On his fishing trip Justin rides in a boat 15 km south. The fish aren't biting, so they go 5 km west. They then follow a school of fish 1km north. What distance did they cover? What was their displacement?

The object displacement over the 9 seconds interval will be 0 m. Displacement can be define as the shift in the position of an object with respect to the reference frame.

An object's location changes if it moves with regard to a reference frame, like when a passenger moves to the back of an airplane or a lecturer moves to the right with respect to a whiteboard. Displacement is the term used to explain this shift in position.

The distance an item travels from its starting point until it reaches a certain velocity can be calculated using the formulas t = (v vi)/g and y = gt2/2 + vit. The equation for the object's velocity at a particular distance from the starting point is the outcome of this.

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Answer:

21.872

Explanation:

Answer: mixture

Explanation:

Answer:

soil is a mixture of minerals, dead and living organisms (organic materials), air, and water. These four ingredients react with one another in amazing ways, making soil one of our planet’s most dynamic and important natural resources.

Another definition of soil

The surface mineral and/or organic layer of the earth that has experienced some degree of physical, biological and chemical weathering.

In summary, soil is a mixture....

Ez = kqz / (z^2+a^2)^3/2 is the answer.

The expression of the electric field is,

E=kq / r^2

Here, r is the distance and its value is [tex]\sqrt{z^2 + a^2}[/tex]

Substitute the value of r in the above expression.

E=kq /  [tex]\sqrt{z^2 + a^2}[/tex]^2

The expression of the electric field along the z-direction is given by,

dEz=dEcos[tex]\int\limits {dEcosθ} \,[/tex]

Here, the value of the cosine function is z /  [tex]\sqrt{z^2 + a^2}[/tex]

On integrating the above expression and substituting the value

[tex]\int\limits{dEz} \,[/tex] =[tex]\int\limits{dEcosθ}[/tex]

Ez = Ecosθ

Ez = kq /  [tex]\sqrt{z^2 + a^2}[/tex]^2 *  z /  [tex]\sqrt{z^2 + a^2}[/tex]

Ez = kqz / (z^2+a^2)^3/2

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Although part of your question is missing the question is Consider a uniformly charged ring in the XY plane, centered at the origin. The ring has a radius a and positive charge q distributed evenly along its circumference. What is the magnitude of the electric field along the positive z-axis due to the ring? Use k in your answer, where k=1/4πε

B. Signals from sensory neurons reach motor neurons through interneurons in the brain and spinal cord that connect sensory neurons and motor neurons.

Sensory neurons are the nerve cells that work based on the sensory input from outside stimulus.

Motor neurons are special type of neurons or never cells that are found within the spinal cord and the brain.

The sensory neurons carry afferent impulse to the central interneuron, which connects with the motor neuron.

The motor neuron carries efferent impulses to the effector, and cause the response observed.

Thus, signals from sensory neurons reach motor neurons through interneurons in the brain and spinal cord that connect sensory neurons and motor neurons.

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Answer:

The speed of individual particle diffusion is influenced by temperature and particle size, not by concentration

Explanation:

The deflecting electric field is 9.50 x 10^14 mv/m.

The force on the drop of ink due to vertical acceleration = ma

And the force on the drop due to electrodes = qE

To calculate the deflecting electric field, we need to equate both these forces,

Hence, qE = ma

As there are 751896 extra electrons, the charge due to them will be = 751896 x 1.6 x 10^-19

M = mass of each drop of ink = 11 kg

A = acceleration of the drop of ink = 104 m/s^2

Putting the above values in the equation, qE = ma

1.6 x 10^-19 x 751896 x E = 11 x 104

On solving the above equation

E = 9.50 x 10^14 mv/m

Hence, the deflecting electric field is 9.50 x 10^14 mv/m.

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When a lever is 8ft long. a force of 80lb is applied to one end of the lever and a force of 560lb is applied to the other end. The fulcrum located when the system balances 6 feet from the greater force.

Define force.

X = length from greater weight to fulcrum

132X = 88(15-X)

132X = 1320-88X

220X = 1320

X = 6

The fulcrum located when the system balances 6 feet from the greater force.

An object experiences a push or pull as a result of interacting with another object. Each object is subject to a force whenever two objects interact. The two items no longer feel the force after the interaction ends.

In physics, a force is an effect with the capacity to change the velocity of an object. A force can cause an object with mass to move at a different speed or accelerate. To describe force, a push or a pull makes intuitive sense. Forces have both magnitude and direction because they are vector quantities.

