The sum of a first and second number is 130. If the second number is 20 less than four times the first number, find the two numbers. Let x represent the first number and y represent the second number.

Write the System of Equations used to solve this problem.

Answers

Answer 1
Use this equation to solve for the first number 130=4x-20 and then subtract that answer to get from 130 to get the second number. Im sorry im not sure what system of equations is hopefully this helped
Answer 2

The system of equations used to solve this problem are: x+y=130 and

y=20-4x. For this system x=-110/3 and y=500/3.

System of Linear Equations

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

You should convert the text into a math expression:

x+y=130 (1)

y=20-4x  (2)

Thus, you should replace the value of y given in equation 2, into equation 1. The,

x+20-4x=130

-3x=130-20

3x=-110

x= - 110/3

Therefore, y will be:

y=20-4*(- 110/3 )

y=20+440/3

y=60/3 +440/3

y=500/3

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Related Questions

what is 19+1 pls help me

Answers

20 you jfjbwjcbdjhdjf

b. Multiply (3 x - 1) by (x + 1)​

Answers

Answer:

(3x - 1)(x + 1) = 3x² + 2x - 1

Step-by-step explanation:

[tex] \rm \longrightarrow (3x - 1)(x + 1) \\ \\ \rm \longrightarrow 3x(x + 1) - 1(x + 1) \\ \\ \rm \longrightarrow (3x)(x) + (3x)(1) + ( - 1)(x) + ( - 1)(1) \\ \\ \rm \longrightarrow 3 {x}^{2} + 3x + ( - x ) + ( - 1) \\ \\ \rm \longrightarrow 3 {x}^{2} + 3x - x - 1 \\ \\ \rm \longrightarrow 3 {x}^{2} + 2x - 1[/tex]

Answer:

(3x - 1)(x + 1) = 3x² + 2x - 1

Step-by-step explanation:

got it right on edge

Answer This math question and ill give brainliest

Answers

Answer:

16 miles

Step-by-step explanation:

there are 8 units between the points each unit is 2 miles so 8*2= 16

I need help with this

Answers

-4,3 is the answer:)
The second one is the answer

The derivative of the function f is given by f′(x)=−3x+4 for all x, and f(−1)=6. Which of the following is an equation of the line tangent to the graph of f at x=−1 ?

Answers

Answer:

The equation of the line tangent to the graph of f at x = -1 is [tex]y = 7\cdot x +13[/tex].

Step-by-step explanation:

From Analytical Geometry we know that the tangent line is a first order polynomial, whose form is defined by:

[tex]y = m\cdot x + b[/tex] (1)

Where:

[tex]x[/tex] - Independent variable, dimensionless.

[tex]y[/tex] - Dependent variable, dimensionless.

[tex]m[/tex] - Slope, dimensionless.

[tex]b[/tex] - Intercept, dimensionless.

The slope of the tangent line at [tex]x = -1[/tex] is:

[tex]f'(x) = -3\cdot x +4[/tex] (2)

[tex]f'(-1) = -3\cdot (-1) +4[/tex]

[tex]f'(-1) = 7[/tex]

If we know that [tex]m = 7[/tex], [tex]x = -1[/tex] and [tex]y = 6[/tex], then the intercept of the equation of the line is:

[tex]b = y-m\cdot x[/tex]

[tex]b = 6-(7)\cdot (-1)[/tex]

[tex]b = 13[/tex]

The equation of the line tangent to the graph of f at x = -1 is [tex]y = 7\cdot x +13[/tex].

The number 0.003 is 1/10 of which decimal?

Answers

Answer:

I'd say it's 0.03

Step-by-step explanation:

0.03 divided by 10 is 0.003 so it's 1/10

0.003 is 1/10th of 0.03.

What is a decimal ?

A decimal is represented by a point or a dot it separates the decimal part and the fractional part for example 24.75 here the whole part is is 24 and the fractional part is 75.

if we divide 0.03 by 10  = [tex]\frac{0.03}{10}[/tex] = 0.003.                     (dividing a number by 10

                                                                                    moves the decimal point

                                                                                    to the left by 1 because                      

                                                                                    10 has 1 no. of zeroes)

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A meat inspector has randomly selected 30 packs of 95% lean beef. The sample resulted in a mean of 96.2% with a sample standard deviation of 0.8%. Calculate an upper prediction bound for the leanness of a new pack using a prediction level of 99%. Assume normality. The contents of seven similar containers of sulfuric acid are 9.8, 10.2, 10.4, 9.8,10.0, 10.2, and 9.6 liters. Find a 95% confidence interval for the mean contents of all such containers, assuming an approximately normal distribution.

