Calculate the longest wavelength (nm) that can provide an energy of at least 415 kj/mol.

∅=2021rad  is the phase difference (in radians) in the light from the two slits.

using the formula below

Φ =( [tex]2\pi d/[/tex]β )sinα

∅=2021rad

The time difference between the same points within the two sounds' wave cycles (the peaks or positive-going zero crossings, for example), expressed as a fraction of one wave cycle, determines the phase difference between two sound waves of the same frequency travelling past a fixed spot.

Phase shift occurs when the sine and cosine function graphs are moved to the left or right of where they usually are, or we can say that the function is moved horizontally how far from its normal position. Functions are typically moved  from their normal place.

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Refraction is the cause of this. We perceive an object when light reflects off of it and travels to our eyes. The penny appears to vanish because light is refracted as it passes through the glass's edges and the water, never reaching our eyes.

Refraction in physics is the change in direction that results from a wave's change in speed as it passes through a medium. The electromagnetic waves that make up light are bent due to their different speeds as they pass past the boundary of one transparent medium and into another.

When partially submerged in water and viewed from an angle other than 90° to the surface, a straight stick seems bent. When travelling from air to glass, a ray of light of a single wavelength (various wavelengths appear as different colours to the human eye) is refracted, or bent, in a way that relies on the speeds of the two mediums.

A straight stick appears bent when partially submerged in water and viewed at an angle other than 90° to the surface. A light ray of a single wavelength—different wavelengths appear as different colors to the human eye—is refracted, or bent, in a way that depends on the speeds of the two media when it travels from air to glass.

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The distance travelled by the train travelling at 22 m/s, which  accelerates uniformly at 0.85 m/s² for 25s is 815.62.

The second equation of motion is used to calculate the distance traversed by the body moving with uniform velocity. Mathematically -

S = ut + 1/2 at²

Given in the question is a train travelling at 22 m/s accelerates uniformly at 0.85 m/s² for 25s. From this, we can write -

Initial velocity [u] = 22 m/s

acceleration [a] = 0.85 m/s²

time taken [t] = 25 s

In order to find the distance travelled by the train, we will use the second equation off motion -

S = ut + 1/2 at²

S = 22 x 25 + 1/2 x 0.85 x 25 x 25

S = 815.62 meters

Therefore, the distance travelled by the train travelling at 22 m/s, which  accelerates uniformly at 0.85 m/s² for 25s is 815.62.

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Answer:600 m is required for smaller plane to reach its takeoff speed. ... So 300 m is required for smaller plane to reach its takeoff speed.

Explanation:

Answer:

300 m

Explanation:

Find acceleration of first plane

v = a t

80 = a (30)   shows a = 2.67 m/s^2

For the smaller plane

v = at

40 = 2.67 t    shows t = 14.98 seconds

d = 1/2 a t^2

  = 1/2 2.67 (14.98^2) = 299.6 = ~ 300 meters

The order of magnitude of the distance between Los Angeles (LA) to New York (NY) is determined as 6.

An order of magnitude of a measurement is an approximation of the logarithm of a value relative to some contextually understood reference value, usually 10, interpreted as the base of the logarithm and the representative of values of magnitude one.

Also, the order of magnitude can be defined as  the power of 10 a number is raised to when it's in scientific notation.

The given measurement;

m = 3,944,000 m

The measurement in scientific notation;

3,944,000 m = 3.944 x 10⁶ m

Thus, the order of magnitude of the distance between Los Angeles (LA) to New York (NY) is determined as 6.

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Relative velocity of the river with respect to shore, V = 20 km/h.

