It is after a time of 25 minutes that the vacationer picks up his lunch after turning around the dock.
Let the speed of the motorboat be v and the speed of the river be u.
Upstream - The term "upstream" refers to a boat that is moving against the direction of the stream. The boat's upstream speed in this situation is its net speed.
Downstream - A boat is said to be moving downstream if it is moving in the same direction as the stream. In this instance, the boat's downstream speed is its net speed.
Given in the question
Distance travelled downstream = d = 2.8 km
Time = t = 25 mins = 25 × 60 = 1500 seconds
Downstream Speed = v + u
Let the time after he picks the lunch be t' seconds
Distance traveled by boat in t' seconds
d = (v + u )t'
Distance traveled by lunch in t + t' seconds
x = u(t + t')
Upstream Speed = v - u
Distance traveled by boat upstream :
x' = (v-u)t
So accordingly,
x + x' = d
u(t + t') + (v-u)t = (v + u )t'
ut + ut' + vt -ut = vt' + ut'
vt = vt'
t = t'
t' = t = 1500 seconds = 25 minutes
So, the vacationer picks up the lunch 25 mins after turning around.
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The village blacksmith dunks a red-hot horseshoe into a large bucket of 22°C water. How much heat was lost by the horseshoe in vaporizing 0.981 kg of water?
Q=mcΔT and Q=mhv (Heat of vaporization of water = 2,260,000 J/kg and the specific heat is 4187 J/kg°C) Round to the tenth place.
The heat lost in this case is obtained as 2537.1 kJ.
What is the heat lost?We know that heat is the form of energy that exists due to temperature difference between two bodies. In this case, the village blacksmith dunks a red-hot horseshoe into a large bucket of 22°C water. This led to the evaporation of 0.981 kg of water.
Now there are two distinct processes here;
The heat required to heat the water from 22 degrees to boiling pointHeat required to vaporize the water.The total heat lost = mcdT + mL
= 0.981 kg * 4187 J/kg°C * ( 100 - 22) + 0.981 kg * 2,260,000 J/kg
H = 320 kJ + 2217
H = 2537.1 kJ
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Question 12 (1 point)
Football player Joe is running toward the opponent's goal line with the football, and slows down as he encounters the other team. If the opponent's goal line is the reference point, which of the following best describes his motion?
Question 12 options:
Negative Velocity, Positive Acceleration
Negative Velocity, Negative Acceleration
Positive Velocity, Positive Acceleration
Positive Velocity, Negative Acceleration
Answer:
d
Explanation:
I remember it was right
A ball is dropped from the top of a tall building of height = 91 m. What was the magnitude of the velocity of the ball at impact?
The magnitude of gravity use 10
m/s²
Answer to the nearest hundredth of a meter/sec
Draw a position time graph that represents the problem
Draw a velocity time graph that represents the problem.
The magnitude of velocity of the ball dropped from a 91 m tall building at the point of impact is 42.8 m / s
s = ut + 1 / 2 at²
a = v / t
s = Distance
u =Initial velocity
a = Acceleration
t = Time
s = 91 m
a = 10 m / s²
s = ut + 1 / 2 at²
91 = 0 + ( 1 / 2 * 10 * t² )
t = √ ( 18.2 )
t = 4.27 s
v = 10 * 4.27
v = 42.7 m / s
The position-time graph and the velocity-time graph that represents the problem is drawn in the image attached.
Therefore, the magnitude of velocity of the ball is 42.7 m / s
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Snow how the units of from the ROU Fundamental for (A) (Area) (B) (speed) is derived whits,
Area and Speed are derived Units Because they are derived from the Fundamental Units
By proceeding using the dimensional analysis,
We can see,
Area = Length of object x Breadth of object
As we know, both the length and the breadth of the object are measured as Meter(M),
Area = M x M
Now, for Speed,
Speed = distance/time
unit of distance is Meter(M) and unit of time is Second(S), both of these are fundamental quantities.
Speed = Meter/second
Speed = M/S
As we can see, the unit of area is a composition of a fundamental unit and speed is also a composition of fundamental unit and any unit which is composition of one or more fundamental unit is called derived Unit.
