [tex])^{2}[/tex]
[tex]a_{b}[/tex] = 2561.63 mi / [tex]hr^{2}[/tex]
[tex]s_{a}[/tex] + [tex]s_{b}[/tex] = 0.606
68 t + 0.5 ( - 2422 ) [tex]t^{2}[/tex] + 37 t + 0.5 ( 2561.63 ) [tex]t^{2}[/tex] = 0.606
105 t + 1280.67 [tex]t^{2}[/tex] - 1211.4 [tex]t^{2}[/tex] - 0.606 = 0
t = 5.75 * [tex]10^{-3}[/tex] hr = 20.7 sec
The equations of motion are basically used to describe the motion of an object using position, velocity, acceleration and time.
Therefore, the vehicles pass each other after 20.7 seconds
The given question is incomplete. The compete question is :
Two automobiles A and B are approaching each other in adjacent highway lanes. At t- 0, A and B are 3200 ft apart, their speeds are VA 68 mi/h and VB 37 mi/h, and they are at points P and Q, respectively. A passes point Q 40 s after B was there and B passes point P42s after A was there. 3200 ft Problem 11.043.b - Uniformly accelerated motion of two particles Determine when the vehicles pass each other
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Does a charge on an atom change the number of valence electrons?
It is thought that oxidation/reduction reactions take place in an atom's valence shell. Therefore, the existence or absence of additional valence electrons is related to the formal charge.
Any of the fundamentally negative charged atom-external particles called valence electrons participate in the synthesis of chemical bonds. The atomic number (Z) of oxygen is 8. The oxygen atom's nucleus has 8 protons (this is what makes it an oxygen atom).
Therefore, the neutral atom should have 8 electrons, but 2 of them are thought to be in the inner core. We typically represent oxygen in a molecule as R- OR, with 2 lone pairs on the oxygen. While the O center is thought to have half of the 2 electrons that make up the C-O bond or 1 electron, these 2 lone pairs are thought to have a charge that is totally connected with the O atom.
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An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength, but would differ based on what physical property of light?.
An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength but would differ due to the amplitude property of light.
It is the amplitude of light which makes one sample brighter than other.
The amplitude plays an important part in differentiating the same colors of the same wavelength. It tells us about the brightness or intensity of a certain light wave as compared to others of the same wavelength. So, whenever two same colors look different due to brightness, it is due to the amplitude property of the light.
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For each question, select the right answer from the choices below:
a Object A weighs 30 N on Earth. Object B weighs 30 N on the Moon (which
has a gravitational field strength 1/6 the size of Earth's). Which object has the greater mass?
i. A
ii. B
iii. neither of them
iv. depends on air resistance
Option (ii) B is the correct option. The object on the moon has greater mass.
To resolve this, utilize the formulas Force = Mass * Acceleration.
The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.
Calculating the mass on earth:
30 N = 9.8 m/s² * mass
This results in a mass of 3.0 kg for the object on Earth.
Calculating the mass of the moon:
30 N = 1.6 m/s²2 * mass
Thus, the moon's object has a mass of 19. kg.
This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).
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A car starts with a velocity of 10 m/s. it
accelerates for 3 seconds at a rate of 2
m/s/s. what is its final velocity?
The final velocity would be 20m/s.
What is a final velocity?An object's final velocity is the speed at which it is moving after experiencing an acceleration over a period of time.The final step in calculating velocity is to multiply the initial velocity by the acceleration over time.The velocity at time t following the starting velocity is represented by the symbol v. Despite frequently being referred to as the last velocity, it is not the "last velocity" of an item.Distance and displacement are connected to speed and velocity in the same way. Velocity is a vector, whereas speed is a scalar. Speed is denoted by the letter v (italic), while velocity is denoted by the letter V. (boldface). A bar is added to the symbol over typical values.What is its final velocity?
Using the first equation of motion
V = U + at
where V = Final Velocity
U = Initial Velocity
a = Acceleration
t = Time
V = 10 + 1*10
V = 20 m/s.
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How does the kinetic energy of the car traveling 32 m/s compare to the energy released by burning a gallon of gasoline. That is, what is the ratio of the two?
The ratio of burning a gallon of gasoline to kinetic energy of the car is 1.27*102 :1
Burning a gallon of gasoline yields Egas = 1.3×108 J of energy.
A car's mass may vary in the range of 990 to 2000 kg.
Kinetic energy of a car is given as 1/2mv2
K.E = ½ m(32)2
K.E = ½*2000(32)2
K.E =1000 * 1024
K.E = 1.024 * 106 J
Comparing the Energy of gas to the kinetic energy of the car travelling at 32 m/s we have
Gas: Car = 1.3×108 J: 1.024 * 106 J
= (1.3 ×〖10〗^8)/(1.024×〖10〗^6 )
= 1.27*102 :1
Hence, the ratio of the energy of a burning gallon of gasoline to that of a car (assume weight is 2000 kg) moving at 32 m/s is 1.27*102 :1.
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A student contends:
"If I climb up a mountain at 1 mile per hour for 2 hours and then turn around and climb back down at 3 miles per hour, then my average speed will be 2 miles per hour."