Relative velocity of the river with respect to shore ,V = 10 km/h

Velocity of the shore = 0 km/h

Relative velocity of the river with respect to shore:

[tex]V = V_{r} - V_{s}[/tex]

Velocity of the river [tex]V_{r}[/tex] = 10 km/h

Relative velocity of the boat with respect to river ,V'= 10 km/h

[tex]V^{'} = V_b} -V_{r}[/tex]

Velocity of the boat [tex]V_b}[/tex] = 20 km/h

Relative velocity of the boat with respect to shore, V":

[tex]V_{"} = V_{b} - V_{s}[/tex]

Relative velocity of the boat with respect to shore is 20 km/h.

It is the pace at which one object's relative location changes in relation to another object over time.

Think about two trains that are traveling in the same direction and at the same pace. Even though the tracks, buildings, and trees on each side of the railway indicate that both trains are moving, to the observer of one train, the other train appears to be stationary. The other train seems to be moving at a constant speed.

The speed at which one thing moves in relation to another is known as the relative velocity of the two objects.

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The maximum permissible tension in cable AB is 3.11 kN

Given that,

I [tex]M_{x}[/tex] I ≤ 61.6 kN.m

I [tex]M_{y}[/tex] I ≤ 13.6 kN.m

I [tex]M_{z}[/tex] I ≤ 9.6 kN.m

OC = √ [tex]OA^{2}[/tex] - [tex]AC^{2}[/tex]

OC = √ [tex]25^{2}[/tex] - [tex]15^{2}[/tex]

OC = 20 m

[tex]r_{A}[/tex] = 15j + 20k

AB = √ [tex]2.5^{2}[/tex] + [tex]15^{2}[/tex] = 15.2069 m

P = P AB / AB = ( P ) 2.5i - 15j / 15.2069

P = 0.164399P i - 0.98639P j

[tex]M_{o}[/tex] = [tex]r_{A}[/tex] * P = [tex]\left[\begin{array}{ccc}i&j&k\\0&15&20\\0.163499P&-0.98639P&0\end{array}\right][/tex]

[tex]M_{o}[/tex] = ( 19.7828P ) i + ( 3.2700P ) j - ( 2.4525P )k

I [tex]M_{x}[/tex] I ≤ 61.6

19.7828P ≤ 61.6

P ≤ 3.11 kN

I [tex]M_{y}[/tex] I ≤ 13.6

3.2700P ≤ 13.6

P ≤ 4.16 kN

I [tex]M_{z}[/tex] I ≤ 9.6

2.4525P ≤ 9.6

P ≤ 3.91 kN

Tension is the act of stretching. It is a force transmitted through a object when pulled by forces across opposite sides.

Therefore, the maximum permissible tension in cable AB is 3.11 kN

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Astronomers observe a typical star using a telescope and a spectrometer, they will see an absorption spectrum and is therefore denoted as option B.

This is referred to as the percentage of incident radiation which have been absorbed by the material over a range of different frequencies.

Astronomers are referred to as scientists who are involved in the study planets and space with the use of instruments such as telescope and a spectrometer and they are most likely to see an absorption spectrum due to the different frequencies of light which are present in space.

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The options are:

The expression for velocity is [tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]

The expression for acceleration is [tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex]

The expression for the rocket's position as measured from the center of the earth is

[tex]y(t)=[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{2}{3}[/tex]

Let

[tex]x(t)=R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t[/tex]

We have,

[tex]y(t)=[x(t)]^\frac{2}{3}[/tex]

The velocity of the rocket as a function  of time is given by

[tex]v(t)=\frac{\mathrm{d} y(t)}{\mathrm{d} t}=\frac{2}{3}[x(t)]^{-\frac{1}{3}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]

[tex]v(t)=\frac{\mathrm{d} y(t)}{\mathrm{d} t}=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]

Since

[tex]x(t)=R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t[/tex]

We have,

[tex]\frac{\mathrm{d} x(t)}{\mathrm{d} t}=3\sqrt{\frac{g}{2}}R_{E}[/tex]

[tex]v(t)=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]

[tex]v(t)=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}} X 3 \sqrt{\frac{g}{2}}R_{E}=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]