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Rate of change is used to mathematically describe the percentage change in value over a defined period of time

A spherical balloon is inflated with gas at a rate of 700 cubic centimeters per minute. the radius of the balloon will be  changing at a rate of 0.035 cm/min at the instant the radius is 40 centimeters

given

Radius = 40 cm

dv / dt = 700

to find

Rate by which radius of balloon is changing = ?

volume of sphere = 4/3 π [tex]r^{3}[/tex]

dv/dt = 4/3 *  π [tex]r^{3}[/tex] dr/dt

dv/dt = 4/3 * 3 * π [tex]r^{2}[/tex] dr/dt

dv/dt = 4/3 * 3 * (3.14) * ([tex]40^{2}[/tex])  dr/dt

dv/dt = 20096 dr/ dt

700 = 20096 dr/dt

dr/dt = 700 / 20096

        = 0.035 cm/min

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According to internal energy, the final volume is 19.75 liters.

We need to know about internal energy to solve this problem. For a closed system, with matter transfer excluded, the changes in internal energy are due to heat transfer and due to thermodynamic work done by the system on its surroundings. It can be determined as

ΔU = Q - W

where ΔU is the change in internal energy, Q is heat and W is work done.

From the question above, we know that

ΔU = -325 J

Q = 155 J

Vo = 15 L = 0.015 m³

P = 1 atm = 1.01 x 10⁵ Pa

By substituting the given parameter, we can calculate the work done

ΔU = Q - W

-325 = 155 - W

W = 480 joule

Find the final volume

W = P . (Vi - Vo)

480 = 1.01 x 10⁵ (Vi - 0.015)

Vi = 0.01975 m³

Vi = 19.75 liters

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A small pebble is dropped from the top of a very high cliff, the pebble will be moving with a speed of 50 m/s.

vi=0

vf=?

a= 10m/[tex]s^{2}[/tex]

s= 125m

By newton's third law of motion,

2as = [tex]v_{f} ^{2}[/tex] - [tex]v_{i} ^{2}[/tex]

[tex]v_{f} ^{2}[/tex] = 2x 10 x 125

[tex]v_{f}[/tex] = [tex]\sqrt{2500}[/tex] = 50m/s

These are the three equations:

v = u + at.

S = ut + 1/2a[tex]t^{2}[/tex];

[tex]v^{2}[/tex] = [tex]u^{2}[/tex]+ 2as.

The fundamental equation of motion in classical mechanics is Newton’s second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration an of its center of mass, or F = ma.

Motion can be divided into three categories depending on its type, as follows: linear movement and Rotational Motion in oscillations.

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The direction of the current flowing in the wire is inside the plane when viewed from above.

The direction of a magnetic field in a current carrying conductor can be found out by using Right Hand Thumb Rule.

According to this rule. if we suppose a straight wire is carrying current, not if we align the thumb of our right hand in the direction of the flowing current, then the direction of the magnetic field is same as that of the the curling fingers.

In our question, if we apply this rule then we can find, if we align our fingers in the same manner as that of the magnetic field, then the direction of our pointing thumb will be inside. The direction of thumb pointing will be same as that of the current.

So, we can say that by Right Hand Thumb Rule, the direction of the flowing current is Inside when viewed from top.

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The distance travelled by the car in the first 20 seconds of the motion is 130 m.

The area under the speed-time graph is the distance the particle travels.

The distance traveled by the car in the first 20 seconds is calculated as follows;

From the speed - time graph, at 20 seconds, the speed of the car is 13 m/s.

Distance = area of the graph = area of triangle formed from time, 0 s to 20 seconds.

Distance = ¹/₂bh

where;

Substitute the given parameters and solve for the distance traveled by the car.

Distance = ¹/₂bh

Distance = ¹/₂(20)(13)

Distance = 130 m

Thus, the distance travelled by the car in the first 20 seconds of the motion is 130 m.

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The missing graph is in the image attached.

Displacement is the movement of unfavorable emotions from one thing or person to another.

As a kind of self-preservation, displacement is the act of shifting one's unfavorable emotions from one thing or person to another.

According to the notion, releasing stress or worry on a non-threatening target helps a person deal with negative emotions like fear or rage.

For instance, if a person feels angry because their boss yells at them, they might project those feelings onto someone or something else, such a member of their family or a piece of furniture.

For fear of losing their work, the person could feel unable to face their manager. As a result, they might vent their rage on a less dangerous person like their partner or housemate.