Answers

Answer:

a

 The upper bound of the 99% prediction level is [tex] 98.2  [/tex]  

b

 The  95% confidence interval is [tex]9.7383 <  \mu < 10.2617 [/tex]

Step-by-step explanation:

Considering first question

From the question we are told that

   The sample size is  n  =  30  

   The sample mean is  [tex]\= x = 96.2\%[/tex]

   The standard deviation is [tex]s = 0.8\%[/tex]

Generally the degree of freedom is mathematically represented as

        [tex]df = n - 1[/tex]

=>      [tex]df = 30 - 1[/tex]

=>      [tex]df = 29[/tex]

From the question we are told the confidence level is  99% , hence the level of significance is    

      [tex]\alpha = (100 - 99 ) \%[/tex]

=>   [tex]\alpha = 0.01[/tex]

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

   [tex]t_{\alpha , 29} = 2.462[/tex]

Generally the  99%  prediction level is mathematically represented as

      [tex]\= x \pm [(t_{\alpha  , df }) * s * (\sqrt{1 + \frac{1}{ n} } )}] [/tex]

Generally the upper bound of the 99%  prediction level is mathematically represented as

      [tex]\= x + [(t_{\alpha  , df }) * s * (\sqrt{1 + \frac{1}{ n} } )}] [/tex]  

=>    [tex] 96.2 + (2.462 ) * 0.8 * (\sqrt{1 + \frac{1}{ 30} } )}] [/tex]  

=>    [tex] 98.2  [/tex]  

Considering second question

 Generally the sample is mathematically represented as

             [tex]\= x = \frac{\sum x_i}{n}[/tex]

=>           [tex]\= x = \frac{ 9.8 + 10.2 + \cdots +9.6 }{7}[/tex]  

=>           [tex]\= x = 10[/tex]    

Generally the standard deviation  is mathematically represented as

           [tex]\sigma = \sqrt{ \frac{ \sum ( x_ i - \= x)}{n-1} }[/tex]

=>        [tex]\sigma = \sqrt{ \frac{ ( 9.8 -10)^2 + ( 10.2 -10)^2 + \cdots + ( 9.6 -10)^2 }{7-1} }[/tex]

=>        [tex]\sigma = 0.283[/tex]

Generally the degree of freedom is mathematically represented as

      [tex] df =  n- 1 [/tex]

=>    [tex] df =  7- 1 [/tex]

=>    [tex] df =  6 [/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the t distribution table the critical value  of   at a degree of freedom of  is  

   [tex]t_{\frac{\alpha }{2} , 6 } =  2.447[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E = t_{\frac{\alpha }{2} , 6 } *  \frac{\sigma }{\sqrt{n} }[/tex]

=>    [tex]E =2.447*    \frac{0.283 }{\sqrt{7} }[/tex]

=>    [tex]E =0.2617[/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x -E <  \mu <  \=x  +E[/tex]

=>   [tex]10 -0.2617 <  \mu < 10 + 0.2617[/tex]

=>   [tex]9.7383 <  \mu < 10.2617 [/tex]

I feel it could be AAS since both angles could be alternate interior but it could also be SAS so could someone help please?

Answers

Answer: D) Side-Angle-Side  (SAS)

Check out the diagram below. Note the color coding to see how the angles and sides correspond to the given information. We aren't given RT = RT, but we use the reflexive property in this case. The angles are between the sides so we use SAS.

We don't have enough information to determine anything about the other angles, so we cannot use AAS or ASA. Also, recall that SSA is not a valid congruence theorem. Luckily the angle is between the sides so we don't have to worry about SSA.

PLEASE HELP


A car dealer offers a 15% discount off the list price x for any car on the lot. At the same time, the manufacturer offers a $1500 rebate for each purchase of a car.


a. Write a function f(x) to represent the price after the discount is applied.


b. Write a function g(x) to represent the price after the rebate is applied.


Suppose the list price of a car is $19,000. Use a composite function to find the price

of the car:


C. if the discount is applied before the rebate;


D. if the rebate is applied before the discount

Answers

Answer:

A) f(x) = 0.85x

B) g(x) = x - 1500

C) g(f(x)) = $14650

D) f(g(x)) = $14875

Step-by-step explanation:

A) The list price is x and a 15% discount is applied.

Thus;

f(x) = x - 15%x

f(x) = 0.85x

B) We are told that the manufacturer offers a $1500 rebate for each purchase of a car.

Thus, the function g(x) to represent the price after the rebate is applied is;

g(x) = x - 1500

C)if the discount is applied before the rebate, the function is;

g(f(x))

Now,

f(x) = 0.85(19000)

f(x) = 16150

g(x) = x - 1500

Thus;

g(x) = 16150 - 1500

g(x) = $14650

D) If discount after rebate, then we have; f(g(x))

g(x) = 19000 - 1500

g(x) = 17500

f(g(x)) = 0.85(17500)

f(g(x)) = $14875

Please help!!!
If h(x)= -3x-10, find h(-3)
Please give an explanation too. Thank you.