[tex]v(t)=\frac{\sqrt{2g}}{\left ( R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t \right )^\frac{1}{3}}R_{E}[/tex]

[tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex] .......(i)

The acceleration as a function of time is given by

[tex]a(t)=\frac{\mathrm{d} v(t)}{\mathrm{d} t}[/tex]

[tex]a(t)=\frac{\mathrm{d}}{\mathrm{d} t}\left (\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}\right )[/tex]

[tex]a(t)=\frac{\mathrm{d}}{\mathrm{d} t}\left ({\sqrt{2g}}R_{E}[x(t)]^{-\frac{1}{3}}\right )[/tex]

[tex]a(t)=\sqrt{2g}R_{E}\frac{\mathrm{d}}{\mathrm{d} t}[(x(t)]^{-\frac{1}{3}}[/tex]

[tex]a(t)=-\frac{1}{3}\sqrt{2g}R_{E} [(x(t)]^{-\frac{4}{3}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]

[tex]a(t)=-\frac{1}{3}\sqrt{2g}R_{E} [(x(t)]^{-\frac{4}{3}}3\sqrt{\frac{g}{2}}R_{E}[/tex]

[tex]a(t)=-gR_{E}^2 [(x(t)]^{-\frac{4}{3}}[/tex]

[tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[x(t)]^\frac{4}{3}} \right )[/tex]

[tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex] .......(ii)

Therefore, the expression for velocity is [tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]

& the expression for acceleration is [tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex]

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In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for a rocket's position measured from the center of the Earth is given by [tex]y(t)=[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{2}{3}[/tex]

where RE is the radius of the Earth (6.38 ✕ 106 m) and g is the constant acceleration of an object in free fall near the Earth's surface (9.81 m/s2).

(a) Derive expressions for v(t) and a(t).

(Use the following as necessary: g, RE, and t. Do not substitute numerical values; use variables only.)

The FIIT plan required for different type of workout is shown in the image attached.

FIIT plan is used to monitor one's workout routine. It also helps to create workout routines that helps one's fitness goal which might differ from each person. It works based on four elements i.e., Frequency, Intensity, Time and Type.

Frequency refers to how often a workout needs to be done. Intensity refers to how hard a workout must be done. Time refers to the amount of time spent on the workout. Type refers to the king of exercise which suits one's final goal.

Therefore, the FIIT plan required for different type of workout is shown in the image attached.

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Answer:The cyclist's acceleration to the nearest tenth is: C. 2.7 .

Given the following data:

Initial velocity = 0 m/s (since the cyclist starts from rest).

Final velocity = 12.5 m/s.

Time = 4.5 seconds.

To find the cyclist's acceleration to the nearest tenth:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

Where:

A is the acceleration.

V is the final velocity.

U is the initial velocity.

t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

Acceleration, A = 2.7  

Therefore, the cyclist's acceleration to the nearest tenth is 2.7 .

Explanation:

Answer:

yeas

Explanation:

beac×high ×sides and after you fins tims you need to add beac+high and add the sides together and add what did you got from beac,high and sides and thin you will add every thing together

Answer:

Replace distance with "direction"

Explanation:

In daily life the common example of isolated system, closed system and open system is themosteel bottle , human body and ecosystem respectively.

Water in a thermos, or thermosteel bottle is an example of isolated system where no transfer of energy neither transfer of matter takes place between the system and surroundings. Although no system is perfectly isolated, after some instant there a hear loss takes place by some means.

There are three types of system in thermodynamics,

Thermodynamics is the branch of science is which we study about the heat, temperature, work and their relation to energy.

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The magnitude of the electric field is

[tex]1.29 \: \times 10 ^{ - 24} \: N/C.[/tex]

The time interval is t.

[tex]t = 3.8 \times 10 ^{ - 6} \: s[/tex]

The distance of the second proton from the first proton is d.