What, if anything, is wrong with this statement? If something is wrong, identify it and explain how to correct it. If this statement is correct, explain why.
The statement is wrong and the correct average speed of the student will be 3/2 or 1.5 miles per hour.
Given in the question,
The student climbs the mountain at a speed of 1 mile per hour, then the distance traveled by the student uphill is given by
Distance = Speed × Time,
Put in the values, we get
Distance = 2 × 1 = 2 miles
So the student travels 2 miles uphill and turns around and climbs back at 3 miles per hour.
So the time taken by the student to climb back is given by
Time = Distance/Speed
Time = 2/3 hr
So Now
Total distance traveled by the student = Uphill climb + Downhill Climb
Total distance traveled by the student = 2 + 2
Total distance traveled by the student = 4 miles
Total time taken = Time to climb uphill + time to climb downhill
Total time taken = 2 + 2/3 hr
Total time taken = 8/3 hr
Now average speed is given by the formula,
Average Speed = Total Distance traveled/Total Time taken
Average Speed = 4 / (8/3)
Average Speed = (4 × 3) / 8
Average Speed = 12 / 8
Average Speed = 3/2 miles per hour
Therefore, the statement that the average speed will be 3 miles per hour is wrong and the correct average speed of the student will be 3/2 or 1.5 miles per hour.
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a simple formula for the distance traveled (x in meters) by an air car traveling a track uses the initial starting point (x0 in meters), the initial velocity (v0 in units meters per second), and the acceleration (a in units meters per second squared), and the time traveled (t in seconds).
The simple formula for the distance travelled ( in m ) by the air car is s = [tex]V_{0}[/tex] t + 1 / 2 at² which is an equation of motion.
According to equations of motion,
s = ut + 1 /2 at²
where,
s = Distance travelled
u = Initial velocity
t = Time travelled
a = Acceleration
Given that,
u = [tex]V_{0}[/tex]
s = [tex]V_{0}[/tex] t + 1 / 2 at²
Equations of motion are used to describe position of an object as a function of time. It is done using acceleration, velocity, distance and time.
Therefore, the simple formula for the distance travelled is s = [tex]V_{0}[/tex] t + 1 / 2 at²
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An object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm. The image height is
Since the magnification is equal to 1, the image height is the same as the object height which is 5 cm
What is Optical Magnification ?Magnification is when the ratio of the size of the image to the size of the object is greater than 1
Given that an object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm.
The object distance u = 20 cmThe object height h = 5 cmFocal length f = 10 cmThe image distance v = ?The image height H = ?To find the image height, let us first find the image distance by using the formula below
1/f = 1/u + 1/v
Substitute all the parameters
1/10 = 1/20 + 1/v
1/v = 1/10 - 1/20
1/v = (2 - 1)/20
1/v = 1/20
v = 20 cm
Magnification = v/u = H/h
20/20 = H/5
H = 5 cm
Therefore, the image height is the same as the object height which is 5 cm
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Which statements best describe the law of conservation of energy? Check all that apply.
The total amount of energy in the universe remains constant.
Energy can be created or destroyed.
Energy cannot be created or destroyed.
Energy can change from one type to another.
In a closed, isolated system, energy is conserved.
Answer:
the 2nd one and the 3rd one
Answer:
1,3,4,5
Explanation:
just got the answer correct on edge
which phrase best describes a chaparral
There are many different types of landforms in the chaparral biome, including rocky hills, level plains, and mountain slopes. Option C
What was the Chaparral Biome's temperature?The Chaparral biome often has very hot days and frigid to freezing nights. The summertime temperature range might be between 15 and 30 degrees.
Winter days are cooler, with temperatures ranging from 4° to 20°. The Chaparral biome has an average temperature of 18 degrees. The average yearly temperature is between -1° and 38° C (30° to 100° F).
Chaparral, or Mediterranean Forests and Shrubs, is a temperate biome distinguished by its hot, dry summers and mild, wet winters. Nearly the majority of the rainfall falls during the winter and spring rainy seasons.
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CQ
Which phrase best describes a chaparral?
O A. Is home to herds of giraffea, zebras, and wildebeests
O B. Receives less than 25 cm of precipitation per year
O C. Has low-growing, tough shrubs and rocky, dry soils
O D. Contains mostly needle-leaved evergreen trees
Answer:
here you go :)
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Explanation:
A spring has a natural length of 0.64m.It extended 0.024 m when a load of 3.6 N is applied. What would bring about an extension of 0.02m.
3N would bring about an extension of 0.02m.
A spring force is the force required or applied to compress or stretch a spring on an object attached to it. When an object exerts a force on a spring, the spring exerts an equal and opposite force on the object. It always acts to return the mass to its equilibrium position.
so here it is given that a spring has a natural length of 0.64m.It extended 0.024 m when a load of 3.6 N is applied.
formula
F₂/F₁=x₂/x₁
so
F₂=x₂/x₁*F₁
=0.02/0.024*3.6
=3N
So from the given data and using the equation we solved the proble and got 3N as the final answer
Learn more about spring force here https://brainly.com/question/12253978
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