Hence it is proved that Area and Speed are Derived Units.
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If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
How to calculate the final velocity a moving object?From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.
It is expressed as;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Initial velocity u = 6m/sAcceleration a = 85m/s²Elapsed time t = 5sFinal velocity v = ?Plug the given values into the first equation of motion and solve for v.
v = u + at
v = 6m/s + ( 85m/s² × 5s )
v = 6m/s + 425ms/s²
v = 6m/s + 425m/s
v = 431m/s
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
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What were you doing when you felt most passionate and alive and where?
A happiness that is full of significance and delight as well as a sense of vitality and freedom results from this kind of all-consuming desire. This is your chance to live a more fulfilled life where finding joy in what you do instead of pursuing the one thing you love is the goal.
Passion fuels our motivation. It aids us in constructing our dreams and goals. It's how we decide what our life's job is, and why we put in the effort to get there. Our lives are useless and unfulfilling without passion—for our friends and family, for creating beauty, for giving back, or for fulfilling a higher purpose.
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A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of the cliff.
The height of the cliff from the ground is 19.6 meters.
What is Projectile motion?Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration due to gravity.
Given is the initial speed of soccer ball kicked horizontally off a cliff which is 8 m/s. It cover a horizontal distance of 16 m. From this, we can write -
Horizontal initial velocity = u [h] = 8m/s
Horizontal distance covered = S [h] = 16m
For horizontal direction, of motion, we can write -
u [h] = 8m/s
S [h] = 16m
From second equation of motion applied for the horizontal direction -
S[h] = u[h] x t + 1/2 a[h] x t²
Since horizontal acceleration a[h] is zero, we can write -
t = S[h]/u[h]
t = 16/8
t = 2 seconds
Since the ball is kicked horizontally, the initial vertical velocity u[v] will be 0 m/s.
The acceleration in the vertical direction a[v] is directed vertically downwards and is equal to 9.8 m/s².
From second equation of motion applied for the vertical direction -
S[v] = u[v] x t + 1/2 x a[v] t²
S[v] = 1/2 x a[v] t² {u[v] = 0}
S[v] = 1/2 x 9.8 x 4
S(v) = 9.8 x 2
S[v] = 19.6 m
Therefore, the height of the cliff from the ground is 19.6 meters.
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[ The given question is not complete, the complete question is -
A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of the cliff: What is the time of flight of the soccer ball? What is the height of the cliff? ]
1. Compare the kinetic energy distributions for the heavy vs. light particles at the same
temperature. Are these the same or different? What about the speed distributions?
2. Compare the kinetic energy distributions for the heavy vs. light particles at different
temperatures. Are these the same or different? What about the speed distributions?
3. Compare the kinetic energy distributions for the mixture to those of the heavy-only and light-
only gases at the same temperature. Are these the same or different? What about the speed
distributions?
4. Summarize your observations about the relationships between molecular mass (heavy vs.
light), kinetic energy, particle speed, and temperature.
Only when the average speed of the heavy particles is lower than that of the light particles will the average kinetic energy of the light particles equal the average kinetic energy of the heavy particles.
How do the kinetic energy of the light and heavy particles compare?Only when the average speed of the heavy particles is lower than that of the light particles will the average kinetic energy of the light particles equal the average kinetic energy of the heavy particles.
As the temperature rises, the particles accumulate kinetic energy and quicken. The actual average speed of the particles is influenced by both their mass and temperature; at a given temperature, larger particles travel more slowly than lighter ones.
Given that the formula for calculating a particle's kinetic energy is
Ek = 1/2 mu²,
The formula for particle speed is [tex]$$c = [3RT/M]^{1/2[/tex].
The graphs of kinetic energy and particle speed show that the heavier particles only have higher peaks, whilst the lighter particles only have lower peaks.
It is clear from the graphs and the temperatures employed that the graphs' shapes were nearly identical. It does not appear to be significantly impacted by temperature.