[tex]d = 1.60 \: 10^{ - 2} \: m[/tex]

[tex]∆x = \frac{1}{2} at ^{2} [/tex]

The magnitude of the electric field is,

[tex]E = \frac{ F}{e}[/tex]

[tex]E = \frac{ma}{e} [/tex]

[tex] = \frac{2 \: ∆x \: m}{e \: t ^{2} } [/tex]

[tex] = 2 \times \frac{(1.6 \times 10 ^{ - 2} )(1.9 \times 10 ^{ - 3}) }{(1.6 \times 10 ^{ - 19})(3.8 \times 10 ^{ - 6} ) ^{2} } [/tex]

[tex] = 1.29 \: \times 10 ^{ - 24} \: N/C[/tex]

Therefore, the magnitude of the electric field is

[tex]1.29 \: \times 10 ^{ - 24} \: N/C.[/tex]

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Simple observation more appropriate than experimenting in a controlled laboratory when the results can be gotten solely by using our sense organs.

This is referred to as a part of a scientific method and it is performed by scientists to test a hypothesis so as to know whether it will be accepted or refuted.

This is usually performed by different people from all over the world so as to ascertain its authenticity before it becomes a theory or law. This doesn't involve only sense organs alone as different techniques are required to arrive at a conclusion in this process.

Observation on the other hand requires the use of sense organs such as the eyes, nose etc to determine the results and may not need the use of experiments which is therefore the reason why it was chosen as the correct choice.

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According to given data, the average speed of train is 25 km/h.

Given data,

distance = 5 km

time = 12 minutes

average speed = ?

changing time from minute to hour

So,

hour = 12 / 60

hour = 0.2

Then to calculate speed use the formula,

s = d / t

s = 5km / 0.2hr

s = 25 km/h

Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector value, whereas speed is a scalar value. It has a dimension of time-distance. As a result, the basic unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.

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Being physically, emotionally, and mentally healthy can keep you healthy and help you avoid significant health issues during exercises.

Exercise boosts mental health by lowering anxiety, depression, and depressive symptoms, as well as by raising self-esteem and increasing cognitive abilities. Additionally, it has been discovered that exercise helps with symptoms including poor self-esteem and social withdrawal.

Exercise on a regular basis can significantly improve symptoms of sadness, anxiety, and ADHD. Additionally, it lowers stress, enhances memory, promotes sound sleep, and uplifts your mood in general. It should be noted that it's important to be in the right state of mind during exercise to prevent injuries.

Therefore, being physically, emotionally, and mentally healthy can keep you healthy and help you avoid significant health issues during exercises.

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The magnitude of the electric field at the center of the square is 4.32 * [tex]10^{5}[/tex] N / C

We know that,

The magnitude of the electric field by the one positive charge and other negative charge at the centre is

E = k ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] ) / [tex]r^{2}[/tex]

The distance of each charge from the centre of the square is

r = d / √ 2

where,

k = Coulomb's constant

[tex]q_{1}[/tex], [tex]q_{2}[/tex], [tex]q_{3}[/tex], [tex]q_{4}[/tex] = Point charges

d = Side of square

Given that,

[tex]q_{1}[/tex] = [tex]q_{2}[/tex] = [tex]q_{3}[/tex] = 3 μ C = 3 * [tex]10^{-6}[/tex] C

[tex]q_{4}[/tex] = - 3 μ C = - 3 * [tex]10^{-6}[/tex] C

d = 0.5 m

k = 9 * [tex]10^{9}[/tex] N m² / C²

E = k ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] ) / [tex]r^{2}[/tex]

E = 2 k / d² ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] )

E = 2 ( 9 * [tex]10^{9}[/tex] ) ( 3 * [tex]10^{-6}[/tex] - ( - 3 * [tex]10^{-6}[/tex] )) / 0.5²

E = 4.32 * [tex]10^{5}[/tex] N / C

Electric field is the field surrounding an electrically charged particle. If any other charged particle enters the field, it exerts force on the particle.