Answers

Answer:

h(-3)=-1

Step-by-step explanation:

Replace all x in h(x)= -3x-10 by -3:

h(-3)=-3(-3)-10

Now multiply -3 and -3:

h(-3)=9-10

Simplify 9 and -10 (aka add 9 and -10 together):

h(-3)=-1

Answer: h(-3)=-1

Hope this helps!

Answer:

-1

Step-by-step explanation:

If h(x)= -3x-10 and we want to solve for h(-3) then we have to plug in -3 for all x variables. h(-3)= -3(-3)-10, then solve using PEMDAS.

First multiple h(-3)= 9-10, multiple -3*-3 to get 9.

Then subtract, h(-3)=-1

On Monday, Deborah ran 3 2− 5miles and on Tuesday she ran 4 1− 5miles. How many miles did she run on these two days together?

Answers

Mixed fraction:

3 2/5 = 17/5

4 4/5 = 24/5

Miles she ran:

17/5 + 24/5

= 41/5 miles or 8.2 miles

The length of one side of a square pond is 15 feet. The pond is surrounded by a 3 foot wide walkway. What is the total area of the pond and the walkway, in square feet

Answers

Answer:

Area = 324 ft²

Step-by-step explanation:

Given

Length = 15ft

Walkway = 3ft

Required

Determine the area of the pond + the walkway

To calculate the required area, we need to get the total length of a side .

This is calculated by adding the length of a side of the pond and the side of the walkway

Total Length = Pond Length + Walkway

Total Length = 15ft + 3ft

Total Length = 18ft

Now, the required area can be calculated as thus:

Area = Total Length * Total Length

Area = 18ft * 18ft

Area = 324 ft²

if my dog was born 4 weeks before August 27th how old will my dog be

Answers

Answer:

the dog was born on july 30th so the dog would be 3 months and a week old

Step-by-step explanation:

2. Determine whether quadrilateral EFGH can
be classified as a parallelogram.
Justify your reasoning.

Now consider quadrilateral EFGH shown

Answers

Answer:

3.4

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

there are two sets of parrallel lines.

I will put brainliest
The bowling club at your school had a car wash last week.
They washed 72 cars in 6.5 hours.

About how many cars did they wash per hour?

Answers

Answer:

11.077 cars / 11 cars (nearest whole number)

Step-by-step explanation:

6.5 hours → 72 cars

1 hour → 72/6.5 cars = 11.077 cars (5 s.f.)

Brainliest Answer
(has to be right for brainliest)

Answers

Answer:

it is 0.7x0.4=0.28

Step-by-step explanation:

Answer:

3627514

Step-by-step explanation:

40% as fraction and decimal

Answers

Answer:

40% as a decimal is 0.4

40% as a fraction is 2/5

Step-by-step explanation:

Let's go over each of these step by step.

First, let's see 40% as a fraction.

Since 40% is out of 100%, we can rewrite that as 40/100.

If you want to simplify it, let's do the following.

40/100

Divide both sides by 20, and you'll end up with:

2/5.

Now, let's do 40% as a decimal.

This is pretty simple.

40% is 40/100 as said before, and to find it as a decimal,

let's divide 40 and 100.

40 divided by 20 = 0.4

Therefore, we can conclude the following:

40% as a fraction is 40/100, or 2/5.

40% as a decimal is 0.4

Hope this helped! :)

Can you do this for me?

Answers

Answer:

10, 20, 30, 40

2.5, 5, 7.5, 10

120.8, 60.4, 30.2, 15.1

3624, 1812, 906, 453

hope this helps!

Make w the subject of the formula y - aw = 2w - 1

Answers

Answer:

[tex]w=\frac{y+1}{a-2} (a\neq 2)[/tex]

Step-by-step explanation:

[tex]y - aw=2w-1\\y-aw-2w=-1\\-aw-2w=-1-y\\-w(a-2)=-(y+1)\\w(a-2)=y+1\\w=\frac{y+1}{a-2} (a\neq 2)[/tex]

Hope this helps!

Which number is divisible by 3?
A) 1,794
B) 1,912
C) 1,270
D) 473

Answers

Answer:

Step-by-step explanation:

should be A.

Azrael and Simon are training for track. Azrael trains at a rate of 6 miles every half hour. Simon trains at a rate of 2 miles every 15 minutes. What is the unit rate in mile per hour for each runner? *
A. Azrael = 12 miles per hour ; Simon = 8 miles per hour
B. Azrael = 8 miles per hour ; Simon = 12 miles per hour
C. Azrael = 6 miles per hour ; Simon = 2 miles per hour
D. Azrael =2 miles per hour ; Simon = 6 miles per hour

Answers

Answer:

A The first one

Answer:

A

Step-by-step explanation: 30 minutes is half an hour so 6 miles is half the miles he runs an hour. Azrael runs 12 miles in an hour. 15 minutes is 1/4 of an hour. 2 is 1/4 of the miles Simon runs in an hour. 2 times 4 is 8. I'm really bad at explaining, sorry. the answer is A.