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A point charge of -3. 00 μC is located in the center of a spherical cavity of radius 6. 80 cm inside an insulating spherical charged solid. The charge density in the solid is 7. 35 x 10^-4 C/m^3. The magnitude of the electric field inside the solid at a distance of 9.20 cm from the center of the cavity is 394.6857x10⁻⁶ N/C.

Charge inside the cavity = -3μC = -3x10⁻⁶ C

Charge density of the sphere, ρ = 7.35x 10⁻⁴ C/m³

Radius of he cavity = 6.90 cm = 0.0690 m

We have to find the electric field at a radius of 9.20 cm, therefore, the effective radius,

Effective radius = 0.092-0.069 = 0.023 m

Effective Volume = [tex]\frac{4}{3}[/tex] π[tex]r^{3}[/tex]= 0.5093 x10⁻⁴ m³

The charge, Q = volume x charge density = 374.33 x 10⁻⁶ C

The net charge enclosed,

[tex]Q_{in} =(374.33-3)x10^{-6} =371.33 x10^{-6}[/tex]C

We know according to the Gauss law,

⇒E=[tex]\frac{Q_{in} }{e_{o} }[/tex]

E=394.6857 X[tex]10^{-6}[/tex]N/C

Hence, the magnitude of the electric field inside the solid at a distance of 9.20 cm from the center of the cavity is 394.6857x10⁻⁶ N/C.

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Answer:

372 252

Explanation:

Both the solar system and interstellar space are very large. 150 million kilometers are equivalent to one astronomical unit. Instead of having to count everything in millions or billions of kilometers, it is much simpler to count the distances if they are in counts of Astronomic Units.

Why do astronomers use light years or astronomical units to describe distances in space instead of miles or meters?

Both the solar system and interstellar space are very large. 150 million kilometers are equivalent to one astronomical unit. Instead of having to count everything in millions or billions of kilometers, it is much simpler to count the distances if they are in counts of Astronomic Units.

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The acceleration of the car is 2.45 m/s².

Acceleration is the rate of change of the velocity of an object with respect to time. Its unit is m/s² and can be given as,

a = dv/dt

Where , dv and dt is the small change in velocity and time of an object.

Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.

V = Δx/Δt

In here , V is velocity ,  Δx is change in displacement and Δt is change in time of an object.

We are know that ,

Initial velocity of the car = u = 15 m/s

Final velocity  of the car = v = 28 m/s

Covered time of the car = t = 5.8 s

Therefore we know the equation of motion can be given as,

v = u + at

Hence , to get the acceleration of the car we may put the values in above equation then,

28 m/s = 15 m/s + (5.3) a

a = (28 m/s - 15 m/s) /5.3s

a = 2.45 m/s²

Thus , acceleration of a car is 2.45  m/s²

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2m/s is the average velocity of the particle.    

Velocity of an object can be defined as the change of distance divided by time it's SI unit is metre per second formula v= d/t.

here we have given that the time taken by the particle is 9s and the displacement is 18m/s

so by applying the given data in the formula

v=d/t

=18/9

=2m/s

so from here we can state that for a object or a paricle with a displacement of 18m and the time taken by it is 9 s the velocity of that will be v=d/t that is 18/9 which is 2m/s.

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The pushing force does not make the brick move as there is not enough power being exerted.

The pushing force does not make the brick move as there is not enough power being exerted.

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Answer:

Ernest Rutherford (later Lord Rutherford)

No. You can say that the car had a constant speed, but not constant velocity if the speedometer consistently displays 50 km/h.

The car's velocity would change if its direction changed, even though it was moving at the same pace.

The speed at which something moves in a specific direction is known as its velocity.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is traveling along a path.

Consider the speed of a car driving north on a highway as an example. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.

The standard unit of velocity magnitude is the m/s.

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Answer:

length

Explanation:

If the falling time of an object is doubled, it will then that means that the length is doubled

Answer: no

Explanation:

momentary rest = object is NOT in motion at that instant of time

In the moment that the object is at rest, the velocity is 0 meaning that there is no acceleration.

By ideal gas approximation, the total number of moles of Ne is 3 moles.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

STP condition (P = 1.01 x 10⁵ Pa, T = 273 K)

n = 3 moles

The ideal gas depends on the number of moles. Hence, the total number of moles of Ne will be the same as CO₂ (3moles).