Therefore, the magnitude of the electric field at the center of the square is 4.32 * [tex]10^{5}[/tex] N / C

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The social cognitive perspective of personality focuses on social factors such as your parents guardians and teachers and cognition means how we as individuals process and store information.

This is referred to as the process in which information is stored and processed through the use of our senses, experience etc and is common to all individuals.

The social cognitive perspective of personality on the other hand focuses on social factors such as parents and also in which cognition is among and it is influenced by genetic and environmental factors which therefore makes it the most appropriate choice.

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Galileo’s telescopic discoveries of the moons of Jupiter are often mentioned. But they did not amount to proof that the Ptolemaic system was incorrect.

It's hard to tell you how big a shakeup this caused in astronomy at the time. Thanks to Galileo, we now knew that planets weren't perfect, ethereal lights in the sky. That things could orbit them, same as (most astronomers thought) things did around Earth, making Earth less special, and providing evidence that maybe that heliocentric theory wasn't that out there.

Basically, before Galileo, astronomers were looking at an unchanging, heavenly firmament, separate from Earth by its very heavenly nature.

After, they were studying planets - actual worlds like ours - and moons and the physical (as opposed to heavenly) reality of their place in the universe.

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When Photons of wavelength 0.024 a are incident on free electrons, the wavelength of a photon which is scattered 30° is 0.0576 x [tex]10^{-11}[/tex] and for the one scattering at 120° is 0.38 x  [tex]10^{-11}[/tex] A.

The incident photon’s energy is equal to the scattered photon’s energy minus the total of the recoil electron’s kinetic energy and binding energy.

Compton scattering causes the loss of an electron and ionization of the absorbing atom, just like photoelectric absorption does.

After the scattering event and before, the photon’s wavelength varies by ∆λ = (h/mc) (1-cosφ). Here, c is the speed of light, m is the rest mass of the electron, and is the angle at which the photon is scattered. H is the Planck constant.

Given photon wavelength λ = 0.024A

φ = 30°

From the Compton effect we know that

∆λ = λ1 - λ = h/mc (1-cosφ)

λ1 = [tex]\frac{6.62*10^{-34}}{9.1}[/tex] x [tex]10^{-3}[/tex] x 3 x [tex]10^{8}[/tex] (1- cos30°) + 0.024A

= 0.0576 x [tex]10^{-11}[/tex] A

And then calculating the same for

φ = 120°

we get,

λ1 = 0.38 x  [tex]10^{-11}[/tex]A

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Complete Question

Photons of wavelength 0.024A are incident on free electrons.

(a) Find the wavelength of a photon which is scattered 30° from the incident direction and the kinetic energy imparted to the recoil electron

(b) Do the same if the scattering angle is 120°.

One 6 oz can of chunk light tuna is to be consumed every four days.

The mercury content in 2010:

White tuna chunks weigh 0.6 ppm in total.

A piece of light tuna has a mass of 0.14 ppm.

The body weighed 63 kg, and the tuna weighed 6 oz.

The maximum quantity of mercury that the body should ingest each day is advised to be no more than 0.1 micrograms.

Solution:

Let's first convert the tuna's mass to grams.

As 1 oz equals 28.3495 g

The tuna weighs 6 oz, or 28.3495 g.= 170.097 g

The maximum daily mercury (Hg) intake for a 63 kg body weight is equal to 63 0.1.

6.3 micrograms per day

But the mass of the mercury (Hg) = concentration (Hg) mass of the tuna

= 0.6 × 10⁻⁶ × 170.097 g

= 1.0206 × 10⁻⁴ g

= 102.06 μg (micrograms)

The interval needed to consume one 6 oz can of chunk white tuna = 102.06/6.3

= 16.2 days

≅ 16 days

An average of 16 days must pass between consuming one 6 oz can of chunk white tuna.

the mass of the mercury (Hg) is equal to the product of the concentration (Hg) and

the mass of the tuna (0.14 106 170.097 g = 2.4814 105 g = 23.814 g).