The distance an object falls is directly proportional to the square of the time it falls. A ball falls 144 feet in 3 seconds. How far will an object fall in 4 seconds?

Answers

Answer:

d = 256 ft.

Step-by-step explanation:

The distance an object falls is directly proportional to the square of the time it falls.

First, we name the variables.

Let d= the distance.

t= time

Write the formula for direct variation, where y varies directly with the square of x.

y=kx2

We will use d in place of y and t in place of x.

d=kt2

Substitute the given values for the variables.

d=144whent=3144=k⋅32

Solve for the constant of variation.

144916=k⋅99=k

Write the equation that relates d and t.

d=kt2

Substitute in the constant of variation.

d=16t2

Find d when t=4.

Write the equation that relates d and t.

d=16t2

Substitute the given value for t.

d=16⋅42

Simplify.

d=256

An object will fall 256 feet in 4 seconds.

The required distance fall by fall in 4 seconds is 192 feet.

Given that,
The distance an object falls is directly proportional to the square of the time it falls. A ball falls 144 feet in 3 seconds, how far will an object fall in 4 seconds is to be determined.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division.

here,
The rate of fall of the ball = 144 / 3
                                      = 48 feet second
Now distance fall by the ball in 4 seconds = 48 * 4 = 192 feets.


Thus, the required distance fall by fall in 4 seconds is 192 feet.

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Help ASAP Find the measure of 2.

21
69
111

Answers

Answer:

69°

Step-by-step explanation:

m∠1 + 111° = 180° ⇒ m∠1 = 69°

m∠1 = m∠2 = 69°

Find the missing measure and write your solution on the blank provided

Answers

Step-by-step explanation:

sum of internal angles of any triangle = 180 degrees

sum of an exterior angle and an interior angle = 180 degrees

Math problem pls help I will give brainiest

Answers

Answer:

y=5

Step-by-step explanation:

125 +125+13y+9y=360

punch it into math-way.

250+22y=360

22y= 110

y=5

Problem
What is the constant of proportionality in the equation y=3xy

Answers

Answer:

-3

Step-by-step explanation:

y=3xy and subtract y on both sides that gives u -1 and then you have -1=3x and then divide 3 on both sides you are left with -3 =x

please help, the question says what statement best describes the placement of the lines Carson Drew​

Answers

Answer:

Only line A is a well-placed line of best fit.

Step-by-step explanation:

I did this on Plato and got it correct.

What is the solution set for 24+ 2 = 6 given the replacement set {1,2,3,4} 1=2 1-4

x = 2

x = 4

x = 1

x = 3​

Answers

Answer:

x is 2

Step-by-step explanation:

HELP!!!!! I dont understand this!​

Answers

Answer:

-14

Step-by-step explanation:

I might be wrong, but this is my interpretation of the problem.

To solve this problem, find the endpoints of the line in the interval. Then draw a line between those two points. Finally, find the slope of the line that passes between the two points.

The line is f(x) = -2x^(2) + 2x + 1

The interval (in standard notation) is (3 [tex]\leq[/tex] x [tex]\leq[/tex] 5)

So when x = 3,

-2x^(2) + 2x + 1

-2(3)^(2) + 2*3 + 1

-2 * 9 + 6 + 1

-18 + 7

- 11

One endpoint is: (3, -11).

When x = 5

-2x^(2) + 2x + 1

-2(5)^2 + 2*5 + 1

-2 * 25 + 10 + 1

-50 + 11

-39

The other endpoint is; (5, -39).

Find the slope of a line passing through these two points.

The formula to find the slope of a line is:

[tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

[tex]x_{1}[/tex] = 3

[tex]y_{1}[/tex] = -11

[tex]x_{2}[/tex] = 5

[tex]y_{2}[/tex] = -39

((-39) - ( -11))/((5) - (3))

Simplify

-28/2

-14

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, and below the cone z = x^2 + y^2.

Answers

Answer:

The volume of the solid is 243[tex]\sqrt{2} \ \pi[/tex]

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

[tex]x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81[/tex]

[tex]2(x^2 + y^2) =81[/tex]

[tex]x^2 +y^2 = \dfrac{81}{2}[/tex]

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

[tex]z = \sqrt{x^2+y^2}[/tex]

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; [tex]\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}[/tex]

Thus, volume: [tex]V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi[/tex]

[tex]V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho[/tex]

[tex]V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}[/tex]

[tex]V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ][/tex]

V = 243[tex]\sqrt{2} \ \pi[/tex]

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