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An auto's velocity increases uniformly from 6.0 m/s to 20 m/s while covering 70 m in a straight line. Find the acceleration and the time taken.
An auto's velocity increases uniformly from 6.0 m/s to 20 m/s while covering 70 m in a straight line, its acceleration is 2.6 [tex]m/s^2\\[/tex] and the time taken is 5.4 s.
AccelerationThe probable rate at which an object’s velocity changes with respect to time is referred to as its acceleration in mechanics. They are vector quantities and accelerations.
The direction of the net force acting on an object determines the direction of its acceleration.
Measurement scaleThe meter per second ([tex]m/s^2\\[/tex]) unit of acceleration is used to measure speed. The square meter is a measure of area ([tex]m^2[/tex])
The auto's velocity increases uniformly from 6m/s to 20m/s while it is covering the total of 70m.
Since it increases uniformly, thus we can use equation of motion
[tex]V^2 - U^2 =2as[/tex]
U = 6m/s
V = 20m/s
s = 70 m
Thus,
[tex](20)^2 - (6)^2 = 2*a*70[/tex]
a = 2.6 [tex]m/s^2\\[/tex]
Then for the time, we have
a = [tex]\frac{(V-U)}{t}[/tex]
2.6 = [tex]\frac{20 - 6}{t}[/tex]
t = 5.4 s
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In a nuclear power plant, a 1.0 kg of water at 58.6 °C is converted into 1.0 kg of steam at 131.8 °C. The total heat (in kcal) supplied by the plant is: Use cwater = 1.00 kcal/(kg.°C), csteam = 0.48 kcal/(kg.°C), and Lv = 540.0 kcal/kg
The total heat supplied by the plant to convert the water to steam is 596.7 kcal.
What is heat capacity?Heat capacity is the quantity of heat required to raise the temperature of entire mass of a substance.
Q = Heat supplied to the water to the boiling point + Heat supplied to vaporize the water.
Q = mc₁Δθ + mc₂Δθ + mLv
where;
m is the mass of the waterc₁ is specific heat capacity of waterc₂ is specific heat capacity of steamΔθ is change in temperatureLv is latent heat of vaporizationSubstitute the given parameters and solve for the heat supplied in the process.
Q = (1)(1)(100 - 58.6) + (1)(0.48)(131.8 - 100) + 540(1)
Q = 41.4 + 15.264 + 540
Q = 596.7 kcal
Thus, the total heat supplied by the plant to convert the water to steam is 596.7 kcal.
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It is observed that 54.90 mL of water at 20∘C completely fills a container to the brim. When the container and the water are heated to 60∘C, 0.35 g of water is lost. Part A What is the coefficient of volume expansion of the container? Density of water at 60 ∘C is 0.98324 g/mL.
The coefficient of volume expansion is given as 1.5012 x10^-4
What is volume?
A volume can simply be defined as the amount of space occupied by any three-dimensional solid. The solids can take the shape or form of a cube, a cuboid, a cone, a cylinder or a sphere
Volume of water that is lost
= (0.35) * (0.98324) mL
= 0.3441 mL
The original volume of
55.50 mL will increase to
55.8441 mL
V(t) = Vo [1 + γ(60.0 - 18.7)]
=> coefficient of volume expansion,
γ = (Vt - Vo) / [Vo * 41.3]
= (0.3441) / [(55.50) (41.3)
= 1.5012 x10^-4
The coefficient of the volume expansion can be the measure of the fractional change of size per unit change in the temperature with the surrounding pressure being constant.
In conclusion, the coefficient of volume is most applicable to the fluids.
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I’m curious to the differences between a rhetorical essay and a persuasive essay? Can anyone help out with a quick thorough answer?
Answer:
In a rhetorical essay you only analyze and cite 1 source in a persuasive essay you cite and analyze many different sources
Explanation:
What is the change in the freezing point of water when 68.5 g of sucrose is
dissolved in 500.0 g of water?