= 23.814/6.3

= 3.78

As a result, it takes 3.78 days plus 4 days to consume one 6 oz can of chunk white tuna.

Approximately every four days, a single 6 oz can of chunk light tuna is consumed and the total 6-ounce tuna can be consumed in 16 days.

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The pair of objects that experiences the largest gravity force is an apple and a brick

An object will be weightless in outer space, away from the gravitational field of Earth (or another massive planet), yet it will still have mass and consequently resistance to a given force.

When one body has a higher mass than another, it is said to be more massive. The electron, with a mass of about 9.11 10-31 kg, is one of the Universe's least massive things. Hence, the combination of a proton and electron would experience the least gravity force. The combination of an apple and a brick has the most mass hence would experience the largest gravity force. Two apples or an apple and a proton are less massive compared to an apple and a brick thus incorrect.

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J. J. Thomson used a cathode-ray tube to calculate the charge-to-mass ratio of the electron. The deflection of cathode rays towards the positively charged surface proved that they are negatively charged particles.

In 1897, J.J Thomson performed a cathode ray tube experiment to determine the charge-to-mass ratio of electrons.

Due to high flow of voltage, a beam of particles was allowed to flow from the negatively charged end to the positively charged end of the tube.

An end of the tube was painted with phosphorous and when electrons struck that end, a green spark was observed which confirmed the presence of negatively charged particles i.e. electrons.

To put it simply, cathode rays came from the cathode tube and deflected towards a positively charged plate showing that they are negatively charged particles.

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According to the given statement the wishbone's initial acceleration is 13.08 m/s².

Velocity's rate of change with time, both in terms of speed and direction. A point or item going straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on a circular accelerates so because direction is always shifting.

In this task, we calculate the acceleration for a given force and the mass on which the force was applied.

F[tex]_n_e_t[/tex] = 0.17 N

m = 13g

m = 1.3 × 10⁻² kg

a =?

F = m × a

a = F/m

a=0.17 N/1.3× 10⁻² kg

a=13.08 m/s²

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Answer:

neither.

they both are going at the same speed

Explanation:

Answer:

They have the same Kinetic Energy

Explanation:

KE  = 1/2 m v^2      if the velocities are the same  and the masses are the same  .....then the Kinetic energies are the same

When the flea jumps straight up, and if air resistance is neglected, the height of the flea will be 0.089m.

Air resistance acts as a force on objects moving through the atmosphere. This force acts in the opposite direction when a body is travelling through the air. Air resistance causes the moving body to experience frictional force. A body's speed decreases as it goes due to air resistance.

It should be noted that the equation of kinematics will be illustrated thus:

V = ✓(2 × 1500 × 0.44mm)

Therefore, h = V² / 2g

= (✓(2 × 1500 × 0.44mm)² / (2 × 9.8)

= 0.089m

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We have that the flea goes as high as

h=0.0889m

From the Question, we are told that
Acceleration =1500ms^2

Distance d=0.47mm

Generally, the equation for height is mathematically given as

h=\frac{u^2}{2 g}

Where

u^2=2 * 1500 * 0.44 * 10^{-3}

u=1.32ms

Therefore

h=\frac{1.32^2}{2 * 9.8}

h=0.0889m

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Yes. If a car is traveling eastward and slowing down, its acceleration is opposite to the direction of travel: its acceleration is westward.

A car that has been traveling at different speeds is already accelerating.

Now suppose it is traveling at different speeds means some force is applied to that car.

It is traveling in a straight line in the east and traveling at a different speed, which means the speed keeps on changing so sometimes it can be possible that acceleration can also be in the opposite direction to that in which it is traveling, so here it can be in the west as it is an easterly course of travel direction so no north or south direction movement.

For more information on speed click on the link below:

https://brainly.com/question/13943409

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