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Answer:

H1 = V t1 - 1/2 g t1^2      where upward is chosen as positive

H2 = -V t2 - 1/2 g t2^1     second stone thrown downwards

V t1 - 1/2 g t1^2 = -V t2 - 1/2 g t2^2

V (t1 + t2) = 1/2 g (t1^2 - t2^2)

V = 1/2 g (t1 - t2)

t2 = 2 V / g = 96 / 9.8 = 9.8 sec

Check:

One can also note the stone 1 will return to the starting point with a time delay of V / g * 2 which is 96 / 9.8 = 9.8 sec because the time for stone 1 to go to zero is 48 / 9.80 = 4.90 sec when its velocity reaches zero

Approximately 9.8 seconds when rounded to one decimal place. Therefore option F is correct.

Calculate the time it takes for the first stone to hit the street (t1) and the time it takes for the second stone to hit the street (t2).

For the first stone (thrown straight down):

Using the equation of motion:

[tex]\rm \[ d = \frac{1}{2} g t_1^2 \][/tex]

where:

d = distance traveled (height of the building)

g = acceleration due to gravity = [tex]\rm 9.8\ m/s^2[/tex] (downward)

Since the stone is thrown from the top of the building, the distance traveled (d) is equal to the height of the building.

Now, let's find t1:

[tex]\[ h = \frac{1}{2} g t_1^2 \]\\\ \\t_1^2 = \frac{2h}{g} \]\\\\\ t_1 = \sqrt{\frac{2h}{g}} \][/tex]

For the second stone (thrown straight up):

The initial velocity of the second stone is also 48.0 m/s, but it is directed upward. We can use the equation of motion for upward motion:

[tex]\rm \[ v = u - gt_2 \][/tex]

where:

v = final velocity = 0 m/s (at the peak of the motion, the velocity becomes 0)

u = initial velocity = 48.0 m/s (upward)

g = acceleration due to gravity = 9.8 [tex]\rm m/s^2[/tex] (downward)

Now, let's find t2:

[tex]\[ 0 = 48.0 - 9.8t_2 \]\\\\\ t_2 = \frac{48.0}{9.8} \]\\\\\ t_2 = 4.898 \][/tex]

Since the second stone takes time [tex]t_2[/tex] to reach the peak and another time [tex]t_2[/tex] to fall back down, the total time before the second stone hits the street is [tex]\( 2 \times 4.898 \)[/tex].

[tex]\[ t_{\text{total}} = 2 \times 4.898 \]\\\ t_{\text{total}} = 9.796 \][/tex]

The correct answer is approximately 9.8 seconds (F) when rounded to one decimal place.

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Answer:

It is 3

Explanation:

the reason its 3 is the wire is electrical and it heats up like a phone screen after using it for too long and its kinetic energy to thermal because the energy in the wires stop when they are broken because there is no way the energy can jump the wires

the wavelength of the standing wave in the string of third harmonic is 0.24 meters.

We need to know about the third harmonic wavelength to solve this problem. When the string is vibrating at its third harmonic, it should follow the rule

λ = 2/3 L

where λ is wavelength and L is the length of string

From the question above, we know that

f = 500 Hz

L = 0.36 m

m = 4 g

By substituting to the following equation, we can calculate the wavelength

λ = 2/3 . L

λ = 2/3 . 0.36

λ = 0.24 m

Hence, the wavelength at its third harmonic is 0.24 meters.

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The maximum length the strig can have is 1.89 x 10^10 m.  

Tensile stress may be defined as the external forces acting per unit area on a material which cause the material to stretch. This stress acts along the axis of the material.

Density is given by the formula:

Density= mass/volume

So, volume is given by;

Volume= mass/density

Mass of string in kg= 4.2/1000= 0.0042 kg.

Density of steel is in kg/m^3.

Then volume V will be;

V= 0.0041/7710 = 5.31 x 10-7m^3

Now we know that stress = Force/Area

Thus, Area is given by; Area = force/stress => 900/7*10^8= 2795.95m^2

Length can be determined by= volume/Area =>5.31^10-7/2795.95

Therefore, the maximum Length of string is = 1.89 x 10^10 m.

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Complete Question:

If A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. One type of steel has a density of 7710kg/m3 and will break if the tensile stress exceeds 7.0×108N/m2. You want to make a guitar string from a mass of 4.2 g of this type of steel. In use, the guitar string must be able to withstand a tension of 900 N without breaking. Your job is the following.

(a) Determine the maximum length the string can have

Answer:

0.5 miles or 800 meters!

Explanation:

Sally traveled 0.5 miles or 800 meters.

I'm not too sure if this is what you were asking but if you need any more help let me know! :D