Kf of water = -1.86°C/mol
molar mass sucrose = 342.30 g/mol
ivalue of sugar = 1
OA. -0.215°C
OB. 0.254°C
C. -0.744°C
D. 0.0186°C
SUBMIT
When 68.5 g of sucrose is dissolved in 500.0 g of water, the freezing point of the water decreases by -0.744°C.
The correct option is C.
What does freezing point mean?The temperature at which a liquid freezes is known as the freezing point. The freezing point normally rises with increased pressure, much like the melting point does. Combinations and some organic materials, such lipids, have freezing points that are lower than melting points.
Briefing:The following formula is used to determine the freezing point depression:
ΔT = i m
where ,
ΔT is the change in freezing point,
i is the van't Hoff factor,
is the freezing point depression constant, and
m is the molality of the solution.
It is given in the question that the
of water = -1.86°C/mol
molar mass sucrose = 342.30 g/mol
i value of sugar = 1
500.0 g of water and 68.5 g of sucrose are dissolved in it.
ΔT = 1 * -1.86° *m
molality = (68.5/342.3)/(500/1000)= 0.200116857/.5
m = 0.400
ΔT = 1 * -1.86° * 0.400
ΔT = - 0.744°C
The change in the freezing point of water when 68.5g of sucrose is dissolved in 500.0 g of water is - 0.744°C .
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The process of estimating values between measured data points is called
interpolation
extrapolation
parallax
Answer:
interpolation
Explanation:
I got it right on the test.
A car accelerates from rest to a speed of 33 m/s. If the distance traveled by the car is 125m, how long
did it take for the car to reach this speed?
The car reaching to the given speed at the time, t = 0.264 s
Equation :To know the time of the car reaching to the given time use formula,
s = d / t
where,
s is speed
d is distance
t is time
Given,
distance, d = 125m
speed, s = 33m/s
time, t = ?
Putting values,
33m/s = 125 m / t
t = 33 m/s / 125m
t = 0.264 s
Speed time and distance relation :Speed is calculated as follows: speed = distance x time. Knowing units for distance and time is necessary to calculate the units for speed. The units will be in metres per second (m/s) in this example because the distance is measured in metres (m) and the time is measured in seconds (s).
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What did the Nuremberg Laws do:
A. Kept Jews from being German citizens and marked them with a Star of David
B. Establish the policy of mass-murder against the Jews
C. Moved Jews from occupied countries to ghettos
D. Prevented Jews from being teachers or judges
The gravitational potential energy of an object
depends on ....
[mark all correct answers]
a. mass of the object
b. velocity of the object
c. gravitational field
d. height of the object
e. stretch of the object
f. stiffness of the object
The gravitational potential energy of an object depends on mass of the object, gravitational field and height of the object.
What is gravitational potential energy?
The gravitational potential energy of an object is the energy possessed by the object due to the object's position above the ground level.
P.E = mgh
where;
m is mass of the objectg is acceleration due to gravityh is the height of the objectThe factors affecting gravitational potential energy of an object include;
mass of the objectheight of the objectacceleration due to gravity or gravitational fieldThus, the gravitational potential energy of an object depends on mass of the object, gravitational field and height of the object.
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The drawing shows two tug-of-war teams. Each person in the red team is
pulling with a force of 250 N. Each person in the blue team is pulling with a
force of 200 N.
S
AX
a What is the total force exerted by the blue team?
b What is the total force exerted by the red team?
c What is the resultant (unbalanced) force on the rope?
d Which team will win?
a) Force exerted by blue team = 1200N
b) Force exerted by red team=1250N
c) Resultant =50N in the direction of red team
d) Red team will win as they are pulling with greater force
There are 6 people on blue team and 5 people on red team
so here it is given that in blue team a person exerts a force of 250N and number of people is 6 , then total force will be 200x6=1200N
so here it is given that in red team a person exerts a force of 200N and number of people is 5 , then total force will be 250x5=1250N
the unbalance force here is 1250-1200=50N
from the above we know that red team have an extra force of 50N so they will win the match as they are pulling with greater force.
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A right triangle has a leg that measures 17 measures 24 ft. What would the missing length be
The lenght of the missing side is 29.41 ft.
To calculate the missing length of the triangle, we use pythagoras theorem.
What is pythagoras theorem?
Pythagoras theorem states that in a right angle triangle, the square the hypotenus is equal to the sum of the square of the two other sides.
These can be expressed mathematically as
a² = b²+c²...............Equation 1From the question,
b = 17 ftc = 24 ftSubstitute these values into equation 1
a² = 17²+24²a² = 289+576a² = 865a = √865a = 29.41 ft.Hence, the lenght of the missing side is 29.41 ft.
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a ball is thrown vertically upward with a speed of 19 m/s from a height of 7 m. how high does the ball rise from original position?
The ball rise 18.42 m from its original position.
What is Height?Height is the vertical distance between two points.
To calculate the height of the ball, from the original position, we use the formula below.
Formula:
v² = u²+2gh.......... Equation 1Make h the subject of the equation
h = (v²-u²)/2g...........Equation 2Where:
v = Final speedu = Initial speedg = Acceleration due to gravityh = Height of the ball from the original positionFrom the question,
v = 0 m/su = 19 m/sg = -9.8 m/s²Substitute these values into equation 2
h = (0-19²)/(2)×(-9.8)h = -361/-19.6h = 18.42 mHence, the ball rise 18.42 m from its original position.
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What balancing level are we at if we are standing at normal posture?
Medium
High
Low
Normal
The balancing level that we are when standing at a normal posture is the Normal balancing level. That is option D.
What is posture?Posture is defined as the bearing of one's body while at rest or while moving.
Normal posture can be defined as the normal position of the body while standing which involves standing straight and tall with shoulders back and the hands by the sides with the head kept in line with the body level.
The balancing level of posture is that level where the body is being positioned in such a manner as to reduce the amount of work done by the muscles.
Therefore, the balancing level that we are when standing at a normal posture is the Normal balancing level.
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An airplane touches down at a speed of 55.0 m/s on a runway that is 600.0 m long. The plane can decelerate at a uniform rate of 2.50 m/s². Will the plane be able to stop before the end of the runway?
The final velocity of the plane at the end of the railway is:
V2f=v2i+2a(x)
v2f=(55m/s)2−(2)(2.5m/s2)(600m)
vf=5m/s.
Since the final velocity is not equal to zero, the plane would not be able to stop at the end of the runway.
Technically, there may be the most effective manner for the aircraft to stay putting motionless inside the air if weight and raise cancel every other out perfectly, and at the equal time thrust and drag cancel every different out too. but this is exceptionally uncommon. To live within the air and sustain its flight, a plane wishes to be moving forward.
In addition to wing spoilers, airplanes use disc brakes. aircraft disc brakes are just like the braking system in automobiles. They consist of a pair of calipers that, while engaged, squeeze pads towards the rotors of an aircraft's landing gear. Disc brakes are designed to stay static at all times. maximum planes use a long runway earlier than takeoff to gain enough velocity for the aircraft to raise up into the air. most airplanes can take off handiest if they are moving rapidly sufficient.
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According to newtons 1st law of motion if u leave a cookie on a plate and there is no one else in the house,where will the cookie be in an hour?
A Ford F150 can slow to a stop from 60 m/s in 2.44 seconds with an acceleration of -0.207 m/s2. What is the braking distance of the car?
The braking distance of the car, given the data from the question is 145.784 m
How to determine the braking distanceFrom the question given above, the following data were obtained:
Initial velocity (u) = 60 m/sTime (t) = 2.44 sAcceleration (a) = -0.207 m/s²Final velocity (v) = 0 m/Breaking distance (s) =?The breaking distance of the car can be obtained as illustrated below:
s = ut + ½at²
s = (60 × 2.44) + (½ × -0.207 × 2.44²)
s = 146.4 + (-0.616)
s = 146.4 - 0.616
s = 145.784 m
From the calculation made above, we can conclude that the breaking distance of the car is 145.784 m
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An archer stands at rest on a frictionless frozen lake; his total mass including his bow and quiver of arrows is 60.00 kg. He then fires a 0.030kg arrow at 50.0 m/s at an angle of 30.0° above the horizontal. If it takes 650N of force to break the ice and the arrow leaves the bow in 10ms, what force does the archer exert on the ice?
The speed of the archer is 0.15m/s
The weight of the arrow compared to the man is
60/0.03 = 2000.
Thus, the man is 2000x heavier than the arrow.
Momentum is defined as P = m v or mass times velocity.
This must always be conserved. Since they stand at rest, the total momentum is zero.
The momentum of the arrow once shot is
50 x 0.03,
and thus the momentum of the archer is given by
60 x speed = 50 x 0.03
This rearranges into speed = (50 x 0.03) / 60
=0.15m/s
The speed of the archer is
=(speed of the arrow x mass of the arrow) / mass of the archer
=(50 × 0.030)/60
=0.15m/s
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A displacement is related to time as x=Asin(2πft).where A is a constant,t is the time and f is the frequency.Find the dimensions of A.
The dimension of the amplitude, A is L.
What is amplitude of a wave?The amplitude of a wave is the maximum displacement of the wave.
The amplitude of a wave is measured in the units of meters.
The given displacement of the light wave;
x = A sin(2πft)
where;
x is the displacement of the waveA is the amplitude of the wavef is frequency of the wavet is time of the wave's motionDimension of of amplitude, ASince amplitude of a wave measures the wave's displacement, then amplitude will have the same dimension as displacement.
A = meters = L
Thus, the dimension of the amplitude, A is L.
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What is the angle of rotation (in degrees) between two hands of a clock if the radius of the clock is 0.70 m and the arc length separating the two hands is 1.0 m?
The angle of rotation (in degrees) between two hands of a clock if the radius of the clock is 0.70 and the arc length separating the two hands is 1.0 m is 81.8°.
What is the angle of rotation (in degrees) between two hands of a clock?The angle of rotation (in degrees) between two hands of a clock if the radius of the clock is 0.70 m and the arc length separating the two hands is 1.0 m is determined as follows:
Total angle in a clock = 360°
radius of the clock, r = 0.70
Circumference of the circle = 2πr
Length of the arc = 1.0 m
Angle that makes the arc length = θ
Length of arc, l = θ/360 * 2πr
Angle that makes the arc length, θ = l * 360/2πr
Angle that makes the arc length, θ = 1.0 * 360 * 7/ (2 * 22 * 0.7)
Angle that makes the arc length, θ = 81.8°
In conclusion, the angle of rotation (in degrees) between two hands of a clock if the radius of the clock is found from the length of the arc and the radius of the clock.
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1.989 x 1030 kg 5.974 x 1024kg 1.5 x 1011 m.
Calculate the gravitational attraction
The Force of Gravitational Attraction is 34.85 ×10²¹N
Gravitational Force is the force acting between two masses separated by a distance. It is dependent on the magnitude of the masses and the distance between the two masses.
The mathematical relation is as follows:
F = Gm₁m₂/r²
where G is Gravitational Constant
m₁ is mass of first body
m₂ is mass of second body
r is the distance between the two masses
Given,
m₁ = 1.989×10³⁰
m₂ = 5.974×10²⁴
r = 1.5×10¹¹
G = 6.6×10⁻¹¹Nm²/kg²
On Substituting the above values,
F = 6.6×10⁻¹¹ × 5.974×10²⁴×1.989×10³⁰/(1.5×10¹¹)²
F = 34.85 ×10²¹N
Hence, the Force of Gravitational Attraction is 34.85 ×10²¹ N
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Calculate the average speed (in m/s) of a cheetah that run 140 meters in 5 seconds
Given :
Distance travelled by Cheetah = 140 mTime taken by Cheetah = 5 seconds.How to calculate average speed?
Average speed is calculated by Distance travelled / time taken.
Here, we know distance is 140 m and time is 5 seconds. Substituting the values,
=) Distance / Time
=) 140 m / 5 s
=) 28 m/s.
Therefore, the average speed (in m/s) of a cheetah that runs 140 meters in 5 seconds is 28m/s.
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